During which stage of sleep, also known as delta sleep, would a person have slow breathing and be difficult to wake.
A.
between stages 1 and 2 of non–rapid-eye-movement sleep
B.
in stage 4 of non–rapid-eye-movement sleep
C.
near the end of stage 3 of rapid-eye-movement sleep
D.
in stage 3 of non–rapid-eye-movement sleep

Answer:

0 J

Explanation:

Given data

force F=1.46N

mass m=0.1kg

time t= 3min

distance= 0 meters----"the object did not move"

We know that work-done is given as

work= Force * distance moved

Work= 1.46*0

work =0joules

We understand that when this is no distance move, then there is no work done, for work to be done, the object must move through a distance

Answer:

120 north west

Explanation:

Answer:

20 m/s

Explanation:

velocity after 2 sec.  

v=40+(−10)t

=40−10∗2=20m/s

We have that for the Question "A ball is thrown up in the air with an initial velocity of 40m/s what is the balls velocity after 2 seconds?" it can be said that the balls velocity after 2 seconds

From the question we are told

A ball is thrown up in the air with an initial velocity of 40m/s what is the balls velocity after 2 seconds?

Generally the Newtons equation for the  Motion  is mathematically given as

[tex]v=u+at\\\\Therefore\\\\v=40+9.8*2.8\\\\v=67.44m/s\\\\[/tex]

Therefore

the balls velocity after 2 seconds

v=67.44m/s

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Answer:

dS/dt = 0.33 cm²/min

Explanation:

Volume of sphere is given by;

V = (4/3)πr³

We are told that gas is escaping from a spherical balloon 4 cm³ per minute. Thus; dV/dt = 4 cm³/min

Now, let's find the rate at which the radius is changing.

dr/dt = (dV/dt) ÷ (dV/dr)

Now, dV/dr = 4πr²

Thus;

dr/dt = 4/(4πr²)

dr/dt = 1/(πr²)

Now, surface area of sphere is given by;

S = 4πr²

Thus, dS/dr = 8πr

Now, let's find the rate at t which area is shrinking.

dS/dt = (dS/dr) × (dr/dt)

Plugging relevant terms, we have;

dS/dt = 8πr × 1/(πr²)

dS/dt = 8/r

At r = 24 cm, we have;

dS/dt = 8/24

dS/dt = 1/3

dS/dt = 0.33 cm²/min

Answer:

Explanation:

We have that the normal force acting on a mountain goat that weighs 550 N and is standing on such a slope is

N=275N

From the question we are told

Generally the equation for the normal force acting on a mountain goat   is mathematically given as

N=mgcos

N=550*cos60

N=275N

Therefore

The normal force acting on a mountain goat that weighs 550 N and is standing on such a slope is

N=275N

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Answer:

The value is  [tex]N = 6051 \ turns[/tex]

Explanation:

From the question we are told that

   The current is  [tex]I = 6.67 \ A[/tex]

  The length is  [tex]l = 13.6 \ cm = 0.136 \ m[/tex]

  The magnetic field is  [tex]B = 0.373 \ T[/tex]

Gnerally the number of turn per unit length is mathematically represented as

      [tex]n = \frac{B}{\mu_o * I}[/tex]

Here [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4*\pi*10^{-7}[/tex]

So

=>    [tex]n = \frac{0.373}{ 4\pi * 10^{-7} * 6.67 }[/tex]

=>    [tex]n = 44496 \ turns /m[/tex]

Generally the number of turn is mathematically represented as

       [tex]N = n * l[/tex]

=>  [tex]N = 44496 * 0.136[/tex]

=>  [tex]N = 6051 \ turns[/tex]

The no of turns dos this solenoid contains will be 6051 turns.

A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire. Which generates a magnetic field when an electric current is passed through the coil .

The given data in the problem is;

B is the current =6.67 A

L is the length =13.6 cm=0.136 m

B is the magnetic field =0.373 T  

The number of turns per unit length is found as;

[tex]\rm n= \frac{B}{\mu_0I} \\\\ \rm n= \frac{0.373}{4 \times 3.14 \times 10^{-7}\times 6.67} \\\\ \rm n = 44496 \ turn /m[/tex]

The number of turns is found as;

[tex]\rm N=n\times l \\\\ \rm N=44496\times 0.136 \\\\ \rm N=6051 \ turns[/tex]

Hence the no of turns dos this solenoid contains will be 6051 turns.

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Answer:

A. stress

Explanation:

Hope this helped. Have an amazing day/night!!

We have that for the Question "elastic limit is equal to" it can be said that

This speaks to a body retaining it shape after changes occur

From the question we are told

elastic limit is equal to

(a) stress

(b)strain

(c) young's modulus

(d)modulus of rigidity

Where

Where

Stress is the force acting on a material

and

strain

The effect of  force acting  on a material

Young's modulus

This speaks to a body retaining it shape after changes occur

Modulus of rigidity

m=sheer stress/shear strain

Now having that

Elastic limit is a point where an elastic body does not return to its original shape

The option chosen is'

Young's modulus

This speaks to a body retaining it shape after changes occur

Option C

​

Generally the equation for the   is mathematically given as

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Explanation:

acceleration is inversely proportional to mass so acceleration will decrease if mass increases

If the mass of the system will increase, then the acceleration of the system will decrease because mass and acceleration are inversely proportional to each other.

In mechanics, acceleration refers to the rate at which the velocity of an object changes in relation to time. The magnitude of accelerations as a vector. The acceleration of an object depends on the direction of the net force acting on it.

It is a vector quantity because acceleration has both a magnitude and a direction. Additionally, velocity is a vector quantity. The change in the vector of velocity during a period of time divided by the period of time is the definition of acceleration.

There are several types of acceleration :

When the mass of the system will increase it will become heavy, and it will affect the acceleration of the body because due to this the acceleration of the body will decrease because both mass and acceleration are inversely proportional to each other.

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Answer:

Explanation:

We know that the relationship for the impulse and momentum is given as

Ft=mv

given data

mass m=0.04kg

t= 26.5ms= 26.5/1000= 0.0265seconds

velocity v= 41.3m/s

substituting in the expression we have

Ft=mv

make F subject of formula we have

F=mv/t

F=(0.04*41.3)/0.0265

F=1.652/0.0265

F=62.33N

Answer:

Approximately [tex]28.3\; \rm kg[/tex], assuming that the spring was pulled horizontally.

Explanation:

Let [tex]k[/tex] denote the spring constant of this spring. Calculate the size of tension in this spring that corresponds to the [tex]\Delta x = 0.88\; \rm m[/tex] stretch:

[tex]F(\text{tension}) = k\cdot \Delta x = 45\; \rm N \cdot m^{-1} \times 0.88\; \rm m = 39.6\; \rm N[/tex].

(The negative sign is ignored.)

If the spring is pulled horizontally, then the tension that the spring exerts would be the only unbalanced force on this object. The net force n this object would be equal to the tension that the spring had exerted: [tex]39.6\; \rm N[/tex].

Newton's Second Law of motion suggests the following relation between the net force [tex]\sum F[/tex] on the object, the mass [tex]m[/tex] of the object, and the acceleration [tex]a[/tex] of the object:

[tex]\sum F = m \cdot a[/tex].

For this object, [tex]a = 1.4\; \rm m \cdot s^{-2}[/tex]. It has been found that the net force on this object is [tex]\sum F = 39.6\; \rm N[/tex]. Rearrange the original equation [tex]\sum F = m \cdot a[/tex] and solve for [tex]m[/tex], the mass of this object:

[tex]\displaystyle m = \frac{\sum F}{a} = \frac{39.6\; \rm N}{1.4\; \rm m \cdot s^{-2}} \approx 28.3\; \rm kg[/tex].

In other words (based on all these assumptions,) the mass of this object should be approximately [tex]28.3\; \rm kg[/tex].

Answer:

The CG is located higher than his original CG.

Explanation:

Centre of gravity (CG), in physics, an imaginary point in a body of matter where, for convenience in certain calculations, the total weight of the body may be thought to be concentrated. In a uniform gravitational field the centre of gravity is identical to the centre of mass, a term preferred by physicists.

 His CG is located higher than his original CG when he is standing without the sack of rice on his head.

A system is said to be in stable equilibrium if, when displaced from equilibrium, it experiences a net force or torque in a direction opposite to the direction of the displacement. A system is in unstable equilibrium if, when displaced, it experiences a net force or torque in the same direction as the displacement from equilibrium. A system is in neutral equilibrium if its equilibrium is independent of displacements from its original position. A marble on a flat horizontal surface is an example.

Answer:

I think A, a car shortly after a stoplight turns green OR if it's wrong it's B☺️

Complete question is;

A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glow, sending the light through a diffraction grating, and measuring the positions of first-order spectral lines on a detector 15.0 cm behind the grating. Unfortunately, she has lost the card that gives the specifications of the grating. Fortunately, she has a known compound that she can use to calibrate the grating. She heats the known compound, which emits light at a wavelength of 461 nm, and observes a spectral line 9.95 cm from the center of the diffraction pattern.

What is the wavelength emitted by compound B that have spectral line detected at position and 12.15 cm?

Answer:

λ ≈ 525 nm

Explanation:

The diffraction grating equation of n-th order is given by;

nλ = dsinθₙ

For 1st order, n=1. Thus;L, we have;

λ = dsinθ₁

We are told that the first-order spectral lines on a detector 15.0 cm behind the grating. Also that, she observes a spectral line 9.95 cm from the center of the diffraction pattern.

Therefore, the angle of the known compound's 1st order is given by the relation:

tanθ₁ = 9.95/15

tanθ₁ = 0.6633

θ₁ = tan⁻¹(0.6633)

θ₁ = 33.56º

We are told that the unknown compound emits light at a wavelength of 461 nm.

Thus, from the first order equation above, we have;

d = λ/sinθ₁

d = 461nm/sin(33.56º)

d = 461nm/0.55281

d ≈ 834nm

λ = dsinθ₁= 870nm sin(29.68º) = 431nm

Now, spectral line is given as 12.15 cm from the center of the diffraction pattern. Thus;

θ₁ = tan⁻¹(12.15/15)

θ₁ = tan⁻¹(0.81)

θ₁ = 39°

Since λ = dsinθ₁

Thus;

λ = 834sin(39°)

λ = 834 × 0.6293

λ ≈ 525 nm

Answer:

Part C

Explanation:

The potential energy would increase almost 25%

Answer:

Explanation:

given

initial velocity u=60mph to ft per sec= 88ft/s

final velocity v=40 mph to ft per sec= 58.6 ft/s

distance s=360ft

convert feet to mile 360ft is 0.06miles

we can apply the expression

v^2=u^2-2as

58.6^2=88^2-2*a*360

3433.96=7744-720a

3433.96-7744=-720a

-4310.04=-720a

a=4310.04/720

a=5.98 ft/sec

Answer: -0.10m/s

Explanation:

khan academy

Answer:

c frequency

hope it helps:))

Explanation:

To solve this we must be knowing each and every concept related to photon. Therefore, the correct option is option C. Photons with the lowest energy have the lowest frequency.

A photon, also known as a light quantum, is a small energy packet containing electromagnetic radiation. The idea came from Albert Einstein's explanation of something like the photoelectric phenomenon (1905), in which he hypothesized the possibility of energy levels packets during light transmission.

Photons all move just at speed of light. Photons are bosons that have no electric charge and rest mass one and unit of spin; they were field particle that are assumed to be the bearers of electromagnetic field. Photons with the lowest energy have the lowest frequency.

Therefore, the correct option is option C. Photons with the lowest energy have the lowest frequency.

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Answer:

Since velocity is considered a vector quantity and vectors show you in what direction it goes the object wont be moving forward but backwards because its a negative and negatives go to the left and that would be considered backwards.

Explanation:

Hope this helps

The forces which act upon the book are Normal, Gravity, Air resistance, and Friction. Therefore, the (A), (B), (D), and (E) options are correct.

The normal force is a contact force that surfaces exert to prevent objects from passing through each other. If two surfaces are not in direct contact, they are able to exert a normal force on each other. The book and the floor are exerting normal on each other.

Gravity is the force by which the earth draws objects toward its center. The force of gravity keeps everything on the surface of the earth. Therefore, the sliding book on the floor experiences the force of gravity.

Air resistance is a force that arises due to air. The force acts in the opposite direction to the motion of an object through the air. As the book slides across the floor, it experiences resistance due to air.

Friction is the resistance caused by the surfaces that are in contact when they slide over each other. Friction arises due to the irregularities on the two surfaces. The book and floor both have irregularities on their surfaces which is caused friction between them.

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Your question is incomplete, but most probably the complete question was,

Consider the situation a book a sliding to a stop while moving across the classroom floor. Of the forces listed identify which act upon the book:

A)Normal,

B) Gravity

C)Applied

D) Air resistance,

E) Friction

F) Tension

Answer:

The ball would fall vertically for 112.45m

Explanation:

The vertical height of a horizontal throw is affected only by the speed of the throw and the acceleration due to gravity.

At this point, we may use this formula to determine the vertical height of the throw

vertical height = [tex]-v^2/2g[/tex]

The initial throwing speed has to be converted to m/s to ensure uniformity during the calculations. To do this we multiply by 1000 and divide by 3600

169.1km/hr = 46.972m/s

Maximum height = [tex]46.972^2 /2 \times 9.81=112.45[/tex] m

The pitch would make the ball fall vertically for 112.45m by the time it reached the home plate 18.2 m away

Answer:

The average net force exerted on the car and riders by the magnets is 33751.8 newtons.

Explanation:

Let assume that car and its riders accelerate at constant rate, such that acceleration ([tex]a[/tex]), measured in meters per square second, can be found by using the following kinematic equation:

[tex]a = \frac{v_{f}-v_{o}}{t}[/tex] (Eq. 1)

Where:

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the car and its riders, measured in meters per second.

[tex]t[/tex] - Acceleration time, measured in seconds.

If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 45\,\frac{m}{s}[/tex] and [tex]t = 6.8\,s[/tex], the average acceleration of the car is:

[tex]a = \frac{45\,\frac{m}{s}-0\,\frac{m}{s}}{6.8\,s}[/tex]

[tex]a = 6.618\,\frac{m}{s^{2}}[/tex]

By the Second Newton's Law, we find that average force exerted on the car and riders by the magnets ([tex]F[/tex]), measured in newtons, is:

[tex]F = m\cdot a[/tex] (Eq. 2)

Where [tex]m[/tex] is the mass of the car-riders system, measured in kilograms.

If we know that [tex]m = 5100\,kg[/tex] and [tex]a = 6.618\,\frac{m}{s^{2}}[/tex], the net force exerted on the car and riders is:

[tex]F = (5100\,kg)\cdot \left(6.618\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 33751.8\,N[/tex]

The average net force exerted on the car and riders by the magnets is 33751.8 newtons.

Answer:

1. The object will not move at all.

Explanation:

The question above is related to "Newton's First Law of Motion." According to this law, an object that is at rest will remain in its position (at rest) unless acted upon by "unbalanced forces." If the forces applied to an object are balanced, the net force is zero. This means that the object will not move nor accelerate.

The law also mentioned that if the object is in motion, it will remain in same velocity (speed with direction) if there's no net force.

Answer:

The absolute pressure on me increases to 130,900 Pa.

Explanation:

Since I dive to a depth of 2.0 m, there is a depth change of 2.0 m which will cause a corresponding pressure change. The pressure change is thus ΔP = ρgΔh where ρ = density of water = 1000 kg/m³, g = acceleration due to gravity = 9.8m/s² and Δh = depth change = 2.0 m

ΔP = ρgΔh  =  1000 kg/m³ × 9.8m/s² × 2.0 m = 19,600 Pa.

Since the absolute pressure P at 1.0 m is the pressure due to atmosphere plus the pressure of 1.0 m of water, we have

P = P₀ + ρgΔh' where P₀ = atmospheric pressure = 101,500 Pa and Δh' = 1.0 m

P = 101,500 Pa + 1000 kg/m³ × 9.8m/s² × 1.0 m = 101,500 Pa + 9800 Pa = 111,300 Pa

So, the absolute pressure at 2.0 m is P' = P + ΔP = 111,300 Pa + 19,600 Pa = 130,900 Pa.

So the absolute pressure on me increases to 130,900 Pa.

Answer:

Large igneous provinces are formed by flood basalt, which can flow tens to hundreds of kilometers.

Explanation:

Answer:

θ = 0

Explanation:

As per the question Given that

Magnitude = 2m

Force F contains MAgnitude = 4N

Based on the above information

T = rFsinθ

Now if

T = 0,

so r and F would not be zero so that sinθ  should be equivalent to zero for holding an equation

Therefore

θ = 0

The same is to be considered as it is relevant as per the question

Answer:

Normal force is the force exerted on an object that is in contact with another non-moving object. Force is push and pull

Ex: When a book rests on a surface (like a table), the table is exerting a force on the book in order to support the weight of it.  

Answer:

Normal Force is a contact force. When 2 objects are touching each other, they are in contact. Like when a cup is sitting on a table they are in contact cause the table has to hold the force of the cup up on the table.

A example of normal force is when a book is sitting on a table, and the table is holding the force of the book up.

Explanation:

Hope this helps!!

Have a blessed day/night! <33

Answer:

B. fast-twitch fibers can deliver a quick burst of power. Slow-twitch fibers can maintain a contraction for a longer time.

Answer:

the person above is right, just came for answers lol :')

Explanation:

Answer:

7.43m/s

Explanation:

Given parameters:

Initial velocity = 1.7m/s

Height  = 2.5m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we apply one of the motion equation. The most fitting one given the parameters is;

           V²  = U² + 2gh

where V is the final velocity

           U is the initial velocity

          g is the acceleration due to gravity = 9.8m/s

           h is the height

Input the parameters and solve;

    V² = 2.5² + 2(9.8)(2.5)

    V = 7.43m/s