A car of mass 750 kg accelerates away from traffic lights. At the end of the first 100 m it has reached a speed
of 12 m/s. During this time, its engine provides an average forward force of 780 N, and the average force of
friction on the car is 240 N.
a Calculate the work done on the car by the force of its engine.
b Calculate the work done on the car by the force of friction.
c Using ke. = mv2, calculate the increase in the car's kinetic energy at the end of the first 100 m.
d Explain whether your answers are consistent with the principle of conservation of energy.​

The cornea is shaped like a dome and bends light to help the eye focus. Some of this light enters the eye through an opening called the pupil (PYOO-pul). The iris (the colored part of the eye) controls how much light the pupil lets in. Next, light passes through the lens (a clear inner part of the eye).

Answer:

3 because

Explanation:

60÷20=3 ans is this

Answer:

[tex]\frac{\pi }{15}[/tex]m

Explanation:

At 10am, the minute hand and hour hand are ' 2 hours apart', since the minute hand is at 12pm and hour hand is at 10am.

Angle between the two hands = 2/12 * 360

= 60°

Arc Length = [tex]2\pi r(\frac{60}{360} )[/tex]

= [tex]2\pi (0.2)(\frac{1}{6} )\\= \frac{\pi }{15} m[/tex]

Chemical reactions produces new substances and may be a synthesis, decomposition, combustion, replacement, or neutralization reaction.

Chemical reactions are changes which occurs in substances producing changes in the chemical properties of the substance.

The chemical reactions described are as follows:

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Answer:

Gravity    (perhaps)

Explanation:

Without a further description or a diagram, I would guess the downward force would be gravity.

Gravity exerts a downward pull on the book with a magnitude of 5 n. the correct answer would be option (A) gravity.

The attraction that the earth, moon, or other immensely big object has on another object is referred to as gravity. By definition, this is the object's weight. Gravity affects all items on Earth and is directed "downward" towards the earth's center. On Earth, gravity gives physical objects weight, while the Moon's gravity causes sublunar tides in the seas (the corresponding antipodal tide is caused by the inertia of the Earth and Moon orbiting one another).

Gravity also plays a significant role in biology, such as regulating plant development through gravitropism and controlling fluid circulation in multicellular animals.

According to research into the consequences of weightlessness, gravity may have a role in immune system function and cell differentiation inside the human body.

Thus, Gravity exerts a downward pull on the book with a magnitude of 5 n.

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The complete question would be as:

A downward force of magnitude 5 n is exerted on the book by the force of downward force of magnitude 5 n is exerted on the book by the force of the table.

A. gravity

B. inertia

C. momentum

D. acceleration

Answer:

Actually, the correct answer is D. The system releases 75 J of heat, and its volume doubles.

Explanation:

I took this computer-scored test, and while I was stuck on this answer for a while, I was able to get 100%. This was my thought process:

We know that molecular motion increases with an increase in temperature, because collisions increase. For that reason, for molecular motion to decrease in a system, as the question states, the system must RELEASE heat and decrease in temperature.  Additionally, when a system's volume is smaller, its molecular motion increases. This is because the molecules hit the container more easily and more often. If the volume is halved then, the molecules would have MORE motion, which we aren't looking for in this question! Therefore, the volume must DOUBLE so that less molecular motion takes place. The answer is D! :)

Point of Aries is a celestial body which can be used to measure sidereal day.

A sidereal day can be defined as an amount of time that it takes planet Earth to rotate once about its axis relative to the stars, so that distant stars appear within the same position in the sky.

Based on astronomical information and records, Point of Aries is a celestial body which can be used to measure sidereal day because it's the amount of time between two (2) consecutive transits of the First Point of Aries.

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The average speed will be 2.38×10⁶ m/sec.The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.

The total distance traveled by an object divided by the total time taken is the average speed.

The speed calculated at any particular instant of time is known as the instantaneous speed.

Given data;

Distance travelled = 4.12x10¹⁶ meter

Time period= 1.73x10¹⁰ sec

The average speed is found as

[tex]\rm V_{avg}= \frac{d}{t} \\\\\ \rm V_{avg}= \frac{4.12 \times 10^{16}}{1.73 \times 10^{10} } \\\\\ V_{avg}=2.38 \times 10^6 \ m/sec[/tex]

Hence, the average speed will be 2.38×10⁶ m/sec.

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According to the research, the agonic line is the line joining all places of zero variation.

It is a term that refers to the zero declination isogon, that is, it joins the points that do not have magnetic declination.

This line crosses the magnetic and geographic poles of the Earth's surface from which they are aligned and along which there is no magnetic variation.

Therefore, we can conclude that according to the research, the agonic line is the line joining all places of zero variation.

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Given the data from the question, the goal kicker did not make the field goal.

To determine if the goal kicker makes the field goal, we shall determine the distance (i.e range) travelled by the ball after it was kicked by the kicker. This can be obtained as follow:

R = u²Sine(2θ) / g

R = 20² × Sine (2×60) / 9.8

R = 400 × Sine 120 / 9.8

R = 35.3 m

Since the distance travelled by the ball is 35.3 m and the goal post is situated 47 yard (43 m) away.

Thus, we can conclude that the goal kicker did not make the goal as the ball did not get to the post which is 47 yard (43 m)

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Answer:

Newton's second law states that force is directly proportional to the product of mass and acceleration.

so if you hit a baseball with a bat it will accelerate according to the applied force.

Answer:

2.24 seconds

Explanation:

xf = xo + vo t + 1/2 at^2

45 = 0 + 15 t  + 1/2 (4.5) t^2

   2.25 t^2 + 15t - 45 = 0              Quadratic formula shows  t = 2.24 seconds

The car takes approximately 2.25 seconds to cover a distance of 45.0 meters under the given conditions of constant acceleration.

Given data:

Initial velocity (u) = 15.0 m/s

Acceleration (a) = 4.50 m/s²

Distance (s) = 45.0 m

We can use the kinematic equation to solve for time (t) when the car covers a certain distance under constant acceleration:

S = ut + 1/2at²

Where:

s = distance

u = initial velocity

a = acceleration

t = time

Plugging in the given values:

45.0 = 15.0t + 1/2 m/s²t²

2.25t² +15t - 45 = 0

t = 2.25sec and -8.92sec

Since time cannot be negative in this context, we discard the negative solution.

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A. The final temperature of the system is 0°C.

B. The amount of ice (if any) remaining is  0.0331 g

C. The initial temperature of the water that would be enough to just barely melt all of the ice is 20.57 °C.

The specific heat is the amount of heat required to change the temperature by 1°C. It is denoted by C.

Heat lost or gained is represented as

Q = m C ΔT

Given, Mass of ice, mice = 9x10⁻² kg, Mass of water, mw =0.35 kg, T = 13 °C

A. If ice is in excess, final water temperature will be 0°C.

B. Specific heat of water Cp = 1000 cal/kg°C

Latent heat of ice L = 80 kcal/kg

In that case, heat lost by water =Heat gain by ice

Q = mCp x dT = mL

0.35 x 1000 x 13 = m x 80 x 1000

m = 0.0569 kg of ice.

The gram of ice remaining = 0.09 - 0.0569

                                             = 0.0331 gram of ice.

Thus,  the amount of ice remaining is 0.0331 g

C. Heat required to melt 90 gram of ice,  Q  mL

Q = 90 x 80 = 7200 cal.

If the initial temperature of water needed = T,

mCp x dT = mL

350 x T = 7200

T = 20.57 °C

Thus,  the initial temperature of the water that would be enough to just barely melt all of the ice is  20.57 °C.

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The velocity of a trip from City A to City B is  30 miles per hour.

The term velocity is defined as the ratio of displacement to time. Displacement refers to the distance that is covered in a specified direction.

Now  given that the straight line distance from A to B is about 120 miles. hen it follows that the velocity of a trip from City A to City B is obtained from; 120 miles/ 4 hours = 30 miles per hour.

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The efficiency of a carnot engine is more when the temperature of the sink is increased by 50% is 33.33%

The efficiency is defined as the work done by the engine divided by the heat supplied.

Work done is the difference between the heat supplied and heat rejected.

So, efficiency η = 1 - T₁/T₂

Where T₁ is the lower temperature and T₂ is the higher temperature.

The temperature of the sink is increased by 50%. If the lower temperature is T₁, then the higher temperature will be 1.50T₁

Substitute the value into the expression , we get

η = 1 - T₁ / 1.5T₁ x 100 %

η = 33.33 %

Thus, the efficiency of the carnot engine is 33.33 %

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The correct statement  for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."

The dynamic equilibrium is defined as a state of a particular system wherein the reversible reaction takes place and ceases modifying the ratio of reactants as well as products.

The chemical reaction is a method for creating novel chemicals with unique features.

The correct statement  for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."

Therefore, the correct answer will be an option (C).

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The claim of the student is True, he can produce linear momentum in carrom with the help of b.

To explain the principle of linear momentum we can say that:-

According to the principle of conservation of momentum, if two things collide, the total momentum before and after the impact will be the same if no external force occurs on the colliding items.

Linear momentum conservation When the net external force is zero, the momentum of the system remains constant, as expressed mathematically by the expression.

Initial momentum = final momentum

Formula of Linear momentum is:-

Linear momentum = mass × linear velocity

P = M × V

The law of momentum conservation is based on Newton's third rule of motion, which states every force has a corresponding and opposing reciprocating force.

So we understand that Principle of Linear momentum. The initial momentum is equal to final momentum after collision hence, the carrom striker follows the concept of linear momentum.

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[tex]\large\bold{\underline{\underline{Answer:-}}}[/tex]

The speed of Vc at the instant bead collide is 1.38 m/s and the instant speed of Vd at the instant bead collide is 0.106 m/s.

The force of attraction on the beads are due to both gravitational force and electrostatic force

As gravitational force is very weak force as compared to electrostatic force the net force will be due to electrostatic force only.

Net Force = Electrostatic force

Net Force = K q1 q2 / r²

Net Force = (9 × 10⁹) (2.5 × 10⁻⁹) (1 × 10⁻⁹) / (14 × 10⁻³) (as distance between there centre of mass is 14 mm)

Net Force = (9 × 2.5 × 10⁻⁶) / 14

Net Force = 1.6 × 10⁻⁶

For bead c

Force = Mc × Ac = 1.6 × 10⁻⁶

(1 × 10⁻³) × Ac = 1.6 × 10⁻⁶

Ac = 1.6 × 10⁻³

Acceleration of bead C is 1.6 × 10⁻³ m/s²

For bead d

Force = Md × Ad = 1.6 × 10⁻⁶

(1.7 × 10⁻³) × Ad = 1.6 × 10⁻⁶

Ad = 0.94 × 10⁻³

Acceleration of bead D is 0.94 × 10⁻³ m/s²

Let us suppose bead C travels y distance before collision

So bead D should travel 12-y distance before collision

So speed of both the beads before the collision can be find out by using newton third law of motion

For bead C

Vc² - Uc² = 2 Ac s

Vc² = 2 × 1.6 × 10⁻³ × y

Vc² = 3.2 × 10⁻³ × y

Vc = √(3.2 × 10⁻³ × y)

For bead D

Vd² - Ud² = 2 Ad s

Vd² = 2 × 0.94 × 10⁻³ × (12-y)

Vd² = 1.88 × 10⁻³ × (12-y)

Vd = √(1.88 × 10⁻³ × (12-y))

Applying energy conservation

initial = final

0 + 0 = (1/2)McVc² - (1/2)MdVd²

(1/2)McVc² = (1/2)MdVd²

McVc² = MdVd²

1 × 10⁻³ × 3.2 × 10⁻³ × y = 1.7 × 10⁻³ × 1.88 × 10⁻³ × (12-y)

3.2 × y = 3.2 × (12-y)

y = 12-y

2y = 12

y = 6

Putting the value of y in Vc and Vd

Vc = √(3.2 × 10⁻³ × y)

Vc = √(3.2 × 10⁻³ × 6)

Vc = √(19.2 × 10⁻³)

Vc = √0.0192

Vc = 1.38 m/s   (approximately)

Vd = √(1.88 × 10⁻³ × (12-y))

Vd = √(1.88 × 10⁻³ × (12-6))

Vd = √(1.88 × 10⁻³ × 6)

Vd = √(11.28 × 10⁻³)

Vd = √0.01128

Vd = 0.106 m/s   (approximately)

So the speed of Vc at the instant beads collide will be approximately 1.38 m/s and Vd at the instant speed the beads collide will be approximately 0.106 m/s.

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Answer:

5.15 when the angle of incidence is equal to critical angle the angle of reflection is equal to 90 if the angle of incidence is bigger than the critical anger the reflected ray will not emerge from the medium but will be reflected back into the medium this is called total internet reflection

Explanation:

hope it's helpful

Extrasolar planets come in a wider range of types than the planets of our solar system due to migration of the extrasolar planets and delay in clearing of the solar nebula.

Extrasolar planets are planets which exists outside our solar system.

Ours solar system consists of the Sun and its planets.

The extrasolar planets come in a wider range of types than the planets of our solar system.

This is due to migration of the extrasolar planets and delay in clearing of the solar nebula.

Also, there are differences in nebula types.

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Answer:

Gas Solid Liquid Plasma

Explanation:

Answer:

plasma

Explanation:

plasma has charged particles and ions and electrons floating around

(1) Our entire solar system orbits around the center of the Milky Way Galaxy about once every 230 million years.

(2) The milky way and andromeda galaxies are among a few dozen galaxies that make up our Local Group.

(3) The sun appears to rise and set in our sky because earth rotates once each day.

(4) You are one year older each time earth orbits about the sun.

(5) On average, galaxies are getting farther apart with time, which is why we say our universe is expanding.

(6) Our solar system is moving toward the star vega at about 70,000 km/hr.

Our entire solar system orbits around the center of the Milky Way Galaxy about once every 230 million years.

The milky way and andromeda galaxies are among a few dozen galaxies that make up our Local Group.

The sun appears to rise and set in our sky because earth rotates once each day.

You are one year older each time earth orbits about the sun.

On average, galaxies are getting farther apart with time, which is why we say our universe is expanding.

Our solar system is moving toward the star vega at about 70,000 km/hr.

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The third charge is in equilibrium, 2a/3

An electric property associated with each point in space when charge is present in any form.

The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.

According to the question,

force on it due to +4e= force due to +e

[tex]\frac{ k(4e)q}{x^{2} } = \frac{ k(e)q}{(a-x)^2}[/tex]

4(a-x)² = x²

2(a-x)=x

2a-2x =x

x= [tex]\frac{2a}{3}[/tex]

Therefore,

The position along the line XY is [tex]\frac{2a}{3}[/tex]

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Consider a person trying to push a large crate across a floor, as in the diagram. As they apply a force to push the crate along the floor in one direction, a frictional force is generated in the opposite direction.

[tex]study \: well.....[/tex]

The force of the string at the bottom is greater than the weight of the ball. The correct option is B.

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

A girl at a state fair swings a ball in a vertical circle at the end of a string.

When the ball is at the bottom . the force acting will be

The tension in the string , T = mass x centripetal acceleration + Force of gravity

So, T = m x ac + mg

Thus, the force of the string at the bottom is greater than the weight of the ball.

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