At what pressure would a 0.175 mole sample of gas at 22.0°C have a volume of 2175
mL?

Answer:

if i am correct it is density =)

Explanation:

Answer:

density

Explanation:

&*

Answer:

Refrigerator

Explanation:

An example of a house-hold appliance whose circuit is connected in series is the refrigerator. The compressor and the thermostat of the refrigerator are connected in series in such a way that when the temperature inside of the refrigerator is high, the thermostat switches the compressor on so as to reduce the temperature inside the refrigerator to a desired level. The series connection of a typical refrigerator is illustrated in the diagram attached.

Some example of electronic appliances at home that are connected using a series connection are: refrigerator, freezer and electric bulbs.

An electric circuit can be defined as an interconnection of electrical components, in such a way that it creates a path for the flow of electric charge (current) with respect to a driving voltage.

Generally, an electric circuit is made up of the following electrical components:

When there are  electrical devices present in a circuit ,

Basically, two or more electrical components present in an electric circuit with an energy source (power), can be connected or arranged in two (2) forms and these are;

I. Parallel circuit.

II. Series circuit.

A series circuit connection allows only a single path for the flow of current and as such the same amount of current flows through each electrical components, regardless of which is turned ON or used.

Additionally, the negative lead of each electrical component is connected to the positive lead of the next electrical component; therefore, sharing a common current.

In conclusion, some example of electronic appliances at home that are connected using a series connection are:

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Answer:

[HF] = 0.23M

0.02M = [F⁻]

[H₃O⁺] = 0.02M

Explanation:

The equilibrium of HF with water is:

HF + H₂O ⇄ H₃O⁺ + F⁻

Where F⁻ is the conjugate base of the HF

The initial concentration of HF is:

[HF] = 0.0500mol / 0.200L = 0.25M

Now, in equilibrium, if the 7.90% is dissociated, the undissociated HF is the 100 - 7.90 = 92.1%

0.25M*92.1% = 0.23M = [HF]

The conjugate base will be 0.25M - 0.23M = 0.02M = [F⁻]

And as the H₃O⁺ ion comes from the same equilibrium of F⁻ and is produced in the same proportion:

[H₃O⁺] = 0.02M

Answer:

C

Explanation:

The nervous system sends signals, or in this case, impulses to parts of your body that direct them to move.

Answer:

11280

Explanation:

Answer:

- Exceed the buffer capacity

- Raise the pH by several units

Explanation:

Will:

(Assume that the volume does not change upon the addition of hydrobromic acid.)

Raise the pH slightly

Lower the pH slightly

Raise the pH by several units

Lower the pH by several units

Not change the pH

Exceed the buffer capacity

1L of a buffer of 0.384M acetic acid and 0.512M of sodium acetate contains 0.384 moles of the acid and 0.512 moles of the salt.

A base as Ca(OH)2 reacts with the acid, CH3COOH as follows:

Ca(OH)2 + 2CH3COOH → Ca(CH3COO)₂ + 2 H2O

For the reaction of the 0.422 moles of calcium hydroxide are required:

0.422 moles Ca(OH)2 * (2 moles CH3COOH / 1 mole Ca(OH)2) = 0.844 moles of CH3COOH

As there are just 0.384 moles of acetic acid:

Exceed the buffer capacity

And:

Raise the pH by several units

-Because the solution becomes more basic-

Answer:

P₂ = 3.43 atm

Explanation:

Step 1: Given data

Step 2: Calculate the final pressure of ammonia

We have an ideal gas experiencing a change in volume and pressure with no change in the temperature. We can calculate the final pressure of ammonia using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁/V₂

P₂ = 1.10 atm × 93.5 mL/30.0 mL

P₂ = 3.43 atm

Answer:

Explanation:

Na₂CO₃+ CuCl₂ = CuCO₃ + 2NaCl

106 g ( 1 mole )                      117 g ( 2 moles )

106 gram   of Na₂CO₃   produces   117 grams of NaCl

23.9 gram  of Na₂CO₃   produces   117 x 23.9 / 106  grams  

grams of NaCl produced =  117 x 23.9 / 106  =  26.38  gram .

The mass of sodium chloride is produced by 23.9 g of sodium carbonate is 26.38 g.

Mass is defined as the amount of matter in a particle or object is represented by mass, which is a dimensionless quantity.

It is also defined as inertia is a quantitative measure of a fundamental feature of all stuff.

Na₂CO₃+ CuCl₂ --> CuCO₃ + 2NaCl

1 mole of Na₂CO₃ = 106 g

2 mole of NaCl = 117 g

So, 23.9 g of  Na₂CO₃  

= 117g x 23.9 / 106g

= 26.38 g

Thus, the  mass of sodium chloride is produced by 23.9 g of sodium carbonate is 26.38 g.

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Answer:K,Potassium

Explanation:

Answer:

CH2O

Explanation:

According to the valence shell electron pair repulsion theory, electron pairs tend to position themselves as far apart in space as possible to minimize repulsion.

The shape of a molecule depends on the number of electron pairs present on the valence shell of the central atom in the molecule- both lone pairs and bond pairs.

CH2O has three electron domains. the possession of three electron domains and no lone pairs of electrons on the central atom corresponds to a trigonal planar geometry.

Answer:

61.8 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above,

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Next, the data obtained from the question include:

Molarity of acid, HCl (M1) = 0.341 M

Volume of base, NaOH (Vb) = 43.9 mL

Molarity of base, NaOH (Mb) = 0.480 M

Volume of acid, HCl (Va) =?

The volume of the acid needed for the reaction can be obtained as follow:

MaVa/MbVb = nA/nB

0.341 × Va / 0.480 × 43.9 = 1/1

Cross multiply

0.341 × Va × 1 = 0.480 × 43.9 × 1

0.341 × Va = 21.072

Divide both side by 0.341

Va = 21.072 /0.341

Va = 61.8 mL

Therefore, 61.8 mL of the acid, HCl is needed for the reaction.

Answer:

mitochondrion

Explanation:

Answer:

D

Explanation:

The cathode rays are being deflected towards the positive plate because the particles of the ray are negatively charged

Explanation:

So, from this, we can conclude that the cathode rays are being deflected towards the positive plate because the particles of the ray are negatively charged.

Learn more about cathode rays here:

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Answer:

Compound 3 i think

Explanation:

Answer:

5.21 g

Explanation:

Density of Red 40 = molar mass/molar volume

since the molar volume = 22.4 L

Density of Red 40 = 496.42 g/mol/22.4 L

Density of 496.42 g/mol = 22.16 g/L

But;

density = mass/volume

volume of Red 40 = 0.235 L

mass = density * volume

mass = 22.16 g/L * 0.235 L

mass = 5.21 g

The mass of the red 40 dye in the 0.235 L solution is 5.21 g

Molar mass of red 40 dye = 496.42 g/mol

Molar volume = 22.4 L

[tex]Density = \frac{mass}{volume}\\\\ = \frac{496.42}{22.4}\\\\[/tex]

Density of red 40 dye = 22.16 g/L

Density of red 40 dye = 22.16 g/L

Volume = 0.235 L

Mass of red 40 dye =?

Mass = Density × Volume

= 22.16 × 0.235

Mass of red 40 dye = 5.21 g

Therefore, the mass of the red 40 dye in the solution is 5.21 g

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Answer:

Ether group.

Explanation:

Ethers are the compounds that connect two aryl or alkyl groups by an oxygen atom and represented by R–O–R′ where R either aryl or alkyl groups. Ether can be identified by the presence of alKyl groups on either side of the oxygen atom commonly. Diethyl ether, methyl ethyl ether are some of the examples of alkyl ether

Thus, the correct answer is - Ether group.

Answer:

pH = 11.179

Explanation:

The sodium carbonate, Na2CO3, is in equilibrium with water as follows:

Na2CO3 + H2O ⇆ NaHCO3 + OH⁻

Where Kb is 1.786x10⁻⁴:

Kb = 1.786x10⁻⁴ = [NaHCO3] [OH-] / [Na2CO3]

Where [NaHCO3] = [OH-] = X, our incognite

And [Na2CO3] is molar concentration of sodium carbonate:

[Na2CO3] = 0.3379g * (1mol / 105.99g) = 3.188x10⁻³ moles Na2CO3

In 250.0mL = 0.2500L:

3.188x10⁻³ moles Na2CO3 / 0.2500L = 0.01275M

Replacing in Kb expression:

1.786x10⁻⁴ = [NaHCO3] [OH-] / [Na2CO3]

1.786x10⁻⁴ = [X] [X] / [0.01275]

2.278x10⁻⁶ = X²

X = [OH⁻] = 1.509x10⁻³M

As pOH = -log [OH⁻] = 2.821

And pH = 14 - pOH

Answer:

its waves

Explanation:

normally thermal energy is transferred through particles but radiation is an exception and it transfers it through waves instead.

I hope this helped :))

Answer:

WAVES

Explanation:

Answer:

true

Explanation:

An organ is made of several types of tissue and therefore several types of cells. For example, the heart contains muscle tissue that contracts to pump blood, fibrous tissue that makes up the heart valves, and special cells that maintain the rate and rhythm of heartbeats.

Answer:

True

Explanation:

Cells make up tissues, which makes up organs

Hope this helps! Good luck :)

Answer:

  about 121.5 K or -151.7 °C

Explanation:

Volume of an ideal gas is proportional to the absolute temperature. At 67 °C, the absolute temperature is 67+273.15 K, or 340.15 K.

Then 50.0/140.0 times that temperature is ...

  (5/14)(340.15 K) ≈ 121.482 K ≈ -151.668 °C

The volume would be 50.0 mL at a temperature of about 121.5 K or -151.7 °C.

D. Plutonium-238 is the most stable isotope

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles (such as alpha (α), beta (β), gamma (γ) particles)

General formulas used in decay:

[tex]\large {\boxed {\bold {N_t = N_0 (\dfrac {1} {2}) ^ {t / t \frac {1} {2}}}}[/tex]

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

Half-life shows the time it takes for an atom to get half of its initial mass (to decay to half of its initial mass)

The longer the half-life indicates the stability of the atom

Half-life (hr) of isotopes :

Polonium-210  : 3,310

Uranium-237  : 162

Francium-227  : 0.04

Plutonium-238 : 768,000

The half-life value above shows that Plutonium-238 has the longest time, making it the most stable

Answer:

Glucose. Fructose. Galactose.

Explanation:

Glucose +fructose=succrose(normal sugar)

Glucose+Glucose= Maltose(wheat sugar)

Glucose+Galactose= Lactose(milk sugar)

Explanation:

A. 3 groups bound to it with no lone pairs