Brainliest!
Which system is represented in the graph?
y>x²-2x-3
y > x + 3
Oy y Oy2x²-2x-3
y ≤ x + 3
Oy>x²-2x-3
y

Answer:

24 ft.

Step-by-step explanation:

Radius = 4 ft

Central angle = 6°

Arc length = radius × central angle

= 4 × 6°

= 24 ft.

Answer:

1936

Step-by-step explanation:

We can start by removing the center tile, because all four diagonals over lap on that tile. We'll add it back later. 88/4=22. which means there are 22 tiles per half, 44+1(the center tile) total tiles per side, which means there are a total of 1936 tiles.

AOPS ANSWER:

Suppose that we have a square with dimensions [tex]$e \times e$[/tex]. The diagonals each have [tex]$e$\\[/tex] tiles. If [tex]$e$\\[/tex] is even, the number of yellow tiles is [tex]$2e$[/tex], because the [tex]2[/tex] diagonals don't intersect. If [tex]$e$[/tex] is odd, then the number of yellow tiles is [tex]$e+e-1=2e-1$[/tex]. (We have to subtract [tex]1[/tex] because the center tile is counted [tex]2[/tex] times). We know that there are [tex]89[/tex] yellow tiles, which is an odd number, so [tex]$89=2e-1$[/tex]. This implies that [tex]$e = 45$[/tex]. So the dimensions of the floor are [tex]$45 \times 45$[/tex], or [tex]2025\\[/tex] square units. Since all of the other tiles are gray, there are [tex]$2025-89=\boxed{1936}$[/tex] gray tiles.

Please, make sure you understand the solution:

We can notice that x + (x - 28) = 90

2x - 28 = 90
2x = 118
x = 59

Now for y:

We can notice that y + 90 + x = 180

y + 90 + 59 = 180
y + 149 = 180
y = 180 - 149

y = 31

Answer:

83.80 = 69 + 4x
x = 3.7
Sarah can use up to 3.7 gigabytes per month to stay within her budget

Step-by-step explanation:

83.80 = 69 + 4x
14.8 = 4x
x = 3.7

The number of gigabytes of data Sarah can use while staying within her budget is 3.7 gigabyte.

Given that, Sarah pays a flat cost of $69 per month and $4 per gigabyte.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the number of gigabyte be g.

69+4g=83.80

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

Now, 4g=83.80-69

⇒ 4g=14.8

⇒ g=14.8/4

⇒ g=3.7 gigabyte

Therefore, the number of gigabytes of data Sarah can use while staying within her budget is 3.7 gigabyte.

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Answer:

The angles are 72° and 108°

Step-by-step explanation:

Supplementary angles add up to 180°

Ratio of supplementary angles = 2 : 3

The angles are 2x , 3x

2x + 3x = 180

        5x = 180

          x = 180 ÷ 5

         x = 36°

2x = 2*36 = 72°

3x = 3*36 = 108°

Hey there!

2(2y - 12) = 0
2(2y) + 2(-12) = 0

4y - 24 = 0

ADD 24 to BOTH SIDES

4y - 24 + 24 = 0 + 24

SIMPLIFY IT!

4y = 0 + 24

4y = 24

4y/4 = 24/4

SIMPLIFY IT!

y = 24/4

y = 6

Therefore, your answer should be:

y = 06 (Option B.)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

y=6 (06) should be your answer

Step-by-step explanation:

4y-24=0

After you simply the first equation in the parenthesis, you then move the 24 to the 0,

4y=24

The answer becomes positive 24 because when you move things across the equal sign you switch the sign

y=6

Then divide 24 by 4 to isolate y, which then gives you the answer 6.

Answer:

[tex]x=(-2,\frac{5}{3} )[/tex]

Step-by-step explanation:

1)  We will use the matrix method to solve this problem.

[tex]\left[\begin{array}{ccc}-2/3&1&3\\1&0&-2\\\end{array}\right][/tex]

2) Swap Row₁ and Row₂ to make row reduction easier.

[tex]\left[\begin{array}{ccc}1&0&-2\\-2/3&1&3\\\end{array}\right][/tex]

3) Apply to Row₂ :  Row₂ + [tex]\frac{2}{3}[/tex] Row₁.

[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\end{array}\right][/tex]

4)  Simplify rows.

[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\\\end{array}\right][/tex]

Note: The matrix is now in row echelon form.

The steps below are for back substitution.

5) Apply Row₁ : Row₁ - 0 Row₂.

[tex]\left[\begin{array}{ccc}1&0&-2\0\\0&1&5/3\end{array}\right][/tex]

6) Simplify rows.

[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\\\end{array}\right][/tex]

Note: The matrix is now in reduced row echelon form.

7) Therefore,

[tex]x=-2\\x=\frac{5}{3}[/tex]

Answer:

C

Step-by-step explanation:

The horizontal line, y=2, is solid and shaded above, so it represents

[tex]y \geqslant 2[/tex]

The slanted line, y=x is dashed and shaded below, so it represents y<x.

Answer:

184.73

Step-by-step explanation:

1 yard = 0.91m

203 yard=?

(203x0.91)/1=184.73.

+1(415) 450-6164

Answer:

135

Step-by-step explanation:

Depending on where you start, the protractor can read in different ways. Since the measure of this angle started from the left, you read the numbers at the top. If the measure would have started from the right, you read the numbers below.

A good rule of thumb is that if the angle appears to be greater than 90 degrees, or an obtuse angle, you would choose the only answer choice that is above 90 degrees.

Hope this helps!

The algebraic expression that represents the number of new accounts that he will add in m months is x ≥ 7m.

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

Every month, a salesperson adds 7 new accounts.

Let m be the number of the month and x be the number of the accounts.

Then the inequality equation will be

x ≥ 7m

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Answer:

The square root of 36/196 is 3/7.

The square root of 36/169 is 6/13.

Answer:

A wave period is the measure of the time it takes for the wave cycle to complete.

The period of the wave is 2 seconds.

Answer:

B. (4, -2)

Step-by-step explanation:

Please see attachment.

Hope this helps!

If not, I am sorry.

Answer: 40/21

Step-by-step explanation:

[tex]3 \times 105=315\\\\6 \times 10^{2}=600\\\\\implies \frac{6 \times 10^{2}}{3 \times 105}=\frac{600}{305}=\boxed{\frac{40}{21}}[/tex]

The distance from the wall defined by the y-axis will be 8 feet. Then the correct option is B.

The equation of line is given as

y = mx + c

Where m is the slope and c is the y-intercept.

The table is given below.

Then the equation of the line will be

(y – 8) = [(8 – 6) / (0 – 20)](x – 0)

       y = -0.1x + 8

If the drain is at the minimum point.

Then the distance from the wall defined by the y-axis will be 8 feet.

Then the correct option is B.

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Answer:

I am not completely sure if this is correct, but I believe the answer should be PM.
This is because the order of the letters that represents a point can be swapped, since they are still forming the same line.

Answer:

C [tex]\sqrt{5}[/tex]

Step-by-step explanation:

Use pythagorean theorem.

[tex]x^{2}[/tex] +[tex]\sqrt{7} ^{2}[/tex] = (2[tex]\sqrt{3}) ^{2}[/tex]    

[tex]x^{2}[/tex] + 7 = 12   Subtract 7 from both sides

[tex]x^{2}[/tex] = 5           Take the square root of both sides to solve

x = [tex]\sqrt{5}[/tex]

The green-colored area of the graph attached below shows the solution set to 3eˣ>(-1/2)x.

Inequality is the relationship between two expressions showing the relationships like greater than, lesser than, lesser than equals to, and greater than equals to.

Here assume f is a function which is given by f(x)=3eˣ

and g be another function which is given by g(x)= (-1/2)x

Here we have to find the solution graph showing the relationship

f(x) > g(x)

Let at point (a,b) the f(x) and g(x) meet each other.

After that intersection point, g(x) will decrease as g(x) is a decreasing function. and f(x) will increase.

So in the solution set will contain the area where g(x) is larger than f(x).

Therefore the solution graph of this inequality is the green-colored area as shown below,

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The value of FY in the triangle will be 30.11

From the information given, the value of BE will be:

= [tex]\sqrt{64.2}[/tex]² - [tex]\sqrt{51.2}[/tex]²

= 38.7

From the triangle, DY will be

= [tex]\sqrt{64.22}[/tex]² - [tex]\sqrt{61.7}[/tex]²

= 17.7

AY will be:

= [tex]\sqrt{61.7}[/tex]² + [tex]\sqrt{17.7}[/tex]²

= 64.2

FY will now be:

= [tex]\sqrt{64.2 - 56.7}[/tex]²

= 30.11

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To find the maxima and minima of the function, we need to calculate the derivative of the function. Note, before the denominator is a perfect square trinomial, so the function can be simplified as

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f(x) = \frac{x^2 - x - 2}{(x - 3)^2}} \end{gathered}$}[/tex]

So the derivative is:

  [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{(2x - 1)(x - 3)^2 - 2(x - 3)(x^2 - x - 2)}{(x - 3)^4} } \end{gathered}$}[/tex]

Simplifying the numerator, we get:

                 [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{(x - 3)(-5x + 7)}{(x - 3)^4} = \frac{-5x + 7}{(x - 3)^3} } \end{gathered}$}[/tex]

The function will have a maximum or minimum when f'(x) = 0, that is,

                  [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{-5x + 7}{(x - 3)^3} = 0 } \end{gathered}$}[/tex]

which is true if -5x + 7 = 0. Then x = 7/5.

To determine whether x = 7/5 is a maximum, we can use the second derivative test or the first derivative test. In this case, it is easier to use the first derivative test to avoid calculating the second derivative. For this, we evaluate f'(x) at a point to the left of x = 7/5 and at a point to the right of it (as long as it is not greater than 3). Since 1 is to the left of 7/5, we evaluate:

                    [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f(1) = \frac{-5 + 7}{(1 - 3)^3} = \frac{2}{-8} < 0} \end{gathered}$}[/tex]

Likewise, since 2 is to the right of 7/5, then we evaluate:

                                   [tex]\large\displaystyle\text{$\begin{gathered}\sf \displaystyle \bf{\frac{-10 + 7}{(2 - 3)^3} = \frac{-3}{-1} > 0} \end{gathered}$}[/tex]

Note that to the left of 7/5 the derivative is negative (the function decreases) and to the right of 7/5 the derivative is positive (the function increases).

The value of f(x) at 7/5 is:

                               [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f\left(\tfrac{7}{5}\right) = \frac{\tfrac{49}{25} - \tfrac{7}{5} - 2}{\tfrac{49}{25} - 6 \cdot \tfrac{7}{5} + 9} = -\frac{9}{16} } \end{gathered}$}[/tex]

This means that [tex]\bf{\left( \frac{7}{5}, -\frac{9}{16} \right)}[/tex] is a minimum (and the only extreme value of f(x)).

[tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

Answer:

[tex]\text{Minimum at }\left(\dfrac{7}{5},-\dfrac{9}{16}\right)[/tex]

Step-by-step explanation:

The local maximum and minimum points of a function are stationary points (turning points).  Stationary points occur when the gradient of the function is zero.  Differentiation is an algebraic process that finds the gradient of a curve.

To find the stationary points of a function:

[tex]\boxed{\begin{minipage}{5.5 cm}\underline{Quotient Rule for Differentiation}\\\\If $y=\dfrac{u}{v}$ then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{v \dfrac{\text{d}u}{\text{d}x}-u\dfrac{\text{d}v}{\text{d}x}}{v^2}$\\\end{minipage}}[/tex]

[tex]\text{Given function}: \quad \text{f}(x)=\dfrac{x^2-x-2}{x^2-6x+9}[/tex]

Differentiate the function using the Quotient Rule:

[tex]\text{Let }u=x^2-x-2 \implies \dfrac{\text{d}u}{\text{d}x}=2x-1[/tex]

[tex]\text{Let }v=x^2-6x+9 \implies \dfrac{\text{d}v}{\text{d}x}=2x-6[/tex]

[tex]\begin{aligned}\implies \dfrac{\text{d}y}{\text{d}x} & =\dfrac{(x^2-6x+9)(2x-1)-(x^2-x-2)(2x-6)}{(x^2-6x+9)^2}\\\\& =\dfrac{(2x^3-13x^2+24x-9)-(2x^3-8x^2+2x+12)}{(x^2-6x+9)^2}\\\\\implies \text{f}\:'(x)& =\dfrac{-5x^2+22x-21}{(x^2-6x+9)^2}\\\\\end{aligned}[/tex]

Set the differentiated function to zero and solve for x:

[tex]\begin{aligned}\implies \text{f}\:'(x)& =0\\\\\implies \dfrac{-5x^2+22x-21}{(x^2-6x+9)^2} & = 0\\\\-5x^2+22x-21 & = 0\\\\-(5x-7)(x-3) & = 0\\\\\implies 5x-7 & = 0 \implies x=\dfrac{7}{5}\\\\\implies x-3 & = 0 \implies x=3\end{aligned}[/tex]

Put the x-values back into the original equation to find the y-values:

[tex]\implies \text{f}\left(\frac{7}{5}\right)=\dfrac{\left(\frac{7}{5}\right)^2-\left(\frac{7}{5}\right)-2}{\left(\frac{7}{5}\right)^2-6\left(\frac{7}{5}\right)+9}=-\dfrac{9}{16}[/tex]

[tex]\implies \text{f}(3)=\dfrac{\left(3\right)^2-\left(3\right)-2}{\left(3\right)^2-6\left(3\right)+9}=\dfrac{4}{0} \implies \text{unde}\text{fined}[/tex]

Therefore, there is a stationary point at:

[tex]\left(\dfrac{7}{5},-\dfrac{9}{16}\right)\:\text{only}[/tex]

To determine if it's a minimum or a maximum, find the second derivative of the function then input the x-value of the stationary point.

Differentiate f'(x) using the Quotient Rule:

Simplify f'(x) before differentiating:

[tex]\begin{aligned}\text{f}\:'(x) & =\dfrac{-5x^2+22x-21}{(x^2-6x+9)^2}\\\\& = \dfrac{-(5x-7)(x-3)}{\left((x-3)^2\right)^2}\\\\& = \dfrac{-(5x-7)(x-3)}{(x-3)^4}\\\\& = -\dfrac{(5x-7)}{(x-3)^3}\\\\\end{aligned}[/tex]

[tex]\text{Let }u=-(5x-7) \implies \dfrac{\text{d}u}{\text{d}x}=-5[/tex]

[tex]\text{Let }v=(x-3)^3 \implies \dfrac{\text{d}v}{\text{d}x}=3(x-3)^2[/tex]

[tex]\begin{aligned}\implies \dfrac{\text{d}^2y}{\text{d}x^2} & =\dfrac{-5(x-3)^3+3(5x-7)(x-3)^2}{(x-3)^6}\\\\& =\dfrac{-5(x-3)+3(5x-7)}{(x-3)^4}\\\\\implies \text{f}\:''(x)& =\dfrac{10x-6}{(x-3)^4}\end{aligned}[/tex]

Therefore:

[tex]\text{f}\:''\left(\dfrac{7}{5}\right)=\dfrac{625}{512} > 0 \implies \text{minimum}[/tex]

Answer:

1st q answer is f(x) is one- to -one function and 2nd q answer is 2

Answer:

Step-by-step explanation:

Let f(x) = y

y = 2x - 3

x = y + 3 / 2

inverse of f(x) = x + 3 / 2

f [g(2)]

f [2+3/2]

f [5/2]

(2×5/2)-3

5-3

= 2

The correct answer is option D which is the probability is 1.

The complete question is given below:-

Jamaal knows that it is certain that he will win the election because he is the only person who is running for class treasurer. Which value represents the probability that he will win the election?

0

1/4

3/4

1

Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

The probability of Event E is given by,

P = favourable outcomes / Total outcomes

Jamaal is the only candidate running in the class treasurer election.

There for Total No. of outcomes = 1

Here Event E is Jamaal winning the Election.

So, No. of favorable outcome = 1

P(E) = 1 / 1

P(E) = 1

This type of event is called a SURE EVENT Because the probability of a sure event is always 1.

The Probability of Jamaal winning the election is 1. So, Option D is correct.

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The probability that he will win the election will be 1. Then the correct option is D.

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

The value of the probability of an event will be varying from zero to one.

Jamaal knows that it is certain that he will win the election because he is the only person who is running for class treasurer.

Then the probability that he will win the election will be

If the event will certainly happen, then the probability will be one.

P = 1

Then the correct option is D.

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The least number of consecutive positive integer that is required to make the sum of the reciprocals greater than three is 7.

An integer is simply a number that is not  a  fraction.

The first four consecutive positive integers are:

1, 2, 3 , 4.

Their reciprocals are:

1/1, 1/2, 1/3, 1/4; and

The sum of them are greater than 2; that is

1/1 + 1/2 + 1/3 + 1/4 = 2.08333333333 > 2

to make the expression >3

We would require the following integers

1/1 + 1/2 + 1/3 + 1/4+ (1/5) + (1/6) + (1/7) + (1/8)+ (1/9) + (1/10) + (1/11) = 3.01987734488

Thus, the additional consecutive reciprocal integers that is required to make the sum of the reciprocal of the fist four greater than 3 is 7.

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The number of matchsticks that each side of the biggest triangle contains is; 137 matchsticks

We know that for a diagram to be a triangle, then two smallest sides must not be greater than the third side.

Now, if there are 273 matchsticks, then the greatest side of the triangle must not be less than 273/2 = 136.5 ≈ 137

Thus, the largest side will have at least 137 matchsticks

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Answer:

720 Course Schedules

Step-by-step explanation:

When you choose the first course, there are 6 to choose from. When you scoose the second, there are only 5. This keeps going until the 6th course where there is only 1 choice.

You multiply these choices together. You should get 6×5×4×3×2×1

6×5=30

30×4=120

120×3=360

360×2=720

720×1=720

You then end up with 720 course schedules.

The solution of the equation 4x = 20, x – 11 = 9, 5x + 6x = 22, and 5(x – 2) = 30 will be 5, 20, 2, and 8.

The solution of the equation means the value of the unknown or variable.

The equations are given below.

4x = 20

 x = 5

x – 11 = 9

      x = 20

5x + 6x = 22

       11x = 22

         x = 2

5(x – 2) = 30

   x – 2 = 6

         x = 8

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Answer: Option 3 or C. 22

Step-by-step explanation:

I got the answer correct on Edge 2022 quiz. Trust me the answer is correct I screenshot it using the prt sc key then uploaded it. The proof is in the pic below.  :)