A researcher notices that atoms of an element x are releasing energy. Why does this happen?

Answers

Answer 1

Answer:

The atoms are affected by light.

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Related Questions

Why is it important to conserve or save our energy resources?
I will give Brainliest
Please Help

Answers

answer:

reducing energy use limits the number of carbon emissions in the environmentconserving energy produces a higher quality of life. Reduced emissions result in cleaner air qualityit helps create a healthier planet, or at least helps sustain the resources we already have

explanation:

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Which component of weather describes the weight of the atmosphere pressing down on Earth? (2 points)

Air pressure

Air temperature

Precipitation

Wind direction

Answers

Answer:

Low-pressure systems are associated with clouds and precipitation that minimize temperature changes throughout the day, whereas high-pressure systems normally associate with dry weather and mostly clear skies with larger diurnal temperature changes due to greater radiation at night and greater sunshine during the day.

Explanation:

How do we know if molecules have kinetic energy?

Answers

By looking at their temperature. The hotter/warmer something is, the more average kinetic energy the thing has. The cooler it is, the slower. Hope this helps!

At which position on the diagram would an apple have the greatest potential energy?

Answers

Answer:

Position 1 because it is the highest from the ground.

Hope this helps!

Describe the bonding process when two hydrogen atoms combine to
form a diatomic molecule of hydrogen.

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Answer:

The electrons located between the two nuclei are bonding electrons. A hydrogen molecule forms from two hydrogen atoms, each with one electron in a 1 s orbital. The two hydrogen atoms are attracted to the same pair of electrons in the covalent bond. The bond is represented either as a pair of dots or as a solid line.

Pls help fast, I will give brainliest!

Answers

Answer:

c

Explanation:

what does energy mean?

Answers

Answer:

strength and vitality required for sustained physical or mental activity

Explanation:

Answer:

energy is the quantitative property that must be transferred to an object in order to perform work on, or to heat, the object.

what are the affects of increasing thermal energy B

Answers

Answer:

The molecules tend to speed up and move faster throughout the substance once thermal energy increases. This is evident whenever we heat up water as its molecules tend to move faster throughout the water as thermal energy tends to increase

Hope this helps!

What statements are true about mutations to DNA?

Answers

Answer:

Is this a general question or is there supposed to be a picture

Explanation:

Help me please!

Main-block transition metals, such as iron, make good building materials for all of the following reasons EXCEPT____.

A. Resistance to corrosion
B. Insulation
C. Strength
D. High density

Answers

the answer is most likely d have a great day

calculate the mass of 0.5mols of CH3COOH​

Answers

Answer:

30 g

Explanation:

In order to convert from moles of CH₃COOH to grams, we need to use its molar mass:

Molar mass of CH₃COOH= (Molar Mass of C)*2 + (Molar Mass of H)*4 + (Molar Mass of O)*2 = 60 g/mol

Now we convert moles into grams:

0.5 mol * 60 g/mol = 30 g

So 0.5 moles of CH₃COOH have a mass of 30 grams.

moles are in 4.3 * 10^22 molecules of H3PO4

Answers

Answer:

The answer is 0.073

Explanation:

Final step: 0.73 x 10^-1

What do you understand by a chemical reaction

Answers

Answer:

A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products. ... A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

What is the specific heat capacity of a 70 g sample of an unknown metal that releases 6700J of heat when it cools from 90 to 25 degrees C?

Answers

q = mCpΔT —> Solve for Cp —> Cp = q/mΔT

q = -6700 J (negative because it released heat
m = 70 g
ΔT = Final temp - initial temp = 25 - 90 = -65°C

Cp = -6700 J / (70 g)(-65°C) = 1.47 J/g°C

1.47 J/g°C is the specific heat capacity of a 70 g sample of an unknown metal that releases 6700J of heat when it cools from 90 to 25 degrees C.

What is specific heat capacity?

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

q = mCpΔT

Solve for Cp —> Cp = q/mΔT

q = -6700 J (negative because it released heat)

m = 70 g

ΔT = Final temp - initial temp = 25 - 90 = -65°C

Cp = (-6700 J) ÷ (70 g)(-65°C)

= 1.47 J/g°C

Hence, 1.47 J/g°C is the specific heat capacity of a 70 g sample of an unknown metal that releases 6700J of heat when it cools from 90 to 25 degrees C.

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What is the relationship between radioactive decay and radiometric dating?

Answers

Answer:

Radiometric dating, is called radioactive dating, is a technique used to determine the age of materials such as rocks. It is based on a comparison between the observed abundance of a naturally occurring radioactive isotope and its decay products, using known decay rates.

Explanation:

:)

How many moles of water are produced when 6.0 moles of hydrogen gas react with 2.5 moles of oxygen gas?

Answers

Answer:

2.5 mole O2 should react (2 * 2.5) = 5.0 mole H2 but there is 6.0 mole H2. H2 remain in excess. O2 is the limiting reactant. mole of H2O formed = 2 * 2.5 = 5.0 mole.

Moles of water are produced when 6.0 moles of hydrogen gas react with 2.5 moles of oxygen gas

Balanced equation: 2H2 + O2 → 2H2O

2.5 mole O2 should react (2 × 2.5) = 5.0 mole

H2 but there is 6.0 mole H2.

H2 remain in excess. O2 is the limiting reactant.

mole of H2O formed = 2 × 2.5 = 5.0 mole.

= 5.0 mole

If less than 6 moles of oxygen are available per mole of glucose, oxygen is the limiting reactant. The ratio is 6 mole oxygen per 1 mole glucose, OR 1 mole oxygen per 1/6 mole glucose.

Limiting reactant-Limiting reactant- the reactant that determines the amount of product that can be produced because of the amount of that reactant present. Whichever reactant yields the LEAST amount of product is the limiting reactant. This will be completely used up in the reaction. After the reaction is complete, there will be product, and unused excess reactant.

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When electrons lost a blank ion is formed

When electrons are gained a blank ion is formed

Answers

Answer:

I love it

Explanation:

☁️ Answer ☁️

annyeonghaseyo!

Your answer is:

When electrons are lost, a positively charged ion is formed. When electrons are gained, a negatively charged ion is formed. (I like the car)

Hope it helps.

Have a nice day noona/hyung!~  ̄▽ ̄❤️


2Na + 2H2O → 2NaOH+ H2
How many grams of sodium would be needed to produce 1.00kg of sodium hydroxide?

Answers

Answer:

575 g

Explanation:

1 kg of sodium hydroxide is 1000/40=25 mol.

So 25 mol of sodium will be needed.

25 mol of sodium is 575 g.

According to the stoichiometry of the given chemical equation, 575 g s of sodium would be needed to produce 1.00 kg of sodium hydroxide.

What is chemical equation?

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

46 g sodium gives 80 g sodium hydroxide, thus 1000 g sodium hydroxide requires 46×1000/80=575 g sodium.

Thus, 575 g s of sodium would be needed to produce 1.00 kg of sodium hydroxide.

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What is the correct illustration of the bonding that occurs in H2O?

Answers

Answer:

covalent is the bonding that occurs in H2O  

Explanation:

What can the period number of an element tell us about that element?

Answers

Answer:

All of the elements in a period have the same number of atomic orbitals.

Explanation:

Which is an example of a homoozygous genotype? (There can be more than one answer)
Hh
HH
hh

Answers

Answer:

HH and hh

Explanation:

they are the same

46:56
A piece of carpet is 8 feet wide and 12 feet long. The carpet needs to be reduced by a scale factor so that the reduced carpet is 2 feet wide. What is the area of the reduced carpet?
6 square feet
12 square feet
24 square feet
48 square feet

Answers

Answer:

12 square feet i jope.please be right

A gas has a volume of 240.0mL at 25.0 oC and 0.79 atm. Calculate its volume at STP (1 atm and 0 oC).

Answers

Answer:

189.6 mL

Explanation:

As per Boyles law when a gas is kept at a constant temperature and mass in a closed container, the volume and pressure vary inversely.

P1V1= P2V2

Here, P1 = 0.79 atm, V1 = 240 ml, P2= 1 atm

therefore, substituting values in above equation we get

0.79×240 = 1×V2

⇒V2 = 189.6 ml

therefore,  its volume at STP (1 atm and 0 oC) = 189.6 ml

1. Calculate the molarity of a solution containing 49.3g of dissolved naphthalene (C10H8) in 217g benzene (C6H6).

2. A solution is prepared by mixing 94.2g of H2O, and 58.7g of ethanol, C2H5OH. Determine the mole fractions of each substance.

3. If you use 2.17mol of sucrose (C12H22O12) and dissolve this into 0.500kg of H2O, what will be the change in the freezing point of your solution? The freezing point depression of water (Kf) is 1.86 degrees Celsius/m.

Answers

Answer:

1. 1.56 M

2. Water →  0.803

Ethanol → 0.197

3. - 8.07°C

Explanation:

1. To solve this problem, we need benzene's density in order to determine the volume.

We assume the volume of solvent, as the volume of solution

Density for benzene is 0.8786 g/mL.

Density = m/V → V = m/density

Volume = 217 g /0.8786 g/mL = 247 mL

We convert the mass to moles and then, to mmoles

49.3 g . 1mol / 128g . 1000mmol / mol = 385.1 mmol

M = 385.1 mmol / 247mL = 1.56 M

2. We determine moles of each, solute and solvent

94.2 g. 1mol /18g = 5.23 moles of water

58.7 g . 1mol /46g = 1.28 moles of ethanol.

Total moles = 5.23 + 1.28 = 6.51

Mole fraction of water = Moles of water / Total moles

Mole fraction of ethanol = Moles of ethanol / Total moles

Water → 5.23 / 6.51 = 0.803

Ethanol →  1.28 / 6.51 = 0.197

3. Freezing point depression → ΔT = Kf . m . i

i = Van't Hoff factor, ions that are present in the solution.

As the solute is organic, i = 1.

Kf = 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

2.17 mol / 0.5kg = 4.34 m

ΔT = Freezing T° of pure solvent - Freezing T° of solution.

We replace data → 0° - Freezing T° of solution = 4.34m . 1.86°c/m . 1

Freezing T° of solution = - 8.07°C

How many moles of solute should be dissolved into 3.0 L of solvent to make a concentration of 2.0 M?
6.0 mol

1.5 mol

0.67 mol

1.0 mol

Answers

Answer:

There are 0.1 moles of solute in 250 mL of 0.4 M solution.

Students were asked to select methods to increase the rate of dissolving a solid. Which methods would increase the rate?

Answers

Increasing the surface area, stirring or agitating the mixture, raising the solvent's temperature, and employing a solvent with a stronger polarity or one that is more similar to the solid's chemical makeup are all ways to speed up the dissolving process.

The methods to increase the rate of dissolving a solid.

There are several methods that can increase the rate of dissolving a solid, including:

Increasing the surface area of the solid by crushing, grinding or pulverizing it into smaller pieces.

- Stirring or agitating the mixture, which helps to distribute the solvent and increase contact between the solvent and the solid.

- Increasing the temperature of the solvent, which increases the kinetic energy of the solvent molecules, making them more likely to collide with and dissolve the solid.

- Using a solvent that has a higher polarity or is more similar in composition to the solid, which can increase the attraction between the solvent and the solid and promote faster dissolving.

Therefore, the methods that would increase the rate of dissolving a solid are increasing surface area, stirring or agitating the mixture, increasing the temperature of the solvent, and using a solvent that has a higher polarity or is more similar in composition to the solid.

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is.
O2(g) + 2H2O(l) + 4e- -----------------> 4OH−(aq)

oxidation or reduction?

Answers

Answer:

Reduction

Explanation:

Oxidation is a process that involves loss of electrons.

Reduction is a process that involves gain of electrons.

In this equation, the electrons (4e-) are in the reactant side. This means that it is gain of electrons.

The reaction is a reduction reaction.

Which organism is an example of a producer?
a. Wheat
b. Pigeon
c. cheetah
d. mushroom

Answers

Answer: wheat

Explanation: a pigeon does not produce food nor a cheetah or mushroom because a mushroom breaks down subsistence.

UGRENT! Please help showing all work

Answers

Answer:

a. The limiting reactant is Ca(OH)₂

b. The theoretical yield of CaCl₂ is approximately 621.488 grams

c. The percentage yield of CaCl₂ is approximately 47.06%

Explanation:

a. The given chemical reaction is presented as follows;

Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O

Therefore;

One mole of Ca(OH)₂ reacts with two moles of HCl to produce one mole of CaCl₂ and two moles of water H₂O

The mass of HCl in an experiment, m₁ = 229.70 g

The mass of Ca(OH)₂ in an experiment, m₂ = 207.48 g

The molar mass of HCl, MM₁ = 36.458 g/mol

The molar mass of Ca(OH)₂, MM₂ =74.093 g/mol

The number of moles of HCl, present, n₁ = m₁/MM₁

∴ n₁ = m₁/MM₁ = 229.70 g/(36.458 g/mol) ≈ 6.3 moles

The number of moles of Ca(OH)₂, present, n₂ = m₂/MM₂

∴ n₂ = m₂/MM₂ = 207.48 g/(74.093 g/mol) ≈ 2.8 moles

The number of moles of Ca(OH)₂, present, n₂ = 2.8 moles

According the chemical reaction equation the number of moles of HCl the 2.8 moles of Ca(OH)₂ will react with, = 2.8 × 2 moles = 5.6 moles of HCl

Therefore, there is an excess HCl in the reaction and Ca(OH)₂ is the limiting reactant

b. According the chemical reaction equation the number of moles of CaCl₂ produced in he reaction by the 2.8 moles of Ca(OH)₂ = 2.8 × 2 moles = 5.6 moles of CaCl₂

The molar mass of CaCl₂ = 110.98 g/mol

The mass of the 5.6 moles of CaCl₂ = 5.6 moles × 110.98 g/mol ≈ 621.488 grams

The theoretical yield of CaCl₂ ≈ 621.488 grams

c. Given that the actual mass of CaCl₂ produced = 292.5 grams, we have;

The percentage yield of CaCl₂ = The actual yield/(The theoretical yield) × 100

∴ The percentage yield of CaCl₂ = (292.5 g)/(621.488 g) × 100 ≈ 47.0644646397%

The percentage yield of CaCl₂ ≈ 47.06%.

Give reasons :
Concentrated H2SO4 cannot be used instead of dilute H2SO4 in laboratory preparation of hydrogen gas why ?

Answers

Because concentrated sulfuric acid is a strong oxidizer, so it has to be in water to react with metals and produce hydrogen properly. Sometimes dilute sulfuric acid is used, but that is another story
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