Answer:
a
[tex]\mu = 25 [/tex]
b
[tex]\lambda =0.04 [/tex]
c
[tex]P(X > 65 ) =0.0742 [/tex]
Step-by-step explanation:
From the question we are told that
The number of success is n = 5
The time duration is N = 125 minutes
Generally the mean of the random variable is mathematically represented as
[tex]\mu = \frac{N}{n}[/tex]
=> [tex]\mu = \frac{125}{5}[/tex]
=> [tex]\mu = 25 [/tex]
Generally the rate parameter is mathematically represented as
[tex]\lambda = \frac{1}{\mu}[/tex]
=> [tex]\lambda = \frac{1}{25}[/tex]
=> [tex]\lambda =0.04 [/tex]
Generally the cumulative distribution function for exponential distribution function is
[tex]F(x) = \left \{0 \ \ \ \ \ \ x \le 0}} \atop {1 -e^{-\lambda t }\ x>0}} \right.[/tex]
Generally the probability that the time to success will be more than 63 minutes is mathematically represented as
[tex]P(X > 65 ) = 1 - P(X \le 65)[/tex]
Here
[tex]P(X \le 65) = 1 -e^{-65 * \lambda }[/tex]
=> [tex]P(X \le 65) = 1 -e^{-65 * 0.04 }[/tex]
=> [tex]P(X \le 65) = 0.92573[/tex]
So
[tex]P(X > 65 ) = 1 - 0.92573 [/tex]
[tex]P(X > 65 ) =0.0742 [/tex]
thanks who ever helped
Answer:
60 × 50 = 3000
7 × 50 = 350
60 × 4 = 240
7 × 4 = 28
3000 + 350 + 240 + 28 =3618
54 × 67 = 3618
I will give brainliest! 2(6x+3)
Answer: 12x+6
Step-by-step explanation:
distributive property
Answer:
=12x + 6
Step-by-step explanation:
Alex has to fill his 10 gallon fish tank with water. He only has a 1 pint bucket. How many times will he have to fill his bucket to fill the tank?????W
Answer:
80
Step-by-step explanation:
8 pints in a gallon so then you multiply 8 x 10 and get 80
Answer:
80
Step-by-step explanation:
1 gallon = 8 pints8 × 10 = 80I hope this helps!
please I need a quick help
Answer:
x intercept (-2,0) y intercept (0,2)
Step-by-step explanation:
Answer:
I'm pretty sure these are the answers
x-intercept (-2,0)
y-intercept (0,2)
Explanation:
x-intercept: Is coordinates where the line hits the x-axis
y-intercept: Is coordinates where the line hits the y-axis
2. Arsenic is a compound that occurs naturally in very low concentrations. Arsenic blood concentrations in healthy individuals are Normally distributed, with a mean of 3.2 mg/dl and a standard deviation of 1.5 mg/dl. A researcher believes that one area of the United States has naturally elevated arsenic levels in the ground and water supplies. An SRS of 25 individuals in this area found a sample mean arsenic level of 3.75 mg/dl. What are the null and alternative hypotheses for this study?
Answer:
The null hypothesis [tex]H_o : \mu = 3.2 \ mg/dl[/tex]
The alternative hypothesis [tex]H_a : \mu > 3.2 \ mg/dl[/tex]
Step-by-step explanation:
From the question we are told that
The mean is [tex]\mu = 3.2 \ mg/dl[/tex]
The standard deviation is [tex]\sigma = 1.5 mg/dl[/tex]
The sample size is n = 25
The sample mean is [tex]\= x = 3.75 \ mg /dl[/tex]
Generally
The null hypothesis is : That the mean of the Arsenic blood concentrations in healthy individuals is [tex]\mu = 3.2 \ mg/dl[/tex]
i.e
The null hypothesis [tex]H_o : \mu = 3.2 \ mg/dl[/tex]
The alternative hypothesis is : That the mean of the Arsenic blood concentrations in healthy individuals is greater than [tex]\mu = 3.2 \ mg/dl[/tex]
The alternative hypothesis [tex]H_a : \mu > 3.2 \ mg/dl[/tex]
Use the stem-and-leaf plot of Monthly Sales Goals to answer the question that follows.
Monthly Sales Goals (in thousands)
Stem Leaf
1 8 9
2 5 6 6 8
3 2 3 3 6 9
4 0
What is the median monthly sales goal? (2 points)
a. $26,000
b. $29,600
c. $30,000
d. $30,500
Answer:
The median monthly sales goal is $30000
Step-by-step explanation:
Monthly Sales Goals (in thousands)
Stem Leaf
1 8 9
2 5 6 6 8
3 2 3 3 6 9
4 0
Data (Salary in thousands) : 18,19,25,26,26,28,32,33,33,36,39,40
n = 12(even)
[tex]Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}[/tex]
[tex]Median = \frac{\frac{12}{2} \text{th term}+(\frac{12}{2}+1) \text{th term}}{2}\\Median = \frac{6 \text{th term}+7 \text{th term}}{2}\\Median = \frac{28+32}{2}\\Median = 30[/tex]
So, The median monthly sales goal is $30000
So, Option C is true
The resting heart rates for a sample of individuals are normally distributed with a mean of 70 and a standard deviation of 15. Use the 68-95-99.7 rule to find the percentage of heat rates greater than 55
Answer:
84%
Step-by-step explanation:
The empirical rule states that 68% values are within 1 standard deviation of mean, i.e,
70
±
15
or from 55 to 85. Since normal distribution is symmetric, we must have (32%) outside this range, and 32/2=16% on the right if this range. Hence below 85 we have (100-16) % = 84%
What is the area of quadrilateral WXYZ?
Answer:
[tex]Area = 105[/tex]
Step-by-step explanation:
Given
[tex]W = (-5,4)[/tex] ---- [tex](x_1,y_1)[/tex]
[tex]X = (3,4)[/tex] ------ [tex](x_2,y_2)[/tex]
[tex]Y = (6,-6)[/tex] ----- [tex](x_3,y_3)[/tex]
[tex]Z = (-7,-6)[/tex] ---- [tex](x_4,y_4)[/tex]
Required
Determine the area;
Area is calculated as thus:
[tex]Area = \frac{1}{2}[(x_1.y_2 +x_2.y_3 + x_3.y_4 + x_4.y_1)-(x_2.y_1 +x_3.y_2 + x_4.y_3 + x_1.y_4)][/tex]
Substitute values
[tex]Area = \frac{1}{2}[(-5*4 +3*-6 + 6*-6 + -7*4)-(3*4 +6*4 + -7*-6 + -5*-6)][/tex]
[tex]Area = \frac{1}{2}[(-102)-(108)][/tex]
[tex]Area = \frac{1}{2}[-102-108][/tex]
[tex]Area = \frac{1}{2}[-210][/tex]
[tex]Area = -105[/tex]
[tex]Area = 105[/tex]
None of the options answer the question:
PLEASE HELP!!! Chloe is working two summer jobs, landscaping and clearing tables. She must work no less than 12 hours altogether between both jobs in a given week. Write an inequality that would represent the possible values for the number of hours landscaping, l and the number of hours clearing tables, c, that Chloe can work in a given week.
Answer:
got u homie
Step-by-step explanation:
Answer:
l +c _> 12
Step-by-step explanation:
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) a. Compute the probability that a randomly selected peanut M&M is not green. 0.850 b. Compute the probability that a randomly selected peanut M&M is green or red. c. Compute the probability that two randomly selected peanut M&M’s are both red. d. If you randomly select two peanut M&M’s, compute that probability that neither of them are red e. If you randomly select two peanut M&M’s, compute that probability that at least one of them is red.
Complete question
The complete question is shown on the first uploaded image
Answer:
a
[tex]y' = 0.85 [/tex]
b
[tex]P(J) = 0.27 [/tex]
c
[tex]P(R) = 0.0144 [/tex]
d
[tex]P(R') = 0.7744 [/tex]
e
[tex]P(Q) =0.2256 [/tex]
Step-by-step explanation:
From the question we are told that
The proportion of M & M's that is brown is b = 0.12
The proportion of M & M's that is yellow is y = 0.15
The proportion of M & M's that is red is r = 0.12
The proportion of M & M's that is blue is b = 0.23
The proportion of M & M's that is orange is o = 0.23
The proportion of M & M's that is green is g = 0.15
Generally the probability that a random selected M&M is not yellow is
[tex]y' = 1-y[/tex]
=> [tex]y' = 1-0.15[/tex]
=> [tex]y' = 0.85 [/tex]
Generally the probability that a randomly selected peanut M&M isgreen or red is mathematically represented as
[tex]P(J) = g + r [/tex]
=> [tex]P(J) = 0.15 + 0.12 [/tex]
=> [tex]P(J) = 0.27 [/tex]
Generally the probability that two randomly selected peanut M&M’s are both red is mathematically represented as
[tex]P(R) = r^2[/tex]
=> [tex]P(R) = 0.12^2[/tex]
=> [tex]P(R) = 0.0144 [/tex]
Generally if two two peanut M&M’s are selected the probability that neither of them are red is mathematically represented as
[tex]P(R') = (1 -r)^2[/tex]
=> [tex]P(R') = (1 - 0.12)^2[/tex]
=> [tex]P(R') = 0.7744 [/tex]
Generally if two two peanut M&M’s are selected the probability that at least one of them is red is mathematically represented as
[tex]P(Q) = 1- P(R')[/tex]
=> [tex]P(Q) = 1- 0.7744 [/tex]
=> [tex]P(Q) =0.2256 [/tex]
For altitudes up to 36,000 feet, the relationship between ground temperature and atmospheric
temperature can be described by the formula t = -0.0035a +g, in which t is the atmospheric
temperature in degrees Fahrenheit,a is the altitude, in feet, at which the atmospheric temperature is
measured and g is the ground temperature in degrees Fahrenheit. Solve the equation for a. If the
atmospheric temperature is -30.5 °F and the ground temperature is 50 °F, what is the altitude?
The equation for a is a =
If the atmospheric temperature is -305 °F and the ground temperature is 50 °F, then
feet
a =
Answer:
The equation for a is [tex]a=-\frac{2000}{7}*(t-g)[/tex]
The altitute is 101,428.57 feet
Step-by-step explanation:
You know that the relationship between ground temperature and atmospheric temperature can be described by the formula
t = -0.0035a +g
where:
t is the atmospheric temperature in degrees Fahrenheita is the altitude, in feet, at which the atmospheric temperature is measured g is the ground temperature in degrees Fahrenheit.Solving the equation for a:
-0.0035a +g=t
-0.0035a= t - g
[tex]a=\frac{t-g}{-0.0035}[/tex]
[tex]a=-\frac{2000}{7}*(t-g)[/tex]
The equation for a is [tex]a=-\frac{2000}{7}*(t-g)[/tex]
If the atmospheric temperature is -305 °F and the ground temperature is 50 °F, then t= -305 °F and g= 50 °F
Replacing in the equation for a you get:
[tex]a=-\frac{2000}{7}*(-305-50)[/tex]
[tex]a=-\frac{2000}{7}*(-355)[/tex]
a= 101,428.57
The altitute is 101,428.57 feet
The sum of two consecutive even numbers is 38. Find the bigger number.
Answer:
20
Step-by-step explanation:
18 plus 20 equals 38
20 is bigger than 18
One case of books weighs 34 pounds. One case of magazines weighs 25 pounds. A book store wants to ship 73 cases of books and 91 cases of magazines to another store. What is the total weight of the shipment?
Answer:
4,757 pounds
Step-by-step explanation:
One case book weighs 34 pounds
One case of magazines weigh 25 pounds
A book store wants to ship 73 cases of book 91 cases of magazines
Therefore the total weight of the shipment can be calculated as follows
= 34×73 + 25×91
= 2482 + 2275
= 4,757
Hence the total weight of the shipment is 4,757 pounds
At a particular university, statistics students miss a mean of 2.1 days of school each semester with a standard deviation of 2.5 days. What is the probability that the mean number of days missed for a random sample of 64 students will be more than 3
Answer:
0.0018
Step-by-step explanation:
P(z>2.88)=1-0.9980= 0.0018
I’LL MARK BRAINLEST! :)
Answer:
9.9
Step-by-step explanation:
7^2+7^2= c^2
c= 9.9
Answer:
the correct answer is 10.9
Step-by-step explanation:
I got this answer right.
Please help me for a TEST review tomorrow!!
Answer:
Hope you understand my writing!
what is bigger 2.50 or 2??
Answer:
2.50
Step-by-step explanation:
2.50 is 2 1/2 vs 2 is only 2
Answer: 2.50
Hope This Helps!
please help
thank you
Answer:
There's your answer!
Step-by-step explanation:
To do these just grab a calculator, or if you know your multiplication tables like I do, it's extremely easy, for example, when multiplying 60 and 80, you can do it in your head by just multiplying 6 and 8 to get 48, then add the two zeros on the end from 60 and 80, and you'll get 4800.
Solving the for angle NMP. *
Answer:
50°
Step-by-step explanation:
Angle NMP is an angle that has its vertex on a point along the circumference of the circle, thus, angle NMP is referred to as an inscribed angle of the circle.
The measure of an inscribed angle is equal to half of the measure of the arc it intercepts.
Therefore, the following equation shows the relationship between inscribed angle NMP and arc NP:
m<NMP = ½ × measure of arc NP
m<NMP = ½*100
m<NMP = 50°
In josh’s classroom the teacher has 625 pencils to pass out to 25 students. If the same number of pencils is given to each student, how many students get?
Answer:
Each student is given 25 pencils
Step-by-step explanation:
There are 25 students and 625 pencils. How many is each student gonna receive?
625 pencils ÷ 25 students = 25 pencils are given to each student
Answer:
Each student is given 25!
Step-by-step explanation:
Hope this helps! ^w^
Anna is 9 years less than twice jims age. The sum of thier ages are 63. how old are anna and jim
Answer:
Jim is 36. Anna is 27.
Step-by-step explanation:
63 -9 = 54
54 ÷ 2 = 27
27 + 9 = 36
Anna's age is 39 years old while Jim's age is 63-year old based on the formation of the equation for their age.
How to form an equation?Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.
Let's say Anna's age is A while Jim's age is J.
As per the given,
Anna is 9 years less than twice Jim's age.
A = 2J - 9
And,
Sum A + J = 63
By solving both equations,
63 - J = 2J - 9
63 + 9 = 3J
J = 24 years old.
A = 2(24) - 9 = 39 years old.
Hence "Anna's age is 39 years old while Jim's age is 63-year old based on the formation of the equation for their age".
For more about the equation,
https://brainly.com/question/10413253
#SPJ2
In ΔFGH, the measure of ∠H=90°, the measure of ∠F=18°, and GH = 9.4 feet. Find the length of HF to the nearest tenth of a foot.
Answer:
28.9
Step-by-step explanation:
tan (18) = 9.4/x times x
x times tan(18) = 9.4 / tan(18)
tan(18)
crosses out.
On a calculator do 9.4/
tan(18).
x = 28.9
How much will cost to buy beef for a family of 5 if each person gets 1/2 pound of beef and the beef cost 5.99 per pound?
Answer: 2.5 or 3
Step-by-step explanation:
4+(8/(8-7)+6-12)x10)
The answer is 24, hopes this helps!
find two numbers that equal 11,000 when added together, but also equal 3,000 when subtracted from each other
Answer:
4000 and 7000
Step-by-step explanation:
18. Naruto practices his harmonica 1/4 hour, spends 2/3 hour working on
homework
, and takes another 1/4hour to do chores every day. How much
longer does Naruto spend practicing his harmonica and doing his chores
than working on homework?
Answer:
2
Step-by-step explanation:
If he uses 1 hour to practice harmonica, one our on homework, and another hour doing chores. He will be spending twice as much time practicing harmonica and doing homework than he would spend on chores.
Answer:
10 minutes more on working with his homework than his chores and harmonica OR 1/6 hour (or any other equivalent fraction).
Step-by-step explanation:
You can convert 1/4 into fifteen minutes. 15+15=30 minutes. Thus, he spends 30 minutes on his harmonica and doing chores.
You can convert 2/3 into 40 minutes.
40-30=10, so he spent 10 minutes more on working with his homework than his chores and harmonica.
Since you want it in fractions, you can find fractions that are equivalent to 10/60. One you can use is 1/6.
P.S. The Naruto reference is amazing xD
PLS HELP ME ILL MARK BRAINLIST!!
Answer:
D
Step-by-step explanation:
Its really easy promise
Answer:
It is answer C
Step-by-step explanation:
8) A committee has fifteen members. There are two members that currently serve as the board’s chairman and vice chairman. Each member is equally likely to serve in any of the positions. Two members are randomly selected and assigned to be the new chairman and vice chairman. What is the probability of randomly selecting the two members who currently hold the positions of chairman and vice chairman and assigning them to their current positions
Answer:
The probability is [tex]P(Z) = 0.0064 [/tex]
Step-by-step explanation:
From the question we are told that
The number of members is n = 15
Generally the number of ways of selecting two member from the fifteen members is mathematically represented as
[tex]K = ^{n}C_2 * 2![/tex]
Here C stands for combination hence we will be making use of the combination functionality in our calculator
[tex]K = ^{15}C_2 * 2 * 1 [/tex]
=> [tex]K = 78 * 2 * 1 [/tex]
=> [tex]K = 156 [/tex]
Gnerally the number of outcome that matches the outcome required by the committee(Which is reselecting the member who where the chairman and vice chairman of the board ) is m = 1
Generally the probability of randomly selecting the two members who currently hold the positions of chairman and vice chairman and assigning them to their current positions is mathematically represented as
[tex]P(Z) = \frac{m}{K}[/tex]
=> [tex]P(Z) = \frac{1}{156}[/tex]
=> [tex]P(Z) = \frac{1}{156}[/tex]
=> [tex]P(Z) = 0.0064 [/tex]
A newspaper article states that 90% of drivers in Iowa wear their seatbelt. Suppose we are interested in estimating the proportion of drivers in Iowa City who wear their seatbelt when driving. We will observe drivers at different times of the day at different locations around town and record whether they are wearing their seatbelt. How large of a sample would we need to estimate this proportion to within 1% with 95% confidence?
Answer:
The sample size is [tex]n = 3457 [/tex]
Step-by-step explanation:
From the we are told that
The population proportion is p = 0.90
The margin of error is E = 0.01
From the question we are told the confidence level is 95% , hence the level of significance is
[tex]\alpha = (100 - 95 ) \%[/tex]
=> [tex]\alpha = 0.05[/tex]
Generally the sample size is mathematically represented as
[tex]n =[ \frac{ Z_{\frac{\alpha }{2} } }{E} ]^2 * p(1-p)[/tex]
=> [tex]n =[ \frac{ 1.96 }{0.01} ]^2 * 0.90(1-0.90)[/tex]
=> [tex]n = 3457 [/tex]