A water turbine is to be designed to produce 27MW when running at 93.7 rev/min
under a head of 16.5m. A model turbine with an output of 37.5kW is tested under
dynamically similar conditions with a head of 4.9m . Calculate the:
a. model speed; b. scale ratio; c. assuming a model efficiency of 88%, estimate the volume
flow rate through the model; and d. if it is estimated that the force on the thrust bearing of
the full-size machine is 7.0GN , determine the bearing thrust of the model.

Answers

Answer 1

The Answers for the given question are as follow:

a. The model speed is approximately 31.62 rev/min.

b. The scale ratio is approximately 0.0417.

c. The estimated volume flow rate through the model is approximately 943.44 m^3/s.

d. The bearing thrust of the model is approximately 9.72 kN.

To calculate the required values for the water turbine model, we can utilize the concept of dynamic similarity.

a. To find the model speed, we can use the principle of geometric similarity, which states that the ratio of speeds is equal to the ratio of the square roots of the head. Thus:

  Model speed = (√(Model head))/(√(Full-size head)) * Full-size speed

              = (√4.9/√16.5) * 93.7 rev/min

              = 31.62 rev/min

b. The scale ratio can be determined using the equation:

  Scale ratio = (√(Model power))/(√(Full-size power))

             = (√37.5kW)/(√27MW)

             ≈ 0.0417

c. To estimate the volume flow rate through the model, we can use the power equation:

  Model power = (Model efficiency) * (Volume flow rate) * (Model head) * (Gravity)

  37.5kW = 0.88 * (Volume flow rate) * 4.9m * (9.81m/s^2)

  Solving for the volume flow rate:

  Volume flow rate = 37.5kW / (0.88 * 4.9m * 9.81m/s^2)

                   ≈ 943.44 m^3/s

d. To calculate the bearing thrust of the model, we can use the principle of force similarity:

  Bearing thrust model = (Model power / Full-size power) * Full-size bearing thrust

                      = (37.5kW / 27MW) * 7.0GN

                      ≈ 9.72kN

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