answer questions 2-20 please 1 and 5-7 are already answered no need to correct them does not need to be correct but please have relistic answers : )

The system of equations to represent the scenario is 1.73x + 3.38y ≤ 28,

and the ordered pair is (8,4).

What is the Linear equation?

A linear equation is an algebraic equation that represents a straight line on a coordinate plane. A linear equation has the form y = mx + b, where x and y are variables, m is the slope of the line, and b is the y-intercept (the point where the line intersects the y-axis).

What is a system of equations?

A system of equations is a set of two or more equations that involve the same variables. In a system of equations, the solution is a set of values for the variables that satisfy all the equations in the system simultaneously. For example, the system of equations:

2x + 3y = 7

x - 2y = 5

has two equations with two variables x and y. The solution to the system is the set of values for x and y that satisfy both equations simultaneously.

According to the given information:

Part 1:

We are given that Apple needs 12 ounces of the stir fry mix, which is made up of rice and dehydrated veggies. Let x be the amount of rice in ounces and y be the amount of dehydrated veggies in ounces.

The total amount of stir fry mix needed is 12 ounces, so we have:

x + y = 12

The cost of the rice is $1.73 per ounce and the cost of the dehydrated veggies is $3.38 per ounce. Apple has $28 to spend and plans to spend it all, so the cost of the stir fry mix must be less than or equal to $28:

1.73x + 3.38y ≤ 28

Part 2:

To solve the system of equations, we can use substitution or elimination. Here, we will use substitution to solve for one variable in terms of the other:

x + y = 12 --> y = 12 - x

Substituting y = 12 - x into the second equation, we get:

1.73x + 3.38(12 - x) ≤ 28

Simplifying and solving for x, we get:

1.73x + 40.56 - 3.38x ≤ 28

-1.65x ≤ -12.56

x ≥ 7.616

We round up to the nearest whole number since we cannot buy a fraction of an ounce of rice. Thus, x = 8 ounces.

Substituting x = 8 into the equation y = 12 - x, we get:

y = 12 - 8

y = 4 ounces

Therefore, Apple buys 8 ounces of rice and 4 ounces of dehydrated veggies. The ordered pair is (8,4).

Part 3:

Our solution (8, 4) means that Apple needs to buy 8 ounces of rice and 4 ounces of dehydrated veggies to make 12 ounces of stir fry mix. The cost of the stir fry mix can be calculated by substituting these values into the cost equation:

1.73(8) + 3.38(4) = $21.48

Since this is less than or equal to the $28 that Apple has to spend, they can afford to buy the necessary ingredients to make the stir fry mix.

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Interpretation:

The regression coefficient b = 16.6 represents the change in the predicted ozone level (in parts per million) for each additional million people in the population.

Specifically, for each additional million people, the predicted ozone level is expected to increase by 16.6 parts per million.

For Rascoville, a city with a population of 3 million people, we can use the estimated regression equation to predict the average ozone level:

ozone⌢ = 8.89 + 16.6 × 3 = 8.89 + 49.8 = 58.69

Therefore, the predicted average ozone level for Rascoville is 58.69 parts per million.

If the ozone level is approximately 142 ppm, we can use the estimated regression equation to estimate the population:

142 = 8.89 + 16.6 × population

Solving for population, we get:

133.11 = 16.6 × population

population ≈ 8.02 million

Therefore, the approximate population of the city is 8 million people (rounded to the nearest million).

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270 students in a seventh-grade class of 450 would have a cell phone which denotes three-fifths of seventh graders using fractions.

Total number of students = 450

Percent of students who have cell phones = 3/5 th

In a class, if there are three-fifths of students have cell phones, that means we need to calculate the remaining percent of students who did not have cell phones.

Students without cell phones = 1 - 3/5 = 2/5

The total number of students with cell phones = (3/5) x 450

The total number of students with cell phones = 270

Therefore, we can conlcude that 270 students in a seventh-grade class of 450 would have a cell phone.

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Answer:

Kerry could give her the range or the standard deviation of the data set.

Step-by-step explanation:

Coach Loren wants one number to describe how all of the values in the data set vary, so Kerry should tell her to use a measure of variability.

Kerry could give her the range or the standard deviation of the data set.

The image coordinates of N′M′O′ if the preimage is translated 7 units to the left is D- N′(−11, −2), M′(−8, −1), O′ (−11, −5)

A triangle is seen as a closed, two-dimensional geometric figure that has three straight sides and three angles.

To get the image coordinates of the preimage translated 7 units to the left, we simply subtract 7 from the x-coordinates of each vertex:

N' = (Nx - 7, Ny) = (−4 - 7, −2) = (−11, −2)

M' = (Mx - 7, My) = (−1 - 7, −1) = (−8, −1)

O' = (Ox - 7, Oy) = (−4 - 7, −5) = (−11, −5)

Therefore, the image coordinates of NMO after the translation 7 are: N′(−11, −2), M′(−8, −1), O′ (−11, −5)

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The distance between the factories is approximately 1704 meters.

To solve this problem, we can use the Law of Cosines. Let's denote the distance between the man and Factory 1 as x, the distance between the man and Factory 2 as y, and the distance between the factories as z.

Given that the time difference for the man to hear the blasts from Factory 1 and Factory 2 is 4.2 seconds and 5.9 seconds respectively, we can calculate x and y using the speed of sound (344 m/s):

x = 4.2 seconds * 344 m/s = 1444.8 meters
y = 5.9 seconds * 344 m/s = 2030.4 meters

Now, we apply the Law of Cosines using the given angle of 40.8°:

z² = x² + y² - 2xy * cos(40.8°)
z² = 1444.8² + 2030.4² - 2(1444.8)(2030.4) * cos(40.8°)
z² ≈ 2904106.33

Take the square root to find the distance between the factories:

z ≈ √2904106.33 ≈ 1704.14 meters

Rounded to the nearest meter, the distance between the factories is approximately 1704 meters. However, this answer is not included in the given options. There might be an error in the question or the provided options.

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By observing the given protractor we know that option (C) is correct which says ∠NOP = ∠ROS.

An instrument for measuring angles is a protractor, which is often made of transparent plastic or glass.

Protractors might be straightforward half-discs or complete circles. Protractors with more complex features, like the bevel protractor, include one or two swinging arms that can be used to measure angles.

To draw arcs or circles, use a compass.

To measure angles, one uses a protractor.

So, we need to observe the given image of the protractor:
We will easily find that ∠NOP = ∠ROS

Therefore, by observing the given protractor we know that option (C) is correct which says ∠NOP = ∠ROS.

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The length of the diagonal of a wide screen TV with an area of 150 inches and an aspect ratio of 2.39:1 is approximately 11.25 inches.

Aspect ratio refers to the proportional relationship between the width and height of an image or screen. In the case of a wide screen TV, the aspect ratio is 2.39:1, which means that for every 2.39 units of width, there is 1 unit of height.

To find the length of the diagonal of a wide screen TV with an area of 150 inches, we need to use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the width and height.

First, we need to find the width and height of the TV screen. We can do this by setting up the equation:

2.39x^2 = 150

where x is the width of the screen. Solving for x, we get:

x = √(150/2.39) = 10.87 inches

Now we can find the height by dividing the width by the aspect ratio:

h = 10.87 / 2.39 = 4.55 inches

Using the Pythagorean theorem, we can find the length of the diagonal:

d^2 = 10.87^2 + 4.55^2 = 126.68

d = √126.68 = 11.25 inches

Therefore, the length of the diagonal of a wide screen TV with an area of 150 inches and an aspect ratio of 2.39:1 is approximately 11.25 inches.

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The volume of the cone is approximately 26.1 cubic inches.

The formula used to calculate the volume of a cone is:

V = (1/3) × π ×[tex]r^2[/tex] × h

where V is the volume of the cone, r is the radius of the base of the cone, h is the height of the cone, and π is a mathematical constant that is approximately equal to 3.14.

Part b. Plugging in the given values, we get:

V = (1/3) × 3.14 ×[tex]2.5^2[/tex]× 4.2

V = (1/3) × 3.14 × 6.25 × 4.2

V = 26.125 cubic inches (rounded to the nearest tenth)

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Answer: 72

Step-by-step explanation:

Q is same as M = 72

N=36

L=x

All 3 angles of a triangle add to 180

72+36+x=180

x=72

The statement that best describes how pollination begins is that it starts when pollen from the male reproductive organ of a flower is transferred to the female reproductive organ of the same or a different flower. Pollination is an essential step in the reproduction of plants, and it allows for the exchange of genetic material between different plants.

Pollination can occur through various methods, including wind, water, and animals such as bees, butterflies, and birds. Once the pollen is transferred, it begins to grow and develop, ultimately leading to the formation of a seed and the growth of a new plant.

Pollination is vital to the continuation of plant life, and without it, many plant species would not be able to survive. It is essential for plant breeders to understand the pollination process, as they can use it to cross different plant varieties and produce new and improved plants.

In conclusion, pollination begins when pollen from the male reproductive organ of a flower is transferred to the female reproductive organ of the same or a different flower, allowing for the exchange of genetic material and the growth and development of new plants.

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The approximate surface area of the glass prism is approximately 1986.66 square millimeters.

To find the surface area of the glass prism, we need to determine the area of each of its faces and then add them together. The prism consists of two congruent equilateral triangles and three rectangular faces.

The area of an equilateral triangle with side length s and height h is given by:

A = (√(3)/4) * s²

Using this formula, we can find the area of each of the two equilateral triangles in the prism:

A = (√(3)/4) * 7² ≈ 21.22 mm²

Next, we need to find the area of each of the three rectangular faces. The length of each rectangular face is equal to the side length of the equilateral triangle (7 mm), and the height is equal to the length of the prism (93 mm). Therefore, the area of each rectangular face is:

A = length x height = 7 mm x 93 mm = 651 mm²

To find the total surface area of the prism, we add the areas of the two equilateral triangles and the three rectangular faces:

Total surface area ≈ 2 x 21.22 mm² + 3 x 651 mm² ≈ 1986.66 mm²

Therefore, the approximate surface area of the glass prism is approximately 1986.66 square millimeters.

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The gardener used 36.9 gallons of gasoline in the lawnmowers in that month.

In mathematics, a proportion is a statement that two ratios are equal. It expresses the relationship between two or more quantities that are directly proportional to each other. A proportion can be represented as an equation of the form:

a/b = c/d

We know that the gardener used a total of 61.5 gallons of gasoline in a month and that 3/5 of that total was used in the lawnmowers.

To find out how much gasoline the gardener used in the lawnmowers, we need to multiply the total amount of gasoline by 3/5:

61.5 gallons x 3/5 = 36.9 gallons

Therefore, the gardener used 36.9 gallons of gasoline in the lawnmowers in that month.

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The length of segment C'D' is given as follows:

C'D' = 2.

A dilation can be defined as a transformation that multiplies the distance between every point in an object and a fixed point, called the center of dilation, by a constant factor called the scale factor.

The length of segment CD is given as follows:

CD = 4. (4 vertical units of difference).

The scale factor is given as follows:

k = 1/2.

Hence the length of segment C'D' is given as follows:

C'D' = 1/2 x 4 = 2.

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The partial derivative using implicit differentiation is:

[tex]dz/dy = (-7x * e^(7xy) * (dx/dy) - 4) / (5x * cos(5xz))[/tex]

To calculate the partial derivative of the given equation with respect to y (dz/dy), we'll use implicit differentiation. The given equation is:

[tex]e^(7xy) + sin(5xz) + 4y = 0[/tex]

First, differentiate both sides of the equation with respect to y:

[tex]d(e^(7xy))/dy + d(sin(5xz))/dy + d(4y)/dy = 0[/tex]

Apply the chain rule for the first and second terms:

[tex](7x * e^(7xy)) * (dx/dy) + (5x * cos(5xz)) * (dz/dy) + 4 = 0[/tex]
Now, we are interested in finding dz/dy. To solve for it, rearrange the equation:

[tex](5x * cos(5xz)) * (dz/dy) = -7x * e^(7xy) * (dx/dy) - 4Finally, divide by (5x * cos(5xz)) to isolate dz/dy:dz/dy = (-7x * e^(7xy) * (dx/dy) - 4) / (5x * cos(5xz))[/tex]

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Answer:

[tex]x^2+\left(y+\dfrac{1}{2}\right)^2=\dfrac{49}{4}[/tex]

Step-by-step explanation:

The center of the circle is the midpoint of its diameter.

[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Midpoint between two points}\\\\Midpoint $=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)$\\\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are the endpoints.\\\end{minipage}}[/tex]

Given the endpoints of the diameter are (0, 3) and (0, -4), to find the coordinates of the center of the circle, substitute the two endpoints into the midpoint formula:

[tex]\text{Center}=\left(\dfrac{0+0}{2},\dfrac{-4+3}{2}\right)=\left(0,-\dfrac{1}{2}\right)[/tex]

As the x-values of the endpoints of the diameter are the same, the length of the diameter, d, is the absolute value of the difference in y-values of the endpoints:

[tex]d=|3-(-4)|=7[/tex]

Therefore, the diameter of circle Q is 7 units.

The radius, r, of a circle is half its diameter. Therefore:

[tex]r=\dfrac{d}{2}=\dfrac{7}{2}[/tex]

[tex]\boxed{\begin{minipage}{4 cm}\underline{Equation of a circle}\\\\$(x-h)^2+(y-k)^2=r^2$\\\\where:\\ \phantom{ww}$\bullet$ $(h,k)$ is the center. \\ \phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}[/tex]

Now we have determined the center and radius of circle Q, we can substitute these values into the equation of a circle to write the equation of circle Q in standard form:

[tex](x-0)^2+\left(y-\left(-\dfrac{1}{2}\right)\right)^2=\left(\dfrac{7}{2}\right)^2[/tex]

[tex]x^2+\left(y+\dfrac{1}{2}\right)^2=\dfrac{49}{4}[/tex]

Therefore, the equation of circle Q in standard form is:

[tex]\boxed{x^2+\left(y+\dfrac{1}{2}\right)^2=\dfrac{49}{4}}[/tex]

1. The area of square C is 625 ft². 2. The perimeter of square C is 46 ft. 3. The area of square B is 1456 ft². 4. The length of square A is 4√15 ft.

A key idea in geometry that connects the lengths of a right triangle's sides is known as the Pythagorean Theorem. It says that the hypotenuse's square length, which is the side that faces the right angle, is equal to the sum of the squares of the lengths of the other two sides in a right triangle. It has the following mathematical expression:

a² + b² = c²

1. The area of square C can be found using the Pythagorean Theorem:

a² + b² = c²

Using the area the side is calculates as follows:

Side length of A = √225 = 15 ft

Side length of B = √400 = 20 ft

Now,

15² + 20² = c²

225 + 400 = c²

625 = c²

c = √625 = 25 ft

So the area of square C is:

Area of C = 25² = 625 ft²

2. The perimeter of square C can be found by adding up the side lengths of all three squares:

Perimeter of A = 36 ft, so each side length of A is 9 ft.

Perimeter of B = 48 ft, so each side length of B is 12 ft.

Perimeter of C = Side length of A + Side length of B + Side length of C

Perimeter of C = 9 + 12 + c

We found earlier that c = 25 ft, so we can substitute that in:

Perimeter of C = 9 + 12 + 25 = 46 ft

3. The area of square B can be found using the fact that the areas of squares A, B, and C are related by the equation:

Area of A + Area of B = Area of C

We know the area of A and the area of C, so we can solve for the area of B:

Area of A = 15² = 225 ft²

Area of C = 1681 ft²

Area of A + Area of B = Area of C

225 + Area of B = 1681

Area of B = 1456 ft²

4. Perimeter of B = 64 ft

Side length of B = 64 / 4 = 16 ft

Now we can use the Pythagorean Theorem to find the side length of C:

a² + b² = c²

a = 15 ft (side length of A)

b = 16 ft (side length of B)

c = √(a² + b²) = √(15² + 16²) = √481 = 22 ft

Finally, we can use the Pythagorean Theorem again to find the side length of A:

a² + b² = c²

b = 16 ft (side length of B)

c = 22 ft (side length of C)

a = √(c² - b²) = √(22² - 16²) = √240 = 4√15 ft

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The quantity of heat which must be removed from the system in order to reduce the pressure from 2 bar to 1.6 bar is 4.23 kJ. The change in enthalpy per unit mass of the system is -123 kJ/kg, and the change in entropy per unit mass of the system is 0.134 kJ/kg-K.

To solve this problem, we need to use the steam tables to determine the properties of the steam at the initial and final conditions. We will assume that the system is undergoing a reversible, adiabatic process, so there is no heat transfer into or out of the system.

First, we determine the specific volume and enthalpy of the steam at the initial conditions of 2 bar and 0.9 dryness fraction. From the steam tables, we find that the specific volume is 0.4019 m^3/kg and the specific enthalpy is 2895.5 kJ/kg.

Next, we use the steam tables to find the specific volume and enthalpy of the steam at the final conditions of 1.6 bar. We find that the specific volume is 0.5059 m^3/kg and the specific enthalpy is 2772.5 kJ/kg.

The change in specific enthalpy per unit mass of the system is then given by:

Δh = h2 - h1 = 2772.5 - 2895.5 = -123 kJ/kg

The change in specific entropy per unit mass of the system is given by:

Δs = s2 - s1 = s2 - s1 = s2 - sf - x2*(sg - sf)

where sf and sg are the specific entropy of saturated liquid and saturated vapor at the final pressure of 1.6 bar, and x2 is the final dryness fraction. From the steam tables, we find that sf = 7.4332 kJ/kg-K, sg = 8.1248 kJ/kg-K, and x2 = 0.714.

Thus, we have:

Δs = s2 - s1 = s2 - sf - x2*(sg - sf) = (7.9757 - 7.4332) - 0.714*(8.1248 - 7.4332) = 0.134 kJ/kg-K

Finally, we can calculate the quantity of heat that must be removed from the system using the first law of thermodynamics:

Q = m*(h1 - h2) = m*Δh

where m is the mass of the steam in the system. To determine the mass of the steam, we use the specific volume at the initial conditions:

V = m/v1

where V is the volume of the system and v1 is the specific volume at the initial conditions. Substituting the given values, we have:

V = 85 L = 0.085 [tex]m^3[/tex]

m = Vv1 = 0.0850.4019 = 0.0344 kg

Substituting this value into the equation for Q, we obtain:

Q = mΔh = 0.0344(-123) = -4.23 kJ

Therefore, the quantity of heat which must be removed from the system in order to reduce the pressure from 2 bar to 1.6 bar is 4.23 kJ.

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The algebraic expression is equivalent to the expression is 125/4x + 34. Option B

Algebraic expressions are simply defined as expressions that are composed of terms, variables, constants, coefficients and factors.

These algebraic expressions are also composed of mathematical operations, such as;

From the information given, we have;

25/4(5x-4/5)+29

expand the bracket, we get;

125x - 100/5 + 29

Find the LCM, we get;

125x - 100 + 145/5

Divide the values

125/4x + 34

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Answer:

Let heads represent a person who exercises the given amount, and let tails represent a person who doesn’t. Because there are three people, flip the coin three times (once for each person) and note the results of each set of three flips. If all three flips land on tails, it would mean that all three randomly selected people do not exercise as much as 50% of Americans do.

Step-by-step explanation:

Answer:

[tex]20,000 \text{ kWh}[/tex]

Step-by-step explanation:

We can convert 68 million British Thermal Units (BTUs) to kilowatt-hours (kWh) using the given conversion ratio:

[tex]\dfrac{1 \text{ kWh}}{3400 \text{ BTUs}}[/tex]

Multiplying by the ratio:

[tex]68,000,000 \text{ BTUs} \cdot \dfrac{1 \text{ kWh}}{3,400 \text{ BTUs}}[/tex]

↓ canceling the BTU units

[tex]68,000,000\cdot \dfrac{1 \text{ kWh}}{3,400}[/tex]

↓ executing multiplication

[tex]\dfrac{68,000,000}{3,400} \text{ kWh}[/tex]

↓ rewriting as a decimal

[tex]\boxed{20,000 \text{ kWh}}[/tex]

The margin of error at the 99% confidence interval is 0.018 or 1.8%.

Interpretation: This means that if we were to repeat the survey many times, about 99% of the intervals calculated from the samples would contain the true proportion of viewers under 30 in the population, and the margin of error for each interval would be no more than 1.8%.

The margin of error is the amount by which the sample statistic (in this case, the proportion of viewers under 30) may differ from the true population parameter.

Using the given formula for margin of error:

Margin of error = z* * sqrt(p*(1-p)/n)

Where:

- z* is the z-score corresponding to the confidence level (99% in this case), which is 2.576

- p is the proportion of viewers under 30, which is 0.3

- n is the sample size, which is 5000

Substituting these values, we get:

Margin of error = 2.576 * sqrt(0.3*(1-0.3)/5000) = 0.018

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The value of given function [tex]\int\limits^1_{-1}[/tex]f(x)dx is equal is 5/6. So, correct option is A.

To find the integral of f(x) from -1 to 1, we need to split the interval [-1,1] into three parts, where f(x) is defined differently.

For x < 0, f(x) = x², so the integral of f(x) from -1 to 0 is:

[tex]\int\limits^0_{-1}[/tex](x²)dx = (-1/3)x³ evaluated at x=0 and x=-1 = (-1/3)(0 - (-1)) = 1/3

For x = 0, f(x) = -1, so the integral of f(x) at x=0 is simply -1.

For x > 0, f(x) = x, so the integral of f(x) from 0 to 1 is:

[tex]\int\limits^1_{0}[/tex](x)dx = (1/2)x² evaluated at x=1 and x=0 = (1/2)(1 - 0)² = 1/2

Therefore, the integral of f(x) from -1 to 1 is:

[tex]\int\limits^1_{-1}[/tex]f(x)dx = [tex]\int\limits^0_{-1}[/tex](x²)dx  + [tex]\int\limits^0_{0}[/tex](-1)dx + [tex]\int\limits^1_{0}[/tex](x)dx

= 1/3 + (-1) + 1/2

= 5/6

Thus, the correct answer is (a) 5/6.

So, correct option is A.

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Answer:

x = 58°

Step-by-step explanation:

Label the point where the diagonals cross as T

Diagonals always meet at right angles

m∠SRT = 32

Sum of interior angles of ΔSRT = 180

x = 180 - 90 - 32 = 58

Answer:

To solve this problem, we need to find an integer to multiply the first equation by so that when we add the two equations together, the x term is eliminated. Let's first rearrange the equations to make them easier to work with:

1/18 x + 4/5 y = 10

-5/6 x - 3/4 y = 3

To eliminate the x term, we need to multiply the first equation by a certain integer so that when we add it to the second equation, the x terms cancel out. To do this, we need to find a common multiple of the denominators of the x coefficients in both equations, which are 18 and -6. The least common multiple of 18 and -6 is 18, so we can multiply the first equation by 18:

18(1/18 x + 4/5 y = 10)

Simplifying this equation, we get:

x + 72/5 y = 180

Now we can add this equation to the second equation:

x + 72/5 y = 180

-5/6 x - 3/4 y = 3

Multiplying the second equation by 15 to get rid of the fractions, we get:

-25/2 x - 45/4 y = 45

Now we can add the two equations together to eliminate the x term:

-25/2 x + x + 72/5 y - 45/4 y = 180 + 45

Simplifying this equation, we get:

-13/20 y = 225/4

Multiplying both sides by -20/13, we get:

y = -450/13

Therefore, the integer we need to multiply the first equation by is 18, which corresponds to option B.

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Answer:

-7x^2 + 15x +7

Step-by-step explanation:

-7x^2 + 5x + 10 - (-10x + 3)

-7x^2 + 5x + 10 + 10x -3.......when u distribute it multiple by -1

-7x^2 + 15x +7 ...... simplify by collecting like term.

If tan theta < 0 and sec theta > 0, the terminal side of theta could lie in either the second quadrant or the fourth quadrant.

If csc theta > 0, the terminal side of theta could lie in either the first quadrant or the second quadrant.

If sin theta < 0 and cot theta < 0, the terminal side of theta could lie in either the third quadrant or the fourth quadrant.

1. If tan theta < 0 and sec theta > 0, the terminal side of theta could lie in either the second quadrant or the fourth quadrant. This is because tan theta is negative in the second and fourth quadrants, and sec theta is positive in the first and fourth quadrants.

2. If csc theta > 0, the terminal side of theta could lie in either the first quadrant or the second quadrant. This is because csc theta is positive in the first and second quadrants.

3. If sin theta < 0 and cot theta < 0, the terminal side of theta could lie in either the third quadrant or the fourth quadrant. This is because sin theta is negative in the third and fourth quadrants, and cot theta is negative in the second and third quadrants.

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If a white dwarf in a binary star system gains mass beyond the Chandrasekhar limit (approximately 1.4 solar masses), it undergoes a runaway nuclear reaction, causing it to collapse and explode in a Type Ia supernova.

A white dwarf is a dense stellar remnant that is left behind after a star has exhausted all its nuclear fuel and has shed its outer layers. In a binary star system, the white dwarf may gain mass from its companion star, either through accretion or a merger. If the mass of the white dwarf exceeds the Chandrasekhar limit, the gravitational forces become so strong that the electrons in the atoms are forced to combine with the atomic nuclei, forming neutrons. This process is called electron capture, and it releases a tremendous amount of energy.

The energy released is enough to ignite a runaway nuclear reaction, causing the white dwarf to collapse and explode in a Type Ia supernova. Type Ia supernovae are important cosmic events because they are used as standard candles to measure the distance to distant galaxies. These explosions are also believed to play a significant role in the chemical evolution of the universe, as they produce heavy elements such as iron and nickel that are scattered into the interstellar medium.

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The gradient of line A and B are 4 and - 2 respectively.

The gradient or slope of a line is a the change in the dependent variable with respect to the change in the independent variable.

Therefore, let's find the gradient of line a and b as follows:

(2, -1)(3, 3)

Gradient  of line A = 3 + 1 / 3 - 2

Gradient  of line A = 4 / 1

Gradient  of line A = 4

Therefore,

(0, 1)(1, -1)

Gradient  of line B = -1 - 1 / 1 - 0

Gradient  of line B =  - 2 / 1

Gradient  of line B = - 2

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La fórmula para calcular el área de un triángulo es:

área = base * altura / 2

Podemos despejar la altura de esta fórmula y sustituir los valores que conocemos:

área * 2 / base = altura

1.5 * 2 / 1.5 = 2

Por lo tanto, la altura del triángulo es de 2 metros.