(a) The frequency observed by the passenger on the east-bound train when they are 1000 m apart is 675.5 Hz.
(b) After 10 seconds, the frequency observed by the passenger on the east-bound train will be greater than the frequency observed when they are 1000 m apart.
Observed frequency
The frequency observed by the passenger on east-bound train is calculated by applying Doppler shift formula.
[tex]f = f_0(\frac{v \pm v_0}{v\pm v_s} )[/tex]
where;
f is observed frequencyf₀ is original frequency or source frequencyv is speed of soundv₀ is speed of observer (positive when moving towards source)vs is source frequency (negative when moving towards observer)when the two trains are 1000 m apart[tex]f = 600(\frac{343 +15}{343-25} )\\\\f = 675.5 \ Hz[/tex]
The frequency observed by the passenger increases with decrease in distance between the two trains.
Thus, after 10 seconds, the frequency observed by the passenger on the east-bound train will be greater than the frequency observed when they are 1000 m apart.
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Against the park ranger's advice, a visitor at a national park throws a stone horizontally off the edge of a 86 m high cliff and it lands a distance of 89 m from the edge of the cliff, narrowly missing a visitor below.
What was the initial horizontal velocity of the rock, in m/s? You can round your answer to the hundredth place and use g ≈ 10 m/s2.
The initial horizontal velocity of the rock, in m/s is 21.241 m/s.
What is projectile?When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.
Time taken by the stone to reach the ground is
t = √2h/g
t = √(2x 86)/9.81
t = 4.19s
The horizontal velocity is
V(x) = Horizontal distance traveled / Time taken t
Put the values, we get
V(x) = 89 m/4.19 s
V(x) = 21.241 m/s
Thus, the horizontal velocity is 21.241 m/s
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A cliff diver jumps off a 57m cliff and lands in the water 4.3 seconds later, a distance of 2.15m from the cliffs edge. What was the magnitude and direction of his starting velocity
The cliff diver jumps off with a velocity of 7.85m/s at an angle of 86° with respect to the ground.
The height of the cliff = 57m
The horizontal distance from the cliff = 2.15m
The time is taken = 4.3s
The acceleration due to gravity g = 9.81m/s²
Consider the vertical y-axis
d = 57mWe know the equationd = ut +1/2gt²
57 = u (4.3) + 1/2 (9.81) (4.3)²
57 = 4.3u + 90.69
u = -7.836m/s
The y component of initial velocity is in the upwards direction
Consider the horizontal x-axis
d = 2.15 mWe know the equation, in case of no accelerationd = ut
2.15 = u (4.3)
u = 0.5 m/s
The net velocity is the square root of the summation of the squares of the x and y components of velocity
Net velocity = 7.85m/s
For the direction, tan θ = y/x = 15.67
θ= 86°
So the cliff diver jumps off with a velocity of 7.85m/s at an angle of 86° with respect to the ground.
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which best describes series
Answer:
a single closed path of electrical components including a voltage source
A mother and her 35.0 -kg child are riding an escalator to the third level of a shopping mall. If the child's gravitational potential energy increases by 3773 J, determine the increase in potential energy of his mother if her mass is 56.0 kg.
The increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.
What is gravitational potential energy?The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.
The potential energy increases by 3773 J
PE₂-PE₁=mg(h₂-h₁)
3773 J = 35.0 × 9.81 × (h₂-h₁)
(h₂-h₁) = 10.98
Case 2 ;
ΔPE =?
ΔPE=mg(h₂-h₁)
ΔPE=56.0 × 9.81 ×10.98
ΔPE=6031.97 J.
Hence, the increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.
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Calculate the time period of simple pendulum whose length is 98.2cm
The time period resulting in oscillations will be 1.986 seconds.
What is the period of oscillation?The period is the amount of time it takes for a particle to perform one full oscillation. T is the symbol for it. Taking the reciprocal of the frequency yields the frequency of the oscillation.
The time period of the oscillation is;
[tex]\rm T = 2 \pi\sqrt{\frac{L}{g}} \\\\ \rm T = 2 \times 3.14 \times \sqrt{ \frac{98.2 \ \times 10^{-2} \ m}{9.81 \ m/s^2}} \\\\ T= 1.986 \ sec[/tex]
Hence the time period resulting oscillations will be 1.986 seconds.
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What is the volume of the cone?
Answer:
42.417 cm³
Explanation:
The formula to find the volume of a cone is :
V = [tex]\frac{1}{3}[/tex] × π r² h
Here,
r ⇒ radius ⇒ 3 cm
h ⇒ height ⇒ 4.5 cm
Let us find it now.
V = [tex]\frac{1}{3}[/tex] × π r² h
V = [tex]\frac{1}{3}[/tex] × π × 3 × 3 × 4.5
V = [tex]\frac{1}{3}[/tex] × π × 9 × 4.5
V = [tex]\frac{1}{3}[/tex] × π × 9 × 4.5
V = [tex]\frac{1}{3}[/tex] × π × 40.5
V = [tex]\frac{1}{3}[/tex] × 3.142 × 40.5
V = [tex]\frac{1}{3}[/tex] × 127.251
V = 42.417 cm³
A car accelerates at a rate of 8.8 m/s² with a force from the tires of 15,840 N.
What is the mass of the car?
Answer:
1,800kg
Explanation:
Force = Mass x Acceleration
F = m x a
15840N = m x 8.8
8.8 x m = 15840
m = 15840/8.8
= 1,800kg
Answer:
[tex]\displaystyle 1800\:kg.[/tex]
Explanation:
[tex]\displaystyle am = F_{net} \\ \\ \frac{15840}{8,8} = \frac{8,8m}{8,8} \\ \\ \boxed{1800 = m}[/tex]
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how does the temperature of water change when it is heated on a stove top and then begins to boil?
Answer:
C
Explanation:
First the water heats up to the boiling point ( temp increases)
then, as it boils it remains at constant temp ( boiling point)
The temperature of water changes when it is heated as it increases first and then remains constant. So, option C is correct.
What is boiling?When a liquid is heated to its boiling point, the temperature at which the vapor pressure of the liquid equals the pressure that the surrounding environment exerts on the liquid, boiling is the fast vaporization of the liquid that takes place.
Boiling can be divided into two primary categories: nucleate boiling, in which tiny bubbles of vapor develop at specific locations, and critical heat flux boiling, in which the boiling surface is heated above a critical temperature and a film of vapor forms on the surface. Transition boiling is an unstable, transitional kind of boiling that contains both sorts of components. Due to the decreased air pressure found at higher elevations, water's boiling point, which is 100 °C or 212 °F, is lower.
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A velocity-time graph can give you
A. Displacement of the moving object
B. Acceleration, displacement, and velocity.
C. Velocity of the moving object
D. Acceleration of the moving object
Answer:
A). Velocity time graph gives displacement..The area under V-t graph gives displacement.
More to know -
Velocity = speed/ time
it's speed with direction.
acceleration = rate of change of velocity
A velocity-time graph provides information about the motion of an object over time Acceleration, displacement, and velocity. The correct option is option (B).
Acceleration: The slope of the velocity-time graph represents the object's acceleration. A positive slope indicates positive acceleration (speeding up), a negative slope indicates negative acceleration (slowing down or decelerating), and a flat line indicates zero acceleration (constant velocity).
Displacement: The area under the velocity-time graph represents the displacement of the object. By calculating the area between the graph and the time axis, we can determine the total displacement.
Velocity: The graph directly shows the object's velocity at different points in time. The vertical position of the graph at any given time represents the object's instantaneous velocity.
Therefore, a velocity-time graph can provide information about the acceleration, displacement, and velocity of the moving object. The correct option is option (B).
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The work function for magnesium is
3.70 eV. What is its cutoff frequency?
Hint: 1 eV 1.60 x 10-19 J
[ ? ] × 10⁰ ² ) Hz
]
The cut off frequency of the magnesium atom is obtained as 8.9 * x 10^18 Hz.
What is the cut off frequency?The cut off frequency is the lowest frequency of the incident ray at which photoelectric effect occurs.
Given that;
1 eV gives 1.60 x 10-19 J
3.70 eV gives 3.70 eV * 1.60 x 10-19 J/1 eV
= 5.92x 10^-19 J
Now;
Wo = hfo
fo = Wo/h
fo = 5.92x 10^-19 J/6.6 * 10^-34
fo = 8.9 * x 10^18 Hz
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Emissions from alpha decay require the least amount of shielding.
Which best describes why the emissions from alpha decay are so easily blocked compared to the emissions of other types of radioactive decay?
The particles released during alpha decay are called alpha particles. Alpha particles have greater mass and charge than other emitted particles.
Radioactive emissions are the transfer of energy through the flow of particles or waves in a mediumThere are 3 types of radioactive emissions which are alpha, beta and gammaIn alpha radiation, the nucleus emits an alpha particle which is equivalent to a helium nucleusIn beta radiation, an electron is emitted to convert a neutron to a protonIn gamma radiation, the nucleus just loses energySince alpha particles have more mass and charge, they are more ionising and lose more energy at a faster rate and can be blocked easily.
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A force of 30 N is exerted on an object on a frictionless surface for a distance of 6.0 meters. If the object has a mass of 10 kg, calculate its velocity.
Answer:The velocity of the object will be 5[tex]\sqrt7[/tex]m/s or 13.23m/s
Explanation:
force exerted by the object= 30N
distance displayed by the object by the action of force=6.0m
mass of object=10kg
velocity gained by the object=?
[tex]\frac{1}{2}mv^{2}= forcexdisplacement\\\frac{1}{2}10v^{2} = 30x6\\ 5v^{2}=180\\ v^{2}= 180-5\\ v^{2} =175\\v=\sqrt{175} \\v=5\sqrt{7} or 13.23[/tex]
Describe how the speed of a moving object can be measured using a tape measure and stopwatch
Answer:
See below
Explanation:
Measure the distance and the amount of time to cover that distance
then speed = distance / time
Answer:
s=d/t
Explanation:
s=speed
d=distance
t=time
Just basic formula stuff
The volume in the pump when the pump piston is all the way down represents the _______
The volume in the pump when the pump piston is all the way down represents the end systolic volume.
What is systolic volume?
End systolic volume is the volume of blood in a ventricle at the end of contraction, or systole, and the beginning of filling, or diastole.
End systolic volume is the lowest volume of blood in the ventricle at any point in the cardiac cycle.
Thus, the volume in the pump when the pump piston is all the way down represents the end systolic volume.
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Select the correct location on the image.
Identify the magnetic north pole of Earth’s magnet.
The magnetic north pole of the earth's magnet is in the geographic south pole.
There are two magnetic and geographic poles each, north and southThe two geographic poles are the locations where the earth's axis of rotation passes through which is imaginaryThe magnetic north and south poles are not the same as the geographic north and south polesIn a compass, the needle points to the magnetic north poleBy convention, the magnetic north pole corresponds to the geographic south poleThe magnetic south pole corresponds to the geographic north poleThe magnetic field lines of a magnet start from the magnetic north pole and end at the magnetic south poleThe magnetic north pole of the earth's magnet is the geographic south pole.
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Rana writes a summary about a mass on a spring in simple harmonic motion as it moves upward from the equilibrium position toward the maximum positive displacement. as the mass moves upward, the velocity is positive and decreasing while the acceleration is negative and decreasing. what error did rana make? the velocity should be negative, not positive. the acceleration should be positive, not negative. the velocity should be increasing, not decreasing. the acceleration should be increasing, not decreasing.
Answer:
The magnitude of acceleration should be increasing.
Velocity is positive as the mass is moving towards the maximum positive displacement. Velocity would be decreasing. Acceleration is negative as velocity is decreasing. Additionally, the magnitude of acceleration would be increasing (becomes more negative.)
Explanation:
As the mass in this question moves upwards, the displacement of this mass is becoming more positive. Hence, the velocity of this mass would be positive.
In a simple harmonic motion, velocity is:
maximized at the equilibrium position (where displacement is [tex]0[/tex],) and[tex]0[/tex] when displacement is maximized.The mass in this question is moving from [tex]0[/tex] displacement (where velocity is maximized) towards maximum displacement (where velocity is [tex]0[/tex].) Thus, the velocity of the mass would be decreasing.
Since the velocity of this mass is decreasing, the acceleration of this mass would be negative. In a simple harmonic motion, acceleration is:
[tex]0[/tex] at the equilibrium position, andmaximum when displacement is maximized, but opposite to the direction of displacement.The mass in this question is moving from the equilibrium position (where acceleration is [tex]0[/tex]) towards maximum displacement (where acceleration is most negative.) Thus, the magnitude of the acceleration of this mass would be increasing, and the acceleration of the mass would become more negative.
Answer:
the acceleration should be increasing, not decreasing.
or in other words, D.
Cancer and diabetes are two common hereditary diseases.
True or False?
in which area of the galaxy would you find stars with fairly circular orbits about the galactic center?
Stars with fairly circular orbits about the galactic center is found in the disk
What are stars?Stars are one of the astronomical object that is usually very bright.
A circular orbit star is a star that moves in circular direction and not elliptical orbit which is most common to starts.
Therefore, Stars with fairly circular orbits about the galactic center is found in the disk
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A.
emotional health : expressing feelings
B.
physical health : respecting others
C.
mental health : living in harmony with the environment
D.
social health : getting adequate sleep
PLEASE ANSWER THESE FAST
AND CORRECT PLEASE
A rare butterfly (0.01 kg) is slowly flapping its wings and moving across a road. An unsuspecting driver in a large car (1000 kg) going very fast makes a sharp turn and runs directly into the butterfly. The butterfly smashes against the windshield (of course) but the car keeps moving down the road. Which object has the greater force: The butterfly or the car?
Both the butterfly and the large car will have equal forces but in opposite direction.
Newton's third law of motion
Newton's third law of motion states that action and reaction are equal and opposite. That is, the force exerted on an object is equal to the reaction experienced by the object.
Fa = - Fb
where;
Fa is the force exerted by the large carFb is the force of the butterflyThus, both the butterfly and the large car will have equal forces but in opposite direction.
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What are two models of light? how does each model explain part of the behavior of light?
The two most successful theories of light were the corpuscular (or particle) theory of Sir Isaac Newton and the wave theory of Christian Huygens. Newton's corpuscular theory stated that light consisted of particles that travelled in straight lines.
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Which of the following differentiates an audiologist from an anthropologist?
An audiologist uses empirical evidence to determine treatment.
An audiologist uses empirical evidence to determine treatment.
An audiologist examines physical characteristics of humans.
An audiologist evaluates communication methods.
An audiologist analyzes observed behaviors.
The statement that differentiates an audiologist from an anthropologist is that an audiologist examines physical characteristics of humans. That is option C.
Who is an audiologist?Audiologist is an individual that specializes in the diagnosis, treatment and management of hearing loss and balance disorders in adults and children.
An anthropologist is also an individual that studied the past and present experiences of individuals.
Therefore, the statement that differentiates an audiologist from an anthropologist is that an audiologist examines physical characteristics of humans.
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2) A skier stands at rest and begins to ski downhill with an acceleration of 3.0 m/s² {downhill). What is
her displacement after 15.0 seconds?
Answer:
337.5m
Explanation:
Kinematics
Under constant acceleration, the kinematic equation holds:
[tex]s=\frac{1}{2}at^2+v_ot+s_o[/tex], where "s" is the position at time "t", "a" is the constant acceleration, "[tex]v_o[/tex]" is the initial velocity, and [tex]s_o[/tex] is the initial position.
Defining Displacement
Displacement is the difference in positions: [tex]s-s_o[/tex] or [tex]\Delta s[/tex]
[tex]s=\frac{1}{2}at^2+v_ot+s_o[/tex]
[tex]s-s_o=\frac{1}{2}at^2+v_ot[/tex]
[tex]\Delta s=\frac{1}{2}at^2+v_ot[/tex]
Using known information
Given that the initial velocity is zero ("skier stands at rest"), and zero times anything is zero, and zero plus anything remains unchanged, the equation simplifies further to the following:
[tex]\Delta s=\frac{1}{2}at^2+v_ot[/tex]
[tex]\Delta s=\frac{1}{2}at^2+(0)*t[/tex]
[tex]\Delta s=\frac{1}{2}at^2+0[/tex]
[tex]\Delta s=\frac{1}{2}at^2[/tex]
So, to find the displacement after 15 seconds, with a constant acceleration of 3.0 m/s², substitute the known values, and simplify:
[tex]\Delta s=\frac{1}{2}at^2[/tex]
[tex]\Delta s=\frac{1}{2}(3.0[\frac{m}{s^2}])(15.0[s])^2[/tex]
[tex]\Delta s=337.5[m][/tex]
Two identical blocks are attached to the same massless rope, which is strung around two massless, frictionless pulleys. A massless scale is connected to the same rope and measures the tension in the rope. The two identical blocks are released from the rest. The experiment is then repeated with two new blocks, with masses m1 and m2. When they are released from rest, the system remains at rest, and the scale measures the same tension as in the previous experiment. Find m1 and m2 in terms of m.
Answer:
The value of mass 1, m1= 6/5m
The value of mass 2, m2= 3/5m
Explanation:
case 1:
here tension and the acceleration will be:
for m1;
mg-T=ma2mg - 2T = 2ma .....1.for m2:
2T-mg = ma/2 ..... 2.adding the both equations,
2mg - 2T + 2T-mg = 2ma + ma/2
a = 2/5 g
putting the value of a into the equation 1.
mg - T = m* (2/5)g
T = 3/5 ( mg )
now
case 2:
The two identical blocks are released from the rest, the tension remains the same as the case 1.
so,
for m1:
2T-m2g=0for m2:
2m2g - 2T =0adding both equations we get,
2T-m2g + 2m2g - 2T = 0
m2 = m1 / 2
T = m1*g / 2
here we know that
T (case1) = T (case2)
3/5 ( mg ) = m1*g / 2
m1 = 6/5 m
hence
m2 = 3/5 m
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The object has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 microme-
tres (mid-infrared light).
(b) What is the wavelength of the light emitted by the object? (c) What type of radiation was originally emitted by the object?
b. The wavelength of light emitted by the object is 233 nm
c. The type of radiation originally emitted by the object is ultraviolet radiation.
To find the wavelength, we need to know what redshift is.
What is redshift?Redshift is the increase in wavelength and the corresponding decrease of frequency and photon energy of electromagnetic radiation.
Redshift is given by z = λ'/λ - 1 where
λ' = observed wavelength and λ = emitted wavelength.Making λ subject of the formula, we have
λ = λ'/(1 + z)
Given that has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 micrometres (mid-infrared light).
So,
z = 7.6 and λ' = 2μm(b) What is the wavelength of the light emitted by the object?Substituting the values of the variables into the equation, we have
λ = λ'/(1 + z)
λ = 2μm/(1 + 7.6)
λ = 2μm/8.6
λ = 0.233 μm
λ = 233 nm
So, the wavelength of light emitted by the object is 233 nm
c. What type of radiation was originally emitted by the object?
Since the wavelength is 233 nm and the wavelength is in the range of ultraviolet radiation 200 nm - 315 nm.
So, the type of radiation originally emitted by the object is ultraviolet radiation.
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Samuel pushes against a door with a force of 10N, but the door doesn't move. Has Samuel done work on the door?
No, Samuel hasn't done work, Since the door doesn't move.
What is work done?Work is said to be done when an applied force moves an object over a given distance.
W = Fd
where;
W is work doneF is the applied forced is the distanceSince the door doesn't move, we can conclude that Samuel hasn't done work.
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When an electromagnet has an iron core inserted, what happens to the strength of the magnet?.
Answer:
The strength of the electromagnet increases.
Explanation:
Ramu,the gardener,is trying to pull out weeds. however,he has to apply great force.why do you think he has to apply to much force?
Answer:
Roots are basically hooked into the ground?
Explanation:
Maybe you could comment here the choices if it's multiple choice.
A projectile is launched at an angle of 29 degrees above the horizontal with an initial velocity of 36.6 at an unknown height.
The magnitude of the vertical velocity upon returning to its original, unknown height is _____ m/s.
The vertical velocity of the projectile upon returning to its original is 17. 74 m/s
How to determine the vertical velocity
Using the formula:
Vertical velocity component , Vy = V * sin(α)
Where
V = initial velocity = 36. 6 m/s
α = angle of projectile = 29°
Substitute into the formula
Vy = 36. 6 * sin ( 29°)
Vy = 36. 6 * 0. 4848
Vy = 17. 74 m/s
Thus, the vertical velocity of the projectile upon returning to its original is 17. 74 m/s
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