Answer:
1,839.375 Joules
Explanation:
Work is said to be done is the force applied to an object cause the object to move through a distance.
Workdone = Force * Distance
Workdone = mass * acceleration due to gravity * distance
Given
Mass = 75.0kg
acceleration due to gravity = 9.81m/s²
distance = 2.50m
Substitute the given parameters into the formula:
Workdone = 75.0*9.81*2.50
Workdone = 1,839.375Joules
Hence the workdone is 1,839.375 Joules
for an emitted wavelength of 500 nanometers and a redshift of 0.4 what will be the observed wavelength g
Answer:
The observed wavelength is [tex] \lambda = 700nm[/tex] (color - Red)
Explanation:
From the question we are told that
The wavelength of the emitter is [tex]\lambda_ e = 500 nm = 500 *10^{-9} \ m[/tex]
The redshift is R = 0.4
Generally red shift is mathematically represented as
[tex]R = \frac{ \lambda - \lambda_e }{\lambda_e}[/tex]
=> [tex]0.4 = \frac{ \lambda - 500 *10^{-9} }{500 *10^{-9} }[/tex]
=> [tex] \lambda - 500*10^{-9} = 200*10^{-9} [/tex]
=> [tex] \lambda = 700 *10^{-9}[/tex]
=> [tex] \lambda = 700nm[/tex]
The emf of the battery is 1.5 V. In Nichrome there are 9 × 1028 mobile electrons per m3, and the mobility of mobile electrons is 7 × 10−5 (m/s)/(N/C). Each thick wire has length 29 cm = 0.29 m and cross-sectional area 9 × 10−8 m2. The thin wire has length 6 cm = 0.06 m and cross-sectional area 1.3 × 10−8 m2. (The total length of the three wires is 64 cm.) In the steady state, calculate the number of electrons entering the thin wire every second. Do not make any approximations, and do not use Ohm's law or series-resistance equations.
Answer:
The number of electrons entering the thin wire every second is 1.75 x 10⁻³ mobile electrons / second
Explanation:
Given;
emf of the battery, V = 1.5 V
electron density, = 9 × 10²⁸ mobile electrons per m³
mobility of electron, u = 7 × 10⁻⁵ (m/s)/(N/C)
length of thin wire, L = 6 cm = 0.06 m
cross sectional area of the thin wire, A = 1.3 x 10⁻⁸ m²
The magnitude of the electric field in the thin wire is given by;
E = V/L
E = (1.5) / (0.06)
E = 25 N/C
the number of electrons entering the thin wire every second is given by;
[tex]e/s = mobility \ x \ Electric \ field\\\\number \ of \ electrons \ per \ second =\frac{7*10^{-5} (m/s)}{N/C} *25 (N/C)\\\\number \ of \ electrons \ per \ second = 1.75*10^{-3} \ m/s[/tex]
Therefore, the number of electrons entering the thin wire every second is 1.75 x 10⁻³ mobile electrons / second
The number of electrons entering the thin wire every second is 1.75 x 10⁻³ mobile electrons / second
Calculation of the number of electrons:Since
emf of the battery, V = 1.5 V
electron density, = 9 × 10²⁸ mobile electrons per m³
mobility of electron, u = 7 × 10⁻⁵ (m/s)/(N/C)
length of thin wire, L = 6 cm = 0.06 m
cross sectional area of the thin wire, A = 1.3 x 10⁻⁸ m²
So here the magnitude should be
E = V/L
E = (1.5) / (0.06)
E = 25 N/C
Now the number of electrons should be
= 7 × 10⁻⁵ *25
= 1.75 x 10⁻³ mobile
hence, The number of electrons entering the thin wire every second is 1.75 x 10⁻³ mobile electrons / second
Learn more about electron here: https://brainly.com/question/24701476
Find the distance along an arc on the surface of the earth that subtends a central angle of 1 minutes (1 minute = 1/60 degree). The radius of the earth is 3960 miles. Round to the thousandths. (3 decimal places)
Answer:
1.152 miles
Explanation:
Given: central angle = 1 minute = [tex](\frac{1}{60}) ^{o}[/tex]
radius of the earth = 3960 miles
The length of an arc = [tex]\frac{\alpha }{360^{o} }[/tex] 2[tex]\pi[/tex]r
where: [tex]\alpha[/tex] is the central angle, and r is the radius.
Thus,
Distance along the arc = [tex]\frac{\alpha }{360^{o} }[/tex] 2[tex]\pi[/tex]r
Distance along the arc = [tex]\frac{(\frac{1}{60}) ^{o} }{360^{o} }[/tex] x 2 x [tex]\frac{22}{7}[/tex] x 3960
= [tex]\frac{(\frac{1}{60}) ^{o} }{360^{o} }[/tex] x 24891.4286
= 1.1524
The required distance along an arc is 1.152 miles.
A small box with mass 0.600 kg is placed against a compressed spring at the bottom of an incline that slopes upward at 37.0∘ above the horizontal. The other end of the spring is attached to a wall. The coefficient of kinetic friction between the box and the surface of the incline is μk=0.400. The spring is released and the box travels up the incline, leaving the spring behind.
What minimum elastic potential energy must be stored initially in the spring if the box is to travel 2.00 m from its initial position to the top of the incline?
Answer:
[tex]10.845\ \text{J}[/tex]
Explanation:
m = Mass of box = 0.6 kg
[tex]\theta[/tex] = Angle of incline = [tex]37^{\circ}[/tex]
[tex]\mu_k[/tex] = Coefficient of kinetic friction = 0.4
l = Distance the box travels = 2 m
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
The potential energy in the spring is given by
[tex]U=mgl\sin\theta+mg\mu_k\cos\theta l\\\Rightarrow U=mgl(\sin\theta+\mu_k\cos\theta)\\\Rightarrow U=0.6\times 9.81\times 2\times(\sin37^{\circ}+0.4\times\cos37^{\circ})\\\Rightarrow U=10.845\ \text{J}[/tex]
The minimum elastic potential energy required is [tex]10.845\ \text{J}[/tex].
The latent heat of fusion of mercury is 11.8 J/g. The amount of energy, rounded to the nearest tenth, needed to change 8.00 grams of mercury to a liquid is
Answer:
94.4
Explanation:
it is
Answer:
94.4 i took the test and got it right :)
hope that helps
A velocity selector uses a fixed electric field of magnitude E and the magnetic field is varied to select particles of various energies. If the electric field strength is 2.2 x 104 N/C, what should be the value of the magnetic field (in tesla) to select protons of velocity 6.4 x 105 m/s
Answer:
The value is [tex]B = 0.034 \ T [/tex]
Explanation:
From the question we are told that
The electric field strength is [tex]E = 2.2*10^{4} \ N/C[/tex]
The velocity is [tex]v = 6.4 *10^{5} \ m/s[/tex]
Generally the magnetic field is mathematically represented as
[tex]B = \frac{E}{v}[/tex]
=> [tex]B = \frac{2.2*10^{4}}{6.4 *10^{5}}[/tex]
=> [tex]B = 0.034 \ T [/tex]
The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determin
how the cars perform based on which scenario?
on racetracks
Answer:
The options are
A.on racetracks
B.in real-world conditions
C.in flooded environments
D.on closed courses
The answer is B. In real world conditions
The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determin
how the cars perform based on real world conditions.
This will ensure they encounter the real and first hand experiences about the challenges and also the advantages associated with using this type of fuel.
Which property of a substance can be determined using a pH indicator.
Answer:
Acidity
Explanation:
A pH indicator measures how acidic or basic a substance is.
Hope this helped :)
Suppose you are given two clay balls of equal size and shape. The two clay balls also weigh the same. One ball is flattened into a pancake-shaped piece. Which of these statements is correct and why?
a. In one short sentence, explain why we call the force of gravity an attractive force.
b. Does a force of gravity exist between any two objects
Answer:
Explanation:
(a) The force of gravity is called an attractive force because it is the force (although weak) in which a planetary body or matter uses to attract an object towards itself.
(b) Yes, it does and the formula for force of gravity between any two object is
F = G[tex]\frac{m1m2}{r}[/tex]
where m1 and m2 are masses of the first and second object respectively
r is the distance between the center of the two masses
G is the gravitational constant
What determines the path that an object in projectile motion follows? (Ignore air resistance)
gravity only
inertia only
gravity and inertia
neither gravity or inertia
Answer:
C
gravity and inertia
Explanation:
Answer:
c :)
Explanation:
Which of the following processes results in the greatest gain in kinetic energy?
A. freezing
B. condensation
C. evaporation
D. sublimation
Thanks for asking your question!
Answer:
D: Sublimation
Explanation:
Sublimation occurs when a substance changes from a solid into a gas. Increases in temperature causes the kinetic energy of particles to also increase. This allows the particles to overcome the intermolecular forces and become mobile. Low pressure also increases the particles' kinetic energy.
What happens to the energy in a closed system?
Answer:
can exchange energy with its surroundings through heat and work transfer. In other words, work and heat are the forms that energy can be transferred across the system boundary.
Sally is on a large sailboat that comes to a stop a small distance from the dock. Since it is such a small distance, Sally decides to jump to the dock. She makes the jump, but the large sailboat moves away from her as she jumps. Since Sally is interested to see what happens on other boats, she makes the same jump from a rowboat that is much smaller than the large sailboat. Which boat will move away from Sally more slowly
Answer:
The rowboat will move away from sally more quickly because the rowboat because the sailboat is larger in mass
Explanation:
Gnerally the row boat will move away from her quicker than the sailboat this is because the mass of the sail boat is larger than the row boat , hence the frictional force that opposes motion will be greater in the sailboat than in the row boat.
Briefly explain why arterial injuries are more dangerous than damage to veins
or capillaries. Explanation should address structure and function of the
blood vessels.
IF YOU SEE THIS PLZ ANSWER RN
Answer:
Injury to a vein increases the risk of forming a blood clot.
Explanation:
hoped this helped
If the experimenter knows who is in the experimental and control groups and treats them accordingly, she runs the risk of ________.
Answer:
Experimenter bias
Explanation:
If the experimenter knows who is in the experimental and control groups and treats them accordingly, she runs the risk of Experimenter bias.
Definitions of Experimenter bias
1) Research bias, also called experimenter bias, is a process where the scientists performing the research influence the results, in order to portray a certain outcome.
2) Observer bias (also called experimenter bias or research bias) is the tendency to see what we expect to see, or what we want to see. When a researcher studies a certain group, they usually come to an experiment with prior knowledge and subjective feelings about the group being studied.
how can philosophy help you become a productive citizen
Answer:
Philosophy is a study that involves the nature of knowledge and truth. It serves as a guide that helps an individual seek which things are valuable and essential in life. ... It gives you a sense of direction, knowing the weight of things, therefore making you more productive.
Which simple machines are used in the tool or device
Answer:
Explanation:
What are simple machines?
Simple machines reduce effort or extend the ability to perform tasks beyond their abilities.
Why do we use simple machines?
Simple machines are used widely as they help humans and save time.
Simple Machine Examples:
MachineScrewWheel and axle - wheeled carry-on luggageLever - see sawPulley - flag polesInclined planeWedge - knifePlease help which one is correct
Answer:
option (i) is correct
Explanation:
as there is no air resistance, no force is acting on the object horizontally, but gravitational acceleration will obviously act, regardless of the air resistance... option (i) is correct
A small child weighs 60 N. If mommy left him sitting on top of the stairs, which are 12 m high, how much energy does the child have!
Please help ASAP
Answer:
6000 joules
Explanation:
I jus learned dis
Answer:6000j
Explanation:
Hope that helps
A 4.45 g object moving to the right at 18.6 cm/s makes an elastic head-on collision with an 8.9 g object that is initially at rest.
18.6 cm/s
4.45 g
8.9 g
Find the velocity of the first object immediately after the collision. The acceleration of gravity is 9.8 m/s 2 . Answer in units of cm/s.
Answer:
v₁f = -6.2 cm/s
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved, as follows:[tex]m_{1} *v_{1o} = m_{1}* v_{1f} + m_{2}* v_{2f}[/tex]
As the collision is elastic, total kinetic energy must be conserved also:[tex]\frac{1}{2}*m_{1}*v_{1o}^{2} = \frac{1}{2}*m_{1}*v_{1f} ^{2} + \frac{1}2}*m_{2}*v_{2f}^{2}[/tex]
From the givens, we know that m₂ = 2* m₁Replacing in the above equations, rearranging both sides and simplifying, we can find the following expression for v₁f:[tex]v_{1f} = \frac{-m_{1} }{3*m_{1}} *v_{1o} =\frac{-v_{1o}}{3} = -\frac{18.6 cm/s}{3} = -6.2 cm/s[/tex]
v₁f = -6.2 cm/s (which means that it bounces back after the collision).A hydraulic press has a safety feature which consists of a hydraulic cylinder with a piston at one end and a safety valve at the other. The cylinder has a radius of 0.0200 m and the safety valve is simply a 0.00750-m radius circular opening at one end, sealed with a disk. The disk is held in place by a spring with a spring constant of 950 N/m that has been compressed 0.0085 m from its natural length. Determine the magnitude of the minimum force that must be exerted on the piston in order to open the safety valve.
Answer:
Explanation:
radius of cylinder r₁ = .02 m
radius of safety valve r₂ = .0075 m
force exerted by spring on safety valve = 950 x .0085 = 8.075 N .
Force required on piston of cylinder = F
Applying Pascal's law
8.075 / 3.14 x .0075² = F / 3.14 x .02²
F = 8.075 x .02² / .0075²
= 8.075 x 7.111
= 57.42 N .
Forces are expressed in ________. (newtons or mass)
A squirrel drops an acorn from a tree. Starting from rest, it reaches the ground 22.0 meters
below. What is the acorn's velocity as it hits the ground?
Streams compensate for changes in their systems by adjusting other factors in order to return to _______
Answer:
Equilibrium.
Explanation:
Streams compensate for changes in their systems by adjusting other factors in order to return to equilibrium because so as to maintain their watershed. When the surface runoff move downslope, it also cause a concentration in small areas and create small channels of streams. These channels normally allow the flow of water during rainfall.
What is the net work, in joules, required to stop a crate of mass 64.5 kg that is moving at a speed of 1.26 m/s
Answer:
51.2Joules
Explanation:
Work done = Force × distance
Force = mg = 64.5×9.81
Force = 632.745N
Next is to get the distance using the equation of motion
v² = u²+2gS
1.26² = 0+2(9.81)S
1.5876 = 19.62S
S = 1.5876/19.62
S = 0.0809m
Get the work done:
Work done = F×S
Work done = 632.745×0.0809
Work done = 51.2Joules
Hence the net work done in Joules is 51.2Joules
The net work done required to stop a crate will be "51.2 Joules".
Force and MassAccording to the question,
Mass, m = 64.5 kg
Speed, v = 1.26 m/s
Acceleration due to gravity, g = 9.8
We know,
The force, F = mg
By substituting the values,
= 64.5 × 9.8
= 632.745 N
By using Equation of motion,
→ v² = u² + 2gS
(1.26)² = 0 + 2(9.81) S
1.5876 = 19.62 S
S = [tex]\frac{1.5876}{19.62}[/tex]
= 0.0809 m
hence,
The work done (W) will be:
= F × S
= 632.745 × 0.0809
= 51.2 Joules
Thus the above response above is correct.
Find out more information about mass here:
https://brainly.com/question/25545050
An ion has unequal numbers of which two particles?
1. A jogger jogs 25 m East, stops to rest, then continues for 10 more meters
East? What is the jogger's displacement?
Answer:
35m
Explanation:
25m + 10m = 35m east.
*(adding since it's in the same direction)
Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.0 kg gibbon has an arm length (hand to shoulder) of 0.60 m. We can model its motion as that of a point mass swinging at the end of a 0.60-m-long, massless rod. At the lowest point of its swing, the gibbon is moving at 3.5 m/s. What upward force must a branch provide to support the swinging gibbon
Answer:
The correct solution will be "271.95 N".
Explanation:
The given values are:
velocity
v = 3.5 m/s
mass
m = 9.0 kg
r = 0.6 m
According to the question:
⇒ [tex]F_{branch}=F_{gravity}+F_{centrifugal}[/tex]
⇒ [tex]=mg+\frac{mv^2}{r}[/tex]
On substituting the values, we get
⇒ [tex]=9\times 9.8+\frac{9\times (3.5)^2}{0.6}[/tex]
⇒ [tex]=88.2+\frac{110.35}{0.6}[/tex]
⇒ [tex]=271.95 \ N[/tex]
Problem I Marcella (see warmup problem, above) gets her car moving steadily at 4m/s but suddenly someone stops ahead to assist her and parks their car 14 meters from the front of her car. Marcella grabs the car bumper and pulls very hard, with 200 N of force. The work she does transfers energy out, it reduces the K of the car, as it gradually approaches the other car. a) What is the initial kinetic energy before she tries to stop the car? b) What is the final kinetic energy, when her car hits the other car? What is the speed? c) Suppose the other person also slowed her car, pushing it from the front. How much force would be needed to stop her car 1 meter from the other car? [1 m allows the person not to be crushed!]
Answer:
Explanation:
a) KE = (1/2) * m * ([tex]v^{2}[/tex]) = F * d = 14m * 200N = 2800 m/N or 2.8 * [tex]10^{3}[/tex] m/N
b) 0J and 0m/s (if Marcella stopped after going 14 meters)
c) Known from part (a) that KE = 2800 J = F1 * d1,
2800J = F1 * (14m - 1m) => F1 = 2800J/13m = 215.384 N