Engineering College

A high strength waste having an ultimate CBOD of 1,000 mg/L is discharged to a river at a rate of 2 m3 /s. The river has an ultimate CBOD of 10 mg/L and is flowing at a rate of 8 m3 /s. Assuming a reaction rate coefficient of 0.1/day, calculate the ultimate and 5-day CBOD of the waste at the point of discharge (0 km) and 20 km downstream. The river is flowing at a velocity of 10 km/day.

Answers

Answer 1

Answer:

Attached below is the detailed solution

answer:

The Ultimate CBOD of waste water at (0) km and 20 Km

= 81.84 mg/l , 67 mg/l

Explanation:

Given Data :

UBOD of waste stream = 1000 mg/l

Volumetric flow rate of waste water = 2 m^3 / s

UBOD of River = 10 mg/l

Volumetric flow rate of river = 8 m^3 / s

reaction rate coefficient = 0.1/day

Velocity of river = 10km/day

The Ultimate CBOD of waste water at (0) km and 20 Km

= 81.84 mg/l , 67 mg/l

A High Strength Waste Having An Ultimate CBOD Of 1,000 Mg/L Is Discharged To A River At A Rate Of 2 M3

Related Questions

Service entrance conductors must be kept a minimum of ____ feet from the sides and bottom of windows that can be opened

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Minimum 2-1/2 inches

At 7:00PM the temperature was 40 degrees F. If the temperature dropped steadily at a rate of 6 degrees per hour, what was the temperature at 11:00 PM? Do you know what it is

Answers

Answer:

Temperature at 11:00 PM = 16 degree

Explanation:

Given:

Temperature at 7:00 PM = 40 degree

Decrease rate = 6 degree per hour

Find:

Temperature at 11:00 PM

Computation:

Total time = 11 - 7 = 4 hour

Total decrease in temperature = 4 x 6 = 24 degree

Temperature at 11:00 PM = 40 - 24

Temperature at 11:00 PM = 16 degree

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