Cyclic Redundancy Check (CRC) is an effective error detection mechanism. Suppose you have data bits of 10010011011 and divisor is 10011. As per the given information, what is encoding bits at the sender side? Similarly, at the receiver end ensure syndrome value is zero. Follow all necessary steps to complete calculation at both ends.

Answer:

Lack of segregation of duties

Explanation:

Internal Controls are set of rules and guidelines that are followed to ensure effectiveness of business operations. The main risk in the business is weak internal controls. There are some organizations with strong internal controls but implementation of such controls is a challenge for organizations. There are human errors, IT security risks, fraud and compliance risk.

The risks associated with Olive limited is that there is no segregation of duties, Richard Palm is preparing journal vouchers, posts the journal vouchers and reconciles the balance himself. If he makes an error in recording a transaction there is no one who reviews his work and can identify an error. Also if Richard is involved in a fraud and collaborates with purchase department or sales department staff, he can pass a transaction without any supervision.

Answer:

numbers = []

count = 0

while True:

   number = int(input("Enter a number: "))

   if number < 0:

       break

   else:

       numbers.append(number)

       count += 1

min_number = min(numbers)  

print(str(min_number) + " was the smallest among " + str(count) + " entered numbers.")

Explanation:

Initialize an empty array, to hold the entered numbers, and count as 0

Create a while loop that iterates until a specific condition is met

Inside the loop, ask the user to enter the numbers. When the user enters a negative number terminate the loop. Otherwise, add the entered number to the numbers array and increment the count by 1.

When the loop is done, find the smallest of the number in the numbers array using min method and assign it to the min_number.

Print the min_number and count

Explanation:

Evaluating the solution is the last step of the problem solving process.

Answer:The users would likely know if an upgrade would be necessary or even useful.

First hand user information is often ignored by developers, change managers etc. However, obtaining first hand user input has proven vastly cost effective ,productive and easier to apply . By having early input the actual working interface can be designed so that daily users find it works effectively for them and others they interact with. It can also allow users to effectively aim to break the functionality before a crisis occurs etc. Furthermore by having user input the users will make a greater effort in ensuring the upgrade works seamlessly.

Explanation:

Answer:

A secure password has the following characteristics:

Phishing is a kind of social engineering where a cyber criminals  trying to trick the victims to get benefit from them. For example, a cyber criminal can send a phishing email to tell the victims about something wrong with their credit card or bank account and provide a malicious link and persuade the victim to access their fake website that resembles an official bank website.  From there, the victims can send credential info to the cyber criminals without their awareness. Phishing can also be done through phone call. Phishing is harmful as a victim can fall into the trap of disclosing highly critical credential info that incur a huge loss of money.

Answer:

Red=R, Yellow=Y, Blue=B, Orange=O, Green=G, Purple=P

Explanation:

Colors of chemical is a physical property which comes from excitation of electrons. The electrons absorbs energy which enables the chemical to change its color. The correct sequence to create cure is to use red, yellow and blue then add gradually the other colored chemicals.

Answer:

I do Stray kids and Tower Of God is good combo mannnn

Answer:

Yes

Explanation:

I dont comprehend how this question requires any intellectual answer but it's ok.

Answer:

Storage devices tend to be built in/physical pieces of storage such as an SD Card or Hard Drive. Virtual storage is more-so like Cloud storage, where the files are hosted elsewhere.

Explanation:

Answer:

A java program was used to run a simple math quiz. the program was used to generate two random integers between 1 and 20 and then ask a series of math questions

Explanation:

Solution

THE CODE:

import java.util.Random;

import java.util.Scanner;

public class LabQuiz {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.println("****Welcome to Quiz******");

System.out.print("Enter your name: ");

String name = in.next();

System.out.println("Welcome "+name+"! Please answer the following questions:");

int scoreCounter=0;

int a;

int b;

int response;

a=getRandomNum();

b=getRandomNum();

System.out.print(a+"+"+b+"=");

response = in.nextInt();

if(response==(a+b)){

scoreCounter++;

System.out.println("That is correct");  

}  

else

System.out.println("No, thats not the right answer, its::"+(a+b));

a=getRandomNum();

b=getRandomNum();

System.out.print(a+"*"+b+"=");

response = in.nextInt();

if(response==(a*b)){

scoreCounter++;

System.out.println("That is correct");  

}  

else  

System.out.println("No, thats not the right answer, its::"+(a*b));

a=getRandomNum();

b=getRandomNum();

System.out.print(a+"/"+b+"=");

response = in.nextInt();

if(response==(a/b)){

scoreCounter++;

System.out.println("That is correct");

}

else

System.out.println("No, thats not the right answer, its::"+(a/b));

a=getRandomNum();

b=getRandomNum();

System.out.print(a+"%"+b+"=");

response = in.nextInt();

if(response==(a%b)){

scoreCounter++;

System.out.println("That is correct");  

}

else

System.out.println("No, thats not the right answer, its::"+(a*b));

System.out.println("You got "+scoreCounter+" correct answers.");

System.out.println("Thats "+(scoreCounter*25)+"%");

in.close();  

}

static int getRandomNum(){

Random rand = new Random();

int a;  

a = rand.nextInt(20);

if(a==0)

a++;  

return a;  

}  

}

The correct format for the output this tree is shown below:

(1) Output this tree

    ×

  ×××

×××××

×××××××

  ×××

(2) The correct format for the Below the tree is shown below:

Below the tree (with two blank lines), output this cat. (3 pts)

  / \        / \

     o     o

 =           =

   -   -   -

Answer:

Explanation:

We are given an Hint that:

A backslash \ in a string acts as an escape character, such as with a newline \n. So, to print an actual backslash, escape that backslash by prepending another backslash.

An Example : The following prints a single backslash: System.out.println("\\");

The main objective here is to use a Java code to interpret the above  (1) Output this tree and  (2) Below the tree.

So Using a Java code to interpret the Program: ASCII art ; we have:

public class AsciiArt {

  public static void main(String[] args) {

      // TODO Auto-generated method stub

      //Draw Tree

    System.out.println(" *");

      System.out.println(" ***");

      System.out.println(" *****");

      System.out.println("*******");

      System.out.println(" ***");

      //output cat

      System.out.println();

      System.out.println("/\\\t/\\");

      System.out.println(" o o");

      System.out.println(" = =")

      System.out.println(" ---");

  }

OUTPUT:

SEE THE ATTACHED FILE BELOW.

The program is a sequential program, and does not require loops and conditional statements.

See attachment for the complete program written in Python, where comments are used as explanation

Read more about Python programs at:

https://brainly.com/question/16397886

Answer:

The odds for the event that either Romance or Downhill wins is 11/4

Explanation:

The odds that Romance will win is 2: 3

The odds that Downhill will win is 1:2

[tex]P(event) = \frac{Odd(event)}{1 + Odd(event)}[/tex]

Where P(event) = Probability that an event occurs

Odd(event) = The odds that an event occurs

Calculate the Probability that Romance wins, P(R):

[tex]P(R) = \frac{2/3}{2/3 + 1} \\P(R) = 2/5[/tex]

Calculate the probability that Downhill wins, P(D):

[tex]P(D) = \frac{1/2}{1/2 + 1} \\P(D) = 1/3[/tex]

Calculate the Probability that either Romance or Downhill wins, P(R or D):

P(R or D) = P(R) + P(D)

P(R or D) = 2/5 + 1/3

P(R or D) = 11/15

[tex]P(R or D) = \frac{Odd(R or D)}{1 + Odd(R or D)} \\\\11/15 = \frac{Odd(R or D)}{1 + Odd(R or D)}\\[/tex]

[tex]\frac{11}{15} + \frac{11}{15}[ Odd(R or D)] = Odd(R or D)\\\\\frac{4}{15}[ Odd(R or D)] = \frac{11}{15}\\\\\\Odd(R or D) = \frac{11}{15} * \frac{15}{4}\\\\Odd(R or D) = 11/4[/tex]

Answer:

Top Secret, (A,B,C)

Explanation:

Solution:

Some information are known to be sensitive, and has a higher level of classification.

Examples for such levels are: Secret, Top secret ,Unclassified and  Confidential, and Unclassified.  all users of the system has a  level of clearance. fro a user to be able to gain access to document, he or she must have posses a level of the document.

Now, this is governed by two rules which is stated below:

No user can have access to any information that is considered higher than their level of clearance.

Secondly, a user can write to files only that contains an equal level or lower of his clearance level, this is to stop what is called the write down effect.

It is important to note that ABC, categories determine what type of access is permitted.

Now, for the given example, since, Bob and charlie cannot read it, which shows that the file must be of top priority or importance, then Bob and Charlie needs clearance to the file,the file 2 is considered a top priority.

Therefore, the File 2 is classified as a Top Secret, (A,B,C)

Answer:

Software? or a person?

Answer:

cout << setprecision(2)<< fixed << number;

Explanation:

The above statement returns 12.35 as output

Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.

The statement starts by setting precision to 2 using setprecision(2)

This is immediately followed by the fixed manipulator;

The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;

Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.

The fixed manipulator is then followed by the variable to be printed.

See code snippet below

#include <iostream>  

#include <iomanip>

using namespace std;  

int main()  

{  

// Initializing the double value

double number = 12.3456;  

//Print  result

cout << setprecision(2)<< fixed << number;  

return 0;  

}  

Answer:

  generate a random number in a known range and map the result to the range you want

Explanation:

Use any of the usual methods to get a random number in the range 0-20, then subtract 9. Use an IF statement to test if the result is 0. If it is, replace the value with -10.

Answer:

Physical / Data link layer

Explanation:

If two computers (A & B) are directly connected through Ethernet cable. A is sending data to B, the data would be transmitted if the network is clear but if the network is not clear, the transmission would wait until the network is clear.

The Open Systems Interconnection model (OSI model) has seven layers each with its own function.

The physical layer is the first layer responsible for data transmission over a physical link. The data packets are converted to signals over a transmission media like ethernet cable.

The data link layer is the second layer in the OSI layer responsible for transmission of data packets between nodes in a network. It also provides a way of detecting errors and correcting this errors produced as a result of data transmission.

Answer:

import math

n = int(input("Enter the number of sides: "))

s = float(input("Enter the length of a side: "))

area = (n * s**2) / (4 * math.tan(math.pi/n))

print("The area is: " + str(area))

Explanation:

*The code is in Python.

Import the math to be able to compute the pi and tan

Ask the user to enter the number of sides and the length of a side

Calculate the area using the given formula

Print the area

Answer:

C

Explanation:

Answer:

Following are code that we fill in the given in the given question

if i %2==0:# check the condition

new_list.append(elements[i])# append the list  

return new_list # return the new_list

Explanation:

Missing Information :

def skip_elements(elements):# function

new_list=[]# Declared the new list

i=0  #variable declaration

for i in range(len(elements)): #iterating over the loop  

if ---------# filtering out even places elements in the list

--------------# appending the list

return -------- # returning the new_list

print(skip_elements(['a','b','c','d','e','f','g'])) #display

Following are the description of the code:

Answer:

Nothing just the video is series of photos together

Explanation:

Answer:

A central processing unit (CPU) is an important part of every computer. The CPU sends signals to control the other parts of the computer, almost like how a brain controls a body. The CPU is an electronic machine that works on a list of computer things to do, called instructions. hope that helps love!

Answer: provided in the explanation section

Explanation:

 Network’s vulnerabilities:

           Vulnerability is a weak spot in your network that might be exploited by a security threat. Risks are the potential consequences and impacts of unaddressed vulnerabilities. In other words, failing to do Windows Updates on your Web server is vulnerability.

           Regularly scheduled network vulnerability scanning can help an organization identify weaknesses in their network security before the bad guys can mount an attack. The goal of running a vulnerability scanner or conducting an external vulnerability assessments is to identify devices on your network that are open to known vulnerabilities without actually compromising your systems.

           The overall objective of a Vulnerability Assessment is to scan, investigate, analyze and report on the level of risk associated with any security vulnerabilities discovered on the public, internet-facing devices and to provide your organization with appropriate mitigation strategies to address those discovered vulnerabilities.

Network topology issues:

Coverage Topology

           Coverage problem reflects how well an area is monitored or tracked. The coverage and connectivity problems in networks have received considerable attention in the research community in recent years

Geographic routing

           Geographic routing uses geographic and topological information of the network to achieve optimal routing schemes with high routing efficiency and low power consumption

Port Numbers

           Port Numbers While IP addresses determine the physical endpoints of a network connection, port numbers determine the logical endpoints of the connection. Port numbers are 16-bit integers with a useful range from 1 to 65535.

Port numbers are assigned by an organization called IANA and ports are allocated to various needs to avoid confusion.

Ports are classified into 3 main categories.

Well Known Ports (Port numbers 0 - 1023)

           In a client-server application, the server usually provides its service on a well-known port number. Well-known port numbers are a subset of the numbers which are assigned to applications. According to RFC1700 [5], well-known port numbers are managed by the Internet Assigned Numbers Authority (IANA). They used to be in the range from 1 to 255, but in 1992 the range was increased up to 1023.

Registered Ports (Port numbers1024 - 49151)

Such ports are used by programs run by users in the system.

           In addition to the well-known ports below 1024 there are more port numbers assigned to applications but are located anywhere from 1024 to 65535.

Private or Dynamic Ports (Port numbers 49152 - 65535)

           Private ports are not assigned for any specific purpose.

Discuss the concepts of well-known ports and give a brief description of the most commonly used ports: 20, 21, 23, 25, 53, and 110.

Commonly Used Port Numbers

The following port numbers are unofficial list of commonly used for linux/unix based servers.

20&21               TCP                FTP (File server protocol)

           FTP is one of the most commonly used file transfer protocols on the Internet and within private networks. An FTP server can easily be set up with little networking knowledge and provides the ability to easily relocate files from one system to another. FTP control is handled on TCP port 21 and its data transfer can use TCP port 20 as well as dynamic ports depending on the specific configuration.

23                   TCP/UDP          Telnet

           Telnet is the primary method used to manage network devices at the command level. Unlike SSH which provides a secure connection, Telnet does not, it simply provides a basic unsecured connection. Many lower level network devices support Telnet and not SSH as it required some additional processing. Caution should be used when connecting to a device using Telnet over a public network as the login credentials will be transmitted in the clear.

25                   TCP/UDP         SMTP   (for sending outgoing emails)

           SMTP is used for two primary functions, it is used to transfer mail (email) from source to destination between mail servers and it is used by end users to send email to a mail system.

53         TCP/UDP        DNS Server (Domain name service for DNS request)

           The DNS is used widely on the public internet and on private networks to translate domain names into IP addresses, typically for network routing. DNS is hieratical with main root servers that contain databases that list the managers of high level Top Level Domains (TLD) (such as .com). T

110             TCP                 POP3 (For receiving emails)

           POP version 3 is one of the two main protocols used to retrieve mail from a server. POP was designed to be very simple by allowing a client to retrieve the complete contents of a server mailbox and then deleting the contents from the server.

Answer:

The java program for the given scenario is shown below.

import java.util.*;

import java.lang.*;

public class Test

{

   //variables to hold the number, digits and sum of the digits

   //variable to hold number is assigned any random value

   static long num=123;

   static int sum=0;

   static int digit;

   static int s;

   //method to add digits of a number

   public static int sumDigits(long n)

   { do

       {

           digit=(int) (n%10);

           sum=sum+digit;

           n=n/10;

       }while(n>0);

       return sum;

   }

public static void main(String[] args) {

    s = sumDigits(num);

 System.out.println("The sum of the digits of "+num+ " is "+s);  }

}

OUTPUT

The sum of the digits of 123 is 6

Explanation:

1. The variables to hold the number is declared as long and initialized.

2. The variables to store the digits of the number and the sum of the digits are declared as integer. The variable, sum, is initialized to 0.

3. The method, sumDigits(), is defined which takes a long parameter and returns an integer value. The method takes the number as a parameter and returns the sum of its digits.

4. Inside method, sumDigits(), inside the do-while loop, the sum of the digits of the parameter is computed.

5. Inside main(), the method, sumDigits(), is called. The integer value returned by this method is stored in another integer variable, s.

6. The sum of the digits is then displayed to the console.

7. All the variables are declared outside main() and at the class level and hence declared static. The method, sumDigits(), is also declared static since it is to be called inside main().

8. In java, the whole code is written inside a class since java is a purely object-oriented language.

9. In this program, object of the class is not created since only a single class is involved having main() method.

10. The program can be tested for any value of the variable, num.

11. The file is saved as Test.java, where Test is the name of the class having main() method.

Answer:

The program goes as follows

Comments are used to explain difficult lines

#include <iostream>

#include <string>

using namespace std;

int main()

{

string userinput;

getline(cin,userinput);

/* My Solution starts here*/

//Initialize sub string position to 0

int stringpos = 0;

// Declare an iterating variable to iterate through userinput

int startpos;  

//Declare and initialize a determinant variable

int k = 0;

while((startpos = userinput.find("darn",stringpos))!=string::npos)

{

 //If userinput contaings "darn", increase k by 1

k++;

// Go to next string position

stringpos = startpos+1;  

}

//If determinant variable k is p then, userinput does not contain "darn"

if(k==0)

{

 cout<<userinput;

}

//Otherwise, it contains "darn"

else

{

 cout<<"Censored";

}

/* My Solution ends here*/

return 0;

}

See attached for .cpp program file

Answer:

Explanation:

The underlined traits in the ER chart speak to essential key since they remarkably recognize the quality  

(a)

(I) The level of the given relationship is 2 i.e it is a parallel connection among Book and Publisher. It is a one to numerous relationship from distributer to book in light of the fact that a distributer can distribute any number of books however a book will have only one publisher,so the cardinality will be 1 to 1..* (one to many)

(b)

(i) The degree of the given relationship is 2 i.e it is a binary relationship between Author and Book. It is a many to many relationship from Book to Author a book can be written by one or more authors and an author can write more than one book, so the cardinality will be 1..* to 1..* (many to many)

(c)

(i) As mentioned in part (b), the degree of given relation is 2 and cardinality is many to many (1..* to 1..*)

(d)

(i) The degree of the given relationship is 1 i.e unary relationship. It is a many to many relationship because one book can belong to any sets and a set can have any number of books, so cardinality is 1..* to 1..* (many to many)

Note: attached below is the image of various options to confirm the explanation (answer).

cheers i hope this helped !!!

Answer:

weight = float(input("Enter your weight in pounds: "))

height = float(input("Enter your height in inches: "))

weight = weight * 0.45359237

height = height * 0.0254

bmi = weight / (height * height)

print("Your BMI is: %.4f" % bmi)

Explanation:

*The code is written in Python.

Ask the user to enter weight in pounds and height in inches

Convert the weight into kilograms and height into meters using given conversion rates

Calculate the BMI using given formula

Print the BMI

Answer:

This is createing a responsive website form for clients.

Explanation:

Using HTML, CSS and JavaScript or python to create an interactive, dynamic website. The html file is used to structure the layout of the website Dom , the CSS, also known as cascaded style sheet is using to style the created web pages. The CSS libraries and frameworks like sass, less and bootstraps can be used for convenience and speed. The JavaScript file is used to manipulate the Dom, creating an interactive site. Python libraries likes flask are used for backend development routing to create dynamic contents and web pages.

Answer:

Webcast

Explanation:

Webcast is the live broadcast of a video or audio feed from your event or conference harnessing the internet. Webcast is a media presentation of an event circulated over the internet by using media technology to distribute a single source to various viewers.

Generally,  webcast is briefly defined as broadcasting over the internet. The broadcast might not be specifically live  . One can capture the video or the audio he or she wants to publish and publish it online anywhere. Webcast allow your viewers to remain engage as if they are face to face with the broadcaster.

Webcasting is a a great tools that has been used by various multinational and company to reach wide range of audience . This web based broadcast can even provide opportunity for audience to ask question and even provide answers in real time.

Answer:

Webcast.

Explanation:

A Webcast is a form of Web conferencing that uses streaming media technologies to broadcast video and/or audio over the Internet from a single content source to many listeners or viewers simultaneously.

The Webcast is an internet conferencing tool that transmits and stores, corporate presentations, lectures, workshops, seminars, etc., with the advantage of being a simple operation tool that can bring together groups in real time offering dynamism and reducing geographical distance.

It is a widely used and useful tool for companies, as it can help when traditional communication channels are not sufficient to deal with extremely relevant issues for the company, such as training and presentation of materials for prospecting customers.

The Webcast is an advantageous technology for companies by reducing personnel displacement and reducing costs with facilities, infrastructure and space rental.

Answer:

Following is the program in the C language

#include <stdio.h> // header file  

int main() // main function

{

float weight1[10]; // array declaration  

float sum=0,max1,t; // variable declaration

for(int k = 0; k < 5; k++) //iterating the loop

{

printf("Enter weight %d: ",k+1);

scanf("%f",&weight1[k]); // Read the array by user

}

printf("\n");

printf("You entered: ");

max1=weight1[0];

for(int k = 0; k < 5 ; k++)

{

sum=sum+weight1[k];

if(max1 < weight1[k]) // check condition for highest element

{

max1=weight1[k];

}

printf("%.2lf ",weight1[k]);

}

t=sum/5.0; // find average

printf("\nTotal weight: %.2lf\n",sum); // displat total

printf("Average weight: %.2lf\n",t); // display Average

printf("Max weight: %.2lf\n",max1); // display maximum value

return 0;

}

Output:

Enter weight 1: 1

Enter weight 2: 2

Enter weight 3:3

Enter weight 4:4

Enter weight 5: 5

You entered:  1.00  2.00  3.00  4.00  5.00

Total weight: 15.00

Average weight:  3.00

Max weight:  5.00

Explanation:

Following are description of program :