Answer:
1975 ohm
Explanation:
The maximum current that can pass through the galvanometer is 50.0µA
p.d across the galvanometer at a full scale deflection is given by
V = IR
V = (50.0×10^-6)*25
V1 = 1/800 or 0.00125volts
Since the p.d across the multiplier and galvanometer at full scale deflection is 0.100volts,the p.d across the multiplier alone must be given by
V2 = 0.100-0.00125
= 0.09875volts
Current passing through the multiplier is (50.0×10^-6)A
Hence if R is the resistance of the multiplier, we have that
V2 = (50.0×10^-6)×R
0.09875volts = (50.0×10^-6)×R
Divide both sides by 0.09875volts
R = 0.09875/(50.0×10^-6)
R =( 0.09875) ÷ 1/20000
R = 0.09875×20000
R = 1975 ohms
What happens if atoms lose energy during a change of state?
Answer: they become slower.
Explanation: because they get pulled together.
Answer:
The atoms are pulled together by attractive forces and become more organized.
Explanation:
Atoms lose energy as a gas changes to a solid. ... Atoms gain energy as a solid changes to a liquid. If atoms energy during a change of state, they are pulled together by attractive forces and become more organized.
Reference by Quizlet.
What height does a frictionless playground slide need so that a 35 kg child reaches the bottom at a speed of 6.5 m/s?
Answer:
h = 2.15 m
Explanation:
Given that,
Mass of the child, m = 35 kg
The child reaches the bottom at a speed of 6.5 m/s
We need to find the height slide by a frictionless playground slide. Let it is equal to h. Using the conservation of energy to find it as follows :
[tex]\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(6.5)^2}{2\times 9.8}\\\\h=2.15\ m[/tex]
So, it will slide to a height of 2.15 m
The height slid by the frictionless playground can be calculated by equating the kinetic and potential energy equations which is 2.16 meters
Mass of child = 35 kg Velocity, v = 6.5 m/s g = 9.8 m/s²K.E = P.E
K. E = 0.5mv² ; P.E = mgh
0.5mv² = mgh
gh = 0.5v²
h = [(0.5v²) ÷ g]
h = [(0.5 × 6.5²) ÷ 9.8]
h = (21.125 ÷ 9.8)
h = 2.155 m
Therefore, the height slid by a frictionless playground is 2.16 meters
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A 3.0-kg mass is located at (0.0 m, 8.0 m), and a 1.0-kg mass is located at (12 m, 0.0 m) where (x, y) represents x and y coordinates respectively on x-y plane. You want to add a 4.0-kg mass so that the center of mass (or center of gravity) of the three-mass system will be at the origin. What should be the coordinates of the 3.0-kg mass
Answer:
The coordinates of the 4.0-kg mass must be [tex](x,y) = (-3\,m,-6\,m)[/tex].
Explanation:
We have a system formed by three particles with known masses and locations with respect to origin. The location of the center of mass is calculated by means of weighted means. That is:
[tex]\bar x = \frac{\Sigma\limits_{i=1}^{n}\,x_{i}\cdot m_{i}}{\Sigma\limits_{i=1}^{n}m_{i}}[/tex] (Eq. 1)
[tex]\bar y = \frac{\Sigma\limits_{i=1}^{n}\,y_{i}\cdot m_{i}}{\Sigma\limits_{i=1}^{n}m_{i}}[/tex] (Eq. 2)
Where:
[tex]\bar x[/tex], [tex]\bar y[/tex] - Coordinates of the center of mass of the system, measured in meters.
[tex]x_{i}[/tex], [tex]y_{i}[/tex] - Coordinates of the i-th particle, measured in meters.
[tex]m_{i}[/tex] - Mass of the i-th particle, measured in kilograms.
If we know that [tex]m_{1} = 3\,kg[/tex], [tex]m_{2} = 1\,kg[/tex], [tex]m_{3} = 4\,kg[/tex], [tex]x_{1} = 0\,m[/tex], [tex]x_{2} = 12\,m[/tex], [tex]\bar x = 0\,m[/tex], [tex]y_{1} = 8\,m[/tex], [tex]y_{2} = 0\,m[/tex] and [tex]\bar y = 0\,m[/tex], the location of the 4.0 kg mass is:
[tex]\frac{(3\,kg)\cdot (0\,m)+(1\,kg)\cdot (12\,m)+(4\,kg)\cdot x_{3}}{3\,kg+1\,kg+4\,kg} = 0\,m[/tex]
[tex]12+4\cdot x_{3} = 0[/tex]
[tex]x_{3} = -3\,m[/tex]
[tex]\frac{(3\,kg)\cdot (8\,m)+(1\,kg)\cdot (0\,m)+(4\,kg)\cdot y_{3}}{3\,kg+1\,kg+4\,kg}= 0\,m[/tex]
[tex]24+4\cdot y_{3} = 0[/tex]
[tex]y_{3} = -6\,m[/tex]
The coordinates of the 4.0-kg mass must be [tex](x,y) = (-3\,m,-6\,m)[/tex].
The coordinates of the 4kg mass so that the center of mass of the three-mass system will be at the origin is (-3,-6)
Finding the coordinates:The coordinates of the 3kg mass are (0.0 m, 8.0 m)
and the coordinates for the 1kg mass are (12 m, 0.0 m)
Let the coordinates of the 4kg mass be (x,y)
The final coordinates of the center of mass of the system are (0,0),
so the equation for x-coordinate is given by:
[tex]0=\frac{3\times0+1\times12+4\times x}{3+1+4}[/tex]
12 + 4x = 0
x = -3
the equation for y-coordinate is given by:
[tex]0=\frac{3\times8+1\times0+4\times y}{3+1+4}[/tex]
24 + 4y = 0
y = -6
So, the coordinates of the 4kg mass are (-3,-6)
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A quarterback applies a force 35 N for .28 seconds. What is the
impulse given to the ball?
What is the most logical explanation for why kilo is a more important prefix to remember than tera
If we put a flammable material in a point where many light rays converge we can set it on fire. With what type of spherical mirror would it be possible to do this
Answer:
Concave mirror
Explanation:
A concave mirror is a type that has the property of converging rays of light that are parallel to the principal axis to a point of focus. Thus, for the convergence of many rays of light (i.e a beam of light) as required in the given question, a concave mirror would serve the purpose. Curved mirrors have various applications in optics.
a decompression chamber used by deep sea divers has a volume of 10.1m^3 and operates at an internal pressure of 4.25 atm. What volume, in cubic meters would the air in the chamber occupy if it were at 1.00 atm pressure, assuming no tempreature change.
Answer:
V2=42.93cm3
Explanation:
According to Gay-Lussac's Law: "The Pressure Temperature Law. This law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. With an increase in temperature, the pressure will go up."
P1V1=P2V2
Given data
P1=4.25atm
V1=10.1cm³
P2=1atm
V2=?
V2=P1V1/P2
V2=(4.25*10.1)/1
V2=42.93cm3
A piece of lead with a specific heat capacity of 126J/kg°C is given 5000J of energy to heat it from 20°C to 250°C. What was the mass of the piece of lead?
Answer:
m = 0.172 [kg]
Explanation:
To solve this problem we must use the expression of thermal energy that relates the heat to the mass, the specific heat, and the temperature differential.
Q = m*Cp*(T_f - T_i)
where:
m = mass [kg]
Cp = specif heat = 126 [J/kg*C]
Q = 5000 [J]
T_f = final temperature = 250 [C]
T_i = initial temperature = 20 [C]
m = Q/ (Cp*(T_f - T_i))
m = 5000/ (126*(250 - 20))
m = 0.172 [kg]
The tendency of an object to resist change in its motion is known as
a. mass
b. inertia
c. force
d. balance
119) You throw a rock horizontally off a cliff with a speed of 20 m/s and no significant air resistance. After 2.0 s, the magnitude of the velocity of the rock is closest to
Answer: 44.54 m/s
Explanation:
Let's break the problem into horizontal and vertical.
Horizontal:
Here we do not have any force, only a constant horizontal velocity, so we can write:
Vx(t) = 20m/s.
Vertical:
Here we have the gravitational acceleration acting on the rock, then we can write:
Ay(t) = -9.8m/s^2
For the vertical velocity, we need to integrate over time and get:
Vy(t) = (-9.8m/s^2)*t + V0
Where V0 is the initial vertical velocity, but the rock was thrown horizontally, so we do not have an initial velocity in the vertical axis.
Vy(t) = (-9.8m/s^2)*t.
Ok, now we want to know the magnitude of the velocity when t = 2.0s.
The magnitude will be equal to:
V = √( Vx(2s)^2 + Vy(2s)^2)
= √( (20m/s)^2 + (-2s*9.8m/s^2)^2) = 44.54 m/s
The magnitude of the velocity after 2 seconds is around 44.54 m/s
34. If R = 4.0 kΩ, C = 3.0 mF, ε = 15 V, Q = 12 mC, and I = 2.0 mA, what is the potential difference Vb − Va?
Answer:the potential difference Vb − Va = -3 V
Explanation:
The potential difference Vb − Va s given by
Vb − Va= Capacitance / Charge + current x resistance - Electromotive force
Vb − Va=Q/C + I X R - E
V=Q / C=(12 x 10^-3) / (3 x 10^-3)
=0.012/0.003ss
=4V
alsoV= 1R = 2.0 x 10^-3 x 4 x 10^3
=0.002 X 4000
=8
Vb − Va= 4V + 8V- 15V
= -3V
Therefore, the potential difference Vb − Va = -3 V
A tuna jumps out of the water with an initial velocity of 44 feet per second
Answer:
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Explanation:
plz do so it is true
A 100-g bullet is fired from a rifle having a barrel 0.600 m long. Choose the origin to be at the location where the bullet begins to move. Then the force (in newtons) exerted by the expanding gas on the bullet is 15 000 1 10 000x 2 25 000x2, where x is in meters. (a) Determine the work done by the gas on the bullet as the bullet travels the length of the barrel. (b) What If
Answer:
9000 J
Explanation:
weight of bullet = 100 g
length of gun barrel = 0.6m
A) determine the work done by the gas on the bullet as the bullet travels the length of the barrel
The work done is an integral of force over distance in this scenario
lets represent the force using some constants ( arbitrary )
Fx = a + bx + cx^2
where : a = 15000, b = 10000, c = - 25000
hence work done ( W ) = [tex]ax_{f } + \frac{bx^{2} _{f} }{2} + \frac{cx^{3} _{f} }{3}[/tex]
where ; xf = 0.6
hence work done(W)
= 15000(0.6) + [(10000*0.6^2)/2] + [(-25000*0.6^3)/3]
= 9000 J
The mass of the moon is about 1/81 the mass of the earth and its radius is 1/4
that of the earth. The
acceleration due to gravity at the earth's surface is 9.8 m/s2. What is the acceleration due to gravity on the moon's surface?
9.8 m/s2
2.8 m/s2
1.9 m/s2
3.0 m/s2
A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling horizontally. As the drawing shows, one person hits the water 5.00 m from the end of the slide in a time of 0.378 s after leaving the slide. Ignore friction and air resistance, find the height H in the drawing.
Answer:
9.63 m
Explanation:
We know that
Δx = vt.
Therefore, v = Δx / t
v = 5 / 0.378
v = 13.23 m/s
h = ½gt, so that
h = ½ * 9.8 * 0.378²
h = 4.9 * 0.1429
h = 0.7 m
Finally, using the law of conservation of energy, we know that
½mv² = mg(H - h)
½v² = g(H - h)
½v²/g = H - h, substituting the values and solving, we have
(½ * 13.23²) / 9.8 = H - 0.7
(½ * 175) / 9.8 = H - 0.7
87.5 / 9.8 = H - 0.7
8.93 = H - 0.7
H = 8.93 + 0.7
H = 9.63 m
A 0.150-kg baseball traveling in a horizontal direction with a speed of 21.0 m/s hits a bat and is popped straight up with a speed of 15.0 m/s. If the bat was in contact with the ball for 51.0 ms, what was the average force of the bat on the ball
Answer:
17.65N
Explanation:
We know that the relationship for the impulse and momentum is given as
Ft=mv
given data
mass m=0.15kg
t= 51ms= 26.5/1000= 0.051seconds
velocity v1= 21m/s
Velocity v2=15m/s
substituting in the expression we have
Ft=m(v1-v2)
make F subject of formula we have
F=m(v1-v2) /t
F=0.15(21-15)/0.051
F=0.15*6/0.051
F=0.9/0.051
F=17.65N
This question involves the concepts of momentum and impulse.
The average force of the bat on ball is "17.65 N".
What is the average force?According to Impulse Equation the change in momentum is equal to the product of applied force and time of contact. Mathematically:
[tex]\Delta P=F\Delta t\\\\F=\frac{m\Delta v}{\Delta t}[/tex]
where,
F = Average force = ?m = mass of baseball = 0.15 kgΔv = change in speed = 21 m/s - 15 m/s = 6 m/sΔt = time of contact = 51 ms = 0.051 sTherefore,
[tex]F=\frac{(0.15\ kg)(6\ m/s)}{0.051\ s}[/tex]
F = 17.65 N
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Which of the following is correct about a motion diagram?
a. A group of images for different objects found in one place at the same time
b. A series of images that show the position of a moving object at equal time intervals
c. A series of images that show the position of a moving object at unequal time intervals
d. Collection of photos taken by a person while moving around different places
Answer:
d. collection of photos taken by a person while moving around different places
Answer:
Moving object at equal time intervals
A dairy farmer notices that a circular water trough near the barn has become rusty and now has a hole near the base. The hole is 0.29 m below the level of the water that is in the tank. If the top of the trough is open to the atmosphere, what is the speed of the water as it leaves the hole
Answer:
2.385 m/s
Explanation:
Here there is a transformation of potential energy of the water at the top to Kinectic energy at the hole
This can be expressed as
Potential energy= Kinect energy
mgh= 1/2m v²
Where m= mass of water
h= Lenght below the level of the water that is in the tank.
v= the speed of the water as it leaves the hole
g= acceleration due to gravity= 9.81m/s
Here there is 'm' at both sides which can cancelled beach other out.
Then we have
gh= ¹/₂v²
making v² subject of the formular
v²=gh/(¹/₂)
v=√(2gh)
V=√2g h
V= √(2×9.81×0.29)
V=2.385 m/s
Therefore, the speed of the water as it leaves the hole is 2.385 m/s
what is compressibility?
Hi! Compressibility is the capacity of something to be flattened or reduced in size by pressure. I hope this helps you! Good luck and have a great day. ❤️
A small, 300 gg cart is moving at 1.30 m/sm/s on a frictionless track when it collides with a larger, 4.00 kgkg cart at rest. After the collision, the small cart recoils at 0.860 m/sm/s . Part A What is the speed of the large cart after the collision
Answer:
v₂f = 0.16 m/s (to the right)
Explanation:
Assuming no external forces acting during the collision, as stated by Newton's 2nd law, total momentum must be conserved.The initial momentum is due to the small cart only, because the big one is at rest.Assuming that the small cart is going to the right and taking this direction as the positive one, we can write the following expression for the initial momentum p₀ :[tex]p_{o} = m_{1} * v_{o1} = 0.3 kg * 1.3 m/s (1)[/tex]
The final momentum can be written as follows:[tex]p_{f} = m_{1} * v_{1f} + m_{2} * v_{2f} = 0.3 kg* (-0.86m/s) + 4.00 kg* v_{2f} (2)[/tex]
As p₀ = pf, from (1) and (2), we can solve for v2f, as follows:
[tex]v_{2f} = \frac{0.3kg* (1.3 + 0.86) m/s}{4.00kg} = \frac{0.3kg*2.16m/s}{4.00kg} = 0.16 m/s[/tex]
As the sign of v2f is positive, we conclude that it starts to move in the same direction that m1 was originally going (to the right), whilst m1 recoils, which means that after the collision, it bounces back from the larger mass.Dangerous substances in an ecosystem that are harmful to its organisms are:
A sediments. B scavengers. C pollutants. D overpopulation.
Answer:
C pollutants
Explanation:
Pollutants are dangerous substances in the ecosystem that are harmful to its organisms. They are contaminants and effluents that leads to pollution in the environment.
There are different types of pollutants. Most of them are introduced into the environment by anthropogenic activities. Also, some natural events also introduce these pollutants into the environment. These materials pose huge health risks to living organisms. They can render the environment unfit for life.Answer:
c
Explanation:
You are walking in Paris alongside the Eiffel Tower and suddenly a croissant smacks you on the
head and knocks you to the ground. From your handy dandy tourist guidebook, you find that the
height of the Eiffel Tower is 300.5 m. If you neglect air resistance, calculate how many seconds
the croissant dropped before it tagged you on the head.
What is the answer
Convert 200km/h to m/s
Answer:
200 kilometers per hour =
55.556 meters per second
Explanation:
have a great day
Answer:
200km × 1000m/1km = 200000 m
1h × 60 mins/h × 60sec/min = 3600s
now you divide 200000m/3600s
= 55.55m/s
Two trains travel from New Orleans to Memphis in 5 h. The first train travels at a constant velocity of 80 mph, but the velocity of the second train varies. What was the second train's average velocity during the trip
Answer:
Explanation:
The first train travels at a constant velocity of 80 mph and it takes 5 h to cover the distance so distance between two station = 80 x 5 = 400 m
second train too takes 5 h to cover the same distance so its average velocity
= total distance / total time
= 400 / 5 = 80 m /h
average velocity = 80 m /h
What is an advantage of using nuclear power over natural gas to generate
electricity?
A. Nuclear power produces no waste.
B. Nuclear power does not contribute to climate change.
C. Nuclear power produces greenhouse gases.
D. Nuclear power is free.
Answer:b
Explanation:
I got the answer right
The main advantage of using nuclear power over natural gas to generate the electricity that nuclear power does not contribute to climate change, therefore the correct answer is option B.
What is a nuclear power plant ?It is a particular kind of power plant where electricity is produced using a nuclear reactor that may use nuclear fusion or nuclear fission .
When a radioactive substance undergoes a nuclear reaction, a tremendous quantity of energy is produced .
As given in the problem , we have to find out what is an advantage of using nuclear power over natural gas to generate electricity .
Option B is the proper response , since employing nuclear power instead of natural gas to produce electricity has the advantage of not causing the climate change .
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When the momentum of an object increases with respect to time, what is true of the net force acting on it?
a. It is zero, because the net force is equal to the rate of change of the momentum.
b. It is zero, because the net force is equal to the product of the momentum and the time interval.
c. It is nonzero, because the net force is equal to the rate of change of the momentum.
d. It is nonzero, because the net force is equal to the product of the momentum and the time interval.
Answer:
C. It is nonzero, because the net force is equal to the rate of change of the momentum
Explanation:
Momentum of an object is given as;
P = mv = ft
f = mv/t
or f = P/t
where;
P is the momentum of the object
m is mass of the object
v is velocity of the object
f is the applied force on the object
t is time
From the given equation above; the net force acting on the object is equal to the rate of change of the momentum, thus it is non-zero.
Therefore, the correct option is "C"
C. It is nonzero, because the net force is equal to the rate of change of the momentum.
The net force acting on the object is non-zero, because the net force is equal to the rate of change of the momentum. Hence, option (c) is correct.
The problem is based on the impulse-momentum concept. As per the impulse -momentum concept, the magnitude of impulse produced by an object is equal to the change in momentum. Then the expression is,
[tex]I = \Delta P[/tex]
here,
I is the magnitude of impulse. And its value is,
[tex]I = F \times t[/tex]
t is the impact time or time interval.
F is the magnitude of net force.
[tex]\Delta P[/tex] is the change in momentum.
Solving as,
[tex]I= \Delta P\\\\F \times t= \Delta P\\\\F = \dfrac{\Delta P}{t}[/tex]
Clearly, the net force is dependent of the change in momentum with respect to time. So, on increasing the momentum change with respect to time, the net force will also increase with non-zero value.
Thus, we can conclude that the net force acting on the object is non-zero, because the net force is equal to the rate of change of the momentum. Hence, option (c) is correct.
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A big dog B and a small dog S are pulling horizontally in opposite directions on a large bone. The bone’s mass is mmm, the big dog’s leftward force magnitude is F_BF
B
F, start subscript, B, end subscript and the small dog’s rightward force magnitude is F_SF
S
F, start subscript, S, end subscript. The bone accelerates to the right along the table with no friction.
The correct expression for the mass m of the bone is m=Fs-Fb/a.
What is force?The force is defined as the shear stress or pressure applied per unit area.
A big dog B and a small dog S are pulling horizontally in opposite directions on a large bone. The bone’s mass is m, the big dog’s leftward force magnitude is Fb and the small dog’s rightward force magnitude is Fs. The bone accelerates to the right along the table with no friction.
Across the bottom is green grass. In the center, there is a brown table with a large bone on top. To the left is a black outline of a large dog facing rightwards that is pulling leftwards on the bone. To the right is a black outline of a small dog facing leftwards that is pulling rightwards on the bone. The small dog stands on a grey box. Across the bottom is green grass.
Two dogs pulling on a large bone. Big dog and small dog images courtesy of pixabay. Consider rightward as the positive direction.
The net force acting on bone will be
F = Fs -Fb
From the Newton's second law of motion, Force = mass x acceleration
F = ma
m = F/a
m = Fs-Fb/a
Thus, correct expression for the mass m of the bone is m=Fs-Fb/a.
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A fully loaded, slow-moving freight elevator has a cab with a total mass of 1200 kg, which is required to travel upward 35 m in 3.5 min, starting and ending at rest. The elevator's counterweight has a mass of only 940 kg, so the elevator motor must help pull the cab upward. What average power is required of the force the motor exerts on the cab via the cable
Answer:
425.1 W
Explanation:
We are given;
Counter mass of elevator; m_c = 940 kg
Cab mass of elevator; m_d = 1200 kg
Distance from rest upwards; d = 35 m
Time to cover distance; t = 3.5 min
Now, this elevator will have 3 forces acting on it namely;
Force due to the counter weight of the elevator; F_c
Force due to the cab weight on the elevator; F_d
Force exerted by the motor; F_m
Now, from Newton's 2nd law of motion,
The force exerted by the motor on the elevator can be given by the relationship;
F_m = F_d - F_c
Now,
F_d = m_d × g
F_d = 1200 × 9.81
F_d = 11772 N
F_c = m_c × g
F_c = 940 × 9.81
F_c = 9221.4 N
Thus;
F_m = 11772 - 9221.4
F_m = 2550.6 N
Now, the average power required of the force the motor exerts on the cab via the cable is given by;
P_m = F_m × v
Where v is the velocity of the elevator.
The velocity is calculated from;
v = distance/time
v = 35/3.5
v = 10 m/min
Converting to m/s gives;
v = 10/60 m/s = 1/6 m/s
Thus;
P_m = 2550.6 × 1/6
P_m = 425.1 W
Which of The following statements best describes the objects motion between zero and four seconds?
Answer:
A OR C
Nearly A.
Explanation:
Calculate the linear acceleration of a car, the 0.300-m radius tires of which have an angular acceleration of 17.0 rad/s2. Assume no slippage and give your answer in m/s2.
Answer:
5.1m/s^2Explanation:
In this problem we want to solve for the linear acceleration
Given data
radius r= 0.3m
angular acceleration α=17rad/s^2
we know that the expression relating angular acceleration and linear acceleration is given as
a=rα
Substituting we have
a=0.3*17
a=5.1m/s^2