Answer:
Explanation:
At both interface light is travelling from a medium of lower refractive index to medium of higher refractive index. So the phase difference of 180⁰ occurring at both interface will cancel out .
Net path difference = 2 μ t where μ is refractive index of thin layer and t is its thickness
For destructive interference
2 μ t = (2n + 1 )λ / 2 where λ is wavelength of light , n is any number
λ = 4 μ t / ( 2 n + 1 )
For largest wavelength , n = 0
λ = 4 μ t
= 4 x 1.22 x 138 nm
= 673.44 nm .
Cloudy days tend to have a greater range of temperatures than clear days. True or false?
Answer:
true
Explanation:
Answer:
true
Explanation:
The wire A and B are made of copper. Both w
wires are in
long but wire A is 1mm thick and wire B is 2mm thick, the
specific resistance is
a) more than A
b) more than B
c) same for both
d) cannot compared
A simplified model of a bungee jump can be analyzed in two sections: a freefall section in which the bungee cord has not yet begun stretching and a section in the lower portion of the jump in which the bungee cord stretches and exerts a force on the jumper. The cord is assumed to exert zero force on the jumper until its length exceeds its maximum unstretched length. Determine the maximum unstretched length of a bungee cord of spring constant 100 N/m such that a 70-kg jumper will not hit the ground when jumping from a height of 45 m.
Answer:
[tex]20.14\ \text{m}[/tex]
Explanation:
m = Mass of person = 70 kg
k = Spring constant = 100 N/m
h = Total length of the bungee cord = 45 m
The energy balance of the system is
[tex]mgh=\dfrac{1}{2}kx^2\\\Rightarrow x=\sqrt{\dfrac{2mgh}{k}}\\\Rightarrow x=\sqrt{\dfrac{2\times 70\times 9.81\times 45}{100}}\\\Rightarrow x=24.86\ \text{m}[/tex]
Maximum unstretched length would be [tex]h-x=45-24.86=20.14\ \text{m}[/tex].
solve the quadratic equation: 5x²-2x-25=0
The temperature of an object is
A. The average kinetic energy of its atoms and molecules
B. The total potential and kinetic energy of its atoms and molecules
C. The transfer of kinetic energy from one place or object to another through collisions between atoms and molecules
Two bodies, A and B, have equal kinetic energies. The mass of A is nine times that of B. The ratio of the momentum of A to that of B is:_______.A. 1:9B. 1:3C. 1:1D.3:1E. 9:1
Answer:
D. 3 : 1
Explanation:
Let suppose that A and B are particles. From statement we know that [tex]K_{A} = K_{B }[/tex] (same kinetic energy) and [tex]m_{A} = 9\cdot m_{B}[/tex]. Then,
[tex]K_{A} = K_{B}[/tex]
[tex]\frac{1}{2}\cdot m_{A}\cdot v_{A}^{2} = \frac{1}{2}\cdot m_{B}\cdot v_{B}^{2}[/tex]
[tex]m_{A} \cdot v_{A}^{2} = m_{B}\cdot v_{B}^{2}[/tex]
[tex]\frac{v_{B}}{v_{A}} = \sqrt{\frac{m_{A}}{m_{B}} }[/tex]
[tex]\frac{v_{B}}{v_{A}} = 3[/tex]
And the ratio of the momentum of A to the momentum of B is:
[tex]r = \frac{m_{A}\cdot v_{A}}{m_{B}\cdot v_{B}}[/tex]
[tex]r = 9\times \frac{1}{3}[/tex]
[tex]r = 3[/tex]
Hence, the correct answer is D.
A student carries a backpack for one mile. Another student carries the same backpack for two miles
Compared to the first student, how much work did the second student do?
Answer:
Compared to the first student, the second student did twice as much work as the first student.
Explanation:
The work done by the first student will be equal to the Force exerted by the backpack on the student carrying it multiplied by one mile (Distance). The work done by the second student will be equal to the Force exerted by the backpack on the student carrying it multiplied by two miles (Distance).
Can any wan help pls
Answer:
b
Explanation:
because of bonds and the bowl is used for heating purpose
Answer:
I think b not sure but I hope its right and is that the nwea test??
is it possible for an atom to lose a proton and have a negative charge?
explain
Answer:
Sometimes atoms gain or lose electrons. The atom then loses or gains a "negative" charge. These atoms are then called ions. Positive Ion - Occurs when an atom loses an electron negative charge it has more protons than electrons.
Explanation:
:)
A ball whose mass is 1.8 kg is suspended from a spring whose stiffness is 8.5 N/m. The ball oscillates up and down with an amplitude of 13 cm. (a) What is the angular frequency
Answer:
The angular frequency of the ball is 2.173 rad/s.
Explanation:
Given;
mass of the ball, m = 1.8 kg
spring constant, k = 8.5 N/m
maximum displacement of the ball, A = 13 cm = 0.13 m
The angular frequency of the ball is calculated as;
[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{8.5}{1.8}} \\\\\omega = 2.173 \ rad/s[/tex]
Therefore, the angular frequency of the ball is 2.173 rad/s.
a cart is pulled along at an angle of 30 degrees along the floor to a distance of 20 metres in 30 seconds with a force of 750 Newton find the power in watts
Answer:
500
p=w/t
w=force *displacement
w=750*20=15000j
p=15000/20=500watt
Explanation:
500
p=w/t
w =force displacement
w=750*20=15000j
p=15000/20=500 watt
A pelican hunts fish in the water. As the pelican flies above the water’s surface, why must it aim for the fish in a slightly different place than where the fish appears to be located?
A. Light reflects off the fish, except for light of the wavelength the fish absorbs, making the fish hard to see.
B. Water absorbs most of the light, so not much light reaches the pelican’s eyes.
C. Energy from the ocean waves is transferred to the light waves.
D. Light waves are refracted as they travel from air to water.
Light reflects off the fish, except for light of the wavelength the fish
absorbs, making the fish hard to see which is why it must aim for the fish in
a slightly different place.
What is Reflection?This is the change in the direction of propagation of a wave that strikes the
boundary between different mediums and in this case, the medium is
water.
The change in direction which occurs during reflection of the light
makes it harder for the Pelican ro see which is why it must aim for the
fish in a slightly different place.
Read more about Reflection here https://brainly.com/question/26494295
A bucket is filled partly with water such that its combined mass is 2.17 kg. It is tied to a rope and whirled in a circle with a radius of 1.13 m. The speed at the top of the circle is 4.42 m/s and the speed at the bottom of the circle is 7.1 m/s. (a) Determine the acceleration, net force and tension force at the top of the circle.
Answer:
1) a = 17.3 m/s²
2) Fnet = 37.5 N
3) T = 16.2 N
Explanation:
1)
When the bucket is at the top of the circle, there are two forces acting on it: the tension force (T) which pulls from the bucket, so it is directed downward, and the force due to gravity, that also points downward, so both forces add:[tex]F_{net} = T + m*g (1)[/tex]According to Newton's 2nd Law, this net force must be equal to the mass of the bucket, times the acceleration.Now, due to the bucket is moving around a circle, there must be a force that keeps the bucket following a circular trajectory, that is the centripetal force, and always aims toward the center of the circle.This force is not a new type of force, it's always the net force that aims toward the center.At the top of the circle, because as the tension force as gravity point downward, the centripetal force, is just this net force.It can be showed that the centripetal force can be written as follows:[tex]F_{c} = m*a_{c} = m*\frac{v^{2}}{r} (2)[/tex]
Since we have already said that a = ac (At the top of the circle), we can solve (1) for a, simplifying and replacing v and r by their values, as follows:[tex]a = a_{c} = \frac{v^{2} }{r} = \frac{(4.42m/s)^{2} }{1.13m} = 17.3 m/s2 (3)[/tex]
2)
Once we got the value of a, applying Newton's 2nd law, we can find easily the net force on the bucket at the top of the circle, as follows:[tex]F_{net} = m*a = 2.17 kg * 17.3 m/s2 = 37.5 N (4)[/tex]
3)
We have already said, that at the top of the circle, the net force is just the sum of the tension T and the force of gravity, as follows:[tex]F_{net} = T + m*g = 37.5 N (5)[/tex]
Replacing m and g by their values, we can solve (4) for T:[tex]T = 37.5 N - m*g = 37.5 N - (2.17kg*98m/s2) \\ = 37.5 N - 21.3 N = 16.2 N (6)[/tex]
If an object has a mass of 210g and the net force acting upon it is 5.0N, what is the acceleration of that object?
Answer:
24ms^-2 (2 sig figs)
Explanation:
F = ma
This means that the sum of all forces (or the net force) acting upon an object is equal to its mass x accelleration.
Its important to convert all parts of this equations in to SI units such that Force (N), Mass (kg) and Accelleration (ms^-2) to make sure that your answer is in the correct units.
F = ma so 5 = 0.21a
a = 5/0.21
a = 23.810 ms^-2 (5 sig figs)
Which is an example of kinetic energy?
A. The energy stored in
ethanol
B. A ball sitting at the top of a ramp
C. A compressed spring
D. A hockey puck sliding across ice
D. A hockey puck sliding across ice
What is the best anime show to watch? I need to watch some more anime and I need some shows lol
Try watching Demon Slayer on Netflix. It's a new series, and it's very entertaining to watch!! :)
(Brainliest please!)
The energy transformation a leaf on a tree undergoes when sunlight shines on it is an example of what?
Radiant to chemical
Mechanical to chemical
Electrical to mechanical
Chemical to radiant
1
2
3
4
5
Answer:Radiant to chemical
Explanation:
Assume all of the resistors in the following circuits have a value of 5 ohms. Which ammeter will have the highest
reading?
Answer:
Circuit B
Explanation:
To know the correct answer to the question, we shall determine the reading of the ammeter i.e the current in each circuit. This can be obtained as follow:
For circuit A:
Resistance (R) = 5 ohms
Voltage (V) = 1.5 V
Current (I) =?
V = IR
1.5 = I × 5
Divide both side by 5
I = 1.5 / 5
I = 0.3 A
For circuit B:
We'll begin by calculating the total resistance in the circuit. This can be obtained as follow:
Resistance 1 (R₁) = 5 ohms
Resistance 2 (R₂) = 5 ohms
Total resistance (Rₜ) =?
Since they are in parallel connections, the total resistance can be obtained as illustrated below:
Rₜ = R₁ × R₂ / R₁ + R₂
Rₜ = 5 × 5 / 5 + 5
Rₜ = 25 / 10
Rₜ = 2.5 ohms
Finally, we shall determine the current in the circuit.
Resistance (R) = 2.5 ohms
Voltage (V) = 1.5 V
Current =?
V = IR
1.5 = I × 2.5
Divide both side by 2.5
I = 1.5 / 2.5
I = 0.6 A
For circuit C:
We'll begin by calculating the total resistance in the circuit. This can be obtained as follow:
Resistance 1 (R₁) = 5 ohms
Resistance 2 (R₂) = 5 ohms
Total resistance (Rₜ) =?
Since they are in series connections, the total resistance can be obtained as illustrated below:
Rₜ = R₁ + R₂
Rₜ = 5 + 5
Rₜ = 10 ohms
Finally, we shall determine the current in the circuit.
Resistance (R) = 10 ohms
Voltage (V) = 1.5 V
Current =?
V = IR
1.5 = I × 10
Divide both side by 10
I = 1.5 / 10
I = 0.15 A
SUMMARY:
Circuit >>>>>>> Current
A >>>>>>>>>>>> 0.3 A
B >>>>>>>>>>>> 0.6 A
C >>>>>>>>>>>> 0.15 A
from the above calculations, circuit B has the highest ammeter reading.
What is cytoplasm in a animal cell?
Answer:
Cytoplasm is the jelly-like fluid that fills in all of the. space between the nucleus and the plasma membrane. All of the organelles within a cell are suspended in this fluid. The main function of the cytoplasm is to support the internal structures of the cell as well as maintaining shape and consistency of the cell.
Two identical conducting spheres are placed with their centers 0.30 m apart. One is given a charge of 12 X10^-9 C and the other is given a charge of -18 X 10^-9 C. a. Find the electric force exerted on one sphere by the other. b. The sphere are connected by a conducting wire. After equilibrium has occurred, find the electric force between the two spheres.
Answer:
Explanation:
Force between two charged conducting sphere
= k x Q₁ x Q₂ / r² , k is a constant Q₁ and Q₂ are charges and r is distance between them .
= 9 x 10⁹ x 12 x 10⁻⁹ x 18 x 10⁻⁹ / .30²
= 21600 x 10⁻⁹
= 2.16 x 10⁻⁵ N .
b )
After the spheres are joined together , there is redistribution of charge and remaining charge will be equally shared by them .
Charge on each sphere = (12 - 18 ) x 10⁻⁹ / 2
= - 3 x 10⁻⁹ C .
Force = 9 x 10⁹ x 3 x 10⁻⁹ x 3 x 10⁻⁹ / .30²
= 900 x 10⁻⁹ N .
what are the types of energy sources based on
time of replacement ? write down their names
Answer:
solar energy
wind power
geothermal energy
hydraulic power
biomass energy
energy storage
(That's all I know).
Describe how a student would use the circuit to take the readings necessary to determine the
resistance of resistor R.
Answer:
[tex]R = \frac{V}{A}[/tex]
Explanation:
See attachment for circuit
From the circuit, we have:
[tex]V = Voltage[/tex]
[tex]A = Current[/tex]
[tex]R = Resistance[/tex]
Resistance is calculated as:
[tex]R = \frac{V}{A}[/tex]
The steps are as follows:
Step 1: The student needs first to power on the circuit
Step 2: The student then take readings from both the ammeter (for current) and from the voltmeter (for voltage)
Step 3: Record new readings for current and voltage by adjusting the variable resistor
Step 4: Draw a voltage-current graph
Step 5: : Lastly, calculate the slope of the graph
The slope represents the resistance
Pick a small appliance in your home that you use regularly and look up on the internet how much power it operates at. Using the household voltage of 120 V, calculate the current flowing in this device. How much resistance would a resistor operating at that power and voltage have? If electricity costs $0.12/kWh, estimate how much you spend each month using this appliance. When you make your video, be sure to show the appliance you are talking about.
Answer:
Estimate money spent on the appliance( 9 Watt bulb ) on a monthly basis is $0.7776
Explanation:
Given the data in the question;
we are to pick a small appliance in our home that we use regularly and look up on the internet how much power it operates at;
so lets consider a 9 Watt bulb
Power p = 9 Watt
Household Voltage = 120 v
we know that; Power = Current I × Voltage V
so,
9 = I × 120
I = 9 / 120
I = 0.075 A
Resistance;
R = V / I
R = 120 / 0.075
R = 1600 Ω
Now, Energy consumed in 1 month(30 days) will be;
E = P × Τ
E = ( 9 / 1000kW ) × ( 30 × 24hrs )
E = 0.009 × 720 hrs
E = 6.48 kWh
Now, the cost for one month will be;
Cost = 6.48 × $0.12
Cost = $0.7776
Therefore, estimate money spent on the appliance( 9 Watt bulb ) on a monthly basis is $0.7776
Two charged particles exert a force of 0.042 N on each other. Suppose that the particles are moved such that they are now one-eighth as far apart. What is the new force between the particles?
Answer:
New force = 2.688 N
Explanation:
Given that,
Two charged particles exert a force of 0.042 N on each other.
Let the initial distance is r. Later the particles are moved such that they are now one-eighth as far apart.
New distance, r' = (r/8)
The force between particles is given by :
[tex]F'=\dfrac{kq_1q_2}{r'^2}\\\\F'=\dfrac{kq_1q_2}{(\dfrac{r}{8})^2}\\\\F'=\dfrac{kq_1q_2}{\dfrac{r^2}{64}}\\\\F'=64\times \dfrac{kq_1q_2}{r^2}\\\\F'=64\times F\\\\F'=64\times 0.042\\\\F'=2.688\ N[/tex]
So, the new force is 2.688 N.
A freight train has a mass of [02] kg. The wheels of the locomotive push back on the tracks with a constant net force of 7.50 × 105 N, so the tracks push forward on the locomotive with a force of the same magnitude. Ignore aerodynamics and friction on the other wheels of the train. How long, in seconds, would it take to increase the speed of the train from rest to 80.0 km/h?
Answer:
t = 300.3 seconds
Explanation:
Given that,
The mass of a freight train, [tex]m=1.01\times 10^7\ kg[/tex]
Force applied on the tracks, [tex]F=7.5\times 10^5\ N[/tex]
Initial speed, u = 0
Final speed, v = 80 km/h = 22.3 m/s
We need to find the time taken by it to increase the speed of the train from rest.
The force acting on it is given by :
F = ma
or
[tex]F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{1.01\times 10^7\times (22.3-0)}{7.5\times 10^5}\\\\t=300.3\ s[/tex]
So, the required time is 300.3 seconds.
Glenn shoots an arrow at a 30.0 degree angle. It has a velocity of 65.0 m/s.
How far will the arrow travel? *
Answer:
The horizontal distance traveled by the projectile is 373.36 m.
Explanation:
Given;
angle of projection; θ = 30⁰
initial velocity of the projectile, u = 65 m/s
The horizontal distance traveled by the projectile or range of the projectile is calculated as;
[tex]R = \frac{u^2 \times sin(2\theta)}{g} \\\\R = \frac{65^2 \times sin(2\times 30^0)}{9.8}\\\\R = \frac{4225\times sin(60)}{9.8} \\\\R = 373.36 \ m[/tex]
Therefore, the horizontal distance traveled by the projectile is 373.36 m.
PLEASE HELP! I WILL GIVE BRAINLIEST! :D
Which of these is true about the total energy in an object?
A - Can be destroyed
B - Cannot be constant
C - Cannot be transferred to other objects
D - Can be changed from one form to another
Answer:
Can be changed from one form to another
Explanation:
According to the law of conservation of energy the total energy of a system remains conserved. It only change state from one form of energy to another.
The total energy is also known as mechanical energy. It is equal to the sum of kinetic energy and the potential energy.
Hence, the correct option is (d) "can be changed from one form to another".
Answer:
D - Can be changed from one form to another
Please help! quick and easy chart.
Answer:
sound and happiness are not matter
Explanation:
The current flow in the light bulb is 0.5A
a.Calculate the amount of electric charge that flow through the bulb in 2 hour
b.If one election carries a
charge 1.6 x 10-14 c Find the number of election through the bulb in 2 hour?
Answer:
Explanation:
Given that,
The current in the light bulb, I = 0.5 A
(a) We know that,
Electric current = charge/time
or
Q = It
Put t = 2 hours = 7200 s
So,
Q = 0.5 × 7200
Q = 3600 C
(b) Charge on one electron, [tex]Q=1.6\times 10^{-19}\ C[/tex]
Let there are n electrons flow through the bulb in 2 hours.
I = Q/t
Since, Q = ne
So,
I = ne/t
[tex]n=\dfrac{I\times t}{e}\\\\n=\dfrac{0.5\times 7200}{1.6\times 10^{-19}}\\\\n=2.25\times 10^{22}[/tex]
Hence, this is the required solution.
TWO forces, one of 12N and another or 24N
act on body in such a way that they make an angle of 90° with each other. Find the resaltant of two forces.
Answer:
26.833 N
Explanation:
The computation of the resaltant of two forces is shown below:
Given that
Force A = 12N
Force B = 24N
Based on the above information
Resultant R is
[tex]=\sqrt{A^2 + B^2 + 2AB \times cos \theta}\\\\=\sqrt{144 + 576 + 2\times 24\times 12\times cos90^{\circ}}\\\\=\sqrt{144+576+576\times 0}\\\\=\sqrt{720}[/tex]
=26.833 N