Answer:
Approximately [tex]122.625\; {\rm m}[/tex] (assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], the ball was launched from ground level, and that the drag on the ball is negligible.)
Explanation:
Let [tex]v_{0}[/tex] denote the velocity at which the ball was thrown upward.
If the drag (air friction) on the ball is negligible, the ball would land with a velocity of exactly [tex](-v_{0})[/tex]. The velocity of the ball would be changed from [tex]v[/tex] to [tex](-v_{0})\![/tex] (such that [tex]\Delta v = (-v_{0}) - v_{0} = (-2\, v_{0})[/tex]) within [tex]t = 10\; {\rm s}[/tex].
Also because the drag on the ball is negligible, the acceleration of the ball would be [tex]a = -g = -9.81\; {\rm m\cdot s^{-2}}[/tex]. Thus:
[tex]\Delta v = a\, t = 10\; {\rm s} \times (-9.81\; {\rm m\cdot s^{-2}}) = -98.1\; {\rm m\cdot s^{-1}}[/tex].
Since [tex]\Delta v = (-2\, v_{0})[/tex]:
[tex]-2\, v_{0} = \Delta v = -98.1\; {\rm m\cdot s^{-1}[/tex].
[tex]\begin{aligned}v_{0} &= \frac{-98.1\; {\rm m\cdot s^{-1}}}{-2}= 49.05\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].
The ball reaches maximum height when its velocity is [tex]v_{1} = 0\; {\rm m\cdot s^{-1}}[/tex]. Apply the SUVAT equation [tex]x = ({v_{1}}^{2} - {v_{0}}^{2}) / (2\, a)[/tex] to find the displacement [tex]x[/tex] between the original position (ground level, where [tex]v_{0} = 49.05\; {\rm m\cdot s^{-1}}[/tex]) and the max-height position of the ball (where [tex]v_{1} = 0\; {\rm m\cdot s^{-1}}[/tex].)
[tex]\begin{aligned}x &= \frac{(0\; {\rm m\cdot s^{-1}})^{2} - (49.05\; {\rm m\cdot s^{-1}})^{2}}{2 \times (-9.81\; {\rm m\cdot s^{-2}})} \\ &\approx 122.625\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
ons: READ each question below and ANSWER each part of the question.
Questions:
1. Ms. Woodard walks 1 m between each desk in her classroom. She walks
from desk 1 to desk 3, from desk 3 to desk 4, and finally from desk 4 back to
desk 2.
a. DRAW Ms. Woodard's path to all the desks here:
a.
a.
What DISTANCE has Ms. Woodard traveled? CONVERT (change) your answer to
millimeters.
What is Ms. Woodard's DISPLACEMENT?
Ms. Woodard has traveled a distance of 5 m.
Ms. Woodard's displacement is 1 m.
When the inferior angle of the scapula moves in the superior and lateral direction, the motion is called:
The motion of the inferior angle of the scapula in the superior and lateral direction is called upward rotation.
What are the possible motions of the scapula?The scapula or the shoulder blade has about six different types of motion it undergoes.
The six ways of movement of the scapula are:
protraction,retraction,elevation,depression,upward rotation, anddownward rotationWhen the inferior angle of the scapula moves in the superior and lateral direction, the motion is called upward rotation.
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How much heat is needed to raise the temperature of 100.0 g of water by 85.0°C ? A. 8,500 J 35,500 J B. C. 1.1 J
The quantity of heat required to raise the temperature of the water is approximately 35,500 J.
Heat required to raise the temperature of water
The quantity of heat required to raise the temperature of the water is calculated as follows;
H = mcΔθ
H = 100 x 4.18 x 85
H = 35,530 J
Thus, the quantity of heat required to raise the temperature of the water is approximately 35,500 J.
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when you rub neutral objects
electrons can be knocked loose from one object and picked up by the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.
b gained electrons
A transformer has two coils. Coil A has 75 turns and coil B has 100 turns. In the first instance, coil A is used as the primary coil, which is connected to an ac current source. As a result, the peak voltage of the secondary coil, B, has a value VP. Then, coil B is used as the primary coil and coil A becomes the secondary coil. The ac current source is then adjusted to deliver the same current to coil B as it did to coil A in the first instance. For this case, how does the peak voltage of the secondary coil, A, compare with VP.
The peak voltage based on the information given will be 1.33V.
How to calculate the voltage?From the information given, Coil A has 75 turns and coil B has 100 turns.
The voltage will be:
IVa = IVb
We will then substitute the values. c
V = 100/75
V = 1.33V
Therefore, the peak voltage based on the information given will be 1.33V.
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In the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaningful in a(n) _____ scale.\
In the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaningful interval scale.
What is an interval scale?It should be noted that an interval scale means a measurement where the difference between the variables is meaningful and equal.
In this case, in the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaningful interval scale.
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A body at rest is given an initial uniform acceleration of 8m/s2 for 30s after which the acceleration is reduced to 5m/s2 for the next twenty seconds. The body maintains the speed attained for 60s, after which it is brought to rest in 20s.
Explanation:
v=u+at, where v,u,a and t are the final velocity, initial velocity, acceleration and time, respectively.
For t=0 s to t=30 s , a =8 m/s 2.
For t=30 s to t=50 s , a = 5 m/s 2.
For t=50 s to t=110 s , a = 0 m/s 2.
For t=110 s to t=130 s , a is such that the body comes to rest at the end of this period.
For t=0 s to t=30 s ,v=0+8t⇒v=8t m/s.
At t=30s,v=8×30=240 m/s.
For t=30 s to t=50 s ,v=240+5(t−30)⇒v=90+5t m/s
At t=50s,v=90+5×50=340 m/s.
For t=50 s to t=110 s ,v=340 m/s.
For t=110 s to t=130 s ,v=340+a(t−110).
The body comes to a halt at t=130 s ⇒0=340+a(130−110).
0=340+20a⇒a=−34020=−17 m/s2.
For t=110 s to t=130 s ,v=340−17(t−110)=2210−17t m/s.
What is the term for producing a current by moving a wire through a magnetic field?.
A car of mass 750 kg accelerates away from traffic lights. At the end of the first 100 m it has reached a speed
of 12 m/s. During this time, its engine provides an average forward force of 780 N, and the average force of
friction on the car is 240 N.
a Calculate the work done on the car by the force of its engine.
b Calculate the work done on the car by the force of friction.
c Using ke. = mv2, calculate the increase in the car's kinetic energy at the end of the first 100 m.
d Explain whether your answers are consistent with the principle of conservation of energy.
the work done on the car by the force of its engine is 78,000 J.
" The work done on the car by the force of friction is 24,000 J.
Increasing the car's kinetic energy at the end of the first 100 m is 54,000J
a. Completed work = force x distance. Engine output = 780 N, that is,
780 N x 100 m = 78,000 J.
b. Completed work = force x distance. Friction force = 240 N, that is,
240 N x 100 m = 24,000 J.
c. Kinetic energy = 1 \ 2 x m x v2
= 1 \ 2 x 750 kg x 12 squared = 375 x 144 = 54,000 J.
How powerful is the engine of a car?Mainstream car and truck engines typically produce 100-400 pounds. -Torque feet. This torque is generated by the engine piston as it moves up and down on the engine crankshaft, causing the engine to rotate (or twist) continuously.
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help pleaaase!!
A train leaves the station from rest and travels along a straight track. if the train is 500 meters from the station when it reaches a velocity of 50m/s what is the acceleration of the train?
Answer:
[tex]2.5m/s^{2}[/tex]
Explanation:
Since the distance ,s = 500m
Initial velocity, u = 0m/s
Final velocity, v = 50m/s
We can one of the kinematics equations to find the acceleration.
[tex]v^{2} =u^{2} +2as\\50^{2} =0^{2} + 2a(500)\\2500 = 0 + 1000a\\1000a = 2500\\a = \frac{2500}{1000} \\= 2.5m/s^{2}[/tex]
Answer:
S=D÷T
Explanation:
50=0.5÷T
T= 100
Which statement about polymers is true?
Options below:
-Polymers are substances that have relatively large molecules.
-Oil and gas are the starting materials for making all polymers.
-Fabrics such as cotton and silk are synthetic polymers.
-All polymers are obtained from living organisms.
Answer:
a
Explanation:
Polymers are large molecules which form long chains
Answer: A. Polymers are substances that have relatively large molecules.
Explanation:
Select the correct answer.
Which statement about polymers is true?
A. Polymers are substances that have relatively large molecules.
B. Oil and gas are the starting materials for making all polymers.
C. Fabrics such as cotton and silk are synthetic polymers.
D. All polymers are obtained from living organisms.
What is the change of state when magma crystallises to form igneous rock?
Answer:
liquid
Explanation:
due to high temperatures in the magma chamber all solids liquidify on reaching the surface with colder temperatures it now solidify to form igneous rock
what evidence can you cite that the interstellar medium contains both gas and dust? (select all that apply.)
(a) The gas of interstellar medium can be detected from the radiations of photons of wavelength 21 cm.
(b) The gas of interstellar medium can be detected from the absorption lines present in the light from distant stars, which must be caused by a medium of density and temperature other than that of the stars emitting the lights.
What is interstellar medium?Interstellar medium is the matter and radiation that exist in the space between the star systems in a galaxy.
Evidence that interstellar medium contains both gas and dustThe gas of interstellar medium can be detected from the radiations of photons of wavelength 21 cm.The gas of interstellar medium can be detected from the absorption lines present in the light from distant stars, which must be caused by a medium of density and temperature other than that of the stars emitting the lights.Learn more about interstellar medium here: https://brainly.com/question/4173326
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Please help me! Uniform acceleration problem sheet:
In 1997, the thrust SSC, a turbofan powerd vehicle, acheive the land speed world record of 780.34 mph (1,223.65km/h) and became the first car to break the sound barrier. If it tool 1 minute for the thrust SSC to reach its top speed, what was the average acceleration during the time?
From the calculation, the value of the acceleration is 5.8 m/s^2.
What is uniform acceleration?The term uniform acceleration refers to a situation in which the velocity increases by equal amounts in equal time intervals.
Given the fact that the car started from rest and reached a velocity of 780.34 mph or 348.84 m/s in 1 minute of 60 seconds;
v = u + at
a = v/t
a = 348.84 m/s/ 60 seconds
a = 5.8 m/s^2
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8. An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120
specific heat capacity of the liquid in this temperature range. Assume that negligible h
O
O
O
2.51 x 10³ J/(kg. C°)
1.67 x 106 J/(kg C°)
2.02 x 104 J/(kg. C°)
The specific heat capacity of the liquid is 2.51 x 10³ J/kg⁰C.
Specific heat capacity of the liquidThe specific heat capacity of the liquid is calculated as follows;
Q = mcΔФ
where;
Q is quantity of heat c is specific heat capacitym is mass of the liquidΔФ is change in temperature = 22.54 - 18.55 = 3.99 ⁰Cc = Q/mΔФ
c = (65 x 120)/(0.78 x 3.99)
c = 2.51 x 10³ J/kg⁰C
The complete question is below:
An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120 s. The mass of the liquid is 0.780 kg and its temperature increases from 18.55°C to 22.54°C. a) Find the average specific heat capacity of the liquid in this temperature range.
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2. A kg of iron and a kilo of lead, both at 1000 degrees Celsius, are kept on ice. It is discovered after some time that the iron has melted more ice than the lead. Why? 2 A vonal containing un or in kont in on oron The tomis motor an hoot
The specific heat capacity of iron is greater than that of lead hence the iron will melt the ice more than the lead.
What is the specific heat capacity?
The specific heat capacity refers to the amount of heat that is required to raise the temperature of 1Kg of a body by 1 K.
We know that the specific heat capacity of iron is greater than that of lead hence the iron will melt the ice more than the lead.
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HELP ME!!PLEASE ANSWER!!!!!!
How many states of matter are there? Describe each state, and give an example of each
What is the magnitude of the magnetic dipole moment of the bar magnet
The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²
Magnetic dipole moment of the bar magnet
The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;
[tex]B = \frac{2\mu_0m}{4\pi r^3} \\\\m = \frac{4\pi r^3 B}{2\mu_0}[/tex]
where;
B is magnetic fieldm is dipole momentμ is permeability of free spacem = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)
m = 1.2 Am²
The complete question is below:
What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.
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Science question! helppppp
Let's take this problem step-by-step:
What does this problem want to solve:
⇒ find two pendulums that will swing back and forth in the least amount
of time
Therefore:
⇒ must find the equation that calculates that period or swing time of a
pendulum
Equation: [tex]T = 2\pi \sqrt{\frac{L}{g} }[/tex]
L: length of the pendulumg: gravitational accelerationBased on the equation:
⇒ the longer the string is ⇒ the greater the swing time
Thus:
⇒ pendulum Y and Z will have the least amount of swing time
Answer: (B)
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Find the maximum energy stored in the spring bumpers
The maximum energy stored in the spring bumpers is given as ¹/₂kx².
Maximum energy stored in a springThe maximum energy stored in a spring is given by the following equations;
E = ¹/₂kx²
where;
E is the energy stored in the springk is spring constantx is extension of the springThus, the maximum energy stored in the spring bumpers is given as ¹/₂kx².
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A crate is pulled with a force of 165 N at an angle 30 ° northwest. What is the resultant horizontal force on the crate?
Answer:
Resultant horizontal force = 143 N
Explanation:
Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;
Resultant horizontal force = 165 * cos 30
Resultant horizontal force = 142.89
Approximating to a whole number gives;
Resultant horizontal force = 143 N
Note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. a 0.4-m3 rigid tank contains refrigerant-134a initially at 160 kpa and 40 percent quality. heat is now transferred to the refrigerant until the pressure reaches 600 kpa. note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. determine the amount of heat transferred. (please provide an answer before moving on to the next part.)
Based on the calculations, the amount of heat transferred is equal to 2,317 kJ.
Given the following data:
Volume of tank = 0.4 m³.
Initial pressure = 160 kPa.
Final pressure = 600 kPa.
Initial quality, x = 40% = 0.4
How to calculate the amount of heat transferred?From the superheat table A-12, the specific volumes of the saturated liquid and vapor at 160 kPa are:
Vf(160 kPa) = 0.0007437 m³/kg. Vg(160 kPa) = 0.12348 m³/kg.Next, we would determine the initial specific volume by using this formula:
V₁ = (1 - x)Vf + xVg
V₁ = (1 - 0.4)0.0007437 + (0.4)0.12348
V₁ = 0.049838 m³/kg.
Also, we would find the mass of this refrigerant at the initial state by using this equation:
m = V/V₁
m = 0.4/0.049838
Mass, m = 8.03 kg.
From the superheat table A-12, the internal energy of the saturated liquid and vapor at 160 kPa are:
Uf(160 kPa) = 31.09 kJ/kg. Ug(160 kPa) = 221.35 kJ/kg.At the initial state, we would find U₁ from the quality:
U₁ = (1 - x)Uf + xUg
U₁ = (1 - 0.4)31.09 + (0.4)221.35
U₁ = 107.19 kJ/kg.
From the superheat table A-13, the final specific volume and internal energy of the saturated liquid and vapor at 600 kPa are:
Vf = 0.057006 m³/kg.Uf = 367.81 kJ/kg.At the final state, we would find U₂ by extrapolating with the last two points in the table:
[tex]U_2 = 357.96 + (\frac{367.81 \; - \; 357.96}{0.057006\;-\;0.055522}) \times (0.049838\;-\;0.055522)\\\\U_2 = 357.96 + (\frac{9.85}{0.001484}) \times (-0.005684)\\\\U_2 = 357.96 + 37.73\\\\[/tex]
U₂ = 395.69 kJ/kg.
Now, we can calculate the amount of heat transferred:
Q = m(U₂ - U₁)
Q = 8.03(395.69 - 107.19)
Q = 8.03(288.5)
Q = 2,316.66 ≈ 2,317 kJ.
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In a Laundromat, during the spin-dry cycle of a washer, the rotating tub goes from rest to its maximum angular speed of 8.70 rev/s in 6.80 s. You lift the lid of the washer the instant the angular speed reaches the maximum value, and notice that the tub decelerates and comes to a stop in 19.0 s. Assuming that the tub rotates with constant angular acceleration while it is starting and stopping, determine the total number of revolutions undergone by the tub during this entire time interval.
Since we assume the accelerations are constant, the instantaneous acceleration is the same as the average acceleration, so in the first 6.80 seconds we have
[tex]\alpha_1 = \alpha_{\rm ave} = \dfrac{\Delta \omega}{\Delta t} = \dfrac{8.70\frac{\rm rev}{\rm s}}{6.80\,\rm s} \approx 1.28 \dfrac{\rm rev}{\mathrm s^2}[/tex]
In this time, the tub undergoes an angular displacement of
[tex]\theta_1 = \dfrac12 \alpha_1 (6.80\,\mathrm s)^2 \approx 29.6\,\mathrm{rev}[/tex]
In the next 19.0 seconds the tub has acceleration
[tex]\alpha_2 = \dfrac{-8.70\frac{\rm rev}{\rm s}}{19.0\,\rm s} \approx -0.458 \dfrac{\rm rev}{\mathrm s^2}[/tex]
and in this time, the tube undergoes an additional displacement of
[tex]\theta_2 = \left(8.70\dfrac{\rm m}{\rm s}\right)(19.0\,\mathrm s) + \dfrac12 \alpha_2 (19.0\,\mathrm s)^2 \approx 82.7\,\mathrm{rev}[/tex]
So the tub completes [tex]\theta_1+\theta_2 \approx \boxed{112\,\mathrm{rev}}[/tex].
A plane is coming in to taxi at an airport. It lands parallel to the surface at 480m/s and takes exactly one minute to come to a complete stop. What is its acceleration?
The acceleration of the plane will be −8 m/s²
How to find the acceleration of a plane?
Acceleration is the rate of change in velocity over time (Δv/t).
Given, that the initial velocity of the plane u=480 m/s
The final velocity of the plane is zero after landing, v= 0 m/s
t= 1 minute= 60 seconds
we know, v=u + at
0= 480 + 60a
a=[tex]\frac{-480}{60}[/tex] = -8m/s²
Thus, the acceleration of the plane is -8 m/s²
(negative acceleration implies that the object is slowing down)
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Kinetic energy of a body is increased by by 300% what is percentage increased in momentum
Answer
100% - double
200% - triple
300% - 4X
For a 300% increase the KE must be 4 time as large
KE2 / KE1 = M V2^2 / M V1^2 = (V1 / V2)^2 = 4
So V2 = 2 V1 for the requested increase
M V2 / M V1 = V2 / V1 = 2
So the momentum would double for a 100% increase
Calculate the mass of an object whose weight is 400n and accleration due to gravity is 10 m/ s
Answer:
40kg
Explanation:
w=m×
w=400n
g=10
m=?
400/10=m×10/10
m=40
as time passes the sound wave
Answer:
Loud to soft while pitch increases
Explanation:
Sound waves shown graphically display their amplitude (height of the graph) and their wavelength (the horizontal distance from peak to peak, or valley to valley... one full cycle).
Instead of wavelength, alternatively, one can observe the frequency of the wave (how many cycles are completed for a given unit of horizontal distance) which is in an inverse relationship with the wavelength (as a wavelength gets shorter, the frequency gets higher, and as the wavelength gets longer, the frequency gets lower).
The amplitude of a wave corresponds to how loud the sound is.
The frequency of a wave corresponds to the pitch of the sound.
Notice that on the graph, the height of the graph decreases over time (the peaks get shorter and shorter). So, the sound volume will get quieter and quieter. Using terminology that matches the answer choices, the sound will start loud and get soft.
Notice that on the graph, the wavelength decreases over time (starts with a pretty long distance between peaks, and then the distance between peaks gets shorter and shorter). Alternatively, looking at frequency, notice that the frequency gets higher and higher (on the left, one finger-width doesn't is less than one full cycle, but on the right, the same finger-width is wider than multiple cycles). So, the pitch of the sound will get higher and higher.
Thus, for this graph, the sound goes from loud to soft, and the pitch increases.
what is the speed of a wave that has a frequency of 11.5Hz and a wavelength of 1.7m?
Answer:
19.55 m/s
Explanation:
Here is HOW to get the answer:
Speed = wavelength * freq
= 1.7 * 11.5 = 19.55 m / s
A car accelerates from a standstill to 60 km/hr in 10.0 seconds. What is its acceleration?
The acceleration of the car is 1.66 m per sec square.
How to calculate acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is accelerating.
Initial velocity=0
Final velocity= 60km/hr
To convert it into m/sec
1 km=1000 m
1 hr=3600 sec
So= (60×1000)÷3600=16.66 m/sec
time=10 sec
We know that acceleration is the rate of change of velocity per unit of time.
acceleration=(final velocity-initial velocity)÷ time taken
= (16.66-0)÷10
= 1.66 m per sec square
So, Acceleration will be, 1.66 m per sec square
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Gravity is the attractive pull between two objects that have mass. The strength of the gravitational distance. As distance between the objects increases, the force of gravity decreases. If the distance
one-fourth as strong as before. Which one of the graphs best represents the relationship between
pull is doubled,
gravity and distance. depends
on mass and the force of gravity is
A. A
B. B
C. C
D. D
Sorry for the bad picture right now i dont have to take a nice picture
Graph A best represents the relationship between pull is doubled, gravity and distance. depends on the mass and the force of gravity. Option A is correct.
What is Newton's law of gravity?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
The expression for the gravitational force is given as;
[tex]\rm F = G\frac{Mm}{r^2}[/tex]
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
Decreasing the distance would increase the gravity of the planet.
Gravity is the attraction force that draws two mass-containing objects together. the gravitational distance's strength.
The force of gravity weakens as the distance between the items rises. if the separation is just one-fourth as great as previously. In the graph, the link between pull and doubled is best represented by A.
Hence option A is correct.
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