All the edges of the object in the diagram are equal in length. The object is cut by a vertical plane containing A and B and bisecting two of the horizontal edges. What is the shape of the cross-section resulting from the cut?

Answer:

39

Step-by-step explanation:

Okay so there are 52 cards in a deck and there are 4 of each card. 4 kings 4 Queens 4 Jacks 4 Ace 4 Twos 4 Threes 4 fours 4 fives 4 sixes 4 sevens 4 eights 4 nines 4 tens. One from each group is a heart there are 13 groups so therefore subtract 13 from 52.

Answer:

35

Step-by-step explanation:

Percent= (part ÷ whole)x100=21/60x100=(0.35)x100=35%

The solution set is 1 ≥ f ≥ -4, and the correct number line is the one in option A.

Here we have the inequality:

-1 ≤ -2f + 1 ≤ 9

To solve this, we need to isolate the "f" on the middle.

First, we can subtract 1 in both sides to get:

-2  ≤ -2f ≤ 8

Now we need to divide both sides by -2, remember that this will change the direction of the symbols:

-2/-2 ≥ f ≥ 8/-2

1 ≥ f ≥ -4

So we need to have a line that starts at -4 and ends at 1, the correct option is number line A.

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Answer:

B. Matter

Explanation:

When rocks break down and become smaller ex: mountains eventually becoming sand, the matter does not disappear or get destroyed, it becomes smaller particles, but the matter is always preserved.

Hope It Helps!!!

Answer:

matter

Step-by-step explanation:

The conservation of matter states that

Here big matters gets down into smaller pieces

but they are not destroyed

Answer:

c ×=4, only

Step-by-step explanation:

4*-8×+16=0

16-32=-16

-16=-16

Answer:

D. x=4 only

Step-by-step explanation:

You can solve using the quadratic equation which is [tex]x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]

where in this case a=1, b=-8, and c=16. But there is any easier way to solve the equation. You can solve by completing the square which consists of moving the constant to the right side and then adding [tex](\frac{b}{2})^2[/tex]. To both sides that way you can rewrite the left side as a perfect square binomial. This is because [tex](x+b)^2[/tex] will expand to [tex]x^2 + 2xb + b^2[/tex]. So when you add [tex](\frac{b}{2})^2[/tex] to both equations. You're able to rewrite the left side as [tex](x+(\frac{b}{2}))^2[/tex]. Because once you expand it out, it becomes [tex]x^2 + 2(\frac{b}{2})x + (\frac{b}{2})^2[/tex]. Which simplifies to [tex]x^2 + bx + (\frac{b}{2})^2[/tex] which is the original equation. In this case there is no need to move the constant, which in this case is 16, to the other side. Since if you calculate the value of (-8/2)^2 it's equal to 16! So this can already be written as a perfect square binomial.

So the equation becomes

[tex]0 = (x+\frac{b}{2})^2[/tex]

Plug values in

[tex]0 = (x+(-\frac{8}{2}))^2[/tex]

Simplify

[tex]0 = (x-4)^2[/tex]

Take the square root of both sides

[tex]0 = x-4[/tex]

Add 4 to both sides

[tex]4 = x[/tex]

Answer:

0.93

Step-by-step explanation:

Answer:

Not enough information.  See below.

Step-by-step explanation:

Z-M = 2

x= 33.5, then Z = ?

How does x relate to Z or M?  Is the Z-M= 2 equation correct?  Or is it M=33.5?

Answer:

The real numbers include all the rational numbers, such as the integer −5 and the fraction 4/3, and all the irrational numbers, such as 2 (1.41421356..., the square root of 2, an irrational algebraic number).

Your question is incomplete. Below you will find the missing content.

Which series of transformations will not map figure H onto itself?

A. O(x+0, y-2), reflection over y = 1

B. O(x+2, y-0), reflection over x=3

C. O(x+3, y+3), reflection over y = -x +7

D. O(x-3, y-3), reflection over y = -x +2

The correct option is Option D: the series of transformation O(x-3, y-3), reflection over y = -x +2 will not map figure H onto itself.

Here given a square with its 4 vertices at coordinates (2,1), (1,2), (2,3) and (3,2).

By checking all the options

Option A:

1st transformation (x+0, y-2) will map 4 vertices of the square into points of coordinates such as

(2,1) → (2,-1)

(1,2) → (1,0)

(2,3) → (2,1)

(3,2) → (3,0)

next transformation which is the reflection over y=1 gives the coordinates (x,2-y)

(2,-1) → (2,3)

(1,0) → (1,2)

(2,1) → (2,1)

(3,0) → (3,2)

These new points are exactly the same as the vertices of the initial square.

Option B:

1st transformation (x+2, y-0) will map 4 vertices of the square into points of coordinates such as

(2,1) → (4,1)

(1,2) → (3,2)

(2,3) → (4,3)

(3,2) → (5,2)

next transformation which is the reflection over x=3 gives the coordinates (6-x,y)

(4,1) → (2,1)

(3,2) → (3,2)

(4,3) → (2,3)

(5,2) → (1,2)

These new points are exactly the same as the vertices of the initial square.

Option C:

1st transformation (x+3, y+3) will map 4 vertices of the square into points of coordinates such as

(2,1) → (5,4)

(1,2) → (4,5)

(2,3) → (5,6)

(3,2) → (6,5)

next transformation which is the reflection over y=-x+7 gives the coordinates such as

(5,4) → (3,2)

(4,5) → (2,3)

(5,6) → (1,2)

(6,5) → (2,1)

These new points are exactly the same as the vertices of the initial square.

Option D:

1st transformation (x-3, y-3) will map 4 vertices of the square into points of coordinates such as

(2,1) → (-1,-2)

(1,2) → (-2,-1)

(2,3) → (-1,0)

(3,2) → (0,-1)

next transformation which is the reflection over y=-x+2 gives the coordinates such as

(-1,-2) → (4,3)

(-2,-1) → (3,4)

(-1,0) → (2,3)

(0,-1) → (3,2)

These new points are not matching with the vertices of the initial square.

Therefore the correct option is Option D: O(x-3, y-3), reflection over y = -x +2 will not map figure H onto itself.

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Answer:

The first option.

Explanation:

Since these numbers are given in scientific notation, we must first look at the exponent to determine whether or not it's big or small. Negative exponents are less, so we start with that. Immediately, that eliminates the second and third options as -8 is less than -6 and 3. The last two numbers given in the first and last options, however, both have 3 as the exponent. Now, we look at the number given in front. 2.5 is less than 7, so we know that the first option is in order from least to greatest.

Answer:

x < 3

Step-by-step explanation:

The last step is to divide by -2. When you divide by a negative number you must reverse (flip) the inequality symbol.

-6 < -2x

-6/-2 > -2x/-2

3 > x

This is the same as

x < 3 (see the pointy side pointing at the x and the wide open side facing the 3)

Because we have a vertical asymptote at x = -1, we conclude that the correct option is C.

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Now, In the graph,

we can see that we have a vertical asymptote at x = -1.

Hence, This means that the denominator of the rational equation becomes zero when x = -1.

So the equation must be:

⇒ y = 1 / (x + 1)

Here, The denominator is x + 1, and as expected, it becomes zero when, x = -1.

Then, we conclude that the correct option is C.

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Answer:

cbrt(x+1)-3=y

Step-by-step explanation:

The inverse of a function is when the domain and range are swapped. So to find the inverse simply swap the x and y in the equation and then solve for y.

[tex]y = (x+3)^3-1\\x=(y+3)^3-1\\x+1=(y+3)^3\\\sqrt[3]{x+1}=y+3\\\sqrt[3]{x+1}-3=y[/tex]

Answer:

C.

Step-by-step explanation:

The reds are counting up in whole numbers by one integer.

Hope this helps!

If not, I am sorry.

Answer + Step-by-step explanation:

y = mx + b where m is the slope and b is the y-intercept

y = x + 3 where m = 1 is the slope and b = 3 is the y-intercept

Table of some points:

| x | 0 | 1 | 2 | 3 |

| y | 3 | 4 | 5 | 6 |

when x = 0, y = 0 + 3 and y = 3

when x = 1, y = 1 + 3 and y = 4

when x = 2, y = 2 + 3 and y = 5

Graph:

The sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.

The coloured portion of the circle is known as a sector. The formula for calculating the area of a sector is given as:

Area of a sector = θ/360 * πr²

where

θ is the central angle

πr² represents the area of a circle.

Therefore the best statement that explains the formula is expressed as the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.

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Answer:

Its A edge 2023

Step-by-step explanation:

the required perimeters are 26 inch, 48 inch, 34 inch and 64 inch respectively.

Perimeter, is the measure of the figure on its circumference.

1. perimeter for a cross section parallel  to base of right rectangular prisms that is 10 inches long, 3 inches wide and 14 inches high:
length = 10 inches and width = 3 inch
The perimeter of that cross section is given by.
= 2 x length + 2 x width
=  2 x 10 + 2 x 3
= 20 + 6
= 26 inches

2.  perimeter of cross section  perpendicular to the base of a cube with 12 inch edge is given by.
= 4 x length
= 4 x 12
= 48 inches

3. perimeter of a cross section perpendicular to the base and passing through the diagonal of the base the right rectangle is given by.
length = 5; width = 12; height = 4; diagonal = 13;
perimeter = 2 x height + 2 x diagonal
                 = 2 x 4 + 2 x 13
                 =  34  inches

4. perimeter of a cross section of a cube having edges of 16 inches each.
   perimeter = 4 x edge
                    =  4 x 16

                    =  64

Thus, The required perimeter of the cross section are 26, 48, 34, 64 all in inches.

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The range of the function lies between (0,8) to (1.5,1.25).

Range and Domain. The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.

The given function is:-

f(x) = 3x² -9x + 8

The value of the range will be from (0,8) to ( 1.5,1.25). When we plot the graph of the function the value of the range lies between the points (0,8) to ( 1.5,1.25). The graph is attached with the answer.

The domain of the function will be all the values of the real numbers for the function ranges from ( 0, ∞ ).

Therefore the range of the function lies between (0,8) to (1.5,1.25).

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Answer:

The answer is 0.45 pounds for an apple and 0.3 pounds for a pear

Step-by-step explanation:

Answer:

Cost of each apple: [tex]0.45[/tex].

Cost of each pear: [tex]0.30[/tex].

Step-by-step explanation:

Let [tex]x[/tex] denote the cost of each apple. Let [tex]y[/tex] denote the cost of each pear.

The question states that the cost of [tex]4[/tex] apples and [tex]3[/tex] pears is [tex]2.70[/tex]. Thus:

[tex]4\, x + 3\, y = 2.70[/tex].

Likewise, since the cost of [tex]2[/tex] apples and [tex]5[/tex] pears is [tex]2.40[/tex]:

[tex]2\, x + 5\, y = 2.40[/tex].

Solve this system of equations for [tex]x[/tex] and [tex]y[/tex] to find the price of each fruit.

[tex]\left\lbrace \begin{aligned} & 4\, x + 3\, y = 2.70 \\ & 2\, x + 5\, y = 2.40\end{aligned}\right.[/tex].

Multiply both sides of the equation [tex]2\, x + 5\, y = 2.40[/tex] by [tex]2[/tex] to match the coefficient of [tex]x[/tex] in the first equation:

[tex]\left\lbrace \begin{aligned} & 4\, x + 3\, y = 2.70 \\ & (2\times 2)\, x + (2 \times 5)\, y = (2 \times 2.40)\end{aligned}\right.[/tex].

[tex]\left\lbrace \begin{aligned} & 4\, x + 3\, y = 2.70 \\ & 4\, x + 10\, y = 4.80 \end{aligned}\right.[/tex].

Substitute the first equation from the new equation to eliminate [tex]x[/tex] and solve for [tex]y[/tex]:

[tex]\begin{aligned}& 4\, x + 10\, y - (4\, x +3\, y) = 4.80 - 2.70\end{aligned}[/tex].

[tex]10\, y - 3\, y = 2.10[/tex].

[tex]7\, y = 2.10[/tex].

[tex]y = 0.30[/tex].

Substitute [tex]y = 0.30[/tex] into an equation from the original system to eliminate [tex]y[/tex] and solve for [tex]x[/tex].

[tex]2\, x + 5\, y = 2.40[/tex].

[tex]2\, x + 5 \times 0.30 = 2.40[/tex].

[tex]2\, x = 0.90[/tex].

[tex]x = 0.45[/tex].

Thus, [tex]x = 0.45[/tex] and [tex]y = 0.30[/tex].

In other words, the price of each apple would be [tex]0.45[/tex]. The price of each pear would be [tex]0.30[/tex].

Answer:

Simultaneous equations are two or more algebraic equations that share variables e.g. x and y . They are called simultaneous equations because the equations are solved at the same time. Each of these equations on their own could have infinite possible solutions.

The value of the expression 2 2/3 - (-3 2/6) is 6

The expression is given as:

2 2/3 - (-3 2/6)

Open the bracket

2 2/3 + 3 2/6

Express as improper fractions

8/3 + 20/6

Rewrite as:

16/6 +20/6

Evaluate the sum

36/6

Evaluate the quotient

6

Hence, the value of 2 2/3 - (-3 2/6) is 6

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Step-by-step explanation:

please mark me as brainlest

Answer:

135

Step-by-step explanation:

2x²/x + x(100 - 15x)

If x = 5 ;

2(5)²/5 + 5(100 - 15×5)

= 2×25/5 + 5(100 - 75)

= 2 × 5 + 5 × 25

= 10 + 125

= 135

Answer:

-4

+3

12

-0.5, 12.25

x = -0.5

Step-by-step explanation:

The x intercepts are the values of x when y = 0 ie the roots of the equation
[tex]-x^2 -x +12 = 0[/tex]

or

[tex]x^2 + x - 12 = 0[/tex]

We can re-write the above as:
(x+4) (x-3) = 0
This gives the two roots as x = -4 and x = +3. Leftmost (smallest) root is -4 and rightmost(largest) root is +3

y intercept is when x = 0. Plugging into the original equation, y value at x = 0 is 12

Vertex x value is given by the formula -b/2a where a is the coefficient of x^2 and b the coefficient of x

Here a = -1, b= -1 so vertex x value = - (-1)/(-1).2 = - 1/2 = -0.5

Plugging this value of x into the original function gives the vertex y value
[tex]y = - (0.5^{2}) - (-0.5) + 12\\= -0.25 + 0.5 + 12 = 12.25[/tex]

The line of symmetry is the vertical line corresponding to the vertex x value so line of symmetry is at x = -0.5

The graph of the quadratic function shows these values

Answer:

65

Step-by-step explanation:

its simple math

Answer:

x+5=12.          x = 7,

7x=21.            x = 3,

b-2/3=5/6.     b = 1.5,

3/4x=6x=8.    x = 1/3,

45=3(x+1).      x = 14,

22.5+1.5x.      x = 15,

20+(5•9).        $65

Step-by-step explanation:

Answer:

There were 120 marbles to start

Step-by-step explanation:

Let x be the number of marbles at the start

x* 5/12 = number of marbles given away

1 -5/12 = 7/12 = fraction of marbles left

x * 7/12 = number of marbles left

x * 7/12 = 70

Multiply each side by 12/7

x *7/12 * 12/7 = 70 * 12/7

x =120

There were 120 marbles to start

Answer:

Step-by-step explanation:

I'm not sure exactly what you're trying to ask
but r and s are parallel
and I'm assuming the 3rd line is line m, line m is not parallel to any line
and angles A and B are equal

First term f = 1

If first four terms are f, f + d, f + 2d, f + 3d

f + f + d + f + 2d + f + 3d = 100

4f + 6d = 100 (divided by 2 , both sides )

2f + 3d = 50

2 + 3d = 50

3d = 50 – 2

3d = 48

d = 48/3

d = 16

The arithmetic sequence is 1, 17, 33, 49, ………….

Answer:

[tex]\sf\large\blue{\underbrace{\red{itz \: jass*}}}:[/tex]

Step-by-step explanation:

[tex]\sf\large\green{\underbrace{\red{hlo \: \: sat \: shri \: akal \: ji \: \: \: *}}}:[/tex]

Answer:

3/5 ..................................  6/9

Step-by-s4tep explanation:

Answer:

300 meters per minute

Step-by-step explanation:

Step 1

Determine the fraction of the total distance for each part of the race.

Given:

[tex]\begin{aligned} \implies \sf 2nd\:part & = \sf \dfrac{2}{5}\:of\:remaining\:distance\\ & = \sf \dfrac{2}{5} \times\left(1-\dfrac{4}{9}\right)\\& = \sf \dfrac{2}{9}\:of\:total\:distance\end{aligned}[/tex]

[tex]\begin{aligned}\implies \sf 3rd\:part & = \sf 1-1st\:part-2nd\:part\\& = \sf 1-\dfrac{4}{9}-\dfrac{2}{9}\\& = \sf \dfrac{1}{3}\:of\:total\:distance\end{aligned}[/tex]

Step 2

Determine the distance of the third part of the race.

Given:

[tex]\begin{aligned}\sf Distance & = \sf speed \times time\\& = \sf 300 \times 15\\& = \sf 4500 \:\:meters\end{aligned}[/tex]

Step 3

If the third part of the race (which is 1/3 of the total distance) is 4500m, then the distance of the whole race is:

[tex]\begin{aligned} \sf Total\:distance & = \sf 4500 \times 3\\& = \sf 13500\:meters \end{aligned}[/tex]

Step 4

Determine the distance of the 1st part of the race:

[tex]\begin{aligned}\sf Distance\:of\:1st\:part\:of\:race & = \sf \dfrac{4}{9} \:of\:total\:distance\\& = \sf \dfrac{4}{9} \times 13500\\& = \sf 6000\:meters \end{aligned}[/tex]

Step 5

Determine the speed of the 1st part of the race:

Given:

[tex]\begin{aligned}\sf Speed\:of\:1st\:part\:of\:race & = \sf \dfrac{distance}{time}\\& = \sf \dfrac{6000}{20}\\ & = \sf 300\:meters\:per\:minute\end{aligned}[/tex]

Answer:

g(b-3) = -b + 7

Step-by-step explanation:

Plug in the value (b-3) as x into the equation

g(b-3) = -(b-3) + 4

distribute the negative sign

g(b-3) = -b + 3 + 4

combine like terms

g(b-3) = -b + 7

There are 16807 number of ways the passengers to be assigned a floor and there are 2520 number of ways the passengers to be assigned a floor but no two passengers are on the same floor.

Given that an elevator starts with five passengers and stops at the seven floors of a building.

From the given information, the total number of floors n=7.

The number of passengers r = 5.

(a) Compute the number of ways that 5 passengers can be assigned to seven floors.

Here, repetition is allowed.

From the known information, if r numbers are selected from n number of observations then the total number of observations that can be drawn from n number of observations is [tex]n^r[/tex].

If 5 passengers can be assigned to seven floors is 7⁵ = 16807.

(b) Compute the number of ways that the passengers to be assigned a floor but no two passengers are on the same floor.

Here, repetition is not allowed.

If 5 passengers can be assigned to seven floors but no two passengers are on the same floor is 7x6x5x4x3 = 2520.

Hence, the number of ways that 5 passengers can be assigned to seven floors is 16807, and the number of ways that the passengers to be assigned a floor but no two passengers are on the same floor is 2520.

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