a circular coil (radius = 0.40m) has 160 turns and is in a uniform magnetic field. when the orientation of the coil is varied through all possible positions , the maximum torque on the coil by the magnetic forces is 0.16N.M

Answers

Answer 1

When the orientation of the coil is varied through all possible positions, the maximum torque on the coil by the magnetic forces is 0.16 N·m. The magnetic field strength required to achieve this torque is approximately 0.000318 Tesla.

The maximum torque on a circular coil in a uniform magnetic field can be calculated using the formula:

τ = N * B * A * sinθ

Where:

τ is the torque,

N is the number of turns in the coil,

B is the magnetic field strength,

A is the area of the coil, and

θ is the angle between the normal to the coil and the direction of the magnetic field.

In this case, The radius of the coil is given as 0.40 m, and the number of turns is 160. We need to find the magnetic field strength (B) and the angle (θ) to calculate the torque.

Since the maximum torque is given as 0.16 N·m, we can write the equation as:

0.16 N·m = 160 * B * π * [tex](0.40 m)^2[/tex] * sinθ

Simplifying the equation:

0.16 N·m = 160 * B * (0.16π) * sinθ

Now, solving for B:

B = (0.16 N·m) / (160 * (0.16π) * sinθ)

B = 0.001 N / (π * sinθ)

The magnetic field strength (B) depends on the angle θ. The maximum torque occurs when sinθ is equal to 1 (sinθ = 1), which gives us the maximum value for B.

Substituting sinθ = 1:

B = 0.001 N / (π * 1) = 0.000318 N/T

Therefore, the magnetic field strength is approximately 0.000318 Tesla (T).

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Related Questions

Air at 273K and 1.01x10³Nm2 pressure contains 2.70x1025 molecules per cubic meter. How many molecules per cubic meter will there be at a place where the temperature is 223K and pressure is 1.33x10 Nm-2

Answers

The molecules of O2 that are present in 3.90 L flask at a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules of O2

Step 1: used the ideal gas equation to calculate the moles of O2

that is Pv=n RT where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by making n the subject of the formula by dividing both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L) /(0.0821 L.atm/mol.k x273)]=0.174 moles

Step 2: use the Avogadro's law constant to calculate the number of molecules

that is according to Avogadro's law

1 mole = 6.02 x10^23 molecules

0.174 moles=? molecules

by cross multiplication

the number of molecules

= (0.174 moles x 6.02 x10^23 molecules)/ 1 mole =1.047 x 10^23 molecules of O2

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What is the formula for Angular velocity?

Answers

Answer:

The formulas are down below

Explanation:

[tex]w = \frac{o}{t} [/tex]

From V=rw

[tex]w = \frac{v}{r} [/tex]

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