Answers
In the context of a scientific investigation, it is often important to provide accurate measurements. In this particular case, the mass of water used in the investigation is 0.05 kg.
How to calculate the massEnergy transferred = mass × specific heat capacity × temperature change
E = m × c × ΔT
We can rearrange this equation to solve for the mass of water:
m = E / (c × ΔT)
Substituting the given values, we get:
m = 1050 J / (4200 J/kg·°C × 0.6 °C) = 0.05 kg
Therefore, the mass of water used in the investigation is 0.05 kg.
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Related Questions
A woman weighs 100 kg and wants to know the force that the heels of her different shoes put on the new carpet by standing on one foot. The different shoes, A, B, C, D have heels of area 1cm, 4cm, 8cm and 64cm.
Which heel applies greater force to the carpet?
Answer: ALL EQUAL
^^^^^^^^^^^^^^^^^^^^^^^
^^^^^^^^^^^^^^^^^^^^^^^
Answer: ALL EQUAL
Answers
The heel of shoe D applies the greatest force to the carpet because it has the largest surface area in contact with it, and thus the largest force is distributed over that larger area.
What is the natural period of oscillation of your leg when you march? Compute your velocity? Explain your answer; make comments. (Please use formula and explain with your words clearly)
Electric Electronics Engineering course - Vibrations and Titrations
Answers
The natural period of oscillation of a leg when marching is the time it takes for one complete cycle of oscillation. It can be calculated using the formula:
T = 2π √(L/g)
What is the oscillation about?Where T is the natural period of oscillation, L is the length of the leg, and g is the acceleration due to gravity (9.81 m/s^2).
Assuming an average leg length of 1 meter, the natural period of oscillation of a leg is:
T = 2π √(1/9.81) ≈ 0.64 seconds
To compute the velocity of the leg during the march, we can use the formula:
v = 2πL/T
where v is the velocity, L is the length of the leg, and T is the natural period of oscillation.
Substituting the values, we get:
v = 2π(1)/(0.64) ≈ 9.8 m/s
Therefore, This means that during the march, the leg moves back and forth with a velocity of approximately 9.8 meters per second. It's important to note that this calculation assumes a simple harmonic motion, which may not be the case in reality due to the complex motion of various joints and muscles involved in marching.
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what is screw guage how does it work
Answers
Answer:
A screw gauge, also known as a micrometer screw gauge, is a precision measuring instrument used to measure small distances with high accuracy. It consists of a calibrated screw and a calibrated thimble with a spindle and an anvil face. The spindle is attached to the screw, and the anvil face is fixed to the body of the instrument.
To use a screw gauge, the object being measured is placed between the spindle and the anvil face, and the screw is turned until the spindle makes contact with the object. The thimble is then turned, which moves the spindle and the screw, until the spindle is firmly in contact with the object. The reading on the scale of the thimble is then taken, which gives the distance between the spindle and the anvil face, with a high degree of precision.
Screw gauges are commonly used in a variety of fields, including engineering, machining, and scientific research, where accurate measurements are required.
Screw gauge measures diameter with high accuracy using a screw and nut mechanism. It has a pitch and graduated thimble.
A screw check is an estimating instrument used to gauge the width of items, particularly wires and chambers, with high exactness. It deals with the rule of a screw and nut component.The screw measure comprises of a U-molded outline with a screw toward one side and a thimble at the other.
The screw has a pitch, which is the distance gone by the screw in one complete turn. The pitch is as a rule of the request for 0.5 mm. The thimble is graduated into 50 or 100 equivalent parts. The roundabout scale on the thimble must be changed to such an extent that the zero of the scale matches with the zero of the pitch scale.
To utilize the screw check, the item whose width is to be estimated is set between the iron block and the shaft. The screw is turned until the shaft simply contacts the item. The pitch scale perusing is noted.
The thimble is then turned until the zero of the thimble scale concurs with the middle line of the pitch scale. The thimble scale perusing is then noted. The breadth of the item is then determined by adding the pitch scale perusing and the thimble scale perusing.
Along these lines, a screw check can gauge widths to an exactness of 0.01 mm or better. It is broadly utilized in designing, fabricating, and logical applications.
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A rifle with a weight of 30 N fires a 5.0-g bullet with a speed of 300 m/s. (a) Find
the recoil speed of the rifle. (b) If a 700-N man holds the rifle firmly against his
shoulder, find the recoil speed of man and rifle.
Answers
The recoil speed of the rifle is 0.5 m/s.
Weight of the rifle, W = 30 N
Mass of the rifle, M = W/g = 30/10 = 3 kg
Mass of the bullet, m = 5 g = 5 x 10⁻³kg
Speed of the bullet, v = 300 m/s
a) The expression for the recoil speed of the rifle is given by,
v(r) = mv/M
v(r) = 5 x 10⁻³ x 300/3
v(r) = 0.5 m/s
b) Weight of the man, W' = 700 N
Mass of the man, M' = W'/g = 700/10 = 70 kg
So, the combined mass of the man and the rifle,
M₁ = M + M'
M₁ = 3 + 70
M₁ = 73 kg
Therefore, the recoil speed of man and rifle,
v(r)' = mv/M₁
v(r)' = 5 x 10⁻³ x 300/73
v(r)' = 0.0205 m/s
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What is the inertia of motion?
Answers
THE INABILITY OF A BODY TO CHANGE ITS STATE OF MOTION BY ITSELF ⚡
._Its_Ńämüđà_.The tendency of matter to resist changes in its velocity or direction of motion is known as the inertia of motion. One of the cornerstones of traditional mechanics, it is also known as the law of inertia.
What is the inertia of motion? This principle states that, without an external force, an object at rest tends to remain at rest and an object in motion tends to maintain its current speed and direction. This means that until a force acts on the moving item to cause it to modify its motion, it will continue to proceed in a straight path and at a constant speed due to inertia of motion.
An object's mass affects how much inertia of motion it possesses. An object's inertia of motion increases with bulk, making it more challenging to alter its speed or direction of motion. This feature of matter has a wide range of practical uses, including predicting how moving objects will behave and creating and building systems that need to precisely regulate motion and forces.
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1.
A megaphone amplifies sound by
all the above
increasing the range of frequencies that can be produced.
focusing sound energy into one specific direction.
spreading out the sound waves over a large area.
Answers
The correct statement explaining how a megaphone amplifies sound is: "A megaphone amplifies sound by focusing sound energy into one specific direction."
How does a loudhailer increase sound volume?By increasing the acoustic impedance perceived by the vocal chords and bringing them into closer proximity to the air, the loudhailer amplifies the sound and increases the amount of sound power that is emitted.
What kind of sound does a loudhailer produce?Many people are familiar with the distinctively distorted sound of a human voice amplified by a loudhailer thanks to its use in train and bus stations and sporting venues. It produces the sound of a vintage acoustic phonograph record player when used with music.
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A solution of ethanol is pumped to a vessel 25 m above a reference level through a 25-mm-inside-diameter steel pipe at a rate of 10 m3 /h. The length of pipe is 30 m and contains two elbows with friction equivalent to 20 diameters each. Compute the power requirements of the pump. Solution properties include density of 975 kg/m3 and viscosity of 4 3 1024 Pa s
Answers
To compute the power requirements of the pump, we need to determine the head loss and the pump's efficiency. The head loss in the pipeline is given by the Darcy-Weisbach equation:
hL = f (L / D) (V^2 / 2g)
where hL is the head loss, f is the friction factor, L is the length of the pipe, D is the inside diameter of the pipe, V is the average fluid velocity, and g is the acceleration due to gravity.
First, we need to calculate the fluid velocity:
Q = A * V
where Q is the flow rate, A is the cross-sectional area of the pipe, and V is the fluid velocity.
The cross-sectional area of the pipe is:
A = π/4 * D^2
A = π/4 * (0.025 m)^2
A = 4.91 x 10^-4 m^2
So, the fluid velocity is:
V = Q / A
V = 10 m^3/h / (3600 s/h) / (4.91 x 10^-4 m^2)
V = 5.04 m/s
Next, we need to calculate the Reynolds number to determine the friction factor:
Re = (ρVD) / μ
where ρ is the fluid density and μ is the fluid viscosity.
Re = (975 kg/m^3)(5.04 m/s)(0.025 m) / (4.3 x 10^-4 Pa s)
Re = 5.73 x 10^5
Using the Moody chart or a Colebrook equation solver, we can determine the friction factor for the given Reynolds number and roughness of the steel pipe. For simplicity, we will assume a friction factor of 0.02.
The head loss due to friction in the pipe is:
hL = f (L / D) (V^2 / 2g)
hL = 0.02 (30 m / 0.025 m) (5.04 m/s)^2 / (2 x 9.81 m/s^2)
hL = 24.4 m
The head loss due to the two elbows is:
hL = K (V^2 / 2g)
where K is the equivalent length of the elbow in diameters and is equal to 20 diameters each. From a piping handbook, K for a long radius 90° elbow is approximately 30 diameters.
hL = 30 (5.04 m/s)^2 / (2 x 9.81 m/s^2)
hL = 7.82 m
The total head loss is:
hL_total = hL_friction + hL_elbows
hL_total = 24.4 m + 7.82 m
hL_total = 32.2 m
The power required by the pump is:
P = ρQhL_total / η
where η is the pump efficiency.
We will assume a pump efficiency of 75%.
P = (975 kg/m^3)(10 m^3/h)(3600 s/h)(32.2 m)/(0.75)
P = 1.13 x 10^6 W or 1.13 MW
Therefore, the power requirements of the pump are 1.13 MW.
The pressure difference between two locations is 0.005 Torr .Which one of the following barometers is preferred to measure the small pressures accurately? (knowing that: Density of mercury = 13600 kg/m³, density water = 1000 kg/m³, density of oil = 800 kg/m³
A-Mercuric barometer
B-Oil-water barometer
C-Water barometer
D-Oil barometer
Answers
Due to its high density, the mercury barometer is the greatest option for precisely measuring minor changes in pressure. The correct option is A.
A barometer is an instrument used to measure atmospheric pressure. It typically consists of a long glass tube filled with a liquid, usually mercury, and inverted in a container of the same liquid.
The preferred barometer to measure small pressures accurately would be the mercury barometer (option A), because it has a higher density compared to the other options and hence it can detect smaller changes in pressure.
To see why the other options are not as good for measuring small pressures accurately, we can compare their densities:
Oil-water barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Water barometer: The density of water is much lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Oil barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Therefore, option A, the mercury barometer, is the best choice for measuring small changes in pressure accurately due to its high density.
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A block is dropped from rest. It takes a time t, to fall the first third of the distance. How long does it take to fall the entire distance? a) √3t₁ b) 3t₁ c) 9t₁ d) None of the above to = 0 ti t₂ TITI Vo = 0 S₂ = X S₁ = x/3
Answers
The time it will take the block to fall the entire distance is (a) √3t₁.
How to determine time in motion?Use the equations of motion to solve this problem. The equation to use is:
S = (1/2)gt²
where S = distance, g = acceleration due to gravity, and t = time.
First find the time it takes to fall the first third of the distance. The distance fallen is S₁ = x/3, so:
x/3 = (1/2)gt₁²
Solving for t₁:
t₁ = √((2x)/(3g))
Now, find the time it takes to fall the entire distance. The total distance is S₂ = x, so:
x = (1/2)gt₂²
Solving for t₂:
t₂ = √((2x)/g)
Substituting x with 3S₁:
t₂ = √((6S₁)/g)
Substituting t₁:
t₂ = √((4x)/(3g)) = √(4/3)t₁
Therefore, the answer is (a) √3t₁.
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What pressure does a 500N - pound girl produce while standing on the floor if the area of the sole of one of her shoes is 60 cm²?. pleaaasee guysss help meee
Answers
The pressure exerted by the girl is approximately 833,333.33 Pa (Pascals).
How many centimeters is half of a 87.3 km road?
Your result must be in multiples of 108 cm. That means if, for example, you get a result of a
9.2200x108 just type 9.2200 in the answer box. Include four digit after the decimal point and
maximum of 1% of error is accepted in your answer.
Answers
Half of 87.3 km is 43.65 km.
To convert km to cm, we need to multiply by 100,000 (since there are 100,000 cm in 1 km).
So, 43.65 km = 43.65 x 100,000 = 4,365,000 cm.
To express the answer in multiples of 108 cm, we need to divide by 108 and round to four decimal places.
4,365,000 cm ÷ 108 = 40,416.6667
Rounding to four decimal places gives us 40.4167.
Therefore, half of an 87.3 km road is approximately 40.4167 x 108 cm.
Ritalin and the pain medication Demerol have a high risk of dependence but may be used for medicinal purposes under a doctor's supervision. These substances are _____ of the CSA list.
Answers
Ritalin and Demerol are both controlled substances that have a high risk of abuse and dependence.
What is the list?Schedule II drugs are believed to have a high abuse potential that could lead to severe psychological or physical dependence. They do, however, occasionally have other known medical applications and can be prescribed by a licensed healthcare provider.
Ritalin is an example of a stimulant, whereas Demerol is an example of an opioid. Thus the drugs that have been mentioned here are drugs that are strictly controlled.
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Two cars are moving with velocities 70 km/hr and west direction respectively.Find their relative velocity.
Answers
Answer:
Explanation:
To find the relative velocity of two cars moving in different directions, we need to subtract their velocities. In this case, one car is moving with a velocity of 70 km/hr and the other car is moving with a velocity in the west direction.
Let's assume that the velocity of the second car is also 70 km/hr. Since the car is moving in the west direction, we can represent its velocity as -70 km/hr (negative sign indicates motion in the opposite direction).
Now, we can find the relative velocity of the second car with respect to the first car by subtracting the velocity of the first car from the velocity of the second car:
Relative velocity = Velocity of the second car - Velocity of the first car
= (-70 km/hr) - (70 km/hr)
= -140 km/hr
Therefore, the relative velocity of the second car with respect to the first car is -140 km/hr, which means that the two cars are moving away from each other at a speed of 140 km/hr.
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What is the force of gravity between two 70.0kg masses that are separated by 2.50m?
Answers
Answer:
F = 5.2324 x 10⁻⁸ N
Explanation:
F = G(m₁ · m₂) / r²
where F is the gravitational force, G is the gravitational constant (6.674 x 10⁻¹¹ N·m²/kg²), m1 and m2 are the masses of the two objects, and r is the distance between them.
Plugging in the given values m1 = m2 = 70.0 kg, r = 2.5 m:
F = (6.674 x 10⁻¹¹)(70.0 kg)² / (2.50 m)²
F = 5.2324 x 10⁻⁸ N
Therefore, the gravitational force between the two 70.0 kg masses separated by 2.50 m is approximately 5.2324 x 10⁻⁸ N.
(i) The car starts from rest. From time = 0 to time = 15 s, the car has a constant acceleration to a speed of 28 m/s. From time = 15 s to time = 32 s, the car has a constant speed of 28 m/s. From time = 32 s, the car has a constant deceleration of 2.0 m/s² until it comes to rest. On Fig. 1.1, draw the graph, using the space below for any calculations.
Answers
The total distance covered during all three phases is approximately 882.375 m.
How to solveThe car undergoes three phases: initial acceleration, constant speed, and deceleration.
In the first phase, it accelerates at 1.8667 m/s² for 15 seconds, covering 210.375 m.
In the second phase, it travels at a constant 28 m/s for 17 seconds, covering 476 m.
In the final phase, it decelerates at 2 m/s² for 14 seconds, covering 196 m.
The total distance covered during all three phases is approximately 882.375 m.
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The graph shows how the speed of a car travelling in a straight line changes with time. Which section shows the largest acceleration? speed A B C D time
Answers
The section that shows the largest acceleration on the graph would be section B, as it has the steepest slope.
This indicates that the car is increasing in speed at a faster rate during this section compared to the other sections.
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complete question not found in search engine.
You are an astronomer and are making observations about a
visible but faraway galaxy. In 2-3 sentences, describe what evidence you could gather to gain more information about (1) the galaxy's elemental
composition and (2) its motion relative to the Milky Way Galaxy.
Answers
To determine the elemental composition of the faraway galaxy, would use spectroscopy to analyze the light that is emitted or absorbed by the galaxy. This technique enables me to determine the types of atoms and molecules that are present in the galaxy, providing insights into its elemental composition.
To determine the galaxy's motion relative to the Milky Way, would use the Doppler effect to measure the galaxy's redshift or blueshift. This would enable me to determine whether the galaxy is moving away from or towards us, and at what speed, providing information about its motion relative to our galaxy.
It could also look for any gravitational lensing effects, which could indicate the presence of massive objects that are influencing the galaxy's motion.
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what is scientific learning
Answers
Answer:
the learning which is gained through observation and experimentation
Identify how each machine changes the way work is done so as to be useful.
Answers
The machine changes how work is done, by making the process easier and increasing output with less effort.
What is a machine?Any device that uses energy to carry out a task is a machine. Machines can be simple, like a lever or pulley, or complex, like a computer or a car engine. The purpose of a machine is to make work easier, faster, or more efficient than it would be without the machine. Different types of energy, including human power, electricity, and fuel, can be used to power machines.
Bicycle: A bicycle is a human-powered machine that allows people to move faster and with less effort than walking or running. A person can travel farther distances faster and with less physical effort by turning the wheels and shifting gears with their pedaling motion.
Ax blade: An ax blade is a cutting tool used for chopping wood. It facilitates the process of splitting wood by utilizing a sharp metal blade to cut through the wood fibers, rather than depending exclusively on physical power to break the wood apart.
Car jack: A car jack is a mechanical device used to lift a car off the ground. A person can raise the car to access the underside for repairs or maintenance by pulling a lever and applying hydraulic pressure. Compared to attempting to lift the car manually, this makes maintenance and repairs easier and safer.
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What force produces an extension of 2.5 cm?
Answers
F = 2.5 N
Explanation:
The force that produces an extension of 2.5 cm in a spring depends on the spring constant, which is a measure of the stiffness of the spring. The force required to extend or compress a spring by a certain amount is given by Hooke's law, which states that the force is proportional to the displacement:
F = k*x
where F is the force, x is the displacement or extension of the spring, and k is the spring constant.
If we know the spring constant, we can calculate the force required to produce an extension of 2.5 cm using the equation above.
For example, if the spring constant is 100 N/m, then the force required to produce an extension of 2.5 cm would be:
F = k*x
F = (100 N/m)*(0.025 m)
F = 2.5 N
Therefore, a force of 2.5 N would produce an extension of 2.5 cm in a spring with a spring constant of 100 N/m
Can the potential of a non uniform charged sphere be the same as that of a point charge? Explain in details
Answers
No. The potential of a non-uniform charged sphere cannot be the same as that of a point charge.
Non-uniform charged sphere as a point chargeThe potential at any point in space is determined by the distribution of charge within the system, and a non-uniform charged sphere has a different charge distribution than a point charge.
A point charge has all of its charges concentrated at a single point, while a non-uniform charged sphere has charge distributed throughout its volume.
As a result, the electric field and potential will be different for these two systems, even if they have the same total charge. Therefore, the potential of a non-uniform charged sphere cannot be the same as that of a point charge.
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What is the S-P difference (sec)?
What is the amplitude (mm)?
What is the distance (km)?
What is the magnitude (M)?
Answers
(a) The S-P difference (sec) is 40 sec.
(b) The amplitude (mm) is 10 mm
(c) The distance (km) is 380 km
(d) The magnitude (M) is 4.5
What is the S-P wave difference (sec)?The S-P wave difference (sec) is a measure used in seismology to determine the distance between a seismic station and an earthquake source.
From the graph, the S-P difference, that is between S and P = 40 s - 0 s
= 40 s
The distance (km) corresponding to 40 sec is 380 km.
The amplitude of the wave is the maximum displacement of the wave and it is equal to 10 mm.
The corresponding magnitude of the wave is 4.5.
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The mass of a density bottle is 20g when empty 70g when full of water and 695g when full of another liquid. Calculate the density of the other liquid (take density of water as 1g/cm³ (2mk) Mass of 20cm³ of the liquid ()
Answers
Answer:
The answer is 13.5g/cm³
Explanation:
m1=20g
m3=70g
m2=695g
v=20cm³
m2-m1/m3-m1
R.d=695-20/70-20
R.d=675/50
R.d=13.5
R.d=density of liquid/density of water
density of liquid =R.d×density of water
D=13.5×1
D=13.5g/cm³
What is the acceleration of a 650 kg racing camel that has a Ford net force of 897N
Answers
The acceleration of the racing camel is 1.38 m/s².
What is the acceleration of the racing camel?From Newton's second law, force is expressed as;
F = m × a
Where is mass of object and a is the acceleration
Given that:
Mass of the camel m = 650 kg Net force f = 897NAcceleration of the camel a = ?To determine the acceleration of the camel, pug the given values into the abovr formula and solve for a.
F = m × a
897N = 650 kg × a
Note that: Newton N is the same as kg·m/s²
Hence;
897kg·m/s² = 650 kg × a
Divide both sides by 650 kg
a = (897kg·m/s²) / (650 kg)
a = 1.38 m/s²
Therefore, the acceleration is 1.38 meters per second sqaure.
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What is the acceleration of a 650 kg racing camel that has a forward net force of 897N
Answers
Answer:
a = 0.724 m/s2
Explanation:
Known:
m = 650 kg
F = 897 N
a = ?
Use this formula:
F = ma
a = F/m
a = 650/897
a = 0.724 m/s2
1. solve this!!! pls help
Answers
The angle of arc m RNW is 60°, given that M is the center and RE and AN are diameters.
How to calculate arc angle?Since RE and AN are diameters, we know that ∠REO and ∠ANO are right angles, where O is the center of the circle. Since M is also the center of the circle:
m∠RMO = 180° - m∠RMN = 80°
m∠EMO = 180° - m∠EMW = 140°
Since ∠RMO and ∠EMO share a common vertex and their non-common sides are radii of the circle, they are congruent. Therefore:
m∠RMO = m∠EMO
80° = 140° - m∠RNW
m∠RNW = 60°
So m RNW = 60°.
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Image transcribed:
10.5.5 Your Turn! HOMEWORK
1. In Circle M, m∠RMN = 100° and m∠EMW = 40°. Calculate m RNW given that M is the center and RE and AN are diameters.
3.
What is sonography?
using infrasonic waves to communicate long distances
through the ground
using ultrasonic waves to communicate and hunt for prey
MacBook Air
using infrasonic waves to create images of submerged
objects
using ultrasonic waves to create images of objects found
inside other objects
Answers
The correct answer is using ultrasonic waves to create images of objects found inside other objects.
What do the terms "infrasonic" and "ultrasonic" mean?Infrasonic Wave: An infrasonic wave is a longitudinal elastic wave whose frequency is lower than that of sound, or 20Hz. For instance: It typically occurs during an earthquake. Ultrasonic Wave: An ultrasonic wave is a longitudinal wave with a frequency greater than the threshold of human hearing, or 20 kHz.
What do ultrasonic and infrasonic waves consist of?The audible range of frequencies below 20 Hz is known as infrasonic. Volcanoes, earthquakes, and thunder all emit sound in the infrasonic range. Human ears cannot hear this sound, but elephants and whales can. Ultrasonic frequencies are those that are above 20,000 Hz.
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You decide to go skiing but fall over. As you are attempting to get back up, you see a child start to head down the hill straight for you. If the coefficient of friction between the child and the snow is assumed to be 0, and the child appears to be 20 m above you when they start down the mountain, and the incline of the mountain is 31 degrees, how long do you have to get up and out of the way before you and the child collide?
Answers
The time taken to get up and out of the way before you and the child collide is 2.82 s.
What is the time taken to get up?The time taken to get up and out of the way before you and the child collide is calculated as follows;
s = v + ¹/₂at²
s = v + ¹/₂(g sin (31)t²
where;
v is the initial velocitys is the displacementt is the time of motionThe time taken to get up is calculated as;
20 = 0 + ¹/₂(9.8 sin (31)t²
20 = 2.524t²
t² = 20/2.524
t² = 7.925
t = 2.82 s
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1.5 Find the center of gravity of a 100 mm x 150 mm x 30 mm T-section. H 150 mm -100 mm- G D BI 30 mm E -30 mm Figure 1.5 1.
Answers
Answer:
Explanation:
que ricos puntitos
HELP ASAP
The specific heat capacity of solid copper metal is 0.385 J/g-K. How many joules of heat are needed to raise the temperature of a 1.55-kg block of copper from 33.0 °C to 99.9 °C?
3.71 × 10^−6J
39.9 J
3.99 × 10^4J
0.00371 J
2.69 × 10^5 J
IT IS A CHEMISTRY QUESTION BUT WAS PUT WITH PHYSICS BY MISTAKE SORRY
Answers
Answer: 3.99•10⁴ J
Explanation:
The Heat Formula is: Q = m • C • ΔT
Your given C, m, T₀, and T
C = 0.385 J/g•K
m = 1.55 kg or 1,550 g
T₀ = 33.0 °C
T = 99.9 °C
(ΔT = T - T₀)
Your only remaining variable is Q, heat, so you can now plug in your values to solve.
Q = (1550)(0.385)(99.9 - 33.0)
(ΔT(°C) = ΔT(K) because the conversion is linear)
Q = 39,922.575 J
or
3.99•10⁴ J