Day
Distance
(miles)
1
Tuesday
Wednesday
Thursday
214
1%
Jesse is training for his track meet on Saturday. This chart shows the number of miles he ran on Tuesday, Wednesday, and Thursda
How many mites did Jesse run on these 3 days

Step-by-step explanation:

The answer is

[tex]q = \frac{cd}{p} [/tex]

Answer:

one tree is 3 feet tall

most of the trees are less than 5 feet tall

Step-by-step explanation:

Answer: Whats the question? I dont see

Step-by-step explanation:

Answer:

$905

Step-by-step explanation:

$50×h+55=?

h=17 and you pay so $50×h

so $50×h=850

so now that you calculated the cost of the labor add the $55 dollar service fee

850+55=905

Answer: 3

Step-by-step explanation:

N=7

Answer:

hshshshshshshshsiqkZjfdudiodjfhfbbxdudijdd

Answer:

to be able to derive the formula if needed

Step-by-step explanation:

as you gain more class grades they sometimes ask you the origin of a certain formula that's why

Answer:

b

Step-by-step explanation:

Answer:

B) 8x + 6 + 4 = 3x - 2x - 4

Step-by-step explanation:

Just took the test on edg :)

The image showing the complete question is attached.

Answer:

1) Scale factor = 2

2) Scale factor = 4

3) Scale factor = ½

4) Scale factor = 2

5) Scale factor = 1

6) Scale factor = ¼

7) Scale factor = 1

Step-by-step explanation:

Scale factor is a number by which the dimensions of an object are multiplied in order to create an enlarged or reduced object.

Now, from the image attached;

1) From P to Q, we see that the length of Q seems to be double that of P. Similarly, the width of Q seems to be double that of P. Thus, each dimension of P is said to be multiplied by 2 to achieve the enlarged dimensions of Q.

Thus, scale factor = 2

2) From P to R, we see that the length of R seems to be 4 times that of P. Similarly, the width of R seems to be 4 times that of P. Thus, each dimension of P is said to be multiplied by 4 to achieve the enlarged dimensions of R.

Thus, scale factor = 4

3) From Q to S, we see that the length of S seems to be half of that of Q. Similarly, the width of S seems to be half of Q. Thus, each dimension of Q is said to be multiplied by ½ to achieve the reduced dimensions of S.

Thus, scale factor = ½

4) From Q to R, we see that the length of R seems to be double that of Q. Similarly, the width of R seems to be double that of Q. Thus, each dimension of Q is said to be multiplied by 2 to achieve the enlarged dimensions of R.

Thus, scale factor = 2

5) From S to P, we can see that the dimensions of both rectangles remain the same. Thus, S was multiplied by a factor of 1 to get P. Scale factor = 1

6) From R to P, we see that the length of P seems to be a quarter that of R. Similarly, the width of P seems to be quarter of R. Thus, each dimension of R is said to be multiplied by ¼ to achieve the reduced dimensions of P.

Thus, scale factor = ¼

7) From P to S, we can see that the dimensions of both rectangles remain the same. Thus, P was multiplied by a factor of 1 to get S. Scale factor = 1

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

[tex]A = \frac{1}{2}\cdot b\cdot h[/tex] (Eq. 1)

Where:

[tex]A[/tex] - Area of the triangle, measured in square centimeters.

[tex]b[/tex] - Base of the triangle, measured in centimeters.

[tex]h[/tex] - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

[tex]\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}[/tex] (Eq. 2)

Where:

[tex]\frac{dA}{dt}[/tex] - Rate of change of area in time, measured in square centimeters per minute.

[tex]\frac{db}{dt}[/tex] - Rate of change of base in time, measured in centimeters per minute.

[tex]\frac{dh}{dt}[/tex] - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

[tex]\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}[/tex]

[tex]\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}[/tex] (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

[tex]b = \frac{2\cdot A}{h}[/tex]

If we know that [tex]A = 130\,cm^{2}[/tex], [tex]h = 15\,cm[/tex], [tex]\frac{dh}{dt} = 2.5\,\frac{cm}{min}[/tex] and [tex]\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}[/tex], the rate of change of the base of the triangle in time is:

[tex]b = \frac{2\cdot (130\,cm^{2})}{15\,cm}[/tex]

[tex]b = 17.333\,cm[/tex]

[tex]\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)[/tex]

[tex]\frac{db}{dt} = -2.262\,\frac{cm}{min}[/tex]

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Answer:   -2

:)

Step-by-step explanation:

Answer:

x= 7.5

(that should be the answer)

Step-by-step explanation:

-7x+50 = x-10

10+50 = x+7x

60= 8x

60/8 = x

7.5= x

Answer:

-7 minus 9 = -16

-3-(-10) =7

8-12=-4

4-(-5)=9

Step-by-step explanation:

im in 7th grade on edginuity got it all right

Answer:

15

Step-by-step explanation:

Pretend a is the number.

We have: 31 + 3a = 76

=> 3a = 76 - 31 = 45

=> a = 45/3

=> a = 15

Answer:

The third answeer

Step-by-step explanation:

Also nice talk

Answer:

x=11/2

Step-by-step explanation:

4+5x‒7=10+3x‒2

5x‒3=8+3x

5x‒3x=8+3

2x=11

2x/2=11/2

x=11/2

Answer:

x=11/2

Step-by-step explanation:

For section 3.01 black, number 1 is correct, but number 2 is wrong.

When you raise an exponent to an exponent, you multiply the 2 exponents.

(x^4)^5 is x^20.

Number 3 is also right.

For 3.02, you use the interest formula. (1 + i/100)^t times x

x is the amount of money you have originally. i is the interest rate, t is the time.

1,500(1.03)^5 = 1738.91111145

$1738.91

For section 3.01 red in fractional exponents the numerator are the powers and the denominator is the root.

[tex]\sqrt[4]{a^{3} } = a^{\frac{3}{4} }[/tex]

Answer:

For section 3.01 black, number 1 is correct, but number 2 is wrong.

When you raise an exponent to an exponent, you multiply the 2 exponents.

(x^4)^5 is x^20.

Number 3 is also right.

For 3.02, you use the interest formula. (1 + i/100)^t times x

x is the amount of money you have originally. i is the interest rate, t is the time.

1,500(1.03)^5 = 1738.91111145

$1738.91

For section 3.01 red in fractional exponents the numerator are the powers and the denominator is the root.

Step-by-step explanation:

Answer:

where's the map

Step-by-step explanation:

Answer:

1.3 meters per sec

Step-by-step explanation:

7.8/6=1.3

hope this helps :3

if it did pls mark brainliest ^^

Answer:

R(x) = -50x2 + 300x + 2000

Maximum revenue of $2450 with x = 3

Step-by-step explanation:

For each 1$ reduced of the price, he sells 50 more candle sets, so if he reduces x times the price by 1$, the final price will be:

price = 10 - x

And the number of sets sold will be:

sets = 200 + 50x

If the revenue is the price times the number of sets sold, we have that:

R(x) = (10 - x) * (200 + 50x)

R(x) = 2000 + 500x - 200x - 50x2

R(x) = -50x2 + 300x + 2000

To find the value of x that gives the maximum revenue, we use the formula of the vertex of the quadratic equation:

x_v = -b / 2a

x_v = -300 / (-100) = 3

And the maximum revenue is:

R(x_v) = -50*3^2 + 300*3 + 2000 = $2450

Answer:

My sister apologized for telling everyone my secret.

Explanation:

Reported (or indirect) speech is a way to express someone's words without explicitly quoting them. The original sentence is an example of direct (quoted) speech, which means that someone's exact words are repeated. An obvious sign of this are the quotation marks. When it comes to the reported speech, these quotation marks are omitted because a direct quotation is no longer present.

Answer:

13.7

Step-by-step explanation:

A{2} + B{2} =C{2} \\

6{2} +B{2} =15{2} \\

6x6+B(2) =15x15\\

36+B(2)=225\\

           -36\\

           \sqrt{189} =13.7

Answer:

Cash it at the issuing bank (this is the bank name that is pre-printed on the check)

Cash a check at a retailer that cashes checks (discount department store, grocery stores, etc.)

Cash the check at a check-cashing store.

Deposit at an ATM onto a pre-paid card account or checkless debit card account.

Step-by-step explanation:

Answer:

Amscot?

Step-by-step explanation:

Answer:

The surface area of the log including the ends and the inside is 80424.8 cm²

Step-by-step explanation:

To determine the surface area of the log with hollow center including the ends and the inside, we will find the surface area of the outer part of the log, surface area of the inner part of the log and the surface area of the two ends; and then sum everything up.

From the question,

Diameter of log = 60 cm

Length of log = 3 m = 300 cm

Diameter of hollow center = 20 cm

For the surface area of the outer part,

Area of the outer part = Circumference of the outer part × length

Circumference = 2πr = πd

∴ Area of the outer part = πd × l

(NOTE: d here is the diameter of the log)

d = 60 cm and l = 300 cm

Area of the outer part = 60π × 300 = 18000π cm²

For the surface area of the inner part,

Area of the inner part = Circumference of the inner part × length = πd × l

(NOTE: d here is the diameter of the hollow center)

d = 20 cm and l = 300 cm

Area of the inner part = 20π × 300 = 6000π cm²

For the surface area of one end

This is the difference between the area of the outer end and the area of the inner end

Here, we can determine the area by using

Area = πr², where r is the radius

Radius = Diameter / 2

Radius of outer end (R) = Diameter of log / 2 = 60cm / 2 = 30cm

Radius of inner end (r) = Diameter of hollow center / 2 = 20cm / 2 = 10 cm

∴ Surface area of one end = πR² - πr² = π(R²-r²)

= π (30²-10²)

= π (900 - 100)

= 800π cm²

This is the area of one end

For the two ends,

Area of the two ends = 2 × 800π cm² = 1600π cm²

Hence, the surface area of the log is 18000π cm² + 6000π cm² + 1600π cm²

Surface area of the log = 25600π cm²

Putting the value of π (π = 3.141592654)

Surface area of the log = 25600 × 3.141592654 cm²

Surface area of the log = 80424.77193 cm²

Surface area of the log = 80424.8 cm²

Hence, the surface area of the log including the ends and the inside is 80424.8 cm² (to one decimal place)

Answer:

3 : 1

Step-by-step explanation:

The biggest circle has a radius of 20 cm

So that means, its area will be,

Area = [tex]\pi r^{2}[/tex]

Area = [tex]\pi * 20^{2}[/tex]

A = [tex]\pi * 400[/tex]

=> A = 400[tex]\pi[/tex]

We do not need to solve this because it is nit required

Then, one small circle has an area of,

Area = [tex]\pi r^{2}[/tex]

Area = [tex]\pi *5^{2}[/tex]

Area = [tex]\pi *25[/tex]

=> Area = 25[tex]\pi[/tex]

As there are 4 circles in, we get that the area covered by the small squares,

=> [tex]25\pi * 4[/tex]

=> [tex]100\pi[/tex]

So, the amount shaded = 100/400 (We can omit the [tex]\pi[/tex] at this stage because we are finding out a ratio)

=> 1/4

So, there is 1 cut region and the remaining is the uncut region,

As we need to find uncut to cut, the ratio will be,

=> remaining : 1

=> 3 : 1

If my answer helped, kindly mark me as the brainliest!!

Thanks!!

I've attached an image showing the coordinates of Ship A and Ship B.

Answer:

distressed vessel is located at (1, 1.5)

Step-by-step explanation:

From the image attached, we can see that;

Coordinate of ship A is (3, 4)

Coordinate of ship B is (1, 1)

Now, we are told that Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north.

This means that the distressed ship is somewhere in between ship A & B.

To solve this, we will extend the arrow line from Ship A in that same SW direction and we will do the same for ship B in the same North direction. Their point of intersection is where the distressed ship is located.

Now, if we do that, we will see that they will intersect at the point; (1, 1.5)

Thus,distressed vessel is located at (1, 1.5)

Answer:

Kindly check explanation

Step-by-step explanation:

For a normal distribution with :

Mean(m) = 0

Standard deviation (s) = 1

Calculate :

(a) less than 1.17 NM Probability

Zscore = (x - m) / s = (1.17 - 0) / 1 = 1.17

P(z < 1.17) = 0.879

(b) between 1.04 NM and 1.99 NM Probability

Zscore = (x - m) / s = (1.04 - 0) / 1 = 1.04

P(z < 1.04) = 0.8508

Zscore = (x - m) / s = (1.99 - 0) / 1 = 1.99

P(z < 1.99) = 0.9767

(0.9767 - 0.8508) = 0.1259

(c) greater than 0.93 NM Probability

P(Z > 0.93) = 1 - p(Z < 0.93) = 1 - 0.8238 = 0.1762

(d) between 0.24 NM and 0.73 NM Probability

P(Z < 0.24) = 0.5948

P(Z <0.73) = 0.7673

0.7673 - 0.5948 = 0.1725

(e) less than or equal to 2.3 NM Probability

P(Z ≤ 2.3) = 0.9893

(f) greater than 2.22 NM or less than .65 NM

P(Z > 2.22) = 1 - p(Z < 2.22) = 1 - 0.9868 = 0.0132

P(Z < 0.65) = 0.7422

0.7422 - 0.0132 = 0.729

(g) greater than or equal to 2.0 NM Probability

P(Z ≥2) = 1 - p(Z ≤ 2)

1 - 0.97725 = 0.02275

Answer:

The big container holds 30 gallons and the small container holds 20 gallons

Step-by-step explanation:

Let

The big container = x

Small container = y

The big container can hold 10 gallons less than twice the small

x = 2y - 10

Total gasoline in both containers = 50 gallons

x + y = 50

Substitute x = 2y - 10 into the equation

2y - 10 + y = 50

3y = 50 + 10

3y = 60

Divide both sides by 3

y = 60 / 3

= 20

y = 20 gallons

Recall,

x + y = 50

x + 20 = 50

x = 50 - 20

= 30

x = 30 gallons

The big container holds 30 gallons and the small container holds 20 gallons

Answer:

The big container has 30 gallons and the small container has 20 gallons.

Step-by-step explanation:

Answer:

C) 53°

Step-by-step explanation:

We know that <3 and <4 are equal, so we can solve for y.

3y+7=5y-73

7+73=5y-3y

80=2y

y=40

Now plug that in to <3

3y+7=3(40)+7=127

We know that <3 and <2 equal 180.

180-127=53

So <2=53°