For the triangle it is given that AE2 + EB2 = 9 and BE2 + EC2 = 16
Find AC =

Answers

Answer 1

Answer:

Step-by-step explanation:Given :  right triangle ABC  ,  AE^2 + EB^2 =9 and BE^2 + EC^2 = 16

To find : AC

Solution:

BE ⊥  AC

∠AEB = 90°

=> ΔAEB is right angled

=> AB² = AE² + EB²

=> AB² =  9

∠BEC = 90°

=> ΔBEC is right angled

=> BC² = BE² + EC²

=> BC² =  16

∠ABC = 90°

=> AC² = AB² + BC²

=> AC² = 9 + 16

=> AC² = 25

=> AC = 5

AC = 5

Answer 2

The length of AC is 5 units.

What is a Triangle?

Any three-sided polygon having three edges and three vertices is referred to as a triangle in geometry. The most important attribute of a triangle is that its internal angles sum to 180 degrees. The triangle's angle sum attribute is what is known as.

As per the given data:

We are given the diagram of ΔABC which is right-angled.

BE is perpendicular to AC.

AE² + EB² = 9 ...(i)

BE² + EC² = 16 ..(ii)

By using the Pythagoras theorem in ΔABE:

AE² + EB² = AB²

From comparing with eq (i)

AB² = 9

AB = √9 = 3 units

By using the Pythagoras theorem in ΔCBE:

BE² + EC² = BC²

From comparing with eq (ii)

BC² = 16

BC = √16 = 4 units

By using the Pythagoras theorem in ΔABC:

AB² + BC² = AC²

AC² = 3² + 4²

AC² = 9 + 16 = 25

AC = 5 units.

The length of AC is 5 units.

Hence, The length of AC is 5 units.

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For The Triangle It Is Given That AE2 + EB2 = 9 And BE2 + EC2 = 16 Find AC =

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