Answer:
to prevent any electric shock to the user. (more info below)
Explanation:
The metallic structure of electrical equipment is bound to the earth by means of earth wire, such that any electrical current leakage is transmitted to the field. This stops the consumer from experiencing any electrical shocks. That's why the electrical devices ought to be earthed.
hope this helled!
In Los Angeles, the temperature at 3:00 p.m on Aug 16th is
73.9 °F. What is the temperature in °C?
°C.
Answer:
The temperature on 16th August is 23.37 degree Celsius.
Explanation:
In Los Angeles, the temperature at 3:00 p.m on Aug 16th is 73.9 °F. It is required to convert it into degree Celsius.
The conversion from Fahrenheit to Celsius is as follows :
[tex]C=(F-32)\times \dfrac{5}{9}\\\\C=(73.9-32)\times \dfrac{5}{9}\\\\T=23.27^{\circ} C[/tex]
So, the temperature on 16th August is 23.37 degree Celsius.
There are 200 turns of wire around an electromagnet. The current in the wire is 6 amp. You want to increase the strength of the magnet to 1.5 times its present strength. What are two changes you can make to achieve your goal? Show all your calculations.
Answer:
i. increasing the number of turns of the wire by half, so that it equals 300.
OR
ii. increasing the value of the current by half of its initial value, so that it equals 9 amp.
Explanation:
An electromagnet consists of a coil of wire wound around a conductor which becomes induced with magnetism when current flows through the coil.
The magnetic strength of the electromagnet can be increased to 1.5 of its initial strength either by;
i. increasing the number of turns by half of its initial value
OR
ii. increasing the current by half of its initial value
The magnetic strength of an electromagnet = I × N
where; I is the amount of current and N the number of turns.
Given that: I = 6 A, N = 200, then;
magnetic strength = 6 ×200
= 1200 Ampere turns
i. Increasing the number of turns to 300 and I = 6 A, we have;
magnetic strength = 6 × 300
= 1800 Ampere turns
OR
ii. increasing the value of current by half of its initial value, so that N = 200 and I = 9 A;
magnetic strength = 9 ×200
= 1800 Ampere turns
At the beginning of a bobsled race, teammates push their bobsled along the track before jumping
into it.
a. Before the teammates jump in, they push the bobsled (m= 100 kg) from rest to a speed of 6
m/s. How much kinetic energy does the bobsled gain
I’ll give brainliest to whoever answers first
KE=1/2mv^2
1/2(100)6^2
1800 J
Help? 25 points and will give brainliest!
Answer: 44.89 times
Explanation:
Given that the earth's average velocity is about 6.7 times faster than that of planetoid Makemake
Given that the formula involved is:
R2/R1 = (V1/V2)^2
Let V1 = earth velocity and R1 = earth orbital distance
While R2 = Makemake velocity and R2 = orbital distance.
Since the earth's average velocity is about 6.7 times faster than that of planetoid Makemake, then,
V1/V2 = 6.7
Substitute this in the formula above
R2/R1 = (6.7)^2
R2/R1 = 44.89
Cross multiply
R2 = 44.89R1
Therefore, Makemake's orbit is about 44.89 times larger than the earth's orbit.
A 1,500 kg car hits a boulder with a force of 500 N, and the collision takes 0.5
seconds. What is the magnitude of its impulse?
A. 75,000 kg-m/s
B. 50 kg-m/s
C. 250 kg-m/s
D. 750 kg-m/s
Answer: C.
250 kg-m/s
Explanation:
Given that the
Mass M = 1,500 kg
Force F = 500 N
Time t = 0.5 seconds
From Newton's second law of motion which state that the rate of change of momentum is proportional to the applied force.
F = mV/t
Ft = mV
Where ft = impulse: the product of time and applied force
Substitutes force and time into the formula
Ft = 500 × 0.5 = 250 Ns
Answer:
c
Explanation:
just took the quiz
How can I makeup a physics scenario that includes concepts of work and energy. Should I make something going up or down a ramp!? JUST a SCENARIO plss!!!I'm stressed! I need to be able to make a solution for this made up scenario that includes work and energy calculations.
Answer:
Work done = 100 Nm
Potential energy = 250J
Explanation:
A person carrying a heavy weight of load without moving does no work. But the load will surely experience potential energy.
Work will be done when he or she covers a little distance.
If the weight of the load = 25 N and the distance covered is 4 metres, the workdone will be the product of the weight and distance covered. That is,
WD = F × d
WD = 25 × 4 = 100Nm
Let assume that the height of the man is 10 m tall.
The load will be experiencing potential energy of mgh. That is,
P.E = mgh
Since weight W = mg
Substitute weight and height into the formula
P.E = 25 × 10 = 250J
Give example of not reversible change...
Answer:
There were many examples of this. One of the most well-known not reversible reaction is a precipitation reaction, in which an insoluble solid is formed from two aqueous solutions. An example is the reaction between silver nitrate and sodium chloride which forms a silver chloride precipitate.
where was forensic science first used to solve a crime?
Answer:
In 1836, Scottish chemist, James Marsh, did the first application of this forensic science technique. This test was actually used successfully in a murder trial at that time.
Explanation:
I hope that is what you were asking
Answer: London , United Kingdom
Explanation:
In 1836, Scottish chemist, James Marsh, did the first application of this forensic science technique.
How much work must be done on a 10-kg bicycle to increase its speed from 5
m/s to 10 m/s?
O A. 500 J
B. 125 J
C. 375J
O D. 5J
Answer:
375 j
Explanation:
Work done = increase in kinetic energy
C is the correct answer for this question. 375 work must be done on a 10 kg bicycle.
1: 1/5*10 * (10+5)(10-5)
Work Done: 375J
Hope this helps.
Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2
seconds. What is Sasha's tangential speed?
O 0.9 m/s
O 1.3 m/s
O 2.7 m/s
Answer:
tangential speed ≈ 2.7 m/s
Explanation:
formula: Vt = 2r / t
r = 3.5 m
t = 8.2 s
Vt = 2(3.5) / 8.2
Vt = 2.68184 m/s
Vt ≈ 2.7 m/s
correct on edge
What is the mass of an object that weighs 198 N?
Answer: An object weighs 2800 lb
Explanation:
A rose has a phenotype ratio of 3:1 where red roses are dominant over white roses. Out of a total of 4 roses, how many of the roses are red? 1 2 3 4
Answer: 3
Explanation:
Since the phenotype ratio is 3 : 1, where red Roses are dominant over white roses, the ratio of red will be 3 while the white will be 1
Finding the value of the two roses will be;
3 + 1 = 4
For red roses,
3/4 × 4 = 3
For white rose,
1/4 × 4 = 1
Therefore, 3 of the red roses are there.
Answer:
3
Explanation:
What statement is best supported by the information in the chart?
Answer:
Object 1
Explanation:
The statement best supported by the information in the chart is that the object 1 is the heaviest.
What is weight?Weight is the product of mass of the object and gravitational acceleration of the Earth g =9.81 m/s².
As the balance tips towards the object, the object is heavier than the weight.
Thus, the object 1 is the heaviest.
Learn more about weight.
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True or false: it is legal for a goalie to jump forward or come off his line during a penalty kick
Answer:
no
Explanation:
the goalie can move side to side but cant go out of the goalie box.
pls mark me brainliest
The table gives some information about the orbits of Mars and Saturn.
Mars completes a number of orbits in the time it takes for Saturn to complete one orbit.
I will rate you brainliest if you answer!
Calculate the number of orbits that Mars completes in the time it takes for Saturn to complete one orbit.Immersive Reader
(5 Points)
Answer: 15 orbits
Explanation:
Given that the
Radius of Mars = 2.28 × 10^8 km
Radius of Saturn = 1.43 × 10^9 km
For a linear speed,
One revolution = 2πR
One revolution of Mars = 2 × π 2.28×10^8
And
One revolutionary of Saturn = 2 × π × 1.43 × 10^9
Since the relationship between angular speed and linear speed is
V = wr
Or
W = V/2πR
The number of orbits that Mars completes in the time it takes for Saturn to complete one orbit will be
(Vs/2π × 1.43 × 10^9) ÷ (Vm/2π × 2.28×10^8)
Where
Vm = linear speed of Mars = 24.1 km/s
Vs = linear speed of Saturn = 9.7km/s
(24.1/2π × 2.28×10^8) ÷ (9.7/2π × 1.43 × 10^9)
(24.1/2π × 2.28×10^8) × ( 2π × 1.43 × 10^9/9.7)
2π Will cancel each other
(24.1/2.28 × 10^8) × (1.43×10^9/9.7)
(24.1 × 1.43×10^9)/(2.28×10^8 × 9.7)
3.4463×10^10 / 2.2116×10^9
15.58 times
Therefore, Mars will complete 15 orbits in the time it takes for Saturn to complete one orbit.
Look at the periodic table which statement about the elements on the periodic table is true
Answer: B
Explanation:
The reactivity of alkaline metal ( example group one ) increases down the group because of the increase in atomic mass from the top to the bottom of the group. As the mass increases, the force between the nucleus and the valence electron gets weaker and the atom will easily give up the electron as a result of this which eventually increases its reactivity.
The reactivity of halogens decreases as atomic mass increases. Therefore, option B is the correct answer.
A rope is vibrating at high frequency. The length of the rope is 2.40 meters. A snapshot of the rope at a given moment in time
is also shown. Use this information to determine the
wavelength of the wave.
Answer:
λ = L / # _ periods
Explanation:
We don't have the image of the string, but a wavelength is the minimum distance when the wave repeats, therefore the distance between two consecutive maxima is the wavelength in the string
A method used to decrease the error is to measure the distance in several consecutive maxima and divide the number of them, in this way the error in the measurements is divided between all the points, so the value of the wavelength is more exact
λ = L / # _ periods
What’s the a chicken nugget
how is energy transformed using a wheel and axle
Answer:
The mechanical advantage of the wheel and axle is the ratio of the distances from the fulcrum to the applied loads, or what is the same thing the ratio of the diameter of the wheel and axle
Explanation:
i looked on Google
The wheel and axle simple machine is closely related to gears. Like all other simple machines the wheel and axle system changes the force by changing the distance over which the force must be applied; if the input force is reduced to the output force, then the force must be applied over five times the distance.
An electric motor has an operating resistance of 25 Ω when a 4.8 A current is flowing through it. What is the potential difference of the outlet the motor is plugged into?
An object is placed 10 m to the left of a convex lens with a focal length of +8 cm Where is the image of the object
18 cm to the left of the lens
40 cm to the right of the lens
40 cm to the left of the lens
18 cm to the right of the lens
Answer:
18 cm to the right
Explanation:
I don't really know i'm just guessing. hope it's right.
There is a limited amount of fossil fuels (our main source of energy for powering our appliances and cars) on Earth. Why? What is an example of a "renewable" energy source, and why is it considered "renewable"?
describe how light reflecting from a mirror can produce an image. In particular, explain how mirrors can produce images that are larger or smaller than life size, as well as upright or inverted.
Answer:
A larger image is produced when [tex]d_i[/tex] > [tex]d_o[/tex]
A smaller image is produced when [tex]d_i[/tex] < [tex]d_o[/tex]
An upright image is produced when m is positive
An upright image is produced when m is negative
Explanation:
The mirror equation is given as follows;
[tex]\dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}[/tex]
[tex]m =-\dfrac{d_i}{d_o} = \dfrac{h_i}{h_o}[/tex]
For concave mirrors, f = focal length
[tex]d_i[/tex] = Image distance from the mirror (-ve [tex]d_i[/tex] = Image is behind the mirror +ve [tex]d_i[/tex] = Image is in front of the mirror)
[tex]d_o[/tex] = Object distance from the mirror (-ve [tex]d_o[/tex] = Object is behind the mirror +ve [tex]d_o[/tex] = Object is in front of the mirror)
m = Magnification (-ve m = Inverted image +ve m = upright image)
[tex]h_i[/tex] = Image height
[tex]h_o[/tex] = Object height
f = Focal length of the mirror
To produce a larger image [tex]d_i[/tex] > [tex]d_o[/tex]
To produce a smaller image [tex]d_i[/tex] < [tex]d_o[/tex]
To produce an upright image, m should be positive hence, [tex]d_i[/tex] will be negative or the image will appear behind the mirror
To produce an inverted image, m should be negative hence, [tex]d_i[/tex] will be positive or the image will form in front of the mirror.
Which statement about magnets and magnetic fields is correct?
A. Magnetic fields apply a force on any object with a mass.
B. Magnetic fields apply a force on any metal.
C. Magnetic fields apply a force on magnets.
D. Magnetic fields apply a force on electrically conductive metals.
Answer:
B. Magnetic fields apply a force on any metal.
Explanation:
hope this helps u
Answer:
Magnetic fields apply a force on magnets.
Explanation:
this is correct
Skin sensitivity may not include:
a. Touch
b. Hearing
c. Pain
d. Temnerature
Assuming that voltage remains constant, what happens to the current in a wire as its diameter decreases? A. The current is not affected by a change in wire diameter. B. The current alternates between high and low values. C. The current increases. D. The current decreases.
Answer:
The current decreases
Explanation:
A P E X
Assuming that voltage remains constant, as its diameter decreases, its current decreases. hence option D is correct.
What is Current ?Current is a flow of charges. it is denoted by i and expressed in ampere A. Mathematically it is expressed as i = q/t, where q is the amount of charge and t is time. Current is nothing but amount of charges flown in the unit time in the electric wire. Charge is expressed in coulomb C and time in second s. hence coulomb per second (C/s) is ampere A. Charge on electron is 1.60217663 × 10⁻¹⁹C which is called as elementary charge.
There are two types of the current, Convectional current and non-conventional current. Convectional current is the current flows from positive to negative. Non convectional current flows from negative to positive. Note that flow of electrons is from negative to positive. Hence direction of flow of conventional current is from positive to negative.
In this problem, voltage is constant and diameter of the wire is decreasing,
The relation between resistance and and resistivity is
R = ρ l/A
When diameter decreases, cross sectionals area decreases, it increases resistance of the wire. and due to increase in resistance, current decreases in order to keep the voltage constant(V=IR).
Hence option D is correct.
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A boy pushes on a wagon so that it accelerates at a rate of 0.50 m/s2. The wagon has a mass of 24 kg. What is the magnitude of the boy's pushing force? (Ignore frictional effects.) 12 N 12 kg 48 N 48 kg
Answer:
12N
Explanation:
Force acting on any body is equal to mass of body multiplied by acceleration produced in the body.
Its formula is
F = M*a
where F is the force acting on body
M is the mass of the body
a is the acceleration produced in the body
Unit of force is Newton represented by N
1 N is force acting on body of mass 1 kg which produces acceleration of 1m/s^2.
_____________________________________
Given
a = 0.50 m/s^2
M = 24 kg
therefore
F = 24*0.5 = 12 N
Thus, magnitude of the boy's pushing force is 12 N.
1. An automobile traveling at 25 km/hour has kinetic energy equal to 1x 10^4J.
a What is the mass of the car?
b. If the velocity of the car is increased to 45 km/hour, what is its kinetic energy?
c. If the velocity is increased to 80 km/hour, what is its kinetic energy?
Explanation:
It is given that,
Speed of an automobile is 25 km/h or 6.95 m/s
Kinetic energy of the automobile is [tex]10^4\ J[/tex]
(a) Kinetic energy of automobile s given by :
[tex]K=\dfrac{1}{2}mv^2\\\\m=\dfrac{2K}{v^2}\\\\m=\dfrac{2\times 10^4}{(6.95)^2}\\\\m=414\ kg[/tex]
(b) If the velocity of the car is increased to 45 km/hour or 12.5 m/s, new kinetic energy becomes :
[tex]K=\dfrac{1}{2}\times 414\times (12.5)^2\\\\K=32343.75\ J[/tex]
(c) If the velocity is increased to 80 km/hour, 22.23 m/s, So
[tex]K=\dfrac{1}{2}\times 414\times (22.23)^2\\\\K=102293.79\ J[/tex]
Hence, this is the required solution.
In the Position versus Time graph of an object moving in a straight line, what is the change in position in the fourth hour?
A) Zero
B) 15 miles
C) 35 miles
D) 75 miles
Answer:
Option B. 15miles.
Explanation:
From the question given, in the 4th hour simply means between 3rd and 4th hour.
Now, let us determine the position of the object at the 3rd and 4th hour. This is illustrated below:
At the 3rd hour:
Position (P3) = 60miles
At the 4th hour:
Position (P4) = 75miles
Finally, we shall determine the change in the position of the object as follow:
Change in the position = P4 – P3
Change in the position = 75 – 60
Change in the position = 15 miles
Therefore, the change in the position of the object in the 4th hour is 15miles.
Answer:
its b
Explanation:
i got it right on my exam
A student is flying west on a school trip from Winnipeg to Calgary in a jet that has an air velocity of 792 km/h.The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h [N] is _____° S of W. (give your answer with the correct number of significant digits and do not include units)
Answer:
The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h[N] is 4.5° S of W
Explanation:
The given parameters are;
Velocity of Jet = 792 km/h
Direction of jet velocity = West
Velocity of wind = 62.0 km/h
Direction of wind velocity = North
Therefore, the jet has to have a component of 62.0 km/h South of West to compensate for the wind velocity
The direction of the plane, θ° South of West (S of W) to compensate for the wind is given as follows;
[tex]Tan \left (\theta \right )= \dfrac{62}{792} = \dfrac{31}{396}[/tex]
Therefore;
[tex]\theta = tan^{-1}\left (\dfrac{31}{396} \right ) = 4.476^{\circ} \approx 4.5^{\circ}[/tex]
The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h[N] = 4.5° S of W.
The direction the plane would have to fly to is : 4.5° south of west
Given data :
Jet velocity = 792 km/h
wind velocity = 62 km/h
Given that the direction of the jet velocity is west and the direction of the wind velocity is north.
The direction of component velocity of the Jet would be 62 km/h south of west
Determine the direction ( ∅ ) of the plane south of westTan ( ∅ ) = 62 / 792
Therefore ( ∅ ) = Tan⁻¹ ( 62/792 )
≈ 4.5° S of W
Hence we can conclude that The direction the plane would have to fly to is : 4.5° south of west
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