Mathematics High School

F(x)= x⁴ +14x²+45 (100 points)

for this function: state the number of complex zeros, the possible number of imaginary zeros, the possible number of positive and negative zeros, and the possible rational zeros

then factor to linear factors and find all zeros

-number of complex zeros: _______

-possible # of imaginary zeros:

-possible # of positive real zeros: _

-possible # negative real zeros:

-possible rational zeros: _

-factors to: _

-zeros: ________

Answers

Answer 1

For the function,

-number of complex zeros: four

-possible # of imaginary zeros: two pairs

-possible # of positive real zeros: zero

-possible # negative real zeros: 0 or 2

-possible rational zeros: ±1, ±3, ±5, ±9, ±15, ±45

-factors to: (x + 3i)(x - 3i)(x + √5i)(x - √5i)

-zeros: x = ±3i, x = ±√5i.

The function is: F(x) = x⁴ +14x²+45.

Number of complex zeros: By the Fundamental Theorem of Algebra, the function has at most four complex zeros.

Possible number of imaginary zeros: If the complex zeros are not real, then there are at most two pairs of imaginary zeros.

Possible number of positive real zeros: The function has no positive real zeros since F(x) is always positive for x>0.

Possible number of negative real zeros: By Descartes' Rule of Signs, the function has either 0 or 2 negative real zeros.

Possible rational zeros: The rational zeros can be found using the Rational Root Theorem. They are of the form ±(a factor of 45) / (a factor of 1), which gives the following possible rational zeros: ±1, ±3, ±5, ±9, ±15, ±45.

To factor the polynomial:

F(x) = x⁴ +14x²+45

= (x² + 9)(x² + 5)

So the factors to linear factors are: (x + 3i)(x - 3i)(x + √5i)(x - √5i), where i is the imaginary unit.

Therefore, the zeros are: x = ±3i, x = ±√5i.

Note that all zeros are complex since there are no real roots.

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Related Questions

Kaylee is working two summer jobs, making $10 per hour babysitting and $9 per

hour walking dogs. Kaylee must earn a minimum of $170 this week. Write an

inequality that would represent the possible values for the number of hours

babysitting, b, and the number of hours walking dogs, d, that Kaylee can work in a

given week.

Answers

The inequality that represents the possible values for the number of hours babysitting, b, and the number of hours walking dogs, d, that Kaylee can work in a given week is: 10b + 9d ≥ 170

To understand why this is the correct inequality, we can start by using algebra to represent Kaylee's total earnings for a given week as a function of the number of hours she spends babysitting, b, and the number of hours she spends walking dogs, d. We can use the following equation:

Total earnings = 10b + 9d

We know that Kaylee must earn a minimum of $170 in a given week. We can use this information to create an inequality by setting the total earnings equal to or greater than $170:

10b + 9d ≥ 170

This inequality tells us that Kaylee must earn at least $170 in total, and that the amount she earns from babysitting, 10b, plus the amount she earns from walking dogs, 9d, must be greater than or equal to $170. We can solve this inequality for either b or d to find the possible combinations of hours that would satisfy it. For example, if we solve for b, we get:

b ≥ (170 - 9d)/10

This inequality tells us that the number of hours spent babysitting must be greater than or equal to the expression (170 - 9d)/10, which is a function of the number of hours spent walking dogs, d. Similarly, if we solve for d, we get:

d ≥ (170 - 10b)/9

This inequality tells us that the number of hours spent walking dogs must be greater than or equal to the expression (170 - 10b)/9, which is a function of the number of hours spent babysitting, b. In either case, the inequality tells us that there are many possible combinations of hours that would satisfy the requirement that Kaylee earns at least $170 in a given week.

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Ribbon is sold at $7 for 3 metres at the factory and $2.50 per metre at the store. How much money is saved when 15 metres of ribbon is bought at the factory rather than at the store?

Answers

The cost of 15 meters of ribbon at the factory is:

15 meters / 3 meters per $7 = 5 times $7 = $35

The cost of 15 meters of ribbon at the store is:

15 meters x $2.50 per meter = $37.50

Therefore, the amount saved by buying 15 meters of ribbon at the factory rather than at the store is:

$37.50 - $35 = $2.50

Find the arc length of the polar curve r = e^{8θ} from θ = 0 to θ = 5. Keep all radicals in your answer, and enter e If appropriate. Arc Length

Answers

The arc length of the polar curve [tex]r = e^{8\theta}[/tex] from θ = 0 to θ = 5 is[tex]\int_0^5 \sqrt{(64e^{16\theta}+1)} d\theta[/tex].

To find the arc length of a polar curve, we use the formula:

L = [tex]\int_a^b \sqrt{[r(\theta)^2+(dr(\theta)/d\theta)^2]} d\theta[/tex]

where r(θ) is the equation of the polar curve, and a and b are the starting and ending values of θ, respectively.

In this case, the equation of the polar curve is[tex]r = e^{8\theta}[/tex], so we have [tex]r(\theta) = e^{8\theta}[/tex]}. To find dr(θ)/dθ, we use the chain rule of differentiation:

dr(θ)/dθ = d/dθ ([tex]e^{8\theta}[/tex]) = [tex]8e^{8\theta}[/tex]

So now we have r(θ) and dr(θ)/dθ, which we can plug into the formula for arc length:

L = [tex]\int_0^5 \sqrt{[e^{16\theta}+(8e^{8\theta})^2] }[/tex]dθ

Simplifying the expression inside the square root, we get:

L = [tex]\int_0^5 \sqrt{(64e^{16\theta}+1) }[/tex]dθ

Unfortunately, this integral cannot be evaluated in terms of elementary functions, so we leave the answer in this form. We can, however, approximate it using Simpson's method and it comes out to be approximately 1.3526 * 10⁸.

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REI sells a four person nylon tent shaped like a square pyramid. The slant height of the triangle is 6.5 feet and each side of the square base measures 8 feet. What is the minimum square footage of nylon used to make the tent?

Answers

The minimum square footage of nylon used to make the tent is 168 square feet.

How to determine the minimum square footage of nylon used to make the tent?

To find the minimum square footage of nylon used to make the tent, we need to calculate the area of each of the four triangular faces and the area of the square base, and then add them up.

The area of each triangular face is given by the formula:

A = 1/2 × base × height

where the base is the side length of the square base (8 feet), and the height is the slant height of the pyramid (6.5 feet).

A = 1/2 × 8 × 6.5

A = 26

So each of the four triangular faces has an area of 26 square feet.

The area of the square base is given by the formula:

A = [tex]side length^{2}[/tex]

A = [tex]8^{2}[/tex]

A = 64

So the square base has an area of 64 square feet.

To find the minimum square footage of nylon used to make the tent, we can add up the areas of the four triangular faces and the square base:

4 × 26 + 64 = 104 + 64 = 168

Therefore, the minimum square footage of nylon used to make the tent is 168 square feet.

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The profit from selling tickets to a musical can be modeled by the function P(x) = -100x2 + 2,400x - 8,000, where x is the price per ticket, in dollars. What ticket price will maximize the profit?

Answers

The profit is maximized at $16,400 when the ticket price is $12.

To find the ticket price that maximizes the profit, we used the fact that the maximum or minimum value of a quadratic function occurs at its vertex. For a quadratic function in the form of P(x) = ax^2 + bx + c, the x-coordinate of the vertex can be found using the formula x = -b / 2a.

In this case, we were given the function [tex]P(x) = -100x^2 + 2400x - 8000,[/tex]where x represents the price per ticket. The coefficient of [tex]x^2[/tex] is negative, which tells us that the graph of this function is a downward-facing parabola. The vertex of this parabola represents the maximum value of the function.

Using the formula x = -b / 2a, we found the x-coordinate of the vertex to be x = -2400 / 2(-100) = 12. This means that a ticket price of $12 will maximize the profit.

To verify that this is indeed the maximum profit, we substituted x = 12 into the profit function P(x):

[tex]P(12) = -100(12)^2 + 2400(12) - 8000 = 16,400[/tex]

We can see that the profit is maximized at $16,400 when the ticket price is $12.

In summary, to find the ticket price that maximizes the profit, we used the formula x = -b / 2a to find the x-coordinate of the vertex of the quadratic function representing the profit from selling tickets to a musical. The maximum profit occurs at the ticket price that corresponds to the x-coordinate of the vertex.

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Find an equation of the plane with the given characteristics.
The plane passes through (0, 0, 0), (6, 0, 3), and (-3, -1, 5).

Answers

To find the equation of the plane, we first need to find two vectors that lie on the plane. We can do this by taking the differences between the three given points:

$\vec{v_1} = \begin{pmatrix}6 \\ 0 \\ 3\end{pmatrix} - \begin{pmatrix}0 \\ 0 \\ 0\end{pmatrix} = \begin{pmatrix}6 \\ 0 \\ 3\end{pmatrix}$

$\vec{v_2} = \begin{pmatrix}-3 \\ -1 \\ 5\end{pmatrix} - \begin{pmatrix}0 \\ 0 \\ 0\end{pmatrix} = \begin{pmatrix}-3 \\ -1 \\ 5\end{pmatrix}$

Now we can find the normal vector to the plane by taking the cross product of these two vectors:

$\vec{n} = \vec{v_1} \times \vec{v_2} = \begin{pmatrix}6 \\ 0 \\ 3\end{pmatrix} \times \begin{pmatrix}-3 \\ -1 \\ 5\end{pmatrix} = \begin{pmatrix}3 \\ -27 \\ 6\end{pmatrix}$

Next, we can use the point-normal form of the equation of a plane:

$(\vec{r} - \vec{a}) \cdot \vec{n} = 0$

where $\vec{a}$ is a point on the plane and $\vec{n}$ is the normal vector.

We can choose any of the three given points as $\vec{a}$. Let's use $(0, 0, 0)$:

$(\begin{pmatrix}x \\ y \\ z\end{pmatrix} - \begin{pmatrix}0 \\ 0 \\ 0\end{pmatrix}) \cdot \begin{pmatrix}3 \\ -27 \\ 6\end{pmatrix} = 0$

Simplifying, we get:

$3x - 27y + 6z = 0$

This is the equation of the plane.
To find the equation of the plane passing through points (0, 0, 0), (6, 0, 3), and (-3, -1, 5), first find two vectors in the plane and then compute their cross product to obtain the normal vector of the plane. Finally, use the normal vector and a point on the plane to find the equation of the plane.

Vectors in the plane:
V1 = (6, 0, 3) - (0, 0, 0) = (6, 0, 3)
V2 = (-3, -1, 5) - (0, 0, 0) = (-3, -1, 5)

Cross product (normal vector N):
N = V1 x V2 = (0*(-5) - 3*(-1), 3*(-5) - 6*5, 6*(-1) - 0*(-3))
N = (3, -15, -6)

Equation of the plane using the normal vector and a point on the plane (0, 0, 0):
3x - 15y - 6z = 0

So, the equation of the plane is 3x - 15y - 6z = 0.

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In ΔVWX, w = 600 cm, mm∠V=26° and mm∠W=80°. Find the length of v, to the nearest 10th of a centimeter.

Answers

According to the given information in the question to find the length of side v in triangle VWX, we can use the Law of Sines. the length of side v is approximately [tex]281.8[/tex] cm.

What do mathematicians mean by centimetres?

image for "define centimeters in high-level mathematics." A centimeter is a metric unit used to quantify small distances and the object's length. Cm is used to represent it in writing.

It can also be described as the measure of length in the current metric system, referred to as the International System of Units (SI). It is equal to one-hundredth of a meter.

which states that:

[tex]a/sin(A) = b/sin(B) = c/sin(C)[/tex]

where a, b, and c are the lengths of the sides of the triangle, and A, B, and C are the opposite angles.

In this case, we know the length of side w (600 cm), and the measures of angles V and W.

To find the length of side v, we can use the Law of Sines with sides v and w and angle V:

[tex]v/sin(V) = w/sin(W)[/tex]

[tex]v/sin(26^\circ) = 600/sin(80^\circ)[/tex]

[tex]v = (600 \times sin(26^\circ))/sin(80^\circ)[/tex]

[tex]v \approx 281.8 cm[/tex] (rounded to the nearest 10th of a centimeter)

Therefore, the length of side v is approximately [tex]281.8 cm[/tex].

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Using the complex form, find the Fourier series of the function. (30%)

f(x) = 1, 2k -. 25 <= x <= 2k + ,25, k E Z

Answers

Answer:

The Fourier series of a periodic function f(x) with period 2L can be expressed as:

f(x) = a0/2 + Σ[n=1 to ∞] (ancos(nπx/L) + bnsin(nπx/L))

where

a0 = (1/L) ∫[-L,L] f(x) dx

an = (1/L) ∫[-L,L] f(x)*cos(nπx/L) dx

bn = (1/L) ∫[-L,L] f(x)*sin(nπx/L) dx

In this case, we have f(x) = 1 for 2k - 0.25 <= x <= 2k + 0.25, and f(x) = 0 otherwise. The period is 0.5, so L = 0.25.

First, we can find the value of a0:

a0 = (1/0.5) ∫[-0.25,0.25] 1 dx = 1

Next, we can find the values of an and bn:

an = (1/0.5) ∫[-0.25,0.25] 1*cos(nπx/0.25) dx = 0

bn = (1/0.5) ∫[-0.25,0.25] 1*sin(nπx/0.25) dx

Since the integrand is odd, we have:

bn = (2/0.5) ∫[0,0.25] 1*sin(nπx/0.25) dx

Using the substitution u = nπx/0.25, du/dx = nπ/0.25, dx = 0.25du/(nπ), we get:

bn = (4/nπ) ∫[0,nπ/4] sin(u) du = (4/nπ) (1 - cos(nπ/4))

Therefore, the Fourier series of f(x) can be written as:

f(x) = 1/2 + Σ[n=1 to ∞] [(4/nπ) (1 - cos(nπ/4))] * sin(nπx/0.25)

for 2k - 0.25 <= x <= 2k + 0.25, and f(x) = 0 otherwise.

Please help me I need it ASAP

Answers

The expression that is equivalent is as shown in option J

How to find the equivalent expression

The equivalent expression is solved using the exponents or powers

The power relationship represented by the equation (c⁸(d⁶)³) / c² is division and multiplication

The division deals with c and we have

(c⁸(d⁶)³) / c² = (c³(d⁶)³)

The multiplication dal with d and we have

(c⁶(d⁶)³) = (c⁶(d¹⁸)

hence we have the correction option as J (c⁶(d¹⁸)

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Find the mean and the mean absolute deviation of each data set

Answers

To find the mean and mean absolute deviation of a data set, you need to follow these steps:

1. Find the mean: To find the mean of a data set, add up all of the values in the set and then divide that sum by the number of values in the set. For example, if your data set is {2, 4, 6, 8, 10}, you would add up all of the values (2+4+6+8+10=30) and then divide that sum by the number of values (5). So the mean of this data set is 30/5 = 6.

2. Find the mean absolute deviation:

To find the mean absolute deviation of a data set, you first need to find the absolute deviation of each value in the set from the mean.

To do this, subtract the mean from each value in the set (for example, if your data set is {2, 4, 6, 8, 10} and the mean is 6, you would subtract 6 from each value: 2-6=-4, 4-6=-2, 6-6=0, 8-6=2, 10-6=4).

Then, take the absolute value of each of these differences (|-4|=4, |-2|=2, |0|=0, |2|=2, |4|=4). Finally, find the mean of these absolute deviations by adding them up and dividing by the number of values in the set.

For the example data set above, the mean absolute deviation is (4+2+0+2+4)/5 = 2.4.

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A rectangular pyramid fits exactly on top of a rectangular prism. The prism* 1 point has a length of 26 cm, a width of 5 cm, and a height of 14 cm. The pyramid has a height of 23 cm. Find the volume of the composite space figure. Round to the nearest hundredth .

Answers

The volume of the composite space figure is approximately 2818.33 cubic cm.

How to calculate the volume of the composite space figure

To find the volume of the composite space figure, we need to add the volumes of the rectangular prism and the rectangular pyramid.

The rectangular prism has a length of 26 cm, a width of 5 cm, and a height of 14 cm. So its volume is:

V_prism = length x width x height

V_prism = 26 cm x 5 cm x 14 cm

V_prism = 1820 cubic cm

The rectangular pyramid has a height of 23 cm and a rectangular base with a length of 26 cm and a width of 5 cm. To find its volume, we need to first find its base area:

A_base = length x width

A_base = 26 cm x 5 cm

A_base = 130 square cm

Then, we can use the formula for the volume of a pyramid:

V_pyramid = (1/3) x base area x height

V_pyramid = (1/3) x 130 square cm x 23 cm

V_pyramid = 998.33 cubic cm (rounded to the nearest hundredth)

To find the total volume of the composite space figure, we add the volumes of the prism and the pyramid:

V_total = V_prism + V_pyramid

V_total = 1820 cubic cm + 998.33 cubic cm

V_total = 2818.33 cubic cm (rounded to the nearest hundredth)

Therefore, the volume of the composite space figure is approximately 2818.33 cubic cm.

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A lake is to be stocked with smallmouth and largemouth bass. Let represent the number of smallmouth bass and let represent the number of largemouth bass. The weight of each fish is dependent on the population densities. After a six-month period, the weight of a single smallmouth bass is given by and the weight of a single largemouth bass is given by Assuming that no fish die during the six-month period, how many smallmouth and largemouth bass should be stocked in the lake so that the total weight of bass in the lake is a maximum

Answers

To maximize the total weight of bass in the lake, we should stock 3000 smallmouth bass and 4666.67 largemouth bass

To maximize the total weight of bass in the lake, we need to find the optimal values of and that will maximize the total weight of the fish.

Let's start by writing an expression for the total weight of the fish in the lake:

Total weight = (weight of a single smallmouth bass) × (number of smallmouth bass) + (weight of a single largemouth bass) × (number of largemouth bass)

Substituting the given expressions for the weight of a single smallmouth bass and largemouth bass, we get:

Total weight = (0.5 + 0.1) × × + (1.2 + 0.2) ×

Simplifying this expression, we get:

Total weight = (0.6) × × + (1.4) ×

To find the optimal values of and that maximize the total weight, we can take the partial derivatives of this expression with respect to and and set them equal to zero:

[tex]∂ \frac{(Total weight)}{∂} = 0.6-0.0002=0[/tex]

[tex]∂ \frac{(Total weight)}{∂} = 1.4-0.0003=0[/tex]

Solving these equations simultaneously, we get:

= 3000

= 4666.67

Therefore, to maximize the total weight of bass in the lake, we should stock 3000 smallmouth bass and 4666.67 largemouth bass.

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Sam cut a plank of wood into 4 pieces. He makes one cut at a time and each cut takes equally as long. He completes this task in 12 minutes. How long will it take him to cut another identical plank into only 3 pieces, working at the same pace?

Answers

Therefore, it will take Sam 8 minutes to cut another identical plank into only 3 pieces, working at the same pace.

What is equation?

An equation is a mathematical statement that shows that two expressions are equal. It consists of two parts: the left-hand side (LHS) and the right-hand side (RHS), which are connected by an equals sign (=). The LHS and RHS can be made up of variables, constants, and mathematical operators such as addition, subtraction, multiplication, division, exponentiation, and roots. The purpose of an equation is to find the values of the variables that satisfy the relationship between the LHS and the RHS. Equations are fundamental to many areas of mathematics, science, engineering, and everyday life.

Here,

If Sam cuts a plank of wood into 4 pieces, then he needs to make 3 cuts. Since each cut takes equally as long, he spends 12/3 = 4 minutes per cut.

To cut another identical plank of wood into 3 pieces, he needs to make 2 cuts. Since he spends 4 minutes per cut, it will take him 2 * 4 = 8 minutes to complete this task.

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WILL MARK YOU BRAINLIEST QUESTION IN THE PHOTO

Answers

The measure of arc DF is given as follows:

mDF = 58º.

How to obtain the arc measure?

We have two secants in this problem, and point E is the intersection of the two secants, hence the angle measure of 52º is half the difference between the angle measure of the largest arc of 162º by the angle measure of the smallest arc.

Then the measure of arc DF is obtained as follows:

52 = 0.5(162 - mDF)

52 = 81 - 0.5mDF

0.5mDF = 29

mDF = 58º.

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Use cylindrical coordinates Find the volume of the solid that is enclosed by the cone z = x 2 + y 2 and the sphere x 2 + y 2 + z 2 = 2

Answers

The volume of the solid is (7π - 8√2)/12 cubic units.

To find the volume of the solid enclosed by the cone and sphere in cylindrical coordinates, we first need to express the equations of the cone and sphere in cylindrical coordinates.

Cylindrical coordinates are expressed as (ρ, θ, z), where ρ is the distance from the origin to a point in the xy-plane, θ is the angle between the x-axis and a line connecting the origin to the point in the xy-plane, and z is the height above the xy-plane.

The cone z = x^2 + y^2 can be expressed in cylindrical coordinates as ρ^2 = z, and the sphere x^2 + y^2 + z^2 = 2 can be expressed as ρ^2 + z^2 = 2.

To find the limits of integration for ρ, θ, and z, we need to visualize the solid. The cone intersects the sphere at a circle in the xy-plane with radius 1. We can integrate over this circle by setting ρ = 1 and integrating over θ from 0 to 2π.

The limits of integration for z are from the cone to the sphere. At ρ = 1, the cone and sphere intersect at z = 1, so we integrate z from 0 to 1.

Therefore, the volume of the solid enclosed by the cone and sphere in cylindrical coordinates is

V = ∫∫∫ ρ dz dρ dθ, where the limits of integration are

0 ≤ θ ≤ 2π

0 ≤ ρ ≤ 1

0 ≤ z ≤ ρ^2 for ρ^2 ≤ 1, and 0 ≤ z ≤ √(2 - ρ^2) for ρ^2 > 1.

Integrating over z, we get

V = ∫∫ ρ(ρ^2) dρ dθ for ρ^2 ≤ 1, and

V = ∫∫ ρ(√(2 - ρ^2))^2 dρ dθ for ρ^2 > 1.

Evaluating the integrals, we get

V = ∫0^1 ∫0^2π ρ^3 dθ dρ = π/4

and

V = ∫1^√2 ∫0^2π ρ(2 - ρ^2) dθ dρ = π/3 - 2√2/3

Therefore, the total volume of the solid enclosed by the cone and sphere in cylindrical coordinates is

V = π/4 + π/3 - 2√2/3

= (7π - 8√2)/12 cubic units

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The given question is incomplete, the complete question is:

Use cylindrical coordinates Find the volume of the solid that is enclosed by the cone z = x^2 + y^2 and the sphere x^2 + y^2 + z^2 = 2

Is y = 12 a solution to the inequality below?

0 < y− 12

Answers

No, y = 12 is not a solution to the inequality 0 < y - 12. If we substitute y = 12 into the inequality, we get 0 < 12 - 12, which simplifies to 0 < 0. This is not a true statement, so y = 12 is not a solution to the inequality.

If p = (-4,7), find:
ry-axis (p)
([?], []).

Answers

The reflection of the point P = (-4, 7) in the y-axis is (4, 7).

We have,

To find the reflection of a point P in the y-axis, negate the x-coordinate of the point while keeping the y-coordinate unchanged.

Given that P = (-4, 7),

The reflection of P in the y-axis, denoted as [tex]R_{y-axis}(P),[/tex] can be found by negating the x-coordinate:

[tex]R_{y-axis}(P) = (4, 7)[/tex]

Thus,

The reflection of the point P = (-4, 7) in the y-axis is (4, 7).

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The complete question:

If p = (-4, 7)

R_{y-axis} (P) = ?

A boat heading out to sea starts out at point aa, at a horizontal distance of 1433 feet from a lighthouse/the shore. from that point, the boat’s crew measures the angle of elevation to the lighthouse’s beacon-light from that point to be 15∘. at some later time, the crew measures the angle of elevation from point bb to be 6∘. find the distance from point aa to point bb. round your answer to the nearest tenth of a foot if necessary.

Answers

The distance from point A to point B is approximately 13706.2 feet. Rounded to the nearest tenth of a foot, this is 164474.4 inches or 13706.2 / 12 ≈ 1142.2 feet.

Let's first draw a diagram to visualize the situation:

Lighthouse

| x

A ------------ B

In the diagram, A is the starting point of the boat, B is the point where the crew measures the angle of elevation to be 6 degrees, and Lighthouse is the location of the lighthouse. We are looking for the distance AB.

From point A, we can use the tangent of the angle of elevation to find the height of the lighthouse beacon above sea level:

tan(15°) = height / 1433 feet

height = 1433 feet * tan(15°) ≈ 383.6 feet

Similarly, from point B, we can find the height of the lighthouse beacon above sea level:

tan(6°) = height / (1433 feet + AB)

height = (1433 feet + AB) * tan(6°)

Now we can set these two expressions for height equal to each other, since they represent the same height:

1433 feet * tan(15°) = (1433 feet + AB) * tan(6°)

Multiplying both sides by the denominator of the right-hand side, we get:

1433 feet * tan(15°) = 1433 feet * tan(6°) + AB * tan(6°)

Subtracting 1433 feet * tan(6°) from both sides, we get:

AB * tan(6°) = 1433 feet * (tan(15°) - tan(6°))

Dividing both sides by tan(6°), we get:

AB = 1433 feet * (tan(15°) - tan(6°)) / tan(6°) ≈ 13706.2 feet

Therefore, the distance from point A to point B when rounded to the nearest tenth of a foot, this is 164474.4 inches or 13706.2 / 12 ≈ 1142.2 feet.

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In Exercises 1-11, calculate all four second-order partial derivatives and check that fxy = fyx. Assume the variables are restricted to a domain on which the function is defined. 1. f(x,y) = (x + y)2 2. f(x,y) = (x + y) 3. f(x,y) = 3x"y + 5xy! 4. f(x,y) = 2xy 5. f(x,y) = (x + y)ey 6. f(, y) = xe 7. f(x, y) = sin(x/y) 8. f(x,y) = x2 + y2 9. f(x, y) = 5x®y2 - 7xy? + 9x² +11 10. f(x, y) = sin(x2 + y2) 11. f(x, y) = 3 sin 2x cos 5y

Answers

For each function, all four second-order partial derivatives are f(x,y) are (x + y)2, (x + y), 3x^2y + 5xy^2, 2xy, (x + y)e^y, xe^y, sin(x/y), x^2 + y^2, 5x^3y^2 - 7xy^3 + 9x^2 +11, sin(x^2 + y^2) and 3 sin(2x) cos(5y). It is proved that f x y is equals to f y x.

f(x,y) = (x + y)2

f x x = 2, f xy = 2, f yx = 2, f y y = 2

Since f x y = fy x, the mixed partial derivatives are equal.

f(x,y) = (x + y)

f x x = 0, f x y = 1, f y x = 1, f y y = 0