artem is inviting 3 friends each friend wants 8 cookies and each box has 4 cookies how many boxes should artem get

The probability that the news and weather report Is NOT on will be 0.8. Then the correct option is J.

Its simple notion is that something will most likely occur. The favorable event's proportion to the overall number of occurrences.

A radio station reports news and weather, every 20 minutes for 4 minutes.

If the radio is turned on at a random time.

Then the probability that the news and weather report Is NOT on will be

P = 1 - 4/20

P = 1 - 0.20

P = 0.8

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Answer:

The answer is (x + 10)² + (y – 7)² = (4)².

Step-by-step explanation:

Here, a = (-10), b = 7 and r = 4.

So,

(x – a)² + (y – b)² = r²

[x – (-10)]² + (y – 7)² = (4)²

(x + 10)² + (y – 7)² = (4)²

Thus, The standard equation of the circle with the centre of (-10, 7) and a radius of 4 is

(x + 10)² + (y – 7)² = (4)².

Answer:

2

Step-by-step explanation:

Hey there!

In order to find the mode, you need to find the number thatis plotted the most

As you can see on the line plot, the number 2 has been plotted more than the other numbers

Meaning, that 2 is the mode

Answer:

2

Step-by-step explanation:

:)

Answer:

0.01%

Step-by-step explanation:

There's no need to worry about a problem like this, it's easy. All you have to do is find the area of the smaller rectangle, being 50, then find the area of the other one, 5000, and divide the smaller by the larger and transfer it to a percentage. 50/5000 = 0.01 = 0.01%

Answer:

i think the answer is (-4,2)

Step-by-step explanation:

The area of the 9th floor is 718.48 m² if the ground floor(floor 0) is the largest and the floor space is reduced by 5% per floor.

It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent :

[tex]\rm y = a^x[/tex]

where a is a constant and a>1

We know we can find the exponential decrease by the below formula:

[tex]\rm y = a(1-r)^n[/tex]

We have a = 1140 m²

r = 5% = 0.05

n = 9

[tex]\rm y = 1140(1-0.05)^9[/tex]

y = 718.48 m²

Thus, the area of the 9th floor is 718.48 m² if the ground floor(floor 0) is the largest and the floor space is reduced by 5% per floor.

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Answer:

The number closest to 300 would end up being 310!

Step-by-step explanation:

Standard form ax²+bx+c=0

Done

Answer:

Area=153.75 divdided by 2 = 76.88

permitere= 8 + 10.25+18.8=37.05

Step-by-step explanation:

Answer:

Step-by-step explanation:

   r = 3 cm

Volume = 27π cm³

                       [tex]\sf \boxed{\text{Volume of cylinder=$\pi r^2h$}}[/tex]

[tex]\sf \pi*3*3*h = 27 \pi\\[/tex]

              [tex]h = \dfrac{27 \pi}{\pi * 3 * 3}\\\\ \boxed{\bf h = 3 \ cm}[/tex]

      [tex]\sf \r_A : r_B = 3 : 9[/tex][tex]\sf r_A : r_B = 3 : 9[/tex]

                 = 1 : 3

      [tex]\sf h_A : h_B = 1 : 3\\[/tex]

            [tex]\sf \dfrac{3}{h_B}=\dfrac{1}{3}\\\\ cross \ multiply,\\\\ 3*3 = 1*h_B\\\\ h_B = 9 \ cm[/tex]

Volume of cylinder B = π * 9 * 9 * 9

                                    = 729π cm³

       [tex]\sf V_A : V_B = 27 \pi :729 \pi[/tex]

                    = 1 : 27

Answer:

50%

Step-by-step explanation:

When you toss a coin it will either land on tails or heads, so we have 2 possibilities who have the same chance of happening. Thus the probability that the coin lands on heads is 50% (same for tails).

Answer:

0.5

Step-by-step explanation:

Because probability is always between 0 and 1

Given a function in a table or in algebraic or graphical form, identify key features such as x- and y-intercepts; intervals where the function is increasing, decreasing, positive, or negative; relative maximums and minimums; symmetries; and end behavior. Use key features of an algebraic function to graph the function.

2.5 quarts will be needed to paint the wall on the right.

The product of length and breadth.

Area of rectangle=  length * breadth

Area of first wall = l * b

= 12*7

= 108 st. ft.

Area of 2nd wall

= l*b

=18*10

=180 sq. ft.

If 1.5 qt required to paint the 108 sq. ft. area

For 1 sq ft, paint would be need= 1.5/108

For 180 sq ft paint needed = 1.5*180/108

                                            = 2.5 qt

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[tex]3 b(broccolis=\frac{1}{8} )=\frac{3}{8}[/tex]

[tex]4c(carrots=\frac{1}{6})=\frac{4}{6}[/tex]

Lastly:

[tex]2t(tomatoes=\frac{1}{4})=\frac{2}{4}[/tex]

Answer:

25 houses in 5 weeks

Step-by-step explanation:

15 house / 3 week    *   5 week = 25 houses

The dimensions of the rectangular prisms are the side lengths of the rectangular prism

A rectangular prism has the following dimensions

Length, width and height

This means that the dimensions of the rectangular prisms are the length, width and height  of the prism

To determine the dimension, we simply take the value of the above terms i.e. length, width and height

To split the rectangular prism, we simply consider the faces of the rectangular prism.

A rectangular prism has 6 faces

Hence, there are 6 shapes when the rectangular prism is split

Note that the question is incomplete, so I gave a general explanation

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A force of 4.05×10⁶ N was exerted on one side of the wall.

Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction.

The following data were obtained from the question:

Breadth (B) = 4 m

Length (L) = 10 m

Standard pressure (P) = 101325 Nm¯²

Next, we shall determine the area of the wall. This can be obtained as follow:

Area (A) = length (L) × breadth (B)

A = 10 × 4

A = 40 m²

Finally, we shall determine the force exerted on one side of the wall as follow:

Standard pressure (P) = 101325 Nm¯²

Area (A) = 40 m²

Pressure (P) = Force (F) /Area (A)

101325 = F/40

F = 101325 × 40

F = 4.05×10⁶ N.

Therefore, a force of 4.05×10⁶ N was exerted on one side of the wall.

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The range of the graph is the set of output values, and the range is (d) (-infinity,infinity)

From the graph in the complete question, we can see that the output values (i.e. the y values) extend indefinitely on both sides of the graph

This means that the range of the graph is the set of all real numbers.

This in other words means that (-infinity,infinity)

Hence, the range of the graph is (d) (-infinity,infinity)

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Answer:

x = 36.9°

Given:

opposite side: 9

adjacent side: 12

angle: x

Using tane rule:

[tex]\sf tan(x) = \dfrac{opposite}{adjacent}[/tex]

Solve:

[tex]\sf tan(x) = \dfrac{9}{12}[/tex]

[tex]\sf x = tan^{-1}(\dfrac{9}{12})[/tex]

[tex]\sf x = 36.87[/tex]

[tex]\sf x = 36.9[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

since the given triangle is an right angled triangle we can use Trigonometric ratios here :

[tex]\qquad \sf  \dashrightarrow \: \tan(x) = \dfrac{9}{12} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \tan(x) = \dfrac{3}{4} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x= tan { }^{ - 1} \bigg( \dfrac{3}{4} \bigg)[/tex]

[tex]\qquad \sf  \dashrightarrow \:x \approx37 \degree[/tex]

Answer:

1/8 of males as females are 7 times of males are x then females are 7x so the fraction of males x will be 1/8

Step-by-step explanation:

The time used for the first part of the trip in minutes is 270 minutes.

Total distance travelled = 675 km

He travelled from 1pm to 9pm.

He rested for 1 hour 30 minutes. The total time used for the trip is 6 hours 30 minutes.

let

the time used for the first part of the trip = x

Therefore,

speed = distance / time

distance = 110x

the time used for the first part of the trip = 6.5 - x

distance = 90(6.5 - x)

distance = 585 - 90x

Hence,

110x + 585 - 90x = 675

20x + 585 = 675

20x = 675 - 585

20x = 90

x  = 90 / 20

x = 4.5 hours = 270 minutes

Therefore, the time used for the first part of the trip is 270 minutes.

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Step-by-step explanation:

option D is correct answer

Answer:

C

Step-by-step explanation:

[tex]\text{Plug} ~(x,y) = ( 2,0)~ \text{in both equations.}\\\\3*0 = 2-2\implies 0=0\\\\0 = -2(2) +4 \implies 0=0\\\\\text{Hence x =2 and y =0.}[/tex]

Answer:

what?

Step-by-step explanation:

Answer:

please reformat the question to be readable !

Step-by-step explanation:

If it is enlarged by a scale factor of 2. Then the coordinates of the translated triangle will be (2, -2), (6, 0), and (2, -8).

Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered.

The coordinates of a triangle are (1,-1), (3,0), and (1,-4).

If it is enlarged by a scale factor of 2.

Then the coordinates of the translated triangle

(1,-1) → (2, -2)

(3,0) → (6, 0)

(1,-4) → (2, -8)

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Answer: D

Step-by-step explanation:

This is the only option that is a line.

Answer:

Show that if [tex]f(a) = f(b) = 0[/tex] for some [tex]a,\, b \in [-2,\, 2][/tex] where [tex]a \ne b[/tex], then by Rolle's Theorem [tex]f^{\prime}(x) = 0[/tex] for some [tex]x \in (-2,\, 2)[/tex]. However, no such [tex]x[/tex] exists since [tex]f^{\prime}(x) < 0[/tex] for all [tex]x \in (-2,\, 2)\![/tex].

Note that Rolle's Theorem alone does not give the exact value of the root. Neither does this theorem guarantee that a root exists in this interval.

Step-by-step explanation:

The function [tex]f(x) = x^{3} - 12\, x + 11[/tex] is continuous and differentiable over [tex][-2,\, 2][/tex]. By Rolle's Theorem. if [tex]f(a) = f(b)[/tex] for some [tex]a,\, b \in [2,\, -2][/tex] where [tex]a \ne b[/tex], then there would exist [tex]x \in (a,\, b)[/tex] such that [tex]f^{\prime}(x) = 0[/tex].

Assume by contradiction [tex]f(x)[/tex] does have more than one roots over [tex][-2,\, 2][/tex]. Let [tex]a[/tex] and [tex]b[/tex] be (two of the) roots, such that [tex]a \ne b[/tex]. Notice that [tex]f(a) = 0 = f(b)[/tex] just as Rolle's Theorem requires. Thus- by Rolle's Theorem- there would exist [tex]x \in (a,\, b)[/tex] such that [tex]f^{\prime}(x) = 0[/tex].

However, no such [tex]x \in (a,\, b)[/tex] could exist. Notice that [tex]f^{\prime}(x) = 3\, x^{2} - 12[/tex], which is a parabola opening upwards. The only zeros of [tex]f^{\prime}(x)[/tex] are [tex]x = (-2)[/tex] and [tex]x = 2[/tex].

However, neither [tex]x = (-2)[/tex] nor [tex]x = 2[/tex] are included in the open interval [tex](-2,\, 2)[/tex]. Additionally, [tex]a,\, b \in [-2,\, 2][/tex], meaning that [tex](a,\, b)[/tex] is a subset of the open interval [tex](-2,\, 2)[/tex]. Thus, neither zero would be in the subset [tex](a,\, b)[/tex]. In other words, there is no [tex]x \in (a,\, b)[/tex] such that [tex]f^{\prime}(x) = 0[/tex]. Contradiction.

Hence, [tex]f(x) = x^{3} - 12\, x + 11[/tex] has at most one root over the interval [tex][-2,\, 2][/tex].

Answer: 10

Step-by-step explanation:

Opposite sides of a parallelogram are congruent, so the sum of the lengths of each pair of adjacent sides must be 5. Thus, the perimeter is 5(2)=10.