Enter x-values into the table below to determine function values for a function f(x)
for various inputs. Use the function values in order to determine lim f(x).

Answer:

the answer is 5 the probability of each colors is 5

Answer:

[tex]\frac{8}{x}[/tex]

Step-by-step explanation:

what is the sum 3/x+9+5/x-9

[tex]\frac{3}{x} + 9 + \frac{5}{x} - 9 =[/tex]     (add [tex]\frac{3}{x}[/tex] and [tex]\frac{5}{x}[/tex])

[tex]\frac{8}{x} + 9 - 9 =[/tex]            (solve 9 - 9 = 0)

[tex]\frac{8}{x}[/tex]                           ( your answer)

The probability of hitting the black circle as required is closer to 0 than. it is to 1.

The probability of hitting the white portion of the target as required is closer to 1 than it is to 0.

It follows from the task content that the probability of hitting the circle is dependent on the area of the black circle and the square shaped target.

Since the area of the square is; 9² = 81.

The area of the black circle is; π(1.5)² = 7.07.

Since the area of the black circle is less than half the area of the square; it follows that the the probability are as stated in the answer section above.

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Answer:

See below

Step-by-step explanation:

For the second step, [tex]\angle T\cong\angle R[/tex] by Alternate Interior Angles. The rest of the steps appear to be correct.

y=1/4x-2 is a perpendicular line and y=-4x+3 is a parallel line.

The equation y= -2 -4x in the form of slope intercept form y=mx+b is y=-4x-2.

Where m represents the slope and y intercept is -2.

The slope of a line perpendicular to another line is the negative reciprocal of the slope of the given line.

The negative reciprocal of -4 is 1/4.

Therefore, the slope of the perpendicular line is 1/4.

The perpendicular line is y=1/4x-2.

We know that the parallel lines have same slope.

y=-4x+3

Hence, y=1/4x-2 is a perpendicular line and y=-4x+3 is a parallel line.

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To find the image of point Q after applying the given translation rule, we need to apply the rule to the coordinates of point Q(-2, 6).

Using the translation rule (x, y) → (x + 4, y - 5), we can apply the rule to the coordinates of point Q:

Q' = (-2 + 4, 6 - 5)

= (2, 1)

Therefore, the image of point Q after the translation is Q'(2, 1).

The correct sum of numbers from 1 to n is 100.

We have,

Let's assume the correct sum of numbers from 1 to n is S.

According to the problem,

Juan made a mistake and added one of the numbers twice.

Let's call this number x.

The wrong sum that Juan obtained is 100.

The correct sum, S, can be expressed as the sum of numbers from 1 to n excluding the number x, plus the number x itself:

S = (1 + 2 + 3 + ... + (x-1) + (x+1) + ... + n) + x.

Since Juan added x twice, the wrong sum can be expressed as the sum of numbers from 1 to n without excluding any number: 100 = 1 + 2 + 3 + ... + (x-1) + x + (x+1) + ... + n.

We can subtract the correct sum equation (step 4) from the wrong sum equation (step 5) to find the value of x:

100 - S = (1 + 2 + 3 + ... + (x-1) + x + (x+1) + ... + n) - ((1 + 2 + 3 + ... + (x-1) + (x+1) + ... + n) + x).

Simplifying further, we get: 100 - S = x - x = 0.

From step 6, we see that 100 - S = 0, which means S = 100.

Therefore,

The correct sum of numbers from 1 to n is 100.

In conclusion, the correct sum of the numbers from 1 to n is 100.

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The complete question:

Juan wants to find the sum of the numbers from 1 to n, but in doing so he makes a mistake and adds one of these numbers twice, obtaining the wrong result 100.

To find a pair of values that make the linear equation 14x - y = -14 a true statement, we can choose any value for x and calculate the corresponding value of y.

Let's choose x = 2:

14(2) - y = -14

28 - y = -14

Now, we can solve for y:

-y = -14 - 28

-y = -42

Dividing both sides by -1 (to isolate y):

y = 42

Therefore, the pair of values (x, y) that make the equation true is (2, 42).

The surface area of the rectangular cuboid is S = 426 feet²

Given data ,

Let the surface area of the cuboid be S

Let the length of the rectangular cuboid be L = 12 feet

Let the width of the rectangular cuboid be W = 9 feet

Let the height of the rectangular cuboid be H = 5 feet

Now , The total surface area of the cuboid is given by the formula

Surface Area = 2 ( LH + LW + HW )

So, S = 2 ( 12 x 5 + 12 x 9 + 5 x 9 )

S = 2 ( 60 + 108 + 45 )

S = 2 x 213

S = 426 feet²

Hence , the surface area is S = 426 feet²

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The final simplified form of the equation using BEDMAS​ is:

76 + (55555co)/12 + TO + 47

To simplify the equation using the order of operations (BEDMAS), we'll follow these steps:

-12 - 11 - 10 - 9 - 8 - 7 + 6 + 5 + (co ÷ 12) × 55555 + 11 + 10 + 9 - 2 - 1 - TO - 9 - 10 - 11 + "12 × (4 ÷ 4) + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12

Let's simplify this step by step:

-12 - 11 - 10 - 9 - 8 - 7 = -57

-57 + 6 + 5 = -46

co ÷ 12 = co/12

co/12 × 55555 = (55555co)/12

(55555co)/12 + 11 + 10 + 9 = (55555co)/12 + 30

-2 - 1 = -3

TO - 9 - 10 - 11 = TO - 30

"12 × (4 ÷ 4) = 12

12 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 = 80

Now we can simplify the entire equation:

-46 + (55555co)/12 + 30 - 3 + TO - 30 + 80

To further simplify the equation:

46 + (55555co)/12 + 30 - 3 + TO - 30 + 80

Let's simplify the expression:

46 + (55555co)/12 + 30 - 3 + TO - 30 + 80

= 76 + (55555co)/12 + TO + 47

The final simplified form of the equation is:

76 + (55555co)/12 + TO + 47

Simplifying further depends on the value or expression assigned to "co" and "TO." Without specific values or expressions, we cannot provide a final simplified form of the equation.

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It is false that for a population of scores, the sum of the deviation scores is equal to expected value.

The sum of deviation scores is not equal to the expected value (EX) of a population of scores. The expected value represents the average value that we expect to obtain if we were to repeatedly sample from the population.

The sum of deviation scores is the sum of the differences between each score and the mean of the population. It provides information about the total variability in the data. While both concepts are related to the distribution of scores, they serve different purposes and are calculated differently.

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Answer: 38.4 + 216 = 254.4

Step-by-step explanation: The volume of the block at the top is 38.4 and the volume of the block at the bottom is 216 so add them together to make 254.4

Hope it helped :D

Answer: 40 is the arithmetic mean

Step-by-step explanation:

The net present value of the equipment is, $7,564.56.

Now, Based on the information , the net present value (NPV) of the equipment can be calculated using the formula:

NPV = (-Initial Investment) + (CF1 / (1+r)) + (CF2 / (1+r)) + ... + (CFn / (1+r)^n)

Where:

Initial Investment = $150,000

CF₁ - CFn = $22,000

r = 8%

Plugging in these values, we get:

NPV = (-$150,000) + ($22,000 / (1+0.08)) + ($22,000 / (1+0.08)) + ($22,000 / (1+0.08)) + ($22,000 / (1+0.08)) + ($22,000 / (1+0.08))

Simplifying the equation, we get:

NPV = -$150,000 + $20,370.37 + $18,828.67 + $17,405.10 + $16,088.71 + $14,871.71

Therefore, the net present value of the equipment is $7,564.56.

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Answer:

The answers are

Emperor Penguin and Artatic wolf

Answer:

1 2/3

Step-by-step explanation:

If the company has budgeted 6 2/3 hours to complete a project, and 1/4 of that time is spent on research, we can find the amount of time spent on research as follows:

Total time for the project = 6 2/3 hours

Time spent on research = (1/4) * (6 2/3) hours

We can simplify 6 2/3 to an improper fraction as follows:

6 2/3 = (6 x 3 + 2) / 3 = 20/3

Substituting this value into the equation above, we get:

Time spent on research = (1/4) * (20/3) hours

Multiplying the fractions, we get:

Time spent on research = 5/3 hours

We can convert this improper fraction to a mixed number as follows:

5/3 = 1 2/3

Therefore, the company plans to spend 1 2/3 hours on research.

Answer: C. not buying any phone

Part: $1.92 (the discount amount)

Percent: 30% (the discount percentage)

Base: The original price of the item before the discount and sale, which we can calculate as follows:

Let x be the original price of the item.

The discount of $1.92 represents 30% of the original price, so we can write:

0.30x = 1.92

Solving for x, we get:

x = 1.92 / 0.30

x = 6.40

Therefore, the base is $6.40 (the original price of the item before the discount and sale).

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The value of the given expression sin(45°) + cos(67°) - 4554 + 97 + 64555 + 755577652 - 6622 is approximately 755,642,129.099.

To find the value of the expression sin(45°) + cos(67°) - 4554 + 97 + 64555 + 755577652 - 6622, we can start by evaluating the trigonometric functions and then simplifying the arithmetic operations.

First, let's find the values of sin(45°) and cos(67°).

sin(45°) is equal to √2/2, approximately 0.7071, and cos(67°) is equal to 0.3919 (rounded to four decimal places).

Now, we can substitute these values into the expression:

0.7071 + 0.3919 - 4554 + 97 + 64555 + 755577652 - 6622

Next, let's perform the arithmetic operations:

0.7071 + 0.3919 = 1.099 (rounded to three decimal places)

1.099 - 4554 + 97 + 64555 + 755577652 - 6622

Simplifying further:

-4554 + 97 + 64555 = 60098

60098 + 755577652 - 6622 = 755642128

Finally, we have:

1.099 + 755642128 = 755642129.099

Note: The answer has been rounded to three decimal places for intermediate steps and provided as an approximate value due to rounding in trigonometric functions.

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Answer:

[tex]\mathrm{23cm,19.81cm^2}[/tex]

Step-by-step explanation:

[tex]\mathrm{Solution:}\\\mathrm{Let\ a=5cm,\ b=8cm\ and\ c=10cm}\\\mathrm{Let\ "P"\ denote\ the\ perimeter\ and\ "A"\ denote\ the\ area\ of\ the\ triangle.}\\\mathrm{Then,\ P=a+b+c=5+8+10=23cm}\\\mathrm{Also,\ Semiperimeter(s)=\frac{P}{2}=\frac{23}{2}=11.5}\\[/tex]

[tex]\mathrm{Now,}\\\mathrm{Area\ of\ triangle=\sqrt{s(s-a)(s-b)(s-c)}}\\\mathrm{=\sqrt{11.5(11.5-5)(11.5-8)(11.5-10)}}\\\mathrm{=\sqrt{11.5\times 6.5\times 3.5\times 1.5}}\\\mathrm{=19.81cm^2}\\\mathrm{So,\ the\ perimeter\ of \ the\ triangle\ is\ 23cm\ and\ area\ is\ 19.81cm^2.}[/tex]

He started walking the dog at the time 12:30 p.m.

We know that Dakota completed hera chores at 1:32 p.m. and that she spent a total of 48 minutes doing them.

That means she must have started her chores at:

⇒    1:32 p.m. - 48 minutes = 12:44 p.m.

We know that she walked the dog for 14 minutes.

We want to find out what time she started walking the dog,

so subtract 14 minutes from the time she started doing chores,

⇒ 12:44 p.m. - 14 minutes = 12:30 p.m.

Therefore,  

Dakota started walking the dog at 12:30 p.m.

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Answer:

Option D

Step-by-step explanation:

       (-5, -2)   ;   x₁ = -5  & y₁ = -2

        (5 , 4)    ;   x₂ = 5   & y₂ = 4

Plugin the points in the below mentioned formula and find the slope.

  [tex]\boxed{\bf slope =\dfrac{y_2-y_1}{x_2-x_1}}[/tex]

             [tex]\sf = \dfrac{4-[-2]}{5-[-5]}\\\\\\=\dfrac{4+2}{5+5}\\\\=\dfrac{6}{10}\\\\=\dfrac{3}{5}[/tex]

Equation of slope-intercept form: y =mx + b

Here, m is the slope and b is the y-intercept.

     [tex]\sf y = \dfrac{3}{5}x + b[/tex]

  The line is passing through (5, 4). So, substitute the points in the equation and find the y-intercept.

           [tex]4 =\dfrac{3}{5}*5 + b\\\\\\4=3+b\\\\[/tex]

      4 - 3 = b

            b = 1

Slope intercept form of the equation:

            [tex]\sf y = \dfrac{3}{5}x + 1[/tex]

The solution of the expression is,

a) 3,724

b) 2,784

We have to given that,

a) Divide 70,756 by 19.

b) Subtract 940 from your answer to part a).​

Now, We can simplify as,

a) Divide 70,756 by 19.

⇒ 70,756 ÷ 19

⇒ 3,724

And, Subtract 940 from your answer to part a).​ that is, 3724

⇒ 3724 - 940

⇒ 2,784

Therefore, The solution of the expression is,

a) 3,724

b) 2,784

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Answer:

(x,y)=(2,0)

Step-by-step explanation:

Multiply top equation by 4 and bottom equation by 5

-5y = 10 - 5x --> -20y = 40 - 20x

-2y = 8 - 4x --> -10y = 40 - 20x

Subtract both equations

-10y = 0

y = 0

Substitute y=0 into one of the original equations to find x

-5y = 10 - 5x

-5(0) = 10 - 5x

0 = 10 - 5x

5x = 10

x = 2

Therefore, the solution is (x,y)=(2,0)

The correct answer is option (C): 0.487

If the typical duration for a customer to receive their food in a dining establishment is 15 minutes, it is possible to utilize the exponential function to estimate the likelihood of obtaining the meal within the initial 10 minutes.

The probability density function (PDF) that characterizes the exponential distribution is expressed as f(x) = (1/µ) * e^(-x/µ), where µ denotes the mean or average value.

The average duration in this scenario is 15 minutes, denoted as µ. Our goal is to determine the probability of X falling between the limits of a and b, where a is set at 0 and b is set at 10.

To calculate this probability, we need to integrate the PDF from a to b:

P(0 ≤ X ≤ 10) = ∫[tex][0 to 10] (1/15) * e^(-x/15) dx[/tex]

Integrating this expression gives us:

P(0 ≤ X ≤ 10) = [tex][-e^(-x/15)] from 0 to 10[/tex]

Plugging in the values, we get:

P(0 ≤ X ≤ 10) = [tex][-e^(-10/15)] - [-e^(0/15)][/tex]

Simplifying further:

P(0 ≤ X ≤ 10) = [tex]-e^(-2/3) + 1[/tex]

Using a calculator, we can evaluate this expression:

P(0 ≤ X ≤ 10) ≈ 0.487

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In both cases considered below, we have either x = m or m ∉ x. Therefore, m is an ∈-minimal element of X.

Let's consider a nonempty subset X ⊆ ℕ.

To prove that X has an ∈-minimal element, we can follow the given hint: pick an arbitrary n ∈ X and look at the intersection of X with the set {0, 1, 2, ..., n}.

Let's denote this intersection as Y = X ∩ {0, 1, 2, ..., n}.

We can observe the following:

Y is a nonempty subset of ℕ: Since X is nonempty, and we are intersecting it with a nonempty set {0, 1, 2, ..., n}, the resulting set Y = X ∩ {0, 1, 2, ..., n} will also be nonempty.

Y is a finite subset of ℕ: The set {0, 1, 2, ..., n} is finite, and the intersection of any two finite sets is also finite. Therefore, Y is a finite subset of ℕ.

Since Y is a nonempty and finite subset of ℕ, it must have a minimal element with respect to the element hood relation ∈.

Let's denote this minimal element as m, where m ∈ Y.

Now, we need to show that m is an ∈-minimal element of X, i.e., for any x ∈ X, either x = m or m ∉ x.

Consider an arbitrary element x ∈ X. We know that x ∈ Y because Y is defined as the intersection of X with {0, 1, 2, ..., n}. Since m is the minimal element of Y, we have two cases:

Case 1: If x = m, then we have x = m, satisfying the condition.

Case 2: If x ≠ m, then x ∈ Y implies that x ∉ {0, 1, 2, ..., n} \ {m}. In other words, x ∉ {0, 1, 2, ..., n} or x = m. But x ≠ m, so x ∉ {0, 1, 2, ..., n} must hold. Since x ∉ {0, 1, 2, ..., n}, we can conclude that m ∉ x.

In both cases, we have either x = m or m ∉ x. Therefore, m is an ∈-minimal element of X.

Since we picked an arbitrary n ∈ X and showed that X ∩ {0, 1, 2, ..., n} has an ∈-minimal element, we have demonstrated that every nonempty subset X ⊆ ℕ has an ∈-minimal element.

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Step-by-step explanation:

Tess's expression is NOT equivalent because she forgot to include the - sign when multiplying -7 and -4.

Bernette's expression is NOT equivalent because she did 2-7 first which is not correct. Since the -7 is connected to the parenthesis, she needs to fully distribute the -7 into the parenthesis before including the 2.

Lucy's expression IS equivalent because she factored it correctly and distributed the -7 into the parenthesis.

Hello!

16 - (2.5 + 4.25) = 9.25

To rewrite equation [tex]x^2 + 5x + 6[/tex] as[tex]x^2 + rx + sx + 6[/tex], we need to choose suitable values for r and s that satisfy r + s = 5.

To rewrite the quadratic expression[tex]x^2 + 5x + 6[/tex] as equivalent to[tex]x^2 + rx + sx + 6[/tex] , we need to find the values of r and s that satisfy the equation.

Let's start by expanding [tex]x^2 + rx + sx + 6:[/tex]

[tex]x^2 + rx + sx + 6 = x^2 + (r + s)x + 6[/tex]

We can see that the coefficient of x in the original expression is 5, and in the rewritten expression, it is (r + s). Therefore, we want to find values for r and s such that r + s = 5.

Next, we need to consider the constant term. In the original expression, the constant term is 6, and in the rewritten expression, it is also 6. Therefore, we want r, s, and 6 to satisfy the equation.

Since r + s = 5, we can solve for one variable in terms of the other. For example, if we choose r = 3, then s = 2 to satisfy the equation. Alternatively, we could choose r = 4 and s = 1, or any other combination that adds up to 5.

So, rewriting [tex]x^2 + 5x + 6[/tex] as [tex]x^2 + rx + sx + 6[/tex]can be achieved by choosing suitable values for r and s that satisfy r + s = 5.

For example, if we choose r = 3 and s = 2, the equivalent expression would be [tex]x^2 + 3x + 2x + 6.[/tex]

In summary, to rewrite[tex]x^2 + 5x + 6[/tex]as [tex]x^2 + rx + sx + 6[/tex], we need to choose suitable values for r and s that satisfy r + s = 5.

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