An ideal heat engine operates between 778 K and 475 K. 267 J of waste heat is exhausted. What is the input heat?

Answers

Answer 1

Answer:

Explanation:

Suppose that the turbines of a coal-fired plant are driven by hot gases at a temperature of 886 K. the temperature of the exhaust area is only 305 K,  the efficiency of this heat engine


Related Questions

Which of the following is a disadvantage of using solar energy

Answers

Please provide options.

Answer:

It requires a high initial investment

Explanation:

How are decompression and how gasses dissolve in liquids related? Explain in your own words.

Answers

In decompression theory the solubility of gases in liquids is of primary importance, as it is the formation of bubbles from these gases that causes decompression sickness. ... Temperature (gases are less soluble in water but may be more soluble in organic solvents, at higher temperatures.)
Because they are like if you think true

2. Write an expression for the work
done when a force is acting on
an object in the direction of its
displacement​

Answers

Answer:

work  done=Fs

Explanation:

F : force

s : displacement

by definition

what is the effect of divorce on females?​

Answers

Answer:

Numerous studies have shown that the economic costs of divorce fall more heavily on women. After separation, women experience a sharper decline in household income and a greater poverty risk (Smock 1994; Smock and Manning

Answer:

sadness and stress...................

If you were to stand in the exact center of a rotating disc, you would only have what kind of
speed?
Tangential speed
Increasing speed
Linear speed
Rotational speed

Answers

Answer:

Tangential speed or Rotational speed

which simple machines make up a wheel barrow

Answers

Answer:

a lever and a wheel and axle (i guess)

Explanation:

don't have any

Transduction is:
A. sending information to the central nervous system.
B. turning energy into nerve impulses.
C. the process of seeing and hearing.
D. transferring information

Answers

Transferring information

Answer:

D

Explanation:

the answer is d because process of genetic recombination in bacteria in which genes from a host cell (a bacterium) are incorporated into the genome of a bacterial virus (bacteriophage) and then carried to another host cell when the bacteriophage initiates another cycle of infection

How does Physics help you as a student?

Answers

Answer:

The goal of physics is to understand how things work from first principles. ... Courses in physics reveal the mathematical beauty of the universe at scales ranging from subatomic to cosmological. Studying physics strengthens quantitative reasoning and problem solving skills that are valuable in areas beyond physics

Answer:

you get to understand why things happen this way

Explanation:

for example, are you not curious about why when standing in the bus and when the bus stops, you will might feel like you are going to fall ,

why does this happen because....

newton's laws explains it,

inertia causes you to be reluctant to change your initial state of motion due to your mass so you fall because you are still moving at the 'speed of the bus ' , something in like that

hope this helps,

please mark also

pdf
Due date: February 22, 2021
10:00 AM EST
5: Holt SF 05Rev 43 - 10.0 pts possible
A 0.290 kg block on a vertical spring with a
spring constant of 4.65 x 103 N/m is pushed
downward, compressing the spring 0.0500 m.
When released, the block leaves the spring
and travels upward vertically.
The acceleration of gravity is 9.81 m/s.
How high does it rise above the point of
release?
Answer in units of m.
x x

Answers

Mass of block(m)=0.290 kg
Spring Constant k = 4.65×10³ N/m
Initial elongation =0.0500 m=5 cm

Thus Initial Potential Energy stored =Final Potential Energy stored in Block


Pi = kx² / 2

Pi = (4.65×10³) (25×10−⁴) / 2

Pi = 5.81 J

Pf = m g h

Pf = (0.290) (9.81) (h)

Pi = Pf

5.81 = 0.29×9.81×h

h = 2.04 m

A 30.0 uC charge is moved 5.00 m West in an electric field of 4000 V/m pointing 40.0° North of East. What potential difference did the charge move through?

Answers

Answer:

20000sin(40) V

Explanation:

Consider component to the east of electric field:

[tex]E_{x} =4000 sin(40)[/tex]

The charge move along this component for 5 meter

Potential difference:

[tex]5E_{x} =20000sin(40)[/tex] = 12900 V (corr, to 3 sig,fig.)

The potential difference through which the charge moved is approximately 20.0 V.

To calculate the potential difference (ΔV) through which the charge moved, we can use the formula:

ΔV = q * E * d * cos(θ)

where:

q = charge = 30.0 uC = 30.0 x 10⁻⁶ C (converted to coulombs)

E = electric field = 4000 V/m

d = displacement = 5.00 m

θ = angle between the electric field and the displacement = 40.0°

Now, substitute the values into the formula:

ΔV = (30.0 x 10⁻⁶ C) * (4000 V/m) * (5.00 m) * cos(40.0°)

First, convert the angle to radians:

θ_radians = 40.0° * (π/180) ≈ 0.6981 radians

Now, calculate ΔV:

ΔV = (30.0 x 10⁻⁶ C) * (4000 V/m) * (5.00 m) * cos(0.6981) ≈ 0.02 V

So, the potential difference through which the charge moved is approximately 20.0 V.

To learn more about potential difference, here

https://brainly.com/question/23716417

#SPJ2

what's the dimension symbol for amount of substance​

Answers

Answer:

The mole (symbol: mol) is the unit of measurement for amount of substance in the International System of Units (SI). It is defined as exactly 6.022 140 76 × 1023 particles, which may be atoms, molecules, ions, or electrons.

Explanation:

Will mark BRAINLYEST

Answers

Answer:

A dribble ends when the player touches the ball with both hands simultaneously or permits the ball to come to rest in one or both hands. The ball being touched with both hands simultaneously (dribble with both hands) is a double dribble

Nothing in the rulebook that says a player cannot start a dribble with two hands. A dribble can end when touching both hands simultaneously, but a single dribble is OK as long as you catch the ball

Explanation:

Answer:

No, so it's false you're correct.

Hope this helped

.You have always been impressed by the speed of the elevators in your apartment building. You wonder about the maximum acceleration for these elevators during normal operation, so you decide to measure it by using your bathroom scale. While the elevator is at rest on the ground floor,you get in, put down your scale, and stand on it. The scale reads 50 kg. You continue standing on the scale when the elevator goes up, carefully watching the reading. During the trip to the 10th floor, the greatest scale reading was

Answers

Answer:

5.51 m/s^2

Explanation:

Initial scale reading = 50 kg  

assume the greatest scale reading = 78.09 kg

Determine the maximum acceleration for these elevators

At rest the weight is = 50 kg

Weight ( F ) = mg = 50 * 9.81 = 490.5 N

At the 10th floor weight = 78.09 kg

Weight at 10th floor ( F ) = 78.09 * 9.81 = 766.11 N

F = change in weight

Change in weight( F ) = ma = 766.11 - 490.5 (we will take the mass as the starting mass as that mass is calculated when the body is at rest)

50 * a = 275.61

Hence the maximum acceleration ( a ) = 275.61 / 50 = 5.51 m/s^2

3. 20P. The potential energy of a two particles is given by

Answers

Explanation:

The potential energy of two particles system will be given by the negative of work by gravitational force due to particle (1)as the second particle is brought from infinity : Gravitational potential energy Second particle is brought in the gravitation of first particle.

Force = mass X acceleration. Acceleration due to gravity is 9.8 m/s/s regardless of height or mass. This means a single object will hit the ground with the same force regardless of the height it is dropped from. If this is true, I normally drop a pumpkin from different heights during this unit. why does dropping the pumpkin stay together when dropped from one meter but break apart when dropped from a height of 5 meters?

Answers

1 yaa I now homar and dog ririnebjeildnbbd

Albert's laboratory is filled with a constant uniform magnetic field pointing up everywhere. Into this magnetic field albert throws some charges. He throws the charges in different directions, and observes the resulting magnetic forces on them. Given the sign of each charge and the direction of its velocity, determine the direction of the magnetic force (if any) acting on the charge.
Resulting magnetic force:
Positive charge moving south:
Negative charge moving west:
Negative charge not moving at all:
Positive charge moving up:
Positive charge moving east:
Negatve charge moving down:
Negative charge moving north:
Positive charge not moving at all:
Positive charge moving west:
Negative charge moving south:
Negative charge moving east:
Positive charge moving north:
options: up, down, no force, north, south, east, west

Answers

Answer:

Follows are the solution to this question:

Explanation:

The magnetic force is parallel to a  [tex]\bar{V} \times \bar{B}[/tex] axis, through right law. The direction would be in a reverse way for a positive particle. The gravitational flux is upward.

1) Its magnet strength will be directed westward.

2) The [tex]\bar{V} \times \bar{B}[/tex] path is parallel to the east. The permanent magnet is oriented against the south so because the object is considered impolite.

3) Its gravitational field of the velocity v of the object is zero. Thus no force was its solution.

4) The magnetic field and velocity are all on the same track. The magnetic strength is also zero. Consequently, the answer is no power.

5) Its gravitational field is to the south.

6) Its magnetic field, as well as the speed, are different. Which magnet strength is also zero. Consequently, no power is the answer.

7) Accessible in French only. The  [tex]\bar{V} \times \bar{B}[/tex] direction parallel to the east. Its magnetic energy is guided west because the particle is charged negatively.

8) Unless the particle velocity is 0, the magnetic strength is 0. Consequentl, no power is the response.

9) Its magnet power is from the north.

10) Another one of these: The  [tex]\bar{V} \times \bar{B}[/tex]  is parallel to the west. Its gravitational field is oriented to the east as the object is negatively charged.

11) The Pope said the following: The [tex]\bar{V} \times \bar{B}[/tex]  direction is parallel to the south. The gravitational fluid is transmitted towards the North because a particle is considered impolite.

12) The gravitational field is from the east.

Messages from the Perseverance Rover on Mars reach Earth in 11 min. The speed of light is 3.00 x 108 m/s. Using this information, how far is Mars from Earth?

Answers

Answer:

[tex]d=1.98\times 10^{11}\ m[/tex]

Explanation:

Messages from the Perseverance Rover on Mars reach Earth in 11 min i.e. time is 660 s

The speed of light is [tex]3\times 10^8\ m/s[/tex]

We need to find the distance between Mars and Earth. Let the distance be d.

We know that,

Distance = speed × time

So,

[tex]d=660\times 3\times 10^8\\\\d=1.98\times 10^{11}\ m[/tex]

So, Mars is [tex]1.98\times 10^{11}\ m[/tex] from the Earth.

In SI units, what is the magnitude the net force acting on a 1,152 kg car that accelerates uniformly along a straight line from a speed of 3 m/s to a speed of 17 m/s in 5s?

Answers

Answer:

Fnet = 14515.2 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

[tex] Fnet = Fapp + Fg[/tex]

Where;

Fnet is the net force. Fapp is the applied force. Fg is the force due to gravitation.

Given the following data;

Mass = 1,152 kg

Initial velocity, u = 3m/s

Final velocity, v = 17m/s

Time, t = 5 seconds

To find the magnitude of the net force;

First of all, we would determine the acceleration of the car.

Acceleration = (v-u)/t

Acceleration = (17 - 3)/5

Acceleration = 14/5

Acceleration = 2.8m/s

To find the applied force;

Fapp = mass * acceleration

Fapp = 1,152 * 2.8

Fapp = 3225.6 N

Next, we would find the force exerted on the car due to gravity.

Fg = mass * acceleration due to gravity

We know that acceleration due to gravity is equal to 9.8m/s²

Fg = 1152 * 9.8

Fg = 11289.6N

Substituting the values into the equation, we have;

Fnet = 3225.6 + 11289.6

Fnet = 14515.2 Newton

An equipotential surface that surrounds a point charge q has a potential of 536 V and an area of 1.20 m2. Determine q.

Answers

Answer:

q = 1.84×10^-8coulombs

Explanation:

Surface area = 4πr²

r is the distance

1.2 = 4(3.14)r²

1.2 = 12.56r²

r² = 1.2/12.56

r² = 0.0956

r = √0.0956

r = 0.309m

Get the charge C

V = kq/r

536 = 9.0×10^9q/0.309

536×0.309 = 9×10^9q

165.73 = 9×10^9q.

q = 165.73/9×10^9

q = 1.84×10^-8coulombs

what is the average speed of a bird that flies 1 km in 5 hours?​

Answers

Answer:

0.25 or 1/4

Explanation:

................

An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the same instant. What was the initial speed of the second object? Neglect air resistance.

Answers

Answer:

Explanation:
Kinematics equation for first Object:

but:
The initial velocity is zero

it reach the water at in instant, t1, y(t)=0:


Kinematics equation for the second Object:
The initial velocity is zero

but:

it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s


The velocity is negative, because the object is thrown downwards

What is the magnitude of the electric field strength between them, if the potential 7.05 cm from the zero volt plate (and 2.95 cm from the other) is 293 V?

Answers

Answer:

E = 4156.02 Vm⁻¹

Explanation:

The magnitude of the uniform electric field between the plates can be given by the following formula:

[tex]E = \frac{\Delta V}{d}\\[/tex]

where,

E = Electric field strength = ?

ΔV = Potetial Difference = 293 V

d = distance between plates = 7.05 cm = 0.0705 m

Therefore,

[tex]E = \frac{293\ V}{0.0705\ m}\\\\[/tex]

E = 4156.02 Vm⁻¹

A man walks 40 m North, then 70 m East and then 40
m south. What is his displacement
from the starting point?​

Answers

Answer:

Displacement = 70 m towards east

Explanation:

Displacement is the shortest distance between the two points.

Let us say that he starts at the point O and travels in a path ABC.

If we join the initial and final point of the path travelled by him, it will give the displacement of the man.

Distance from O to A = 40 m

Distance from A to B = 70 m

Distance from B to C = 40 m

Distance from O to A = Distance from B to C

We want the displacement which is distance between the points O and C

In rectangle opposite sides are equal. Hence Distance from O to C = Distance from A to B

Displacement = Distance from A to B

Hope it helps,

Please mark me as the brainliest.

Thank you

Answer:

Displacement = 70 m towards east

Explanation:

microwaves are produced by ​

Answers

Answer:

Microwaves are basically extremely high frequency radio waves, and are made by various types of transmitter. In a mobile phone, they're made by a transmitter chip and an antenna, in a microwave oven they're made by a "magnetron". Their wavelength is usually a couple of centimetres. Stars also give off microwaves.

microwaves are produced by magnetron . They are produced inside a an electron tube called a magnetron .

In this unit, you learned about Athenian democracy and government in ancient Greece. What were some of the main characteristics of Athenian democracy? How is Athenian democracy similar to modern democracy? How is it different? Do you think Athenian democracy would be possible in the United States today? Why or why not?


(PLEASE HELP, WORTH 70 POINTS)

Answers

under this system all male citizens had equal political rights freedom of speech and the opportunity to participate directly in the political Arena

Answer:

Today, government in the United States is most similar to the Roman Republic because it is a representative democracy.

Although Athens is known as the world's first democracy, system that exist in United States today is most similar to Roman system.

Namely, Roman Republic was choosing its officials to represent them in the bodies such as Senate, which is also the case today with United States.

Explanation:

Pls help me I’m failing

Answers

Answer:

A is the answer okkkkkkkkkkkkkkkk

. A single strand of wire of adjustable length is wound around the circumference of a round balloon that has a diameter of 21.0 cm. A uniform magnetic field with a magnitude of 1.40 T is perpendicular to the plane of the loop. If the balloon is blown up such that its diameter and the diameter of the wire loop increase to 31.0 cm in 0.048s, what is the magnitude of the average value of the emf induced in the loop

Answers

Answer:

EMF = 1.1929 V

Explanation:

In this case we need to use the following expression:

EMF = B *ΔA / t   (1)

Where:

B: Magnetic field

ΔA: Difference of area of the balloon

t: time

To get the area, we have the innitial diameter of the balloon, and the expanded diameter when the balloon is blown up, so, assuming the circunference of the balloon, the area can be determined with:

A = π r²   (2)

So, let's calculate the Area of the balloon before and after the blown. Remember to use the units in meter (I just divided the diameter by 2 to get the ratio, and then divide by 100 to convert the units of cm to m)

A₁ = π * (0.105)² = 0.0346 m²

A₂ = π * (0.155)² = 0.0755 m²

Now that we have both areas, let's calculate ΔA:

ΔA = A₂ - A₁

ΔA = 0.0755 - 0.0346 = 0.0409 m²

Finally, we can determine the value of the EMF, using (1):

EMF = 1.4 * 0.0409 / 0.048

EMF = 1.1929 V

Hope this helps

The torque required to turn the crank on an ice cream maker is 4.50 Nm. How much work does it take to turn the crank through 300 full turns?
A) 4240 J
B) 8480 J
C) 2120 J
D) 1350 J
E) 2700 J

Answers

Answer:

B) 8480 J

Explanation:

From the question,

The work required to turn the Crank in on turn is

W = 2πT................ Equation 1

Where W = work, T = torque.

Given: T = 4.50 Nm, π = 3.14

Substitute into equation 1

W = 4.5(2)(3.14)

W = 28.26 J per turn.

For 300 full tern,

W = 28.26×300

W = 8476 J

Hence,

W≈ 8480 J.

The right answer is B) 8480 J

A piece of glass with index of refraction 1.50 is coated with a coating of thickness 138 nm and index of refraction 1.22. Light traveling perpendicular to the surface of the glass reflects at the interface between air and the coating, and at the interface between the coating and the glass. What is the largest vacuum wavelength for which the interference between the two reflected rays is completely destructive

Answers

Answer:

Explanation:

At both interface light is travelling from a medium of lower refractive index to medium of higher refractive index. So the phase difference of 180⁰ occurring  at both interface will cancel out .

Net path difference = 2 μ t where μ is refractive index of thin layer and t is its thickness

For destructive interference

2 μ t  = (2n + 1 )λ / 2 where λ is wavelength of light , n is any number

λ = 4  μ t / ( 2 n + 1 )

For largest wavelength , n = 0

λ = 4  μ t

= 4 x 1.22 x 138 nm

= 673.44 nm .

An automobile tire is filled to a gauge pressure of 200 kPa when its temperature is (Gauge pressure is the difference between the actual pressure and atmospheric pressure.) After the car has been driven at high speeds, the tire temperature increases to (a) Assuming that the volume of the tire does not change and that air behaves as an ideal gas, find the gauge pressure of the air in the tire. (b) Calculate the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent.

Answers

This question is incomplete, the complete question is;

An automobile tire is filled to a gauge pressure of 200 kPa when its temperature is 20°C (Gauge pressure is the difference between the actual pressure and atmospheric pressure.)

After the car has been driven at high speeds, the tire temperature increases to 55°C

(a) Assuming that the volume of the tire does not change and that air behaves as an ideal gas, find the gauge pressure of the air in the tire. (kPa)

(b) Calculate the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent. (kPa)

Answer:

a) the gauge pressure of the air in the tire is 236 kPa

b) the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent is 205.33 kPa

Explanation:

Given the data in the question;

Gauge pressure at 20°C = 200 kPa

Absolute pressure at 20°C is; p = 200 + 101.3 = 301.3 kPa

Initial temperature T = 20°C = 20 + 273 = 293 k

Final temperature T" = 55°C = 55 + 273 = 328 K

Now, at constant volume, P"/P = T"/T  

P"T = PT"

P" = PT" / T

P" = PT" / T

we substitute

P" = ( 301.3 × 328 ) / 293

P" = 98826.4 / 293

P" = 337.29

so Gauge pressure at 55°C is;

⇒ P" - 101.3

⇒ 337.29 - 101.3 = 235.99 ≈ 236 kPa

Therefore, the gauge pressure of the air in the tire is 236 kPa

b)

Final Volume V'' = V + 10% of V  

V" = V + 0.1V

V" = 1.1V

we know that;

P"V"/T" = PV/T

P" = P (T"/T)(V/V")

we substitute

P" = 301.3 (328 /293 )(V/1.1×V)

P" =  × 1/1.1 × V/V

P" = 337.29 × 1/1.1  

P" = 306.628 kPa

so, absolute pressure at 55°C = 306.628 - 101.3 = 205.33 kPa

Therefore, the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent is 205.33 kPa

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