Check all the answers that apply. Energy is the ability to
A. Change temperature
B. Change speed
C. Do work
D. Change direction

Answer:

2 : 1

Explanation:

Given that The magnitude of the acceleration due to gravity on the surface of planet A is twice as great as on the surface of planet B. What is the ratio of the weight of mass X on the surface of planet A to its weight on the surface of planet B?"

Since the magnitude of the acceleration due to gravity on the surface of planet A is twice as great as on the surface of planet B. And

Weight W = mg

Mass is always constant

2g : g

The ratio of the weight of mass X on the surface of planet A to its weight on the surface of planet B will be:

2 : 1

Answer:

θ = 0

Explanation:

As per the question Given that

Magnitude = 2m

Force F contains MAgnitude = 4N

Based on the above information

T = rFsinθ

Now if

T = 0,

so r and F would not be zero so that sinθ  should be equivalent to zero for holding an equation

Therefore

θ = 0

The same is to be considered as it is relevant as per the question

Answer:

7.43m/s

Explanation:

Given parameters:

Initial velocity = 1.7m/s

Height  = 2.5m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we apply one of the motion equation. The most fitting one given the parameters is;

           V²  = U² + 2gh

where V is the final velocity

           U is the initial velocity

          g is the acceleration due to gravity = 9.8m/s

           h is the height

Input the parameters and solve;

    V² = 2.5² + 2(9.8)(2.5)

    V = 7.43m/s

Answer:

Explanation:

Let the two forces be acting in the horizontal direction on the object.

Given

Mass m = 6kg

One of the force = 10N

acceleration = 2m/s²

Taking the sum of forces along the x component, we will have:

[tex]\sum F_x = ma_x\\Ff - 10 = 6(2)\\Ff - 10 = 12\\Ff = 12+10\\Ff = 22N[/tex]

Note that Ff is the greatest possible magnitude of the other force.

Hence the greatest possible magnitude of the other force is 22N

Answer:

Approximately [tex]28.3\; \rm kg[/tex], assuming that the spring was pulled horizontally.

Explanation:

Let [tex]k[/tex] denote the spring constant of this spring. Calculate the size of tension in this spring that corresponds to the [tex]\Delta x = 0.88\; \rm m[/tex] stretch:

[tex]F(\text{tension}) = k\cdot \Delta x = 45\; \rm N \cdot m^{-1} \times 0.88\; \rm m = 39.6\; \rm N[/tex].

(The negative sign is ignored.)

If the spring is pulled horizontally, then the tension that the spring exerts would be the only unbalanced force on this object. The net force n this object would be equal to the tension that the spring had exerted: [tex]39.6\; \rm N[/tex].

Newton's Second Law of motion suggests the following relation between the net force [tex]\sum F[/tex] on the object, the mass [tex]m[/tex] of the object, and the acceleration [tex]a[/tex] of the object:

[tex]\sum F = m \cdot a[/tex].

For this object, [tex]a = 1.4\; \rm m \cdot s^{-2}[/tex]. It has been found that the net force on this object is [tex]\sum F = 39.6\; \rm N[/tex]. Rearrange the original equation [tex]\sum F = m \cdot a[/tex] and solve for [tex]m[/tex], the mass of this object:

[tex]\displaystyle m = \frac{\sum F}{a} = \frac{39.6\; \rm N}{1.4\; \rm m \cdot s^{-2}} \approx 28.3\; \rm kg[/tex].

In other words (based on all these assumptions,) the mass of this object should be approximately [tex]28.3\; \rm kg[/tex].

Complete question is;

A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glow, sending the light through a diffraction grating, and measuring the positions of first-order spectral lines on a detector 15.0 cm behind the grating. Unfortunately, she has lost the card that gives the specifications of the grating. Fortunately, she has a known compound that she can use to calibrate the grating. She heats the known compound, which emits light at a wavelength of 461 nm, and observes a spectral line 9.95 cm from the center of the diffraction pattern.

What is the wavelength emitted by compound B that have spectral line detected at position and 12.15 cm?

Answer:

λ ≈ 525 nm

Explanation:

The diffraction grating equation of n-th order is given by;

nλ = dsinθₙ

For 1st order, n=1. Thus;L, we have;

λ = dsinθ₁

We are told that the first-order spectral lines on a detector 15.0 cm behind the grating. Also that, she observes a spectral line 9.95 cm from the center of the diffraction pattern.

Therefore, the angle of the known compound's 1st order is given by the relation:

tanθ₁ = 9.95/15

tanθ₁ = 0.6633

θ₁ = tan⁻¹(0.6633)

θ₁ = 33.56º

We are told that the unknown compound emits light at a wavelength of 461 nm.

Thus, from the first order equation above, we have;

d = λ/sinθ₁

d = 461nm/sin(33.56º)

d = 461nm/0.55281

d ≈ 834nm

λ = dsinθ₁= 870nm sin(29.68º) = 431nm

Now, spectral line is given as 12.15 cm from the center of the diffraction pattern. Thus;

θ₁ = tan⁻¹(12.15/15)

θ₁ = tan⁻¹(0.81)

θ₁ = 39°

Since λ = dsinθ₁

Thus;

λ = 834sin(39°)

λ = 834 × 0.6293

λ ≈ 525 nm

Answer:

The absolute pressure on me increases to 130,900 Pa.

Explanation:

Since I dive to a depth of 2.0 m, there is a depth change of 2.0 m which will cause a corresponding pressure change. The pressure change is thus ΔP = ρgΔh where ρ = density of water = 1000 kg/m³, g = acceleration due to gravity = 9.8m/s² and Δh = depth change = 2.0 m

ΔP = ρgΔh  =  1000 kg/m³ × 9.8m/s² × 2.0 m = 19,600 Pa.

Since the absolute pressure P at 1.0 m is the pressure due to atmosphere plus the pressure of 1.0 m of water, we have

P = P₀ + ρgΔh' where P₀ = atmospheric pressure = 101,500 Pa and Δh' = 1.0 m

P = 101,500 Pa + 1000 kg/m³ × 9.8m/s² × 1.0 m = 101,500 Pa + 9800 Pa = 111,300 Pa

So, the absolute pressure at 2.0 m is P' = P + ΔP = 111,300 Pa + 19,600 Pa = 130,900 Pa.

So the absolute pressure on me increases to 130,900 Pa.

Answer:

B. The medium increases in temperature while remaining in the same phase.

Explanation: The most important factor influencing the speed of sound in air is temperature. The speed is proportional to the square root of the absolute temperature, giving an increase. Due to this information, B is the best answer.

Answer:

Popped-Eye is 3 times more powerful than Mack Sparrow.

Explanation:

Popped-Eye is 6 times more powerful than Mack Sparrow.

In science and engineering, power is the rate at which work is completed or energy is delivered. It can be expressed as the product of the work completed (W) or the energy transferred (E) divided by the time interval (t), or W/t.

Given parameters:

Popped-Eye's treasure is three times heavier than Mack Sparrow's.

Mack Sparrow requires twice as much time.

So, Popped-Eye can lift  times heavier treasure  in half of time compere to Mack Sparrow .

Hence, Popped-Eye's power is 3÷(1/2) = 3×2 = 6 times more than Mack Sparrow's.

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Answer:

Explanation:

We have that the normal force acting on a mountain goat that weighs 550 N and is standing on such a slope is

N=275N

From the question we are told

Generally the equation for the normal force acting on a mountain goat   is mathematically given as

N=mgcos

N=550*cos60

N=275N

Therefore

The normal force acting on a mountain goat that weighs 550 N and is standing on such a slope is

N=275N

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Answer:

ω = 1899.5 radian / s

Explanation:

EMF induced by a rotating rod = 1 /2 B ω L² where ω is angular velocity of rod and L is its length . B is magnetic field

1 /2 B ω L² = 1.5

1/2 x .7 x ω x .0475² = 1.5

ω = 1899.5 radian / s

Answer:

c

Explanation:

Answer:

Exercise can reduce pain, relieve stress, and increase energy.Explanation:

Answer:

c frequency

hope it helps:))

Explanation:

To solve this we must be knowing each and every concept related to photon. Therefore, the correct option is option C. Photons with the lowest energy have the lowest frequency.

A photon, also known as a light quantum, is a small energy packet containing electromagnetic radiation. The idea came from Albert Einstein's explanation of something like the photoelectric phenomenon (1905), in which he hypothesized the possibility of energy levels packets during light transmission.

Photons all move just at speed of light. Photons are bosons that have no electric charge and rest mass one and unit of spin; they were field particle that are assumed to be the bearers of electromagnetic field. Photons with the lowest energy have the lowest frequency.

Therefore, the correct option is option C. Photons with the lowest energy have the lowest frequency.

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Answer:

Part C

Explanation:

The potential energy would increase almost 25%

Answer:

V_ce = 1128 m/s

Explanation:

We are given;

Speed of space vehicle relative to the earth; V_i = 4140 km/h = 1150 m/s

relative speed between the motor and the command module; V_mc = 99 km/h = 27.5 m/s

mass of the motor is four times the mass of the module.

If the mass of the module is m

Mass of motor = 4m

From conservation of momentum, since the system is isolated, then;

Initial momentum = final momentum.

Thus;

MV_i = 4m(V_me) + m(V_ce) - - - (eq 1)

Where;

M is mass of space vehicle

V_me is speed of motor relative to the earth

V_ce is speed of command module relative to the earth

Now, relative speed between the motor and the command module is given by the formula;

V_mc = V_me - V_ce

Thus, V_me = V_mc + V_ce

Putting (V_mc + V_ce) for V_me in eq 1, we have;

MV_i = 4m(V_mc + V_ce) + m(V_ce)

Now, the mass of the space vehicle will be the sum of the mass of the module and mass of the motor.

Thus;

M = m + 4m

M = 5m

Thus;

5mV_i = 4m(V_mc + V_ce) + m(V_ce)

Divide through by m to get;

5V_i = 4(V_mc + V_ce) + (V_ce)

5V_i = 4V_mc + 4V_ce + V_ce

5V_i = 4V_mc + 5V_ce

We want to find the speed of the command module relative to Earth just after the separation. Thus, let's make V_ce the subject;

V_ce = (5V_i - 4V_mc)/5

V_ce = ((5 × 1150) - (4 × 27.5))/5

V_ce = 1128 m/s

Answer:

0 J

Explanation:

Given data

force F=1.46N

mass m=0.1kg

time t= 3min

distance= 0 meters----"the object did not move"

We know that work-done is given as

work= Force * distance moved

Work= 1.46*0

work =0joules

We understand that when this is no distance move, then there is no work done, for work to be done, the object must move through a distance

B, Its the one with the kid trying to lift a weight.

Explanation:

Got it right Edge 2020.

Answer:

it's the weights kid!!! the other user got it thank them, i got it right bc of them :)

Explanation:

Answer:

dS/dt = 0.33 cm²/min

Explanation:

Volume of sphere is given by;

V = (4/3)πr³

We are told that gas is escaping from a spherical balloon 4 cm³ per minute. Thus; dV/dt = 4 cm³/min

Now, let's find the rate at which the radius is changing.

dr/dt = (dV/dt) ÷ (dV/dr)

Now, dV/dr = 4πr²

Thus;

dr/dt = 4/(4πr²)

dr/dt = 1/(πr²)

Now, surface area of sphere is given by;

S = 4πr²

Thus, dS/dr = 8πr

Now, let's find the rate at t which area is shrinking.

dS/dt = (dS/dr) × (dr/dt)

Plugging relevant terms, we have;

dS/dt = 8πr × 1/(πr²)

dS/dt = 8/r

At r = 24 cm, we have;

dS/dt = 8/24

dS/dt = 1/3

dS/dt = 0.33 cm²/min

Answer:

1. The object will not move at all.

Explanation:

The question above is related to "Newton's First Law of Motion." According to this law, an object that is at rest will remain in its position (at rest) unless acted upon by "unbalanced forces." If the forces applied to an object are balanced, the net force is zero. This means that the object will not move nor accelerate.

The law also mentioned that if the object is in motion, it will remain in same velocity (speed with direction) if there's no net force.

Answer:The ampere is unique in that it uses the base unit of time (t) in its definition (second). All other electrical and magnetic units (such as voltage, power, and magnetic flux) use various combinations of base units in their definitions and are called derived units.

Explanation:

Answer:

2.66 s

Explanation:

Given The initial angular speed ([tex]\omega_o[/tex]) =  1.34 x 10⁴ rad/s, the final angular speed (ω) = 4.37 x 10⁴ rad/s, the angular acceleration (α), distance (θ) = 3.10 x 10⁴ rad.

Using the formula:

[tex]\omega^2=\omega_o^2+2\alpha \theta\\\\Substituting:\\(4.37*10^4)^2=(1.34*10^4)^2+2(3.1*10^4)\alpha\\\\(4.37*10^4)^2-(1.34*10^4)^2=2(3.1*10^4)\alpha\\\\2(3.1*10^4)\alpha=1.73*10^9\\\\\alpha=2.79*10^4\ rad/s^2[/tex]

The constant acceleration = 2.79 * 10⁴ rad/s.

Since there is constant acceleration, to reach a final speed of  7.43 x 10⁴ rad/s, we use the formula:

[tex]\omega =\omega_o +\alpha t\\\\\omega_o=0,\omega=7.43*10^4\ rad/s,\alpha=2.79*10^4\ rad/s^2\\\\Substituting:\\\\7.43*10^4=0+2.79*10^4t\\\\7.43*10^4=2.79*10^4t\\\\t=2.66\ s[/tex]

Answer:

The minimum radius of the curve is 6125 m

Explanation:

Given;

speed limit of the highway, V = 90 km/h = 25 m/s

banking angle, θ = 45°

The minimum radius of the curve will be calculated by applying banking angle formula;

[tex]mg tan \theta = F_{centripetal \ force}\\\\mg tan \theta = \frac{mv^2}{r}\\\\ g tan \theta = \frac{v^2}{r}\\\\r = \frac{v^2}{ g tan \theta}\\\\r = \frac{(25)^2}{(9.8)(1)} \\\\r = 6125 \ m[/tex]

Therefore, the minimum radius of the curve is 6125 m

Answer:

I think A, a car shortly after a stoplight turns green OR if it's wrong it's B☺️

Answer:

c

Explanation:

Answer:

b

Explanation:

Answer:

C I just did it. so yeah....

The correct answer is B. Weight directly measures force while mass directly measures the amount of matter.

Explanation:

Weight and mass are two related but not identical concepts. The first term "mass" can be found by measuring the amount of matter in a body or substance. For example, the mass in an apple is around 80 grams depending on its size. In this context, mass is measured using units such as grams or kilograms. On the other hand, weight considers not only the matter in an object but the force exerted in it, especially, the gravitational force. In the case of the apple, the weight is 1 N as newtons (N) are used to measure force and this is the result of multiplying the mass by gravity. According to this, option B is correct.

Answer:

The value is  [tex]N = 6051 \ turns[/tex]

Explanation:

From the question we are told that

   The current is  [tex]I = 6.67 \ A[/tex]

  The length is  [tex]l = 13.6 \ cm = 0.136 \ m[/tex]

  The magnetic field is  [tex]B = 0.373 \ T[/tex]

Gnerally the number of turn per unit length is mathematically represented as

      [tex]n = \frac{B}{\mu_o * I}[/tex]

Here [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4*\pi*10^{-7}[/tex]

So

=>    [tex]n = \frac{0.373}{ 4\pi * 10^{-7} * 6.67 }[/tex]

=>    [tex]n = 44496 \ turns /m[/tex]

Generally the number of turn is mathematically represented as

       [tex]N = n * l[/tex]

=>  [tex]N = 44496 * 0.136[/tex]

=>  [tex]N = 6051 \ turns[/tex]

The no of turns dos this solenoid contains will be 6051 turns.

A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire. Which generates a magnetic field when an electric current is passed through the coil .

The given data in the problem is;

B is the current =6.67 A

L is the length =13.6 cm=0.136 m

B is the magnetic field =0.373 T  

The number of turns per unit length is found as;

[tex]\rm n= \frac{B}{\mu_0I} \\\\ \rm n= \frac{0.373}{4 \times 3.14 \times 10^{-7}\times 6.67} \\\\ \rm n = 44496 \ turn /m[/tex]

The number of turns is found as;

[tex]\rm N=n\times l \\\\ \rm N=44496\times 0.136 \\\\ \rm N=6051 \ turns[/tex]

Hence the no of turns dos this solenoid contains will be 6051 turns.

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Answer:

The CG is located higher than his original CG.

Explanation:

Centre of gravity (CG), in physics, an imaginary point in a body of matter where, for convenience in certain calculations, the total weight of the body may be thought to be concentrated. In a uniform gravitational field the centre of gravity is identical to the centre of mass, a term preferred by physicists.

 His CG is located higher than his original CG when he is standing without the sack of rice on his head.

A system is said to be in stable equilibrium if, when displaced from equilibrium, it experiences a net force or torque in a direction opposite to the direction of the displacement. A system is in unstable equilibrium if, when displaced, it experiences a net force or torque in the same direction as the displacement from equilibrium. A system is in neutral equilibrium if its equilibrium is independent of displacements from its original position. A marble on a flat horizontal surface is an example.