Answer:
An exergonic reaction releases free energy, and an endergonic reaction absorbs free energy.
Explanation:
hope it helps
10.5 mL of an unknown solution are diluted to 80.0 mL. The concentration of the
new solution was determined to be 0.172 M. What was the molarity of the
unknown solution? (Report your answer to two places past the decimal point.
Moodle is looking for a number only, no units.)
The molarity of the unknown solution will be 1.310 M.It is denoted by M₂.
What is molarity?Molarity is defined as the ratio of the moles to the volume of the solution.
Given data;
Volume of unknown solution,V₁ = 10.5 mL
The volume of diluted solution,V₂ = 80.0 mL
Molarity of new solution,M₁ = 0.172 M
Molarity of unknown solution, M₂=?
For dilution we use the formula as;
M₁V₁=M₂V₂
M₂=M₂V₂/V₁
M₂ = ( 80 × 0.172 ) / 10.5
M₂= 1.310 M
Hence the molarity of the unknown solution will be 1.310 M.
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When producing a soluble salt in a reaction between an acid and an alkali, how can you prepare dry solid crystals from the solutions
1)evaporation/crystallization
2)filtration
3)condensation
4)nuetralisation
Explanation:
Making a salt from an alkali
If you are using an alkali - which is a soluble base - then you need to add just enough acid to make a neutral solution (check a small sample with universal indicator paper).
Warm the salt solution to evaporate the water. You get larger crystals if you evaporate the water slowly.
What kind of exercise does not require the use of oxygen to metabolize energy? strength aerobic stretching anaerobic
Answer:
See Below
Explanation:
'an aerobic ' means it does not use oxygen
Answer:
anaerobic
Explanation:
A container with a volume 2.0 L is filled with a gas at a pressure of 1.5 atm. By decreasing the volume of the container to 1.0 L, what is the resulting pressure? Type in your answer using the correct number of significant figures. Remember to use the formula for Boyle's law: P1V1 = P2V2
After reducing the starting volume, the gas has a resultant pressure of 3 atm.
Describe Boyle's Law.
Boyle's Law states that a gas's pressure is inversely proportionate to its volume at constant temperature:
P ∝ 1/V
The necessary equation for the posed question is:
P1V1 = P2V2, and
Initial pressure is P1 and is 1.5 atm.
Initial volume = 2 L for V1.
final pressure = P2 =?
Final volume = 1 L, or V2.
Using the aforementioned equation and all of these data, we obtain
P₂ = [tex]\frac{(1.5x2)}{1}[/tex]= 3atm
Therefore, 3 atm of pressure is needed.
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what is the approximate partial pressure of oxygen at 1500 m?
The approximate partial pressure of oxygen at 1500 m is 0.18 atm.
Pressure of the airFrom barometric pressure table;
1500 m = 85 kPa
1 kPa = 0.0099 atm
85 kPa = ?
= 0.84 atm
Oxygen percentage in air = 21%
Partial pressure of oxygen in air
P = 0.21 x P(total)
P = 0.21 x 0.84 atm
P = 0.18 atm
Thus, the approximate partial pressure of oxygen at 1500 m is 0.18 atm.
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n
What is an isotope?
6.0 mol NaOH reacts with
9.0 mol H3PO4 according to
the equation below:
3NaOH + H3PO4 → 3H₂O + Na3PO4
How many moles of Na3PO4 form from
6.0 mol NaOH?
[?] mol Na3PO4
Round your answer to the tenths place.
2 moles of Na3PO4 form from 6.0 mol NaOH. Details about stoichiometry can be found below.
How to calculate number of moles?The number of moles of a substance can be calculated stoichiometrically as follows:
3NaOH + H3PO4 → 3H₂O + Na3PO4
According to this equation,
3 moles of NaOH produces 1 mole of Na3PO4
This means that 6 moles of NaOH will produce 6/3 = 2 moles of Na3PO4
Therefore, 2 moles of Na3PO4 form from 6.0 mol NaOH.
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Choose the correct statements when comparing 1 mole of carbon
monoxide and one mole of helium gas.
a: they weigh the same
b: they have the same amount of particles
c: they occupy the same volume
Answer: they have the same amount of particles
Explanation:
This statement is true by Avogadro's Law, which states that in a mole of any substance, there are [tex]6.022 \times 10^{23}[/tex] particles.
Lucite contains 59.9 g C, 8.06 g H,
and 32.0 g O. You want to
determine the empirical formula.
How many moles of H are in the
sample?
{?} mol H
Answer:
8.00
Explanation:
I hope the spurs get wembanyama so bad
A sealable bag holds 3.79 L of
gas. How many moles of H₂
gas are needed to fill the bag
at 1.0 atm and 293 K?
The H₂ gas are needed 0.157moles to fill the bag .
For solving this problem we use the ideal gas equation. It is also called the general gas equation . This equation use for a hypothetical ideal gas. . It has several limitations. It was first stated by Benoit Paul Emile Clapeyron in 1834 . The ideal gas law is written by an empirical form:
PV = n R T
where-
P = Pressure
V = volume
T = Temperature
n = The amount of substance
R = Ideal gas constant
Now we have the values of these terms as-
P = 1 atm , V = 3.79L , T = 293K
and R = 0.0826 L/atm
For getting moles of hydrogen we can use the values of variables in ideal gas equation as -
P V = n R T
Now (1 atm) × ( 3.79L ) = n × ( 0.0826 L/atm) × ( 293K)
n = (1 × 3.79) ÷ (0.0826 x 293)
= 0.157 moles
So that the 0.157moles of H₂ gas are needed for fill the bag .
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The theoretical yield of NaBr from
2.36 mol FeBr3 is 7.08 mol NaBr.
What is the percent yield if 6.14 mol
NaBr were collected?
[?]%
the percent yield of the reaction is 100%.
The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:
% yield = actual yield / theoretical yield * 100%
% yield of a reaction in this case Rate
In this case, the molar mass of NaBr is 102.9 g / mol, as you know:
444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g
theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g
, Replaced by the definition of percent yield:
percent yield = 728.532 grams / 728.532 grams * 100%
percent yield = 100%
Finally, the percent yield of the reaction is 100%.
FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.
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Answer: 87%
Explanation:
14- Which statements about acids and bases are correct? (1 mark) 1- An acid reacts with a metal to give off hydrogen. 2- A base reacts with an ammonium salt to give off ammonia. 3-An acid reacts with a carbonate to give off carbon dioxide. 4- Alkaline solutions are orange in methyl orange.
A) 1, 2 and 3
B) 1, 2 and 4
C) 1, 3 and 4
D) 2, 3 and 4
Answer:
a)
Explanation:
4th is incorrect.
Alkaline solutions are yellow in methyl orange.
Which statements about acids and bases are correct ?
A) 1, 2 and 3<3
Nitrogen monoxide (NO) is a pollutant known to
destroy the ozone layer. Nitrogen monoxide reacts
with ozone molecules (0,) to release oxygen and
a nitrogen-containing compound Q. Given that one
molecule of nitrogen monoxide reacts with one
molecule of ozone to produce one molecule of
of Q.
oxygen and one molecule of Q, identify the formula.
Answer:
See below
Explanation:
NO + O3 ====> NO2 + O2 (ozone is O3)
What does the NaBr + Cl₂ represent
in the reaction?
NaBr + Cl₂ →>>
NaCl + Br₂
Answer:
The reactants
Explanation:
The molecules on the left side of the reaction are the reactants. Reactants are the molecules which react with one another to form something new.
The molecules on the right side of the reaction are the products. Products are the molecules that form in response to the reaction.
Which of the following observations would indicate that a material is a pure substance?
O It does not dissolve in water.
O It changes color after heating.
O It cannot be physically broken down into different types of atoms.
O It can be physically broken down into different types of molecules.
Answer:
C
Explanation:
Got it right on a test
what mass of aluminium is required to produce 500g of aluminium chloride?
2Al + 3Cl₂ --> 2AlCl₃
Answer:
101.18 grams
Explanation:
From the equation you can see that the same number of MOLES will be required as MOLES of aluminum chloride produced.
Mole weight of aluminum chloride = 26.981 + 3 * 35.45 = 133.331 gm
500 gms of this is then 500 / 133.331 = 3.75 moles
So you need 3.75 moles of aluminum
3.75 moles * 26.981 g/mole = 101.18 grams of Al
101.07 grams of aluminum (Al) are required to produce 500 grams of aluminum chloride (AlCl₃) according to the given chemical equation.
Mass is a fundamental physical property of matter that represents the amount of substance contained in an object. It is a measure of the total amount of matter or material in an object, and it is typically measured in units such as grams (g) or kilograms (kg).
Molar mass, also known as molecular mass or formula mass, is the mass of one mole of a chemical substance. It is usually expressed in grams per mole (g/mol). Molar mass is a fundamental concept in chemistry that allows scientists to relate the mass of a substance to the number of moles it contains.
The balanced chemical equation is:
2Al + 3Cl₂ → 2AlCl₃
From the balanced equation, 2 moles of aluminum (Al) react with 3 moles of chlorine gas (Cl₂) to produce 2 moles of aluminum chloride (AlCl₃).
Molar mass of Al = 26.98 g/mol
Molar mass of Cl = 35.45 g/mol
Molar mass of AlCl₃ = 2 × (26.98 g/mol) + 3 × (35.45 g/mol)
= 133.34 g/mol
moles of AlCl₃ = mass / molar mass
moles of AlCl₃ = 500 g / 133.34 g/mol
= 3.749 moles
In the reaction, 2 moles of Al react to produce 2 moles of AlCl₃.
Therefore, moles of Al = moles of AlCl₃
moles of Al = 3.749 moles
Step 4: Calculate the mass of Al required:
mass of Al = moles of Al × molar mass of Al
mass of Al = 3.749 moles × 26.98 g/mol
= 101.07 g
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What is the common uses of bases
What is the name of this compound
Hydrobrome Aicd
I think so...
Answer:
[tex]\fbox {1,2-di bromo pentane}[/tex]
Explanation:
⇒ Bromine atoms present on 1st and 2nd Carbon atoms
⇒ 5 carbon atoms
⇒ Only single bonds
Hence, the IUPAC name will be :
1,2-dibromopentane
How do we investigate translocation using tracers?
Translocation can be investigated by using radioactively labelled tracers, which are absorbed into glucose during photosynthesis.
What is translocation?Translocation can be defined as a biological process which involves the transfer (movement) of water and other soluble nutrients from one part of a plant to another, especially through the xylem and phloem.
Generally, translocation can be investigated by using radioactively labelled tracers, which are absorbed into glucose during photosynthesis. Also, an x-ray turns black when exposed to this biological process in plants.
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How many grams of NaCl can be created from 9.8 moles of HCl? (molar mass of NaCl= 58.44g, HCl=36.46g)
The mass of NaCl that can be produced from 9.8 moles of HCl is 572.712 g
Balanced equation2Na + 2HCl --> 2NaCl + H₂
From the balanced equation above,
2 moles of HCl reacted to produced 2 moles of NaCl.
Therefore,
9.8 moles of HCl will also react to produce 9.8 moles of NaCl
How to determine the mass of NaClMolar mass of NaCl = 58.44 g/molMole of NaCl = 9.8 molesMass of NaCl =?Mass = mole × molar mass
Mass of NaCl = 9.8 × 58.44
Mass of NaCl = 572.712 g
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The difference in an area with high concentration and an area with low concentration is called.
The difference in an area with high concentration and an area with low concentration is called the concentration gradient.
What is Concentration Gradient ?
A concentration gradient occurs when the concentration of particles is higher in one area than another.
In passive transport, particles will diffuse down a concentration gradient, from areas of higher concentration to areas of lower concentration, until they are evenly spaced.
This difference in an area with high concentration and an area with low concentration is called the concentration gradient.
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When you have added as much solute as can dissolve in solvent the solution is called
Solubility limit. that's the answer
9- Which pair of formulae represents two alkanes? (1 mark)
A)CH4 and C8H18
B)C₂H6 and C5H8
C) C3H6 and C5H12
D) C₁0H8 and C4H8
Answer:
A) CH4 and C8H18
Explanation:
General Formula for an Alkane = CnH2n+2This means for every number of Carbon (C) atoms, there are twice as many Hydrogen (H) atoms with an additional two added onto that.Therefore, if there is one Carbon Atom, and we multiply that by two, and then add an additional two, we get 4 Hydrogen atoms, so CH4, which is our first FormulaeSecondly, if we have eight Carbon Atoms, and we multiple that by two (16), and then add an additional two, we get 18 Hydrogen atoms, so C8H18, which is our second FormulaeThe other Formulas do not follow this 'General Formula'When molten magma rises to the surface it cools ________, forming ________ igneous rocks.
A. slowly, extrusive
B. slowly, intrusive
C. rapidly, intrusive
D. rapidly, extrusive
Answer:
B)Slowly, intrusive
Dalton law states that the partial pressure of a gas in a mixture of gases is _____ to the total pressure of the mixture.
Answer:
Dalton law states that the partial pressure of a gas in a mixture of gases is equal to the total pressure of the mixture.
A 609 ml sample of naoh has a ph of 13.5292. if 594 ml of distilled water was added to the initial naoh solution, what would the new ph of the solution be g
The new pH of the solution after the addition of water would be 13.22.
Total volume of the solutionV(total) = 609 ml + 594 ml
V(total) = 1203 ml
Concentration of waterC = (594 ml)/(1203 ml)
C = 0.493
pOH = -log(0.493)
pOH = 0.31
New pH of the solution = 13.5292 - 0.31 = 13.22
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what is formed when mixing a weak acid and strong base
Explanation:
when a weak acid and a strong based are mixed they react the pH can be determined by consider ing the equilibrium
A graduated cylinder is filled to 12.5 mL
with water and a piece of tin is placed
in the cylinder, displacing the level to
16.8 mL.
What is the volume of the tin piece in
cubic centimeters?
[?] cm³
Record your answer to the tenths place.
Volume (cm³)
The volume of the tin piece in cubic centimetres is 4.3 cm³
What is a graduated cylinder?A graduated cylinder is a standard piece of laboratory glassware used to measure the volume of an object or amount of liquid. As its name indicates, it is a glass cylinder with marks along the side similar to those on a measuring cup.
When adding an object to a liquid, the displayed volume difference corresponds to the volume of the added object.
In this way, to find the value of the object's volume, subtract the initial volume from the final volume:
16.8ml - 12.5ml = 4.3ml
To convert to cubic centimetres, the conversion scale of volume and length measurements need to be used, finding that mL is equal to cubic centimetres. So, the final answer is:
4.3 cm³
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What is the empirical formula for the molecular formula given? Molecular formula: C5H12O
What is the empirical formula for the molecular formula given? Molecular formula: C5H12O
The empirical formula for the given molecular formula C₅H₁₂O. As the molecular formula cannot be reduced into simplest ratio, therefore, the empirical formula and the molecular formula are the same.
What is the empirical formula?The empirical formula can be described as the simplest ratio of the number of different atoms present in a compound. The molecular formula of the compound can be described as the actual number of each different atom in a molecule. This formula is generally used and is also a multiple of the empirical formula of a compound.
The empirical formula provides the ratio of the number of atoms of a chemical in a given compound. The percentage composition directly gives the empirical formula of the compound.
The molecular formula can be reduced into the empirical formula of the compound by dividing the subscripts with a number that can provide the smallest ratio of the elements in the compound.
For the given molecular formula, the further simplest or most reduced ratio cannot be possible. Therefore, the empirical formula of the compound will be the same as the molecular formula. Therefore empirical formula of the compound is C₅H₁₂O.
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Perform the following operation
and express the answer in
scientific notation.
2.36×10-2 8.4×10²
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \:2.8 × {10}^{-5}[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: \dfrac{2.36 \times 10 {}^{ - 2} }{8.4 \times {10}^{2} } [/tex]
[tex]\qquad \tt \rightarrow \: \dfrac{2.36 }{8.4 } \times \cfrac{10 {}^{ - 2} }{10 {}^{2} } [/tex]
[tex]\qquad \tt \rightarrow \: 0.28 \times 10 {}^{ - 2 - 2} [/tex]
[tex]\qquad \tt \rightarrow \: 0.28 \times 10 {}^{ - 4} [/tex]
[tex]\qquad \tt \rightarrow \: 2.8 \times 10 {}^{ - 5} [/tex]
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