g Drop the object again and carefully observe its motion after it hits the ground (it should bounce). (Consider only the first bounce and do NOT assume the total energy is the same as the total energy of the object before it hits the ground.) a. List the quantities that you need to know to determine the total energy of the object after it hits the ground. b. Record your measurements and describe how you measured them. c. Calculate the total energy of the object after it hit the ground. Your final answer: ______________ d. Determine whether or not the object’s energy was conserved when it hit the ground. If it was not conserved, explain where the energy went.

Answers

Answer 1

Answer:

a) quantity to be measured is the height to which the body rises

b) weighing the body , rule or fixed tape measure

c)   Em₁ = m g h

d) deformation of the body or it is transformed into heat during the crash

Explanation:

In this exercise of falling and rebounding a body, we must know the speed of the body when it reaches the ground, which can be calculated using the conservation of energy, since the height where it was released is known.

a) What quantities must you know to calculate the energy after the bounce?

The quantity to be measured is the height to which the body rises, we assume negligible air resistance.

So let's use the conservation of energy

starting point. Soil

          Em₀ = K = ½ m v²

final point. Higher

          Em_f = U = mg h

         Em₀ = Em_f

         Em₀ = m g h₀

b) to have the measurements, we begin by weighing the body and calculating its mass, the height was measured with a rule or fixed tape measure and seeing how far the body rises.

c) We use conservation of energy

starting point. Soil

          Em₁ = K = ½ m v²

final point. Higher

          Em_f = U = mg h

         Em₁ = Em_f

         Em₁ = m g h

d) to determine if the energy is conserved, the arrival energy and the output energy must be compared.

There are two possibilities.

* that have been equal therefore energy is conserved

* that have been different (most likely) therefore the energy of the rebound is less than the initial energy, it cannot be stored in the possible deformation of the body or it is transformed into heat during the crash


Related Questions

finger bones do not have joints true or false

Answers

Explanation:

Finger bones have joints.

Answer: true , finger bones have joints

Explanation:

Air plane travels 224 in 2 hours.
How fast was the plane traveling?

Answers

The airplane is traveling 112 per hour

Answer:

112mph

Explanation:bugyg

two identical neutral metal spheres rest on an isolated table if you wanted to give it a net positive charge while spear to is given a net negative charge Which statement explains the movement of charges during the charging process​

Answers

Answer:

its c

Explanation:

An important news announcement is transmitted by radio waves to people who are 46 km away, sitting next to their radios, and by sound waves to people sitting across the newsroom, 2.1 m from the newscaster. Take the speed of sound in air to be 348 m/s. What is the difference in time that the message is received

Answers

Answer:

[tex]0.005847\ \text{s}[/tex]

Explanation:

Radio waves travel at the speed of light

[tex]c[/tex] = Speed of light = [tex]3\times 10^8\ \text{m/s}[/tex]

[tex]d_r[/tex] = Distance between two radios = 46 km

[tex]v[/tex] = Speed of sound in air = 348 m/s

[tex]d_s[/tex] = Distance sound travels across the newsroom = 2.1 m

Time taken by the radio signal to reach the required location is

[tex]t_r=\dfrac{d_r}{c}\\\Rightarrow t_r=\dfrac{46\times 10^3}{3\times 10^8}\\\Rightarrow t_r=0.000153\ \text{s}[/tex]

Time taken by sound to reach the required location is

[tex]t_s=\dfrac{d_s}{v}\\\Rightarrow t_s=\dfrac{2.1}{348}\\\Rightarrow t_s=0.006\ \text{s}[/tex]

The time difference is

[tex]t_s-t_r=0.006-0.000153=0.005847\ \text{s}[/tex]

The difference in time that the message is received is [tex]0.005847\ \text{s}[/tex].

A human body consists of

Answers

Answer:

60% of the human adult body is water. According to H.H. Mitchell, Journal of Biological Chemistry 158, the brain and heart are composed of 73% water, and the lungs are about 83% water. The skin contains 64% water, muscles and kidneys are 79%, and even the bones are watery: 31%.

Explanation:

diffused reflection occurs if a ray of light is reflected by a ​

Answers

Answer:

Diffused reflection occurs if ray of light is reflected by rough surface

A stone with a mass of 0.600 kg is attached to one end of a string 0.900 m long. The string will break if its tension exceeds 50.0 N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed.
A. Draw a free-body diagram of the stone.
B. Find the maximum speed the stone can attain without breaking the string.

Answers

Answer:

8.7 m/s

Explanation:

Given data

Mass= 0.6kg

radius= 0.9m

Force= 50N

A. Please see attached the FBD of the stone

B. Apply the formula

F= mv^2/r

Substitute

50= 0.6*v^2/0.9

cross multiply

50*0.9= 0.6v^2

45= 0.6v^2

v^2= 45/0.6

v^2= 75

v= √75

v= 8.7 m/s

Hence the maximum speed attained without breaking the string is 8.7 m/s

A 1.6-kg ball is attached to the end of a 0.40-m string to form a pendulum. This pendulum is released from rest with the string horizontal. At the lowest point of its swing, when it is moving horizontally, the ball collides with a 0.80-kg block initially at rest on a horizontal frictionless surface. The speed of the block just after the collision is 3.0 m/s. What is the speed of the ball just after the collision?a. 1.5 m/sb. 1.3 m/sc. 2.1 m/sd. 1.1 m/se. 1.7 m/s

Answers

Answer:

a. 1.5 m/s

Explanation:

We will apply the law of conservation of energy in this situation between the initial position and the lowest point of the swing:

[tex]m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}\\[/tex]

where,

m₁ = mass of ball = 1.6 kg

m₂= mass of block = 0.8 kg

u₁ = initial speed of ball = 0 m/s

u₂ = initial speed of block = 0 m/s

v₁ = final speed of ball = ?

v₂ = final speed of block = 3 m/s

Therefore,

[tex](1.6\ kg)(0\ m/s)+(0.8\ kg)(0\ m/s)=(1.6\ kg)(v_{1})+(0.8\ kg)(3\ m/s)\\\\v_{1} = \frac{2.4\ N.s}{1.6\ kg}\\[/tex]

v₁ = 1.5 m/s

Therefore, the correct option is:

a. 1.5 m/s

mention the characteristics of small scale business(any5)​

Answers

Explanation:

plzzzz mark me brainliest if it helps you then

•Ownership: They have a single owner. ...
•Management: All the management works are controlled by the owner.
•Limited Reach: They have restricted area of operation. ...
•Labor Intensive: Their dependency on technology is very little because they are dependent on labours and manpower.

describe how electrons create electricity

Answers

describe how electrons create electricity

Atoms are made up of even smaller elements, called protons, electrons and neutrons. When electrical and magnetic forces move electrons from one atom to another, an electrical current is formed

Electrons in atoms can act as our charge carrier, because every electron carries a negative charge. If we can free an electron from an atom and force it to move, we can create electricity. ... In its balanced state, copper has 29 protons in its nucleus and an equal number of electrons orbiting around it.

Hope It Helps!

5. It takes
to get a job done.

Answers

Answer:

determination

Explanation:

Assume a uniformly charged ring of radius R and charge Q produces an electric field Ering at a point P on its axis, at distance x away from the center of the ring. Now the charge Q is spread uniformly over the circular area the ring encloses, forming a flat disk of charge with the same radius. How does the field Edisk produced by the disk at P compare to the field produced by the ring at the same point?Assume a uniformly charged ring of radius R and charge Q produces an electric field Ering at a point P on its axis, at distance x away from the center of the ring. Now the charge Q is spread uniformly over the circular area the ring encloses, forming a flat disk of charge with the same radius. How does the field Edisk produced by the disk at P compare to the field produced by the ring at the same point?

Answers

Answer:

* E_ring = [tex]k \ \frac{x}{(x^2+ y^2)^{3/2} } \ Q[/tex]

*E_ disk= 2kQ  [tex]\frac{1}{R^2} \ (1 - \frac{x}{(x^2+ R^2)^{1/2} } )[/tex]

Explanation:

Let's start by finding the electric field of the charged ring

in the attachment we can see a diagram of the system. Due to circular symmetry, the electric field perpendicular to the axis is canceled and only the electric field remains parallel to the axis.

            Eₓ = E cos θ          (1)

            E = k ∫  [tex]\frac{dq}{r^2}[/tex]

            cos θ = x / r

             

using the Pythagorean theorem

            r = [tex]\sqrt{x^2 + y^2}[/tex]

we substitute

            Eₓ = k ∫ [tex]\frac{dq}{x^2+y^2} \ \frac{x}{\sqrt{ x^2+y^2} }[/tex]

            Eₓ =  [tex]k \frac{x}{(c^2+y^2)^{3/2} }[/tex]   ∫ dq

             Eₓ = k \frac{x}{(c^2+y^2)^{3/2} }  Q

the ring's electric field

             E_ring = [tex]k \ \frac{x}{(x^2+ y^2)^{3/2} } \ Q[/tex]

Now let's find the electric field of the disk

The charge is distributed over the entire disk, so let's use the concept of charge density

              σ = [tex]\frac{dq}{dA}[/tex]

Let's approximate the disk as a group of rings, the width of each ring is dr, the area is

              dA = 2πr dr

               

we substitute

             σ = [tex]\frac{1}{2\pi r} \ \frac{dq}{dr}[/tex]

             dq = 2π σ r dr

we substitute in equation 1, where the electrioc field is of each ring

             Eₓ = [tex]k \int\limits^R_0 \ { \frac{x}{(x^2+r^2)^{3/2} } \ 2\pi \sigma \ r } \, dr[/tex]

             

if we use a change of variable

               dv = 2rdr

               v = r²

              Eₓ =  [tex]k x \pi \sigma \int\limits^a_b { \frac{1}{(x^2+v)^{3/2} } } \, dv[/tex]

we integrate

              Eₓ = k x π σ   [tex][ \frac{ (x^2 + r^2)^{-1/2} }{-1/2} ][/tex]

we value in the limits from r = 0 to r = R

              Eₓ = k π σ x  (-2) [ [tex]\frac{1}{ \sqrt{x^2+R^2} } - \frac{1}{x}[/tex]]

              Eₓ = 2π k  σ ([tex]1 - \frac{x}{(x^2 + R^2 ) ^{1/2} }[/tex]  )

 

             σ = Q/πR²

substitute

             Eₓ = 2 k Q/R² (1 - \frac{x}{(x^2 + R^2 ) ^{1/2} } )

             E_ disk= 2kQ  [tex]\frac{1}{R^2} \ (1 - \frac{x}{(x^2+ R^2)^{1/2} } )[/tex]

             

The two electric fields are

* E_ring = [tex]k \ \frac{x}{(x^2+ y^2)^{3/2} } \ Q[/tex]

*E_ disk= 2kQ  [tex]\frac{1}{R^2} \ (1 - \frac{x}{(x^2+ R^2)^{1/2} } )[/tex]

we can see that the functional relationship of the two fields is different

A pail in a water well is hoisted by means of a frictionless winch, which consists of a spool and a hand crank. When Jill turns the winch at her fastest water-fetching rate, she can lift the pail the 26.0 m to the top in 12.0 s. Calculate the average power supplied by Jill's muscles during the upward ascent. Assume the pail of water when full has a mass of 6.50 kg. W

Answers

Answer:

140.83 W

Explanation:

From the question given above, the following data were obtained:

Height (h) = 26 m

Time (t) = 12 s

Mass (m) = 6.50 Kg

Power (P) =?

Power is simply defined as the rate at which energy is used up. Mathematically, it is expressed as:

Power (P) = Energy (E) / Time (t)

But:

Energy (E) = mass (m) × acceleration due to gravity (g) × height (h)

E = mgh

P = E/t

P = mgh / t

With the above formula i.e

P = mgh / t

We can obtain the power supplied by Jill's muscles as follow:

Height (h) = 26 m

Time (t) = 12 s

Mass (m) = 6.50 Kg

Acceleration due to gravity (g) = 10 m/s²

Power (P) =?

P = mgh / t

P = 6.5 × 10 × 26 / 12

P = 140.83 W

Therefore, the power supplied by Jill's muscles is 140.83 W

When the frequency of a sound wave is doubled, then:

Answers

Answer:

If the frequency of a wave is doubled, what happens to its wavelength? If the frequency is doubled, the wavelength is only half as long.

Answer:

Hey,

QUESTION)

✔ We have : λ = v/f

According to this relationship, the wavelength is inversely proportional to the frequency. So when the frequency doubles, the wavelength is halved.

Look at the circuit diagram. What does the diagram show?

Answers

Answer:

the second one i gues

Explanation:

the stripes tells about the batery input/ the x is the lightbulbs/ and two switches

This square solenoid has sides length 25 cm, and 100 turns of wire. The resistance is 10 ohms. Find the magnitude of the induced emf in the coil if the magnetic field of 10 T is passing through the face of the loop as pictured. What is the induced current in the wire. Find the emf and current if the solenoid was a circle with radius 25 cm instead of a square.

Answers

Explanation:

Area of square = 25^2 = 625 cm^2 or  = 0.0625 m^2

number of turns = 100

Solenoid resistance = 10 ohms

now we know , Φ = B.A

where , Φ = magnetic flux, B= magnetic field strength, and A = area.

Φ = 10 × 0.0625 = 0.625 W

induced emf ε = dΦ/dt = d(BA)/dt  =0

This is because both B and A are constants.

⇒ Induced current is also zero.

Replacing square by a circle will not change situation as the value of B and A will remain constant with time hence, no emf induced, so no current induced.

A marble at the front of a truck bed traveling at 20 m/s relative to the highway rolls toward the back of the truck bed with a speed of 7m/s relative to the truck bed. What is the velocity of the marble relative to the highway?

Answers

14 m/s in the direction of the truck

During a lab experiment, a student took his resting pulse rate, counting 25 beats in 20 seconds. What was the student's pulse rate in beats per minutes (bpm)?

Answers

Answer:

75 bpm

Explanation:

60 seconds in a minute

60seconds / 20 seconds = 3

25 beats * 3 = 75 bpm

NEED HELP ASAP!!!

-The difference between chemical reactions and nuclear reactions
-The difference between fission and fusion
-What is given off during nuclear decay (how elements change into others)
-How to calculate half life or amount of sample left from half life ​

Answers

Explanation:

Chem has to do with stored energy while nucleic deals with nucleic reactions.

Can light have inertia??

Answers

Answer:

Yes.

Explanation:

Yes Light has inertia, since inertia is in units of mass.

Yes! Interim is in units of mass so yes!

what is the reason for timing more than one oscillation in a simple pendulum​

Answers

Answer:

Time period is the time taken by the body to complete one oscillation and it is noted more than once to get accurate reading from averaging of all the observed values.

a girl runs and cover a distance of 200m in 20 secends.The speed of the girl is ................ m/s.

Answers

Speed = distance/time

Speed = (200m)/(20s)

Speed = 10 m/s

12. A baseball (m = 0.14 kg) with initial velocity of -40 m/s (90 mph) is hit. It leaves the bat with a velocity of 60m/s after 0.001s. What is the impulse and average net force applied to the ball by the bat? ​

Answers

Answer:

the impulse is 14 kg-m/s and the net force applied is 14000 N

Explanation:

Given that,

The mass of a baseball, m = 0.14 kg

Initial velocity of the baseball, u = -40 m/s

Final velocity, v = 60 m/s

Time, t = 0.001 s

We need to find the impulse and average net force applied to the ball by the bat.

Impulse = change in momentum

i.e.

J = m(v-u)

J = 0.14 × (60-(-40))

J = 14 kg-m/s

Now,

J = Ft

F is average force applied to the ball

So,

[tex]F=\dfrac{J}{t}\\\\F=\dfrac{14}{0.001}\\\\F=14000\ N[/tex]

So, the impulse is 14 kg-m/s and the net force applied is 14000 N.

We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top of the tree exerts a horizontal force, and thus a torque that can topple the tree if there is no opposing torque. Suppose a tree's canopy presents an area of 9.0 m2 to the wind centered at a height of 7.0 m above the ground. (These are reasonable values for forest trees.)

Answers

Answer:

A,)FD= 114.1N

B)Torque=798.5Nm

Explanation:

We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top of the tree exerts a horizontal force, and thus a torque that can topple the tree if there is no opposing torque. Suppose a tree's canopy presents an area of 9.0 m^2 to the wind centered at a height of 7.0 m above the ground. (These are reasonable values for forest trees.)

If the wind blows at 6.5 m/s, what is the magnitude of the drag force of the wind on the canopy? Assume a drag coefficient of 0.50 and the density of air of 1.2 kg/m^3

B)What torque does this force exert on the tree, measured about the point where the trunk meets the ground?

A)The equation of Drag force equation can be expressed below,

FD =[ CD × A × ρ × (v^2/ 2)]

Where CD= Drag coefficient for cone-shape = 0.5

ρ = Density

Area of of the tree canopy = 9.0 m^2

density of air of = 1.2 kg/m^3

V= wind velocity= 6.5 m/s,

If we substitute those values to the equation, we have;

FD =[ CD × A × ρ × (v^2/ 2)]

F= [ 0.5 × 9.0 m^2 × 1.2 kg/m^3 ( 6.5 m/s/ 2)]

FD= 114.1N

B) the torque can be calculated using below formula below

Torque= (Force × distance)

= 114.1 × 7

= 798.5Nm

A) how many cm³ are there in 0.08L?
B) How many dm³ are there in 750mL?​

Answers

Answer:

A) 80 cm³

B) 0.75 dm³

Explanation:

I hope this help❤️

What instrument makes the slowest vibration? A drum? A whistle? A flute? Or a harmonica?

Answers

Answer:

A harmonica.

Explanation:

The structure of a harmonica is built in such a way that when the air is blown by the player in it, the air moves within the rectangular structure and making sound vibrations. Sound is heard when an object vibrates. The movement of this vibration creates sound waves, and these waves enter our ears in the form of music.

Therefore, the instrument that will make the slowest vibration among the given instrument will be the harmonica. Thus option D is correct.

An instrument that produces an electric current in the presence of
a radioactive substance is called a
a. particle accelerator.
b. Geiger counter.
c. cloud chamber.
d. bubble chamber.

Answers

Answer:

Option B, Geiger counter

Explanation:

Which of the following is an example of an ascribed status?

Multiple Choice

1. musician

2. poor

3. female

4. college student​

Answers

From the given options the best example of an ascribed status will be poor.  Hence, option 2 is the correct one.

What is ascribed status?

In sociology, the term "ascribed status" refers to a human's social standing as it is either allocated to them at birth or implicitly assumed in later life. The position of status is one that a person neither chooses for themselves nor earns. Instead, the position is decided upon in accordance with cultural and societal norms and standards. No matter how hard you try or how much you want to, these slots are filled. These fixed social designators are independent of the favorable or unfavorable stereotypes associated with one's assigned statuses and stay unchanged throughout a person's life.

Every society engages in the process of classifying people into categories based on factors including gender, race, family history, and ethnicity. This process is cross-cultural.

To know more about ascribed status:

https://brainly.com/question/9382045

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4. If the cooling of magma takes place slowly beneath Earth's surface, the rock is that is formed
is called
a. extrusive igneous rock
b. intrusive igneous rock
c. sedimentary rock
d. metamorphic rock

Answers

I agree with the answer above listen to them :)

(WILL MARK BRAINLIAST)( 1 answer question.. look the photo)

As the cars come closer together, the amount of potential energy in the system:


-Increases

-Decreases

-Stays the same

Answers

Answer:

increases

Explanation:

due to less speed

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