Find the distance between A and B ​

Answer:

29 days.

Step-by-step explanation:

200 • 29 = 5800

Hope this helps

Answer:

29

Step-by-step explanation:

5,800  ÷ 200 = 29

Answer:

x=7

Step-by-step explanation:

2{x+8}+5{x-1}=60

Distribute

2x+16+5x-5 = 60

Combine like terms

7x +11 = 60

Subtract 11 from each side

7x+11-11 = 60-11

7x = 49

Divide each side by 7

7x/7 = 49/7

x = 7

Answer:

69.12

Step-by-step explanation:

Answer:

to use integers for certain problems and equation on math, i can also use it for future use in life in case i need it, Its very helpful to learn since it isnt that complicated nor hard, its just a good skill to keep in mind as a student.

Answer:

p² -5

Step-by-step explanation:

pxp      + p√ 5    -p√ 5        -√ 5√ 5

   pxp  -√ 5√ 5

pxp  -√ 5√ 5

         p² -5

Answer:

43.98 (44) Circumference

Area: 153.94 (154)

Step-by-step explanation:

Answer:

Circumference: 14π square inches or approximately 43.96 square inches

Area: 49π square inches or 153.86 square inches

Step-by-step explanation:

Circumference = 2πr, where r = radius

2π(7) = 14π or 14(3.14) = 43.96

Area = πr^2, where r = radius

π7^2 = 49π or 49(3.14) = 153.86

Answer:

The answers are 4,5,6,

the answer you are looking for is 4

Step-by-step explanation:

the first thing you have to do is define a variable for stuff that you don't know. In this problem, you don't know any of the integers, so you should assign a variable to them.

will put  the first integer as n. The second integer, since it is right after the first, will be n+1. The third integer, since it is right after the second, will be (n+1)+1=n+2. consider the integers 1, 2, and 3. 2 is one more than 1, or in other words, 2=1+1. same for 3, except 3 is two more than 1, so 3=1+2. Since the integers are consecutive, each is one more than the last.We're told that the sum of our three integers is 15. Therefore, n+(n+1)+(n+2)=15 Solving this equation is pretty straightforward:

3n+3=15

3n=12

n=4 That means our first integer is 4. Our second integer is 4+1, or 5, and our third integer is 5+1, or 6. Our answer is confirmed because 4+5+6=15

i hope I helped!!

His mistake was adding 12+2 when he was supposed to subtract.

Answer:

a=-b

Step-by-step explanation:

Or,

b=-a

Answer:

no

at every 30 minutes, a third of the popcorn is consumed.

After an hour, 1/3 + 1/3 = 2/3 of popcorn would be consumed.

At one hour 30 minutes, 2/3 + 1/3 = 3/3 or 1 or all of the popcorn would have been consumed

Step-by-step explanation:

The rate at which popcorn is consumed is 1/3 in 30 minutes

so, in 1 and a half hours, all the popcorn would be finished

1/3 + 1/3 + 1/3 = 1

Answer: $300

Step-by-step explanation:

Mr. Calvin earned  [tex]\$2400[/tex]

He spent  [tex]\frac{3}{8}[/tex] on food i.e.

[tex]\Rightarrow \dfrac{3}{8}\times 2400=\$900[/tex]

[tex]\dfrac{1}{3}\quad \text{on taxes i.e.}\\\\\Rightarrow \dfrac{1}{3}\times 2400=\$800[/tex]

[tex]\dfrac{1}{6}\ \text{on other expenses i.e.}\\\\\Rightarrow \dfrac{1}{6}\times 2400=\$400[/tex]

Remaining money = [tex]2400-900-800-400=\$300[/tex]

So, he saved $300 after expenses

Answer:

The height of the railway = 361 feet

Step-by-step explanation:

This question can be solved by applying the required trigonometric function. Let the height of the railway be represented by h.

Sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]

Sin 52 = [tex]\frac{h}{458}[/tex]

h = Sin 52 x 458

  = 0.788 x 458

  = 360.904

h = 361

So that, the railway is 361 feet high.

Answer: 4 = 90

Step-by-step explanation:

90

Answer:

1. 135° = obtuse angle

2. 245° = Reflex angle

3. 62° = acute angle

4. 110° = obtuse reflex angle

Answer:

1200÷2000=0.6

0.6×100%= 60%

The answer is 60%

Answer:

each of them has to pay $11.5 individually

Step-by-step explanation:

The computation of the amount paid by each one is shown below:

As carla and Ana gone for an icecream and the bill is $23 that should be divided equally

So here the carla should pay

= $23 ÷ 2

= 11.5

And, Ana should pay

= $23 ÷ 2

= $11.5

Hence, each of them has to pay $11.5 individually

Given:

The graph of a parabola.

To find:

The equation of the parabola.

Solution:

From the given graph, it is clear that the vertex of the parabola is at point (0,0) and it is a horizontal parabola.

The general equation of a horizontal parabola is:

[tex]x=ay^2[/tex]

Where, a is a constant.

If a<0, then the parabola opens left and if a>0, then the parabola opens right.

Equations in options B and D are of the form [tex]x=ay^2[/tex] but a<0 in option B and a>0 in option D.

In the given graph the parabola opens right, so the value of a mus be a positive number. So, the required equation is:

[tex]x=\dfrac{1}{6}y^2[/tex]

Therefore, the correct option is D.

Step-by-step explanation:

2*22/7*48=301.714 .This the answer

Answer:

Yeah, what they said above.

Step-by-step explanation:

Answer:

x=11.2

Step-by-step explanation:

Set up a proportion:

x+11/36 = 37/60

Cross multiply:

1332=60(x+11)

Distribute:

1332=60x+660

Subtract 660 from 1332

672=60x

Divide:

x=11.2

I'm not sure if this is the correct answer but I hope this helps! :)

Correct me if I'm wrong!

Answer:

1  19/60

Step-by-step explanation:

pls make me the brainleaist

Answer:

selling indulgences

Step-by-step explanation:

Answer:

In his these, Luther condemned the excesses and corruption of the Roman Catholic Church, especially the papal practice of asking payment-called”indulgences”-for the forgiveness of sins

Step-by-step explanation:

Answer:

Silicone types in common use in the industry include:

High Modulus.

Low modulus.

Neutral cure.

Acetoxy cure.

Hope u won't forget to mark brainiest

have a good day!

Answer:

Interés compuesto:

El tiempo entre dos fechas en las que los intereses se agregan al capital se llama periodo

de capitalización, y el número de veces por año en que los intereses se capitalizan se llama

frecuencia de conversión y de denota con la “p”.

A la frecuencia de conversión se le conoce también como frecuencia de capitalización de

intereses.

P = 1 Para periodos anuales, los intereses se capitalizan cada año.

P = 2 Si los periodos son semestrales

P = 3 Para periodos cuatrimestrales.

P = 4 Para periodos trimestrales.

P = 6 Cuando son periodos bimestrales

P = 12 Para periodos de un mes.

P = 13 Si los periodos son de 28 días.

P = 24 Para periodos quincenales

P = 52 Para periodos semanales

P = 360 0 365 Si son periodos diarios.

M = Ceit

M = C(1 + i / p)tp

Donde:

t = periodo en años

tp = es el número de periodos

i = La tasa de interés anualizada en “p” periodos por año.

Ejemplo: Inversión de un capital para monto preestablecido. (Villalobos, 2007, pág. 171)

a) ¿Qué capital debe invertirse ahora al 12.69% anual capitalizable por bimestre para tener

$40,000 en 10 meses?

b) ¿A cuánto ascienden los intereses?

Datos:

El plazo “t” debe estar en años, por lo que para expresar 10 meses en estas unidades se divide

entre 12, o sea, el número de meses que tiene un año. En consecuencia, el plazo en años es t =

10 / 12. La frecuencia de conversión o capitalización de intereses es p = 6 porque 6 son los

bimestres que tiene un año. Entonces:

tp = (10/12)6 = 5 bimestres.

El monto es M = $40,000, la tasa de interés es i = 0.1269 o 12.69% anual, capitalizable por

semestres, y la incógnita es C, la cual se despeja de la igualdad que resultó de sustituir estos

valores en la ecuación:

Solución:

Fórmula: M = C(1 + i/p)tp

40,000 = C(1 + (0.1269 / 6))5

Apuntes de Matemáticas Financieras Prof. Gerardo Gutiérrez Jiménez

40

40,000 = C(1.02115)5

40,000 = C(1.110318838)

C = 40,000 / 1.110318838

C = $36,025.68797

Solución b) Los intereses son la diferencia entre el monto y el capital:

I = M – C

I = 40,000 – 36,025.69

I = $3,974.31

Ejemplo: Monto que se acumula al invertir un capital.

El capital es C = $65,000, la tasa anual es i = 0.10, la frecuencia de conversión es p = 2 por que

el año tiene dos semestres, t = 3 porque el capital se acumula tres años, el número de periodos

en el plazo es tp = 6, entonces el monto según el teorema es: (Villalobos, 2007, págs. 170-171)

R = $87,106.22

Ejemplo: Tasa de interés para duplicar un capital.

¿Con qué tasa de interés anual capitalizable por bimestres se duplica un capital en 3 años?

(Villalobos, 2007, pág. 172)

R = 23.55%

Ejemplo: Valor presente de un crédito e intereses.

El 25% del precio de un mueble de sala se paga con un documento con valor nominal de $4,000

y vencimiento a 30 días. Un 30% se liquida mediante un pago a 60 días de plazo, otro 30% con

un documento a 90 días de la compra y el 15% restante se dejan como anticipo. Obtenga:

a) El precio del mueble.

b) El anticipo y los otros dos pagos.

c) El cargo total por intereses.

Suponga que la mueblería carga el 22.20% anual compuesto por mes en sus ventas a crédito.

(Villalobos, 2007, págs. 173-174)

Solución inciso a:

C1 = $3,927.344134

Entonces:

Precio = $15,709.38

Solución del inciso b: “el anticipo es el 15% de este precio”.

C2 = 4,712.81

Entonces, el segundo pago es el valor futuro de este capital, es decir:  

Apuntes de Matemáticas Financieras Prof. Gerardo Gutiérrez Jiménez

41

M2 = $4,888.80

El valor presente del último pago es igual al del anterior y por tanto, este pago es:

M3 = $4,979.24

Finalmente, solución del inciso c), Los intereses son la diferencia entre el total pagado y el precio

del mueble:

I = $512.07

Note que la tasa de interés global es:

G = 3.2787%

Step-by-step explanation:

Answer:

y=(2,1)

z=( 1,7)

Step-by-step explanation:

Because from their original point you would have to count to the left four unit and up two units

Answer:

A = 45 cm²

Step-by-step explanation:

The area (A) of a trapezium is calculated as

A = [tex]\frac{1}{2}[/tex] h( b₁ + b₂)

where h is the height and b₁, b₂ the parallel bases

Here h = 5, b₁ = 10 and b₂ = 8 , then

A = 0.5 × 5 × (10 + 8) = 0.5 × 5 × 18 = 45 cm²

Answer:

5

Step-by-step explanation:

0+3+6+7+9=25

25/5=5

Answer:

it goes up by 3 2 times and up by 1 once and repeat that

Step-by-step explanation:

Answer:

To graph a rational function, you find the asymptotes and the intercepts, plot a few points, and then ... graphing showing vertical asymptote at x = 1 ... Next, I'll find any x- or y- intercepts.