Car #1 has a mass of 1000 kg and moves with a velocity of 10 m/s north.
Car #2 has a mass of 500 kg and moves with a velocity of 10 m/s north.
Compare and contrast Car #1 and Car #2.
A.
Car #1 has 2-times the momentum as Car #2
В.
Car #1 has 4-times the momentum as Car #2
Car #2 has 2-times the momentum as Car #1
D.
Car #2 has 4-times the momentum as Car #1

Answers

Answer 1

Answer:

A.  Car #1 has 2-times the momentum as Car #2

Explanation:

Momentum is defined as the product of mass and velocity:

[tex]P = mv[/tex]

where,

P = Momentum

m = mass

v = velocity

FOR CAR # 1:

m = 1000 kg

v = 10 m/s

Threfore,

[tex]P_1 = (1000\ kg)(10\ m/s)\\P_1 = 10000\ N.s[/tex]

FOR CAR # 2:

m = 500 kg

v = 10 m/s

Threfore,

[tex]P_2 = (500\ kg)(10\ m/s)\\P_2 = 5000\ N.s[/tex]

Dividing both momentums:

[tex]\frac{P_1}{P_2} = \frac{10000\ N.s}{5000\ N.s}\\\\P_1 = 2P_2[/tex]

Therefore, the correct option is:

A.  Car #1 has 2-times the momentum as Car #2


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In physics, a force is any interaction that, when unopposed, will change the motion of an object.

[tex] \\ [/tex]

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A student looks at the image of a ball rolling down a ramp. The image shows four different positions for the ball Use this image to answer Questions 4–5 are attached.

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A for the first one, B for the second

The law of conservation of energy states that energy is always conserved, and cannot be destroyed.

At the top of the hill, the ball is at the maximum height. Because the equation for gravitational potential energy is ([tex]U_{g}[/tex] = mgH), we can safely conclude that the GPE at A, the top of the hill, is the greatest in all 4 options.

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The equation v=rω says that the tangential speed v is proportional to the distance r from the center of rotation. ... This makes sense because a point farther out from the center has to cover a longer arc length in the same amount of time as a point closer to the center.

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What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30 m?

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Complete the following sentence.

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Answer:

the order of liquids from bottom to top is    Mercury - Water - Oil

Explanation:

In general, when several substances are mixed we can have two cases, that the substances dissolve some enter and that the substances have not been miscible (insoluble) this is our case, the three substances do not dissolve.

Therefore they must be deposited according to the principle of Archimedes,

           B -W = 0

if the thrust (B) of the liquid is greater than the weight of the upper body, the body floats and if less, the body sinks.

           B = ρ_{liquid1}   g  V_{liquid2}

           W = m_{liquid2} g

substance densities are tabulated

ρ_{oil} = 750 to 950 kg / m3

ρ_ water = 1.00 10³ kg / m³

ρ_ Hg = 13.6 10³ kg / m #

The thrust created by the mercury is

          B_Hg = ρ_Hg g V_ Liquid2

          B_Hg = 13.6 10³  9.8 V

          B _Hg = 133.3 10³ V

The push of the water

          B_water = 1  10³ 9.8 V

          B_water = 9.8 10³ V

The oil density, let us use ρ_oil =  ​​0.75 10³ kg / m³

          B_ oil = 0.750 10³  9.8 V

          B _ oil = 7.35 10³ V

let's find the volumes of the bodies

Mercury

          ρ = m / V

     

         V_hg = m /ρ_Hg

          V_Hg = 20 10⁻³/ 13.6 10³

          V_Hg = 1.47 10⁻⁶ m³

Water

          V_water = 50 10⁻³ L

we reduce from liter to m³ 1000 l = 1 m³

           V_water = 50 10⁻⁶ m³

Oil

          V_oil = 25 10⁻³ l

           V_oil = 25 10⁻⁶ m³

Let's look for the push for every two substances

The mercury  in the bottom and upper  sustabce the water and oil  

           B_hg = 133.3 10³ (V_water + V_oil)

           B = Hg = 133.3 10³ (50 + 25) 10⁻⁶

           B = 10 N

the weight of substance on mercury is

          W = W_water + W_oil

          W = ρ_water g V_water + ρ_oil ​​g V_oil

          W = g (ρ_water V_water + ρ_oil ​​V_oil)

          W = 9.8 (1 10³ 50 10⁻⁶ + 0.75 10³ 25 10⁻⁶)

          W = 9.8 68.75 10⁻³

          W = 6.7 10⁻¹ N

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Suppose the water is below

            B₂ = ρ_water g V_oil

            B₂ = 1 10³ 9.8 25 10⁻⁶

            B₂ = 245 10⁻³ N

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            W = 0.750 10³ 9.8 25 10⁻⁶

             W = 183.75 10⁻³

            W = 1.8 10⁻¹ N

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