C. The driver is looking at her phone and has a total reaction time of 4.6 seconds as the car is moving at a constant speed of 11 m/s. If the driver slams on her brakes and slows down at a rate of -8.2 m/s2, what is the stopping distance for the car in this situation

Answers

Answer 1

Answer:

The stopping distance for the car when the driver slams on her brakes is 7.38 m.

Explanation:

The distance traveled for the car after stopping can be found using the following equation:

[tex] v_{f}^{2} = v_{0}^{2} + 2ad [/tex]

Where:

vf is the final speed = 0 (it stops)

v₀ is the initial speed = 11 m/s

a is the acceleration = -8.2 m/s²

d is the distance =?

When the driver slams on her brakes the distance traveled is:

[tex]d = -\frac{v_{0}^{2}}{2a} = -\frac{(11 m/s)^{2}}{2*(-8.2 m/s^{2})} = 7.38 m[/tex]

 

Therefore, the stopping distance for the car when the driver slams on her brakes is 7.38 m.

I hope it helps you!                                        


Related Questions

A 1.5 kg block is pulled across a horizontal surface that has a coefficient of kinetic friction of 0.60. a. What is the force of friction exerted by the surface on the block?

Answers

Answer: 8.82 N

Fg= (1.5) (9.8) = 14.7

Fk= (0.60) (14.7) = 8.82

A train slows down as it rounds a sharp horizontal turn, going from 100 km/h to 60.0 km/h in the 14.0 s it takes to round the bend. The radius of the circle is 160 m. Compute the total acceleration and the angle at the moment the train speed reaches 60.0 km/h.

Answers

Answer:

The magnitude of the total acceleration of the train is approximately 1.909 meters per square second.

The direction of total acceleration with respect to radial acceleration is approximately -24.578º.

Please note that negative sign indicates that train is decelerating.

Explanation:

From Physics, we know that magnitude of the acceleration experimented by the train ([tex]a[/tex]), measured in meters per square second, while rounding the bend is the Pythagorean identity involving radial and tangential accelerations ([tex]a_{r}[/tex], [tex]a_{t}[/tex]), measured in meters per square second:

[tex]a = \sqrt{a_{t}^{2}+a_{r}^{2}}[/tex] (Eq. 1)

If we assuming that train decelerates at constant rate, then each component is determined by following expressions:

[tex]a_{t} = \frac{v_{f}-v_{o}}{t}[/tex] (Eq. 2)

[tex]a_{r} = \frac{v_{f}^{2}}{R}[/tex] (Eq. 3)

Where:

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds, measured in meters per second.

[tex]t[/tex] - Deceleration time, measured in seconds.

[tex]R[/tex] - Bend radius, measured in meters.

If we know that [tex]v_{o} = 27.778\,\frac{m}{s}[/tex], [tex]v_{f} = 16.667\,\frac{m}{s}[/tex], [tex]t = 14\,s[/tex] and [tex]R = 160\,m[/tex], then each acceleration component is calculated:

[tex]a_{t} = \frac{16.667\,\frac{m}{s}-27.778\,\frac{m}{s} }{14\,s}[/tex]

[tex]a_{t} = -0.794\,\frac{m}{s^{2}}[/tex]

[tex]a_{r} = \frac{\left(16.667\,\frac{m}{s} \right)^{2}}{160\,m}[/tex]

[tex]a_{r} = 1.736\,\frac{m}{s^{2}}[/tex]

Then, the magnitude of the total acceleration of the train is:

[tex]a = \sqrt{\left(-0.794\,\frac{m}{s^{2}} \right)^{2}+\left(1.736\,\frac{m}{s^{2}} \right)^{2}}[/tex]

[tex]a \approx 1.909\,\frac{m}{s^{2}}[/tex]

The magnitude of the total acceleration of the train is approximately 1.909 meters per square second.

After that, we obtain the angle of acceleration by using the following trigonometric expression:

[tex]\theta = \tan^{-1} \frac{a_{t}}{a_{n}}[/tex] (Eq. 4)

Where [tex]\theta[/tex] is the direction of total acceleration with respect to radial acceleration, measured in sexagesimal degrees.

If we get that [tex]a_{t} = -0.794\,\frac{m}{s^{2}}[/tex] and [tex]a_{r} = 1.736\,\frac{m}{s^{2}}[/tex], the direction of total acceleration experimented by the train is:

[tex]\theta = \tan^{-1}\left(\frac{-0.794\,\frac{m}{s^{2}} }{1.736\,\frac{m}{s^{2}} } \right)[/tex]

[tex]\theta \approx -24.578^{\circ}[/tex]

Please note that negative sign indicates that train is decelerating.

The direction of total acceleration with respect to radial acceleration is approximately -24.578º.

a rocket is fired upwards with an intial velocity of 46.5 m/s. find the rocket's maximum height

Answers

Answer:

The value is [tex]s = 110.32 \ m[/tex]

Explanation:

From the question we are told that

   The initial velocity is  u=  46.5 m/s

Generally from kinematic equations we have that

     [tex]v^2 = u^2 + 2as[/tex]

Here  [tex]a = -g = -9.8 \ m/s^2[/tex]

   The negative sign is because it is moving against gravity

At maximum height v =  0 m/s        

So

     [tex]0 = (46.5)^2 + 2* (-9.8)s[/tex]

=>   [tex]s = 110.32 \ m[/tex]

What is a quantity Described completely by its magnitude

Answers

Answer:

Scalar

Explanation:

A physical quantity that is completely described by its magnitude; examples of scalars are volume, density, speed, energy, mass, and time. Other quantities, such as force and velocity, have both magnitude and direction and are called vectors.

3. A satellite orbits Earth at a constant speed.
What part of the satellite's motion is
changing?
A speed
B friction
C inertia
D acceleration

Answers

I believe the answer is D.

Select the correct answer. In which situation is maximum work considered to be done by a force? A. The angle between the force and displacement is 180°. B. The angle between the force and displacement is 90°. C. The angle between the force and displacement is 60°. D. The angle between the force and displacement is 45°. E. The angle between the force and displacement is 0°.

Answers

Answer:

A.  The angle between the force and displacement is 180°.

Answer:

a

Explanation:

A car starts from a spotlight and is traveling with a velocity of 10 m/s Ein
20 seconds. What is the acceleration of the car?

Answers

Answer:

ANSWER

Initial Velocity (u) = 10 m/sec

Acceleration (a) = 5 m/sec

2

Distance (s) = 30 m

Final velocity (v) = ??

Using Newton's Third law of Motion,

v

2

=u

2

+2as

v

2

=10

2

+2×5×30

v

2

=100+300

v

2

=400

v =

400

v = 20 m/sec

_____________________________

ANSWER =

FINAL VELOCITY = 20 m/sec

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More Questions by difficulty

EASY

MEDIUM

HARD

Explanation:

it's easy

A car starts at a position of 4km and moves a final position of 5 km. What is the total distance traveled by the car?
A. 1 km
B.-9 k m
C. 9 km
D. -1 km

Answers

Answer:

its c. 9km

Explanation:

Because it you add the 4km+5km that gives you a total of 9km

A man is walking toward the back of an airplane at 7 m/s. The plane is flying West at 245 m/s. What is the speed and direction of the plane relative to the man?

Answers

Answer:

The speed of the plane relative to the man is 245.1 m/s

The direction of the plane is S 88.36⁰ W

Explanation:

Given;

velocity of the man toward the airplane, Vy = 7 m/s

velocity of the airplane, Vx = 245 m/s west

The speed of the plane relative to man is given by;

<----------------------

                          ↑

                          ↑

                          ↑

Complete this diagram to form a right angled triangle, with the hypotenuse as the relative velocity of the plan with respect to the man.

R² = 245² + 7²

R² = 60074

R = √60074

R = 245.1 m/s

The direction of the plane is given by;

tan θ = 245 / 7

tan θ = 35

θ = tan ⁻¹ (35)

θ = 88.36°

The direction of the plane is S 88.36⁰ W

                   

What is the velocity of a car that travels 400meters in 16 seconds

Answers

Answer:

The answer is 25 m/s

Explanation:

The velocity of the car can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex]v = \frac{400}{16} \\ [/tex]

We have the final answer as

25 m/s

Hope this helps you

A person ran with a speed of 6 m/s onto the skateboard .What is the speed with which he ride on the skate board

Answers

Answer:

First, remember the conservation of energy.

We can define the kinetic energy as:

K = (1/2)*m*v^2

where m is the mass, and v is the velocity.

The velocity of the person is 6m/s, and the mass is unknown.

Now, when the person rides the skateboard, this kinetic energy must remain constant, if M is the mass of the skateboard, the speed after the person rides ir will be:

K' = (1/2)*(m + M)*v'^2

Where v' is the new velocity.

In this case, we can suppose that the skateboard has really small mass compared with the person.

M < < m

then:

(m + M) ≈ m

then:

K' = (1/2)*m*v'^2 = K = (1/2)*m*v^2

from that equation, we can conclude that:

v' = v

Then if the velocity before riding the skateboard was 6m/s, then after would be also 6m/s.

Manu takes 30 minutes from his house to reach his school on a bicycle. If the cycle has a speed of 4m/s find the difference between his house and the school.

Answers

Answer:

7200 m

Explanation:

From the question given above, the following data were obtained:

Time (t) = 30 mins

Speed (S) = 4 m/s

Distance (d) =.?

Next, we shall convert 30 mins to seconds. This can be obtained as follow:

1 mins = 60 s

Therefore,

30 mins = 30 mins × 60 s / 1 mins

30 mins = 1800 s

Thus, 30 mins is equivalent to 1800 s.

Finally, we shall determine the difference between Manu's house and his school by calculating the distance. This is illustrated below:

Time (t) = 1800 s

Speed (S) = 4 m/s

Distance (d) =.?

Speed = Distance /time

4 = Distance /1800

Cross multiply

Distance = 4 × 1800

Distance = 7200 m

Therefore, the difference between Manu's house and his school is 7200 m

Help plz
Which of the following graphs best represents the expected experimental data between the force of gravitational attraction between two varying masses positioned 1 m apart

Answers

Answer:

I'm pretty sure it's D

Explanation:

because the greater the mass, the greater the gravitational pull is on it. but you probably shouldn't take my word on it, lol

what is a convalent bond
I JUST NEED A ANSWER DONT CARE WHAT IT IS

Answers

Answer: A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. 

Hope that helps! :)

Covalent bond, in chemistry, the interatomic linkage that results from the sharing of an electron pair between two atoms. The binding arises from the electrostatic a

In a transformer, the incoming primary voltage is 120 V. There are 100 windings in the primary coil. The secondary coil has 65 windings. What is the outgoing voltage of this transformer?
a
151.9 V
b
64.41 V
c
102.8 V
d
78.02 V

Answers

Answer:

78.02 V

Explanation:

Given that,

Primary voltage in a transformer is 120 V

No of windings in the primary coil is 100

No of windings in the secondary coil is 65

We need to find the outgoing voltage of the transformer. For a transformer, the ratio of primary voltage to the secondary voltage is equal to the ratio of turns in Primary coil to the turns in secondary coil are equal. So,

[tex]\dfrac{V_p}{V_s}=\dfrac{N_p}{N_s}\\\\\dfrac{120}{V_s}=\dfrac{100}{65}\\\\V_s=\dfrac{120\times 65}{100}\\\\V_s=78\ V[/tex]

So, out of the given options, the correct one is option (d) i.e. 78.02 V

9. Which of Newton's laws explains why a rocket can be sent into space by aiming a force downward?​

Answers

Answer:

Newton's third law

Explanation:

the fuel is the action force

and the rocket going up is the reaction force


A bowling ball is dropped from rest. What is the ball's velocity after falling for 5 seconds?
Equation: Vy =g*t

Answers

Answer:

545432344455555322 we 45year 7of and

If a cheetah can maintain a constant speed of 5.00 m/s, how far does it travel in 1.00 minute?

Answers

Answer: 300 m/m

Explanation: 5.00 m/s • 60 =300/m/m

PLEASE ANSWER
For an object launched horizontally the acceleration in the y direction will always be ____.​

Answers

Answer: initial velocity in y direction

Explanation: coz i did dis before XD

How do scientists determine the number of neutrons in an isotope of an atom?


They subtract the atomic number from the atomic mass.


They find the number of protons.


They divide the atomic mass by two.


They add the number of electrons and protons.

Answers

Answer:

They subtract the atomic number from the atomic mass

Hope this helps

Please mark as the brainliest

What is the net force on the runner below if the
applied force is + 40 N and the resistive force is -2
N?

Answers

Answer:

What is the net force on the runner below if the

applied force is + 40 N and the resistive force is -2

N?

Explanation:

What is the net force on the runner below if the

applied force is + 40 N and the resistive force is -2

N?

Describe how resistance affects the flow of current in a circuit

Answers

Resistance decreases the flow of current in a circuit.

Where does transpiration occur

Answers

Answer:

it's when the water in water in plants is evaporated and turned into water vapor

Explanation:

hope it helps

A type of elevator called a cage is used to raise and lower miners in a mine
shaft. Suppose the cage carries a group of miners down the shaft. If the
unbalanced force on the cage is 60.0 N, and the mass of the loaded cage is
1.50 x 10²kg, what is the acceleration of the cage?

Answers

Answer:

Acceleration, a = 0.04 m/s²

Explanation:

Given the following data;

Force = 60N

Mass = 1500kg

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

[tex] F = ma[/tex]

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

[tex]Acceleration (a) = \frac{F}{m}[/tex]

Substituting into the equation;

[tex]Acceleration (a) = \frac{60}{1500}[/tex]

Acceleration, a = 0.04 m/s²

Acceleration due to gravity (ag) = 9.8 m/s2. An object is dropped from a bridge. How
fast will the object be falling in 6.3 seconds?

Answers

Answer:

V = 61.74m/s

Explanation:

Given the following data;

Acceleration due to gravity = 9.8m/s²

Time, t = 6.3 secs

Since it's a free fall, initial velocity = 0

Thus, to find the final velocity, we would use the first equation of motion;

[tex] V = U + at[/tex]

Substituting into the equation, we have;

[tex] V = 0 + 9.8 * 6.3[/tex]

V = 61.74m/s

Therefore, the final velocity is 61.74m/s

When two strands of DNA line up, adenine always pairs up with _____.


guanine

phosphate

thymine

cytosine

Answers

thymine (i’m pretty sure)

HELP!!!! ILL GIVE BRAINLIEST!!HURRY !!!!



what is 5.6 x 10^15 converted to x10^12

Answers

Answer:

5,600

Explanation:

You split x10^15 into x10^12 and x10^3. Our new equation is 5.6x10^3x10^12

We do 5.6x10^3 and we get 5,600. Our new equation is 5,600x10^12. I hope this answered your question.

5,600 i did it in my calculator hope this helps

(Physical science!!!)
Wetlands have characteristics of both dry land and of bodies of water. How have amphibians adapted to this environment?

A.
They can lay their eggs underwater or on dry land.
B.
Water can pass through their lungs; they have night vision.
C.
Water can pass through the skin; they have lungs.
D.
They retain a set of gills their whole lives.

Answers

Amphibians retain a set of gills their whole lives that help them to breathe in the water. So, the correct option is D.

What are Amphibians?

Amphibians are defined as the class of cold-blooded vertebrates which is made up of frogs, toads, salamanders, newts, and caecilians. All amphibians that spend part of their lives in water and part of their lives on land.

Amphibians are born with gills, and some outgrow them when they become adults while others retain them for their entire lives.

Thus, the correct option is D.

Learn more about Amphibians, here:

https://brainly.com/question/14213726

#SPJ1

A force is applied to a 2.1 kg mass and produces 3 m/s- acceleration.
What acceleration would be produced by the same force applied to a 12.1 kg mass?
Answer in units of m/s2.

Answers

Answer:

f=m×a

f=2.1×3

f=6.3

f=ma

6.3=12.1a

a=0.52m/s²

you weigh 500n,what stops you from falling to the center of the earth

Answers

Answer:

bedrock?

Explanation:

The ground is in the way.

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