Draw a force diagram, find any resultant force and describe the object's motion.
a. An object with mass of 4kg, lying on a rough table, is acted upon by a horizontal
force of 25N. The object experiences a frictional force of 15N.

Answers

Answer 1

An object with a mass of 4kg, lying on a rough table, experiences a frictional force of 15N and a horizontal force of 25N, resulting in a net force of 10N, causing the object to accelerate to the right with an acceleration of 2.5 m/s².

Normal force Frictional force (15N)

The normal force points upwards and is equal in magnitude to the weight of the object (mg = 4kg * 9.81m/s² = 39.24N) since the object is not accelerating in the vertical direction.

The frictional force points to the left and is equal in magnitude to the force applied to the object (15N = 25N), indicating that the object is not moving horizontally.

The resultant force is found by subtracting the frictional force from the applied force:

F_net = F_applied - F_friction = 25N - 15N = 10N

The object will accelerate to the right with an acceleration of:

a = F_net/m = 10N/4kg = 2.5 m/s²

Therefore, the object will move to the right with increasing speed.

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Draw A Force Diagram, Find Any Resultant Force And Describe The Object's Motion.a. An Object With Mass

Related Questions

A defensive driving solution for a mature driver with diminished


vision is to


DRIVERS ED PLEASE ANSWER Select your answer, then click or


tap Submit.


Avoid driving at night


Drive 5 miles per hour under the


speed limit


Take frequent rest breaks


Ask other passengers to watch


the traffic

Answers

A defensive driving solution for a mature driver with diminished capabilities is to ask other passengers to watch and assist. This approach is beneficial because it promotes a safer driving experience for all occupants and others on the road.

Firstly, the mature driver must recognize their limitations, such as slower reaction times or diminished visual acuity. This self-awareness is crucial for ensuring safe driving practices.

Next, it is essential to communicate openly with passengers about the driver's needs. Inform them about any specific concerns or areas where they may require assistance. This honest communication fosters trust and understanding among all occupants.

Then, assign specific roles to passengers. For instance, one passenger can be responsible for monitoring blind spots while another keeps an eye on the speed limit. This way, the mature driver can focus on the task at hand with reduced distractions.

Another defensive driving strategy is for the mature driver to adapt their driving habits. This includes maintaining a safe distance from other vehicles, allowing more time for braking and accelerating, and using turn signals well in advance.

Additionally, it is crucial to encourage passengers to speak up if they notice any dangerous situations or unsafe driving behaviors. This collaborative effort will provide an extra layer of protection for everyone in the car.

Lastly, the mature driver should consider attending a defensive driving course specifically designed for their age group. This will help them stay updated on current best practices and techniques for safe driving.

In conclusion, a defensive driving solution for a mature driver with diminished capabilities involves asking passengers to watch and assist while also adapting their driving habits and attending defensive driving courses. This approach ensures a safer driving experience for all parties involved.

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Andrew was running late for class and could only find a parking space next to the golf course. His new truck was hit by a 0. 300 kg golf ball which left a 0. 400 cm dent in the hood. The golf ball was falling with a velocity of 8. 00 m/s.


a) What is the initial momentum of the golf ball? b) what average force did the hood of the truck exert on the ball to stop it? c) how long did it take for the hood to stop the ball?

Answers

The initial momentum of the golf ball is 2.40 kg⋅m/s. The average force exerted by the hood of the truck on the ball to stop it is [tex]-2.40 \times 10^4 N[/tex] and the time taken for the hood to stop the ball is [tex]1.00 \times 10^{-4} s[/tex]

a) The initial momentum of the golf ball can be calculated by using the formula:

p = mv

where m is the mass of the ball and v is the velocity of the ball. Plugging in the given values, we get:

p = (0.300 kg)(8.00 m/s) = 2.40 kg⋅m/s

Therefore, the initial momentum of the golf ball is 2.40 kg⋅m/s.

b) The average force exerted by the hood of the truck on the ball to stop it can be calculated using the formula:

[tex]F = \Delta p/ \Delta t[/tex]

where Δp is the change in momentum of the ball and Δt is the time taken for the ball to come to rest. Since the ball comes to rest, the final momentum of the ball is zero. So the change in momentum is:

[tex]\Delta p[/tex] = 0 - 2.40 kg⋅m/s = -2.40 kg⋅m/s

To find the time taken, we need to use the formula for distance traveled during a uniform deceleration:

[tex]d = (1/2)at^2[/tex]

where d is the distance traveled, a is the deceleration, and t is the time taken. The distance traveled by the ball can be taken as the dent made by the ball on the hood, which is 0.400 cm or 0.00400 m. The deceleration of the ball can be found by using the formula:

[tex]v^2 = u^2 + 2ad[/tex]

where u is the initial velocity (8.00 m/s), v is the final velocity (0 m/s), and d is the distance traveled (0.00400 m). Solving for a, we get:

[tex]a = (v^2 - u^2)/2d = -80,000 \;m/s^2[/tex]

(Note that the negative sign indicates that the ball is decelerating.)

Now we can find the time taken:

[tex]t = \sqrt{(2d/a)}[/tex]

[tex]t = \sqrt{(2 \times 0.00400\; m/80,000 \;m/s^2) }[/tex]

[tex]t = 1.00 \times 10^{-4} s[/tex]

So the average force exerted by the hood of the truck on the ball to stop it is:

[tex]F = \Delta p/ \Delta t[/tex]

[tex]F = (-2.40\; kg\;m/s)/(1.00 \times 10^{-4} s)[/tex]

[tex]F = -2.40 \times 10^4 N[/tex]

(Note that the negative sign indicates that the force is in the opposite direction to the motion of the ball.)

c) The time taken for the hood to stop the ball is [tex]1.00 \times 10^{-4} s[/tex], as found in part (b).

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While at the parent-teacher conference, murphy’s teacher mentions that the apollo program-the same program that landed humans on the moon-was just propaganda to convince the soviet union to bankrupt themselves trying to do the same. the reason for this was to encourage children to take care of their own planet, rather than wasting precious resources day dreaming of leaving it. which side of the fence would you sit on? would you look for ways to save earth and our ability to stay there, or would you look to the sky, and find a new plant to live on? why?



interstellar movie☝️

Answers

I would sit on the side of looking for ways to save Earth and our ability to stay there, rather than looking to the sky to find a new planet to live on.

While finding new habitable planets is an interesting scientific pursuit, it is not a practical solution to the problems we face on Earth. Instead, we should focus on preserving and restoring our planet's ecosystems, reducing our carbon footprint, and developing sustainable technologies. Furthermore, the idea that the Apollo program was just propaganda is a conspiracy theory without any evidence to support it.

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Josh pushes a table with a force of 80. N at an angle of 30°


to the table. If he pushes the table 5 meters, how much


work has he done? Joules

Answers

Josh pushes a table with a force of 80. N at an angle of 30° to the table. If he pushes the table 5 meters then Josh has done 346.41 Joules of work on the table.

To calculate the work done by Josh on the table, we can use the formula:

[tex]W = F \times d \times cos(\theta)[/tex]

where W is the work done, F is the force applied, d is the distance moved, and theta is the angle between the force and the direction of motion.

Substituting the given values, we get:

[tex]W = 80 N \times 5 m \times cos(30^{\circ})[/tex]

W = 346.41 J

Therefore, Josh has done 346.41 Joules of work on the table. To understand the concept of work, it is important to note that work is done when a force is applied to an object and it causes it to move.

In this case, Josh applies a force of 80 N at an angle of 30° to the table, causing it to move 5 meters. The work done is calculated by multiplying the force, distance, and cosine of the angle between them.

In summary, to calculate the work done by Josh on the table, we use the formula [tex]W = F \times d \times cos(\theta)[/tex] , where W is the work done, F is the force applied, d is the distance moved, and theta is the angle between the force and the direction of motion.

By substituting the given values, we find that Josh has done 346.41 Joules of work on the table.

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What is the speed of light in a medium having an
absolute index of refraction of 2.3?

Answers

About 130,346,719.13 meters per second is the speed of light in a medium having an absolute index of refraction of 2.3.

To solve this problem

The difference between the speed of light in the medium and the speed of light in a vacuum or in air is known as the refractive index of a media.

n = c / v

We are given that the absolute refractive index of the medium is 2.3. So, we can write:

n = 2.3

Thus, the speed of light in the medium is:

v = c / n = c / 2.3

The speed of light in a vacuum or in air, denoted by the symbol c, is around 299,792,458 meters per second. Therefore, by substituting this value, we obtain:

v = 299,792,458 m/s / 2.3

Simplifying this expression gives:

v = 130,346,719.13 m/s

Therefore, About 130,346,719.13 meters per second is the speed of light in a medium having an absolute index of refraction of 2.3.

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A 3. 2 kg cannon ball at rest is fired from a cannon. The cannon ball leaves the cannon with a speed of 6. 0 m/s. Determine the force provided by the cannon if it


takes 0. 55 seconds to launch the cannon ball


0 10,6 N


0 27,8 N


0 34 9 N


0 159 N

Answers

The force provided by the cannon to launch a 3.2 kg cannonball at rest with a speed of 6.0 m/s in 0.55 seconds is 34.88 N.

To determine the force, we'll first need to find the acceleration of the cannonball using the formula:

final velocity (vf) = initial velocity (vi) + acceleration (a) * time (t).

Then, we'll use Newton's second law of motion (F = m * a) to find the force.

Step 1: Calculate the acceleration.
Given: vi = 0 m/s (cannonball at rest), vf = 6.0 m/s, t = 0.55 seconds
Formula: vf = vi + a * t
Rearranging the formula: a = (vf - vi) / t

Step 2: Plug in the given values.
a = (6.0 m/s - 0 m/s) / 0.55 seconds
a = 6.0 m/s / 0.55 seconds
a ≈ 10.9 m/s²

Step 3: Calculate the force using Newton's second law of motion.
Given: mass (m) = 3.2 kg, acceleration (a) ≈ 10.9 m/s²
Formula: F = m * a

Step 4: Plug in the given values.
F = 3.2 kg * 10.9 m/s²
F ≈ 34.88N

Thus, the force provided by the cannon is approximately 34.88 N.

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You travel 20.0 km to the right and you realized you have to drive back 5.0 km. the journey took 2 hours to complete. find the following:
a. the total distance you traveled
b. the total displacement you traveled
c. your average speed
d. your average velocity
(pls put an explanation the the answers ty!!)

Answers

The total distance you traveled is 25.0 km, and the total displacement you traveled is 15.0 km to the right and average speed is  12.5 km/h and velocity is 7.5 km/h to the right.

a. To find the total distance you traveled, add the distance you traveled to the right (20.0 km) and the distance you traveled back (5.0 km). Total distance = 20.0 km + 5.0 km = 25.0 km.

b. To find the total displacement, subtract the distance you traveled back (5.0 km) from the distance you traveled to the right (20.0 km). Total displacement = 20.0 km - 5.0 km = 15.0 km to the right.

c. To find your average speed, divide the total distance you traveled by the time it took to complete the journey. Average speed = Total distance / Time = 25.0 km / 2 hours = 12.5 km/h.

d. To find your average velocity, divide the total displacement by the time it took to complete the journey. Average velocity = Total displacement / Time = 15.0 km / 2 hours = 7.5 km/h to the right.

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Answer Please With Explanation

Answers

The change, on its own, that will cause the voltmeter to show a positive reading is Reduce the intensity of light incident on the light-dependent resistor (LDR). Option C

Why would reduction in the intensity of Light on the LDR cause the voltmeter to show a positive reading?

When the intensity of light incident is reduced on the light-dependent resistor  LDR, it will increase its resistance.

This would cause a massive drop in voltage across the LDR.

This will then cause the potential at Y to be lower than that at X. This change alone could result in a positive reading on the voltmeter.

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your group has invented a solar cell that works by applying photosynthesis chemistry to generating hydrogen which is stored for use in a fuel cell. in 10 different regions differing by weather. you set up solar-city installations (using solar cells and lead acid batteries for storage) and your technology comparing the kilowatt hours generated in a month the results are:

Answers

The solar cell that applies photosynthesis chemistry to generate hydrogen is different from traditional solar cells that directly convert sunlight into electricity because it uses a chemical process to store the energy generated by sunlight, whereas traditional solar cells directly produce electricity.

In the photosynthesis-based solar cell, the energy from sunlight is used to split water into hydrogen and oxygen through a chemical reaction, and the hydrogen is stored for later use in a fuel cell to generate  the electricity. Traditional solar cells, on the other hand, generate electricity by converting sunlight directly into electrical energy through the photovoltaic effect.

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--The complete Question is, How does the solar cell that applies photosynthesis chemistry to generate hydrogen differ from traditional solar cells that directly convert sunlight into electricity? --

Eye color is an example of a??

Answers

Answer:

Trait

Explanation:

You already have the right answer chosen.

Answer:

trait

Explanation:

Looks like you already had the right answer

Need help!!!!! 10 points


ari has a big exam tomorrow, and he can’t stop worrying about it. he decides to exercise and see if that takes his mind off it. he goes to the gym, but it is not really helping. he can’t get into his exercise like he usually does, and he almost dropped a weight because he is so preoccupied. what should ari do?

a.

keep working out since that is important.

b.

find an exercise routine that requires less skill and do that.

c.

he should practice mindfulness and shut out all distractions.

d.

if he can’t focus, he could hurt himself, so he should go home.


please no links

Answers

Ari should prioritize his safety and well-being above all else. He should take a break from his exercise, go home, and engage in activities that help him relax and reduce his anxiety. Therefore, the correct option is D.

Ari's inability to focus on his exercise and his preoccupation with the exam can be a safety hazard as he almost dropped a weight. Therefore, he should prioritize his safety and well-being above everything else.

The best course of action for Ari would be to go home and take a break from his exam worries. He can engage in activities that help him relax, such as taking a warm bath, reading a book, or listening to music

Additionally, Ari can try practicing some relaxation techniques, such as deep breathing or meditation, to help calm his mind and reduce anxiety. It is important to note that while exercise can be a great stress reliever, it may not work for everyone in all situations.

In this case, Ari's anxiety is too high to focus on his workout. Therefore, finding an exercise routine that requires less skill (option b) may not necessarily work for him. Similarly, practicing mindfulness (option c) may be difficult for him at the moment since his mind is preoccupied with the exam.

In summary, Ari should prioritize his safety and well-being above all else. He should take a break from his exercise, go home, and engage in activities that help him relax and reduce his anxiety.

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What is the absolute index of refraction of medium x?

Answers

The refractive index of the wave in medium X is 0.577.

What is the refractive index?

The refractive index of a substance or medium measures how much light can bend through it. The difference between the speed of light in an object or medium and the speed of light in a vacuum (or in air) is how it is defined. Usually, the letter n is used to denote the refractive index.

The refractive index of a substance or medium is a critical property that determines how light will behave when it passes through it.

We know that the refractive index can be obtained as;

n = sin i/sinr

Thus we have that;

sin i = sin 30

sin r = sin 60

n = sin 30/sin 60

n = 0.577

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Which class of fires consists of flammable liquids including.

Answers

Answer:

class b

Explanation:

flamabal liquids , gas alcohol or oil

c. To what height can a 400w engine lift a 100kg mass in 3s? ​

Answers

We need to use the formula for work done, which is :

W = F x D

P = W / T

In this case, the force (F) is equal to the weight of the mass, which is :

F = m x g

where m is the mass (100kg) and g is the acceleration due to gravity (9.81 m/s²).

F = 100kg x 9.81 m/s² = 981 N

The power (P) of the engine is 400 W, and the time (T) is 3 seconds.

P = W / T, therefore W = P x T = 400 W x 3 s = 1200 J

Now we can use the work formula to find the distance (D) that the engine can lift the mass :

D = W / F = 1200 J / 981 N = 1.22 m

Therefore, the 400W engine can lift a 100kg mass to a height of 1.22 meters in 3 seconds.

Water has a specific heat capacity of 4. 184 J/g℃. The experiment heated 200g of water from 30℃ to 100℃. How much energy is absorbed by the water?

1) 25,104J
2) 83,680J
3) 14,000J
4) 58,576J

Answers

The amount of energy absorbed by the water is 58,576J. The answer is 4) 58,576J.

The formula to calculate the amount of energy absorbed by the water is:

Q = m x c x ΔT

Where Q is the amount of energy absorbed (in Joules), m is the mass of water (in grams), c is the specific heat capacity of water (in J/g℃), and ΔT is the change in temperature (in ℃).

Substituting the given values, we get:

Q = 200g x 4.184 J/g℃ x (100℃ - 30℃)
Q = 200g x 4.184 J/g℃ x 70℃
Q = 58,576J

Therefore, the amount of energy absorbed by the water is 58,576J. The answer is 4) 58,576J.

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A harmonic wave travels in a wire with amplitude 2.51 mm, wavelength 1.09 m, and frequency 649 hz. what is the speed with which the wave travels

Answers

The speed with which the harmonic wave travels in the wire is approximately 707.41 meters per second.

To find the speed of a harmonic wave traveling in a wire, we need to use the following formula:

Speed (v) = Wavelength (λ) * Frequency (f)

In this case, we are given the amplitude, wavelength, and frequency of the wave. The amplitude (2.51 mm) is not necessary to calculate the speed, so we can focus on the wavelength and frequency:

Wavelength (λ) = 1.09 m
Frequency (f) = 649 Hz

Now, we can use the formula to calculate the speed of the wave:

Speed (v) = 1.09 m * 649 Hz

Multiplying the wavelength and frequency together:

v = 707.41 m/s

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PLS ANSWER ASAP
1. A gardener uses a wheelbarrow to move 20 kilograms of soil from a compost pile to a flower bed, a distance of 53 meters. The wheelbarrow has a mass of 17 kilograms. he expands 94.5 Newtons of forced. How much work does the gardener do? (1 point)
O 135.4 N
O 5,008.5 N
O 1,961 N
O 3,496 N

2. A force of 30 N is applied to a ball, and it takes the balls 1.5 seconds to travel 4 meters. What is the work done on the ball? (1 point)
O 45 J
O 80 J
O 120 J
O 180 J

3. A mechanic wants to use a compound pulley to lift a go-kart from the ground to work table, a distance of 1.2 meters. Without the pulley, 1,620 Newtons of force would be needed to lift the go-kart. If the pulley has a mechanical advantage of 4, how much force must the mechanic expend? (1 point)
O 1,616 N
O 405 N
O 5,400 N
O 1,350 N​

Answers

The gardener does a work of 5,008.5 J

The work done is 120 J
The force exerted is 405 N

What is the work done?

Work is defined as the product of the force applied to an object and the distance it moves in the direction of that force. In other words, work is done when a force causes an object to move in the same direction as the force. The formula for work is W = F x d,

Given that;

W = Fd

F = force

d = distance

W = work done

Thus;

W = 94.5 N * 53 m

= 5,008.5 J

2) W = Fd

W = 30 N * 4 m

=  120 J

3) MA = 1620/x

x = 1620/4

x =  405 N

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When you added 50 V battery to circuit what happens to the


intensity of light bulbs? increase or decrease

Answers

Adding a 50 V battery to a circuit can potentially increase the intensity of the light bulbs, assuming the bulbs are designed to operate at a higher voltage.

The intensity of light bulbs is generally related to the power (P) consumed by the bulbs. In an electrical circuit, the power can be calculated using the formula:

P = V² / R

Where V is the voltage and R is the resistance of the bulb.

By increasing the voltage (V), the power consumed by the bulbs may increase if the resistance (R) remains constant. A higher power output generally results in increased brightness and intensity of the light bulbs.

However, it's important to note that if the light bulbs are not designed to handle the increased voltage, it could lead to overloading and potential damage.

Therefore, it is crucial to ensure that the light bulbs are compatible with the increased voltage before making any modifications to the circuit.

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A steel railroad track has a length of 21 m when the temperature is 0 C. what is the increase in the length of the rail on a hot day when the temperature is 32 C? the linear expansion coefficient of steel is 11*10-6(C)-1

Answers

The increase in the length of the rail on a hot day is 0.007392 m.

Length calculation.

To solve this problem, we can use the formula for linear expansion:

ΔL = αLΔT

Where:

ΔL = change in length

α = linear expansion coefficient

L = original length

ΔT = change in temperature

We are given:

L = 21 m

ΔT = 32°C - 0°C = 32°C

α = 11×10^(-6) (°C)^(-1)

Substituting the values into the formula, we get:

ΔL = (11×10^(-6) (°C)^(-1)) × (21 m) × (32°C)

ΔL = 7.392 m × 10^(-3)

ΔL = 0.007392 m

Therefore, the increase in the length of the rail on a hot day is 0.007392 m.

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An unknown force is applied to a 12 kg mass. The force acts at an angle of 30.0 degrees above the horizontal.
Determine the force acting if the force acts for a horizontal displacement of 22 meters and increases the 12 kg mass's
speed from 11 m/s to 26 m/s.

Answers

The force acting on the 12 kg mass would be 11 N.

To solve this problem, we need to use the work-energy principle, which states that the work done by a force on an object is equal to the change in the object's kinetic energy.

First, we need to calculate the initial and final kinetic energy of the 12 kg mass.

The initial kinetic energy is given by:

K₁ = (1/2) * m * v₁²

= (1/2) * 12 kg * (11 m/s)²

= 726 J

The final kinetic energy is given by:

K₂ = (1/2) * m * v₂²

= (1/2) * 12 kg * (26 m/s)²

= 936 J

The change in kinetic energy is:

ΔK = K₂ - K₁

= 936 J - 726 J

= 210 J

Next, we need to calculate the work done by the unknown force. We can do this by using the formula:

W = F * d * cosθ

where W is the work done, F is the force, d is the displacement, and θ is the angle between the force and displacement vectors.

In this case, the displacement is 22 meters, and the angle θ is 30 degrees. So we have:

W = F * d * cosθ

= F * 22 m * cos(30°)

= 19.1 F

Finally, we can use the work-energy principle to solve for the unknown force:

W = ΔK

19.1 F = 210 J

F = 11 N

Therefore, the force acting on the 12 kg mass is 11 N.

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12) A girl of mass 50 Kg transports a box of mass 20 Kg up a flight of 10 steps, each step 20 cm


high. She takes 16 Seconds to climb up the steps.


a. What is her weight?


b. What is the weight of the box?


c. When she reaches the top what vertical height has she traveled?


Pls help its urgent and I will mark you brainliest

Answers

A girl carrying a 20 Kg box climbs up 10 steps, each 20 cm high, in 16 seconds. Her own mass is 50 Kg. Her weight is 490.5N. The weight of the box is 196.2 N. When the girl reaches the top, she has traveled a vertical height of 2 meters.

a. The girl's weight is given by the product of her mass and the acceleration due to gravity. Thus, her weight is:

Weight = mass x acceleration due to gravity

Weight = [tex]50 \;kg \times 9.81 \;m/s^2[/tex]

Weight = 490.5 N

b. The weight of the box is also given by the product of its mass and the acceleration due to gravity. Thus, its weight is:

Weight = mass x acceleration due to gravity

Weight = [tex]20 \;kg \times 9.81 \;m/s^2[/tex]

Weight = 196.2 N

c. The vertical height of each step is given as 20 cm or 0.2 m. Therefore, the total vertical height traveled by the girl is:

Total height = number of steps x height of each step

Total height = 10 steps x 0.2 m/step

Total height = 2 m

Hence, when the girl reaches the top, she has traveled a vertical height of 2 meters.

In summary, we calculated the weight of the girl and the box, and determined the vertical height traveled by the girl when she climbed a flight of 10 steps, each step 20 cm high, in 16 seconds.

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31. Two parallel rails with negligible resistance are 10. 0 cm apart and are connected by a 5. 00 ohm resistor. The circuit also contains two metal rods having resistances of 10. 0 ohm and 15. 0 ohm sliding along the rails (Fig. P31. 31). The rods are pulled away from the resistor at constant speeds of 4. 00 m/s and 2. 00 m/s, respectively. A uniform magnetic field of magnitude 0. 0100 T is applied perpendicular to the plane of the rails. Determine the current in the 5. 00 ohm resistor.
question taken from physics for scientists and engineers, 6th edition. Chapter 31, q. 31​

Answers

The current in the 5.00 ohm resistor is 0.052 A.

The induced emf in each metal rod is given by e = Blv, where B is the magnetic field strength, l is the length of the metal rod moving in the magnetic field, and v is the velocity of the rod. For the 10.0 ohm rod, the induced emf is e = (0.0100 T)(0.100 m)(4.00 m/s) = 0.00400 V. The current through the 10.0 ohm rod is then I1 = e/R1 = 0.000400 A.

For the 15.0 ohm rod, the induced emf is e = (0.0100 T)(0.100 m)(2.00 m/s) = 0.00200 V. The current through the 15.0 ohm rod is then I2 = e/R2 = 0.000133 A. Since the two rods are connected in series, the current through the 5.00 ohm resistor is the same as the current through the two rods: I = I1 + I2 = 0.000533 A.

Using Ohm's law, the voltage drop across the 5.00 ohm resistor is V = IR = (0.000533 A)(5.00 ohm) = 0.00266 V. Therefore, the current in the 5.00 ohm resistor is I = V/R = (0.00266 V)/(5.00 ohm) = 0.052 A.

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1. Describe something other than the examples you've been given that you believe uses a
capacitor and describe its function in the device.

Answers

Because capacitors have the ability to filter signals, they are frequently employed in a variety of audio devices like loudspeakers, microphones, woofers, tweeters, and other similar devices.

What are some practical applications for capacitors?

Energy storage, power conditioning, electronic noise filtering, distant sensing, and signal coupling and decoupling are some of the most typical uses for capacitors. Capacitors are employed in a variety of industries because they serve an essential and adaptable function in a wide range of applications.

Do phones make use of capacitors?

Today's smartphone antenna systems depend heavily on capacitors. They are mostly employed for impedance matching, frequency tuning, and filtering.

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What angular acceleration would be required in order to stop the earth from rotating over a period of 30.0 minutes

Answers

The angular acceleration required to stop the rotation of the Earth over a period of 30 minutes would be equal to the final angular velocity divided by the time interval.

The Earth's rotation is an example of rotational motion, which is described by angular velocity and angular acceleration. Angular velocity is the rate of change of angular displacement with respect to time, and angular acceleration is the rate of change of angular velocity with respect to time.  

The final angular velocity would be zero, since the Earth would have stopped rotating, and the initial angular velocity can be calculated by dividing the circumference of the Earth (40,075 km) by the time period of 24 hours or 1,440 minutes, which gives a value of approximately 0.28 degrees per minute.

Therefore, the initial angular velocity would be (0.28 degrees/minute)(2pi radians/360 degrees) = 0.00489 radians/minute. Dividing this value by 30 minutes gives an angular acceleration of approximately 0.000163 radians/(minute²).

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The microwave transmitters that we use have a frequency of about 10 ghz. What is the approximate wavelength?.

Answers

The wavelength of a microwave frequency is the inverse of its frequency; that is, the wavelength is equal to the speed of light (in a vacuum) divided by the frequency. In this case, the frequency is 10 GHz, meaning the wavelength is approximately 3 cm.

Wavelength is the distance from one peak of a wave to the next, and is inversely proportional to frequency; that is, as frequency increases, wavelength decreases. Microwaves, which have frequencies between 300 MHz and 30 GHz, have wavelengths of 1 m to 1 cm, respectively. This makes them ideal for applications that require short-range communication, such as microwave ovens, wireless communication, and radar.

Microwaves are also used in remote sensing, as they can penetrate some materials, such as clouds, allowing us to measure the properties of objects behind them.

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How does a van de graaff generator create static electricity?.

Answers

Answer:

The generator makes static electricity the same way you do when you rub your feet on the carpet and then touch a doorknob.

Explanation:

. Inside the generator is a giant rubber band that rubs across a piece of felt, stealing its electrons. The rubber band then spins around and the electrons travel up to the big metal ball on top.

A soda bottle (m=0. 1 kg) filled with a flammable vapor is ignited and a rubber stopper (m=0. 01kg) is fired across the room at 100m/s. Find the recoil velocity of the soda bottle

Answers

The recoil velocity of the soda bottle is -10 m/s

To find the recoil velocity of the soda bottle, we'll need to use the conservation of momentum principle. The initial momentum of the system is zero since both the soda bottle and rubber stopper are initially at rest. The equation for conservation of momentum is:

m1v1 + m2v2 = 0

Where m1 and v1 are the mass and velocity of the soda bottle, and m2 and v2 are the mass and velocity of the rubber stopper. We know the masses and the velocity of the rubber stopper, so we can plug in those values:

(0.1 kg) * v1 + (0.01 kg) * (100 m/s) = 0

Now, solve for v1 (the recoil velocity of the soda bottle):

0.1 kg * v1 = -1 kg*m/s
v1 = -1 kg*m/s / 0.1 kg
v1 = -10 m/s

The recoil velocity of the soda bottle is -10 m/s, with the negative sign indicating that it moves in the opposite direction to the rubber stopper.

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Two devices of rating 22 W; 220 V and 11 W; 220 V are connected in series. The combination is
connected across a 440 V mains. The fuse of which of the two devices is likely to burn when
switch is on ? Justify your name. ​

Answers

The fuse of the 22 W device is more likely to burn out.

When two devices of different power ratings are connected in series, the voltage across each device is equal, but the current through each device will be different.

In this case, the two devices have power ratings of 22 W and 11 W, and are connected in series across a 440 V mains.

To determine which device is likely to burn out when the switch is turned on,

we need to calculate the current through each device using Ohm's law, which states that I = V/R, where I is the current, V is the voltage, and R is the resistance.

The resistance of each device can be calculated as follows:

For the 22 W device, R = V^2/P = (220 V)^2/22 W = 2200 ohms

For the 11 W device, R = V^2/P = (220 V)^2/11 W = 4400 ohms

The total resistance of the circuit can be found by adding the individual resistances:

R_total = R1 + R2 = 2200 + 4400 = 6600 ohms

Using Ohm's law, we can calculate the current through each device:

For the 22 W device, I1 = V/R1 = 220 V/2200 ohms = 0.1 A

For the 11 W device, I2 = V/R2 = 220 V/4400 ohms = 0.05 A

Since the 22 W device has a higher current flowing through it, it is more likely to burn out when the switch is turned on.

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The most massive Shinkansen bullet trains are the series-200 trains. This type of train also has one of the highest operating speeds: 76. 4 m/s. If a series-200 train has a maximum kinetic energy of 2. 78x 10 to the 9J, what is its mass?

Answers

The mass of the series-200 Shinkansen bullet train is approximately 953,000 kg.

High-speed trains like the Shinkansen bullet train are well-known for their quickness and effectiveness. With a top speed of 76.4 m/s, the series-200 train is one of the largest bullet trains currently in use. Knowing the train's mass is crucial for ensuring correct operation since the kinetic energy of the train plays a significant role in its performance and safety.

To find the mass of the series-200 Shinkansen bullet train, we'll use the formula for kinetic energy:

Kinetic Energy (KE) = 0.5 * mass (m) * velocity^2 (v^2)

The highest kinetic energy (2.78 x 109 J) and velocity (76.4 m/s) are provided. We'll now calculate the mass:


1. Rearrange the formula to isolate mass:

mass (m) = (2 * KE) / v^2

2. Plug in the given values:

mass (m) = (2 * 2.78 x 10^9 J) / (76.4 m/s)^2

3. Calculate the mass:

mass (m) = (5.56 x 10^9 J) / (5833.76 m^2/s^2)

mass (m) = 9.53 x 10^5 kg


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A 12 V battery is connected across two parallel metal plates separated by 0.59 cm. Find the magnitude of the electric field.

Answers

The magnitude of the electric field between two parallel plates is given by:

E = V/d

where V is the potential difference between the plates and d is the distance between them.

In this case, V = 12 V and d = 0.59 cm = 0.0059 m. Substituting these values, we get:

E = 12 V / 0.0059 m

E = 2033.9 V/m

Therefore, the magnitude of the electric field is 2033.9 V/m.

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