A tank holds 22.1 L of oxygen ( O2 ) at a pressure of 18.0 atm . What is the final volume, in liters, of this gas when it is released at a pressure of 2.90 atm with no change in temperature and amount of gas.

Answers

Answer 1

The final volume of gas will be 137.17L .

According to ideal gas equation , PV=nRT , where P is pressure of gas , V is volume of gas , n is moles of gas , R is universal gas constant and T is the temprature of gas.

Now , according to the que at initial and final stage the temprature and amount of gas stays constant , so we would simply equate the initial PV to the final PV.

[tex]P_{i} V_{i} = P_{f} V_{f} \\[/tex]

where [tex]P_{i}[/tex] ans [tex]V_{i}[/tex] are the initial pressure and volume of the gas and  [tex]P_{f}[/tex]  and [tex]V_{f}[/tex] are the final pressure and volume of the gas .

Here we have to find final volume of gas .

So , putting all values in above eq we get

18 x 22.1 = 2.9 x  [tex]V_{f}[/tex]

⇒ [tex]V_{f}[/tex] = 137.17 L

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Related Questions

6a. 0.898 mol sample of hydrogen gas at a temperature of 20.0 °C is found to occupy a volume of 24.5 liters. The pressure of this gas sample is
mm Hg.

6b. A sample of helium gas collected at a pressure of 991 mm Hg and a temperature of 300 K has a mass of 2.82 grams. The volume of the sample is
L.

8a. What volume is occupied by a 0.814 mol sample of xenon gas at a temperature of 0 °C and a pressure of 1 atm?

8b. A 1.21 mol sample of oxygen gas occupies a volume of
L at STP.

9b.What volume of carbon dioxide is produced when 7.95 liters of butane (C4H10) react according to the following reaction? (All gases are at the same temperature and pressure.)

butane (C4H10)(g) + oxygen(g) carbon dioxide(g) + water(g)

liters carbon dioxide

10b. What volume of carbon dioxide is produced when 0.504 mol of calcium carbonate reacts completely according to the following reaction at 0°C and 1 atm?

calcium carbonate ( s ) calcium oxide ( s ) + carbon dioxide ( g )

liters carbon dioxide

Answers

Gas law refers to the relationship between the temperature, volume and pressure of a gas.

What is gas laws?

The term gas law refers to the relationship between the temperature, volume and pressure of a gas.

6a) PV =nRT

P = nRT/V

P =  0.898 * 0.082 * 293/24.5

P = 0.88 atm

6b)  Number of  moles of helium = 2.82 g/4 g/mol = 0.705 moles

Pressure =  991 mm Hg or 1.3 atm

V = nRT/P

V = 0.705 * 0.082 * 300/1.3

V = 13.3 L

8a) V = nRT/P

V = 0.814 * 0.082 * 273/1

V = 18.22 L

8b) 1 mole of oxygen occupies 22.4 L

1.21 mole of oxygen occupies   1.21 mole *  22.4 L/ 1 mole

= 27.1 l

9b) C4H10(g) + 13/2O2 -----> 4CO2 + 5H20

1 moles of butane produces 4 moles of CO2, It then follows that the volume of carbon dioxide produced is 4( 7.95 liters) = 31.8 litres

10b) CaCO3 ------> CO2 + CaO

Since the reaction is 1:1,  0.504 mol of CO2 is produced

PV =nRT

V = 0.504 * 0.082 * 273/1 atm

V = 11.3 L

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What is the rule when "ao" or "oo" are together when naming covalent bonds

Answers

They are converted into a single “o” when "ao" or "oo" are together when naming covalent bonds.

What is a covalent bond?

A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms.

Sometimes, while naming the chemical compounds, a problem arises when compounds with “ao” and “oo” are written with -ide name. Conventionally, they are converted into a single “o”.

For example, the “ao” in the dichlorine hept-ao-xide ([tex]Cl_2O_7[/tex]). This “ao” in the [tex]Cl_2O_7[/tex] can be converted into “o”. As the result, the correct name of this compound would be dichlorine hept-o-xide.

Hence, they are converted into a single “o” when "ao" or "oo" are together when naming covalent bonds.

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If 13.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?

Answers

6.349 g mass of anhydrous magnesium sulfate will remain.

What are moles?

A mole is defined as 6.02214076 × 1023 of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Molar mass MgSO₄.7 H₂O = 246.52 g/mol

[tex]Moles =\frac{mass}{molar \;mass}[/tex]

[tex]Moles =\frac{13.0 g}{246.52}[/tex]

0.0527 moles

Molar mass MgSO₄ = 120.4 g/mol

Mass of anhydrous magnesium sulfate :

( 0.0527 x 120.4 ) => 6.349 g

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Write and balance the equation for the combustion of the fatty acid stearic acid, (C18H36O2).Express your answer as a chemical equation. Identify all of the phases in your answer.

Answers

The combustion of the fatty acid called stearic acid has the  the complete equation; C18H36O2(s) + 26O2(g) ------> 18CO2 (g) + 18 H2O(g)

What is combustion?

The term combustion has to do with the burning of a substance in air. For organic compounds, we get carbon dioxide and water as the products.

Thus, for the combustion of the fatty acid called stearic acid, the complete equation is; C18H36O2(s) + 26O2(g) ------> 18CO2 (g) + 18 H2O(g)

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How many moles of zinc, Zn, are in 1.31×1024 Zn atoms?

Answers

Answer:

=7.89013× 10^47 moles of zinc

Explanation:

1 atom contains 6.023×10^23 moles.

1.31×10^24 atoms of zinc contain6.023×10^24×1.31×10^.24

What is organic chemistry? Name at least three categories of compounds that are studied as
a part of organic chemistry.

Answers

Answer:

organic chemistry is chemistry focused on structure and composition, extending to recations and properties of compounds.

often centered around compounds with carbon.

alcohols, amines, and aldehydes are some groups that are studied on organic chemistry

SHORT ANSWER:

a) chemistry focused on the structure qnd composition of compounds

b) alcohols, amines, aldehydes

Explanation:

Organic compounds, which are the compounds associated with life processes, are the subject matter of organic chemistry. Among the numerous types of organic compounds, four major categories are found in all living things: carbohydrates, lipids, proteins, and nucleic acids.

uses of radio isotopes​

Answers

Answer:

1. Used in many smoke detectors for homes and businesses to measure levels of toxic lead in dried paint sample to ensure uniform thickness in rolling processes like steel and paper production and to help determine where oil wells should be drilled.

2.Used to treat cancerous tumors to measure correct patient dosages of radioactive pharmaceutical to measure and control the liquid flow in oil pipelines to tell researchers whether oil wells are plugged by sand and to ensure the right fill level for packages of food, drugs, and other

products.

3.Used in medical diagnosis

4.Used to treat thyroid disorders. (Graves’s disease).

5.Used in molecular biology and genetics research.

6.Used in nuclear medicine for lung ventilation and blood flow studies.

7.Used in dental fixtures like crowns and dentures to provide a Uranium-234 natural color and brightness.

8.Used in electric blanket thermostats and to gauge the thickness of thin plastics, thin sheet metal, rubber, textile and paper.

A 1dm3 solution was made by mixing 0.0040 mol of HCl(aq) and 0.0025 mol of NaOH(aq). What was the pH of the resulting solution?

Answers

The pH of the resulting solution is 2.82.

What is pH ?

pH is the measure of acidity and alkalinity of a solution , It has a range of 1 to 14.

HCl          +                   NaOH      →         NaCl       +         H₂O

0.0040                         .0025                 0                       0

0.0040 -0.0025             0                   0.0025          0.0025

Moles of HCl = 0.0015

As 0.0025 moles of NaOH reacts with 0.0025 moles of HCl leaving behind 0.0015 moles of HCl

Concentration of HCl = 0.0015/ 1 = 0.0015 M

[ H⁺] = 0.0015 M

pH = -log [ H⁺]

pH = -log [ 0.0015]

pH = 2.82

Therefore the pH of the resulting solution is 2.82.

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What is the osmotic pressure, in atm, of a 0.287 M solution of MgCl2 at
37.0 °C? (assume complete dissociation).

Answers

Answer:

Π = 21.9 atm

Explanation:

The equation used to find osmotic pressure is:

Π = iMRT

In this formula,

   >> Π = osmotic pressure (atm)

   >> i = van't Hoff factor

   >> M = molarity (M)

   >> R = constant (0.0821 atm*L/mol*K)

   >> T = temperature (K)

Remember, van't Hoff factor is the amount of ions the species (MgCl₂) dissociates into while in solution. MgCl₂ dissociates into 3 ions. These ions are Mg²⁺ and 2 Cl⁻.

The temperature needs to be in Kelvin....

37.0 °C + 273.15 = 310.15 K

You now know the value of all the variables.

Π = iMRT

Π = (3)(0.287 M)(0.0821 atm*L/mol*K)(310.15 K)

Π = 21.9 atm

How would you describe the kinetic energy of the particles in a solid?

Answers

Answer:

Solid objects have the least kinetic energy

Explanation:

because solid particles vibrate in place. Gases have the most kinetic energy because their particles move very quickly.

Solid objects have the least kinetic energy

In an experiment, a student gently heated a hydrated copper compound to remove the water of hydration. The following data was recorded:
Mass of crucible, cover, and contents before heating = 23.4 g.
Mass of empty crucible and cover = 18.82 g.
Mass of crucible, cover, and contents after heating to constant mass = 20.94 g.

Answers

The percent of water in the hydrated salt will be 55.08 %

What is mass?

Mass is a numerical measure of quantity, which is a basic feature of all matter. The kilogram is the international system of units of mass.

Given data;

Mass of crucible, cover, and contents before heating = 23.4 g.

Mass of empty crucible and cover = 18.82 g.

Mass of crucible, cover, and contents after heating to constant mass = 20.94 g.

⇒Mass of hydrated salt used =  Mass of the crucible, cover, and contents before heating - Mass of the empty crucible and cover                    

⇒Mass of hydrated salt used =   = 23.54 g – 18.82 g

⇒Mass of hydrated salt used =  = 4.72 g

⇒Mass of dehydrated salt after heating = Mass of the crucible, cover, and contents after heating to constant mass-Mass of the empty crucible and cover

Mass of dehydrated salt after heating = 20.94 g – 18.82 g

Mass of dehydrated salt after heating = 2.12 g

Mass of water liberated from salt = Mass of hydrated salt used -   Mass of dehydrated salt after heating

⇒  Mass of water liberated from salt = 4.72 g – 2.12 g    

⇒  Mass of water liberated from salt = 2.60 g  

   

Water % in the hydrated salt is found as;

% water =(mass of water/  mass of hydrated salt)× 100

% water =(2.60/4.72) × 100

% water =55.08 %

Hence the percent of water in the hydrated salt will be 55.08 %

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Under which conditions will gases best dissolve in liquids?
A. when the pressure is low and the temperature is low
B. when the pressure is high and the temperature is high
C. when the pressure is low and the temperature is high
D. when the pressure is high and the temperature is low

Answers

c option is correct answer

What is the frequency of the green light emitted by a hydrogen atom with a wavelength of 525 nm?

Answers

The frequency of the green light emitted by a hydrogen atom with a wavelength of 525 nm is [tex]5.71[/tex]×[tex]10^{14} s^{-1}[/tex]

What is wavelength?

It is the length between two successive crests or troughs of any wave.

What is a frequency?

It is the total number of waves that pass through a fixed point in unit time.

Wavelength=525nm

The relation between wavelength and frequency

[tex]v=\frac{c}{lambda}[/tex]

[tex]v=[/tex]frequency

[tex]c=[/tex]speed of light = [tex]3.0[/tex]×[tex]10^{8}[/tex][tex]m/sec[/tex]

λ(lambda)=wavelength

substitute the value in the equation mentioned above

[tex]v=3.0[/tex]×[tex]10^{8}[/tex][tex]/525[/tex]×[tex]10^{-9}[/tex]

[tex]=5.71[/tex]×[tex]10^{14}[/tex][tex]s^{-1}[/tex]

hence, the frequency of the green light emitted by a hydrogen atom with a wavelength of 525 nm is [tex]5.71[/tex]×[tex]10^{14} s^{-1}[/tex]

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Which is the best One to One tutoring website?

Answers

Answer:

Brainly or Chegg tutors.

Explanation:

Try those!

Activity 1.3 Put an unlit incense stick in a corner of your class. How close do you have to go near it so as to get its smell? Now light the incense stick. What happens? Do you get the smell sitting at a distance? Record your observations.​

Answers

for the first one you have to be very close to smell it, when lit the aroma fills the class because there is no ventilation and how there is no way for the gas to leave the room

Determine the hybrid orbital of this molecule.

Answers

There are three sigma bonds, so hybridization of the molecule will be sp²

What are other portals of entry besides needlesticks?

Answers

Answer:

Inhalation (via the respiratory tract)Absorption (via mucous membranes such as the eyes) Ingestion (via the gastrointestinal tract)

Explanation:

The opening where an infectious disease enters the host's body such as mucus membranes, open wounds, or tubes inserted in body cavities like urinary catheters or feeding tubes.

What is open system?
What is close system?
What is the valency of an atom?
State Heisenberg uncertainty principle
Define endothermic reaction

Answers

Answer:

1) open system is the system through which both matter and energy and enter as well as leave

ex - open beaker

2) close system is the system through which only energy can leave but matter cannot

ex - pressure cooker.. ( energy leave as air)

3) Valency of an atom is the no. of outer most electron which can participate in a reaction.

4). Heisenberg uncertainty principal states that it is impossible to measure or calculate exactly, both the position and the momentum of an object

5) The reaction in which heat is required to make products are called endothermic reaction. it cools down the surrounding .

QUESTION TO
What would I have to change to have a lunar eclipse happen every month?

Answers

You would have to fix the tilt of the Moon's orbit and make the Moon orbit planet Earth within the same plane that the Earth orbits the Sun.

What is a lunar eclipse?

A lunar eclipse can be defined as a phenomenon which occurs when the planet Earth comes in between the Moon and the Sun, thereby causing the Earth to cover the Moon with its shadow.

In order to have a lunar eclipse occur every month, you would have to fix the tilt of the Moon's orbit and make the Moon orbit planet Earth within the same plane that the Earth orbits the Sun, so as to block any ray of sunlight from reaching the Moon.

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Refer to the following table of Ksp values to answer the question below.
Compound
PbS
SnS
ZnS
HgS
Ksp
3 x 10-29
1 x 10-26
2x 10-25
1.6 x 10-52
A solution has 0.01 M Pb²+, 0.01 M Sn²+, 0.01 M Zn²+, and 0.01 M Hg2+. As tiny amounts of sulfide ion are slowly added
to the solution, which compound will precipitate first?
PbS
O Fes
HgS
SnS

Answers

HgS will precipitate first when tiny amounts of sulfide ion are slowly added to the solution.

What is Ksp?

The solubility product constant, Ksp​, is the equilibrium constant for a solid substance dissolving in an aqueous solution. It represents the level at which a solute dissolves in solution.

If Solubility product is greater than the ionic product then no precipitate will form on adding more solute because unsaturated solution is formed.

If Solubility product is lower than the ionic product then excess solute will precipitate out because of the formation of super saturated solution.

Here, Ksp value of HgS is very low. Hence, HgS will precipitate first when tiny amounts of sulfide ion are slowly added to the solution.

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water boils at 100 degrees celsius at sea level. If the water in this experiment did not boil to 100 degrees celsius, what could the reason be?

Answers

Answer:

It depends on how high you are above sea level

Explanation:

I did an experiment in my Scince class that showed, the less air that is around water will lessen it’s boiling level. We put water in a glass beaker inside of our vacuum chamber, we made a vacuum in he chamber. Making a vacuum is like being on a mountain, the less air the lower the boiling point. The water then began to boil due to the water evaporating. When we reached to maximum vacuum that we could the water started to boil at 61°C. No the water was not very hot, it was just warm water that just so happened to also be boiling, cool right!!! Anyways, we played with dry ice the next day.


Hoped this helped.

Hope I earned your star rating or helpful rating from this.

the air pressure around the experiment is lower than at sea level

An imaginary element, Y, has two different isotopes.
y has a percentage abundance of 25% and 29y has a percentage abundance of
75%.
Which of the following is the relative atomic mass of Y?
26
25
27
28

Answers

Answer:

kliujhygfdsalikumjyhbtgvf

Explanation:

The answer is:

28

I just got this answer so I don't know how to work it out but i hope it helps.

What hazard symbol does Pesticides have?

Answers

The hazard symbol that pesticides have are skull and cross bones.

What are hazard symbols?

Hazard symbols represent those symbols that are used as a warning sign towards materials that are dangerous to health.

Example of symbols used are:

Exploding bomb symbol: used for explosives

Flame symbol: used for flammables

skull with cross bones symbol: used for toxic substances such as pesticides.

Therefore, the hazard symbol that pesticides have are skull and cross bones.

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The hazard symbol of pesticides is a picture of the skull and crossbones.

What are pesticides?

Pesticides are known as  substances that are meant to control or destroy pests. They include herbicide, insecticide, nematicide, avicide, rodenticide, bactericide, insect repellent, etc.

The hazard symbol of pesticides is a picture of the skull and crossbones

Thus, the hazard symbol of pesticides is a picture of the skull and crossbones.

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Which are the product(s) of this chemical reaction? FeCl 3 + 3NH 4OH ->
a. 3NH4Fe + Cl3OH
b. 3FeCl3NH4OH
c. 3NH4Cl + 3FeOH
d. Fe(OH)3 + 3NH4Cl ​

Answers

The answer is D

FeCl3 + 3 NH4OH → Fe(OH)3 + 3 NH4Cl

what kind of investigations allow for the control of variables?

Answers

The experimental investigations allow for the control of variables.

What is control of variables?

The control of variables is the experimental element that remains constant and unchanged throughout the experiment of the investigation.

The control of variables is held constant during the experiment to test the relation between the dependent and independent variables.

Thus, An experimental investigation allows the control of variables all the time.

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In a container with 512.1 L water, the pH should be changed to 5 using 95% sulfuric acid. The question is how much sulfuric acid is needed.

Answers

Answer:

15

Explanation:

I got it right I just had the answer

A temperature of 300 Kelvin is how many degrees Celsius?
A. 273
B. 27
C. 573
D. 300

Answers

Answer:

The answer is B, to convert kelvin to temperature you :

Subtract 273 (k - 273)

Determine the hybrid orbital of this molecule.

Answers

The hybrid orbital of this molecule is [tex]sp^3[/tex]. Hence, option C is correct.

What is hybridisation?

Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.

In this compound, [tex]sp^3[/tex] a hybrid orbital makes I-O bonds. Due to [tex]sp^3[/tex]hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of [tex]IO^{3-}[/tex] the ion is pyramidal.

The hybrid orbital of this molecule is [tex]sp^3[/tex]. Hence, option C is correct.

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How many molecules in HNO3?

Answers

HNO3 is Hydrogen, Nitrogen and oxygen. Total number of atoms = 3+1+1=5 atoms are present in 1 molecule of HNO3.

Please help thanks in advance

Calculate the equilibrium constant K for the following reaction at 25°C from standard electrode potentials. Fe³(aq) + Cu(s) = Fe²(aq) + Cu²(aq)
The equation is not balanced. Use standard reduction electrode potentials.

Answers

The equilibrium constant K for the following reaction at 25°C from standard electrode potentials is Antilog (37.5).

What is chemical equilibrium?

Chemical equilibrium is the condition in the course of a reversible chemical reaction in which no net change in the amounts of reactants and products occurs.

Reduction Half-Reaction

[tex]Fe^{3+}[/tex](aq)+[tex]e^-[/tex] →[tex]Fe^{2+}[/tex](aq)

Standard reduction electrode potentials = +0.77

Oxidation Half-Reaction

Cu(s) = [tex]Cu^{+2}[/tex](aq) + 2[tex]e^-[/tex]

Standard reduction electrode potentials = -0.34

E° cell= E°cathode- E°anode

E° cell= +0.77+0.34

E° cell=1.11

E°cell= 0.0592÷n logK

From the redox reaction equations above, n=2

1.11 V= 0.0592÷2 logK

37.5 =  logK

K= Antilog (37.5)

Hence,  the equilibrium constant K for the following reaction at 25°C from standard electrode potentials is Antilog (37.5).

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