Frank wants to find the area enclosed by the figure at the right the figure on each side has semicircles of a 40 meter by 40 meter square. Find the area by the figure use 3. 14 for pi

To use the Comparison Test, we need to find a series that we know is either always greater than or always less than our given series

. Since cosine values oscillate between -1 and 1, we know that 2 + cos(n) is always greater than or equal to 1. Therefore, we can compare our given series to the series 1/n, which we know is a p-series with p = 1 and is divergent.

Using the Comparison Test, we can say that since 1/n is divergent and 1/n ≤ 2 + cos(n) for all n ≥ 71.1, then the series 2 + cos(n) n 71.1 must also be divergent. Therefore, the series 2 + cos(n) n 71.1 is divergent.
Hi! To determine whether the series Σ(2 + cos(n)), where n ranges from 1 to infinity, is convergent or divergent using the Comparison Test, we need to compare it with another series whose convergence behavior is known.

Consider the series Σ(2), which is a constant series where every term is 2. This series diverges, as its partial sums keep increasing without bound. Since cos(n) is bounded between -1 and 1, we know that for every n, 1 ≤ (2 + cos(n)) ≤ 3.

Now, using the Comparison Test, we can compare Σ(2 + cos(n)) with Σ(2). Since Σ(2) is divergent and 2 + cos(n) is always greater than or equal to 2, we can conclude that the series Σ(2 + cos(n)) is also divergent.

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Answer: m*n

Step-by-step explanation:

Answer:

The sum of all numbers divisible by 6 between 100 and 400 is 12450.

Step-by-step explanation:

I think this is correct.

If it isn't, I'm sorry.

The value of integral of (198r² + 9r – 50 dr  is  (16/27)ln|11r + 2| - (2/3)ln|9r - 4| + C

Now, we can write the integrand as a sum of two fractions:

(198r² + 9r - 50) / (11r + 2)(9r - 4) = A/(11r + 2) + B/(9r - 4)

To find A and B, we need to solve for them using the method of equating coefficients:

198r² + 9r - 50 = A(9r - 4) + B(11r + 2)

Setting r = 4/9 and r = -2/11, we get two equations:

198(4/9)² + 9(4/9) - 50 = A(9(4/9) - 4) + B(11(4/9) + 2)

198(-2/11)² + 9(-2/11) - 50 = A(9(-2/11) - 4) + B(11(-2/11) + 2)

Solving these equations gives A = 16/27 and B = -2/3.

So, the integral can be written as:

∫(198r² + 9r - 50) / (11r + 2)(9r - 4) dr = ∫16/27(11r + 2)^-1 dr - ∫2/3(9r - 4)^-1 dr

Integrating each term gives:

(16/27)ln|11r + 2| - (2/3)ln|9r - 4| + C

where C is the constant of integration.

In summary, using partial fraction decomposition, we can express the given integral as a sum of two simpler integrals, which can be evaluated using the natural logarithm function.

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Answer:

In an isosceles right triangle, the length of the diagonal is √2 times the length of a leg.

c = 6√2 in. = 8.5 in.

An equation that express each relationship for the joint variation is X = kyz. Solving for y will give the equation y = X/(kz)

Joint variation is a mathematical concept that describes the relationship between two or more variables. 

If X varies jointly as y and z, we can express this relationship mathematically using the formula:

X = k × y × z

X = kyz

where k is a constant of proportionality.

We can solve for y by dividing both sides by kz follows:

X/kz = kyz/kz

X/(kz) = y

Therefore, the equation that express each relationship for the joint variation is X = kyz. And the equation solved for y is y = X/(kz).

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So the area of the rectangle (or lane) whose length is 19 feet and whose width is the free throw line, together with the two circles at each end of the court that surround the free throw line, is approximately 450.39 square feet.

Since the circle at each end of the court that surrounds the free throw line is the same size as the jump ball circle, they both have the same radius. Let's call this radius "r".

The diameter of the circle is equal to the width of the lane, which is the same as the width of the free throw line. Therefore, the diameter of the circle is also 12 feet (the width of the free throw line is always 12 feet).

We know that the area of a circle is given by the formula A = πr^2, so the area of each circle is πr^2.

The rectangle (or lane) has a length of 19 feet and a width of 12 feet. Therefore, its area is simply the product of its length and width, which is:

A = 19 feet * 12 feet

A = 228 square feet

Since there are two circles, the total area of the circles is 2πr^2.

We know that the diameter of the circle is equal to the width of the lane, which is 12 feet. Therefore, the radius is half of the diameter, or:

r = 12 feet / 2

r = 6 feet

Now we can calculate the area of the circles:

A = 2πr^2

A = 2π(6 feet)^2

A = 72π square feet

Therefore, the total area of the rectangle and circles (or lane and circles) is:

A_total = A_rectangle + A_circles

A_total = 228 square feet + 72π square feet

A_total ≈ 450.39 square feet

So the area of the rectangle (or lane) whose length is 19 feet and whose width is the free throw line, together with the two circles at each end of the court that surround the free throw line, is approximately 450.39 square feet.

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The house is currently 6 years old.

It is mentioned that when the mortgage is completely paid off for Mark and Lynne's house, it will be 3 times as old as it is now. They have 12 years left on the mortgage.

Let's denote the current age of the house as x. When the mortgage is paid off, the house will be x + 12 years old (since they have 12 years left on the mortgage). At that point, the house will be 3 times its current age, so we can write the equation:

x + 12 = 3x

Now we can solve for x:
12 = 2x
x = 6

So, the house is currently 6 years old.

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The biologist predicts that the population would be fewer than 50 in approximately 30 years from the initial count.

The biologist likely used the exponential decay function to model the coyote population over time. This function takes the form:

P(t) = P0 * (1 - r)^t

Where:
P(t) is the population at time t,
P0 is the initial population (100 coyotes),
r is the rate of decrease (0.045 or 4.5%),
t is the time in years.

To predict when the population would be fewer than 50, the biologist would solve the equation:

50 = 100 * (1 - 0.045)^t

t = 30

This equation can be used to find the value of t, which represents the number of years it takes for the population to decrease to fewer than 50 coyotes in the tri-county area, which is 30 years.

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Answer:

[tex]\overset{\frown}{BX}=\angle BCX=2\angle BNX[/tex]

Step-by-step explanation:

A chord is a straight line joining two points on the circle.

Therefore, the chords in the given diagram are BN and XN.

An inscribed angle is the angle formed (vertex) when two chords meet at one point on a circle.

Therefore, the inscribed angle in the given diagram is BNX.

An intercepted arc is the arc that is between the endpoints of the chords that form the inscribed angle.

Therefore, the intercepted arc in the given diagram is BX.

The radius is a straight line joining the center to a point on the circle.

Therefore, the radii in the given diagram are CB and CX.

The central angle of a circle is the angle formed at its center by two radii.

Therefore, the central angle in the given diagram is BCX.

[tex]\hrulefill[/tex]

The measure of the central angle of a circle is equal to the measure of the corresponding intercepted arc. Therefore:

    [tex]\angle BCX=\overset{\frown}{BX}[/tex]

According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of the intercepted arc. Therefore:

    [tex]\angle BNX=\dfrac{1}{2}\overset{\frown}{BX}[/tex]

So the relationship between the arc BX, the central angle BCX and the inscribed angle BNX is that both the arc and central angle are equal to twice the inscribed angle:

[tex]\overset{\frown}{BX}=\angle BCX=2\angle BNX[/tex]

Dilating the figure by a scale factor of 3, the new coordinates are:

A' (-3, 12)

B' (9, 6)

C' (5886, -6)

D (unknown)

To dilate a figure by a scale factor, we need to multiply the coordinates of each point by the scale factor. Given the scale factor K = 3, we can dilate the figure using the formula:

New x-coordinate = K * original x-coordinate

New y-coordinate = K * original y-coordinate

Let's apply this to the given coordinates:

(-1, 4)

New x-coordinate = 3 * (-1) = -3

New y-coordinate = 3 * 4 = 12

A' (-3, 12)

(3, 2)

New x-coordinate = 3 * 3 = 9

New y-coordinate = 3 * 2 = 6

B' (9, 6)

(1962, -2)

New x-coordinate = 3 * 1962 = 5886

New y-coordinate = 3 * (-2) = -6

C' (5886, -6)

Dilating the figure by a scale factor of 3, the new coordinates are:

A' (-3, 12)

B' (9, 6)

C' (5886, -6)

D (unknown)

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Answer:

AEC is similar to BDC in terms of the type of triangle

That's all I can really say

I hope this helps :)

Answer: x = -3

Step-by-step explanation:

Hope this helps.

An author can show indirect characterization through a character's thoughts, feelings, actions, and the setting of the story, as well as through their effect on others and their role in the rising action of the plot.

All of these elements can provide insights into a character's personality, motivations, and values, without the author explicitly stating them.

By carefully observing the character's interactions with others, their reactions to events, and the situations in which they find themselves, readers can draw conclusions about who the character is and what drives them.

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The associations rhat are shown by the graph are

A graph depicting a negative linear association appears as points on the chart are concomitantly placed around a straight line that confidently descends from left to right. In simpler terms, there is a notable inverse correlation between the x and y variables, which can be best comprehended with the help of an illustration.

For instance, if one were to consider a dataset representing the age of an automobile (x) and its fuel efficiency in miles per gallon (y), a graph displaying a rigorous negative linear association implies that with an increase in the age of the car, its energy proficiency has an inclination to decrease.

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Answer:

First, we need to calculate the control limits for the X-chart. Since the sample size is 4, the standard deviation of the sample mean is:

σ/√n = 2/√4 = 1

The 3σ control limits for the X-chart are:

Upper Control Limit (UCL) = 8 + 3(1) = 11

Lower Control Limit (LCL) = 8 - 3(1) = 5

Next, we need to find the probability that a point falls outside the control limits when the process mean shifts to 9. This can be calculated using the Gaussian distribution:

P(X < 5 or X > 11) = P(Z < (5-9)/2) + P(Z > (11-9)/2) = 0.00135 + 0.00135 = 0.0027

where Z is the standard normal distribution.

Therefore, the average run length (ARL) is:

ARL = 1/p = 1/0.0027 = 370.37

So on average, it will take 370.37 samples before the process mean shift is detected on an X-chart.

The answer is (d) a convenience sample.

This is because the sample is not randomly selected from the population of all students at Ross College. Instead, it relies on individuals who are willing and available to respond to the question through the methods provided by the newspaper.

Therefore, the sample is more likely to be composed of individuals who feel strongly about the issue of student parking or who have had particularly positive or negative experiences with it, rather than being representative of the entire population of Ross College students.

In conclusion, the Ross Times student newspaper's feature column asking for opinions on the provision of student parking at Ross College represents a convenience sample of responses, and may not be representative of the entire population of Ross College students.

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To test whether shoes cost less on average at Payless than at Famous Footwear, we can conduct a two-sample t-test for the difference in means.

The null hypothesis is that there is no difference in the mean prices between the two stores, and the alternative hypothesis is that the mean price at Payless is less than the mean price at Famous Footwear.

We can calculate the t-statistic using the formula:

t = [tex](x1 - x2 - 0) / sqrt(s1^2/n1 + s2^2/n2)[/tex]

where x1 and x2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.

Substituting the values given in the table, we get:

t =[tex](21.39 - 45.66 - 0) / sqrt((7.47^2/30) + (16.54^2/30))[/tex] = -10.78

The degrees of freedom for this test is (30-1) + (30-1) = 58.

Using a t-table or calculator, we find the p-value to be very small, much less than 0.05.

Therefore, we reject the null hypothesis and conclude that there is convincing evidence at the 0.05 significance level that shoes cost less on average at Payless than at Famous Footwear.

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The correct answer is option B, a reflection over the y-axis followed by a translation of (1,y) → (1, y-6).

To solve this problem, we need to find the sequence of rigid motions (i.e., transformations that preserve distance and angle) that maps quadrilateral ABCD to quadrilateral EFGH.

First, we need to identify the corresponding vertices of the two quadrilaterals. Let's assume that vertex A maps to vertex E, vertex B maps to vertex F, vertex C maps to vertex G, and vertex D maps to vertex H.

Now, we can apply different transformations to map each vertex of quadrilateral ABCD to the corresponding vertex of quadrilateral EFGH. We can try each option provided and check if it maps all the vertices correctly.

Option A involves a reflection over the x-axis, followed by a translation of (0,y) → (0, y - 4). This transformation does not map vertex A to vertex E correctly.

Option B involves a reflection over the y-axis, followed by a translation of (1,y) → (1, y - 6). This transformation maps vertex A to vertex E, vertex B to vertex F, vertex C to vertex G, and vertex D to vertex H, which is the correct mapping.

Option C involves a translation of (+,y) → (2, y - 3) followed by a reflection over the y-axis. This transformation does not map vertex A to vertex E correctly.

Option D involves a translation of (1-6, y) followed by a reflection over the x-axis. This transformation does not map vertex A to vertex E correctly.

Therefore, the unique sequence of rigid motions that maps quadrilateral ABCD to quadrilateral EFGH is a reflection over the y-axis followed by a translation of (1,y) → (1, y-6), which is option B.

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Step-by-step explanation:

18 m = hypotenuse = c

5 m = b

a² + b² = c²

a² + (5)² = (18)²

a² + 25 = 324

a² = 324 - 25

a² = 299

a = √299

a = 17.29 or 17.3 m

perimeter = a + b + c

= 17.3 + 18 + 5

= 40.3 m

The equation of the function h(x) from the transformation is h(x) = f(x + 1)

From the question, we have the following parameters that can be used in our computation:

The functions f(x), g(x) and h(x)

In the graph, we can see that

Horizontal Shift = 1 unit left

This is represented as

h(x) = f(x + 1)

This means that the transformation of f(x) to h(x) is f(x) is shifted left 1 unit to h(x).

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The total length of the ramp is 222.18 inches

Let's denote the length of the incline and decline pieces by x, and use the given information to form an equation in terms of x:

Length of incline + length of decline = 2(13√37) inches

= 26√37 inches

The total length of the ramp is the sum of the lengths of all three sections:

Total length = Length of incline + Length of center + Length of decline

Total length = 26√37 inches + 10√41  inches

Total length = 222.18 inches

Therefore, the total length of the ramp is 222.18 inches

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We know that after 36 months, Martin will have to pay Richard P193,969.

Hi! Based on your question, Richard lends P154,600 to Martin at an 8.5% simple interest rate per annum, and the debt is payable after 36 months. To find out how much Martin will have to pay Richard after 36 months, we'll first calculate the interest.

Simple Interest = Principal × Rate × Time
Interest = P154,600 × 8.5% × (36 months / 12 months per year)
Interest = P154,600 × 0.085 × 3
Interest = P39,369

Now, add the interest to the principal to find the total amount Martin needs to pay Richard:
Total Amount = Principal + Interest
Total Amount = P154,600 + P39,369
Total Amount = P193,969

After 36 months, Martin will have to pay Richard P193,969.

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The absolute maximum value of f(x) on the interval [-2,3] is 201 and occurs at x = -2, and the absolute minimum value of f(x) on the interval [-2,3] is -79 and occurs at x = 2.

To find the absolute maximum and absolute minimum values of f(x) on the interval [-2,3], we need to first find the critical points of the function and evaluate the function at these points as well as at the endpoints of the interval.

To find the critical points, we need to find where the derivative of the function equals zero or does not exist. Taking the derivative of f(x), we get:

f'(x) = 12x^3 - 12x^2 - 24x

Setting this equal to zero and factoring out 12x, we get:

12x(x^2 - x - 2) = 0

Using the quadratic formula to solve for x^2 - x - 2 = 0, we get:

x = -1, 0, 2

These are our critical points.

Now we evaluate f(x) at the critical points and the endpoints of the interval:

f(-2) = 201
f(-1) = 6
f(0) = 1
f(2) = -79
f(3) = 16

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Answer:3

Step-by-step explanation: We see that 217361.05 =217000+361.05 so our answer is 3

Answer:

x = 7 is not a function--it is a vertical line.

The equation for the line that passes through the point ( 3,-1/2) and is perpendicular to the line y =-2x+3 is:

y = (1/2)*x - 2

Remember that two linear equations are perpendicular if the product between the slopes is -1, here we want a line perpendicular to:

y =-2x+3

Then if the slope of our line is a, we must have that:

a*-2 = -1

a = 1/2

Then our line is something like:

y = (1/2)x + b

Now we also want our line to pass through (3, -1/2), then:

-1/2 = (1/2)*3 + b

-1/2 = 3/2 + b

-1/2 - 3/2 = b

-2 = b

The linear equation is:

y = (1/2)*x - 2

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Rate of change in the temperature of lasagna given by function T(t) = 70 + (200 - 70) × [tex]e^{(-0.0001t)}[/tex] exactly 2 hours after taking it out of oven is -0.013 °F/hour.

Surrounding room temperature is equal to 70°F

Temperature at which lasagna comes out of the oven = 200°F

The temperature T (in °F) of the lasagna at time t (in hours) after taking it out of the oven is equal to,

T(t) = 70 + (200 - 70) × [tex]e^{(-0.0001t)}[/tex]

To find the rate of change in the temperature of the lasagna exactly 2 hours after taking it out of the oven,

Find the derivative of the temperature function with respect to time t.

T'(t) = -0.013[tex]e^{(-0.0001t)}[/tex]

Substituting t = 2 into this expression gives:

T'(2) = -0.013[tex]e^{(-0.0001\times 2)}[/tex]

= -0.013[tex]e^{-0.0002}[/tex]

= -0.013 × 0.99980

= -0.0129974

= -0.013

Therefore, the rate of change in the temperature of the lasagna exactly 2 hours after taking it out of the oven is approximately -0.013 °F/hour.

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The given question is incomplete, I answer the question in general according to my knowledge:

A tray of lasagna comes out of the oven at 200°F and is placed on a table where the surrounding room temperature is 70°F. The temperature T (in °F) of the lasagna is given by the function T(t) = 70 + (200 - 70) × [tex]e^{(-0.0001t)}[/tex] where t is time(in hours) after taking the lasagna out of the oven. What is the rate of change in the temperature of the lasagna exactly 2 hours after taking it out of the oven?

Note that the point ( 1 , 92 ) (1,92) represents the estimated number of people in the hall at 7pm.

This is based on the given graph.

Note tha the horizontal axis  = x = 0

which corresponds to 6pm

the vertical is the number of scanned tickets.

Also, the pont (1, 92) is the line of best fit so that means that at 7pm which is a n hour after 6pm, there were about 92 persons still in the hall.

Hence we are correct to state that  the point ( 1 , 92 ) (1,92) represents the estimated number of people in the hall at 7pm.

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Full Question:
See attached image/graph