An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.323 M HI, 4.34E-2 M H2 and 4.34E-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.228 mol of HI(g) is added to the flask?

Answers

Answer 1

Answer:

[HI] = 0.5239M

[H₂] = 7.05x10⁻²

[I₂] = 7.05x10⁻²

Explanation:

The reaction of HI to produce H₂ and I₂ is:

2HI → H₂ + I₂

Where K of reaction is defined as:

K = [H₂] [I₂] / [HI]²

Replacing with the concentrations of the gases in equilibrium:

K = [4.34x10⁻²] [4.34x10⁻²] / [0.323] ²

K = 0.0181

If you add 0.228 mol = 0.228M (Because volume of the flask is 1.0L), the concentration when the system reaches the equilibrium are:

[HI] = 0.228M + 0.323M - X = 0.551M - X

[H₂] = 4.34x10⁻² + X

[I₂] = 4.34x10⁻² + X

Where X is reaction coordinate.

Replacing in K formula:

K = 0.0181 = [4.34x10⁻²+ X] [4.34x10⁻²+ X] / [0.551 - X] ²

0.0181 =  0.00188356 + 0.0868 X + X² / 0.303601 - 1.102 X + X²

0.005495 - 0.01995 + 0.0181X² = 0.00188356 + 0.0868 X + X²

0 = -0.003611 + 0.10675X + 0.9819X²

Solving for X:

X = -0.136 → False solution, there is no negative concentrations.

X = 0.0271 → Right solution.

Replacing for concentrations of each species:

[HI] = 0.5239M[H₂] = 7.05x10⁻²[I₂] = 7.05x10⁻²

Related Questions


Write the identity of the missing nucleus for the following nuclear decay reaction:
232 Th 228Ra+?
90
88
low.
Express your answer as a particle.
View Available Hints
Hint 1. Determine the missing mass number
1
Hint 2. Determine the missing atomic number
Hint 3. Determine the symbol of the new nucleus
?

Answers

Answer:

Alpha decay: 4 2He

Explanation:

Considering the equation given in the question, we can see that the mass number of daughter nuclei (228 88Ra) reduce by 4 and the atomic number reduce by 2 when compared with the parent nucleus (232 90Th). This simply indicates that the parent nucleus is undergoing alpha decay.

Therefore, the missing nucleus is

4 2He i.e alpha decay.

Please see attachment photo for further details.

Hydrogen chloride gas can be prepared by the following reaction: 2NaCl(s) + H2SO4(aq) → 2HCl(g) + Na2SO4(s) How many grams of HCl can be prepared from 2.00 mol H2SO4 and 2.56 mol NaCl?

Answers

Answer:

The correct answer is is option B

b. 93.3 g

Explanation:

SEE COMPLETE QUESTION BELOW

Hydrogen chloride gas can be prepared by the following reaction: 2NaCl(s) + H2SO4(aq) → 2HCl(g) + Na2SO4(s)

How many grams of HCl can be prepared from 2.00 mol H2SO4 and 2.56 mol NaCl?

a. 7.30 g

b. 93.3 g

c. 146 g

d. 150 g

e. 196 g

CHECK THE ATTACHMENT FOR STEP BY STEP EXPLANATION


A substance is considered to have a smaller surface area when...

A. it is a fine powder
B. it is in large chunks
C. you have a small amount of
the substance
D. you have a large amount of E. the substance

Answers

Answer: C you have a small amount of substance

Acetone is a solvent used in fingernail polish remover. Acetone is polar. It will form
solutions, or be soluble, in all the following except
O A. ethanol, which has molecules that have
one end with a slight charge
B. ammonia, which is made of molecules with
a slightly negative nitrogen atom and three
slightly positive hydrogen atoms
O C. water, which has oxygen atoms with a
slight negative charge
D. vegetable oil, which has atoms that share
electrons equally, so that there is no charge
difference
Read Question
Correct:

Answers

Answer:

d

Explanation:

When of benzamide are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing point of pure . On the other hand, when of iron(III) chloride are dissolved in the same mass of , the freezing point of the solution is lower than the freezing point of pure . Calculate the van't Hoff factor for iron(III) chloride in . Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.

Answers

The given question is incomplete, the complete question is:

When 238.g of benzamide (C7H7NO) are dissolved in 600.g of a certain mystery liquid X, the freezing point of the solution is 5.0°C lower than the freezing point of pure X. On the other hand, when 238.g of iron(III) chloride are dissolved in the same mass of X, the freezing point of the solution is 11.5°C lower than the freezing point of pure X.

Calculate the van't Hoff factor for iron(III) chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to 2 significant digits.

Answer:

The correct answer is 3.0.

Explanation:

Based on the given question, the weight of benzamide given is 238 grams, the molecular mass of benzamide is 121.14 gram per mole. The benzamide is dissolved in 600 grams of liquid X, therefore, the solution's total weight is,  

= 238 + 600 = 838 grams

In case of benzamide, ΔTf = kf × molality (It is given that the solution's freezing point is 5 degree C lesser in comparison to the pure X's freezing point). Now putting the values we get,  

5 = kf × 238 / (121.14×838) × 1 (Van't Hoff factor) -------- (i)

In case of benzamide, the van't Hoff factor will be 1, as it is neither associate nor dissociate.  

On the other hand, the mass of ferric chloride given is 238 grams getting dissolved in the similar mass of X, therefore again the total mass of the solution will be 838 grams. The freezing point of the solution is 11.5 degree C lesser than the pure X's freezing point. The molecular mass of ferric chloride is 162.2 gram per mol.  

For FeCl3,  

ΔTf = kf × molality

11.5 = kf × 238/ (162.2 × 838) × i (Van't Hoff factor)------ (ii)

Now dividing equation (ii) by (i) we get,  

11.5 / 5 = (kf/kf) × (121.14 / 162.2) × i  

i = 3.0

Which hormones are secreted from the posterior pituitary gland?

a. Growth hormone
b. Oxytocin
C. ACTH
d. PTH

Answers

the answer is b

The posterior pituitary secretes two important endocrine hormones—oxytocin and antidiuretic hormone

which of the following objects have kinetic energy? check all that apply

Answers

Answer:

what are the options?

Explanation:

do you have multiple choice for this question?

Answer:

A book inside a vehicle, a running cat, and a falling meteorite.

Explanation:

I just took it

Where does the stored energy in these cabbage leaves come from ?

Answers

Answer:

The energy in cabbage leaves comes from the light from the sun.

Explanation:

The plant keeps the light (in the leaves) as energy to help make it grow.

Based on the activity series provided which reactants will form products? F>Cl>Br>l

Answers

Answer:

CuI₂ + Br₂

Explanation:

Answer:

a

Explanation:

A sample of copper absorbs 4.31E+1 kJ of heat, resulting in a temperature rise of 6.71E+1 °C. Determine the mass (in kg) of the copper sample if the specific heat capacity of copper is 0.385 J/g°C.

Answers

Answer: 1.67 kg

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]Q=m\times c\times \Delta T[/tex]

Q = Heat absorbed=[tex]4.31\times 10^1kJ[/tex] = [tex]43100J[/tex]   (1kJ=1000J)

m= mass of substance = ?

c = specific heat capacity = [tex]0.385J/g^0C[/tex]

Change in temperature ,[tex]\Delta T=T_f-T_i=6.71\times 10^1^0C=67.1^0C[/tex]

Putting in the values, we get:

[tex]43100J=m\times 0.385J/g^0C\times 67.1^0C[/tex]

[tex]m=1670g=1.67kg[/tex]   (1kg=1000g)

Thus the mass (in kg) of the copper sample is 1.67

(i) 1s 2 2s 2 2p 6 3s 1 (ii) 1s 2 2s 2 2p 6 3s 2 (iii) 1s 2 2s 2 2p 6 3s 2 3p 1 (iv) 1s 2 2s 2 2p 6 3s 2 3p 4 (v) 1s 2 2s 2 2p 6 3s 2 3p 5 The electron configuration of the atom that is expected to have a positive electron affinity is ________.

Answers

Answer:

 (V) 1s 2 2s 2 2p 6 3s 2 3p 5

Explanation:

Electron Affinity can be defined as the energy associated with a neutral atom, when an electron is added to form a negative ion.

1s 2 2s 2 2p 6 3s 2 3p 5 , is the electronic configuration of Chlorine.

The electron affinity is positive because it is an exorthermic reaction, meaning that, energy was released during the addition of an electron to the atom.

Cl (g)  +  e-   ------->  Cl- (g)    = -349KJ/mol

Assign priorities in the following set of substituents according to Cahn-Ingold-Prelog rules.-Cl, -OH, -CH_2OH, -CH_2SHA B C D(Provide your ranking through a string like abed, starting with the one with the highest priority. Your answer does not need to be capitalized.)

Answers

Answer:

1) [tex]-Cl[/tex]

2) [tex]-OH[/tex]

3) [tex]-CH_2SH[/tex]

4) [tex]-CH_2OH[/tex]

Explanation:

We have the substituents:

a) [tex]-Cl[/tex]

b) [tex]-OH[/tex]

c) [tex]-CH_2OH[/tex]

d) [tex]-CH_2SH[/tex]

If we remember that Cahn-Ingold-Prelog rules the highest priority is given by the atomic number. Therefore the highest priority is "Cl" (an atomic number equal to 17), the next one is "OH" due to the oxygen (an atomic number equal to 8). For c) and d) we have a carbon bonded to the chiral carbon, therefore we have to check the next atom. The difference between c) and d) are the "O" and "S" atoms, the atom with the highest atomic number is "S" (an atomic number equal to 16)  therefore the highest priority is for d) and then c). So finally, the priority is:

1) [tex]-Cl[/tex]

2) [tex]-OH[/tex]

3) [tex]-CH_2SH[/tex]

4) [tex]-CH_2OH[/tex]

I hope it hepls!

The pressure in car tires is often measured in pounds per square inch (lb/in.2), with the recommended pressure being in the range of 25 to 45 lb/in.2. Suppose a tire has a pressure of 34.5 lb/in.2 . Convert 34.5 lb/in.2 to its equivalent in atmosphere

Answers

Answer:

2.35 atm  

Explanation:

1 atm = 14.70 lb/in²

[tex]p = \text{34.5 lb/in}^{2} \times \dfrac{\text{1 atm}}{\text{14.70 lb/in}^{2}} = \textbf{2.35 atm}[/tex]

Complete the sentence indicating the number of protons and electrons in the given ion. Match the numbers in the left column to the appropriate blanks in the sentences on the right. The ion P3− has The ion P 3 − has blank protons and blank electrons. protons and The ion P 3 − has blank protons and blank electrons. electrons.
What isotope has 17 protons and 18 neutrons? Enter the name of the element followed by a hyphen and the mass number (e.g., uranium-234).
Which element does X represent in the following expression: 4120X? Enter the chemical symbol of the element. X is the element symbol . Provide Feedback Correct. Followup. All bromine atoms have 35 protons. A neutral atom also has 35 electrons. The sum of the protons and neutrons gives the mass number, . End of followup.

Answers

Answer: (Chlorine-35)

Element X is Ca

Explanation:

Number of proton plus the number of electron gives the mass number.

Can the pH scale be utilized for all acids (Arrhenius, Bronsted-Lowery, and Lewis)? Give examples of substances from each definition category that can/cannot use the pH scale and explain your reasoning.

Answers

Explanation:

Before proceeding to answering the questions, let us go over some definitions.

pH scale: The pH scale measures how acidic or basic a substance is. The pH scale ranges from 0 to 14. A pH of 7 is neutral. A pH less than 7 is acidic.

pH stands for Potential of Hydrogen. It refers to the hydrogen ion concentration in a solution.

The keywords being; Hydrogen Ion concentration.

A Bronsted-Lowry acid is a chemical species that donates one or more hydrogen ions in a reaction.

A Lewis acid is  any substance that can accept a pair of nonbonding electrons. It is an electron pair acceptor.

An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons.

Based on the definitions of given above, it is obseved that both Bronsted lowry and arrhenius acids deals with hydrogen ions. Hence both of this acids can be measured using the pH scale. The  lewis acid on the other hand do not necessarily contain hydrogen ions, hence the pH scale cannot be utilized for it.

Examples includes;

Arrhenius acid; Nitric Acid – HNO3 etc

Lewis acid; boron trifluoride (BF3) and aluminum fluoride (AlF3) etc

Bronsted lowry acid; HCl etc

The pressure exerted by 1.5 mol of gas in a 13 L flask at 22 °C is ____ kPa

Answers

Answer:

282.7KPa

Explanation:

Step 1:

Data obtained from the question.

Number of mole of (n) = 1.5 mole

Volume (V) = 13L

Temperature (T) = 22°C = 22 + 273°C = 295K

Pressure (P) =..?

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Determination of the pressure exerted by the gas.

This can be obtained by using the ideal gas equation as follow:

PV = nRT

P = nRT /V

P = 1.5 x 0.082 x 295 / 13

P = 2.79atm.

Step 3:

Conversion of 2.79atm to KPa.

This is illustrated below:

1 atm = 101.325KPa

Therefore, 2.79atm = 2.79 x 101.325 = 282.7KPa

Therefore, the pressure exerted by the gas in KPa is 282.7KPa

Pressure is defined as the force exerted by the molecules colliding with the surface of the object and other surfaces. The ideal gas follows the general gas law equation, PV = nRT.

The pressure exerted by the gas is 282.7 KPa.

Given:

Pressure (P) = ?

Gas constant (R) = 0.082atm.L/Kmol  

Temperature (T) = 22°C = 22 + 273°C = 295K

Volume (V) = 13L

Number of mole of (n) = 1.5 mole

Now, using the ideal gas equation:

PV = nRT

Substituting the values, we get:

P x 13 = 1.5 x 0.082 x 295

P x 13 = 36.285

P = [tex]\dfrac{36.285}{13}[/tex]

Pressure = 2.79 atm.

Also, 1 atm = 101.32 KPa

2.79 atm = 2.79 x 101.32 = 282.7 KPa.

Thus, the pressure exerted by the gas molecules is 282.7 KPa.

To know more about ideal gas law, refer to the following link:

https://brainly.com/question/12124605

Combustion analysis of a 13.42-g sample of an unknown organic compound (which contains only carbon, hydrogen, and oxygen) produced 36.86 g CO2 and 10.06 g H2O. The molar mass of the compound is 288.38 g/mol . Part A Find the molecular formula of the unknown compound. Express your answer as a chemical formula.

Answers

Answer:

[tex]C_{18}H_{24}O_3[/tex]

Explanation:

Hello,

In this case, combustion analyses help us to determine the empirical formula of a compound via the quantification of the released carbon dioxide and water since the law of conservation of mass is leveraged to attain it. In such a way, as 36.86 g of carbon dioxide were obtained, this directly represents the mass of carbon present in the sample, thus, we first compute the moles of carbon:

[tex]n_{C}=36.86gCO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molC}{1molCO_2} =0.838molC[/tex]

Then, into the water one could find the moles of hydrogen:

[tex]n_{H_2O}=10.06gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O} =1.12molH[/tex]

Now, we compute the moles of oxygen by firstly computing the mass of oxygen:

[tex]m_{O}=13.42g-36.86gCO_2*\frac{12gC}{44gCO_2} -10.06 gH_2O*\frac{2gH}{18gH_2O} =2.25gO[/tex]

[tex]n_O=2.25gO*\frac{1molO}{16gO} =0.141molO[/tex]

Then, we have the mole ratio:

[tex]C_{0.838}H_{1.12}O_{0.141}\rightarrow C_6H_8O[/tex]

Whose molar mass is 12x6+1x8+16=96 g/mol, but the whole compound molar mass is 288.38, the factor is 288.38/96 =3, Therefore the formula:

[tex]C_{18}H_{24}O_3[/tex]

Regards.

Answer:

Molecular mass = [tex]C_{6} H_{8} O_{16}[/tex]

Explanation:

[tex](\frac{36.86gCO_{2} }{44g/molCO_{2} })[/tex] [tex](\frac{10.06gH_{2}O}{18g/molH_{2}O} )[/tex]

(0.8377mol of CO2) (0.556 mol of H2O)

mole ratio of CO2 to H2O = 1.5 : 1 ≅ 3 : 2

[tex](CO_{2} )_{3} , (H_{2} O)_{2}[/tex]

⇒ [tex](C_{3} H_{4} O_{8} )_{x}[/tex] = 288.38

(12 × 3 + 1 × 4 + 16 × 8)x = 288.38

168x = 288.38

x = 1.71 ≅ 2

∴ Molecular mass = [tex]C_{6} H_{8} O_{16}[/tex]

Olive oil has a density of 0.92g/ml. How much would 1.0 Liter of olive oil weigh in grams?

Answers

Answer:

9.2x10²g

Explanation:

Data obtained from the question include the following:

Density = 0.92g/ml

Volume = 1L = 1 x 1000 = 1000mL

Mass =..?

Density is simply defined as the mass of the substance per unit volume of the substance. Mathematically it can be represented as:

Density = Mass /volume.

Mass = Density x volume

Mass = 0.92 x 1000

Mass = 9.2x10²g.

Therefore, 1L of olive will weigh 9.2x10²g.

A boy reached his home by riding motorcycle within 5 minutes by travelling 8 km distance ,them what is his average velocity?​

Answers

Answer:

1.6

Explanation:

velocity=distance/time

=8/5

The potential in an electrochemical cell, E, is related to the Gibb's free energy change (ΔG) for the overall cell redox reaction: (1) ΔG0 = - n F E0 where n is the number of electrons transferred during the redox reaction, F is Faraday's constant (96,500 C / mol), and the superscript 0 indicates standard conditions (1 atm, 1 M concentrations, and 25 °C). Thus, a measurement of the cell voltage at standard conditions can be used to determine ΔG0. As an example, the following cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m) generates a cell voltage of +1.10 V under standard conditions. Calculate and enter delta G degree (with 3 sig figs) for this reaction in kJ/mol.

Answers

Answer:

Explanation:

As an example, the following cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m) generates a cell voltage of +1.10 V under standard conditions. Calculate and enter delta G degree (with 3 sig figs) for this reaction in kJ/mol.

Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m)

ΔG = ΔG° + RTInQ

Q = 1

ΔG = ΔG°

ΔG = =nFE°

n=no of electrons transfered.

E° = 1.1v

ΔG° = -2 * 96500 * 1.10

= -212300J

ΔG° =-212.3kJ/mol

Therefore, the ΔG° = -212.3kJ/mol

A titanium cube contains 3.10•10^23 atoms. The density of a titanium is 4.50g/cm^3. What is the edge length of the cube?

PLEASE HELPPP! :(

Answers

Answer:

1.76cm

Explanation:

We'll begin by calculating the mass of titanium that contain 3.10x10²³ atoms. This can be obtained as follow:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10²³ atoms. This implies that 1 mole of titanium also contains 6.02x10²³ atoms.

1 mole of titanium = 48g

Now, if 48g of titanium contains 6.02x10²³ atoms,

Then Xg of titanium will contain 3.10x10²³ atoms i.e

Xg of titanium = (48x3.10x10²³)/6.02x10²³

Xg of titanium = 24.72g

Next, we shall determine the volume of the titanium. This is illustrated below:

Density of titanium = 4.50g/cm³

Mass of titanium = 24.72g

Volume of titanium =..?

Density = Mass /volume

Volume = Mass /Density

Volume of titanium = 24.72g/4.50g/cm³

Volume of titanium = 5.49cm³

Finally we shall determine the edge length of the titanium cube as follow:

Volume = L³

5.49cm³ = L³

Take the cube root of both side

L = 3√(5.49cm³)

L = 1.76cm

Therefore, the edge length is 1.76cm

4. Alex is a soil specialist and he sells manure best suited for wheat. He goes to a village where farmers are
planning to sow wheat which grows best in clayey and loamy soil. He tests the soil sample and finds
that the soil is more suitable for the growth of cotton rather than wheat. He tells the villagers about
this despite knowing that they will not buy his manure.

(a) Why is clayey-loamy soil preferred for growing wheat?

(b) Which value is shown by Alex?

Please answer the question fast

Answers

Answer:

Explanation:

1) Clayey-loamy soil tends to be excellent at retaining water which is critical for proper growth of wheat thus this kind of soil is preferred.

2) Alex is showing honesty as he informing the villagers about the actual truth and reality (he is not basing his answers on judgements rather he is basing it on scientific knowledge and being honest about it)

If you made a three-dimensional model of an atom and its nucleus, how would you represent the atom? 7th grade

Answers

Answer:

it shows the breakdown of the atom

Explanation:

it will show it molecularly

he Punnett square shows the possible genotype combinations for the offspring of two parents. What are the genotypes of the parents? Gg and Gg GG and GG gg and gg Gg and gg


Answers

The genotypes of the parents are Gg and Gg.

Answer:

Its A! Gg and Gg

Explanation:

A flexible container at an initial volume of 4.11 L contains 6.51 mol of gas. More gas is then added to the container until it reaches a final volume of 11.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Answers

Answer:

The added mole will be "11.388 moles".

Explanation:

The given values are:

Initial volume,

V₁ = 4.11 L

Final volume,

V₂ = 11.3 L

Number of moles,

n₁ = 6.51

On applying Avogadro's law,

⇒  [tex]\frac{V_{1}}{n_{1}}=\frac{V_{2}}{n_{2}}[/tex]

On putting the estimated values, we get

⇒  [tex]\frac{4.11}{6.51} =\frac{11.3}{n_{2}}[/tex]

On applying cross-multiplication, we get

⇒  [tex]4.11 \ n_{2}=11.3\times 6.51[/tex]

⇒  [tex]4.11 \ n_{2}=73.563[/tex]

⇒  [tex]n_{2}=\frac{73.563}{4.11}[/tex]

⇒  [tex]n_{2}=17.898 \ moles[/tex]

So that the number of moles at added gas will be:

[tex]=17.898-6.51[/tex]

[tex]=11.388 \ moles[/tex]

Automobile battery acid is 38% H2SO4 and has a destiny of 1.29g/ml. Calculate the molality and the molarity of this solution. ​

Answers

Answer:

[tex]M=5.0M\\\\m=6.2m[/tex]

Explanation:

Hello,

In this case, 38 % is commonly a by mass concentration, meaning that we have 38 grams of solute (sulfuric acid) per 100 grams of solution (water+sulfuric acid):

[tex]38\%=\frac{m_{H_2SO_4}}{m_{H_2SO_4}+m_{H_2O}}[/tex]

Hence, we compute the moles of sulfuric acid in 38 grams by using its molar mass (98 g/mol):

[tex]n_{H_2SO_4}=38g*\frac{1mol}{98g}=0.39mol H_2SO_4[/tex]

Next, the volume of the solution in litres by using the density of the solution:

[tex]V_{solution}=100g*\frac{1mL}{1.29g}*\frac{1L}{1000mL} =0.0775L[/tex]

This is done since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in litres, thus we have:

[tex]M=\frac{n}{V}=\frac{0.38mol}{0.0775L}=5.0M[/tex]

On the other hand, the molality is defined as the ratio of the moles of the solute to the mass of the solvent in kilograms, thus, we compute the mass of water (solvent) as shown below:

[tex]m_{H_2O}=100g-38g=62g*\frac{1kg}{1000g}=0.062kg[/tex]

So compute the molality:

[tex]m=\frac{n_{solute}}{m_{solvent}}=\frac{0.39mol}{0.062kg}=6.2m[/tex]

Regards.

1. The molarity of the solution is 5 M

2. The molality of the solution is 6.26 M

Let the mass of the solution be 100 g.

Therefore, the mass of 38% of H₂SO₄ in the solution is 38 g.

Next, we shall determine the mole of 38 g of H₂SO₄.

Mass of H₂SO₄ = 38 gMolar mass of H₂SO₄ = (2×1) + 32 + (16×4) = 98 g/mol Mole of H₂SO₄ =?

Mole = mass / molar mass

Mole of H₂SO₄ = 38 / 98

Mole of H₂SO₄ = 0.388 mole

Next, we shall determine the volume of the solution

Mass of solution = 100 gDensity of solution = 1.29 g/mL

Volume of solution =?

Volume = mass / density

Volume of solution = 100 / 1.29

Volume of solution = 77.52 mL

1. Determination of the molarity of the solution

Mole of H₂SO₄ = 0.388 mole Volume of solution = 77.52 mL = 77.52/1000 = 0.07752 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.388 / 0.07752

Molarity = 5 M

2. Determination of the molality of the solution

Mole of H₂SO₄ = 0.388 mole Mass of H₂SO₄ = 38 gMass of solution = 100 gMass of water = 100 – 38 = 62 g Mass of water = 62 / 1000 = 0.062 KgMolality =?

Molality = mole / mass (Kg) of water

Molality = 0.388 / 0.062

Molality = 6.26 M

Learn more about concentration of solution:

https://brainly.com/question/12154684

Determine the number of moles of air present in 1.35 L at 750 torr and 17.0°C.
Which equation should you use?


Answers

Answer:

0.0560 mol

Explanation:

You need to use the ideal gas law equation:

[tex]PV = nRT[/tex]

P = 750 torr

V = 1.35 L

n = moles

R = 62.364 L torr [tex]mol^{-1}[/tex] [tex]K^{-1}[/tex]

T = 17.0 ˚C + 273.15 = 290.15 K

Rearranging the equation for n:

[tex]n= \frac{PV}{RT}[/tex]

[tex]n= \frac{(750)(1.35)}{(62.364)(290.15)}[/tex]

n = 0.0560 mol

Answer:

n=PV/RT

Explanation:

on edge 2020

What is the color of litmus solution in sodium hydroxide?

Answers

Answer:

Sodium Hydroxide turns blue litmus red .

Assign priorities in the following set of substituents according to Cahn-Ingold-Prelog rules. -NH2 -CH2OH -OH -Br A B C D (Provide your ranking through a string like abcd, starting with the one with the highest priority. Your answer does not need to be capitalized.)

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Complete Question

The complete question is shown on the first uploaded image

Answer:

[tex]-SH \ \ A[/tex]

[tex]-NH_2 \ \ B[/tex]

[tex]-COOH \ \ C[/tex]

[tex]-CH_3 \ \ D[/tex]

Explanation:

Now to correctly assign priorities in the following set of substituents we need to consider the molecular weight of the atom that is been directly attached to  the carbon bond

Now an atom with a higher molecular weight will imply that the substituent will have the the highest priority

So  S (32.065 u)with a the highest molecular weight implies that -SH has the highest priority

Next is   N with molecular weight(14.0067 u) implies that -[tex]NH_2[/tex] will  have the next priority

Next is   O with molecular weight(15.999 u) implies that [tex]-COOH[/tex] will  have the next priority

The Last is  H with molecular weight(1.00784 u) implies that  [tex]-CH_3[/tex] will  have the next priority

What is the kinetic energy,in J,of an Ar atom moving at a speed of 650 m/s

Answers

Answer:

1.40 × 10⁻²⁰ J

Explanation:

Step 1: Calculate the mass of 1 atom of argon

The molar mass of argon is 39.95 g/mol, that is, 6.02 × 10²³ atoms of Ar have a mass of 39.95 g. We can use this relation to find the mass of 1 atom of Ar.

[tex]\frac{39.95g}{1mol} \times \frac{1mol}{6.02 \times 10^{23}atom } =6.64 \times 10^{-23}g/atom[/tex]

Step 2: Convert the mass of 1 atom of argon to kilograms

We will use the relationship 1 kg = 1,000 g.

[tex]6.64 \times 10^{-23}g \times \frac{1kg}{1,000g} =6.64 \times 10^{-26}kg[/tex]

Step 3: Calculate the kinetic energy of 1 atom of Ar moving at 650 m/s

[tex]E=\frac{1}{2} \times m \times v^{2} = \frac{1}{2} \times 6.64 \times 10^{-26}kg \times (650m/s)^{2} = 1.40 \times 10^{-20}J[/tex]

The kinetic energy of an Ar atom at a speed of 650 m/s is 1.40 × 10⁻²⁰ J

Kinetic Energy:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity:

K.E = [tex]\frac{1}{2}[/tex] x [tex]m[/tex] x [tex]v^{2}[/tex]

Step 1: Calculate the mass of 1 atom of argon

The molar mass of argon is 39.95 g/mol, that is, 6.02 × [tex]10^{-23}[/tex] atoms of Ar have a mass of 39.95 g. We can use this relation to find the mass of 1 atom of Ar.

[tex]\frac{39.95 g}{1 mol} * \frac{1 mol}{1,000 g} = 6.64 * 10^{-26} g/ atom[/tex]  

Step 2: Convert the mass of 1 atom of argon to kilograms

We will use the relationship 1 kg = 1,000 g.

6.64 x [tex]10^{-23}[/tex] g x [tex]\frac{1 kg}{1,000g}[/tex] = 6.64 x [tex]10^{-26}[/tex] kg

Step 3: Calculate the kinetic energy of 1 atom of Ar moving at 650 m/s

E= [tex]\frac{1}{2}[/tex] x [tex]m[/tex] x [tex]v^{2}[/tex] = [tex]\frac{1}{2}[/tex] x 6.64 x [tex]10^{-26}[/tex] kg x (650 m/s)² = 1.40 x [tex]10^{-20}[/tex] J

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