A ship maneuvers to within 2.47×10^3 m of an island’s 1.77 × 10^3 m high mountain peak and fires a projectile at an enemy ship 6.02 × 10^2 m on the other side of the peak, as illustrated. The ship shoots the projectile with an initial velocity of 2.55×10^2 m/s at an angle of 72.4. The acceleration of gravity is 9.81 m/s 2. How close (vertically) does the projectile
come to the peak?

Answer:

2 : 1

Explanation:

Given that The magnitude of the acceleration due to gravity on the surface of planet A is twice as great as on the surface of planet B. What is the ratio of the weight of mass X on the surface of planet A to its weight on the surface of planet B?"

Since the magnitude of the acceleration due to gravity on the surface of planet A is twice as great as on the surface of planet B. And

Weight W = mg

Mass is always constant

2g : g

The ratio of the weight of mass X on the surface of planet A to its weight on the surface of planet B will be:

2 : 1

Answer:

The minimum radius of the curve is 6125 m

Explanation:

Given;

speed limit of the highway, V = 90 km/h = 25 m/s

banking angle, θ = 45°

The minimum radius of the curve will be calculated by applying banking angle formula;

[tex]mg tan \theta = F_{centripetal \ force}\\\\mg tan \theta = \frac{mv^2}{r}\\\\ g tan \theta = \frac{v^2}{r}\\\\r = \frac{v^2}{ g tan \theta}\\\\r = \frac{(25)^2}{(9.8)(1)} \\\\r = 6125 \ m[/tex]

Therefore, the minimum radius of the curve is 6125 m

Answer:

c

Explanation:

Answer:

b

Explanation:

Answer:

The value of resistor is 525.76 ohms

Explanation:

Given;

capacitance, C = 2.6 μF = 2.6 x 10⁻⁶ F

let the initial charge on the capacitor = Q₀

time , t = 2.2 ms = 2.2 x 10⁻³ s

The discharge of the capacitor is given by;

[tex]Q(t) = Q_oe^{-\frac{t}{RC} }[/tex]

Where;

Q(t) is the charge after 2.2ms = 20% of Q₀ = 0.2Q₀

[tex]Q(t) = Q_oe^{-\frac{t}{RC} }\\\\0.2Q_o = Q_oe^{-\frac{t}{RC} }\\\\0.2 = e^{-\frac{t}{RC} }\\\\ln(0.2) = -\frac{t}{RC}\\\\-1.6094 = -\frac{t}{RC}\\\\R = \frac{t}{1.6094C} \\\\R = \frac{2.2*10^{-3}}{1.6094*2.6*10^{-6}}\\\\R = 525.76 \ ohms[/tex]

Therefore, the value of resistor is 525.76 ohms

Answer:

B and D

Explanation:

Answer:

It is B. inherits all the traits from its parent

And D. is identical to the parent's structure

Explanation:

Hope this helped have an amazing day!

Answer:

Four times

Explanation:

The electrostatic force between the two charges is given by :

[tex]F=\dfrac{kq_1q_2}{d^2}[/tex]

d is the distance between two charges

k is electrostatic constant

When both charges are doubled, [tex]q_1'=2q_1\ \text{and}\ q_2'=2q_2[/tex], new force is given by :

[tex]F'=\dfrac{kq_1'q_2'}{d^2}\\\\F'=\dfrac{k(2q_1)(2q_2)}{d^2}\\\\F'=4\times \dfrac{kq_1q_2}{d^2}\\\\F'=4F[/tex]

So, the electrostatic force between them will be four times what it was before.

Answer:

B. The medium increases in temperature while remaining in the same phase.

Explanation: The most important factor influencing the speed of sound in air is temperature. The speed is proportional to the square root of the absolute temperature, giving an increase. Due to this information, B is the best answer.

Answer:

D.

Explanation:

Answer:

2.66 s

Explanation:

Given The initial angular speed ([tex]\omega_o[/tex]) =  1.34 x 10⁴ rad/s, the final angular speed (ω) = 4.37 x 10⁴ rad/s, the angular acceleration (α), distance (θ) = 3.10 x 10⁴ rad.

Using the formula:

[tex]\omega^2=\omega_o^2+2\alpha \theta\\\\Substituting:\\(4.37*10^4)^2=(1.34*10^4)^2+2(3.1*10^4)\alpha\\\\(4.37*10^4)^2-(1.34*10^4)^2=2(3.1*10^4)\alpha\\\\2(3.1*10^4)\alpha=1.73*10^9\\\\\alpha=2.79*10^4\ rad/s^2[/tex]

The constant acceleration = 2.79 * 10⁴ rad/s.

Since there is constant acceleration, to reach a final speed of  7.43 x 10⁴ rad/s, we use the formula:

[tex]\omega =\omega_o +\alpha t\\\\\omega_o=0,\omega=7.43*10^4\ rad/s,\alpha=2.79*10^4\ rad/s^2\\\\Substituting:\\\\7.43*10^4=0+2.79*10^4t\\\\7.43*10^4=2.79*10^4t\\\\t=2.66\ s[/tex]

Answer:

C I just did it. so yeah....

Complete Question

A helicopter of mass  [tex]1.40 *10^{3}[/tex] kg is descending vertically at 3.00 m/s. The pilot increases the upward thrust provided by the main rotor so that the vertical speed decreases to 0.450 m/s as the helicopter descends 5.00 m. What is the magnitude of the upward thrust force (assumed constant)?Express your answer with the appropriate units.

Answer:

The value is  [tex]F = 11257 \ N[/tex]

Explanation:

From the question we are told that

   The mass of the helicopter is  [tex]m = 1.40 *10^{3} \ kg[/tex]

   The initial descending speed is [tex]u= 3.00 \ m/s[/tex]

   The  descending speed after the upward thrust has been increased is [tex]v = 0.450 \ m/s[/tex]

    The  height when descending speed is [tex]v = 0.450 \ m/s[/tex]  is  [tex]s = 5.0 \ m[/tex]

Generally according to the kinematics equations

   [tex]v^2 = u^2 + 2(a)s[/tex]

Here a is the acceleration due to gravity plus the acceleration of the helicopter

So

    a  =  [tex]a = -g + a_h[/tex]

the negative sign is due to the fact that the direction of the plane is in the negative y axis

So

       [tex]v^2 = u^2 + 2(-g + a_h)s[/tex]

=>    [tex]0.45^2  =  3^2  + 2(-9.9 + a_h) * 5[/tex]

=>   [tex]a_h = \frac{-8.7975}{5} + 9.8[/tex]    

=>   [tex]a_h = 8.0405 \ m/s^2[/tex]    

Generally the thrust force is mathematically represented as

     [tex]F = m * a_h[/tex]

=> [tex]F = 1.40 *10^{3} * 8.0405[/tex]

=> [tex]F = 11257 \ N[/tex]

Answer:

Explanation:

Thrust produced = v dm / dt

v is speed of exhaust and dm / dt is rate at which mass of gas is being thrown out .

= 2.603 x 10³ x 1.503 x 10⁴

= 3.91 x 10⁷ N  ,

The correct answer is B. Weight directly measures force while mass directly measures the amount of matter.

Explanation:

Weight and mass are two related but not identical concepts. The first term "mass" can be found by measuring the amount of matter in a body or substance. For example, the mass in an apple is around 80 grams depending on its size. In this context, mass is measured using units such as grams or kilograms. On the other hand, weight considers not only the matter in an object but the force exerted in it, especially, the gravitational force. In the case of the apple, the weight is 1 N as newtons (N) are used to measure force and this is the result of multiplying the mass by gravity. According to this, option B is correct.

Answer:

[tex]\epsilon=1.2\times 10^{-3}\ V[/tex]

Explanation:

Given that,

Length of a wire, l = 1.95 m

Speed of the wire, v = 15.5 m/s

The vertical component of Earth's magnetic field in this region is 40.0 μT directed downward.

We need to find the induced emf between the ends of the wire and determine which end is positive. The induced emf for a wire is given by :

[tex]\epsilon=Blv\\\\\epsilon = 40\times 10^{-6}\times 1.95\times 15.5\\\\\epsilon=1.2\times 10^{-3}\ V[/tex]

So, the induced emf between the ends of the wire is [tex]1.2\times 10^{-3}\ V[/tex].

Answer:

400 seconds

Explanation:

Divide the total distance by the unit rate

200/0.5 = 400

400 seconds

Answer:

400 seconds

Explanation:

Answer:5

Explanation:

5 right

Answer:

4

Explanation:

Carbon, with 4 electrons in its valence shell, will need another four electrons to fulfill the octet rule. Thus it needs to combine with 4 hydrogen atoms to form a stable compound called methane(CH4)

Answer:

Explanation:

Let the two forces be acting in the horizontal direction on the object.

Given

Mass m = 6kg

One of the force = 10N

acceleration = 2m/s²

Taking the sum of forces along the x component, we will have:

[tex]\sum F_x = ma_x\\Ff - 10 = 6(2)\\Ff - 10 = 12\\Ff = 12+10\\Ff = 22N[/tex]

Note that Ff is the greatest possible magnitude of the other force.

Hence the greatest possible magnitude of the other force is 22N

B, Its the one with the kid trying to lift a weight.

Explanation:

Got it right Edge 2020.

Answer:

it's the weights kid!!! the other user got it thank them, i got it right bc of them :)

Explanation:

Answer:The ampere is unique in that it uses the base unit of time (t) in its definition (second). All other electrical and magnetic units (such as voltage, power, and magnetic flux) use various combinations of base units in their definitions and are called derived units.

Explanation:

Answer:

ω = 1899.5 radian / s

Explanation:

EMF induced by a rotating rod = 1 /2 B ω L² where ω is angular velocity of rod and L is its length . B is magnetic field

1 /2 B ω L² = 1.5

1/2 x .7 x ω x .0475² = 1.5

ω = 1899.5 radian / s

Answer:

Initial height

Answer:

A: the hardness of the sidewalk where the mug landed

Explanation:

did the quick check

Answer:

c

Explanation:

Answer:

Exercise can reduce pain, relieve stress, and increase energy.Explanation:

Answer:

Explanation:

In this problem we want to solve for the height given the potential energy

the potential energy is the energy possessed  by a body by virtual of it position.

given data

mass m=59kg

PE(potential energy)= 200J

Height h=?

assuming g=9.81,/s^2

we know that the expression for potential energy is

PE=mgh

substituting we have

200=59*9.81*h

200=578.79h

divide both sides by 578.79

h=200/578.79

h=0.35m

Therefore the height is 0.35m

Answer:

Popped-Eye is 3 times more powerful than Mack Sparrow.

Explanation:

Popped-Eye is 6 times more powerful than Mack Sparrow.

In science and engineering, power is the rate at which work is completed or energy is delivered. It can be expressed as the product of the work completed (W) or the energy transferred (E) divided by the time interval (t), or W/t.

Given parameters:

Popped-Eye's treasure is three times heavier than Mack Sparrow's.

Mack Sparrow requires twice as much time.

So, Popped-Eye can lift  times heavier treasure  in half of time compere to Mack Sparrow .

Hence, Popped-Eye's power is 3÷(1/2) = 3×2 = 6 times more than Mack Sparrow's.

Learn more about power here:

https://brainly.com/question/12127373

#SPJ2

Answer:

V_ce = 1128 m/s

Explanation:

We are given;

Speed of space vehicle relative to the earth; V_i = 4140 km/h = 1150 m/s

relative speed between the motor and the command module; V_mc = 99 km/h = 27.5 m/s

mass of the motor is four times the mass of the module.

If the mass of the module is m

Mass of motor = 4m

From conservation of momentum, since the system is isolated, then;

Initial momentum = final momentum.

Thus;

MV_i = 4m(V_me) + m(V_ce) - - - (eq 1)

Where;

M is mass of space vehicle

V_me is speed of motor relative to the earth

V_ce is speed of command module relative to the earth

Now, relative speed between the motor and the command module is given by the formula;

V_mc = V_me - V_ce

Thus, V_me = V_mc + V_ce

Putting (V_mc + V_ce) for V_me in eq 1, we have;

MV_i = 4m(V_mc + V_ce) + m(V_ce)

Now, the mass of the space vehicle will be the sum of the mass of the module and mass of the motor.

Thus;

M = m + 4m

M = 5m

Thus;

5mV_i = 4m(V_mc + V_ce) + m(V_ce)

Divide through by m to get;

5V_i = 4(V_mc + V_ce) + (V_ce)

5V_i = 4V_mc + 4V_ce + V_ce

5V_i = 4V_mc + 5V_ce

We want to find the speed of the command module relative to Earth just after the separation. Thus, let's make V_ce the subject;

V_ce = (5V_i - 4V_mc)/5

V_ce = ((5 × 1150) - (4 × 27.5))/5

V_ce = 1128 m/s