Determine whether the integral is convergent or divergent. 1 59 1 − x2 dx 0 convergent divergent Correct: Your answer is correct. If it is convergent, evaluate it. (If the quantity diverges, enter DIVERGES

Answers

Answer 1

Complete Question

The complete question is shown on the first uploaded image  

Answer:

it is convergent and  the solution is  [tex]= \frac{33 \pi }{2}[/tex]

Step-by-step explanation:

From the question we are given  

        [tex]\int\limits^1_0 {\frac{33}{\sqrt{1-x^2} } } \, dx[/tex]

When integrated

         [tex]= 33 sin^{-1} x \left | \ 1} \atop {0}} \right.[/tex]

        [tex]= 33[ \frac{\pi }{2} - 0][/tex]

        [tex]= \frac{33 \pi }{2}[/tex]

This implies that the integral converges

Determine Whether The Integral Is Convergent Or Divergent. 1 59 1 X2 Dx 0 Convergent Divergent Correct:

Related Questions

looking for the 2 correct answers please

Answers

Answer:

ROQQOP

Step-by-step explanation:

The sine of an angle is equal to the cosine of its complement, and vice versa.

  sin ∠QOP = cos ∠ROQ

  cos ∠ROQ = sin ∠QOP

The square rootof which number is rational a7. b 1.96. c. 0.04. d. 13​

Answers

Answer:

B and C

Step-by-step explanation:

We need to find which one of these numbers is a perfect square. We know 7 and 13 can be eliminated since they're prime numbers so they can't be perfect squares. B and C are both perfect squares so that's the answer.

Answer:

B and C

Step-by-step explanation:

7 = 7

1.96 = [tex]\frac{196}{100}[/tex]

0.04 = [tex]\frac{4}{100}[/tex]

13 = 13

What is the range of g?

Answers

Answer:

   {-7, -4, -1, 3, 7}

Step-by-step explanation:

The range is the list of y-coordinates of the points:

  range = {-7, -4, -1, 3, 7}

what is the slope of the line that contains the points (4 -1) and (-1,4)

Answers

Answer:

-1

Step-by-step explanation:

The slope formula when given two points is

m = ( y2-y1)/(x2-x1)

    = (4 - -1)/(-1 -4)

    = (4+1)/(-5)

    = 5/-5

   =-1

Answer:

-1

Step-by-step explanation:

Use the equation for slope.

[tex]m=\frac{y_{2}-y_{1} }{x_{2}- x_{1} }[/tex]

Plug in the given points into the equation.

[tex]m=\frac{4-(-1) }{-1- 4 }\\m=\frac{4+1 }{-5 }\\m=\frac{5}{-5 }\\m=\frac{1}{-1 }\\m=-1[/tex]

The slope is -1.

A padaria Beira Baixa vem perdendo dinheiro com a sua política de produção de venda do pãozinho francês. Atualmente, a cada dia é feita uma quantidade igual à procura do dia anterior. O proprietário, Sr. Joaquim, recolheu os seguintes dados:

Lucro na venda= $ 0,20 por unidade

Perda no pão não vendido = $ 0,05

(os pães não vendidos são moídos e vendidos como farinha de rosca: cada pão equivale a $0,15 de farinha de rosca)

Distribuição de frequência da demanda diária. Quantos pães devem ser fabricados diariamente para maximizar o lucro médio do Sr. Joaquim


1000 0,10

1100 0,10

1200 0,10

1300 0,15

1400 0,20

1500 0,15

1600 0,10

1700 0,05

1800 0,05

Answers

Answer:

The number of loaves to be made daily to maximize Mr. Joaquim's average profit is 1400.

O número de pães a serem feitos diariamente para maximizar o lucro médio do Sr. Joaquim é 1400.

Step-by-step explanation:

The table gives the daily demand of bread and the average profit that corresponds to each demand.

The daily demand values recorded ranged from 1000 to 1800.

And the corresponding average profit for the demands for each daily demand provided showed a steady increase from $0.10 as at a daily demand of 1000, through $0.15, then peaking at $0.20 at a daily demand of 1400.

After this point, the average profit begins to decline again as we move further away from the peak obtained at a daily demand of 1400.

Hence, it is evident that the daily demand that corresponds to the maximum average profit is 1400.

A daily demand of 1400 is where the peak average profit of $0.20 is obtained.

Any other demand lower or higher than 1400 corresponds to a departure from the peak profit obtained at that point according to the table of daily demand and average profits provided in the question.

In portugese/Em português

A tabela fornece a demanda diária de pão e o lucro médio que corresponde a cada demanda.

Os valores diários de demanda registrados variaram de 1000 a 1800.

E o lucro médio correspondente às demandas de cada demanda diária fornecida mostrou um aumento constante de US $ 0,10, com uma demanda diária de 1000, passando por US $ 0,15, atingindo um pico de US $ 0,20 com uma demanda diária de 1400.

Após esse ponto, o lucro médio começa a declinar novamente à medida que nos afastamos do pico obtido com uma demanda diária de 1400.

Portanto, é evidente que a demanda diária que corresponde ao lucro médio máximo é de 1.400.

Uma demanda diária de 1400 é onde é obtido o lucro médio máximo de US $ 0,20.

Qualquer outra demanda menor ou maior que 1400 corresponde a um afastamento do pico de lucro obtido nesse momento, de acordo com a tabela de demanda diária e lucros médios fornecidos na pergunta.

Hope this Helps!!!

Espero que isto ajude!!!

The graph to the right is the uniform density function for a friend whoThe graph to the right is the uniform density function for a friend who is x minutes late. Find the probability that the friend is at least 21 minutes late. is x minutes late. Find the probability that the friend is at least 21 minutes late.

Answers

Answer:

0.30

Step-by-step explanation:

Data provided in the question

Uniform density function for a friend = x minutes late

The Friend is at least 21 minutes late

Based on the above information, the probability that the friend is at least 21 minutes late is

[tex]= \frac{Total\ minutes - minimum\ minutes}{Total\ minutes}[/tex]

[tex]= \frac{30 - 21}{30}[/tex]

= 0.30

Based on the above formula we can easily find out the probability for the friend who is at least 21 minutes late

The probability of the friend to be at least 21 minutes late for the uniform density function shown in the graph is 0.30.

What is probability?

Probability of an event is the ratio of number of favorable outcome to the total number of outcome of that event.

The graph is attached below shows the uniform density function for a friend who is x minutes late.

The probability that the friend is at least 21 minutes late-

The friend is at least 21 minutes late. This means that the friend is 21 minutes late or more than it. 21 or more minutes goes from 21 to 30. Thus, the difference is,

[tex]d=30-21\\d=9[/tex]

The density of the graph is 1/30. The probability will be equal to the area under the curve.

In this, the length of the rectangle will be 9 and width will be 1/30 for the probability of at least 21 minutes late. The probability is,

[tex]P=9\times\dfrac{1}{30}\\P=0.30[/tex]

Thus, the probability of the friend to be at least 21 minutes late for the uniform density function shown in the graph is 0.30.

Learn more about the probability here;

https://brainly.com/question/24756209

Type the correct answer in the box. Spell all words correctly.
Which term describes the solution to a multiplication problem?
The
describes the solution to a multiplication problem.

Answers

Answer:

product is right

Step-by-step explanation:

What is the solution to the following system?
a
x+y+z= 6
X-Y+Z= 8
X+y-Z=0

Answers

Answer:

x= 4

Y= -1

Z= 3

step by step procedure:

let x+y+z=6, x-y+z=8, x+y-z=0 be equations 1, 2, and 3 respectively.

subtract equation 2 from equation 1 ; x+y+z-(x-y+z) = 6 - 8 y+y = -2 , 2y = -2, therefore y = -1substituting the value of y into equations 1, 2, and 3 . we get x+z=7---eqn 4, x+z=7---eqn 5 and x-z=1---eqn 6now add equation 6 to equation 5 ; x+z+(x-z)=7+1 ,x+x=7+1, 2x=8, therefore x=4put the value of x (x=4) back into equation 5; 4+z=7, z=7-4, therefore z=3.

you are welcome bro....

Determine whether b can be written as a linear combination of Bold a Subscript Bold 1a1​, Bold a Subscript Bold 2a2​, and Bold a Subscript Bold 3a3. In other​ words, determine whether weights x 1x1​, x 2x2​, and x 3x3 ​exist, such that x 1x1Bold a Subscript Bold 1a1plus+x 2x2Bold a Subscript Bold 2a2plus+x 3x3Bold a Subscript Bold 3a3equals=b. Determine the weights x 1x1​, x 2x2​, and x 3x3 if possible.

Answers

Complete  Question

The complete question is shown on the first uploaded image

Answer:

 a

    b can be written as a linear combination of  [tex]a_1 \ and \ a_2[/tex]

b

   The values of   [tex]x_1 = 4 \ and \ x_2 = 2[/tex]

Step-by-step explanation:

From the question we are told that

      [tex]x_1 a_1 +x_2 a_2 = b[/tex]

Where [tex]a_ 1 = (4, 5,-4)[/tex],  [tex]a_2 = (-4 , 3, 3)[/tex] and  [tex]b = (8,26 , -10)[/tex]

   So  

      [tex]x_1 ( 4, 5,-4) + x_2 (-4 , 3, 3) = (8,26 , -10)[/tex]

     [tex]4x_1, 5x_1,-4x_1 + -4x_2 , 3x_2, 3x_2 = (8,26 , -10)[/tex]

=>   [tex]4x_1 -4x_2 =8[/tex]

     [tex]x_1 -x_2 =2 ---(1)[/tex]

=>   [tex]5x_1 + 3x_2 = 26 --- (2)[/tex]

=>   [tex]-4x_1 + 3x_2 = -10 ---(3)[/tex]

Now multiplying equation 1 by 3 and adding the product to equation 2

          [tex].\ \ \ 3x_1 -3x_2 = 6\\+ \ \ 5x_1 + 3x_2 = 26 \\=> \ \ \ 8x_1 = 32[/tex]

=>        [tex]x_1 = 4[/tex]

 substituting [tex]x_1[/tex] into equation 1

        [tex]4 - x_2 =2[/tex]

        [tex]x_2 =2[/tex]

Now to test substitute [tex]x_1 \ and \ x_2[/tex] into equation 3

       [tex]-4(4) + 3(2) = -10[/tex]

      [tex]-10 = -10[/tex]

Since LHS = RHS then there exist values [tex]x_1 = 4 \ and \ x_2 = 2[/tex]  such that

       [tex]x_1 a_1 +x_2 a_2 = b[/tex]

Hence b can be written as a linear combination of  [tex]a_1 \ and \ a_2[/tex]

     

According to the image whats the answer? 80 points brainliest

Answers

Answer:

Hey!

Your answer is 150 square meters!

Step-by-step explanation:

13*3=39 (the tilted face)

12*3=36 (the flat face)

5*3=15 (the base)

TO FIND THE TRINGLULAR AREA:

1/2 base x height...

1/2 x 5 x 12 = 30

(WE DOUBLE THIS BECAUSE THERE ARE TWO TRIANGLES)

SO 60...

ADD THESE TOGETHER...

39 + 36 + 15 + 30 + 30...

GIVES US 150 square metres

HOPE THIS HELPS!!

Answer:

150 square meters

Step-by-step explanation:

Harper's Index reported that the number of (Orange County, California) convicted drunk drivers whose sentence included a tour of the morgue was 506, of which only 1 became a repeat offender.

a. Suppose that of 1056 newly convicted drunk drivers, all were required to take a tour of the morgue. Let us assume that the probability of a repeat offender is still p= 1/596. Explain why the Poisson approximation to the binomial would be a good choice for r = number of repeat offenders out of 963 convicted drunk drivers who toured the morgue.

The Poisson approximation is good because n is large, p is small, and np < 10.The Poisson approximation is good because n is large, p is small, and np > 10. The Poisson approximation is good because n is large, p is large, and np < 10.The Poisson approximation is good because n is small, p is small, and np < 10. What is λ to the nearest tenth?

b. What is the probability that r = 0? (Use 4 decimal places.)
c. What is the probability that r > 1? (Use 4 decimal places.)
d. What is the probability that r > 2? (Use 4 decimal places.)
e. What is the probability that r > 3? (Use 4 decimal places.)

Answers

Answer:

a. The Poisson approximation is good because n is large, p is small, and np < 10.

The parameter of thr Poisson distribution is:

[tex]\lambda =np\approx1.6[/tex]

b. P(r=0)=0.2019

c. P(r>1)=0.4751

d. P(r>2)=0.2167

e. P(r>3)=0.0789

Step-by-step explanation:

a. The Poisson distribution is appropiate to represent binomial events with low probability and many repetitions (small p and large n).

The approximation that the Poisson distribution does to the real model is adequate if the product np is equal or lower than 10.

In this case, n=963 and p=1/596, so we have:

[tex]np=963*(1/596)\approx1.6[/tex]

The Poisson approximation is good because n is large, p is small, and np < 10.

The parameter of thr Poisson distribution is:

[tex]\lambda =np\approx1.6[/tex]

We can calculate the probability for k events as:

[tex]P(r=k)=\dfrac{\lambda^ke^{-\lambda}}{k!}[/tex]

b. P(r=0). We use the formula above with λ=1.6 and r=0.

[tex]P(0)=1.6^{0} \cdot e^{-1.6}/0!=1*0.2019/1=0.2019\\\\[/tex]

c. P(r>1). In this case, is simpler to calculate the complementary probability to P(r<=1), that is the sum of P(r=0) and P(r=1).

[tex]P(r>1)=1-P(r\leq1)=1-[P(r=0)+P(r=1)]\\\\\\P(0)=1.6^{0} \cdot e^{-1.6}/0!=1*0.2019/1=0.2019\\\\P(1)=1.6^{1} \cdot e^{-1.6}/1!=1.6*0.2019/1=0.3230\\\\\\P(r>1)=1-(0.2019+0.3230)=1-0.5249=0.4751[/tex]

d. P(r>2)

[tex]P(r>2)=1-P(r\leq2)=1-[P(r=0)+P(r=1)+P(r=2)]\\\\\\P(0)=1.6^{0} \cdot e^{-1.6}/0!=1*0.2019/1=0.2019\\\\P(1)=1.6^{1} \cdot e^{-1.6}/1!=1.6*0.2019/1=0.3230\\\\P(2)=1.6^{2} \cdot e^{-1.6}/2!=2.56*0.2019/2=0.2584\\\\\\P(r>2)=1-(0.2019+0.3230+0.2584)=1-0.7833=0.2167[/tex]

e. P(r>3)

[tex]P(r>3)=1-P(r\leq2)=1-[P(r=0)+P(r=1)+P(r=2)+P(r=3)]\\\\\\P(0)=1.6^{0} \cdot e^{-1.6}/0!=1*0.2019/1=0.2019\\\\P(1)=1.6^{1} \cdot e^{-1.6}/1!=1.6*0.2019/1=0.3230\\\\P(2)=1.6^{2} \cdot e^{-1.6}/2!=2.56*0.2019/2=0.2584\\\\P(3)=1.6^{3} \cdot e^{-1.6}/3!=4.096*0.2019/6=0.1378\\\\\\P(r>3)=1-(0.2019+0.3230+0.2584+0.1378)=1-0.9211=0.0789[/tex]

what is 1+1, this is for you to get points.

Answers

Answer:

2

Step-by-step explanation:

1+1 = 2

Hope this helps;)

Answer:

1 + 1 =2

Step-by-step explanation:

Hi, how are you?

Do u want to be my friend?

Also, I hope this answered your question?

What is the volume of a cube with a side length of 14 cm.?

Answers

Answer:

V =2744 cm^3

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

V = 14^3

V =2744 cm^3

Answer: 2,744 cm³

Step-by-step explanation: Since the length, width, and height of a cube are all equal, we can find the volume of a cube by multiplying side × side × side.

So we can find the volume of a cube using the formula .

Notice that we have a side length of 14cm.

So plugging into the formula, we have (14 cm)³ or

(14 cm)(14 cm)(14 cm) which is 2,744 cm³.

So the volume of the cube is 2,744 cm³.

what is an equation of the line that passes through the point (-3,-1) and is perpendicular to the line y=1/2x - 3​

Answers

Answer:

Step-by-step explanation: gradient of perpendicular line is

-2

y+1/x+3=-2

y+1=-2x-6

y=-2x-7

Can someone help me on this question please

Answers

Answer:

about 11.11%, or 4/36

Step-by-step explanation:

Answer:

1/9

Step-by-step explanation:

There are 4 possible ways to get a sum of 5 out of total ways of 6*6= 36

So the probability of getting sum of 5 is 4/36= 1/9

Pedro is selling candy bars for his school baseball team each candy bar cost 1.25 and a box contains 20 bars

Answers

Answer:

$25

Step-by-step explanation:

You do 1.25. Y 20

In a study, 37% of adults questioned reported that their health was excellent. A researcher wishes to study the health of people living close to nuclear plant. Among 12 adults randomly selected from this area, only 3 reported that their health was excellent. Find the probability that when 12 adults are randomly selected, 3 or fewer are in excellent health.

Answers

Answer:

The probability that when 12 adults are randomly selected, 3 or fewer are in excellent health is 0.2946

Step-by-step explanation:

BIONOMIAL DISTRIBUTION

pmf of B.D is = f ( k ) = ( n k ) p^k * ( 1- p) ^ n-k

where

k = number of successes in trials    

n = is the number of independent trials    

p = probability of success on each trial

I.

mean = np

where

n = total number of repetitions experiment is excueted

p = success probability

mean = 12 * 0.37

= 4.44

II.

variance = npq

where

n = total number of repetitions experiment is excueted

p = success probability

q = failure probability

variance = 12 * 0.37 * 0.63

= 2.7972

III.

standard deviation = sqrt( variance ) = sqrt(2.7972)

=1.6725

the probability that when 12 adults are randomly selected, 3 or fewer are in excellent health

P( X < = 3) = P(X=3) + P(X=2) + P(X=1) + P(X=0)    

= ( 12 3 ) * 0.37^3 * ( 1- 0.37 ) ^9 + ( 12 2 ) * 0.37^2 * ( 1- 0.37 ) ^10 + ( 12 1 ) * 0.37^1 * ( 1- 0.37 ) ^11 + ( 12 0 ) * 0.37^0 * ( 1- 0.37 ) ^12    

= 0.2947

Find the sample space for a committee of two chosen from Alice (A), Bill (B), Carol (C), and David (D).
A. {(A, B), (C, D)}
B. {A, B, C, D}
C. {(A, B), (A, C), (A, D), (B, C), (B, D), (C, D)}
D. {(A, B), (A, D), (B, C), (C, D)}
Find the sample space if both sexes must be represented.
A. {(A, B), (A, C), (A, D), (B, C), (B, D), (C, D)}
B. {(A, B), (C, D)}
C. {(A, B), (A, D), (B, C), (C, D)}
D. {A, B, C, D}

Answers

Answer:

(a) C.  {(A, B), (A, C), (A, D), (B, C), (B, D), (C, D)}

(b) C. {(A,B),(A,D),(B,C),(C,D)}

Step-by-step explanation:

Given four members eligible for selection:

Alice (A), Bill (B), Carol (C), and David (D).

The possible combinations are:

(A,B),(A,C),(A,D),(B,A),(B,C),(B,D),(C,A),(C,B),(C,D), (D,A),(D,B), (D,C)

Part A

Since the same pairs are equal i.e. (A, B)=(B , A),

The Sample space for a committee of two is:

{(A,B),(A,C),(A,D),(B,C),(B,D),(C,D)}

This is Option C.

Part B

If both genders must be represented, we remove the entries that contain the same gender from the sample space above.

A and C -Female

B and D - Male

{(A,B),(A,C),(A,D),(B,C),(B,D),(C,D)}

Therefore, the sample space if both genders are to be represented is:

{(A,B),(A,D),(B,C),(C,D)}

This is Option C.

Answer:

1. A

2. C

Not 100% sure but its my best guess

Convert 8.25% to a decimal

Answers

Answer: 0.0825

Step-by-step explanation:

8.25% to decimal is simply divide 8.25 by 100

8.25/100= 0.0825

The required solution after convert it into decimal is,

⇒ 0.0825

We have to given that,

Convert 8.25% into a decimal.

We can change it as,

⇒ 8.25%

Since, 1% = 1/100

Hence,

⇒ 8.25/100

⇒ 0.0825

Therefore, After convert it into decimal number solution is,

⇒ 0.0825

Learn more about the percent visit:

https://brainly.com/question/24877689

#SPJ6

1. Divide 6/13 by 6/12
A. 12/13
B. 1/12
C. 13/12
D.916

Answers

Answer:

C

Step-by-step explanation:

[tex]\frac{6}{13}[/tex]÷[tex]\frac{6}{12}[/tex]  can also be [tex]\frac{6}{13}[/tex]×[tex]\frac{12}{3}[/tex] and [tex]\frac{6}{13}[/tex]×[tex]\frac{12}{3}[/tex]=13/12

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

\frac{6}{13}136 ÷\frac{6}{12}126  can also be \frac{6}{13}136 ×\frac{12}{3}312 and \frac{6}{13}136 ×\frac{12}{3}312 =13/12

A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per second.(a) What is the velocity of the top of the ladder when the base is given below?7 feet away from the wall ft/sec20 feet away from the wall ft/sec24 feet away from the wall ft/sec(b) Consider the triangle formed by the side of the house, ladder, and the ground. Find the rate at which the area of the triangle is changing when the base of the ladder is 7 feet from the wall. ft2/sec(c) Find the rate at which the angle between the ladder and the wall of the house is changing when the base of the ladder is 7 feet from the wall. rad/sec

Answers

Answer:

a) The height decreases at a rate of [tex]\frac{7}{12}[/tex] ft/sec.

b) The area increases at a rate of [tex]\frac{527}{24}[/tex] ft^2/sec

c) The angle is increasing at a rate of [tex]\frac{1}{12}[/tex] rad/sec

Step-by-step explanation:

Attached you will find a sketch of the situation. The ladder forms a triangle of base b and height h with the house. The key to any type of problem is to identify the formula we want to differentiate, by having in mind the rules of differentiation.

a) Using pythagorean theorem, we have that [tex] 25^2 = h^2+b^2[/tex]. From here, we have that

[tex]h^2 = 25^2-b^2[/tex]

if we differentiate with respecto to t (t is time), by implicit differentiation we get

[tex]2h \frac{dh}{dt} = -2b\frac{db}{dt}[/tex]

Then,

[tex]\frac{dh}{dt} = -\frac{b}{h}\frac{db}{dt}[/tex].

We are told that the base is increasing at a rate of 2 ft/s (that is the value of db/dt). Using the pythagorean theorem, when b = 7, then h = 24. So,

[tex]\frac{dh}{dt} = -\frac{2\cdot 7}{24}= \frac{-7}{12}[/tex]

b) The area of the triangle is given by

[tex]A = \frac{1}{2}bh[/tex]

By differentiating with respect to t, using the product formula we get

[tex] \frac{dA}{dt} = \frac{1}{2} (\frac{db}{dt}h+b\frac{dh}{dt})[/tex]

when b=7,  we know that h=24 and dh/dt = -1/12. Then

[tex]\frac{dA}{dt} = \frac{1}{2}(2\cdot 24- 7\frac{7}{12}) = \frac{527}{24}[/tex]

c) Based on the drawing, we have that

[tex]\sin(\theta)= \frac{b}{25}[/tex]

If we differentiate with respect of t, and recalling that the derivative of sine is cosine, we get

[tex] \cos(\theta)\frac{d\theta}{dt}=\frac{1}{25}\frac{db}{dt}[/tex] or, by replacing the value of db/dt

[tex]\frac{d\theta}{dt}=\frac{2}{25\cos(\theta)}[/tex]

when b = 7, we have that h = 24, then [tex]\cos(\theta) = \frac{24}{25}[/tex], then

[tex]\frac{d\theta}{dt} = \frac{2}{25\frac{24}{25}} = \frac{2}{24} = \frac{1}{12}[/tex]

A consumer agency is investigating the blowout pressures of Soap Stone tires. A Soap Stone tire is said to blow out when it separates from the wheel rim due to impact forces usually caused by hitting a rock or a pothole in the road. A random sample of 29 Soap Stone tires were inflated to the recommended pressure, and then forces measured in foot-pounds were applied to each tire (1 foot-pound is the force of 1 pound dropped from a height of 1 foot). The customer complaint is that some Soap Stone tires blow out under small-impact forces, while other tires seem to be well made and don't have this fault. For the 29 test tires, the sample standard deviation of blowout forces was 1358 foot-pounds.
(a) Soap Stone claims its tires will blow out at an average pressure of 26,000 foot-pounds, with a standard deviation of 1020 foot-pounds. The average blowout force is not in question, but the variability of blowout forces is in question. Using a 0.1 level of significance, test the claim that the variance of blowout pressures is more than Soap Stone claims it is.
Classify the problem as being a Chi-square test of independence or homogeneity, Chi-square goodness-of-fit, Chi-square for testing or estimating σ2 or σ, F test for two variances, One-way ANOVA, or Two-way ANOVA, then perform the following.
(ii) Find the sample test statistic. (Use two decimal places.)
(iii) Find the P-value of the sample test statistic. (Use four decimal places.)
(b) Find a 99% confidence interval for the variance of blowout pressures, using the information from the random sample. (Use one decimal place.)

Answers

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: Impact force needed for Sap Stone tires to blow out. (foot-pounds)

n= 29, S= 1358 foot-pound

a)

Soap Stone claims that "The tires will blow out at an average pressure of μ= 26000 foot-pounds with a standard deviation of σ= 1020 foot-pounds.

According to the consumer's complaint, the variability of the blown out forces is greater than the value determined by the company.

I)

Then the parameter of interest is the population variance (or population standard deviation) and to test the consumer's complaint you have to conduct a Chi-Square test for σ².

σ²= (1020)²= 1040400 foot-pounds²

H₀: σ² ≤ 1040400

H₁: σ² > 1040400

α: 0.01

II)

[tex]X^2= \frac{(n-1)S^2}{Sigma^2} ~~X^2_{n-1}[/tex]

[tex]X^2_{H_0}= \frac{(n-1)S^2}{Sigma^2}= \frac{(29-1)*(1358)^2}{1040400} = 49.63[/tex]

III)

This test is one-tailed to the right and so is the p-value. This distribution has n-1= 29-1= 28 degrees of freedom, so you can calculate the p-value as:

P(X²₂₈≥49.63)= 1 - P(X²₂₈<49.63)= 1 - 0.99289= 0.00711

⇒ The p-value is less than the significance level so the test is significant at 1%. You can conclude that the population variance of the blowout forces is less than 1040400 foot-pounds², at the same level the population standard deviation of the blow out forces is less than 1020 foot-pounds.

b)

99% CI for the variance. Using the X² statistic you can calculate it as:

[tex][\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ][/tex]

[tex]X^2_{n-1;\alpha /2}= X^2_{28; 0.005}= 13.121[/tex]

[tex]X^2_{n-1;1-\alpha /2}= X^2_{28; 0.995}= 49.588[/tex]

[tex][\frac{28*(1358)^2}{49.588} ;\frac{28*(1358)^2}{13.121} ][/tex]

[1041312.253; 3935415.898] foot-pounds²

I hope this helps!

A manufacturer of detergent claims that the contents of boxes sold weigh on average at least 20 ounces. The distribution of weight is known to be​ normal, with a standard deviation of 0.4 ounces. A random sample of 25 boxes yielded a sample mean weight of 19.87 ounces. Test at the 1​% significance level the null hypothesis that the population mean weight is at least 20 ounces.

Answers

Answer:

[tex]z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625[/tex]    

The p value for this case would be given by:

[tex]p_v =P(z<-1.625)=0.052[/tex]  

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

Step-by-step explanation:

Information provided

[tex]\bar X=19.87[/tex] represent the sample mean

[tex]\sigma=0.4[/tex] represent the population deviation

[tex]n=25[/tex] sample size  

[tex]\mu_o =68[/tex] represent the value that we want to test

[tex]\alpha=0.01[/tex] represent the significance level

z would represent the statistic

[tex]p_v[/tex] represent the p value

Hypothesis to test

We want to test if the true mean is at least 20 ounces, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \geq 20[/tex]  

Alternative hypothesis:[tex]\mu < 20[/tex]  

The statistic is given by:

[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex]  (1)  

Replacing the info given we got:

[tex]z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625[/tex]    

The p value for this case would be given by:

[tex]p_v =P(z<-1.625)=0.052[/tex]  

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

a cell phone company test 95 cell phones and finds that seven of them have defects out of the 760 cell phones how many would you expect to have defects ​

Answers

Answer:

56

Step-by-step explanation:

simple ratio: 7/95 = x/760

first, calculate 7/95 which is 0.0736

next, multiply that by 760, which would be 56

What is the quadratic formula?

Answers

Answer:

The quadratic formula is x= -b±√b²-4ac all over 2a

Step-by-step explanation:

The -b±√b²-4ac is part of the numerator of the fraction. And b²-4ac is all under the radical sign. The denominator is 2a so you divide -b±√b²-4ac by 2a to get the solutions of the quadratic function. Hope this helps!!

It’s this under here is a photo to remember what it looks like

Rachel is conducting a study in her cognitive psychology lab about people's ability to remember rhythms. She played

a short rhythm to 425 randomly chosen people. One minute later, she asked them to repeat it by clapping. If 121

people were able to successfully reproduce the rhythm, estimate the proportion of the population (including margin

of error) that would be able to successfully reproduce the rhythm.

Answers

Answer:

Rachel can conclude that 28% were able to successfully reproduce the rhythm plus or minus 5.6%

Step-by-step explanation:

To find the sample proportion that is able to successfully reproduce the rhythm = 121/425 = 0.2847 = p

Using this formula, we can calculate the margin of error

Margin of error = z*√{[p (1-p)] / n}

Where we assume a 95% level of confidence so that z* = 1.96. since one is not given, p = 0.28457 and n = 245.

Margin of error = 1.96 x √(0.28457 (1-0.28457)] / 245}

Margin of error = 1.96 x √[(0.28457 (0.7154)] / 245

 = 1.96 x √(0.20/245)

 = 1.96 x √0.000816

  = 1.96 x 0.03

 = 0.056.

Thus, Rachel can conclude that 28% were able to successfully reproduce the rhythm plus or minus 5.6%

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

Weights of Dogs in Shelter A

6

8

10

12

14

16

18

20

22

24

26

28

30

Weights of Dogs in Shelter B

Which describes the spread of the data in the two box plots?

O

The data in shelter A show more spread than the data in shelter B.

The data in shelter B show more spread than the data in shelter A

The data in shelter A range from about 17 to 28, while the data in shelter B range from about 16 to 20

The data in shelter A range from about 21 to 28, while the data in shelter B range from about 18 to 20.

Answers

Answer:

The data in shelter A show more spread than the data in shelter B.

Step-by-step Explanation:

Judging from the data set given for shelter A and shelter B in the diagram of the box plots attached below, shelter A has a data set that ranges from 8 pounds to 30 pounds, while shelter B ranges from e can infer that the data in shelter A has more spread than the data in shelter B ranges from 10 to 28.

Taking into consideration the range of the data set of each shelter, shelter A obviously has a larger range compared to shelter B. This implies that, the data in shelter A show more spread than the data in shelter B.

Answer:

A

Step-by-step explanation:

Find the value of -1/3-(-5/12)

Answers

1/12 or decimal form 0.083 with repeating line

Benson asked a group of 9th, 10th, 11th, and 12th graders the
number of hours they work per week in the summer. The means of
each group are provided below:
9th: 14.2 hours
10th: 18.8 hours
11th: 21.2 hours
12th: 24.9 hours
Which conclusion can be made from this data?

Answers

Answer:

YlThe higher the grader the more hours they can work.

Step-by-step explanation:

We can see that the higher the grader the more hours they can work ; which could mean less academic work if the work defined is that with which to earn money but if the work defined is academic it means more hours of academic work

The estimator Yis a random variable that varies with different random samples; it has a probability distribution function that represents its sampling distribution, and mean and variance. Using the properties on expected values and variances of linear functions of random variables and sum operators, show that:
A. E(Y) = μ
B. Var(Y) σ2/N.

Answers

Answer:

Check Explanation

Step-by-step explanation:

According to the Central limit theorem, the population mean (μ) is approximately equal to the mean of sampling distribution (μₓ).

And the standard deviation of the sampling distribution (σₓ) is related to the population standard deviation (σ) through

Standard deviation of the sampling distribution = (Population standard deviation)/(√N)

where N = Sample size

σₓ = (σ/√N)

So, population mean (μ) = Mean of sampling distribution (μₓ)

Population Standard deviation = (Standard deviation of the sampling distribution) × √N

= σ × √N

A) The expected value of a given distribution is simply equal to the mean of that distribution.

Hence, the expected value of random variable Y thay varies with different samples is given as

E(Y) = Mean of sampling distribution = μₓ

But μₓ = μ

Hence, E(Y) = μ (Proved)

B) Var (Y) is given as the square of the random distribution's standard deviation.

Var (Y) = (standard deviation of the sampling distribution)²

= (σ/√N)²

= (σ²/N) (Proved)

Hope this Helps!!!

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