5. suppose it costs $4 for a ticket to the school dance. at that price, the dance committee sells 200 tickets.
the dance committee realizes that for every $1 increase in ticket price, they sell 10 fewer tickets. find the
maximum revenue and the ticket price that maximizes the revenue.


broo plsss heloo meeee

[tex]7x + 8 = ( - 5x) + 32 \\ 7x + 5x = 32 - 8 \\ 12x = 24 \\ x = \frac{ \cancel{24} {}^{ \: \: \: 2} }{ \cancel{12}}\\x=2 [/tex]

[tex] \Large{\boxed{\sf x = 2}} [/tex]

[tex] \\ [/tex]

Given equation:

[tex] \sf 7x + 8 = -5x + 32 [/tex]

[tex] \\ [/tex]

Substract 8 from each side :

[tex] \sf 7x + 8 - 8 = -5x + 32 - 8 \\ \\ \sf 7x = -5x + 24 [/tex]

[tex] \\ [/tex]

Add 5x to both sides :

[tex] \sf 7x + 5x = -5x + 24 + 5x \\ \\ \sf 12x = 24 [/tex]

[tex] \\ [/tex]

Divide both sides by 12 :

[tex] \sf \dfrac{12x}{12} = \dfrac{24}{12} \\ \\ \\ \boxed{\boxed{\sf x = 2}} [/tex]

[tex] \\ \\ [/tex]

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Answer:

$43.30

Step-by-step explanation:

What we know,

3 hamburgers = $12.99

Coleman wants to know how much would he have to pay for 10 hamburgers,

In order to find out how much 10 hamburgers cost, you need to find out how much 1 hamburger costs,

To find how much 1 hamburger costs divide 12.99 by 3,

12.99/3

= 4.33

Now we know that 1 hamburger cost $4.33,

Now time to find out how much 10 hamburgers cost,

Multiply 4.33 by 10,

4.33 × 10

= 43.30

Therefore it cost $43.30 for 10 hamburgers.

Answer:

Step-by-step explanation:

f(x) = 4-x

g(x) = h[tex]x^{2}[/tex]+k

g(f(x)) = 2[tex]x^{2}[/tex]-16x+26

so put  f(x)  in g(x)

h[tex](4-x)^{2}[/tex]+k

h((4-x)(4-x) + k

h([tex]x^{2}[/tex]-8x+16)+k

if h = 2 , then

2[tex]x^{2}[/tex]-16x+32 + k

and we want 26  instead of 32 so subtract 6 so K = (-6)

2[tex]x^{2}[/tex]-16x+32 + (-6)

2[tex]x^{2}[/tex]-16x+32 - 6

2[tex]x^{2}[/tex]-16x+26

h=2

k=(-6)

Answer: Heyaa!

Your Answer Is x+y = 5

Step-by-step explanation:

(x+y)^3 = 125

x+y = 5

Hopefully this helps you

- Matthew :)

Answer:

one can would be about $0.41

Step-by-step explanation:

Take $2.46 and divide it by 6 because that is the number of cans in the pack, the answer is $0.41 per can.

what is the result of the addition of 20 and 6

[tex]\boxed{\sf twenty~plus~six }\boxed[/tex]

Answer:

-1√5-3√5=(√5)(-1-3)=(√5)(-4)=-4√5

Step-by-step explanation:

if you combine the radicals, you will receive the answer that is shown above.

Answer:

[tex]-4\sqrt{5}[/tex]

Step-by-step explanation:

Given expression: (square root 5) - (3 square root 5)

Since we have √5 common in both terms, let's factor √5.

Finally, we can simplify;

Therefore, the combined radical of (square root 5) - (3 square root 5) is [tex]-4\sqrt{5}[/tex]

Area of vertical rectangle

Area of horizontal rectangle

Total:-

The Highbrook account which offers 25%  compound interest each year is a better place to  save as much money as possible.

The term interest is the amount that is obtained as the return for money invested or the amount paid on top of a loan.

We can clearly see that the Highbrook account which offers 25%  compound interest each year is a better place to  save as much money as possible.

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Answer:

b

Step-by-step explanation:

64 = 2x^2

32 = x^2

x = 4√2

ans is b

Any smooth curve connecting two points is called an arc. The correct option is c.

Any smooth curve connecting two points is called an arc. The arc length is the measurement of how long an arc is. The length of an arc is given by the formula,

[tex]\rm{ Length\ of\ an\ Arc = 2\times \pi \times(radius)\times\dfrac{\theta}{360} = 2\pi r \times \dfrac{\theta}{2\pi}[/tex]

where

θ is the angle, that arc creates at the centre of the circle in degree.

If the central angle has a measure of π/2(90°), then the length of the arc will be one-fourth of the total, while if the measure of the angle is π(180°), then the length of the arc will be half of the total.

Similarly, if the measure of the angle is 3π/4, then the length of the arc will be three-fourth of the total, while if the measure of the angle is 2π(360°), then the length of the arc will be 2πr.

Hence, the correct option is c.

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Answer:

D

Step-by-step explanation:

Answer:5.4

Step-by-step explanation:

so first you cross multiply and then you solve for x from there. You shold get 5.385164807. But you need to round that so I rounded to the nearest tenth, which would be 5.4

4 1/2 ⋅ 4 1/2=(4 x 4)^1/2

The coordinates of solution of the system of equation which is obtained by plotting the equation on the graph is (-2,2).

A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.

The first equation given in the problem is,

[tex]x+y=0[/tex]

Rearrange it,

[tex]y=-x[/tex]                    .....1

The second equation given as,

[tex]-3x+4y=14[/tex]

Rearrange it,

[tex]-3x+4y=14\\4y=14+3x\\y=\dfrac{14+3x}{4}[/tex]                    .....2

Plot the graph of both the line as shown below in the attached image. In this equation the solution is the point of intersection which is (-2,2).

Thus, the coordinates of solution of the system of equation which is obtained by plotting the equation on the graph is (-2,2).

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The length which result in a ratio closest to the golden ratio is equal to  7.5 inches and 4.5 inches. Option C is correct.

The line segment is made with two end points. Length of a line segment is the distance of both the ends of it.

A 12 inch line segment is divided into two parts. Suppose the line segment is AC which is divided into AB and BC parts. Thus,

AB+BC=AC

AB+BC=12                   ....1

The value of golden ratio is equal to 1.618. It can also be given as (1+√5)/2. The ratio of both segment is equal to golden ratio. Thus

[tex]\dfrac{AB}{BC}=\dfrac{AC}{AB}=\dfrac{1+\sqrt{5}}{2}\\\dfrac{12}{AB}=1.618\\AB=7.4166 \rm\; in[/tex]

Put this value in equation one as,

AB+7.4166=12    

AB=4.5834

The length which result in a ratio closest to the golden ratio is equal to  7.5 inches and 4.5 inches. Option C is correct.

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The game is an illustration of probability, and the probability that each player wins is 1/12

From the question, we have the following parameters:

Number of a pair of numbers = 3

A die has 6 possible outcomes.

So, the probability of getting the first pair is:

P1 = 1/6

The probability of getting the second pair is:

P2 = 1/6

The probability of getting the first and the second pairs is

P = 1/6 * 1/6

Evaluate

P = 1/36

There are three pairs of numbers in total.

So, the probability of winning is:

P(Win) = 3 * 1/36

Evaluate

P(Win) = 1/12

Hence, the probability that each player wins is 1/12

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Answer:

1/12.

Step-by-step explanation:

The probability that each player has of winning is 1/12.

Answer:

Step-by-step explanation:

Nothing else to say lol.

Answer:

x=5

Step-by-step explanation:

x+8= 13

x=13-8

x= 5

hope it helpsss

Answer:

B

Step-by-step explanation:

It goes up by one, to the right by 2. Or flip that, Im dyslexic

Answer:

B!!

Step-by-step explanation:

Hope nthis helps!!!!!

Answer:

x=7.16 or0.84

Step-by-step explanation:

The solution is in the image

Answer:

the sum of 10+16 multiplied by 49

Step-by-step explanation:

The volume of the given figure is 434 ft³. The volume of the figure is obtained in the two parts.

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

The volume of the given figure is;

[tex]\rm V = l_1 \times b_1 \times h_1 + l_2 \times b_2 \times h_2 \\\\ V= 7 \times 13 \times 4 + 2\times 5 \times 7 \\\\ V= 434 \ fT^3[/tex]

Hence, the volume of the given figure is 434 ft³.

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The area of the considered trapezoid  PQRS in simplest radical form is given by: Option c: 256 + 128√3 (in sq. units)

The area of a trapezoid is the half of the product of sum of its parallel sides to the height of that trapezoid (the distance between those parallel sides).

Thus, if we have:

Length of its parallel sides = 'a' and 'b' units respectively

Perpendicular distance between its parallel sides = 'h' units,

Then, we get:

[tex]A = \dfrac{1}{2}\times(a+b) \times h \: \rm unit^2[/tex]

Consider the figure attached below, which is a bit more labeled figure of the given trapezoid.

We constructed PA perpendicular to the level of SR, and therefore, as SR is parallel to PQ, we have PA perpendicular to PQ too.

Similarly, QB is constructed perpendicular to both PQ and SR.

Thus, for PQBA, all pair of adjacent sides are perpendicular to each other, therefore its a rectangle.

Sum of parallel sides = Length of PQ + Length of SR

= 24 + |SR| = 24 + |SB| + |BR| = 24 + |AS| - |AS| + |SB| |+ |BR|

= 24 + |AS| + |SB| + |BR| - |AS| = 24 + |AB| + |BR| - |AS|

Due to PABQ being a rectangle (its four sides are such that adjacent sides are perpendicular to each other), we have |PQ| = |AB| = 24 units.

Thus, we get:

Sum of parallel sides = 24 + |AB| + |BR| - |AS| = 48 + |BR| - |AS|

Perpendicular distance between its parallel sides = |PA| = |QB|

Thus, we need to find the values of 3 line segments, which are:

|BR|, |AS|, and |PA| (instead of |PA|, we can find |QB| too, since both are of same length).

From the perpective of angle R(interior) in right triangle RBQ, we know the side RQ's length (32 units), and want length of BR.

Thus, its hypotenuse and base from the perspective of angle R (interior).

Thus, we can use cosine ratio or secant ratio. Let we use cosine ratio.

Then, we get:
[tex]\cos(30^\circ) = \dfrac{|BR|}{|RQ|} \\\\|BR| = 32 \times \cos(30^\circ) = 32 \times \dfrac{\sqrt{3}}{2} = 16\sqrt{3}\: \rm units[/tex]

For the same triangle as in case 1 (ie RBQ), but now taking the sine ratio, we get:

[tex]\sin(30^\circ) = \dfrac{|BQ|}{|RQ|} \\\\|BQ| = 32 \times \sin(30^\circ) = 16 \: \rm units[/tex]

This is same as |PA| because of PQBA being a rectangle.

The angle PSA is supplement of angle PSR as both joined make a straight line ASR. Thus, we get:
[tex]m\angle PSA + m\angle PSR = 180^\circ\\m\angle PSA = 180^\circ-135^\circ = 45^\circ[/tex]

Thus, for the triangle PSA, similar to the first case or second case, but now using tangent ratio as we've got |PA| = |QB| = 16 units, we get:

[tex]\tan(m\angle PSA) = \dfrac{|PA|}{|AS|}\\\tan(45^\circ) = \dfrac{|PA|}{|AS|} \\\\|AS| = 1 \times 16 = 16 \: \rm units[/tex]

Thus, we get:

Sum of parallel sides = 48 + |BR| - |AS| = 48 + 16√3 - 16 = 32 + 16√3 units

Perpendicular distance between its parallel sides = |PA| = |QB| = 16 units.

Thus, Area of the trapezoid PQRS is evaluated as:

[tex]A = \dfrac{1}{2} \times \text{Sum of parallel sides} \times \text{Distance between those sides}\\A =\dfrac{1}{2} \times (32 + 16\sqrt{3}) \times 16 \\\\A = 256 + 128\sqrt{3} \: \rm unit^2[/tex]

Thus, the area of the considered trapezoid  PQRS in simplest radical form is given by: Option c: 256 + 128√3 (in sq. units)

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Answer:

B. supplementary angles

Step-by-step explanation:

Answer:

35

Step-by-step explanation:

Directly plug in the limit and evaluate

[tex]\displaystyle \lim_{x\rightarrow-2}x^4-3x^3+x-3=(-2)^4-3(-2)^3+(-2)-3=35[/tex]

[tex]~~~~~~4(2x-3)(5x+2) = 0\\\\\implies (2x -3)(5x+2) = 0\\\\\implies 2x -3=0 ~~~~~~\text{or}~~~~~~ 5x +2 = 0\\\\\implies 2x =3 ~~~~~~~~~~~\text{or}~~~~~~ 5x = -2\\\\\implies x = \dfrac 32 ~~~~~~~~~~~~ \text{or}~~~~~~ x = -\dfrac 25\\\\\text{Hence,}~ x = \dfrac 32, ~ x = -\dfrac 25[/tex]

Step-by-step explanation:

out of the 21 students, 8 do not play neither basketball nor baseball.

so, 13 students play at least one of these games.

10 play basketball, and 9 play baseball. that would be 19 together. but we have only 13 players.

that means 6 students (19 - 13) must play both games.

remember, a probability is always

desired cases / possible cases

so, when we are looking for the students, who play both games, we have 6 desired cases out of a total of 21.

and the probability to pick one of them is therefore

6/21 = 2/7 = 0.285714286...