Find the range for the population mean value with 95% and 65% confidence intervals for each set of data. 3.611 0.02cm n 24

Answers

Answer 1

Complete Question

Find the range for the population mean value with 95% and 65% confidence intervals for each set of data.

 [tex]\= x_1= 3.611 \ cm[/tex], [tex]\sigma_1=0.02\ c m[/tex], [tex]n_1=24[/tex],

[tex]\=x_2=3.632 \ cm[/tex], [tex]\sigma_2=0.06 \ cm[/tex], [tex]n_2= 17[/tex]

Answer:

The range for the population mean value with 95% confidence intervals for the first set of data  is

    [tex]2.602 <\mu <  2.619[/tex]

The range for the population mean value with 95% confidence intervals for the second  set of data  is

    [tex]2.601 <\mu <  2.661[/tex]

The range for the population mean value with 65% confidence intervals for the first   set of data  is

    [tex]2.605 <\mu<  2.617[/tex]  

The range for the population mean value with 65% confidence intervals for the second set of data  is

    [tex]2.611 <\mu <  2.6526[/tex]  

Step-by-step explanation:

Generally the range for the population mean value with 95% confidence intervals for the first set of data  is mathematically evaluated as follows

Generally the degree of freedom is mathematically evaluated as

     [tex]df = n_1 -1[/tex]

=>  [tex]df = 24 -1[/tex]

=>  [tex]df = 23[/tex]

From the question we are told the confidence level is  95% , hence the level of significance is    

      [tex]\alpha = (100 - 95 ) \%[/tex]

=>   [tex]\alpha = 0.05[/tex]

Generally from the t distribution table the critical value  of    at  is  

   [tex]t_{\frac{\alpha }{2}  , df = 23} =  2.068[/tex]

Generally the margin of error is mathematically represented as  

      [tex]E_1 = t_{\frac{\alpha }{2}  , df = 23}  *  \frac{\sigma_1 }{\sqrt{n_1} }[/tex]

=>   [tex]E_1 = 2.068  *  \frac{0.02}{\sqrt{24} }[/tex]  

=>   [tex]E_1 =  0.00844 [/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\= x_1 -E_1 <  \mu <  \=x_1  +E_1[/tex]

       [tex]2.611  - 0.00844 < \mu < 2.611  + 0.00844[/tex]

=>   [tex]2.602 <\mu <  2.619[/tex]

Generally the range for the population mean value with 95% confidence intervals for the second set of data  is mathematically evaluated as follows

Generally the degree of freedom is mathematically evaluated as

     [tex]df_2 = n_2 -1[/tex]

=>  [tex]df_2 = 17 -1[/tex]

=>  [tex]df_2 = 16[/tex]

From the question we are told the confidence level is  95% , hence the level of significance is    

      [tex]\alpha = (100 - 95 ) \%[/tex]

=>   [tex]\alpha = 0.05[/tex]

Generally from the t distribution table the critical value  of    at  is  

   [tex]t_{\frac{\alpha }{2}  , df = 16} =  2.12 [/tex]

Generally the margin of error is mathematically represented as  

      [tex]E_1 = t_{\frac{\alpha }{2}  , df = 23}  *  \frac{\sigma_2 }{\sqrt{n_2} }[/tex]

=>   [tex]E_2 =2.12  *  \frac{0.06}{\sqrt{17} }[/tex]  

=>   [tex]E_2 =  0.03085  [/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\= x_2 -E_2 <  \mu <  \=x_2  +E_2[/tex]

       [tex]2.632  - 0.03085<\mu < 2.632  + 0.03085[/tex]

=>   [tex]2.601 <\mu <  2.661[/tex]

Generally the range for the population mean value with 65% confidence intervals for the first set of data  is mathematically evaluated as follows

Generally the degree of freedom is mathematically evaluated as

     [tex]df = n_1 -1[/tex]

=>  [tex]df = 24 -1[/tex]

=>  [tex]df = 23[/tex]

From the question we are told the confidence level is  95% , hence the level of significance is    

      [tex]\alpha = (100 - 65 ) \%[/tex]

=>   [tex]\alpha = 0.35[/tex]

Generally from the t distribution table the critical value  of    at  is  

   [tex]t_{\frac{\alpha }{2}  , df = 23} = 1.3995 [/tex]

Generally the margin of error is mathematically represented as  

      [tex]E_3 = t_{\frac{\alpha }{2}  , df = 23}  *  \frac{\sigma_1 }{\sqrt{n_1} }[/tex]

=>   [tex]E_3 = 1.3995 *  \frac{0.02}{\sqrt{24} }[/tex]  

=>   [tex]E_3 =  0.00571 [/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\= x_1 -E_3 <  \mu <  \=x_1  +E_3 [/tex]

       [tex]2.611  - 0.00571 <\mu <  2.611  + 0.00571[/tex]

=>   [tex]2.605 <\mu<  2.617[/tex]  

Generally the range for the population mean value with 65% confidence intervals for the second set of data  is mathematically evaluated as follows

Generally the degree of freedom is mathematically evaluated as

     [tex]df_2 = n_2 -1[/tex]

=>  [tex]df_2 = 17 -1[/tex]

=>  [tex]df_2 = 16[/tex]

From the question we are told the confidence level is  95% , hence the level of significance is    

      [tex]\alpha = (100 - 65 ) \%[/tex]

=>   [tex]\alpha = 0.35[/tex]

Generally from the t distribution table the critical value  of    at  is  

   [tex]t_{\frac{\alpha }{2}  , df = 16} =  1.41930 [/tex]

Generally the margin of error is mathematically represented as  

      [tex]E_4 = t_{\frac{\alpha }{2}  , df = 23}  *  \frac{\sigma_2 }{\sqrt{n_2} }[/tex]

=>   [tex]E_4 =1.41930 *  \frac{0.06}{\sqrt{17} }[/tex]  

=>   [tex]E_4 =  0.020653  [/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\= x_2 -E_4 <  \mu <  \=x_2  +E_4[/tex]

       [tex]2.632  - 0.020653<\mu < 2.632  + 0.020653[/tex]

=>   [tex]2.611 <\mu <  2.6526[/tex]  


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Answers

Here is the full question.

In city A, the temperature rises 9° F from A.M to 9 A.M. Then the temperature drops 8°F from 9 A.M. to 10 A.M. in city B, the temperature drops 1°F from  8 A.M. to 9 A.M. Then the temperature drops 3°F from 9 A.M. to 10 A.M.

Write an expression that represents the change In temperature from  8 A.M. to 10 A.M for each city. Simplify and interpret each sum. Use a pencil and paper. Which expression represents the change in temperature for city A?

Answer:

In City A, the expression for the change in temperature is = 9 + (-8)

The amount the temperature changes for City A = 1°F

In City B, the expression for the change in temperature is -1 + (-3)

The amount the temperature changes for City B = -4°F

Thus, City A has a greater change in temperature.

Step-by-step explanation:

From the information above; Given that:

In City A, the rise in temperature from 8 A.M to 9 A.M is = 9°F

In City A, the drop in temperature from 9 A.M to 10 A.M = 8°F

Similarly;

In City B, the drop in temperature from 8 A.M to 9 A.M = 1°F

In City B, the drop in temperature from 9 A.M to 10 A.M = 3°F

For City A

The temperature change from 8 A.M to 10 A.M are :

8 A.M to 9 A.M = +9°F

9 A.M to 10 A.M = -8°F

In conclusion, The sum for the change from 8 A.M to 10 A.M = 9 + (-8) = 1°F

For City B

The temperature change from 8 A.M to 10 A.M are:

8 A.M to 9 A.M = -1°F

9 A.M to 10 A.M = -3°F

In conclusion, The sum for the change from 8 A.M to 10 A.M = -1 + (-3) = -4°F

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lopum no shindeu he no vinciedique

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[tex] \LARGE{ \underline{ \pink{ \sf{Required \: answer:}}}}[/tex]

Heya mate!

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Answers

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

I did:

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Step-by-step explanation:

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[tex] \huge{ \boxed{ \bold{ \tt{2 \: \frac{7}{15} }}}}[/tex]

Step-by-step explanation:

[tex] \tt{5 \frac{4}{5} - 3 \frac{1}{3} }[/tex]

Convert the mixed number into improper fraction

[tex] \tt{↦ \: \frac{5 \times 5 + 4}{5} - \frac{3 \times 3 + 1}{3} }[/tex]

[tex] \tt{↦ \: \frac{25 + 4}{5} - \frac{9 + 1}{3}} [/tex]

[tex] \tt{ ↦ \: \frac{29}{5} - \frac{10}{3} }[/tex]

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Take the L.C.M of 5 and 3

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prime factors of 3 = 1 × 3

L.C.M = Common factors × Remaining factors

= 1 × 5 × 3

= 15

[tex] \tt{↦ \frac{29 \times (15 \div 5)}{15} - \frac{10 \times (15 \div 3)}{15} }[/tex]

[tex] \tt{↦ \: \frac{29 \times 3}{15} - \frac{10 \times \: 3 }{15} }[/tex]

[tex] \tt{↦ \: \frac{87}{15} - \frac{30}{15}} [/tex]

While performing the addition or subtraction of like fractions , you just have to add or subtract the numerator respectively in which the denominator is retained same.

[tex] \tt{ ↦ \: \frac{87 - 30}{15} }[/tex]

[tex] \tt{↦ \: \frac{37}{15} }[/tex]

Convert the improper fraction into mixed fraction.

[tex] \tt{↦ \boxed{ \tt{ 2 \frac{7}{15} }}}[/tex]

And we're done!

Hope I helped!

Best regards! :D

~[tex] \text{TheAnimeGirl}[/tex]

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Answers

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Answers

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Step-by-step explanation:

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Answers

Answer:

m=1

Step-by-step explanation:

y=mx+b

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Add  

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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V100
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V64
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Answers

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ex

100 square root is 10

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81 square root is 9

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Answer:

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Step-by-step explanation:

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