A marble is randomly selected from a bag containing 3 red marbles, 3 blue marbles, and 3 green marbles. What is the probability that the selected marble is green?

Answer:

The first thing that we have to do is add 33 to both sides to try to reduce the amount of variables on the left hand side.

[tex]\frac{x}{6} - 33 = -27[/tex]

[tex]\frac{x}{6} - 33 + 33 = -27 + 33[/tex]

[tex]\frac{x}{6} = 6[/tex]

Now that we have simplified the left hand side even more we only have one part left to get x by itself which is to multiply both sides by 6.

[tex]\frac{x}{6} = 6[/tex]

[tex]\frac{x}{6} * 6 = 6 * 6[/tex]

[tex]x = 36[/tex]

Therefore, our final answer for what the value of x equals is 36.

Hope this helps!  Let me know if you have any questions

Answer:

see explanation

Step-by-step explanation:

a² + 8a

using the method of completing the square

add ( half the coefficient of the a- term)²

a² + 2(4)a + 16

= (a + 4)²

Answer:

c is the answer

Step-by-step explanation:

your welcome

Answer:

Number one is not reasonable

The linear equation that has a slope of -7 and crosses the x-axis at (3, 0) is:

y =  -7x + 21

A general linear equation is:

y = a*x +b

Where a is the slope and b is the y-intercept.

The slope must be equal to the limit found in part a, and you say that it is equal to -7, so the slope is -7. And for how is written the problem, I understand that it crosses the x-axis at x = 3.

Then we will have:

y = -7*x + b

Such that, when x = 3, y = 0, then:

0 = -7*3 + b

21 = b

Then the linear equation is y = -7x + 21

If you want to learn more about linear equations:

https://brainly.com/question/1884491

#SPJ1

Answer:

The line will pass through (3,-7) and has a slope of 3

Step-by-step explanation:

x=3 , f(x) = x^3 - 4x^2 + 2

f(3) = 3^3 -4(3)^2 + 2

f(3) = -7

Answer:

x=4

Step-by-step explanation:

Given M is the midpoint

We know that midpoint of a line divides the line into two equal parts

Therefore on equating we get

[tex]4x + 1 = 8x - 15[/tex]

[tex]1 + 15 = 8x - 4x[/tex]

[tex]16 = 4x[/tex]

[tex]x = 4[/tex]

Steps:

[tex]4x+1= 8x-15[/tex]  

=>subtract 4 on both sides with 8x

[tex]1=4x-15[/tex]

=>now do add 15 both sides

[tex]16=4x[/tex]

=>Now divide 4x both sides

[tex]\frac{16}{4} =\frac{4x}{4}[/tex]

[tex]4=x[/tex]

So 4 is the answer

☆( O u O ) ☆

╔uu══════════════════╗☆

❝ carry on learning. ❞

╚══════nn════════════╝

Step-by-step explanation:

Volume = 4πr³/3

= 4•7³•π/3

=1372π/3

= 1372•3.14/3

≈ 1436.03 units³

to the nearest hundredth.

Answer:

164.6

Step-by-step explanation:   i'm a human calculator

Answer:

164.6

Step-by-step explanation:

Divide 987.6 by 6 = 987.6/6= 164.6

Answer:

should be 5.05

Step-by-step explanation:

rounded to nearest hundredth

Answer:

5.02

Step-by-step explanation:

Formula for area= π x r^2

(π is 3.14)

Formula for diameter= 2 x r

So all you basically have to do is go backwords with the first equation

20/π=6.36

Now you have 6.36, though you need to go even further back because of the ^2

√6.36=2.51

Now we have the radius, so stick that into the diameter formula

2 x 2.51

5.02 is the diameter :)

Answer:

a₆ = 96

Step-by-step explanation:

assuming you mean find a₆

using the recursive rule and a₁ = 3 , then

a₂ 2a₁ = 2 × 3 = 6

a₃ = 2a₂ = 2 × 6 = 12

a₄ = 2a₃ = 2 × 12 = 24

a₅ = 2a₄ = 2 × 24 = 48

a₆ = 2a₅ = 2 × 48 = 96

The elastic curve between 0 to L/2 is a cubic curve. And the elastic curve is shown in the given diagram.

The flexible curve of a beam is the curve generated by the crossover of the horizontal member with the beam's side, with continuous stresses on the fibers considered to be within the elastic limit.

The slope at L/2 will be

[tex]\rm \theta _{L/2} = \dfrac{PL^2}{8EI}[/tex]

The deflection of the beam at L/2 will be

[tex]\rm y_{L/2} = \dfrac{P(L/2)^3}{3EI}\\\\\rm y_{L/2} = \dfrac{PL^3}{24EI}[/tex]

And the deflection of the beam at L will be

[tex]\rm y_{L} = \dfrac{PL^3}{24EI} + \dfrac{L}{2} \times \theta _{L/2} \\\\\rm y_{L} = \dfrac{PL^3}{24EI} + \dfrac{L}{2} \times \dfrac{PL^2}{8EI}\\\\\rm y_{L} = \dfrac{5PL^3}{48EI}[/tex]

Then the elastic curve will be shown in the diagram.

More about the elastic curve link is given below.

https://brainly.com/question/24230581

#SPJ4

Answer:

try youre best to complete youre succsess

Answer:

DB = 32

Step-by-step explanation:

Given :

⇒ C is the midpoint of the line AB

⇒ E is the midpoint of the line DC

⇒ AE = 16

=============================================================

Understanding :

⇒ AC = BC = 1/2AB

⇒ AD = DC = 1/2AC = 1/4AB

⇒ DE = 1/2AD = 1/4AC = 1/8AB

=============================================================

Finding AB :

⇒ AE = AD + DE

⇒ 16 = 1/4AB + 1/8AB

⇒ 3/8AB = 16

⇒ AB = 16 x 8 / 3

⇒ AB = 128/3

=============================================================

Finding DB :

⇒ DB = DC + CB

⇒ DB = 1/4AB + 1/2AB

⇒ DB = 3/4AB

⇒ DB = 3/4 × 128/3

⇒ DB = 128/4

⇒ DB = 32

Answer:

60

Step-by-step explanation:
(* = multiplication symbol)

6^2+8*3

36+8*3

36+24

60

Answer:60

Step-by-step explanation:

Use bidmas

(Brackets Indices Division Multiplication Addition Subtraction)
so first do 6 squared =36

Then 8x3 =24

Then 36+24= 60

Answer:

[tex]30[/tex]

Step-by-step explanation:

Given expression:

[tex]5(x + 4) + 5(2 - x)[/tex]

Note: The value of "x" is undefined because the given sum is not an equation. Thus, I will simplify the expression as much as possible.

Let us simplify all the distributive properties stated in the expression.

Apply the distributive property rule [a(b + c) = ab + ac]

[tex]\implies5(x) + 5(4) + 5(2) - 5(x)[/tex]

Since 5(x) is being subtracted from 5(x), we get:

[tex]\implies 5(x) + 5(4) + 5(2) - 5(x)[/tex]

[tex]\implies 5(4) + 5(2)[/tex]

Finally, let us simplify the sum of the product of (5 and 4) and (5 and 2).

[tex]\implies20 + 10[/tex]

[tex]\implies \boxed{30}[/tex]

Learn more about one-variable expressions: https://brainly.com/question/15139917

Answer:

x= 2

1 =0.5

x=0

Step-by-step explanation:

Answer:

19/117

Step-by-step explanation:

Because the dice did land on 5, 19 times out of 117

Answer:

24

Step-by-step explanation:

k = t - 5k

→ Substitute in k

4 = t - 20

→ Add 20 to both sides

24 = t

Answer:0

<—————|—————>
                0

Step-by-step explanation:

Answer: 2

Step-by-step explanation:

Answer: 5

Step-by-step explanation:

Answer:

A. 38

Step-by-step explanation:

Diagonals of a rhombus bisect 90° at the center. Taking O to be the center :

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

[tex]cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}[/tex]

[tex]\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}[/tex]

Answer:

2(x - 5)(x + 1)

Step-by-step explanation:

2x² - 8x - 10 ← factor out 2 from each term

= 2(x² - 4x - 5) ← factor the quadratic

consider the factors of the constant term (- 5) which sum to give the coefficient of the x- term (- 4)

the factors are - 5 and + 1 , since

- 5 × 1 = - 5 and - 5 + 1 = - 4 , then

x² - 4x - 5 = (x - 5)(x + 1)

then

2x² - 8x - 10 = 2(x - 5)(x + 1) ← in factored form

Answer: [tex]2(x-1)(x+5)[/tex]

Step-by-step explanation:

Factor [tex]2[/tex] out of [tex]2x^2[/tex] [tex]+~8x-10[/tex]

[tex]Factor[/tex] [tex]2 ~out~ of ~2x^2[/tex]:

[tex]2(x^2)+8x-10[/tex]

[tex]Factor ~2~ out ~of ~8x[/tex]:

[tex]2(x^2)+2(4x)-10[/tex]

[tex]Factor ~2~ out~ of ~-10[/tex]:

[tex]2x^2+2(4x)+2~x~-5[/tex]

[tex]Factor ~2~ out~ of ~2x^2+2(4x):[/tex]

[tex]2(x^2+4x)+2[/tex] × [tex]-5[/tex]

[tex]Factor ~2~out ~of ~2(x^2+4x)+2[/tex] × [tex]-5:[/tex]

[tex]2(x^2+4x-5)[/tex]

factor:

[tex]Factor ~x^2+4x-5~ using ~the ~AC~ method.[/tex]

Consider the form [tex]x^2+bx+c.[/tex] Find a pair of integers whose product is [tex]c[/tex] and whose sum is [tex]b[/tex].  In this case, whose product is [tex]-5[/tex] and whose sum is [tex]4.[/tex]

[tex]-1,5[/tex]

Write the factored form using these integers.

[tex]2((x-1)(x+5))[/tex]

Remove unnecessary parentheses.

[tex]=2(x-1)(x+5)[/tex] ← final answer

Step-by-step explanation:

here you go hope it helps