Answer:
The ice skater will spin at an angular speed of 7.5 revolutions per second.
Explanation:
From statement we notice that ice skater can be considered as a system, on which no external forces are exerted, such that Principle of Angular Momentum can be applied:
[tex]I_{1}\cdot \omega_{1} = I_{2}\cdot \omega_{2}[/tex] (Eq. 1)
Where:
[tex]I_{1}[/tex] - Moment of inertia of the ice skater when her arms are outstretched, measured in kilogram-square meters.
[tex]\omega_{1}[/tex] - Angular speed when arms are outstretched, measured in revolutions per second.
[tex]I_{2}[/tex] - Moment of inertial of the ice skater when her arms are pulled, measured in kilogram-square meters.
[tex]\omega_{2}[/tex] - Angular speed when arms are pulled, measured in revolutions per second.
If [tex]I_{1} = 5\,kg\cdot m^{2}[/tex], [tex]\omega_{1} = 3\,\frac{rev}{s}[/tex] and [tex]I_{2} = 2\,kg\cdot m^{2}[/tex], the angular speed when arms are pulled is:
[tex]\omega_{2} = \frac{I_{1}}{I_{2}} \cdot \omega_{1}[/tex]
[tex]\omega_{2} = \left(\frac{5\,kg\cdot m^{2}}{2\,kg\cdot m^{2}} \right)\cdot \left(3\,\frac{rev}{s} \right)[/tex]
[tex]\omega_{2} = 7.5\,\frac{rev}{s}[/tex]
The ice skater will spin at an angular speed of 7.5 revolutions per second.
Describe how resistance affects the flow of current in a circuit
Will the velocity of the book change as it moves across the surface with NO friction? Explain your answer.
Explanation:
If we push on the book with a force of less than 5 N, the book won't move, because the frictional force will exactly balance the force we apply. If we push with a 1 N force, a 1 N frictional force opposes us.
As mass is constant during free-weight resistance training, a greater impulse will result in a greater velocity.Explanation:
Acceleration due to gravity (ag) = 9.8 m/s2. An object is dropped from a bridge. How
fast will the object be falling in 6.3 seconds?
Answer:
V = 61.74m/s
Explanation:
Given the following data;
Acceleration due to gravity = 9.8m/s²
Time, t = 6.3 secs
Since it's a free fall, initial velocity = 0
Thus, to find the final velocity, we would use the first equation of motion;
[tex] V = U + at[/tex]
Substituting into the equation, we have;
[tex] V = 0 + 9.8 * 6.3[/tex]
V = 61.74m/s
Therefore, the final velocity is 61.74m/s
an aiplane is traveling at 500 mph for 3.5 hours. how far did the plane travel
Answer:
1750mile
Explanation:
500/h
3.5h=3.5×500=1750
A man is walking toward the back of an airplane at 7 m/s. The plane is flying West at 245 m/s. What is the speed and direction of the plane relative to the man?
Answer:
The speed of the plane relative to the man is 245.1 m/s
The direction of the plane is S 88.36⁰ W
Explanation:
Given;
velocity of the man toward the airplane, Vy = 7 m/s
velocity of the airplane, Vx = 245 m/s west
The speed of the plane relative to man is given by;
<----------------------
↑
↑
↑
Complete this diagram to form a right angled triangle, with the hypotenuse as the relative velocity of the plan with respect to the man.
R² = 245² + 7²
R² = 60074
R = √60074
R = 245.1 m/s
The direction of the plane is given by;
tan θ = 245 / 7
tan θ = 35
θ = tan ⁻¹ (35)
θ = 88.36°
The direction of the plane is S 88.36⁰ W
A 10 kg block is pushed with a constant horizontal force of 20 N against a constant horizontal frictional force of 10 N.
What is the acceleration of the block?
1. 2 m/s2
2.5 m/s2
3. Zero
4. None of these
5. 1 m/s2
6. 10 m/s2
7. Insufficient information is provided.
Answer:
1 m/s2
Explanation:
The net force on the block is 20 N-10 N in the direction of its acceleration, so by Newton’s law F=Ma
a=10N/10kg
=1 m/s2
A force is applied to a 2.1 kg mass and produces 3 m/s- acceleration.
What acceleration would be produced by the same force applied to a 12.1 kg mass?
Answer in units of m/s2.
Answer:
f=m×a
f=2.1×3
f=6.3
f=ma
6.3=12.1a
a=0.52m/s²
Look at SS and answer
A car starts at a position of 4km and moves a final position of 5 km. What is the total distance traveled by the car?
A. 1 km
B.-9 k m
C. 9 km
D. -1 km
Answer:
its c. 9km
Explanation:
Because it you add the 4km+5km that gives you a total of 9km
Molten material beneath an erupting volcano. Point A at molten material under ground to the left of the volcano. Point B is at the bottom on the side of the volcano. Use the drop-down menus to answer the questions. Label the type of igneous rock that will form at point A. Label the type of igneous rock that will form at point B.
Answer:
Magma
Lava
:)
Explanation:
i did it and got it right
Select the correct answer. In which situation is maximum work considered to be done by a force? A. The angle between the force and displacement is 180°. B. The angle between the force and displacement is 90°. C. The angle between the force and displacement is 60°. D. The angle between the force and displacement is 45°. E. The angle between the force and displacement is 0°.
Answer:
A. The angle between the force and displacement is 180°.
Answer:
a
Explanation:
A bowling ball is dropped from rest. What is the ball's velocity after falling for 5 seconds?
Equation: Vy =g*t
Answer:
545432344455555322 we 45year 7of and
In a transformer, the incoming primary voltage is 120 V. There are 100 windings in the primary coil. The secondary coil has 65 windings. What is the outgoing voltage of this transformer?
a
151.9 V
b
64.41 V
c
102.8 V
d
78.02 V
Answer:
78.02 V
Explanation:
Given that,
Primary voltage in a transformer is 120 V
No of windings in the primary coil is 100
No of windings in the secondary coil is 65
We need to find the outgoing voltage of the transformer. For a transformer, the ratio of primary voltage to the secondary voltage is equal to the ratio of turns in Primary coil to the turns in secondary coil are equal. So,
[tex]\dfrac{V_p}{V_s}=\dfrac{N_p}{N_s}\\\\\dfrac{120}{V_s}=\dfrac{100}{65}\\\\V_s=\dfrac{120\times 65}{100}\\\\V_s=78\ V[/tex]
So, out of the given options, the correct one is option (d) i.e. 78.02 V
A person ran with a speed of 6 m/s onto the skateboard .What is the speed with which he ride on the skate board
Answer:
First, remember the conservation of energy.
We can define the kinetic energy as:
K = (1/2)*m*v^2
where m is the mass, and v is the velocity.
The velocity of the person is 6m/s, and the mass is unknown.
Now, when the person rides the skateboard, this kinetic energy must remain constant, if M is the mass of the skateboard, the speed after the person rides ir will be:
K' = (1/2)*(m + M)*v'^2
Where v' is the new velocity.
In this case, we can suppose that the skateboard has really small mass compared with the person.
M < < m
then:
(m + M) ≈ m
then:
K' = (1/2)*m*v'^2 = K = (1/2)*m*v^2
from that equation, we can conclude that:
v' = v
Then if the velocity before riding the skateboard was 6m/s, then after would be also 6m/s.
Manu takes 30 minutes from his house to reach his school on a bicycle. If the cycle has a speed of 4m/s find the difference between his house and the school.
Answer:
7200 m
Explanation:
From the question given above, the following data were obtained:
Time (t) = 30 mins
Speed (S) = 4 m/s
Distance (d) =.?
Next, we shall convert 30 mins to seconds. This can be obtained as follow:
1 mins = 60 s
Therefore,
30 mins = 30 mins × 60 s / 1 mins
30 mins = 1800 s
Thus, 30 mins is equivalent to 1800 s.
Finally, we shall determine the difference between Manu's house and his school by calculating the distance. This is illustrated below:
Time (t) = 1800 s
Speed (S) = 4 m/s
Distance (d) =.?
Speed = Distance /time
4 = Distance /1800
Cross multiply
Distance = 4 × 1800
Distance = 7200 m
Therefore, the difference between Manu's house and his school is 7200 m
Gas stored in a tank at 273 K has a pressure of 388 kPa. The safe limit for the pressure is 825 kPa. At what temperature will the gas reach pressure?
Answer: At 508k temperature the gas will reach the pressure.
Explanation:
[tex]T_{2} =\frac{P_{2} T_{1}}{P_{1}} \\T_{2} =\frac{825kPa * 237K }{388kPa} = 580k[/tex]
Answer: 580k
Explanation: Gradpoint
(Physical science!!!)
Wetlands have characteristics of both dry land and of bodies of water. How have amphibians adapted to this environment?
A.
They can lay their eggs underwater or on dry land.
B.
Water can pass through their lungs; they have night vision.
C.
Water can pass through the skin; they have lungs.
D.
They retain a set of gills their whole lives.
Amphibians retain a set of gills their whole lives that help them to breathe in the water. So, the correct option is D.
What are Amphibians?Amphibians are defined as the class of cold-blooded vertebrates which is made up of frogs, toads, salamanders, newts, and caecilians. All amphibians that spend part of their lives in water and part of their lives on land.
Amphibians are born with gills, and some outgrow them when they become adults while others retain them for their entire lives.
Thus, the correct option is D.
Learn more about Amphibians, here:
https://brainly.com/question/14213726
#SPJ1
If the block in the picture has an acceleration of 5 m/s2, what would be the block's mass?
Answer:
0.4 Kg
Explanation:
From the question given above, the following data were obtained from the question:
Acceleration (a) of block = 5 m/s²
Force in the right direction (Fᵣ) = 3 N
Force in the left direction (Fₗ) = 5 N
Mass (m) of block =...?
Next, we shall determine the net force acting on the block. This can be obtained as follow:
Force in the right direction (Fᵣ) = 3 N
Force in the left direction (Fₗ) = 5 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 5 – 3
Fₙ = 2 N
Thus the net force acting on the block is 2 N to the left.
Finally, we shall determine the mass of the block as follow:
Acceleration (a) of block = 5 m/s²
Net force (Fₙ) = 2 N
Mass (m) of block =...?
Net force (Fₙ) = mass (a) × acceleration (a)
Fₙ = m × a
2 = m × 5
Divide both side by 5
m = 2/5
m = 0.4 Kg
Therefore, the mass of the block is 0.4 Kg
Where does transpiration occur
Answer:
it's when the water in water in plants is evaporated and turned into water vapor
Explanation:
hope it helps
Help plz
Which of the following graphs best represents the expected experimental data between the force of gravitational attraction between two varying masses positioned 1 m apart
Answer:
I'm pretty sure it's D
Explanation:
because the greater the mass, the greater the gravitational pull is on it. but you probably shouldn't take my word on it, lol
cerebrum what is the meaning
Answer:
Plural cerebrums cerebra The largest part of the vertebrate brain, filling most of the skull and consisting of two cerebral hemispheres divided by a deep groove and joined by the corpus callosum, a transverse band of nerve fibers. The cerebrum processes complex sensory information and controls voluntary muscle activity.
Explanation:
What is the sum of all of the forces acting on an object
Answer:
Explanation:
The sum of all the forces acting on an object is the net force or resultant force. If all the forces cancel out, the resultant force is zero, else, the unbalanced force will cause acceleration of the object. Force is a vector and hence has both a direction and magnitude. For example, gravitational force (on earth) acts in downward direction and has a magnitude equal to mass of the object and acceleration due to gravity. Once we know all the forces that are acting on a body, we resolve all of them into components (typically horizontal and vertical) and take summation of forces in each direction. If such forces cancel out (in each direction), the object maintains its state of rest or constant motion. If however, forces do not cancel out, there is a net resultant force on the object that will cause acceleration of the object (as given by Newton's second law of motion).
Hope this helps.
The sum of all of the forces acting on an object is called net force. It is categorized as a vector quantity because it has both direction and magnitude to be considered.
What is Force?Force may be defined as the process of pushing or pulling on an object with mass provoking it to change its velocity. It is an external agent capable of altering a body's state of rest or motion. It has a magnitude and a direction, so it is a vector quantity.
Net force in a case where forces of different magnitude and opposite directions will be the difference between greater and lesser force. The combination of the resultant of all the forces acting on an object is called Net Force, which is basically the sum of all the forces acting on that object.
Therefore, the sum of all of the forces acting on an object is called net force.
To learn more about Net force, refer to the link:
https://brainly.com/question/20795823
#SPJ2
A type of elevator called a cage is used to raise and lower miners in a mine
shaft. Suppose the cage carries a group of miners down the shaft. If the
unbalanced force on the cage is 60.0 N, and the mass of the loaded cage is
1.50 x 10²kg, what is the acceleration of the cage?
Answer:
Acceleration, a = 0.04 m/s²
Explanation:
Given the following data;
Force = 60N
Mass = 1500kg
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
[tex] F = ma[/tex]
Where;
F represents force.
m represents the mass of an object.
a represents acceleration.
Making acceleration (a) the subject, we have;
[tex]Acceleration (a) = \frac{F}{m}[/tex]
Substituting into the equation;
[tex]Acceleration (a) = \frac{60}{1500}[/tex]
Acceleration, a = 0.04 m/s²
How do scientists determine the number of neutrons in an isotope of an atom?
They subtract the atomic number from the atomic mass.
They find the number of protons.
They divide the atomic mass by two.
They add the number of electrons and protons.
Answer:
They subtract the atomic number from the atomic mass
Hope this helps
Please mark as the brainliest
9. Which of Newton's laws explains why a rocket can be sent into space by aiming a force downward?
Answer:
Newton's third law
Explanation:
the fuel is the action force
and the rocket going up is the reaction force
HELP!!!! ILL GIVE BRAINLIEST!!HURRY !!!!
what is 5.6 x 10^15 converted to x10^12
Answer:
5,600
Explanation:
You split x10^15 into x10^12 and x10^3. Our new equation is 5.6x10^3x10^12
We do 5.6x10^3 and we get 5,600. Our new equation is 5,600x10^12. I hope this answered your question.
The cheetah is the fastest land animal, able to reach quickly a maximum speed of 31.0 m/s. But it is able to maintain this speed for only about 10.0 s. Suppose that the cheetah stalks a prey that has a maximum speed of 25.0 m/s, but is able to maintain this speed for much longer than 10.0 s. If it is to catch its prey, what is the maximum distance the cheetah can be from the prey when the chase begins?
Answer:
60 m
Explanation:
Given that a cheetah is able to reach quickly a maximum speed of 31.0 m/s. But it is able to maintain this speed for only about 10.0 s.
The distance = speed × time
The distance = 31 × 10
The distance = 310 m
Suppose that the cheetah stalks a prey that has a maximum speed of 25.0 m/s, but is able to maintain this speed for much longer than 10.0 s.
The prey distance = 25 × 10
Distance = 250m
If it is to catch its prey, the maximum distance the cheetah can be from the prey when the chase begins must be:
Maximum distance = 310 - 250
Maximum distance = 60 m
If a volleyball accelerates towards the ground at 10m/s/s and it takes 1.6 seconds to hit the ground, how tall is the building
Answer:
Distance, S = 12.8m
Explanation:
Given the following data;
Acceleration = 10
Time = 1.6
Initial velocity = 0
To solve for acceleration, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Substituting the values into the equation;
[tex] S = 0(1.6) + \frac {1}{2}*10*(1.6)^{2}[/tex]
[tex] S = 5 *2.56[/tex]
Distance, S = 12.8m
Therefore, the height of the building is 12.8 meters.
The average velocity and time of motion for an objects are recorded as
Vavg = +2.0 m/s. Ai= 3.0 s
What is the displacement of the object?
O 0.67 m
O 6m
o 3m
O 1.5 m
A train slows down as it rounds a sharp horizontal turn, going from 100 km/h to 60.0 km/h in the 14.0 s it takes to round the bend. The radius of the circle is 160 m. Compute the total acceleration and the angle at the moment the train speed reaches 60.0 km/h.
Answer:
The magnitude of the total acceleration of the train is approximately 1.909 meters per square second.
The direction of total acceleration with respect to radial acceleration is approximately -24.578º.
Please note that negative sign indicates that train is decelerating.
Explanation:
From Physics, we know that magnitude of the acceleration experimented by the train ([tex]a[/tex]), measured in meters per square second, while rounding the bend is the Pythagorean identity involving radial and tangential accelerations ([tex]a_{r}[/tex], [tex]a_{t}[/tex]), measured in meters per square second:
[tex]a = \sqrt{a_{t}^{2}+a_{r}^{2}}[/tex] (Eq. 1)
If we assuming that train decelerates at constant rate, then each component is determined by following expressions:
[tex]a_{t} = \frac{v_{f}-v_{o}}{t}[/tex] (Eq. 2)
[tex]a_{r} = \frac{v_{f}^{2}}{R}[/tex] (Eq. 3)
Where:
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds, measured in meters per second.
[tex]t[/tex] - Deceleration time, measured in seconds.
[tex]R[/tex] - Bend radius, measured in meters.
If we know that [tex]v_{o} = 27.778\,\frac{m}{s}[/tex], [tex]v_{f} = 16.667\,\frac{m}{s}[/tex], [tex]t = 14\,s[/tex] and [tex]R = 160\,m[/tex], then each acceleration component is calculated:
[tex]a_{t} = \frac{16.667\,\frac{m}{s}-27.778\,\frac{m}{s} }{14\,s}[/tex]
[tex]a_{t} = -0.794\,\frac{m}{s^{2}}[/tex]
[tex]a_{r} = \frac{\left(16.667\,\frac{m}{s} \right)^{2}}{160\,m}[/tex]
[tex]a_{r} = 1.736\,\frac{m}{s^{2}}[/tex]
Then, the magnitude of the total acceleration of the train is:
[tex]a = \sqrt{\left(-0.794\,\frac{m}{s^{2}} \right)^{2}+\left(1.736\,\frac{m}{s^{2}} \right)^{2}}[/tex]
[tex]a \approx 1.909\,\frac{m}{s^{2}}[/tex]
The magnitude of the total acceleration of the train is approximately 1.909 meters per square second.
After that, we obtain the angle of acceleration by using the following trigonometric expression:
[tex]\theta = \tan^{-1} \frac{a_{t}}{a_{n}}[/tex] (Eq. 4)
Where [tex]\theta[/tex] is the direction of total acceleration with respect to radial acceleration, measured in sexagesimal degrees.
If we get that [tex]a_{t} = -0.794\,\frac{m}{s^{2}}[/tex] and [tex]a_{r} = 1.736\,\frac{m}{s^{2}}[/tex], the direction of total acceleration experimented by the train is:
[tex]\theta = \tan^{-1}\left(\frac{-0.794\,\frac{m}{s^{2}} }{1.736\,\frac{m}{s^{2}} } \right)[/tex]
[tex]\theta \approx -24.578^{\circ}[/tex]
Please note that negative sign indicates that train is decelerating.
The direction of total acceleration with respect to radial acceleration is approximately -24.578º.