From Khan Academy Pre Algebra

Please Evaluate This Question:

Answer:

x = 3

Step-by-step explanation:

8/2 = 4

6/2 = 3

x = 3

Answer:

20-2h

Step-by-step explanation:

20 is the original amount. The variable stands for the number of hours. You are TAKING AWAY 2 degrees every hour so you would subtract.

Answer:

No. greater than of equal to (-5) = -4,-3,-2,-1,0,1,2,3,4,5,6...........

No. less than 5 = 4,3,2,1 ,0,-1......

{ -4,-3,-2,-1,0,1,2,3,4}

Answer: (1,4) and (1,3) because the have the same x-value

Step-by-step explanation:

A function is defined so that for each input (known as the domain), there is no more than one output (known as the range).

Answer:

x = 9 or B

Step-by-step explanation:

Formula

(x + 2)^2 = 121                        

Comment

The easiest way to do this is to take the square root immediately, which is usually possible.

Solution

√(x + 2)^2 = √121                     Take the square root

x + 2 = 11                                   Subtract 2 from both sides

x + 2 -  2 = 11 - 2

x = 9

Answer: B) 9 inches by 9 inches

Step-by-step explanation:

Edg 2022

Answer:

x=12

Step-by-step explanation:

16x-30-(14x-6)=2x-24=0. add 24 on both sides to get 2x=24. divide by 2 on both sides to get x=12

The function that represents the Scooter Company's total profit is given by:

P(x) = -2x² + 250x - 2,000.

The profit function is calculated by the revenue function subtracted by the cost function, hence:

P(x) = R(x) - C(x).

In this problem, we have that:

Hence the profit function is:

P(x) = R(x) - C(x).

P(x) = 400x - 2x² - (150x + 2000).

P(x) = -2x² + 250x - 2,000.

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The complete question is attached below.

The most correct phases that imply correlation without causation are 1, 5, and 6.

The correlation of two pairs of data values tells about the degree of movement(along or opposite) that can occur in one of the data values when another data value is increased or decreased respectively.

The most correct phases imply correlation without causation are;

The number of stuffed animals produced at a factory and the number of newborn babies.

The number of videos rented and the number of films in the theater.

The number of pets in the neighborhood and the amount of grass nearby.

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Answer:

p = 4

Step-by-step explanation:

[tex]m =\frac{p}{2} +3r[/tex]

[tex]\Longrightarrow m-3r=\frac{p}{2}[/tex]

[tex]\Longrightarrow 2m-6r=p[/tex]

[tex]\Longrightarrow p = 2m-6r[/tex]

If m = 5 and r = 1

Then

p = 2(5) - 6(1)

  = 10 - 6

  = 4

Step-by-step explanation:

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Answer: A. She substituted incorrectly into the distance formula

She should be subtracting x from x and y from y but she is subtracting y from x.

The coordinate of C( a+c , b) ,  AC are ((a+c)/2 , b/2) , BD are ((a+c)/2 , b/2)

Coordinates is the value assigned to a point in a x-y graph to determine its location.

The coordinates of parallelogram is

A ( 0,0) B (a,0) , C ( __ , ___) , D ( c , b)

The y coordinate is same as D as b

and the x coordinate will be a+c

C( a+c , b)

The coordinate of the mid point of AC are ((a+c)/2 , b/2)

The coordinate of the mid point of BD are ((a+c)/2 , b/2)

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The equation for the red graph is f(x) = -x².

From the information given, g(x) = 4 - x².

The vertex of the point (0, 4) and (0, 0) for g(x) and f(x) respectively. The rule of the translation will be:

(x, y) = (x, y -4).

The equation of the function will be:

f(x) = g(x) - 4

f(x) = (4 - x²) - 4

f(x) = -x²

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The standard error will be equal to 0.75.

The standard deviation of a statistic's sample distribution, or an approximation of that standard deviation, is the statistic's standard error. The term "standard error of the mean" is used when referring to a statistic that is the sample mean.

The standard error will be calculated by using the formula:-

SE = [tex]\sigma[/tex] / √n

Here [tex]\sigma[/tex] is the standard deviation and n is the sample number.

SE = 6.5 / √75

SE = 0.75

Therefore the standard error will be equal to 0.75.

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The slope of line p is -5, so substitute into point-slope form, we get

[tex]\boxed{y-37=-5(x+2)}[/tex]

The true statements are (A), (B) and (D)

Data is information that has been translated into a form that is efficient for movement or processing.

As, from the given table we can see that

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Answer: C

Explanation:i got it right on my test

Answer:

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Step-by-step explanation:

i need it

Answer:

3^1 multiplied by 3^2 = 3^(1 + 2) = 3^3

162

Simplify ——————

(2•3^3)

Canceling out 2 as it appears on both sides of the fraction line

3^4 divided by 3^3 = 3^(4 - 3) = 3^1 = 3

Step-by-step explanation:

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Answer:

$809.25

Step-by-step explanation:

→ Find the sum of the sales amount

2400 + 3200 + 1900 + 800 = 8300

→ Find the amount that s commission

( 9.75 × 8300 ) ÷ 100 = $809.25

A one-to-one function has an inverse. The inverse is another function that undoes the action of the first one, so if we evaluate a function [tex]f[/tex] at some point [tex]x[/tex] to get the number [tex]f(x)[/tex], evaluating the inverse at [tex]f(x)[/tex] will recover the original input [tex]x[/tex]. In other words,

[tex]f^{-1}(f(x)) = x[/tex]

The process works in the opposite direction, too:

[tex]f\left(f^{-1}(x)\right) = x[/tex]

From the given definition of [tex]g[/tex], we have [tex]g(-4) = 3[/tex], so taking inverses on both sides, we find

[tex]g(-4) = 3 \implies g^{-1}(g(-4)) = g^{-1}(3) \implies \boxed{g^{-1}(3) = -4}[/tex]

Given [tex]h(x)=2x-13[/tex], evaluating [tex]h[/tex] at its inverse will recover [tex]x[/tex], so that

[tex]h\left(h^{-1}(x)\right) = x \implies 2h^{-1}(x) - 13 = x \implies \boxed{h^{-1}(x) = \dfrac{x+13}2}[/tex]

[tex](h\circ h^{-1})(x)[/tex] is another way of writing the compound function [tex]h\left(h^{-1}(x)\right)[/tex]. As already discussed, this reduces to [tex]x[/tex], so

[tex]\boxed{\left(h\circ h^{-1}\right)(-9) = -9}[/tex]

Answer: 49 in

Step-by-step explanation:

Step-by-step explanation:

To get the angle of QPR, we subtract 90-60=30. This proves that the triangle is a 30,60,90, as angle QRP must be 60°. To get the area, we must know the length and width. These can be derived from a known relationship within 30,60,90 triangles.

[tex]qp = \frac{\sqrt{3}}{2} n[/tex]

[tex]qr = \frac{1}{2} n[/tex]

[tex]pr = n[/tex]

because half of pr is 10, we can conclude that n is 20. So we plug 20 into N for QP and QR, and get values of

[tex]qp = 5 \sqrt{3} [/tex]

[tex]qr = 5[/tex]

Now we multiply (l*w)/2 and get:

[tex] \frac{(5 \sqrt{3} \times 5)}{2} = 21.65 \: units[/tex]

Answer:

C

Step-by-step explanation:

x = [tex]\frac{2}{3}[/tex] πr³ ( multiply both sides by 3 to clear the fraction )

3x = 2πr³ ( divide both sides by 2π )

[tex]\frac{3x}{2\pi }[/tex] = r³ ( take cube root of both sides )

[tex]\sqrt[3]{\frac{3x}{2\pi } }[/tex] = r

Answer:

[tex]r=\sqrt[3]{\frac{3x}{2\pi }}[/tex]

Step-by-step explanation:

This question make look scary, but don't judge its book by its cover.

[tex]x=\frac{2}{3} \pi r^{3} \\\frac{2}{3} \pi r^{3}=x\\r^{3} =x / \frac{2\pi }{3} \\r^{3} =x*\frac{3}{2\pi } \\r^{3} =\frac{3x}{2\pi } \\r=\sqrt[3]{\frac{3x}{2\pi }}[/tex]

Answer:

b and d

Step-by-step explanation:

there are two

but only one is an answer choice

b and d

the other which is not an answer choice is

a and c

gathmath

Bikash borrowed Rs150,000 from Anish at the rare 21% per year at the end of 9 month. How compound interest should he pay compound half yearly.

Answer:

[tex]\frac{4}{3}[/tex] or [tex]1\frac{1}{3}[/tex]

Step-by-step explanation:

[tex]1 + \frac{1}{3} \\= \frac{3}{3} + \frac{1}{1}\\= \frac{4}{3}[/tex]

(if the question is asking for the simplified form , it is [tex]1\frac{1}{3}[/tex]

Answer:

huh

Step-by-step explanation:

Answer:

[tex]27[/tex]

Step-by-step explanation:

[tex]g(f(0))=g(2(0)+3)=g(3)=3^3=27[/tex]

Answer:

[tex]\text{C.} \ \ \ {\left(\textit{AB}\right)}^{2} \ = \ \left(\textit{AC}\right)\left(\textit{AD}\right)[/tex]

Step-by-step explanation:

This problem uses the concept of the tangent-secant theorem which describes the relationship of the segments a secant line and a tangent line with the associated circle. This theorem is found as Proposition 36 in Book 3 of Euclid's Elements.

As shown in the figure attached below, segment AB (in blue) forms a tangent with the circle BCD and segment AD (in orange) is the secant where it intersects the circle at point C.

Furthermore, let two segments (in green) be drawn one from point C and point D.

To show that [tex]\triangle ABC[/tex] is similar to [tex]\triangle ADB[/tex], notice that both triangles share a common angle [tex]\angle BAC[/tex]. Additionally, by the alternate segment theorem, [tex]\angle ABC[/tex] is equal to [tex]\angle ADB[/tex]. Therefore, [tex]\angle ACB[/tex] is also equal to [tex]\angle ABD[/tex].

Hence, [tex]\triangle ABC[/tex] is indeed similar to [tex]\triangle ADB[/tex]. This implies the ratio of the sides of both triangles is the same. Particularly,

                                                  [tex]\displaystyle{\frac{AB}{AD} \ \ = \ \ \frac{AC}{AB}}[/tex].

Then, performing cross multiplication yields

                                             [tex]{\left(AB\right)}^{2} \ \ = \ \ \left(AC\right)\left(AD\right)[/tex].

Therefore, the product of the lengths of the secant segment and its external segment is equal to the square of the length of the tangent segment.