Calculate the pH for each of the given points in the titration of 50.0 mL of 2.1 M H3PO3(aq) with 2.1 M KOH(aq) g

Answer:

λ [Wavelength] = 3.04357825 m [meters]

Explanation:

Given a frequency, to find the wavelength, divide the speed of light by the frequency. Wavelength = Speed Of Light In Seconds / Frequency .

Wavelength in meters is: λ = 299,792,458 m/s / f Hz .

Then substitute in the frequency to find the wavelength: λ = 299,792,458 m/s / f Hz → λ = 299,792,458 m/s / 9.85 × 10^7 Hz → λ = 2.99792458 × 10^8 m/s / 9.85 × 10^7 → λ = 2.99792458 × 10^8 m / 9.85 × 10^7 → λ = 29.9792458 / 9.85 m → λ = 3.04357825 m

Answer:  

Neptune is 34 times bigger than Earth.

Earth has life, Neptune does not.

Neptune is a gas planet, Earth is not.

Neptune has rings, Earth does not.

Neptune has 13 moons, Earth has 1.

Explanation:

The planets Earth and Neptune are different from each other as Neptune is 34 times bigger than Earth.Earth has life, Neptune does not.Neptune is a gas planet, Earth is not.Neptune has rings, Earth does not.

A planet is a large, rounded astronomical body that is neither a star nor its remnant. The best available theory of planet formation is the nebular hypothesis, which posits that an interstellar cloud collapses out of a nebula to create a young protostar orbited by a protoplanetary disk.

Planets grow in this disk by the gradual accumulation of material driven by gravity, a process called accretion. The Solar System has at least eight planets: the terrestrial planets Mercury, Venus, Earth and Mars, and the giant planets Jupiter, Saturn, Uranus and Neptune.

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Here is the full question:

A chemistry graduate student was given 500 mL of a 1.60 M hydrocyanic acid (HCN) solution. Hydrocyanic acid is a weak acid with [tex]K_a = 4.9 \times 10^{-10}[/tex]. What mass of KCN should the student dissolve in the HCN solution to turn it into a buffer with pH  = 9.16?

Answer:

36.85 g

Explanation:

From the given information above:

Recall that  number of moles of HCN = mass of HCN / molar mass of HCN= mass of HCN / molar mass of HCN

Therefore;

the number of moles of HCN =  [tex]\dfrac{500 \times 1.60}{1000}[/tex]

the number of moles of HCN = [tex]\dfrac{800}{1000}[/tex]

the number of moles of HCN =  0.8

The acid dissociation constant [tex]K_a[/tex] = [tex]4.9 \times 10^{-10}[/tex]

Thus the pKa = [tex]- log (4.9 \times 10^{-10})[/tex]

pKa = 9.31

However, the pH is given as:

[tex]pH = pKa + log \bigg ( \dfrac{KCN}{HCN} \bigg )[/tex]

[tex]9,16 =9.31 + log \bigg ( \dfrac{KCN}{0.8} \bigg )[/tex]

[tex]9,16 -9.31 =log \bigg ( \dfrac{KCN}{0.8} \bigg )[/tex]

[tex]-0.15 =log \bigg ( \dfrac{KCN}{0.8} \bigg )[/tex]

KCN = 0.566 mol

The standard molar mass of KCN = 65.11 g/mol

Thus, the mass of KCN = number of moles of KCN × molar mass of KCN

the mass of KCN = 0.566 × 65.11

the mass of KCN that the student needs to dissolve in HCN is =  36.85 g

Answer:

rip you

Explanation:

Answer:

I got e but you might want to wait for someone else to answer it just incase...

Answer:

Magma cooling = metamorphic rock formation

Explanation:

Did you mean formation not folio?

Answer:

Molecules are moving the fastest and are the farthest apart in the gaseous phase.

Explanation:

Answer:

See explanation

Explanation:

a) Look at the electronic configuration of both species;

Cu^2+- [Ar]  3d9 4s0

Co^2+- [Ar]  3d7 4s0

We  can now see that a Jahn Teller effect occurs in [CuCl4]2– due to its d9 configuration. This  Jahn-Teller distortion causes the symmetry of  [CuCl4]2–  to change from tetrahedral  T

d  to trigonal pyramidal  C3v.

b) This is a consequence of Jahn-Teller effect in [CoF6]3– which makes the Co-F bonds lie along the z-axis and become elongated in comparison  to the remaining four Co-F bonds

Answer:

Find the molar mass of all the elements in the compound in grams per mole.

Find the molecular mass of the entire compound.

Divide the component's molar mass by the entire molecular mass.

You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.

Explanation:

Mass spectrometry is used to measure the mass of atoms and to determine the percent composition of compounds.

There have been qualitative and numerical implications for mass spectroscopy. These include distinguishing unrecognized compounds, determining out a molecule's elemental isotopic makeup, and figuring out a compound's structure by analyzing at how it fragmented.

In order to determine the mass-to-charge ratio (m/z) of one or more molecules present in a sample, mass spectrometry is a proven to be a valuable instrument. The precise molecular weight of the sample's individual components may typically be estimated using these measures and also.

Thus, mass spectrometry is used to measure the mass of atoms and to determine the percent composition of compounds.

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Answer:

14.9%m/m

Explanation:

The percent m/m concentration of a solution (%m/m) indicates the grams of solute there are in 100 g of solution. It can be calculated as follows:

[tex]%m/m= \frac{mass of solute (g)}{mass of solution(g)} x 100[/tex]%m/m= mass of solute(g)/mass of solution(g) x 100

As the solution is composed by solute + solvent, the mathematical expression can be transformed in:

[tex]%m/m= \frac{mass of solute (g)}{mass of solution(g)} x 100[/tex]%m/m= mass of solute(g)/(mass of solute + mass of solvent (g) )x 100

         = 24.34 g[tex]%m/m= \frac{mass of solute (g)}{mass of solution(g)} x 100[/tex]/(24.34 g + 138.87 g) x 100

         = 24.34 g/(163.21 g) x 100

         = 14.9%

[tex]%m/m= \frac{mass of solute (g)}{mass of solution} x 100 = \frac{mass of solute (g)}{mass of solute (g) + mass of solvent (g)}[/tex]

Answer:

its polar

Explanation:

Answer:

267.498 J is required to expand the volume of a pump from 0.0 L to 2.2 L against an external pressure of 1.2 atm

Explanation:

The volume change work of a gas is the work necessary for the gas to go from an initial volume Vi to a final volume Vf. If the volume decreases, the gas will have been compressed and it is a compression work; whereas if the volume increases, the gas will have expanded and it is expansion work.

The work is calculated by:

W= - P*ΔV= -P*(Vfinal - Vinitial)

In this case:

Replacing:

W= -121590 [tex]\frac{N}{m^{2} }[/tex]*0.0022 m³= - 267.498 N*m= -267.498 J

267.498 J is required to expand the volume of a pump from 0.0 L to 2.2 L against an external pressure of 1.2 atm

The work require to expand the volume of the given pump is 267.5 J.

The given parameters;

The work require to expand the volume of the given pump is calculated as follows;

W = PΔV

W = 1.2 atm (2.2 L - 0 L)

W = 2.64 atm.L

[tex]W = 2.64 \ atm.L \times \frac{101325 \ Pa}{1 \ atm} \times \frac{0.001 \ m^3}{1 \ L} \\\\W = 267.5 \ J[/tex]

Thus, the work require to expand the volume of the given pump is 267.5 J.

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Answer:

Paper, some plastics, frosted glass, etc.

Explanation:

Answer:

Positive charged

Explanation:

Explanation:

Then there is no net charge separation. a BH3 b CHCl3 c C2H2 d NH3. Optionally the ... Oxygen O2 c. ... BH3 2. Com Bh3 Polar Or Nonpolar In the case of non polar molecules dispersion forces or London forces are present between them.

The polar molecules is NO.

A polar molecule is one that has one end that is slightly positive and the other end that is slightly negative. Ionic or polar covalent bonds can form in polar molecule. A dipole is a molecule that has two poles. The dipole moment is the outcome of measuring the amount of polarity in a molecule.

NO molecule, In the periodic table, nitrogen is to the right of oxygen. Nitrogen has a lower electronegative potential than oxygen. All N-O bonds are polar, with the oxygen atom having a higher electron density. The uneven distribution of electrons in the NO molecule is quite minor. When a molecule is non-polar, the electrons are shared evenly, resulting in a non-polar bond, or the polar bonds are symmetric. So, oxygen, nitrogen and boron trihydride molecules are non-polar molecule.

Hence the correct option is D.

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Answer:

-183.15 °C

Explanation:

Given data:

Mass of F₂ = 5.00 g

Pressure = 119.96 KPa (119.96/101 = 1.2 atm)

Volume = 750.0 mL ( 750.0/1000 = 0.75L)

Temperature = ?

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/molar mass

Number of moles = 5.00 g/ 38g/mol

Number of moles = 0.13 mol

Now we will calculate the temperature:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1.2 atm × 0.75 L = 0.13 mol ×0.0821 atm.L/ mol.K  × T

0.9 atm.L = 0.01 atm.L/ K  × T

T = 0.9 atm.L /0.01 atm.L/ K

T = 90 K

Kelvin to degree celsius:

90K -273.15 = -183.15 °C

Answer:

[tex]M=1.02M[/tex]

Explanation:

Hello.

In this case, since the molarity of a solution is computed as the moles of solute over volume of solution:

[tex]M=\frac{n_{solute}}{V}[/tex]

Since the volume of the solution is 257 mL or also 0.257 L, we compute the moles of solute, which is magnesium nitrate (molar mass = 148.3 g/mol), as shown below:

[tex]n_{solute}=39.0gMg(NO_3)_2*\frac{1molMg(NO_3)_2}{148.3 gMg(NO_3)_2}=0.263molMg(NO_3)_2[/tex]

Thus, the required molarity turns out:

[tex]M=\frac{0.263molMg(NO_3)_2 }{0.257L}\\ \\M=1.02M[/tex]

Best regards.

Answer:

Chromium (III) bromide.

Explanation:

Hello.

In this case, for the reaction:

[tex]3F_2+2CrBr_3\rightarrow 3Br_2+2CrF_3[/tex]

Since there is a 3:2 mole ratio between fluorine (molar mass = 38.0 g/mol) and chromium (III) bromide (molar mass = 291.7 g/mol) we can compute the available moles of fluorine and the moles of fluorine consumed by 22.22 g chromium (III) bromide in order to realize whether it is the limiting reactant or not:

[tex]n_{F_2}^{available}=22.22gF_2*\frac{1molF_2}{38.0gF_2}=0.585molF_2\\ \\n_{F_2}^{consumed}=22.22gCrBr_3*\frac{1molCrBr_3}{291.7gCrBr_3}*\frac{3molF_2}{2molCrBr_3} =0.114molF_2[/tex]

In such a way, since just 0.114 off 0.585 moles of fluorine are consumed, we conclude it is in excess and the chromium (III) bromide is the limiting reactant, it means it gets completely used up.

Best regards!

Answer: The freezing point of the solution will be [tex]4.3^0C[/tex]

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=T_f^0-T_f=(5.5-T_f)^0C[/tex] = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

[tex]K_f[/tex] = freezing point constant = [tex]4.90^0C/m[/tex]

m= molality

[tex]\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}[/tex]

Weight of solvent (benzene)= 800 g = 0.8 kg

Molar mass of solute ( methyl salicylate) = 152.1 g/mol

Mass of solute ( methyl salicylate) = 30 g

[tex](5.5-T_f)^0=1\times 4.90^0C/m\times \frac{30g}{152.1 g/mol\times 0.8kg}[/tex]

[tex](5.5-T_f)0C=1.2[/tex]

[tex]T_f=4.3^0[/tex]

The freezing point of the solution will be [tex]4.3^0C[/tex]

Answer:

74.1 amu

Explanation:

Given that,

The molecular mass of propanoic acid is 74.1 amu.

One of the isomer of propanoic acid is methyl ethanoate.

We know that, isomers are have same molecular formula. They also have same mass.

In this case, it is very clear that the molecular mass of methyl ethanoate is as same as molecular mass of propanoic acid i.e. 74.1 amu

Answer:

a

Explanation:

Total pressure in the flask : 468 mmHg

Dalton's law of partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases  

Can be formulated:  

P tot = P1 + P2 + P3 ....  

The partial pressure is the pressure of each gas in a mixture  

For partial gas :

Pgas₁=x₁.P tot

x₁ = mole fraction of gas 1

mol of each gas :

H₂ = 14 g : 2 g/mol= 7 moles

N₂ = 84 g : 28 g/mol = 3 moles

O₂ = 2 moles

Total moles = 7+3+2= 12 moles

Partial pressure of O₂ :

[tex]\tt P_{O_2}=x_{0_2}\times P_{tot}\\\\78~mmHg=\dfrac{2}{12}\times P_{tot}\\\\P_{tot}=\dfrac{78\times 12}{2}=468~mmHg[/tex]

The study of chemicals is called chemistry.

The correct answer is 468mmhg.

Dalton's law defined as partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases  

The formula is stated as follows:-

[tex]P_{total} = P_1 + P_2 + P_3...[/tex]

The partial pressure is the pressure of each gas in a mixture. For partial gas is as follows :

[tex]P_{gas}_1=X_1.P_{total}[/tex]

The [tex]X_1[/tex] defined as a mole fraction of gas 1

The mole of each gas is as follows:-

[tex]H_2 = \frac{14}{2}= 7 molesN_2 = \frac{84}{28} = 3 molesO-_2 = 2 moles[/tex]

Total moles = [tex]7+3+2= 12 moles[/tex]

The partial pressure  [tex]O_2[/tex] is as follows:-

[tex]P_{total} = \frac{78*12}{2} =468mm[/tex].

Hence, the correct answer is 468mmhg.

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Answer:

B) Group 1 and 17

Explanation:

alkali metals and the halogens are the most reactive because of valence electrons

Answer:

1.98 M

Explanation:

Step 1: Write the balanced reaction

2 NH₃ + 3 BrO⁻⟶ N₂ + 3 Br⁻ + 3 H₂O

Step 2: Calculate the moles corresponding to 0.325 g of ammonia

The molar mass of NH₃ is 17.03 g/mol.

0.325 g × (1 mol/17.03 g) = 0.0191 mol

Step 3: Calculate the reacting moles of hypobromite

The molar ratio of NH₃ to BrO⁻ is 2:3. The reacting moles of hypobromite are 3/2 × 0.0191 mol = 0.0287 mol

Step 3: Calculate the molar concentration of the hypobromite solution

M = 0.0287 mol / 0.0145 L = 1.98 M

The concentration of the hypobromite solution (BrO⁻) needed for the reaction is 1.97 M

We'll begin by calculating the number of mole in 0.325 g of NH₃. This can be obtained as follow:

Mass of NH₃ = 0.325 g

Molar mass of NH₃ = 17.031 g/mol

Mole = mass / molar mass

Mole of NH₃ = 0.325 / 17.031

Next, we shall determine the number of mole of BrO⁻ needed to react with 0.01908 mole of NH₃. This can be obtained as follow:

2NH₃ + 3BrO⁻ —> N₂ + 3Br⁻ + 3H₂O

From the balanced equation above,

2 moles of NH₃ reacted with 3 moles of BrO⁻.

Therefore,

0.01908 mole of NH₃ will react with = [tex]\frac{0.01908 * 3 }{2}\\\\[/tex] = 0.02862 mole of BrO⁻.

Finally, we shall determine the concentration of the BrO⁻ solution.

Mole of BrO⁻ = 0.02862 mole

Volume of BrO⁻ solution = 14.5 mL = 14.5 / 1000 = 0.0145 L

Concentration = mole / Volume

Concentration of BrO⁻ = 0.02862 / 0.0145

Therefore, the concentration of the hypobromite solution (BrO⁻) is 1.97 M

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Answer:

1011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010, You're welcome

Explanation:

Answer:

0.44 M

Explanation:

Answer:

Both empirical and molecular formulas are NH₃.

Explanation:

Hello.

In this case, since we know the percent compositions of both nitrogen and hydrogen, in order find out the molecular formula and the empirical formula of that compound, we can first assume we have 82.27 g of nitrogen and 17.76 g of hydrogen as a first approximation to compute the present moles:

[tex]n_N=82.27g/(14.01g/mol)=5.872mol\\\\n_H=17.76g/(1.01g/mol)=17.58mol[/tex]

Next, we compute the subscripts in the empirical formula first, by diving the moles of each element by the moles of the element with fewest moles:

[tex]N:\frac{5.872}{5.872}=1\\\\H:\frac{17.58}{5.872}=3[/tex]

It means that the empirical formula is NH₃ and its molar mass is about 17.04 g/mol which is about the same the reported molar mass slightly more than 17 g, it means that the molecular formula is also NH₃.

Best regards!

Answer:

It was deflected by a magnet charged particles

Answer:

False

Explanation: