Every orbital in a sub level is singly occupied before any orbital is doubly occupied is the statement of

Answer:

1. H2 + Cl2 => 2HCl

2. Na2S + 2HCl => 2NaCl + H2S

3. 6HCl + 2Al => 2AlCl3 + 3H2

4. C3H8 + 5O2 => 3CO2 + 4H2O

5. C6H12O6 + 6O2 => 6CO2 + 6H2O

6. 4C12H23O11 + 49O2 => 48CO2 + 46H2O

7. 4NH3 + 7O2 => 4NO2 + 6H2O

8. 2Mg + 02 => 2MgO

hope it helps

Answer:

the answer to this question is A H202

Answer:

im absoulutely positive it is C

Answer:

See answer below

Explanation:

In this case, let's draw the butane molecule:

CH₃ - CH₂ - CH₂ - CH₃

According to what the exercise states, we removed an atom of hydrogen from the frist carbon. This could be any of the terminals. I'll grab the first from left to right.

CH₂⁺ - CH₂ - CH₂ - CH₃

When this happens, the atom of carbon is lacking one space and it forms a carbocation.

Followed this step, an hydroxile group replace the atom of hydrogen. The hydroxile is the OH, and when we have an alkane with an OH group in the molecule, we are actually converting this molecule into an alcohol, therefore the molecule formed is:

Hope this helps

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In the first box, you should draw a chicken. In the second box, you should draw a cow or a horse.

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Answer:

See Explanation

Explanation:

Given:

moles M = 0.600 mole

moles F = excess (for rxn stoichiometry)

Formula Weight (F.Wt.) of F = 19 grams/mole (from Periodic Table)

Yield in grams = 46.8 grams (assuming theoritical yield)

Rxn:         M          +        F₂       =>   MF₂

         0.600mol         Excess          0.600mol (1:1 rxn ratio for M:MF₂)

a. moles of F in MF₂ = 2(0.600) moles F = 1.2 moles F

b. mole weight MF₂ = 46.8g/0.600mol = 78g/mole

    F.Wt. MF₂ = F.Wt. M + 2(F.Wt. F)

     => mass M = F.Wt. M = [F.Wt. MF₂ - 2(F.Wt. F)] = 78g/mol. - 2(19g/mol.)

     = (78 - 38) grams/mole = 40 grams/mole

c. Calcium (Ca) has F.Wt. = 40 grams/mole (compared to Calcium on Periodic Table.

From the question, the metal is the limiting reactant and must be used to obtain the required results which are;

a) There are 1.20 mol F in MF2.

b) There are 40g of M in MF2.

c) M is calcium.

From the reaction equation;

M + F2 ----> MF2

Since the reaction is 1:1, 0.600 mol of MF2 is formed

Note that 1 mole of MF2 contains two moles of F and one mole of M

Hence, number of moles of F in MF2 = 2 *  0.600 mol = 1.20 mol F

Since 1 mole of M is contained in MF2, there are 0.600 moles of M in MF2.

If 1 mol of M forms 1 mole of MF2

And, 0.600 mol of M form 0.600 mol of MF2

Number of moles of MF2 = mass/molar mass

Number of moles of MF2 =  0.600 mol

Mass of MF2 formed = 46.8 g

Molar mass of MF2 = mass/Number of moles of MF2

Molar mass of MF2 = 46.8 g/0.600 mol

Molar mass of MF2 = 78 g/mol

Molar mass = Sum of Relative atomic mass of component atoms.

Hence;

78 = M + 2(19)

M = 78 - 2(19)

M = 40 g

The element must be calcium

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Answer:

See explanation

Explanation:

The percentage by mass of oxygen is defined as;

Mass of oxygen/ molar mass of the compound * 100/1

The average percentage by mass of oxygen = 38.933 + 38.940 + 38.871 + 38.892 + 38.900/5

The average percentage by mass of oxygen = 38.907

Percentage Error  = (|accepted value – experimental value| \ accepted value) x 100%

Percentage Error  = 39.13 - 38.907 / 39.13 * 100

Percentage Error  = 0.57%

Brenda argument is supported.

Here moss and lichens are still there after the flood which will recolonize the colony once there.

Primary succession is ecological succession that begins in essentially lifeless areas, such as regions in which there is no soil or where the soil is incapable of sustaining life.

It is a type of ecological succession in which plants and animals recolonize a habitat after a major disturbance such as a devastating flood, wildfire, landslide, lava flow, flood or human activity.

To know more about ecological succession here

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Answer:

mole ratio, which is equivalent to a 1;1 mole ratio, to a gram ratio. This means that when the reaction consumes 84.03 g of carbon monoxide, it should theoretically produce 132.03 g of carbon dioxide. Use this gram ratio to calculate the theoretical yield for your reaction.

Explanation:

Answer:

A satellite may be malfunctioning.

Line of sight may be blocked.

low batteries in your GPS.

Answer:

the enantiomeric excess of the mixture is 40%

Explanation:

The computation of the enantiomeric excess of the mixture is shown below:

As we know that

[tex]= |\frac{R - S}{R + S} |\times 100\\\\= |\frac{70 - 30}{70 + 30}| \times 100\\\\= 40\%[/tex]

Hence, the enantiomeric excess of the mixture is 40%

Answer:

warm

Explanation:

Answer:

D H2PO4– + HPO42–

Explanation:

The acid dissociation constant for [tex]\mathbf{H_3PO_4 , H_2PO^{-}_4 , HPO_4^{2-}}[/tex] are [tex]\mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \ 5\times 10^{-13}}[/tex] respectively.

[tex]\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}[/tex]

[tex]\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}[/tex]

[tex]\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}[/tex]

The reason while option D is the best answer is that, the value of pKa for both

[tex]\mathbf{H_2PO^{-}_4 ,\ \& \ HPO_4^{2-}}[/tex] lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.

Using Henderson-Hasselbach equation:

[tex]\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}[/tex]

The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex]. Thus, option D is correct.

The buffers are the solutions of acids and base of appropriate pH, that are able to limit the change in pH in the reaction mixture.

The buffer pH is adjusted with the compounds that has been able to add base or acid to the solution.

For the formulation of buffer of specific pH, the acid and base solutions are required.

The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex], as they are able to provide acid and base to the solution.

Thus, option D is correct.

Learn more about buffers, here:

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Answer:0

.63

Explanation:

Answer:

If Mountain lions are removed from a habitat/ecosystem, their prey will overpopulate, which may lead to extinctions on the pray of the secondary consumers. ex. A mountain lion would eat rabbits who eat berries, if there are no mountain lions to kill the rabbits, then the berries may be scarce

Explanation:

bc i know everthing

Answer:

[tex]Y=12.2 \frac{gpm}{ft}[/tex]

Explanation:

Hello!

In this case, since we can find that the well produces 280 gpm, and the given drawdown is 23 ft, we need to divide 280 by 23 to obtain the yield in gmp/ft as shown below:

[tex]Y=\frac{280gpm}{23ft} \\\\Y=12.2 \frac{gpm}{ft}[/tex]

Best regards!

Answer:

Differences between Orbit and Orbitals

Orbit

An orbit is the simple planar representation of an electron.

It can be simply defined as the path that gets established in a circular motion by revolving the electron around the nucleus

The shape of molecules cannot be explained by an orbit as they are non-directional by nature.

An orbit that is well-defined goes against the Heisenberg principle.

Orbital

An orbital refers to the dimensional motion of an electron around the nucleus in a three-dimensional motion.

An orbital can simply be defined as the space or the region where the electron is likely to be found the most.

The shapes of the molecules can be found out as they are directional by nature.

An ideal orbital agrees with the theory of Heisenberg’s Principles.

Answer:

true

Explanation:

it is because hormone determines various factors

Answer:

pump that is the answer hope its right

Answer:

I2(g)/I^-(aq)//H2 (g)/H^+(aq)

Explanation:

Let us remember that in every redox reaction, a specie is oxidized and a specie is reduced.

This means that one specie looses electrons while the other species gains electrons.

Considering the overall reaction; H2 + I2 = 2 HI

Oxidation half equation;

H2 (g) ------> 2H^+(aq) + 2e

Reduction half equation;

I2(g) + 2e ------> 2I^-(aq)

Line notation;

I2(g)/I^-(aq)//H2 (g)/H^+(aq)

Answer:

i) ∴∫[tex]\frac{dA}{A}[/tex]  = ∫ [tex]\frac{-1}{10} dt[/tex] ------ ( 1 )

ii) C = 4.303

Explanation:

Given data:

water in tank = 10 liters

concentration of salt flowing in = 0.5 liters/min

10 grams of salt is left in tank after 20 minutes

mixed water is drained at 1 liter per minute

i) Adequate mathematical model for the scenario

lets assume ; A( t ) amount of salt after t minute

A( t ) = 10grams   where t = 20 minutes

differentiate A(t)

dA / dt = ( rate in ) - ( rate out )

           = 0.5 * 0  - A/10

∴∫[tex]\frac{dA}{A}[/tex]  = ∫ [tex]\frac{-1}{10} dt[/tex] ------ ( 1 )

ii) hence;  In A = [tex]\frac{-1}{10} t + C[/tex]  -----  ( 2 )

at  t = 20 , A = 10grams

find C = In 10 + 2

          = 2.303 + 2 = 4.303

back to ( 2 )

In A = [tex]\frac{-t}{10} + 4.303[/tex]

∴ A = e [tex]\frac{-t}{10} + 4.303[/tex]

Answer:

Within three molecules of Ethane, it would have 6 carbon, and 18 hydrogen atoms in it.

Explanation:

Answer:It is the ground state of NA

Answer:

liquid

Explanation:

it's not plasma, solid, or gas

so I think liquid

Answer:

The answer is (a)

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