A ball is thrown eastward into the air from the origin (in the direction of the positive x-axis). The initial velocity is 40 i + 32 k, with speed measured in feet per second. The spin of the ball results in a southward acceleration of 6 ft/s2, so the acceleration vector is a = −6 j − 32 k. Where does the ball land? (Round your answers to one decimal place.) ft from the origin at an angle of ° from the eastern direction toward the south. With what speed does the ball hit the ground? (Round your answer to one decimal place.) ft/s

Answers

Answer 1

Answer:

The answer is "52.61 ft/s"

Explanation:

Taking the motion in the z-direction is [tex]u_z = 32 , \ \ a_z = - 32[/tex]

[tex]t = 2 \frac{u_z}{( - a_z )}\\\\[/tex]

  [tex]= 2 \times \frac{32}{32}\\\\ = 2 \ sec\\\\[/tex]

z-axis change is zero z and the  x-path the same way:

[tex]= u_x t + \frac{1}{2} a_x t^2 \\\\= 40 \times 2 + 0.5 \times 0 \times 2^2 \\\\ = 40 \times 2 + 0.5 \times 0 \times 4 \\\\ = 80 +0\\\\= 80 \ ft \ \ i[/tex]

In y-direction:

[tex]= 0 \times t - \frac{1}{2} \times (6) \times 2^2\\\\ = - \frac{1}{2} \times (6) \times 4\\\\ = - (6) \times 2\\\\= - 12 ft \ \ j[/tex]

the ball lands at:[tex]( 80 i - 12 j + 0 k ) ft[/tex]  

Magnitude:

[tex]\to ( 80^2 + (-12)^2 )^{\frac{1}{2}}\\\\\to ( 6400 + 144 )^{\frac{1}{2}}\\\\\to ( 6544 )^{\frac{1}{2}}\\\\\to 80.89 \ ft[/tex]from the origin.

angle:

[tex]\to \tan^{-1} ( \frac{12}{80} )\\\\\to 8.53^{\circ}[/tex]

velocity:

[tex]\to 40 i + ( 0 - 6 \times 2 ) j + ( 32- 32 \times 2 ) k\\\\\to 40 i + ( - 12 ) j + ( 32- 64 ) k\\\\\to 40 i - 12 j - 32 k\\\\\to ( 40^2 + 12^2 + 32^2 )^{\frac{1}{2}}\\\\\to (1600+144+1024)^{\frac{1}{2}}\\\\\to 2768^{\frac{1}{2}}\\\\\to 52.61\ \ \frac{ft}{s}[/tex]


Related Questions

A swimmer can travel 2.30 m/s in still water. The swimmer heads directly west across a steam whose current is 1.20 m/s n. What is his velocity relative to the ground

Answers

Answer:

velocity relative to the ground = 2.54 m/s

Explanation:

given data

still water Vx = 2.30 m/s

across a steam Vy = 1.20 m/s

solution

we get here first velocity relative to the ground is express as

velocity = [tex]\sqrt{Vx^2+Vy^2}[/tex]      ...............1

put here value and we get

velocity  = [tex]\sqrt{2.3^2+1.20^2}[/tex]

velocity = 2.54 m/s

which molecule has the longest bond length nitrogen, hydrogen or oxygen

Answers

Answer:

Hydrogen

Explanation: hopefully.

HELP PLEASE!!
You throw a rock with sufficient speed to put it into orbit around the asteroid 234 Ida very close to its surface. How long would it take the rock to make one orbit around the asteroid? Assume 234 Ida is spherical. Ida's mass is 4 x 1016 kg and its radius is 16 km.

A) 0.62 hr
B) 2.2 hr
C) 1.6 hr
D) 3.4 hr

Answers

Answer:

The correct option is;

B) 2.2 hr

Explanation:

The location of the rock in the orbit of the asteroid = Close to the surface of the asteroid

The required equation is given as follows;

[tex]\dfrac{G \times M \times m}{r^2} = \dfrac{m \times v^2}{r}[/tex]

[tex]\therefore v^2 = \dfrac{G \times M}{r}[/tex]

Where;

v = The orbital velocity

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r = The radius of the planet = 16 km = 16,000 m

M = The mass of the planet = 4 × 10¹⁶ kg

∴ v² = 6.67430 × 10⁻¹¹ × 4 × 10¹⁶/16,000 = 166.8575

v = √(166.8575) = 12.92 m/s

The orbital velocity = v = 12.92 m/s

The time it takes for the rock to make one orbit round the asteroid is given as follows

The length of the orbit = The circumference of the asteroid = 2 × π × r  

The length of the orbit =  2 × π × 16,000 ≈ 100530.965 m

The time it takes for the rock to make one orbit round the asteroid = The length of the orbit/(The speed of the asteroid)

The time it takes for the rock to make one orbit round the asteroid = 100530.965/(12.92) ≈ 7781.034 seconds or 2.2 hours (by approximation by one decimal place)

The time it takes for the rock to make one orbit round the asteroid ≈ 2.2 hours.

what determines the roll and pitch of a satellite.
This is for my Physical science class

Answers

Answer: Rotation around the side-to-side axis is called pitch. Rotation around the vertical axis is called yaw.

Br
A tow truck pulls a 1,500 kg car with a net force of 2,000 N. What is the
acceleration of the car? DO NOT FORGET CORRECT UNITS.

Answers

Answer:

a = F/m = 4000/1500 = 2.66m/s^2

Explanation:

A tow truck pulls a mass of 1500 kg with a force of 2000 N then the acceleration of the truck will be equal to 1.33 m/s².

What is Force?

A force in physics is an input that has the power to change an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe forces.

Being such a vector quantity, a force does have magnitude and direction. The SI unit metric newton is used to measure it (N). The letter F stands for force.

According to Newton's second law's original formulation, an object's net force is equal to the speed that its momentum is changing over time.

As per the given information in the question,

Mass of car, m = 1500 kg

Force, F = 2000 N

Then, the acceleration will be,

F = m × a

a = 2000/1500

a = 1.33 m/s²

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if an engine applies a force of 600N on a 200kg scooter. what will be the change of speed? answer in m/s^2

Answers

Gr
R
R
T
T
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R
R

(Forensic Science)

Officer Piddington has been called to a murder scene. He arrives to find EMTs tending to the victim lying on the living room floor with a large knife protruding from his sternum. It is clear that this is where the crime occurred, and Officer Piddington does not see any evidence of dangerous chemicals on site. He secures the area and then begins to document the scene. What is one of the first things that Officer Piddington records in his notes about the crime scene?

The victim's past criminal history
A description of the crime scene when he arrived
The estimated time of death of the victim
A list of possible suspects involved in the crime

Answers

Answer:

The answer is B

Explanation:

The detective begins his/her documentation of the crime scene by writing down the date, time, and location of the crime scene. this is always important to start the report with so that any who reads the notes know when and wher this all happened before reading about evidence other wise the reader could be confused and pass evidence off as faulty.

Answer:

A description of the crime scene when he arrived

Explanation:


A wagon, initially traveling at a constant 8.5 m/s, starts going down a hill that creates an
acceleration of 4.1 m/s2. How far downhill has the wagon gone after 2.7 s ?

Answers

Answer:

Explanation:

Given parameters:

Initial velocity  = 8.5m/s

Acceleration  = 4.1m/s²

Time  = 2.7s

Unknown:

Distance downhill traveled  = ?

Solution:

To solve this problem, we have to adopt the right motion equation;

          S = ut + [tex]\frac{1}{2}[/tex]at²

where  s = distance

            u = initial velocity

            a = acceleration

            t = time taken

Insert the parameters and solve;

  S = (8.5 x 2.7) + ([tex]\frac{1}{2}[/tex] x 4.1 x 2.7²)

  S = 22.95 + 14.95

  S = 37.9m

5. An airplane must reach a velocity of 71 m/s for takeoff. If the runway is 1.0 km long, what
must the constant acceleration be?

Answers

Answer:

final velocity 'v' = 71m/s distance 's' = 1000m intial velocity 'u' =0 therefore,using third equation of motion v^2- u^2=2*a*s 71*71=2*a*1000 a=71*71/(2*1000 a= 2.52m/s^2

Explanation:

Johnny kicked a football from a hill 20 meters tall. The ball leaves at a 45.0 degree angle with an initial velocity of 30.0 m/second. How many seconds was the ball in the air? Report your answer to 3 sig figs. Seconds

Answers

Answer:

The value is [tex]t = 5.124 \ s[/tex]

Explanation:

From the question we are told that

   The height of the tree is [tex]s = 20 \ m[/tex]

    The angle the ball leaves is  [tex]\theta = 45^o[/tex]

    The initial velocity  is  [tex]u = 30.0 \ m/s[/tex]

Generally the vertical of the ball's initial velocity is mathematically evaluated as

      [tex]u_y = u * sin (45)[/tex]

=>   [tex]u_y =- 30 * sin (45)[/tex]

=>   [tex]u_y = -21.21 \ m/s[/tex]

Here  [tex]u_y[/tex] is negative because it is in the direction of the negative y-axis

Generally from kinematic equation we have

      [tex]s = u_yt + \frac{1}{2} g t^2[/tex]

=>   [tex]20= -21.21 t +4.9 t^2[/tex]

=>   [tex]4.9 t^2 -21.21 t- 20= 0[/tex]

Solving using quadratic formula we have that

        [tex]t = 5.124 \ s[/tex]

   

What are examples of Electrical Potential Energy

Answers

Lightning is probably the most flamboyant example that we are familiar with in our normal lives.

Lightning results from a negative charge in the bottoms of clouds and a positive charge on the surface. When the potential energy becomes great enough to overcome the insulation caused by the atmosphere, it jumps the gap.

Calculate the work done by a 60 N force pushing a pencil 0.25 m

Answers

In case we are asked useful work done then we calculate net force used for pushing the pencil:
Net force used for pushing the pencil
=
47

23
=
24

N

Assuming that direction of movement of pencil and net force is same.
Useful Work done by force in moving the penc

Need help ASAP!! Why does the ray bend as it enters the glass

Answers

Answer:

Explanation:

because as the light shines through the glass, The glass reflects the light from different places in the glass causing the light to bend

Answer: If light enters any substance with a higher refractive index  it slows down. The light bends towards the normal line. If light travels enters into a substance with a lower refractive index it speeds up. The light bends away from the normal line.

EASY QUESTIONS! DUE IN 15 MIN WILL MARK BRAINLIEST.

1. What is the sum of a vector 8 m south and a vector 12 m north? *
2. What is the sum of a vector 12 m north and a vector 8 m north? *

PLEASE SHOW WORK AND EXPLAIN

Answers

Explanation:

As they are in same direction, you can add them directly. And result is 12 + 8 m = 20 m North. If you use vector addition: Vectors = 12m & 8 m & angle b/w them is 0°(as both are in same direction).

Which does NOT illustrate Newton's First Law?

Answers

Answer:

u didnt have options? to this question


The area under which of
these graphs can be used
to estimate the value of
impulse?
Graph A
O Graph B
O Graph C
Graph D

Answers

Answer:

Graph A is the Answer

Friction force is the opposition to the motion of surfaces sliding across each other. Based on your observations, what is one factor that affects the amount of friction?

Answers

One factor that affects the amount of friction is roughness or smoothness of the sliding object.

Factors affecting friction

There are several factors affecting the amount of friction and they include the following;

Roughness or smoothness of the sliding object.Roughness or smoothness of the surface.Shape of the object.Normal force acting upon the sliding bodies.Dry friction is independent of the surface area of a contact.

Thus, one factor that affects the amount of friction is roughness or smoothness of the sliding object.

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Answer: It depends on the surface is the surface bumpy? Or is the surface flat and smooth?

Explanation: If a surface is to bumpy friction slows it down, if a surface is flat and smooth it glides with ease.

A person with a mass of 70 kg exerts a force of 60 N when she runs.

What is her acceleration?

Answers

Answer:

a = 0.857143 m/s2

Explanation:

a=f/m

60/70

People have vastly different opinions on the role and responsibility of schools to provide sex education. Teenage pregnancy and sexually transmitted diseases are real problems facing our adolescent population. In some cases, the decision to engage in a sexual relationship is a life or death decision.

References:

Coon, D., Mitterer, J.O., & Martini, T. (2019). Introduction to psychology: Gateways to mind and behavior (15th ed.). Belmont, CA: Cengage Learning.

Answers

Answer: ummm is this a question?

Explanation: what I said up there ^

is it true that mass is a measure of the force of gravity on an object​

Answers

Answer:

yes it is true

Explanation:

What is a coastal plain? A high mound or ridge of sand The boundary between the land and an ocean A flat, low-lying piece of land next to the ocean The piece of land formed when a river splits into smaller rivers

Answers

Answer:

Hi I learned that it is something pretty and it's a flat low-lying piece of land next to the ocean

Explanation:

Answer:

A coastal plain is flat, low-lying land adjacent to a sea cost. A fall line commonly marks the border between a coastal plain and a piedmont area. Some of the largest coastal plains are in Alaska and the southeastern United States.

Explanation:

Se tiene una esfera gaussiana que encierra a un cubo de lado "a" que tiene una carga neta q. ¿Cuál es el flujo de campo eléctrico sobre la superficie de la esfera gaussiana?

Answers

Answer:

Φ =    Q/ε₀

Explanation:

Una esfera Gaussiana, es una esfera imaginaria en cuya superficie el campo eléctrico es constante. El campo eléctrico es el producido por la carga que está encerrada por la superficie. De tal modo que si tenemos un cubo con una carga neta igual a Q y la asumimos ubicada en el centro del cubo (que es el centro de la esfera gaussiana de radio x), tendremos:

El flujo eléctrico es:

Φ = ∫ E*dS = Q/ε₀       Esta es la primera ecuación de Maxwell como E es constante por definicion

El area de una esfera es: A(s) = 4*π*x²

E * 4*π*x² = Q/ε₀

E = Q/4*π*ε₀* x²

La distancia que hay del centro del cubo a un vertice (x) es:

x² = a² + a²

x = √2a²

x = a*√2

Sustituyendo x por su valor  

E =    Q/4*π*ε₀*2*a²

Entonces

Φ =    Q/4*π*ε₀*2*a²* ∫ dS

Φ =    [Q/4*π*ε₀*2*a²] *[4*π*2*a²  ]

Φ =    Q/ε₀

If a squirrel climbs a tree at 16m/s, how many meters will it travel every hour?

Answers

Answer:

57600 m and hour

Explanation:

A bird flies 1.3\,\text m1.3m1, point, 3, start text, m, end text with an average speed of 2.4\,\dfrac{\text m}{\text s}2.4 s m ​ 2, point, 4, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction.

Answers

Explanation:

We are not asked what to look for, bot we can as well get the time taken by the bird to cover the distance at that speed.

Given

average speed = 2.4m/s

Distance = 1.3m

From the formula

Speed = Distance/Time

Time = Distance/Speed

Time = 1.3/2.4

Time = 0.542secs

Hence the total time covered by the bird is 0.542secs

If a 6kg bird is pushed by the wind with a force of 10 N. how fast does the bird
accelerate?

Answers

Answer:

a=1.667 m[tex]s^{-2}[/tex]

Explanation:

F=ma, here force is given as 10N and mass of bird is 6kg, so using the formula acceleration can be calculated as follows

∴ F=ma

1N= 1 kg m[tex]s^{-2}[/tex]

[tex]a=\frac{F}{m}[/tex]

[tex]a=\frac{10 kg ms^{-2} }{6 kg}[/tex]

∴ a= 1.667 m[tex]s^{-2}[/tex]

What is the driving energy source for the heating of the Earth?

Answers

The sun is the driving energy source for the heating of the Earth

7. A car drives 750 m directly to the north, stops, and then backs up 300 m to the south.
a) What is the magnitude of the car's displacement?

Answers

Answer:

what grade is this?

Explanation:

Answer:

is it cumpulsary to know how fast the car was moving or it dosn't have to deal with velocity

Explanation:

:)

Works by separating the different wavelengths of light, used to
determine which elements are present in a star or sample

Answers

Answer:the light from an astronomical source can consist of a continuous spectrum, an emission (bright line) spectrum, or an absorption (dark line) spectrum. Because each element leaves its spectral signature in the pattern of lines we observe, spectral analyses reveal the composition of the Sun and stars.

Explanation:

when your bikes in motion and you slam on the brakes, do you experience positive or negative acceleration?

Answers

Answer:

negative

Explanation:

Is it possible to analyze the motion of an object that has non-constant acceleration?

Answers

Answer:

B

It is possible, but with formulas not yet derived by physicists.

Explanation:

Yes, it is possible to analyze the motion of an object that has non-constant acceleration but not with the help of Newton's equation of motion, as these equations are only valid for constant acceleration.

What are the three equations of motion?

There are three equations of motion given by  Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

Note that these equations are only valid for a uniform acceleration.

It is feasible to study an object's motion with non-constant acceleration, but not using Newton's equations of motion because these equations are only applicable for constant acceleration.

For analyzing the variable acceleration we have to use the calculus tools such as differentiation and integration.

Hence, it is possible to analyze the motion of an object that has non-constant acceleration

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