Answer:
Explanation:
We shall first calculate the electric field at origin .
Field due to first charge
= KQ / R²
= 9 x 10⁹ x 50 x 10⁻⁶ / .03²
E₁ = 5 x 10⁸ N/C
Field due to second charge
= KQ / R²
= 9 x 10⁹ x 77 x 10⁻⁶ / .04²
E₂ = 4.33 x 10⁸ N/C
Resultant field E = √ ( 5² + 4.33² ) x 10⁸
= 6.6 x 10⁸ N/C
Force on electron = E x q
= 6.6 x 10⁸ x 1.6 x 10⁻¹⁹ N
= 10.56 x 10⁻¹¹ N
Acceleration = force / mass
= 10.56 x 10⁻¹¹ / 9.1 x 10⁻³¹
= 1.16 x 10²⁰ m /s²
Answer:
[tex]a=1.16\times 10^{20}\ m/s^2[/tex]
Explanation:
Given that,
First charge, [tex]q_1=50\ \mu C = 50\times 10^{-6}\ C[/tex]. It is placed at y = 3 cm
Second charge, [tex]q_2=77\ \mu C = 77\times 10^{-6}\ C[/tex] . It is placed at x = 4 cm.
Force on electron due to q₁.
[tex]F_1=\dfrac{kq_1e}{r^2}\\\\F_1=\dfrac{9\times 10^9\times 1.6\times 10^{-19}\times 50\times 10^{-6}}{(0.03)^2}\\\\F_1=8\times 10^{-11}\ N[/tex]
Force on electron due to q₂.
[tex]F_2=\dfrac{kq_1e}{r^2}\\\\F_2=\dfrac{9\times 10^9\times 77\times 10^{-6}\times 1.6\times 10^{-19}}{(0.04)^2}\\\\F_2=6.93\times 10^{-11}\ N[/tex]
The net force on the electron is given by :
[tex]F=\sqrt{F_1^2+F_2^2} \\\\F=\sqrt{(8\times 10^{11})^2+(6.93\times 10^{-11})^2} \\\\F=1.058\times 10^{-11}\ N\\\\\text{or}\\\\F=10.58\times 10^{-11}\ N[/tex]
Let a is the acceleration of the electron. Net force is given by :
F = ma
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{10.58\times 10^{-11}}{9.1\times 10^{-31}}\\\\a=1.16\times 10^{20}\ m/s^2[/tex]
So, the acceleration of the electron is [tex]1.16\times 10^{20}\ m/s^2[/tex].
Manu takes 30 minutes from his house to reach his school on a bicycle. If the cycle has a speed of 4m/s find the difference between his house and the school.
Answer:
7200 m
Explanation:
From the question given above, the following data were obtained:
Time (t) = 30 mins
Speed (S) = 4 m/s
Distance (d) =.?
Next, we shall convert 30 mins to seconds. This can be obtained as follow:
1 mins = 60 s
Therefore,
30 mins = 30 mins × 60 s / 1 mins
30 mins = 1800 s
Thus, 30 mins is equivalent to 1800 s.
Finally, we shall determine the difference between Manu's house and his school by calculating the distance. This is illustrated below:
Time (t) = 1800 s
Speed (S) = 4 m/s
Distance (d) =.?
Speed = Distance /time
4 = Distance /1800
Cross multiply
Distance = 4 × 1800
Distance = 7200 m
Therefore, the difference between Manu's house and his school is 7200 m
Describe how resistance affects the flow of current in a circuit
A car starts from a spotlight and is traveling with a velocity of 10 m/s Ein
20 seconds. What is the acceleration of the car?
Answer:
ANSWER
Initial Velocity (u) = 10 m/sec
Acceleration (a) = 5 m/sec
2
Distance (s) = 30 m
Final velocity (v) = ??
Using Newton's Third law of Motion,
v
2
=u
2
+2as
v
2
=10
2
+2×5×30
v
2
=100+300
v
2
=400
v =
400
v = 20 m/sec
_____________________________
ANSWER =
FINAL VELOCITY = 20 m/sec
Answered By
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More Questions by difficulty
EASY
MEDIUM
HARD
Explanation:
it's easy
A bowling ball is dropped from rest. What is the ball's velocity after falling for 5 seconds?
Equation: Vy =g*t
Answer:
545432344455555322 we 45year 7of and
In a transformer, the incoming primary voltage is 120 V. There are 100 windings in the primary coil. The secondary coil has 65 windings. What is the outgoing voltage of this transformer?
a
151.9 V
b
64.41 V
c
102.8 V
d
78.02 V
Answer:
78.02 V
Explanation:
Given that,
Primary voltage in a transformer is 120 V
No of windings in the primary coil is 100
No of windings in the secondary coil is 65
We need to find the outgoing voltage of the transformer. For a transformer, the ratio of primary voltage to the secondary voltage is equal to the ratio of turns in Primary coil to the turns in secondary coil are equal. So,
[tex]\dfrac{V_p}{V_s}=\dfrac{N_p}{N_s}\\\\\dfrac{120}{V_s}=\dfrac{100}{65}\\\\V_s=\dfrac{120\times 65}{100}\\\\V_s=78\ V[/tex]
So, out of the given options, the correct one is option (d) i.e. 78.02 V
A force is applied to a 2.1 kg mass and produces 3 m/s- acceleration.
What acceleration would be produced by the same force applied to a 12.1 kg mass?
Answer in units of m/s2.
Answer:
f=m×a
f=2.1×3
f=6.3
f=ma
6.3=12.1a
a=0.52m/s²
Help plz
Which of the following graphs best represents the expected experimental data between the force of gravitational attraction between two varying masses positioned 1 m apart
Answer:
I'm pretty sure it's D
Explanation:
because the greater the mass, the greater the gravitational pull is on it. but you probably shouldn't take my word on it, lol
A man is walking toward the back of an airplane at 7 m/s. The plane is flying West at 245 m/s. What is the speed and direction of the plane relative to the man?
Answer:
The speed of the plane relative to the man is 245.1 m/s
The direction of the plane is S 88.36⁰ W
Explanation:
Given;
velocity of the man toward the airplane, Vy = 7 m/s
velocity of the airplane, Vx = 245 m/s west
The speed of the plane relative to man is given by;
<----------------------
↑
↑
↑
Complete this diagram to form a right angled triangle, with the hypotenuse as the relative velocity of the plan with respect to the man.
R² = 245² + 7²
R² = 60074
R = √60074
R = 245.1 m/s
The direction of the plane is given by;
tan θ = 245 / 7
tan θ = 35
θ = tan ⁻¹ (35)
θ = 88.36°
The direction of the plane is S 88.36⁰ W
A train slows down as it rounds a sharp horizontal turn, going from 100 km/h to 60.0 km/h in the 14.0 s it takes to round the bend. The radius of the circle is 160 m. Compute the total acceleration and the angle at the moment the train speed reaches 60.0 km/h.
Answer:
The magnitude of the total acceleration of the train is approximately 1.909 meters per square second.
The direction of total acceleration with respect to radial acceleration is approximately -24.578º.
Please note that negative sign indicates that train is decelerating.
Explanation:
From Physics, we know that magnitude of the acceleration experimented by the train ([tex]a[/tex]), measured in meters per square second, while rounding the bend is the Pythagorean identity involving radial and tangential accelerations ([tex]a_{r}[/tex], [tex]a_{t}[/tex]), measured in meters per square second:
[tex]a = \sqrt{a_{t}^{2}+a_{r}^{2}}[/tex] (Eq. 1)
If we assuming that train decelerates at constant rate, then each component is determined by following expressions:
[tex]a_{t} = \frac{v_{f}-v_{o}}{t}[/tex] (Eq. 2)
[tex]a_{r} = \frac{v_{f}^{2}}{R}[/tex] (Eq. 3)
Where:
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds, measured in meters per second.
[tex]t[/tex] - Deceleration time, measured in seconds.
[tex]R[/tex] - Bend radius, measured in meters.
If we know that [tex]v_{o} = 27.778\,\frac{m}{s}[/tex], [tex]v_{f} = 16.667\,\frac{m}{s}[/tex], [tex]t = 14\,s[/tex] and [tex]R = 160\,m[/tex], then each acceleration component is calculated:
[tex]a_{t} = \frac{16.667\,\frac{m}{s}-27.778\,\frac{m}{s} }{14\,s}[/tex]
[tex]a_{t} = -0.794\,\frac{m}{s^{2}}[/tex]
[tex]a_{r} = \frac{\left(16.667\,\frac{m}{s} \right)^{2}}{160\,m}[/tex]
[tex]a_{r} = 1.736\,\frac{m}{s^{2}}[/tex]
Then, the magnitude of the total acceleration of the train is:
[tex]a = \sqrt{\left(-0.794\,\frac{m}{s^{2}} \right)^{2}+\left(1.736\,\frac{m}{s^{2}} \right)^{2}}[/tex]
[tex]a \approx 1.909\,\frac{m}{s^{2}}[/tex]
The magnitude of the total acceleration of the train is approximately 1.909 meters per square second.
After that, we obtain the angle of acceleration by using the following trigonometric expression:
[tex]\theta = \tan^{-1} \frac{a_{t}}{a_{n}}[/tex] (Eq. 4)
Where [tex]\theta[/tex] is the direction of total acceleration with respect to radial acceleration, measured in sexagesimal degrees.
If we get that [tex]a_{t} = -0.794\,\frac{m}{s^{2}}[/tex] and [tex]a_{r} = 1.736\,\frac{m}{s^{2}}[/tex], the direction of total acceleration experimented by the train is:
[tex]\theta = \tan^{-1}\left(\frac{-0.794\,\frac{m}{s^{2}} }{1.736\,\frac{m}{s^{2}} } \right)[/tex]
[tex]\theta \approx -24.578^{\circ}[/tex]
Please note that negative sign indicates that train is decelerating.
The direction of total acceleration with respect to radial acceleration is approximately -24.578º.
9. Which of Newton's laws explains why a rocket can be sent into space by aiming a force downward?
Answer:
Newton's third law
Explanation:
the fuel is the action force
and the rocket going up is the reaction force
Where does transpiration occur
Answer:
it's when the water in water in plants is evaporated and turned into water vapor
Explanation:
hope it helps
How do scientists determine the number of neutrons in an isotope of an atom?
They subtract the atomic number from the atomic mass.
They find the number of protons.
They divide the atomic mass by two.
They add the number of electrons and protons.
Answer:
They subtract the atomic number from the atomic mass
Hope this helps
Please mark as the brainliest
Select the correct answer. In which situation is maximum work considered to be done by a force? A. The angle between the force and displacement is 180°. B. The angle between the force and displacement is 90°. C. The angle between the force and displacement is 60°. D. The angle between the force and displacement is 45°. E. The angle between the force and displacement is 0°.
Answer:
A. The angle between the force and displacement is 180°.
Answer:
a
Explanation:
an aiplane is traveling at 500 mph for 3.5 hours. how far did the plane travel
Answer:
1750mile
Explanation:
500/h
3.5h=3.5×500=1750
Acceleration due to gravity (ag) = 9.8 m/s2. An object is dropped from a bridge. How
fast will the object be falling in 6.3 seconds?
Answer:
V = 61.74m/s
Explanation:
Given the following data;
Acceleration due to gravity = 9.8m/s²
Time, t = 6.3 secs
Since it's a free fall, initial velocity = 0
Thus, to find the final velocity, we would use the first equation of motion;
[tex] V = U + at[/tex]
Substituting into the equation, we have;
[tex] V = 0 + 9.8 * 6.3[/tex]
V = 61.74m/s
Therefore, the final velocity is 61.74m/s
3. A satellite orbits Earth at a constant speed.
What part of the satellite's motion is
changing?
A speed
B friction
C inertia
D acceleration
A 1.5 kg block is pulled across a horizontal surface that has a coefficient of kinetic friction of 0.60. a. What is the force of friction exerted by the surface on the block?
Answer: 8.82 N
Fg= (1.5) (9.8) = 14.7
Fk= (0.60) (14.7) = 8.82
A car starts at a position of 4km and moves a final position of 5 km. What is the total distance traveled by the car?
A. 1 km
B.-9 k m
C. 9 km
D. -1 km
Answer:
its c. 9km
Explanation:
Because it you add the 4km+5km that gives you a total of 9km
If a cheetah can maintain a constant speed of 5.00 m/s, how far does it travel in 1.00 minute?
Answer: 300 m/m
Explanation: 5.00 m/s • 60 =300/m/m
The average velocity and time of motion for an objects are recorded as
Vavg = +2.0 m/s. Ai= 3.0 s
What is the displacement of the object?
O 0.67 m
O 6m
o 3m
O 1.5 m
Molten material beneath an erupting volcano. Point A at molten material under ground to the left of the volcano. Point B is at the bottom on the side of the volcano. Use the drop-down menus to answer the questions. Label the type of igneous rock that will form at point A. Label the type of igneous rock that will form at point B.
Answer:
Magma
Lava
:)
Explanation:
i did it and got it right
Will the velocity of the book change as it moves across the surface with NO friction? Explain your answer.
Explanation:
If we push on the book with a force of less than 5 N, the book won't move, because the frictional force will exactly balance the force we apply. If we push with a 1 N force, a 1 N frictional force opposes us.
As mass is constant during free-weight resistance training, a greater impulse will result in a greater velocity.Explanation:
PLEASE ANSWER
For an object launched horizontally the acceleration in the y direction will always be ____.
Answer: initial velocity in y direction
Explanation: coz i did dis before XD
a rocket is fired upwards with an intial velocity of 46.5 m/s. find the rocket's maximum height
Answer:
The value is [tex]s = 110.32 \ m[/tex]
Explanation:
From the question we are told that
The initial velocity is u= 46.5 m/s
Generally from kinematic equations we have that
[tex]v^2 = u^2 + 2as[/tex]
Here [tex]a = -g = -9.8 \ m/s^2[/tex]
The negative sign is because it is moving against gravity
At maximum height v = 0 m/s
So
[tex]0 = (46.5)^2 + 2* (-9.8)s[/tex]
=> [tex]s = 110.32 \ m[/tex]
HELP!!!! ILL GIVE BRAINLIEST!!HURRY !!!!
what is 5.6 x 10^15 converted to x10^12
Answer:
5,600
Explanation:
You split x10^15 into x10^12 and x10^3. Our new equation is 5.6x10^3x10^12
We do 5.6x10^3 and we get 5,600. Our new equation is 5,600x10^12. I hope this answered your question.
cerebrum what is the meaning
Answer:
Plural cerebrums cerebra The largest part of the vertebrate brain, filling most of the skull and consisting of two cerebral hemispheres divided by a deep groove and joined by the corpus callosum, a transverse band of nerve fibers. The cerebrum processes complex sensory information and controls voluntary muscle activity.
Explanation:
A type of elevator called a cage is used to raise and lower miners in a mine
shaft. Suppose the cage carries a group of miners down the shaft. If the
unbalanced force on the cage is 60.0 N, and the mass of the loaded cage is
1.50 x 10²kg, what is the acceleration of the cage?
Answer:
Acceleration, a = 0.04 m/s²
Explanation:
Given the following data;
Force = 60N
Mass = 1500kg
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
[tex] F = ma[/tex]
Where;
F represents force.
m represents the mass of an object.
a represents acceleration.
Making acceleration (a) the subject, we have;
[tex]Acceleration (a) = \frac{F}{m}[/tex]
Substituting into the equation;
[tex]Acceleration (a) = \frac{60}{1500}[/tex]
Acceleration, a = 0.04 m/s²
A person ran with a speed of 6 m/s onto the skateboard .What is the speed with which he ride on the skate board
Answer:
First, remember the conservation of energy.
We can define the kinetic energy as:
K = (1/2)*m*v^2
where m is the mass, and v is the velocity.
The velocity of the person is 6m/s, and the mass is unknown.
Now, when the person rides the skateboard, this kinetic energy must remain constant, if M is the mass of the skateboard, the speed after the person rides ir will be:
K' = (1/2)*(m + M)*v'^2
Where v' is the new velocity.
In this case, we can suppose that the skateboard has really small mass compared with the person.
M < < m
then:
(m + M) ≈ m
then:
K' = (1/2)*m*v'^2 = K = (1/2)*m*v^2
from that equation, we can conclude that:
v' = v
Then if the velocity before riding the skateboard was 6m/s, then after would be also 6m/s.
What is the velocity of a car that travels 400meters in 16 seconds
Answer:
The answer is 25 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{400}{16} \\ [/tex]
We have the final answer as
25 m/sHope this helps you
(Physical science!!!)
Wetlands have characteristics of both dry land and of bodies of water. How have amphibians adapted to this environment?
A.
They can lay their eggs underwater or on dry land.
B.
Water can pass through their lungs; they have night vision.
C.
Water can pass through the skin; they have lungs.
D.
They retain a set of gills their whole lives.
Amphibians retain a set of gills their whole lives that help them to breathe in the water. So, the correct option is D.
What are Amphibians?Amphibians are defined as the class of cold-blooded vertebrates which is made up of frogs, toads, salamanders, newts, and caecilians. All amphibians that spend part of their lives in water and part of their lives on land.
Amphibians are born with gills, and some outgrow them when they become adults while others retain them for their entire lives.
Thus, the correct option is D.
Learn more about Amphibians, here:
https://brainly.com/question/14213726
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