Answer:
yes
Explanation:
because no matter what voltage you connect it up to, the current always increases proportionally to the voltage.
this is because it follows ohm's law V = I X R.
(voltage = current X resistance)
so to calculate the resistance, change the formula to R = V / I giving you 60 ohm (resistor value)
the value of the resistor is always 60 ohm's, no matter which combination of voltage and current you used and measured, so it follows ohm's law, therefore being an ohmic resistor
A hydrogen line in a star's spectrum
has a frequency of 6.17x10^14 Hz
when stationary. In Rigel's spectrum,
it is shifted downward by 4.26x10^10
Hz. What is Rigel's velocity relative
to us?
PLS HELP!
Answer: V = 299,958589.8 m/s
Explanation: To calculate Rigel velocity relative to us, we should use doppler effect formula.
Fo = (c + Vo) f/ ( c - Vs)
Fo/f = (c + Vo) / ( c - Vs)
If Vo = Vs = V approximately
4.26 × 10^10 = (3×10^8 + V) 6.17×10^14/(3×10^8 - V)
4.26×10^10/6.17×10^14 = (3×10^8 + V)/(3×10^8 - V)
6.9×10^-5 = (3×10^8 + V)/(3×10^8 - V)
Cross multiply
20713.13 - 6.9×10^-5V = 3×10^8 + V
Collect the like terms
6.9×10^-5V + V = 3×10^8 - 20713.13
1.000069V = 299979286.9
V = 299979286.9/1.000069
V = 299,958589.8 m/s
Therefore, Rigel's velocity relative to us is 299,958589.8 m/s
Assertion: A normal human eye can see clearly all the objects below and above 25 cm
Reason: The human eye has the capacity to suitable adjust the focal length of its lens to a certain extent.
(a) Both Assertion and Reason are true and the Reason is the correct explanation of the Assertion.
(b) Both Assertion and Reason are true but Reason is not a correct explanation of the Assertion.
(c) The assertion is true but the Reason is false.
(d) Both Assertion and Reason are false.
Answer: d)
Both Assertion and Reason are false
Explanation:
The least distance of distinct vision for normal human beings is 25 cm. That is,
normal eye can not be able to see clearly the objects placed closer than 25 Centimetre.
Havong an Assertion that normal human eye can see clearly all the objects below and above 25 cm is false. And since the assertion is false, the reason behind it is invalid. Therefore, having a reason that the human eye has the capacity to suitable adjust the focal length of its lens to a certain extent is also false.
Which of the following are features of the nucleus of an atom?
derive a relation between time period anf frequency of a wave
Answer:
The relation between frequency and time period is given by:
f = 1/T
Explanation:
In a wave motion, the particle move about the mean position with the passage of time. The particles rise to reach the highest point which is crest, and similarly falls to reach the lowest point which is trough. The cycle keeps on repeating.
The time period of the wave can be defined as the time taken to complete one such cycle. Time period is given by:
T = 2π/ω
Frequency can be defined as the number of cycles completed in unit time, which can be taken as the inverse of time period. frequency is given by
f = ω/2π
or
f = 1/T
An electromagnet is a ____________ with a _________core.
Answer:
Solenoid with a Metal core
Early in the twentieth century, a group of German psychologists noticed that people tend to organize a cluster of sensations into a(n) Group of answer choices parallel process. monocular cue. afterimage. gestalt.
Answer:
The correct option is D
D) Gestalt
Explanation:
In the earlier 20th century, a group of German scientists named Max Wertheimer, Wolfgang Köhler and Kurt Koffka, noticed that people tend to organzie a cluster of information into a Gestalt.
Gestalt is a German word which means the way things are placed or put together as a whole. In the field of phychology, it can be defined as a pattern or configuration. In this context, it included the human mind and its behavior as a whole.
The Gestalt theory states that:
"The whole of anything is greater than its parts and that attributes of the whole can't be deduced by analyzing any of the parts on their own accord"
The Washington Monument is 169.20 meters tall.
A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the monument. A nickel with a mass of 0.005 kg is in her shirt pocket. What is the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument?
Answer: K.E = 8.3 J
Explanation:
The given parameters are
Height h = 169.2 m
Mass m = 0.005kg
From conservation of energy, at the top of the monument, the total energy will be kinetic energy which is equal to the potential energy. That is,
K.E = P.E
And
P.E = mgh
Where g = 9.81 m/s^2
Substitutes all the parameters into the formula
P.E = 0.005 × 9.81 × 169.2
P.E = 8.2908 J
Therefore, the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument is approximately 8.3 Joule.
The kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument is 8.2908 Joules.
Given the following data:
Mass of nickel = 0.005 kgHeight of Washington Monument = 169.20 metersScientific data:
Acceleration due to gravity = 9.8 [tex]m/s^2[/tex]To calculate the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument, we would apply the law of conservation of energy.
The law of conservation of energy.According to the law of conservation of energy, the kinetic energy (KE) of the nickel is equal to the potential energy (PE) possessed by the nickel at the top of the monument.
Mathematically, this is given by this expression:
[tex]K.E =P.E =mgh[/tex]
Substituting the given parameters into the formula, we have;
[tex]K.E = 0.005 \times 9.8 \times 169.20[/tex]
K.E = 8.2908 Joules.
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PLEASE HELP ME SOLVE THIS!! PLZ
Banpo Bridge fountain is 60 metres above the water.
The water is projected with a horizontal speed of 6m/s
-Calculate:
1. The time taken to hit the river for a single droplet of water.
2. The range of the projectile for a single droplet of water.
3. The velocity (diagonal) when it hits the water.
Answer:
1.) Time = 3.5 seconds
2.) Range = 21 m
3.) Velocity = 34.8 m/s
Explanation:
Given that the
Height h = 60 m
Initial velocity U = 6 m/s
1.) The time taken to hit the river for a single droplet of water can be achieved by using second equation of motion
h = Ut + 1/2gt^2
Let assume that the water drops from rest. Therefore, U = 0
60 = 1/2 × 9.8t^2
60 = 4.9t^2
t^2 = 60/4.9
t^2 = 12.24
t = sqrt (12.24)
t = 3.5s
2.) The range of the projectile for a single droplet of water will be calculated by using the formula
R = Ut
Range R = 6 × 3.5 = 20.99
Range = 21 m
3.) The velocity (diagonal) when it hits the water.
Using third equation of motion
V^2 = U^2 + 2gH
Substitute values into the equation
V^2 = 6^2 + 2 × 9.8 × 60
V^2 = 36 + 1176
V^2 = 1212
V = sqrt (1212)
V = 34.8 m/s
Which of the following statements about the negative influence of stress is TRUE?
A.
Stress can raise your blood pressure.
B.
Stress puts your body in a state of exhaustion.
C.
Stress weakens your immune system.
D.
All of the above.
Answer:
Its D
Explanation:
assuming that voltage remains constant, what happpens to the current in a wire as its diameter decreases?
Jake has a car that accelerates at 10 m/s2. If the car has a mass of 1000 kg, how much force does the car produce?
Answer:
10,000 N
Explanation:
Force = mass · acceleration
F = m · a
Jake's car:
Accelerates at 10 m/s²
Weighs 1000 kg
F = 1000 · 10
F = 10000 N
Answer:
10,000 Newtons
Please mark my answer.
Cheers, Jake
True or false when a person swims through water no work is done
Answer:
False
Explanation:
First we need to know the definition of work.
Work is done when a body moves through a distance with an applied force.
When swimming in water, you exert a force while moving through a distance. Therefore, work is done!
A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the speed of the car? PLS HELP
Answer: V = 15 m/s
Explanation:
As stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,
F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz
Using doppler effect formula
F = C/ ( C - V) × f
Where
F = observed frequency
f = source frequency
C = speed of light = 3×10^8
V = speed of the car
Substitute all the parameters into the formula
2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10
2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)
1.000000049 = 3×10^8/(3×10^8 - V)
Cross multiply
300000014.7 - 1.000000049V = 3×10^8
Collect the like terms
1.000000049V = 14.71429
Make V the subject of formula
V = 14.71429/1.000000049
V = 14.7 m/s
The speed of the car is 15 m/s approximately
Answer: 7.36m/s
Explanation:
(Fo- f)/fo = 2v/c
1030/2.10 x 10^10 = 2v/ 3 x 10^10
4.905= 2v/3 x 10^10
Rearrange for v
V = ((1030/2.10 x 10^10) x (3x 10^10)) / 2
V = 7.36 ( right for acellus)
True or false: it is legal for a goalie to jump forward or come off his line during a penalty kick
Answer:
no
Explanation:
the goalie can move side to side but cant go out of the goalie box.
pls mark me brainliest
a spring has a constant of 20 n/m. how far will it extend when the following forces are applied. (assume the spring does not pass its elastic limit)
a) 10 N
b) 50 N
c) 0.2 KN
Answer:
A.) 0.5 m
B.) 2.5 m
C.) 10 m
Explanation:
Given that the
Spring constant K = 20 N/m
From hooks law
F = Ke
Where
F = force applied
K = spring constant
e = extension
A.) When F = 10 N
Substitute F and K into the formula
10 = 20e
e = 10/20 = 0.5 m
B.) When F = 50 N
50 = 20e
e = 50/20 = 2.5 m
C.) When F = 0.2 KN
0.2 × 1000 = 20e
200 = 20e
e = 200/20 = 10m
All of the following are stress management techniques EXCEPT:
A.
Eliminate or reduce the stressor.
B.
Use relaxation techniques.
C.
Ignore the stress you feel.
D.
Alter your perception of the stressor.
Ignoring the stress we feel is not a possible thing as long as it persist. We must identify the source that creates stress and try to eliminate or reduce its effect through relaxation techniques.
What is stress management ?There isn't a one-size-fits-all approach to managing stress. Your stress-reduction routine will be very different from someone else's depending on the kind and frequency of your stress. However, it's useful to have a toolkit of stress-reduction methods on hand in case you require them.
It's common to have difficult circumstances in life. The daily commute and paying taxes are only two examples of daily pressures. It has an impact on everyone. The key is to learn how to control it so that our stress levels don't become too high.
There are many relaxation techniques to get rid of stresses such as yoga, community work out, music therapy. etc. Be active and control yourselves always and proper food and positive talks make everything out of stress.
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Luis and Aisha conducted an experiment. They exerted different forces on four objects. Their results are shown in the table.
A 3-column table with 4 rows. The first column labeled Object has entries 1, 2, 3, 4. The second column labeled Mass has entries 10 kilograms, 100 grams, 10 grams, 1 kilogram. The third column labeled Force (Newtons) has entries 4 Newtons, 20 Newtons, 4 Newtons, 20 Newtons.
Based on the data, which object has the greatest acceleration?
Object 1
Object 2
Object 3
Object 4
Answer:
Object 3
Explanation:
The object has the greatest acceleration is Object 2.
The following information should be considered;
The option 2 should be considered becasue 100 grams is lighter than 1 kilogram and therefore it has the greater amount of force that being applied to it, Due to this, it will have the greater acceleration.learn more: https://brainly.com/question/5303391?referrer=searchResults
Non-living factors in an ecosystem are
biotic
abiotic
antibiotic
Answer:
Abiotic
Explanation:
The non living factors of the ecosystem which is essential for the survival of living factors of the ecosystem are abiotic factors.
Examples for abiotic factors include temperature, sunlight, water, wind etc....
Answer:
B
Explanation:
is the correct answer
Explain the function of earth wire. Why is it necessary to earth metallic appliances?
Answer:
to prevent any electric shock to the user. (more info below)
Explanation:
The metallic structure of electrical equipment is bound to the earth by means of earth wire, such that any electrical current leakage is transmitted to the field. This stops the consumer from experiencing any electrical shocks. That's why the electrical devices ought to be earthed.
hope this helled!
The frequency of purple light is ____ that of yellow light. higher than lower than the same as faster than
Answer:
Faster
Explanation:
Purple light's frequency is faster than yellow
The frequency of purple light is higher that of yellow light.
What is color?The electromagnetic spectrum is the basis for the visual sense of colour. Color perception is connected to an object's light absorption, reflection, emission spectra, and interference, even though color is not an inherent property of matter.
The majority of humans use three different types of cone cells to see color in the visible light spectrum (trichromacy). Other species may have a distinct range of color sensitivity because they have a different number of cone cell types or eyes that are sensitive to a different wavelength, such as bees that can discern ultraviolet.
Different light wavelengths or spectral sensitivity in various cone cell types serve as the basis for animal perception of color, which is then processed by the brain.
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What happens when a light bulb is disconnected in a series circuit?
Answer:
it will most likely turn off?
Which of the following statements cannot be supported by Kepler's laws of planetary motion? a. The distance of a planet around the sun changes throughout its orbit. b. The speed a planet is moving around the sun changes throughout the year. c. The orbital period of Mercury can be calculated using the orbital period of Jupiter and the average distances of both planets. d. The age of the four largest planets can be determined using the age of the four smallest planets and the average distances of each planet.
Answer:
Kepler studied the periods of the planets and their distance from the Sun, and proved the following mathematical relationship, which is Kepler's Third Law: The square of the period of a planet's orbit (P) is directly proportional to the cube of the semimajor axis (a) of its elliptical path.
Explanation:
Answer:
D
Explanation:
Just got a 100 on the test
critical mass depends on ___. Check all that apply.
A. the polarity
B. the purity
C. the density
D. the shape
how do radios work?
music has 3 things that make them pleasing to hear..
ANSWERS ASAP
Answer:
radios work when electrons are speeding up and dow the attena, patters structure and shape make music pleasing to hear. (more info below)
Explanation:
a radio works when electrons are speeding up and down the antenna, sending out electromagnetic waves. Radiation waves travel through the air at the speed of light. When the radio waves reach the antenna, the electrons vibrate within the antenna and reproduce the initial signal. to make music pleasing to hear it has to have patterns, structure, shape.
hope this helped!
A man climbs a ladder. Which two quantities can be used to calculate the energy stored of the man at the top of the ladder.
A. The Weight of the man and the time taken only
B. The Weight of the man and the vertical distance moved only
C. The work don't by the man and the time taken only
D. The work don't by the man and the vertical distance moved only
Answer:The answer must be The weight of the man and the vertical distance moved.
Explanation: you calculate it by the force you applied times the distance you moved
What type of radiation exposure of 100,000 mrem can cause radiation sickness or increase the risk of cancer?
Long term exposure
Short term exposure
Both long and short term exposure
Explain how mirrors can produce images that are larger or smaller than life size, as well as upright or inverted
Answer:
1) When [tex]d_{o}[/tex] < [tex]d_{i}[/tex] (hence [tex]d_{o}[/tex] < f ) and they are both in front of the mirror (positive), the image will be larger and inverted
2) When [tex]d_{o}[/tex] > [tex]d_{i}[/tex] (and [tex]d_{o}[/tex] < f ) such that they are both positive (in front of the mirror), the image will be smaller and inverted
3) When the image is behind the mirror, for convex mirrors and the object is in front the image will be uptight. The magnification of the image will be the ratio of the image distance to the object distance from the mirror
Explanation:
The position of an object in front of a concave mirror of radius of curvature, R, determines the size and orientation of the image of the object as illustrated in the mirror equation
[tex]\dfrac{1}{f}=\dfrac{1}{d_{o}} + \dfrac{1}{d_{i}}[/tex]
[tex]Magnification, \, m = \dfrac{h_{i}}{h_{o}} = -\dfrac{d_{i}}{d_{o}}[/tex]
Where:
f = Focal length of the mirror = R/2
[tex]d_{i}[/tex] = Image distance from the mirror
[tex]d_{o}[/tex] = Object distance from the mirror
[tex]h_{i}[/tex] = Image height
[tex]h_{o}[/tex] = Object height
[tex]d_{o}[/tex] is positive for an object placed in front of the mirror and negative for an object placed behind the mirror
[tex]d_{i}[/tex] is positive for an image formed in front of the mirror and negative for an image formed behind the mirror
m is positive when the orientation of the image and the object is the same
m is negative when the orientation of the image and the object is inverted
f and R are positive in the situation where the center of curvature is located in front of the mirror (concave mirrors) and f and R are negative in the situation where the center of curvature is located behind the mirror (convex mirrors)
∴ When [tex]d_{o}[/tex] < [tex]d_{i}[/tex] (hence [tex]d_{o}[/tex] < f ) and they are both in front of the mirror (positive), the image will be larger and inverted
When [tex]d_{o}[/tex] > [tex]d_{i}[/tex] (and [tex]d_{o}[/tex] < f ) such that they are both positive (in front of the mirror), the image will be smaller and inverted
When the image is behind the mirror, for convex mirrors and the object is in front the image will be uptight. The magnification of the image will be the ratio of the image distance to the object distance from the mirror.
Find the electric field at the center of square. Assume that q1=11.8nC, q2=-11.8nC, q3=23.6nC, q4=-23.6nC and a=5.2cm. Such that 'a' is the distance between any two charges. The charge q1 and q3 are along two sides of a diagonal.
Answer:
[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]
Explanation:
You have four charges at the corners of a square of side a=5.2cm
In order to calculate the electric field at the center of the square, you sum the contribution of the electric field generated by each charge.
The total electric field is given by:
[tex]E_T=E_1+E_2+E_3+E_4\\\\[/tex] (1)
each contribution to the total electric field has two components x and y. The signs of the components depends of the direction of the field, which is given by the sign of the charge that produced the electric field. Then, you have
[tex]E_1=k\frac{q_1}{r^2}cos\theta\hat{i}-k\frac{q_1}{r^2}sin\theta\hat{j}\\\\E_1=k\frac{q_1}{r^2}(cos\theta \hat{i}-sin\theta \hat{j})[/tex] (2)
q1 = 11.8*10^-9 C
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
For a square you obtain that
[tex]r=\sqrt{2}a=\sqrt{2}(5.2cm)=7.35cm=7.35*10^{-2}m[/tex]
and the angle is 45°
Then, you have in the equation (2):
[tex]E_1=(8.98*10^9Nm^2/C^2)\frac{11.8*10^{-9}C}{(7.35*10^{-2}m)^2}(cos45\° \hat{i}-sin45\° \hat{j})=[13869.7\hat{i}-13869.7\hat{j}]\frac{N}{C}[/tex]
In the same way you obtain for the other contributions to the total electric field:
For E2:
[tex]E_2=k\frac{q_2}{r^2}(cos45\°\hat{i}+sin45\° \hat{j})\\\\E_2=[13869.7\hat{i}+13869.7\hat{j}]\frac{N}{C}[/tex]
For E3:
[tex]E_3=k\frac{q_3}{r^2}(-cos45\°\hat{i}+sin45\°\hat{j})\\\\E_3=(8.98*10^9Nm2/C^2)\frac{23.6*10^{-9}C}{(7.35*10^{-2}m)^2}(-cos45\°\hat{i}+sin45\°\hat{j})\\\\E_3=39229.58(-cos45\°\hat{i}+sin45\°\hat{j})\frac{N}{C}\\\\E_3=[-27739.5\hat{i}+-27739.5\hat{j}]\frac{N}{C}[/tex]
for E4:
[tex]E_4=k\frac{q_4}{r^2}(-cos45\°\hat{i}-sin45\°\hat{j})\\\\E_4=[-27739.5\hat{i}-27739.5\hat{j}]\frac{N}{C}[/tex]
Finally, you sum component by component the four contributions to the total electric field (equation (1)):
[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]
There still are four chargers in the corners of a square with side a=5.2cm. To compute the electric field just at the center of the composition, add the contributions of each shield's electromagnetic current.
entire electric field
[tex]\to E_T=E_1+E_2+E_3+E_4\ \ \ \ \ \ \ (1)[/tex]
Every contribution to the total electric field is comprised of two components, x, and y. These components' signs were determined by the direction of the field, which is determined by the sign of the charge that produced the electric field. There's
[tex]\to E_1=k\frac{q_1}{r^2}\cos\theta\hat{i}-k\frac{q_1}{r^2}\sin\theta\hat{j}\\\\\to E_1=k\frac{q_1}{r^2}(\cos\theta \hat{i}-\sin\theta \hat{j}) \ \ \ \ (2)\\\\\to q_1 = 11.8\times 10^{-9}\ C\\\\[/tex]
Coulomb’s constant (K) [tex]= 8.98\times 10^9\ \frac{Nm^2}{C^2}[/tex]
square, you obtain that
[tex]\to r=\sqrt{2}\\\\\to a=\sqrt{2}(5.2\ cm)=7.35\ cm=7.35\times 10^{-2}\ m[/tex]
angle= [tex]45\°[/tex] then, you have in the equation (2):
[tex]\to E_1=(8.98\times 10^9\ \frac{Nm^2}{C^2})\frac{11.8 \times 10^{-9}\ C}{(7.35 \times 10^{-2}m)^2}(\cos 45^{\circ} \hat{i}-\sin 45^{\circ} \hat{j})[/tex]
[tex]=[13869.7\hat{i}-13869.7\hat{j}]\ \frac{N}{C}[/tex]
Similarly, for other components to the overall electric field, you get:
For E2:
[tex]\to E_2=k\frac{q_2}{r^2}(\cos45^{\circ}\hat{i}+\sin45^{\circ} \hat{j})\\\\ \to E_2=[13869.7\hat{i}+13869.7\hat{j}]\ \frac{N}{C}[/tex]
For E3:
[tex]\to E_3=k\frac{q_3}{r^2}(-\cos45^{\circ}\hat{i}+\sin45^{\circ} \hat{j})\\\\\to E_3=(8.98\times 10^9 \ \frac{Nm^2}{C^2}) \ \frac{23.6 \times 10^{-9}\ C}{(7.35\times 10^{-2}\ m)^2}(-\cos45^{\circ} \hat{i}+\sin45^{\circ} \hat{j})\\\\\to E_3=39229.58(-\cos45^{\circ} \hat{i}+\sin45^{\circ} \hat{j})\frac{N}{C}\\\\\to E_3=[-27739.5\hat{i}+-27739.5\hat{j}]\ \frac{N}{C}\\[/tex]
For E4:
[tex]\to E_4=k\frac{q_4}{r^2}(-\cos45^{\circ}\hat{i}-\sin45^{\circ}\hat{j})\\\\ \to E_4=[-27739.5\hat{i}-27739.5\hat{j}]\ \frac{N}{C}[/tex]
Finally, we add up the four contributions to the total electric field (equation (1)):
[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]
Learn more:
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Please answer as soon as possible.
A Physics question about electricity and circuits.
Answer:
Explanation:
The formula P=VI, just rearrange to find I
So
I=P/V
=75/120
=0.625amps
625mA
WILL MARK BRAINLIEST
Using the fact that pressure is defined as force : area, what is the pressure
exerted by 1 book in N/m??
Answer:
Pressure= force/ area
12/ 2033.33= 24400 N/m2.
i believe this is it :)