Answer:
A) Total distance Alf travel during the same amount of time = [tex]\frac{1}{4}s[/tex]
B) Speed of Beth = 4v
Explanation:
Given - Consider two musicians, Alf and Beth. Beth is four times the
distance from the inside of the curve as Alf.
To find - A) Knowing that If Beth travels a distance s during time Δt, how
far does Alf travel during the same amount of time.
B) If Alf moves with speed v, what is Beth's speed?
Proof -
A)
As we know that
Speed = Distance / Time
⇒Distance = Speed ×Time
Now,
Given Speed of Alf = v
⇒Distance of Alf = vt
Also,
Distance of Beth = Speed of beth×time
Given that
Beth is four times the distance from the inside of the curve as Alf. Knowing that If Beth travels a distance s during time Δt, how far does Alf travel during the same amount of time=
⇒Distance of Alf = Speed of Alf×time
= [tex]\frac{1}{4}[/tex] Distance of Beth
⇒Distance of Alf = [tex]\frac{1}{4}s[/tex]
∴ we get
Total distance Alf travel during the same amount of time = [tex]\frac{1}{4}s[/tex]
B)
We know the conversion of angular velocity
ω(Alf) = ω(Beth)
⇒V(Alf)/ r = V(Beth)/4r
⇒V(Alf) = V(Beth) / 4
⇒V(Beth) = 4 V(Alf)
As given, Alf moves with speed v
⇒V(Beth) = 4v
So, the correct option is - a.4v
How to calculate the voltage of a light bulb
A) how many cm³ are there in 0.08L?
B) How many dm³ are there in 750mL?
Answer:
A) 80 cm³
B) 0.75 dm³
Explanation:
I hope this help❤️
NEED HELP ASAP!!!
-The difference between chemical reactions and nuclear reactions
-The difference between fission and fusion
-What is given off during nuclear decay (how elements change into others)
-How to calculate half life or amount of sample left from half life
Explanation:
Chem has to do with stored energy while nucleic deals with nucleic reactions.
. What is the height in meters of a 5'4" person?
Answer:
1.62 meters
Explanation:
For an approximate result, divide the feet (height) by 3.3 to get your approximate meters (height).
Match the following items.
1. Extremely small building blocks of matter.
2. Forming new matter from old matter.
3. Small bits of matter.
atom
molecule
chemical change
An acceleration constraint says that in some circumstances An acceleration constraint says that in some circumstances the acceleration of an object has to be positive. two objects have to accelerate in the same direction. two objects must have accelerations of equal magnitude. an object is prevented from accelerating.
Answer:
two objects must have accelerations of equal magnitude.
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
[tex]a = \frac{v - u}{t}[/tex]
Where,
a is acceleration measured in [tex]ms^{-2}[/tex]
v and u is final and initial velocity respectively, measured in [tex]ms^{-1}[/tex]
t is time measured in seconds.
Acceleration constraint refers to a precise relationship between the acceleration of two physical objects.
An acceleration constraint says that in some circumstances two objects must have accelerations of equal magnitude.
What is double stroking
Answer: The double stroke roll works just like the single stroke roll - it's played in a sequence of alternating strokes (roll). But instead of having one stroke per hand you'll have two, as shown on the sheet music below. You can use full wrist turns to play each stroke of the double stroke at slower speeds.
Explanation: hope this helps!
Explanation:
it is played as a sequence of alternating strokes
An instrument that produces an electric current in the presence of
a radioactive substance is called a
a. particle accelerator.
b. Geiger counter.
c. cloud chamber.
d. bubble chamber.
Answer:
Option B, Geiger counter
Explanation:
We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top of the tree exerts a horizontal force, and thus a torque that can topple the tree if there is no opposing torque. Suppose a tree's canopy presents an area of 9.0 m2 to the wind centered at a height of 7.0 m above the ground. (These are reasonable values for forest trees.)
Answer:
A,)FD= 114.1N
B)Torque=798.5Nm
Explanation:
We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top of the tree exerts a horizontal force, and thus a torque that can topple the tree if there is no opposing torque. Suppose a tree's canopy presents an area of 9.0 m^2 to the wind centered at a height of 7.0 m above the ground. (These are reasonable values for forest trees.)
If the wind blows at 6.5 m/s, what is the magnitude of the drag force of the wind on the canopy? Assume a drag coefficient of 0.50 and the density of air of 1.2 kg/m^3
B)What torque does this force exert on the tree, measured about the point where the trunk meets the ground?
A)The equation of Drag force equation can be expressed below,
FD =[ CD × A × ρ × (v^2/ 2)]
Where CD= Drag coefficient for cone-shape = 0.5
ρ = Density
Area of of the tree canopy = 9.0 m^2
density of air of = 1.2 kg/m^3
V= wind velocity= 6.5 m/s,
If we substitute those values to the equation, we have;
FD =[ CD × A × ρ × (v^2/ 2)]
F= [ 0.5 × 9.0 m^2 × 1.2 kg/m^3 ( 6.5 m/s/ 2)]
FD= 114.1N
B) the torque can be calculated using below formula below
Torque= (Force × distance)
= 114.1 × 7
= 798.5Nm
A 1.6-kg ball is attached to the end of a 0.40-m string to form a pendulum. This pendulum is released from rest with the string horizontal. At the lowest point of its swing, when it is moving horizontally, the ball collides with a 0.80-kg block initially at rest on a horizontal frictionless surface. The speed of the block just after the collision is 3.0 m/s. What is the speed of the ball just after the collision?a. 1.5 m/sb. 1.3 m/sc. 2.1 m/sd. 1.1 m/se. 1.7 m/s
Answer:
a. 1.5 m/s
Explanation:
We will apply the law of conservation of energy in this situation between the initial position and the lowest point of the swing:
[tex]m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}\\[/tex]
where,
m₁ = mass of ball = 1.6 kg
m₂= mass of block = 0.8 kg
u₁ = initial speed of ball = 0 m/s
u₂ = initial speed of block = 0 m/s
v₁ = final speed of ball = ?
v₂ = final speed of block = 3 m/s
Therefore,
[tex](1.6\ kg)(0\ m/s)+(0.8\ kg)(0\ m/s)=(1.6\ kg)(v_{1})+(0.8\ kg)(3\ m/s)\\\\v_{1} = \frac{2.4\ N.s}{1.6\ kg}\\[/tex]
v₁ = 1.5 m/s
Therefore, the correct option is:
a. 1.5 m/s
Look at the circuit diagram. What does the diagram show?
Answer:
the second one i gues
Explanation:
the stripes tells about the batery input/ the x is the lightbulbs/ and two switches
PLEASE HELP ME WITH THIS ONE QUESTION
A tuning fork of 500 Hz is struck in a room with a speed of sound of 340 m/s. What is the distance between a point of rarefaction and the next compression point, in the resulting sound?
Answer:
0.34 m
Explanation:
From the question,
v = λf................ Equation 1
Where v = speed of sound, f = frequency, λ = Wave length
Make λ the subject of the equation
λ = v/f............... Equation 2
Given: v = 340 m/s, f = 500 Hz.
Substitute these values into equation 2
λ = 340/500
λ = 0.68 m
But, the distance between a point of rarefaction and the next compression point, in the resulting sound is half wave length
Therefore,
λ/2 = 0.68/2
λ/2 = 0.34 m
Hence, the distance between a point of rarefaction and the next compression point, in the resulting sound is 0.34 m
two identical neutral metal spheres rest on an isolated table if you wanted to give it a net positive charge while spear to is given a net negative charge Which statement explains the movement of charges during the charging process
Answer:
its c
Explanation:
This square solenoid has sides length 25 cm, and 100 turns of wire. The resistance is 10 ohms. Find the magnitude of the induced emf in the coil if the magnetic field of 10 T is passing through the face of the loop as pictured. What is the induced current in the wire. Find the emf and current if the solenoid was a circle with radius 25 cm instead of a square.
Explanation:
Area of square = 25^2 = 625 cm^2 or = 0.0625 m^2
number of turns = 100
Solenoid resistance = 10 ohms
now we know , Φ = B.A
where , Φ = magnetic flux, B= magnetic field strength, and A = area.
Φ = 10 × 0.0625 = 0.625 W
induced emf ε = dΦ/dt = d(BA)/dt =0
This is because both B and A are constants.
⇒ Induced current is also zero.
Replacing square by a circle will not change situation as the value of B and A will remain constant with time hence, no emf induced, so no current induced.
ANSWER DIS ASAP FOR LUCK TMRW :}
List down ten situations that show how friction affects the movement of objects. I NEED THE ANSWER IN ONE MINUTE
Answer:
Walking –We can walk only if we apply frictional force. Friction is what holds your shoe to the ground. The friction present on the ice is very little, this is the reason why it is hard to walk on the slippery surface of the ice.
Writing – A frictional force is created when the tip of the pen comes in contact with the surface of the paper. Rolling friction is what comes into play while writing with a ballpoint pen while sliding friction arises when one writes with a pencil.
Skating – A thin film of water under the blade is necessary to make the skate slide. The heat generated by the skate blade rubbing against the surface of ice causes some of the ice to melt right below the blade where the skater glides over the ice. This water acts as a lubricant reducing friction.
Lighting a matchstick – When the head of the matchstick is rubbed against a rough surface, heat is generated and this heat converts red phosphorous to white phosphorous. White phosphorous is highly inflammable and the match stick ignites. Sometimes, matchsticks fail to ignite due to the presence of water. Water lowers friction.
Driving of the vehicle on a surface- While driving a vehicle, the engine generates a force on the driving wheels. This force initiates the vehicle to move forwards. Friction is the force that opposes the tyre rubber from sliding on the road surface. This friction avoids skidding of vehicles.
Applications of breaks in the vehicle to stop it- Friction braking is the most widely used braking method in vehicles. This process involves the conversion of kinetic energy to thermal energy by applying friction to the moving parts of a vehicle. The friction force resists the motion and in turn, generates heat. This conversion of energy eventually bringing the velocity to zero.
Flight of aeroplanes- Drag is the force that opposes the forward motion of the aeroplane. The friction which resists the motion of an object moving through a fluid or immobile in a moving fluid, as occurs when we fly a kite. The friction of the air is created as it meets and passes over an aeroplane and its components. Drag is generated by air impact force, skin friction and displacement of the air.
Drilling a nail into the wall- Friction is responsible for fixing of nails in a wall. As the nail is driven into the wall, the nearby material to the nail of the wall gets compressed. This exerts a force on the nail. This force is the friction that converts the normal force exerted by the compressed layers of the wall into the resisting shear force. In this manner the friction cause nails and screws to hold on to walls.
The dusting of the carpet by beating it with a stick- When the carpet is beaten with the stick, the dust comes out. The dust is carried off by the wind or falls on the floor. The carpet exhibits a little static friction that holds the dust to the carpet. When the carpet is beaten, it will overcome the friction and the carpet will move away from the dust making the carpet free from dust.
Sliding on a garden slide- We know that friction is a force that is present whenever two objects rub against each other. In case of a slide in the garden such as a slide and a person’s backside rub each other’s surface. Without friction, a slide would accelerate the rider too quickly, resulting in possible injury due to the fall. The friction reduces the velocity of the sliding person and makes him stop.
Hope that helps! :D Sorry if it's too lengthy...
Explanation:
Assume a uniformly charged ring of radius R and charge Q produces an electric field Ering at a point P on its axis, at distance x away from the center of the ring. Now the charge Q is spread uniformly over the circular area the ring encloses, forming a flat disk of charge with the same radius. How does the field Edisk produced by the disk at P compare to the field produced by the ring at the same point?Assume a uniformly charged ring of radius R and charge Q produces an electric field Ering at a point P on its axis, at distance x away from the center of the ring. Now the charge Q is spread uniformly over the circular area the ring encloses, forming a flat disk of charge with the same radius. How does the field Edisk produced by the disk at P compare to the field produced by the ring at the same point?
Answer:
* E_ring = [tex]k \ \frac{x}{(x^2+ y^2)^{3/2} } \ Q[/tex]
*E_ disk= 2kQ [tex]\frac{1}{R^2} \ (1 - \frac{x}{(x^2+ R^2)^{1/2} } )[/tex]
Explanation:
Let's start by finding the electric field of the charged ring
in the attachment we can see a diagram of the system. Due to circular symmetry, the electric field perpendicular to the axis is canceled and only the electric field remains parallel to the axis.
Eₓ = E cos θ (1)
E = k ∫ [tex]\frac{dq}{r^2}[/tex]
cos θ = x / r
using the Pythagorean theorem
r = [tex]\sqrt{x^2 + y^2}[/tex]
we substitute
Eₓ = k ∫ [tex]\frac{dq}{x^2+y^2} \ \frac{x}{\sqrt{ x^2+y^2} }[/tex]
Eₓ = [tex]k \frac{x}{(c^2+y^2)^{3/2} }[/tex] ∫ dq
Eₓ = k \frac{x}{(c^2+y^2)^{3/2} } Q
the ring's electric field
E_ring = [tex]k \ \frac{x}{(x^2+ y^2)^{3/2} } \ Q[/tex]
Now let's find the electric field of the disk
The charge is distributed over the entire disk, so let's use the concept of charge density
σ = [tex]\frac{dq}{dA}[/tex]
Let's approximate the disk as a group of rings, the width of each ring is dr, the area is
dA = 2πr dr
we substitute
σ = [tex]\frac{1}{2\pi r} \ \frac{dq}{dr}[/tex]
dq = 2π σ r dr
we substitute in equation 1, where the electrioc field is of each ring
Eₓ = [tex]k \int\limits^R_0 \ { \frac{x}{(x^2+r^2)^{3/2} } \ 2\pi \sigma \ r } \, dr[/tex]
if we use a change of variable
dv = 2rdr
v = r²
Eₓ = [tex]k x \pi \sigma \int\limits^a_b { \frac{1}{(x^2+v)^{3/2} } } \, dv[/tex]
we integrate
Eₓ = k x π σ [tex][ \frac{ (x^2 + r^2)^{-1/2} }{-1/2} ][/tex]
we value in the limits from r = 0 to r = R
Eₓ = k π σ x (-2) [ [tex]\frac{1}{ \sqrt{x^2+R^2} } - \frac{1}{x}[/tex]]
Eₓ = 2π k σ ([tex]1 - \frac{x}{(x^2 + R^2 ) ^{1/2} }[/tex] )
σ = Q/πR²
substitute
Eₓ = 2 k Q/R² (1 - \frac{x}{(x^2 + R^2 ) ^{1/2} } )
E_ disk= 2kQ [tex]\frac{1}{R^2} \ (1 - \frac{x}{(x^2+ R^2)^{1/2} } )[/tex]
The two electric fields are
* E_ring = [tex]k \ \frac{x}{(x^2+ y^2)^{3/2} } \ Q[/tex]
*E_ disk= 2kQ [tex]\frac{1}{R^2} \ (1 - \frac{x}{(x^2+ R^2)^{1/2} } )[/tex]
we can see that the functional relationship of the two fields is different
two masses are attached by a light string and looped over two frictionless pulleys. object 1 has mass 200g and accelerates upwards at the rate of 4.90m/s^2. determine the mass of object 2
Answer:
F=ma
F=10(mass of object 2-0.2)
F=ma
=0.2×4.9
=0.98N
10x-2=0.98(assume that mass of second object is X)
10x =0.98+2
10x=2.98
X=0.298kg
the mass of second object=298g
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define prism and itz colo
Answer:
A prism is a piece of glass or plastic in the shape of a triangle.
Explanation:
The colors of the rainbow in order are: red, orange, yellow, green, blue, indigo, and violet.
Which of the following is an example of an ascribed status?
Multiple Choice
1. musician
2. poor
3. female
4. college student
From the given options the best example of an ascribed status will be poor. Hence, option 2 is the correct one.
What is ascribed status?In sociology, the term "ascribed status" refers to a human's social standing as it is either allocated to them at birth or implicitly assumed in later life. The position of status is one that a person neither chooses for themselves nor earns. Instead, the position is decided upon in accordance with cultural and societal norms and standards. No matter how hard you try or how much you want to, these slots are filled. These fixed social designators are independent of the favorable or unfavorable stereotypes associated with one's assigned statuses and stay unchanged throughout a person's life.
Every society engages in the process of classifying people into categories based on factors including gender, race, family history, and ethnicity. This process is cross-cultural.
To know more about ascribed status:
https://brainly.com/question/9382045
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A marble at the front of a truck bed traveling at 20 m/s relative to the highway rolls toward the back of the truck bed with a speed of 7m/s relative to the truck bed. What is the velocity of the marble relative to the highway?
During a lab experiment, a student took his resting pulse rate, counting 25 beats in 20 seconds. What was the student's pulse rate in beats per minutes (bpm)?
Answer:
75 bpm
Explanation:
60 seconds in a minute
60seconds / 20 seconds = 3
25 beats * 3 = 75 bpm
An important news announcement is transmitted by radio waves to people who are 46 km away, sitting next to their radios, and by sound waves to people sitting across the newsroom, 2.1 m from the newscaster. Take the speed of sound in air to be 348 m/s. What is the difference in time that the message is received
Answer:
[tex]0.005847\ \text{s}[/tex]
Explanation:
Radio waves travel at the speed of light
[tex]c[/tex] = Speed of light = [tex]3\times 10^8\ \text{m/s}[/tex]
[tex]d_r[/tex] = Distance between two radios = 46 km
[tex]v[/tex] = Speed of sound in air = 348 m/s
[tex]d_s[/tex] = Distance sound travels across the newsroom = 2.1 m
Time taken by the radio signal to reach the required location is
[tex]t_r=\dfrac{d_r}{c}\\\Rightarrow t_r=\dfrac{46\times 10^3}{3\times 10^8}\\\Rightarrow t_r=0.000153\ \text{s}[/tex]
Time taken by sound to reach the required location is
[tex]t_s=\dfrac{d_s}{v}\\\Rightarrow t_s=\dfrac{2.1}{348}\\\Rightarrow t_s=0.006\ \text{s}[/tex]
The time difference is
[tex]t_s-t_r=0.006-0.000153=0.005847\ \text{s}[/tex]
The difference in time that the message is received is [tex]0.005847\ \text{s}[/tex].
Why do scientists perform multiple trials of the same experiment?
Answer:
it's a good idea to do multiple trials, that is, do the same experiment lots of times. When we do multiple trials of the same experiment, we can make sure that our results are consistent and not altered by random events. Multiple trials can be done at one time.
Explanation:
the last one which is to increase the likelihood of accurate experiment results
Explanation:
12. A baseball (m = 0.14 kg) with initial velocity of -40 m/s (90 mph) is hit. It leaves the bat with a velocity of 60m/s after 0.001s. What is the impulse and average net force applied to the ball by the bat?
Answer:
the impulse is 14 kg-m/s and the net force applied is 14000 N
Explanation:
Given that,
The mass of a baseball, m = 0.14 kg
Initial velocity of the baseball, u = -40 m/s
Final velocity, v = 60 m/s
Time, t = 0.001 s
We need to find the impulse and average net force applied to the ball by the bat.
Impulse = change in momentum
i.e.
J = m(v-u)
J = 0.14 × (60-(-40))
J = 14 kg-m/s
Now,
J = Ft
F is average force applied to the ball
So,
[tex]F=\dfrac{J}{t}\\\\F=\dfrac{14}{0.001}\\\\F=14000\ N[/tex]
So, the impulse is 14 kg-m/s and the net force applied is 14000 N.
finger bones do not have joints true or false
Explanation:
Finger bones have joints.
Answer: true , finger bones have joints
Explanation:
A human body consists of
Answer:
60% of the human adult body is water. According to H.H. Mitchell, Journal of Biological Chemistry 158, the brain and heart are composed of 73% water, and the lungs are about 83% water. The skin contains 64% water, muscles and kidneys are 79%, and even the bones are watery: 31%.
Explanation:
A pail in a water well is hoisted by means of a frictionless winch, which consists of a spool and a hand crank. When Jill turns the winch at her fastest water-fetching rate, she can lift the pail the 26.0 m to the top in 12.0 s. Calculate the average power supplied by Jill's muscles during the upward ascent. Assume the pail of water when full has a mass of 6.50 kg. W
Answer:
140.83 W
Explanation:
From the question given above, the following data were obtained:
Height (h) = 26 m
Time (t) = 12 s
Mass (m) = 6.50 Kg
Power (P) =?
Power is simply defined as the rate at which energy is used up. Mathematically, it is expressed as:
Power (P) = Energy (E) / Time (t)
But:
Energy (E) = mass (m) × acceleration due to gravity (g) × height (h)
E = mgh
P = E/t
P = mgh / t
With the above formula i.e
P = mgh / t
We can obtain the power supplied by Jill's muscles as follow:
Height (h) = 26 m
Time (t) = 12 s
Mass (m) = 6.50 Kg
Acceleration due to gravity (g) = 10 m/s²
Power (P) =?
P = mgh / t
P = 6.5 × 10 × 26 / 12
P = 140.83 W
Therefore, the power supplied by Jill's muscles is 140.83 W
Two objects A and B (both masses are m) are connected by a spring of elastic constant k and placed on a frictionless surface. At some point, A gains an initial velocity v parallel to the spring, and this system will thus start moving. Knowing that the spring is undeformed in the beginning, determine (a) the highest elastic potential energy that can be stored in the spring and (b) the highest velocity that can be reached by B.
Answer:
a) Em_f = ½ m vₐ², b) v = vₐ /√2
Explanation:
a) For this part we use conservation of energy
starting point .. block A moving, spring unstretched
Em₀ = K = ½ m vₐ²
end point. Stretched spring
Em_f = K_e = ½ k x²
energy is conserved
Em₀ = Em_f
Em_f = ½ m vₐ²
b) Let's analyze the movement a little, block A began to move at a speed va, I stretch the spring an amount Dx, it exerts a force on block b that begins to move and the elongation of the spring decreases.
In all this process there is no friction force, therefore the energy is conserved, therefore the maximum energy stored in the spring must be distributed among the bodies.
Em₀ = K_e = E₀
where E₀ is the initial energy of block a
E₀ = ½ m vₐ²
At the point where we are in equilibrium
Em_f = Kₐ + K_b = ½ m vₐ² +1/2 m [tex]v_{b}^2[/tex]
so that the spring does not stretch or shrink, the two bodies must go at the same speed.
Em_f = m v²
energy is conserved
Em₀ = Em_f
½ m vₐ² = m v²
v = vₐ /√2
therefore both blocks must go at this speed
what is the reason for timing more than one oscillation in a simple pendulum
Answer:
Time period is the time taken by the body to complete one oscillation and it is noted more than once to get accurate reading from averaging of all the observed values.
Can light have inertia??
Answer:
Yes.
Explanation:
Yes Light has inertia, since inertia is in units of mass.