Sorry but I can't help you cuz the words you use makes no sens if you are going to ask a question pls do and dont joke around about it thank you very much and have a great day! ^^
Draw a schematic diagram of a circuit consisting of a battery of five 2 V cells, a 5 ohm resistor, a 10 ohm resistor, a 15 ohm resistor, an ammeter and a plug key, all connected in series. Calculate the electric current passing through the above circuit when the key is closed..
Please help ASAP..
Answer:
Current = 0.33 AExplanation:
For diagram refer the attachment.It is given that five cells of 2V are connected in series, so total voltage of the battery:
[tex]\dashrightarrow \: \: \sf V = 2 \times 5 = 10 V [/tex]
Three resistor of 5[tex]\Omega[/tex], 10[tex]\Omega[/tex], 15[tex]\Omega[/tex] are connected in Series, so the net resistance:
[tex]\dashrightarrow \: \: \sf R_{n} = R_{1} + R_{2} + R_{3}[/tex]
[tex]\dashrightarrow \: \: \sf R = 5 + 10 + 15 [/tex]
[tex]{ \pink{\dashrightarrow \sf \: \: { \underbrace{R = 30 \: \Omega}}}}[/tex]
According to ohm's law:
[tex]\dashrightarrow \sf\: \: V = IR [/tex]
[tex]\dashrightarrow \sf \: \: I = \dfrac{V}{R}[/tex]
On substituting resultant voltage (V) as 10 V and resultant resistant, as 30 [tex]{\pmb{\sf{\Omega}}}[/tex] we get:
[tex]\dashrightarrow \sf \: \: I = \dfrac{10V}{30\Omega}[/tex]
[tex]{ \pink{\dashrightarrow \sf \: \: { \underbrace{I = 0.33 A}}}}[/tex]
[tex]\therefore[/tex]The electric current passing through the above circuit when the key is closed will be 0.33 A
Answer:
Resistance = 5 + 10 + 15 = 30
Explanation:
Current= 0.33 Amperes
A narrow beam of ultrasound waves reflects off a liver tumor as illustrated. The speed of sound in the liver is 10\% less than in the surrounding medium. What is the depth of the tumor
When the narrow beam of ultrasound waves reflects off a liver tumor, the depth of the tumor is found to be 6.30 cm.
What is Snell's law?Snell's law states that the ratio of the sin of the angle of incidence to the angle of reflection is equal to the ratio of the speed of the wave in the first medium to the speed of the wave in the second medium.
[tex]\dfrac{sin\:i}{sin\:r} =\dfrac{v_{1} }{v_{2} }[/tex]
Where, i represents the angle of incidence and r is the angle of reflection.
Given the speed of sound in the liver is 10% less than in the medium, so
[tex]\dfrac{v_{liver} }{v_{medium} }=0.900[/tex]
According to the figure, the angle of incidence is 50°, then from the Snell's law, we have
[tex]sin\:r=(\dfrac{v_{liver} }{v_{medium} } )\times sin\:i\\\\r=sin^{-1} [(0.900)sin 50][/tex]
The angle of reflection comes out to be
r = 43.6°
From the law of reflection,
[tex]d =\dfrac{12\:\rm cm}{2} =6\:\rm cm[/tex]
The depth of the tumor is
[tex]h=\dfrac{d}{tan\:r} =\dfrac{6}{tan\:43.6} \\\\h=6.30\:\rm cm[/tex]
The depth of the tumor in the liver is 6.30 cm.
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a car is traveling at 20 km in 15 minutes. What is its average velocity
Vector Q is 0.321 m long in a
123° direction. Vector S is
0.876 m long in a -32.1°
direction.
magnitude (m)
Find the magnitude of their vector sum
The magnitude of the vector sum of Q and S is determined as 0.6 m.
Resultant vector of Q and S
The magnitude of the vector sum of Q and S is determined from their resultant vector.
Qx = Qcosθ
Qy = Qsinθ
Qx = 0.321 x cos(123) = -0.175 m
Qy = 0.321 x sin(123) = 0.269 m
Sx = 0.876 x cos(-32.1) = 0.742 m
Sy = 0.876 x sin(-32.1) = -0.466 m
Qx + Sx = -0.175 m + 0.742 m = 0.567 m
Qy + Sy = 0.269 m - 0.466 m = -0.197 m
Resultant vectorR = √[(0.567)² + (-0.197) ²]
R = 0.6 m
Thus, the magnitude of the vector sum of Q and S is determined as 0.6 m.
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Motion is a change in
1.Time
2.Speed
3.Position
4.Velocity
Motion is a change in position measured by distance and time.
A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball initially moving in the same direction at a spe
Final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.
What is conservation of momentum?Momentum of an object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity. By the law of conservation of momentum,
[tex]m_1u_1 + m_2u_2 = (m_1+m_2)v[/tex]
Here, (m) is the mass, (u) is initial velocity before collision, v is final velocity after collision and (subscript 1, and 2) are used for body 1 and 2 respectively. Rewrite the formula for final velocity as,
[tex]v=\dfrac{m_1u_1 + m_2u_2}{(m_1+m_2)}[/tex]
A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s, has a head-on collision with a 0. 090-kg ball, initially moving in the same direction at a speed of 3.44 m/s. Thus, the initial velocity of the second ball is,
[tex]v_{2f}=5.82+3.44+v_{1f}\\v_{2f}=2.38+v_{1f}[/tex]
Let v1f is the final velocity of first ball. Thus, the initial velocity of the first ball is,
[tex]v_{1f}=\dfrac{(0.060)(5.82) + (0.090)(3.44-2.38)}{(0.060)+(0.090)}\\v_{1f}=2.964\rm\; m/s[/tex]
Thus, final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.
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When white light shines on a thin film of soap, light is reflected from:.
When white light shines on a thin film of soap, light is reflected from back surface of the film only.
What is doppler shift?Doppler Shift is the change in frequency of sound based on the observer’s point of view.
When white light falls on a thin film of soap, light gets reflected and refracted inside the soap. This results in refraction of the reflected light rays.
When white light shines on a thin film of soap, light is reflected from the back surface of the film only.
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What is the speed of a wave with a frequency of 2 Hz and a wavelength of 87 m? 0. 023 m/s 43. 5 m/s 89 m/s 174 m/s.
why is the battery run flat with reference to the energy transformations that take place
Answer:
Rechargeable batteries can still go flat after repeated use because the materials involved in the reaction lose their ability to charge and regenerate
Explanation:
they go flat because they a rechargeable and sometimes don't always work
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A pendulum takes 60 seconds to swing through 2 complete cycles.
A. How long does it take to complete one cycle?
B. What is its period?
C. What is its frequency?
Starting at a position of 10m [W] of your car, you run to a position of 150m [W] of your car in 35s. What was your
velocity?
Answer:
4 m/s
Explanation:
you moved 140 meters in 35 seconds
v = 140 / 35 = 4 m/s
A package is dropped from a helicopter moving upward at 15 m/s
The distance the package above the ground when it was released, s ≈ 530 meters
What are kinematic equations?The kinematic equation of motion gives the interrelationships of the variables of motion.The correct option for the distance the package above the ground when it was released, is the third option;
It is given that:
The velocity of the helicopter from which the package was dropped = 15 m/s
The time it takes the package to strike the ground = 12 seconds
The required parameter:
The height of the package from the ground when it was dropped
The kinematic equation of motion relating distance, s, time, t, acceleration due to gravity, g, initial velocity, u, and final velocity, v, is applied as follows;
The package continues the upward motion for some time, t₁, given as follows;
Upward motion of the package
v = u - g·t₁
v = 0 at highest point reached by the package;
Therefore;
0 = 15 m/s - 9.81 m/s² × t₁
t₁ = 15 m/s/(9.81 m/s²) ≈ 1.5295022 seconds
The time the package takes to return to the initial starting point, t₂ = t₁
The time the package falls after returning to the point it was dropped, t₃, is given as follows;
t₃ = t - (t₂ + t₁) = t - 2 × t₁
∴ t₃ = 12 s - 2 × 1.5295022 s ≈ 8.940996 s
From the symmetry of the motion of a projectile, the velocity of the package when returns to its staring point where it was dropped = u (Downwards) = 15 m/s
The distance the package falls, s, which is the distance the package above the ground when it was released, is given as follows;
s = u·t + (1/2)·g·t²
s = 15× 8.940996 + (1/2) × 9.81 × 8.940996² = 526.22755346 ≈ 530
The distance the package falls, s ≈ 530 m = The height of the
The distance the package above the ground when it was released, s ≈ 530 meters
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Consider a pendulum of length 3. 171 m. The acceleration of gravity is 9. 832 m/s2. A) what is its period at the north pole?answer in units of s
The period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.
What is time period of pendulum?Pendulum is the body which is pivoted to a point and perform back and forth motion around that point by swinging due to the influence of gravity.
The time period of a pendulum is the time taken by it to complete one cycle of swing left to right and right to left.
It can be given as,
[tex]T=2\pi \sqrt{\dfrac{L}{g}}[/tex]
Here, (g) is the gravitational force of Earth and (L) is the length of the pendulum.
A pendulum of length 3.171 m. The acceleration of gravity is 9.832 m/s2. The period at the north pole is,
[tex]T=2\pi \sqrt{\dfrac{3.171}{9.832}}\\T=3.57\rm\; s[/tex]
Thus, the period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.
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plss answer my question i really need it
Can someone please answer this, ill give you brainliest Would be very appreciated.
Answer:
See below ~
Explanation:
ice wedging : mechanical weathering
oxidation : chemical weathering
abrasion : mechanical weathering
plant roots : biological weathering
hydrolysis : chemical weathering
Two cats are sitting on a 30 m hill. One cat
has a mass of 4 kg and the other 6 kg.
Which cat has greater potential energy?
Answer:
Cat with 6 kg sitting on a 30 meter hill has greater potential energy.
Explanation:
gravitational potential energy (J) = mass (kg) × gravitational field × height (m)
Note:gravitational field in Earth is 10 N/kg = fixed unit
Given:1st Cat: 4 kg
2nd Cat: 6 kg
Both of their height is 30 meters.
Solve for g.p.e:1st cat = mgh = 4 × 10 × 30 = 1200 Joules
2nd cat = mgh = 6 × 10 × 30 = 1800 Joules
A particle moves along a line so that at time t0 its acceleration is given by a(t) = 12t
The value of distance covered by the particle during the first 3 second which moves along a line so that its acceleration is 12t, is 54 ft.
What is the acceleration of an object?Acceleration of an object is the rate of change of velocity of the object per unit time.
A particle moves along a line so that at time t0 its acceleration is given by [tex]a(t) = 12t\rm\; ft/sec^2[/tex]
The value of distance covered by the particle during the first 3 second has to be obtained.
Acceleration is the change in velocity (v) per unit time. Thus, the above equation can be written as,
[tex]a(t) = 12t\rm\; ft/sec^2\\\dfrac{dv}{dt}= 12t\rm\; ft/sec^2[/tex]
The equation can be solved as further.
[tex]\dfrac{dv}{dt}= 12t\\v= 6t^2+v_0\rm[/tex]
Here, the vo is the initial velocity which is equal to zero.
[tex]v=6t^2[/tex]
Velocity is the change in distance(s) per unit time. Thus, the above equation can be written as,
[tex]\dfrac{ds}{dt}=6t^2\\\dfrac{ds}{dt}=2t^3+s_0[/tex]
Here, the so is the initial position which is equal to zero. Thus,
[tex]s=2t^3[/tex]
Put the value of time t=3.
[tex]s=2(3)^3\\s=54\rm\; ft[/tex]
Thus, the value of distance covered by the particle during the first 3 second which moves along a line so that its acceleration is given by a(t) = 12t is 54 ft.
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what is a acceleration of a bicycle that goes from 3m/s to 1 m/s in 2 seconds?
Answer:
1m/s²
Explanation:
a = (v2 - v1) / t
= (3 - 1) / 2
= 1m/s²
The acceleration of the center of mass of the blocks-string-pulley system has magnitude of a_cm
The acceleration of the center of mass of the blocks-string-pulley system has magnitude equal to the ratio of difference to the sum of masses of block multiplied with gravitational acceleration.
What is center of mass?The center of mass of a object or for a system of object is the point, where the center of distribution of mass in space. The center of mass for the two bodies can be given as,
It can be given as,
[tex]x_{cm}=\dfrac{m_1x_1+m_2x_2}{m_1+m_2}[/tex]
Here, (m) represents the mass and (x) represents the distance.
The acceleration of the center of mass of the blocks-string-pulley system has magnitude of a_cm has to be find out.
The image of the blocks-string-pulley system is attached below. The acceleration of this system is,
[tex]\vec a_{cm}=\left(\dfrac{m_1-m_2}{m_1+m_2}\right)g[/tex]
Thus, the acceleration of the center of mass of the blocks-string-pulley system has magnitude equal to the ratio of difference to the sum of masses of block multiplied with gravitational acceleration.
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Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is
The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.
What is pascal law?Pressure applied to a closed system of fluid will be transfer at each point of the fluid and the boundaries of the system.
Let suppose at the two point of such system the input force apllied is F₁ and output force we get is F₂. The area of this points is A₁ and A₂ respectively. As the pressure at both point is same. Then by the pascal law,
[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\[/tex]
In case of radius,
[tex]\dfrac{F_1}{\pi r_1^2}=\dfrac{F_2}{\pi r_2^2}\\\\\dfrac{F_1}{r_1^2}=\dfrac{F_2}{ r_2^2}[/tex]
Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. Thus,
[tex]r_1=2.67\rm\; cm[/tex]
[tex]r_2=20.0\rm\; cm[/tex]
The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is The force applied on second piston is,
[tex]F_2=mg\\F_2=2000\times9.81\\F_2=19620 \rm\; N[/tex]
Put the values in the above formula,
[tex]\dfrac{F_1}{2.67^2}=\dfrac{19620}{20^2}\\F_1=\dfrac{19620\times2.67^2}{20^2}\\F_1\approx 350\rm\; N[/tex]
Thus, the downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.
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A wave hits a wall as shown. A brick wall with a green arrow pointing to the wall from below and right at a shallow angle. Another green arrow starts where the first arrow touched the wall and goes up and left at the same shallow angle. As the wave interacts with a wall, which kind of wave interaction is shown? absorption diffraction refraction reflection
Answer:
reflection
Explanation:
Answer: Reflection
Explanation: I have my ways :>
The Andromeda Galaxy (our nearest spiral neighbor) has spectral lines that show a blue shift. From this we may conclude that:
The universe is the collection of galaxies, The Andromeda Galaxy has spectral lines with blue shift. The conclusion is that the Universe has stopped expanding.
What is Andromeda Galaxy?The Andromeda Galaxy is the nearest spiral neighbor that has spectral lines showing a blue shift.
Therefore, this concludes that, the Universe has stopped expanding. This galaxy is slowly shifting towards us.
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A negatively charged balloon has 3. 5 µc of charge. How many excess electrons are on this balloon?
The number of electrons running in a stream comprises the charge. The excess electrons on this balloon with the given charge are 2.9 × 10¹³.
What is the charge?The charge is the number of electrons flowing in the stream of current times the charge on that electrons.
Q= n×e
The charge on the electrons e =1.6×10⁻¹⁹ C and the given charge on the balloon is 3.5μC = 3.5×10⁻⁶ C
the number of the excess electrons will be
[tex]n=\dfrac{3.5\times10^{-6} C}{1.6\times10^{-19} C}=2.19\times10^{13}[/tex]
The excess electrons on this balloon with the given charge are 2.9 × 10¹³.
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2 Name the device in a car that we use to change the speed of the car
Answer:
Speedometer
Explanation:
Have a good day! :3
Help!
11. A string vibrates at a frequency of 15 Hz. What is its period?
12. A speaker vibrates at a frequency of 292 Hz. What is its period?
13. A swing has a period of 12 seconds. What is its frequency?
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
As we know, period (t)of a wave and it's frequency (f) are Reciprocal of each other, so if one is know then we can just reverse the order to get the other one.
that is :
[tex]\qquad \sf \dashrightarrow \: frequency = \dfrac{1}{period} [/tex]
Now, let's move on to problems ~
# 11. f = 15 hertz, t = ?
[tex]\qquad \sf \dashrightarrow \: t = \dfrac{1}{15} \: \: sec[/tex]
[tex]\qquad \sf \dashrightarrow \: t \approx0.067 \: \: sec[/tex]
#12. f = 292 hertz, t = ?
[tex]\qquad \sf \dashrightarrow \: t = \dfrac{1}{292} \: \: sec[/tex]
[tex]\qquad \sf \dashrightarrow \: t \approx0.0034 \: \: sec[/tex]
#13. t = 12 seconds, f = ?
[tex]\qquad \sf \dashrightarrow \: f= \dfrac{1}{12} \: \: hertz[/tex]
[tex]\qquad \sf \dashrightarrow \: f \approx0.083 \: \: hertz[/tex]
We know that, frequency = reciprocal of the period of time an object swings or vibrates at. Therefore,
[tex]\tt\:FORMULA \downarrow\\\\\star\boxed{\mathfrak{Frequency = \frac{1}{period \: of \: time}}}[/tex]
Now, let's solve the questions by using this formula.
[tex]\rule{150pt}{2pt}[/tex]
11. Frequency = 15 Hz
Period = ?
[tex]\sf\:Frequency = \frac{1}{period}\\\sf\:15 = \frac{1}{period}\\\boxed{\bf\:period = \frac{1}{15} = 0.67 \: s}[/tex]
[tex]\rule{150pt}{2pt}[/tex]
12. Frequency = 292 Hz
Period = ?
[tex]\sf\:Frequency = \frac{1}{period}\\\sf\:292 = \frac{1}{period}\\\boxed{\bf\:period = \frac{1}{292} = 0.0034 \: s}[/tex]
[tex]\rule{150pt}{2pt}[/tex]
13. Period = 12 s
Frequency = ?
[tex]\sf\:Frequency = \frac{1}{period}\\\sf\:Frequency = \frac{1}{12}\\\boxed{\bf\:Frequency = 0.083 \: Hz}[/tex]
[tex]\rule{150pt}{2pt}[/tex]
Note:The SI units of,
Frequency = Hertz (Hz)Period of time = Second (s / sec)[tex]\rule{150pt}{2pt}[/tex]
Question 8 of 10
What type of optical device can be used to project an image onto a screen?
© A. Any mirror
• B. A convex lens
• C. A convex mirror
•
D. Any lens
Answer:
The correct answer is the Convex lens. An image is formed when a ray of light coming from a point intersects at another point. The image is formed by the real intersection of light. The image is formed by the virtual intersection of Light.
here is the site : textbook.com
The current in the electron beam of a typical video display terminal is 200 µa. How many electrons strike the screen each minute?
The number of electrons strike the screen each minute when thee current in the electron beam of a typical video display terminal is 200 µa is 7.5×10¹⁶.
How to calculate electric charge?Electric charge is equal to the product of electricity current flowing and the total time. It can be given as,
[tex]q=It[/tex]
Here, I is current and t is time.
The current in the electron beam of a typical video display terminal is 200 µa for one minute. Thus, the total charge is,
[tex]q=200\times10^{-6}\text{ A}\times(60\text{ s})\\q=0.012\rm \;C[/tex]
The number of electron flow is the ratio of total charge to the charge of one electron. The charge on one electron is 1.6×10⁻¹⁹ C. Thus, the number of electron is,
[tex]n=\dfrac{0.012}{1.6\times10^{-19}}\\n=7.5\times10^{16}[/tex]
Thus, the number of electrons strike the screen each minute when the current in the electron beam of a typical video display terminal is 200 µa is 7.5×10¹⁶.
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What effect does the pendulum have on the time period if the length of string increases
Answer:
If the length of the pendulum string increases, the period of time increases
Explanation:
The period of a simple pendulum is directly proportional to the square root of length of the pendulum
Directions: identify the input work and output work in the different situations.
1. A cyclist is pedaling on his bicycle.
2. You exert force to move a rake.
3. You sweep the dry leaves in your garden using bamboo.
4. Lifting a handless wheelbarrow.
5. Ben lifts the 50 kgs weight of barbel.
Answer:
it would have to be 1 or maybe 2
at 20° c, 33 meters of copper wire has a restaurants of 0.6 ohms. what is the resistance of 165 meters?
Resistance for 165 metres is 3 ohms.