Answer:
8.44 atm
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 2.25 L
Initial temperature (T₁) = 350 K
Initial pressure (P₁) = 1.75 atm
Final volume (V₂) = 1 L
Final temperature (T₂) = 750 K
Final pressure (P₂) =?
The final pressure of the gas can be obtained as illustrated below:
P₁V₁/T₁ = P₂V₂/T₂
1.75 × 2.25 / 350 = P₂ × 1 / 750
3.9375 / 350 = P₂ / 750
Cross multiply
350 × P₂ = 3.9375 × 750
350 × P₂ = 2953.125
Divide both side by 350
P₂ = 2953.125 / 350
P₂ = 8.44 atm
Thus, the final pressure of the gas is 8.44 atm.
What is the volume of a 5.00 molar solution containing 20 moles of 0.40 10.0L 0.010L
Answer:
Volume of solution = 4 liter
Explanation:
Given:
Molarity = 5 M
Number of moles = 20 moles
Find:
Volume of solution
Computation:
Moles of solute mixed per litre of solution is known as molarity. A 1 M sample is the one in which 1 molecule of solvent is soluble in one liter of solution volume.
M = Mol / L
5 = 20 / L
Volume of solution = 4 liter
Question 13
A hot air balloon has a pressure of 0.715 atm while the temperature outside is 30
degreeſ C. What will the pressure be if the temperature drops to 10 degrees C while
volume remains constant? Do not write units in the answer. Make sure to convert
temperature values to Kelvin.
Answer:
0.668 atm
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 0.715 atm
Initial temperature (T₁) = 30 °C
Final temperature (T₂) = 10 °C
Volume = constant
Final pressure (P₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 30 °C
Initial temperature (T₁) = 30 °C + 273
Initial temperature (T₁) = 303 K
Final temperature (T₂) = 10 °C
Final temperature (T₂) = 10 °C + 273
Final temperature (T₂) = 283 K
Finally, we shall determine the final. This can be obtained as follow:
Initial pressure (P₁) = 0.715 atm
Initial temperature (T₁) = 303 K
Final temperature (T₂) = 283 K
Final pressure (P₂) =?
P₁ / T₁ = P₂ / T₂
0.715 / 303 = P₂ / 283
Cross multiply
303 × P₂ = 0.715 × 283
303 × P₂ = 202.345
Divide both side by 303
P₂ = 202.345 / 303
P₂ = 0.668 atm
Thus, the final pressure of the hot air balloon is 0.668 atm
Can somebody please help me!!!
Answer:
energy
Explanation:
Energy is used to do work or produce change. Friction and velocity do not do this.
What does evaporation produce?
a precipitation
b rain or snow
C water vapor
d condensation
Answer:
C water vapor.
or saturated water vapor ( steam )
The activation energy for the gas phase decomposition of isobutyl bromide is 211 kJ.
(CH3)2CHCH2Br(CH3)2C=CH2 + HBr
The rate constant at 686 K is 1.04×10-3 /s. The rate constant will be 1.24×10-2 /s at __kj
Answer:
whatttttttttttttttt do you meam
In gas chromatography, the stationary phase is made up of high molecular weight non-volatile polymer coated on solid support packed inside a column and the mobile phase is an inert gas that carries the volatilized components of the sample mixture through the column toward the detector. The physical form of the stationary (s) and mobile phase (m) in gas chromatography are:
Answer:
liquid (s), gas (m)
Explanation:
In gas chromatography, the phase of stationary would be made of great molecular weight that have non-volatile coated on the packed i.e. inside a column also the mobile phase represent the inert gas that carries the components that should be volatilized.
Now the physical form and the mobile phase is the liquid and the gas
The same would be relevant and considered too
After she explains commensalism to her friend, Hailey tries to think of an example of it. Which of the following is an example of commensalism?
fleas and and a dog
barnacles on a whale
a human and chicken pox
a bee and a flower
Answer:
bernacles on a while.
Explanation:
These crustaceans stick to the bodies of baleen whales during their larval stage, when they are still able to swim, and establish a commensal relationship with the mysticetes, since they neither harm nor benefit the host that hosts them, whom they will accompany throughout their lives. .
What can happen to a rock when water flows through cracks or holes in the rock?
Answer:
it will crack because if the water inside of a rock freezes the water would start to expand and start stretching it causing it to break
Explanation:
11. Which of the following elements CANNOT violate the octet rule?
a.
Nitrogen
b. Phosphorus
c. Sulfur
d. lodine
Answer:
I think it's Nitrogen is right answer
How does the entropy change in the reaction 2C3H6(g) + 9O2(g) → 6C02(g) + 6H2O (g)?
I will mark brainliest!! Thank you so much!!
Answer:
The entropy increases!!!
Explanation:
a pex
The entropy increases in the reaction.
What is entropy?Entropy is defined as the measure of the disorder of a system.Entropy is an extensive property of a thermodynamic system, to put it in simple words, its value changes depending on the amount of matter that is present.Entropy is denoted by the letter S and has units of joules per kelvin (JK−1)The entropy increases in the reaction if the total number of product molecules are greater than the total number of reactant molecules.
2C3H6(g) + 9O2(g) → 6C02(g) + 6H2O (g)
In the above reaction, the product molecules are greater than the reactant molecules. Hence, entropy increases.
Hence, we can conclude that option A is the answer.
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When water evaporates from a plant's leaves, this process is
called
Answer:
transpiration
Explanation:
Answer:
Transpiration
Explanation:
What is the molarity of a 9.0 L solution that contains 0.500 mol HCl?
A.8.29 M
B.0.879 M
C.0.018 M
D.0.056 M
Answer: 0.056
Explanation:
The molarity of the solution is the ratio of the number moles of solute to the volume of solution. Hence, the molarity of the given solution is 0.056 M. Thus, option D is correct.
What is molarity ?Molarity is a common term used to express the concentration of a solution . It is the ratio of the number of moles of solute to the volume of solution in liters.
Given that,
volume of HCl solution = 9 L
no. of moles of HCl = 0.50 moles.
Then,
molarity = no.of moles/volume in L
M = 0.50 Moles/9 L
= 0.056 M.
Therefore, the molarity of the solution is 0.056 M.
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Of the 8 planets, why does the sun have the most gravitational attraction to Mercury?
Answer:
It is the closest sir.
Have an amazing day and enjoy. P.S Good luck!
Explanation:
Let's chek the orders where mercury and rest planets present
MercuryVenusEarthMarsJupiterSaturnUranusNeptuneMercury is closest to sun so gravitational force is most
Calculate the mass of each element in the
compound by multiplying its molar mass by the
number of moles of the element present in one
mole of the compound
Mass N =
Mass H =
Mass O =
Answer:
For Mass N, Mass H, and Mass O, the mass is 28.0 g N, 4.0 g H, and 48.0 g respectively
Explanation:
The computation of the mass of each element is given below:
As we know that
A1 mole of ammonium nitrate i.e. 2 mol N, 4 mol H, 3 mol
Now we multiply each of above by the molar masses
For N
= 14.0 g/mol × 2
= 28.0 gN
For H
= 1.0 g/mol × 4
= 4.0 gN
ANd, for O
= 16.0 g/mol × 3
= 48.0 gN
Hence, For Mass N, Mass H, and Mass O, the mass is 28.0 g N, 4.0 g H, and 48.0 g respectively
Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
2H2(g) + O2(g)
—>2H20(9)
Answer:
ΔH°r = -483.64 kJ
Explanation:
Let's consider the following balanced equation.
2 H₂(g) + O₂(g) ⇒ 2 H₂O(g)
We can calculate the standard enthalpy change of the reaction (ΔH°r) using the following expression.
ΔH°r = ∑ΔH°f(p) × np - ∑ΔH°f(r) × nr
where
ΔH°f: standard heat of formation
n: moles
p: products
r: reactants
ΔH°r = ΔH°f(H₂O(g)) × 2 mol - ΔH°f(H₂(g)) × 2 mol - ΔH°f(O₂(g)) × 1 mol
ΔH°r = (-241.82 kJ/mol) × 2 mol - 0 kJ/mol × 2 mol - 0 kJ/mol × 1 mol
ΔH°r = -483.64 kJ
How many grams of aluminum chloride are produced when 5.96 grams of aluminum are reacted with excess chlorine gas? Start with a balanced equation.
Answer:
29.47 g of AlCl₃.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2Al + 3Cl₂ —> 2AlCl₃
Next, we shall determine the mass of Al that reacted and the mass of AlCl₃ produced from the balanced equation. This can be obtained as follow:
Molar mass of Al = 27 g/mol
Mass of Al from the balanced equation = 2 × 27 = 54 g
Molar mass of AlCl₃ = 27 + (35.5× 3)
= 27 + 106.5
= 133.5 g/mol
Mass of AlCl₃ from the balanced equation = 2 × 133.5 = 267 g
SUMMARY:
From the balanced equation above,
54 g of Al reacted to produce 267 g of AlCl₃.
Finally, we shall determine the mass of AlCl₃ produced by the reaction of 5.96 g of Al. This can be obtained as follow:
From the balanced equation above,
54 g of Al reacted to produce 267 g of AlCl₃.
Therefore, 5.96 g of Al will react to produce = (5.96 × 267)/54 = 29.47 g of AlCl₃.
Thus, 29.47 g of AlCl₃ were obtained from the reaction.
If DG for a reaction equals zero, the reaction
a. is spontaneous.
b. is at equilibrium.
c. may or may not be spontaneous.
d. is not spontaneous.
Answer: If [tex]\Delta G[/tex] for a reaction equals zero, the reaction is at equilibrium.
Explanation:
When a thermodynamic closed system tends to do the maximum amount of non-expansion work then the energy used to do this work is called Gibb's free energy.
The expression for [tex]\Delta G[/tex] can be written as follows.
[tex]\Delta G = \Delta H - T \Delta S[/tex]
where,
[tex]\Delta H[/tex] = enthalpy change
T = temperature
[tex]\Delta S[/tex] = entropy change
This means that [tex]\Delta G[/tex] is the difference between heat released in a process and the amount of heat released in a reversible manner for the same process. So, when the value of of [tex]\Delta G[/tex] comes out to be equal to zero then it means no heat is released or absorbed.
Hence, the reaction is stable or at equilibrium.
Thus, we can conclude that the value of [tex]\Delta G[/tex] = 0 then it means that the reaction is at equilibrium.
CaF2(s)⇄Ca2+(aq)+2F−(aq) Ksp=3.9×10−11
HF(aq)⇄H+(aq)+F−(aq) Kc=6.8×10−4
The dissolution of calcium fluoride is represented by the equilibrium system above at 25°C. The F− ion is produced when the weak acid HF dissociates. If solid calcium fluoride is added to equal volumes of the following solutions at 25°C, in which solution will the most calcium fluoride dissolve?
A) Pure distilled water
B) 1MHNO3(aq)
C) 1MNaOH(aq)
D) A saturated aqueous CaF2 solution
The solution in which the most calcium fluoride dissolves is 1M HNO3(aq).
Option (B) is correct.
What is Le Châtelier's principle?A system in equilibrium is subjected to change (change in concentration/pressure of reactants/products, temperature, etc.) according to Le Châtelier's principle.
To counterbalance the change and restore equilibrium, the System advances in a direction.
In solution, HNO is a strong acid that will dissociate fully to generate H+ and No3-.
This increasing concentration of H+ will cause the second equilibrium reaction in question to reverse direction, resulting in the production of additional HF.
As a result of the drop in F- concentration, the dissolution equilibrium process of Caf2 moves forward, dissolving more valid CaF2 to produce Ca2+ and F_ and thereby boosting Caf2 solubility.
Thus, HNO3 (B) is the correct option.
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2 NaClO3→ 2 NaCl + 3 O2
How many moles of O2 are produced when 40g of NaCl are formed?
Answer:
75.6
Explanation:
Calculate the percent error, with correct sig figs, in the atomic weight if the mass of a Zn electrode increased by 0.3681 g and 6.514x10-3 moles of Zn was produced. Select the response with the correct Significant figures. You may assume the molar mass of elemental zinc is 65.38 g/mol. Refer to Appendix D as a guide for this calculation.
Answer:
the percent error is -13.5%
Explanation:
Given the data in the question;
Exact atomic weight = 65.38 g/mol
For approx
increased mass = 0.3681 g
moles = 6.514 x 10⁻³
we know that; moles = mass / (Atomic mass )
so
Atomic mass_[tex]_{approx[/tex] = mass / moles
Atomic mass_[tex]_{approx[/tex] = 0.3681 / 6.514 x 10⁻³
Atomic mass_[tex]_{approx[/tex] = 56.509
so approx atomic weight = 56.51 g/mol
we know that;
% error = ( [approx - exact] / exact ) × 100
we substitute
% error = ( [56.51 - 65.38] / 65.38 ) × 100
% error = (-8.87 / 65.38 ) × 100
% error = ( -0.1356684 ) × 100
% error = -13.5%
Therefore, the percent error is -13.5%
Is carbon moving into the air moving out of the air or both
Answer:
Carbon is moving into the air
Why are weather front boundaries turbulent?
Answer:
Answer Below Hope Its Correct.
Explanation:
A weather front is a transition zone between two different air masses at the Earth's surface. Each air mass has unique temperature and humidity characteristics. Often there is turbulence at a front, which is the borderline where two different air masses come together. The turbulence can cause clouds and storms.
Instead of causing clouds and storms, some fronts just cause a change in temperature. However, some storm fronts start Earth's largest storms. Tropical waves are fronts that develop in the tropical Atlantic Ocean off the coast of Africa. These fronts can develop into tropical storms or hurricanes if conditions allow.
Fronts move across the Earth's surface over multiple days. The direction of movement is often guided by high winds, such as Jet Streams. Landforms like mountains can also change the path of a front.
There are four different types of weather fronts: cold fronts, warm fronts, stationary fronts, and occluded fronts.
A transverse wave is observed to be moving along a lengthy rope. Adjacent crests are positioned 2.4 m apart. Exactly six crests are observed to move past a given point along the medium in 9.1 seconds. Determine the frequency of these waves
Answer:
f = 0.65 hz
Explanation:
Given that,
The distance between adjacent crests, wavelength = 2.4 m
6 crests are observed to move past a given point along the medium in 9.1 seconds.
We need to find the frequency of these waves.
We know that,
Frequency = no. of waves per second.
[tex]f=\dfrac{6}{9.1}\ Hz\\\\=0.65\ Hz[/tex]
So, the frequency of these waves is equal to 0.65 Hz.
A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:
Fe2O3(s) + 3 H2(
92Fe(s) + 3 H2O(9)
Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation
of H2O(g) is
kJ/mol.
Answer: The standard enthalpy of formation of [tex]H_2O(g)[/tex] is -252.1 kJ/mol.
Explanation:
The balanced chemical reaction is,
[tex]Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)[/tex]
The expression for enthalpy change is,
[tex]\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactantss}][/tex]
Putting the values we get :
[tex]\Delta H=[2\times H_f{Fe}+3\times H_f{H_2O}]-[1\times H_f{Fe_2O_3}+3\times H_f{H_2}][/tex]
[tex]67.9kJ=[(2\times 0)+(3\times H_f{H_2O})]-[(1\times -824.2kJ/mol)+3\times 0kJ/mol)][/tex]
[tex]H_f{H_2O}=-252.1kJ/mol[/tex]
Thus standard enthalpy of formation of [tex]H_2O(g)[/tex] is -252.1 kJ/mol.
Dinitrogen monoxide gas is collected at 12.0°C in an evacuated flask with a measured volume of 10.0 L. When all the gas has been collected, the pressure in
the flask is measured to be 0.070 atm.
Calculate the mass and number of moles of dinitrogen monoxide gas that were collected. Round your answer to 2 significant digits.
mass: 1
mole: mol
?
Answer:
0.030 moles N2O and 1.3 grams N2O
Explanation:
Attatched is an image of the explanation. Hope this helps!
What is the molar mass of a gas if 0.102 g of the gas occupies 0.070 L at STP? a. 32.6g / mol b. 28.2 g/mol c. 40.0g / mol d. 47.9 g/mol
Answer:
A. 32.6 g/mol
Explanation:
First convert the volume of gas to moles using the ratio 1 mol / 22.4 L at STP.
0.070 L • (1 mol / 22.4 L) = 0.00313 mol
Now divide the grams of gas by the moles of gas:
0.102 g / 0.00313 mol = 32.6 g/mol
Can somebody please help me!!!
Answer:
speed
Explanation:
Speed is the rate at which something moves. The speed of light is faster than the speed of sound.
Section I: Experimental Overview
Provide background information.
Include the hypothesis(es).
Summarize the procedures.
Section II: Data and Observations
Summarize the data you collected in the lab guide.
Include information from data tables.
Include any written observations that are relevant.
Section III: Analysis and Discussion
Discuss any important calculations or formulas used.
Identify key results, what the results indicate, and any trends in the data.
Include graphs (if constructed) that display trends in the data.
Provide possible reasons for any problems with the experiment, or unexpected data.
Section IV: Conclusions
Identify if the hypothesis(es) was (were) supported or refuted.
Provide logical reasoning based on data.
Explain how the experiment could be improved.
To help you write your lab report, you will first answer the questions listed below by reflecting on the experiment you have just completed. Then you will use the answers to these questions to write the lab report that you will turn into your teacher.
You can upload your completed report with the upload tool in formats such as , Microsoft Word, or PDF. Alternatively, your teacher may ask you to turn in a paper copy of your report or use a web-based writing tool.
Questions
Section I: Experimental Overview
What is the purpose of the lab, the importance of the topic, and the question you are trying to answer?
What is your hypothesis (or hypotheses) for this experiment?
What methods are you using to test this (or each) hypothesis?
Section II: Data and Observations
Locate the data and observations collected in your lab guide. What are the key results? How would you best summarize the data to relate your findings?
Do you have quantitative data (numerical results or calculations)? Do you have qualitative data (written observations and descriptions)? How can you organize this date for your report?
Section III: Analysis and Discussion
What do the key results indicate?
If you constructed graphs, what trends do they indicate in your data?
Answer:
If you constructed graphs, what trends do they indicate in your data?
Convert 0.809 mol AlCl3 to formula units AlCl3.
Answer:
133.340538.
Explanation:
The answer is 133.340538. We assume you are converting between grams AlCl3 and mole. You can view more details on each measurement unit: molecular weight of AlCl3 or mol This compound is also known as Aluminium Chloride. The SI base unit for amount of substance is the mole.
Which of these hazmat products warnings or labels are allowed in your FC?
Please choose all that apply.
Fully Regulated Aerosol Placard
Fully Regulated Flammable
Liquid Placard
Fully Regulated Flammable Solid Placard
Lithium-Ion/Metal Battery label
Answer:
The following are the Hazmat products warnings that are allowed:
Fully Regulated Aerosol Placard
Fully Regulated Flammable
Fully Regulated Flammable Solid Placard
Lithium-Ion/Metal Battery label
Explanation:
Hazmat products are substances and materials that are dangerous and poses a risk to people when stored, handled or transported from one location to another at any given time.
Those products are meant to be handled with utmost care, and any carelessness on the individual in question could lead to harm. For example, regulated flammable liquid like kerosene needs utmost care when stored to avoid causing fire outbreak in the location where it is stored.